if g(x)=1/5(x-1)+2, what is the value of g(11)

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

It is [tex]y=2x+2[/tex]  because you should use [tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]  then just plug it in using

(1, 4) and (-2, -2).

[tex]\frac{4--2}{1--2} =\frac{6}{3} =2[/tex]

That eliminates everything except the second one and the third.

So now we would find the b in the equation [tex]y=mx+b[/tex]

[tex]y=mx+b\\4=2(1)+b\\4=2+b\\2=b\\b=2[/tex]

and that's all

Answer:

D

Step-by-step explanation:

Please see the attached picture for full solution.

Answer:

Step-by-step explanation:

No of students study math = 3/5 of 50 = 30

No of students study English = 3/10 of 50 = 15

Total = 30 + 15 = 45

Remaining students = 5

No of students study geography = 5

Fraction of geography to whole class = 5/45 = 9

Answer: The side links of polygons ABCD are equal to corresponding side lengths in the translated images. this means that lengths of sides of the polygon are preserved as the figure is translated in any direction.

Answer:

B

Step-by-step explanation:

sine = opposite/hypotenuse

sin45 = x/4

sin45/1 = x/4

cross multiply

1 × x = 4 × sin45

x = 4sin45

x = 2.828427125

x = 2 × square root of 2 = 2.828427125

Answer:

B )  2[tex]\sqrt{2}[/tex]

Steps:

α = 90°, β = 45°, a = 4: b = 2.82842. . .

β = 45°

a = 4

α = 90°

b =  [tex]\frac{4sin(45)}{sin(90)}[/tex]

b = 2.82842. . .

2[tex]\sqrt{2}[/tex] = 2.82842. . .

Answer:

550

Step-by-step explanation:

It´s 550 because 612-62 is 550

Given parameters:

Length of earring hook  = 1.5cm

Length of given wire = 45cm

Dimension of the triangle = 3.2cm, 3.2cm and 2.1cm

Unknown:

Number of earrings that can be made from the wire = ?

To solve this problem, we need to calculate the total length of the earring we want to make.

  Total earring length  = Perimeter of earring + length of earring hook

                                      = 3.2 + 3.2 + 2.1 + 1.5  

                                      = 10cm

Now the length of the wire is 45cm,

  Number of earrings  = [tex]\frac{45}{10}[/tex]  = 4.5 earrings

  But this is not reasonable, therefore, we can only forge 4 complete earrings from the given length with 5cm of wire remaining.

The number of earrings that can be made is 4.

Answer: A dot plot

Step-by-step explanation: According to the scenario described above, the dot plot or chart will be the best to display the information. The dot plot represents data point using tiny dots or circles. The dot represent the frequency of an observation, with each observation lined in vertical arrangement. The number of dots in each data point represents the frequency value of each observation or class. In the scenario above, the number of minutes taken to complete the quiz will be on the horizontal axis with the frequency or number of student who fall into each category represented by dots arranged vertically

The total interest you will earn in 30 years is approximately $241.61.

To calculate the total interest earned in 30 years, we need to use the formula for compound interest:
A = P(1 + r/n)^(nt) - P
Where:
A = the future value of the investment
P = the principal amount (initial deposit)
r = the annual interest rate (in decimal form)
n = the number of times the interest is compounded per year
t = the number of years
In this case, the principal amount is $200, the annual interest rate is 3% (or 0.03 as a decimal), the interest is compounded monthly (so n = 12), and the time period is 30 years (so t = 30).
Plugging in these values into the formula:
A = 200(1 + 0.03/12)^(12*30) - 200
Now we can simplify and calculate:
A = 200(1.0025)^(360) - 200
A = 200(2.208040033) - 200
A ≈ 441.6080066 - 200
A ≈ 241.6080066

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Answer:

-29a - 6b + 59c

Step-by-step explanation:

First, keep in mind that only like terms can be combined.

