If g(x)=f(x)+k g ( x ) = f ( x ) + k , what is the value of k?

Therefore, the required probabilities are:

a) P(red car) = 0.537

b) P(speeding ticket) = 0.546

c) P(speeding ticket | red car) = 0.421

d) P(red car | speeding ticket) = 0.413

e) P(red car and speeding ticket) = 0.226

f) P(red car or speeding ticket) = 0.857

a) The probability that a randomly chosen person has a red car is the number of people with red cars divided by the total number of people, which is:

P(red car) = 335/624

= 0.537 (rounded to the nearest thousandth).

b) The probability that a randomly chosen person has a speeding ticket is the number of people with speeding tickets divided by the total number of people, which is:

P(speeding ticket) = 341/624

= 0.546 (rounded to the nearest thousandth).

c) The probability that a randomly chosen person has a speeding ticket given they have a red car is the number of people with red cars and speeding tickets divided by the number of people with red cars, which is:

P(speeding ticket | red car) = 141/335

= 0.421 (rounded to the nearest thousandth).

d) The probability that a randomly chosen person has a red car given they have a speeding ticket is the number of people with red cars and speeding tickets divided by the number of people with speeding tickets, which is:

P(red car | speeding ticket) = 141/341

= 0.413 (rounded to the nearest thousandth).

e) The probability that a randomly chosen person has a red car and got a speeding ticket is the number of people with red cars and speeding tickets divided by the total number of people, which is:

P(red car and speeding ticket) = 141/624

= 0.226 (rounded to the nearest thousandth).

f) The probability that a randomly chosen person has a red car or got a speeding ticket is the sum of the probabilities of having a red car and having a speeding ticket minus the probability of having both, which is:

P(red car or speeding ticket) = P(red car) + P(speeding ticket) - P(red car and speeding ticket)

= 0.537 + 0.546 - 0.226

= 0.857 (rounded to the nearest thousandth).

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The correct statement about a global minimum is: it is also a local minimum. This means that a global minimum is not only the lowest value in its surrounding area, but also the lowest value in the entire domain of the function.

A global minimum is a point on a function where the value of the function is the lowest over the entire domain of the function. In contrast, a local minimum is a point on the function where the value of the function is the lowest within some small neighborhood of the point.

It is true that a global minimum is also a local minimum. This is because, by definition, the value of the function at a global minimum is lower than the value of the function at any other point in the entire domain of the function. Therefore, the value of the function at the global minimum is also lower than the value of the function at any point in a small neighborhood around the global minimum. This means that the global minimum is also a local minimum.

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The conclusion of conjuncture that robyn will be 6 ft , 2 in. tall when she has completed 22 years age is not valid. So, option(b) is right one.

We have some statement or conjectures. We have to determine the final or produced conjecture is valid or not. According to statement, In fast five years,

The growth rate of Robyn's height = 2 in. per year

But for next five years the growth rate may or may not be remain same, i.e, 2 in. every year. Now, Age of Robyn = 15 years and Height of Robyn = 5 feet, 4 in. = 64 inches ( from conversion factor, 1 ft = 16 inches)

The final statement is that she will be 6 ft , 2 in. that is 74 inches tall when she's 22 years old. After 7 years from now, the increase in her height = 2 × 7 = 14 inches

and new height = 64 inches + 14 inches

= 78 in. = 6 feet, 6 inch.

So, this is not valid conjecture.

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Complete question

determine if the following conjecture is valid. given: for the past five years, robyn has grown 2 in . every year. she is now 15 years old and is 5 ft , 4 in . tall. conclusion: robyn will be 6 ft , 2 in . tall when she's 22 years old.

a) valid

b) not valid

c) valid only if she is male

Systems (i) and (ii) are linear, while systems (iii) and (iv) are nonlinear.

A linear system satisfies the properties of superposition and homogeneity, meaning that if the input is scaled or if multiple inputs are added together, the output will also be scaled or added together accordingly. Systems (i) and (ii) are both linear since they both satisfy these properties. However, systems (iii) and (iv) are nonlinear since they do not satisfy the properties of superposition and homogeneity. System (iii) contains a non-linear term (y(t))^2 and system (iv) contains a non-linear term (u(t))^2.

The determination of whether a system is linear or nonlinear can have important implications for the analysis and control of the system. It is important to recognize the differences between these types of systems in order to effectively model and manipulate them.

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The edges of the square may be linearly parameterized as follows:- The bottom edge from (0,0) to (5,0) can be parameterized as (t, 0) for t in [0, 5].