5a + 7b - 12a + 6c - 13b - 22a + 53c

You can rearrange them to make it easier:

5a - 12a - 22a + 7b - 13b + 6c + 53c

-29a - 6b + 59c

Answer:

24.36

Step-by-step explanation:

hopes this helps

Answer:

its 24.36 trust me

Step-by-step explanation:

Answer:

rational becuse its a decimal and if u divided it u get 21.5 so u can round it to 22 so i think its rational hope this helps

Step-by-step explanation:

Answer:

circle=6, triangle=2, star=8, square=4

Step-by-step explanation:

6+2=8

6-2=4

8+4=12

8-4=4

4+4=8

Inequalities can be represented and analyzed using tables. A table is a useful tool for organizing and comparing different values, making it easier to understand and solve inequalities.

When working with inequalities, a table can display the variable values and their corresponding inequality outcomes, helping to identify the range of solutions.

To create a table for inequalities, start by selecting a range of values for the variable(s) involved in the inequality. Substitute these values into the inequality expression and evaluate whether the inequality holds true or not. Record the results in the table, indicating whether the values satisfy the given inequality.

The table allows for easy comparison of the values and their corresponding inequality outcomes. It helps identify the regions or intervals of the variable(s) that satisfy the inequality. By observing patterns in the table, such as increasing or decreasing values that meet the inequality criteria, one can gain insights into the solution set and the behavior of the inequality.

Tables are particularly useful when dealing with linear inequalities or systems of inequalities. They provide a visual representation of the inequality relationships, aiding in understanding and solving the inequality problem at hand.

In conclusion, tables serve as a valuable tool for working with inequalities. They help organize and compare values, allowing for a clearer understanding of the range of solutions and the behavior of the inequality. By utilizing tables, individuals can effectively analyze and solve inequalities in a systematic manner.

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The net present value of the project is $56,105.26.

The project being evaluated in this case is the purchase of a computer that has an economic life of 5 years. The computer has a purchase cost of $410,000 and a salvage value of $74,000.

It is proposed that this purchase will eliminate the need for five employees, which in turn will result in a reduction of salaries paid to employees worth $119,000.

The working capital that would be released as a result of this purchase is $94,000. The corporate tax rate that will be used for the evaluation of this project is 24%.

The cost of capital of the company is 14%.The cash outflow at the beginning of the project is equal to the purchase price of the computer, which is $410,000.

The reduction in salary expense is an annual cash inflow that will last for the duration of the project.

This inflow is equal to $119,000 per year. Since the computer purchase will result in a reduction in working capital, it will result in an immediate cash inflow equal to $94,000.

The annual depreciation expense is equal to the purchase price of the computer, divided by the economic life of the computer.

Therefore, the annual depreciation expense is $82,000 per year. At the end of five years, the computer will have a salvage value of $74,000. This will result in a cash inflow at the end of the project, which is equal to the salvage value of the computer.

The net cash inflows from the project will be calculated by subtracting the cash outflow at the beginning of the project from the present value of all cash inflows. Since the discount rate is 14%, we will use this rate to discount the cash inflows.

The present value of each cash inflow is calculated as the cash inflow, divided by (1+discount rate)^number of years in the future.

For example, the present value of the $119,000 annual salary savings is equal to $119,000/(1+14%)^1 = $104,385.96.

The net present value of the project is the sum of the present values of all cash inflows, minus the cash outflow at the beginning of the project.

In this case, the net present value of the project is $56,105.26.

This is a positive net present value, which means that the project is expected to generate a return greater than the cost of capital.

Therefore, the company should proceed with the purchase of the computer. The NPV method is used to evaluate investment projects. It involves the calculation of the present value of all cash inflows from a project, minus the cash outflows.

If the net present value is positive, then the project should be undertaken. If the net present value is negative, then the project should be rejected.

The decision to accept or reject a project depends on the net present value, which is a measure of the profitability of the project.

The net present value of the project is $56,105.26. This is a positive net present value, which means that the project is expected to generate a return greater than the cost of capital. Therefore, the company should proceed with the purchase of the computer.

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Answer:

49

Step-by-step explanation:

If the smaller number is

x

, then the larger number is

2

x

−

3

Explanation:

(

x

)

+

(

2

x

−

3

)

=

75

3

x

−

3

=

75

3

x

=

78

x

=

26

The numbers are 26 and 49.

The value of the larger number will be 26.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The sum of two numbers is 75.

And, The second number is three less than twice the first.

Now,

Let the larger number = x

So, The second number = 2x - 3

Since, The sum of two numbers is 75.

Hence, We can formulate;

⇒ x + 2x - 3 = 75

⇒ 3x - 3 = 75

⇒ 3x = 78

⇒ x = 26

Thus, The value of the larger number will be 26.

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Answer:

f(x+2h)=−(f(x)+2hf′(x)+4h22f′′(x)+o(h3)==−f(x)−2hf′(x)−4h22f′′(x)−o(h3)

f(x−2h)=f(x)−2hf′(x)+4h22f′′(x)−o(h3)

8f(x+h)=8(f(x)+hf′(x)+h22f′′(x)+o(h3)=8f(x)+8hf′(x)+8h22f′′(x)+8o(h3)

−8f(x−h)=−8(f(x)−hf′(x)+h22f′′(x)−o(h3)=−8f(x)+8hf′(x)−8h22f′′(x)+8o(h3)

So

|f′(x)−112h[−f(x+2h)+8f(x+h)−8f(x−h)+f(x−2h)]|==|f′(x)−112h[−4hf′(x)−2o(h3)+16hf′(x)+16o(h3)]|==|f′(x)−f′(x)−14o(h3)12|=o(h3)?

2.

We just plug x+2h,x+h,x−h,x−2h to the approximation and get:

f′′(x)≈[−f(x+4h)−16f(x+3h)+16f(x+h)−130f(x)+64f(x+2h)+64f(x−h)+64f(x−2h)−64f(x−3h)]144h2

Step-by-step explanation:

Answer:

x = 13 1/2

Step-by-step explanation:

The value stored in the total variable will be "156" rather than the arithmetic sum of the two variables. In JavaScript, when you use the + operator with two strings, it concatenates them together instead of performing numerical addition. Therefore, "15" and "6" will be combined to form "156".

In JavaScript, the + operator is used for both numerical addition and string concatenation. However, the behavior of the + operator depends on the types of the operands involved.

In the given example, the variables glazedDonuts and cakeDonuts are both defined as strings. When you use the + operator with two strings, JavaScript interprets it as a string concatenation operation rather than numerical addition.

So, when you perform cakeDonuts + glazedDonuts, JavaScript concatenates the strings "15" and "6" together, resulting in the string "156". It simply combines the characters from both strings into a new string.

Therefore, in this specific example, the value stored in the total variable will be "156", not the sum of the numerical values of cakeDonuts and glazedDonuts.

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Answer:

7,077,888

Step-by-step explanation:

8^4= 8×8×8×8= 4096

6^3= 6×6×6= 216

16^= 16×16= 256

4096×216×256=226492416

226492416÷32

7,077,888

Answer:

2 batches

Step-by-step explanation:

if you can make it with 1/4 chips, then if you have 2/4 then you can make 2 batches because its double.

Given expressions:

  Area of a rectangle  = L W

  Area of a triangle = [tex]\frac{1}{2} B H[/tex]

Problem;

Create problems using the formula;

Solution:

Problem 1; Find the area of a rectangle whose length is 10cm and the width is half the size of the length?

    Given parameters:

    Length of rectangle  = 10cm

    Width of rectangle  = [tex]\frac{1}{2}[/tex] x length  = [tex]\frac{1}{2}[/tex] x 10  = 5cm

So, the area of the rectangle = 10cm x 5cm  = 50cm²

2. A triangle with a base length of 30cm and a height of 2cm will have an area of what?

    Given parameters:

         base length  = 30cm

         height  = 2cm

 Solution:

   Area of a triangle  = [tex]\frac{1}{2}[/tex] x b x h

   Area of a triangle  = [tex]\frac{1}{2}[/tex] x 30 x 2  = 30cm²

The area of the triangle will be 30cm²

Answer:

6 + 4 + 10

Step-by-step explanation:

Answer: 10

Step-by-step explanation: 6+4=10

Answer:

Incorrect

Step-by-step explanation:

deleted

Answer:

Step-by-step explanation:

Ok! figure out all even integers between 99 and 999. All even integers are divisible by 2... 999-99=900/2=450

Well, there are 450 even integers between 99 and 999, so all even are divisible by 2, and the answer is 450.