- The right edge from (5,0) to (5,5) can be parameterized as (5, t) for t in [0, 5], - The top edge from (5,5) to (0,5) can be parameterized as (t, 5) for t in [5, 0]., - The left edge from (0,5) to (0,0) can be parameterized as (0, t) for t in [5, 0].
To linearly parameterize the edges of square C with corners (0,0), (5,0), (5,5), and (0,5), oriented counterclockwise,

we can use the following parameterizations: 1. Bottom edge: from (0,0) to (5,0)
Parameterization: (x, y) = (t, 0), where 0 ≤ t ≤ 5

2. Right edge: from (5,0) to (5,5)
Parameterization: (x, y) = (5, t), where 0 ≤ t ≤ 5

3. Top edge: from (5,5) to (0,5)
Parameterization: (x, y) = (t, 5), where 0 ≤ t ≤ 5

4. Left edge: from (0,5) to (0,0)
Parameterization: (x, y) = (0, t), where 0 ≤ t ≤ 5, These linear parameterizations represent each edge of the square and follow the counterclockwise orientation.

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Ortiz would be paid $1056 for working 48 hours under the given pay rate of $22 per hour.

If Ortiz worked for 48 hours at a pay rate of $22 per hour, the calculation of his total earnings can be done by multiplying the number of hours worked by the hourly rate.

To calculate Ortiz's earnings for 48 hours, we multiply 48 by $22, which gives us a total of $1056.

Therefore, Ortiz would be paid $1056 for working 48 hours under the given pay rate of $22 per hour.

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It is found that Ortiz paid $1056 for working 48 hours under the given pay rate of $22 per hour.

We are given that Ortiz worked for 48 hours at a pay rate of $22 per hour

Then the calculation of his total earnings could be done by multiplying the number of hours worked by the hourly rate.

To determine Ortiz's earnings for 48 hours, we multiply 48 by $22, that will gives us a total of $1056.

48 x 22 = 1056

Therefore, Ortiz will be paid 1056 dollars for working 48 hours under the  pay rate of $22 per hour.

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The value of the cscθ will be 3/5.

Trigonometric ratios are mathematical formulas that connect the angles and side lengths of a right triangle. The following are the top three trigonometric ratios:

Sine (sin): The proportion of the hypotenuse's length to the length of the side that faces an angle.

Cosine (cos): The proportion of the hypotenuse's and adjacent sides' lengths.

The tangent (tan) is the proportion of a side's length to that of its neighboring side.

The value csc is inverse of the sin angle, so the value of csc angle will be,

csc = hypotenuse / Perpendicular

csc = 1/sinθ = 5 /3

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Statement iii is correct.

The test statistic is significant at the 0.03 level of significance, which is equivalent to a 97% confidence level.

Therefore, we can conclude that a 90% confidence interval for the difference in means will not contain the value 0 (Option I is false). Similarly, a 95% confidence interval for the difference in means will also not contain the value 0 (Option II is false). However, we cannot make any conclusion about a 99% confidence interval for the difference in means.

In general, as the level of confidence increases, the width of the confidence interval also increases. Therefore, it is possible that a 99% confidence interval for the difference in means may include the value 0 even though the 97% level of significance rejects the null hypothesis.

So, the only statement that must be true is III. A 99% confidence interval for the difference in means may or may not contain the value 0.

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Answer:

Step-by-step explanation:

24/6 = 4

24/0.6 = 0.4?

24/6/10

24: 6/10

24 * 10/6

240/6 =40

False

Answer:

60 mph

Step-by-step explanation:

Each way of the trip is 240 miles.

The round trip is 2 × 240 miles = 480 miles

The first half of the trip, 240 miles, was made at a speed of 30 mph.

s = d/t

st = d

t = d/s

t = 240 miles / 30 mph = 8 hours

The first part of the trip took 8 hours.

The entire round trip is 240 miles × 2 = 480 miles

The speed for the entire trip is 40 mph.

480 miles / 40 mph = 12 hours

12 hours - 8 hours = 4 hours

The return trip takes 4 hours.

The return trip is 240 miles.

s = d/t = 240 miles / 4 hours

s = 60 mph

Answer: 60 mph

The equations that are true for x = -2 and x = 2 are x² – 4 = 0 and 4x² = 16. So, correct options are A and D.

The solutions for the equations when x = -2 and x = 2 can be found by substituting these values of x into the equations and simplifying.