Answer:

x² + x = 342

Step-by-step explanation:

Let x be the 1st integer

x + 1 be the 2nd integer

x(x+1) = 342

Simplify

x² + x = 342

or in standard form:

x² + x - 342 = 0

Answer:

D. x2 − x − 342 = 0

Step-by-step explanation:

the value of greater integers can be 19 or -18.

(Edge 2023)

a. The control limits for the 3-sigma x-bar chart are: UCL x-bar = 61.744 lb. and LCL x-bar = 59.756 lb.

b. The control limit for the 3-sigma R-chart is UCL R = 4.051 lb., rounded to three decimal places.

(a) To determine the control limits for the 3-sigma x-bar chart, we need to use the given information of the sample size, overall mean, and average range.

For the x-bar chart, the control limits are calculated using the formula:

Upper Control Limit (UCL x-bar) = overall mean + (A2 * average range)

Lower Control Limit (LCL x-bar) = overall mean - (A2 * average range)

Where A2 is a constant depending on the sample size. For a sample size of 7, the value of A2 is 0.577.

Substituting the values into the formula, we get:

Upper Control Limit (UCL x-bar) = 60.75 + (0.577 * 1.78) = 61.744

Lower Control Limit (LCL x-bar) = 60.75 - (0.577 * 1.78) = 59.756

Therefore, the control limits for the 3-sigma x-bar chart are: UCL x-bar = 61.744 lb. and LCL x-bar = 59.756 lb.

(b) To calculate the control limits for the 3-sigma R-chart, we only need the value of the average range.

The control limits for the R-chart are calculated as follows:

Upper Control Limit (UCL R) = D4 * average range

Lower Control Limit (LCL R) = D3 * average range

For a sample size of 7, the values of D3 and D4 are 0 and 2.282, respectively.

Substituting the values into the formula, we get:

Upper Control Limit (UCL R) = 2.282 * 1.78 = 4.051 lb.

Therefore, the control limit for the 3-sigma R-chart is UCL R = 4.051 lb., rounded to three decimal places.

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Answer:

p = 2

Step-by-step explanation:

Step 1: Write equation

9(p - 4) = -18

Step 2: Solve for p

Step 3: Check

Plug in p to verify it's a solution.

9(2 - 4) = -18

9(-2) = -18

-18 = -18

(a) The intersection of two subspaces U and V in R^n is always a subspace of R^n.

(b) The union of two subspaces U and V in R^n may not be a subspace of R^n, and a counterexample can be provided.

(a) To prove that the intersection of two subspaces U and V in R^n is a subspace of R^n, we need to show that it satisfies the three properties of a subspace: closure under addition, closure under scalar multiplication, and contains the zero vector.

Let x and y be two vectors in the intersection of U and V. Since x and y are in both U and V, they belong to U + V. Therefore, x + y is in U + V, and by definition, it is also in the intersection of U and V. Similarly, for any scalar c, cx is in U and V, and thus in their intersection. Finally, the zero vector is in both U and V, and therefore it is in their intersection.

(b) To demonstrate that the union of two subspaces U and V in R^n may not be a subspace of R^n, consider the following example: Let U be the x-axis and V be the y-axis in R^2. Both U and V are subspaces of R^2. However, their union is the set of all points in R^2, which includes vectors that do not lie on either the x-axis or the y-axis. For example, the vector (1, 1) is not in either U or V, but it is in their union. Since the union contains vectors that are not closed under addition or scalar multiplication, it fails to be a subspace of R^2.

In conclusion, the intersection of two subspaces U and V in R^n is always a subspace of R^n, while the union of two subspaces U and V in R^n may not be a subspace of R^n, as shown by the counterexample of the x-axis and y-axis in R^2.

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