For x² – 4 = 0, substituting -2 and 2 for x gives (-2)² – 4 = 0 and (2)² – 4 = 0, which are both true. Therefore, this equation is true for x = -2 and x = 2.

For x² = –4, substituting -2 and 2 for x gives (-2)² = –4 and (2)² = –4, which are both false. Therefore, this equation is not true for x = -2 and x = 2.

For 3x² + 12 = 0, substituting -2 and 2 for x gives 3(-2)² + 12 = 0 and 3(2)² + 12 = 0, which are both false. Therefore, this equation is not true for x = -2 and x = 2.

For 4x² = 16, substituting -2 and 2 for x gives 4(-2)² = 16 and 4(2)² = 16, which are both true. Therefore, this equation is true for x = -2 and x = 2.

For 2(x – 2)² = 0, substituting -2 and 2 for x gives 2(-2 – 2)² = 0 and 2(2 – 2)² = 0, which are both true. Therefore, this equation is true for x = -2 and x = 2.

Therefore, correct options are A and D.

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To answer this question, a chi-square test of independence can be used to determine if there is a significant association between region of the country and support for new national parks (for or against).

The null hypothesis would be that there is no association between the two variables, and the alternative hypothesis would be that there is an association.

To analyze whether support for new national parks differs by region in the country (West, Midwest, South, Northeast), you would use an Analysis of Variance (ANOVA) test. The ANOVA test allows you to compare the means of multiple groups (in this case, the regions) to determine if there is a significant difference in support for new national parks among them.

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The circumference of the great circle of the sphere is approximately 31.4 inches.

To find the circumference of the great circle of the sphere with a volume of (500π)/3 cubic inches, we will first find the radius (r) using the volume formula, and then use the circumference formula.

Step 1: Use the volume formula to find the radius.
The volume formula for a sphere is V = (4/3)π[tex]r^3[/tex]. We are given the volume as (500π)/3, so we can set up the equation:

(500π)/3 = (4/3)π[tex]r^3[/tex]

Step 2: Solve for r.
To solve for r, we can first divide both sides by (4/3)π:

[(500π)/3] / [(4/3)π] = [tex]r^3[/tex]

Cancelling the π and the 3 from both sides, we get:

500 / 4 = [tex]r^3[/tex]
125 = [tex]r^3[/tex]

Now, take the cube root of both sides:

r = 5

Step 3: Use the circumference formula to find the circumference of the great circle.
The circumference formula for a circle is C = πd, and since the diameter (d) is twice the radius, we have:

C = π(2r) = π(2 × 5) = 10π

Step 4: Calculate the circumference using 3.14 for π and round to the nearest tenth.
C = 10 × 3.14 ≈ 31.4

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The pool dimensions are approximately 12.22 by 21.22 feet.

To start, we know that the pool must be a 77 sq ft rectangle, so we can use the formula for the area of a rectangle (length x width = area) to solve for the dimensions.

77 = length x width

Next, we know that the fenced off plot is a 17 by 26 feet rectangle. We can use this information to set up an equation for the distance between the pool and the fence:

17 - 2x = length
26 - 2x = width

We also know that the fence should be twice as far away on the end where the lifeguard chair will be located, so we can set up another equation:

17 - 4x = length (on the side with the lifeguard chair)

Now we can substitute the expressions for length and width into the formula for the area of a rectangle:

77 = (17 - 2x)(26 - 2x)

Expanding the expression on the right side, we get:

77 = 442 - 86x + 4x^2

Rearranging and simplifying, we get a quadratic equation:

4x^2 - 86x + 365 = 0

Using the quadratic formula, we can solve for x:

x = (86 +/- sqrt(86^2 - 4(4)(365))) / (2(4))

x = (86 +/- sqrt(55284)) / 8

x = (86 +/- 234.85) / 8

x = 36.86 or 2.39

We can ignore the negative value, so x = 2.39 feet.

Now we can use the equations for length and width to solve for the dimensions of the pool:

length = 17 - 2x = 17 - 2(2.39) = 12.22 feet
width = 26 - 2x (except on the side with the lifeguard chair, where it is 4x) = 26 - 2(2.39) = 21.22 feet

So the pool dimensions are approximately 12.22 by 21.22 feet.

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The value of n in the global truncation error of the Runge-Kutta method can be determined by taking the number of steps required to reach a certain point.

As the local truncation error is of O(h3), it means that the error in each step is proportional to h3. Therefore, if we take n steps, the total error would be proportional to h3n. Since we are given that the global truncation error is of O(hn), we can conclude that n must be equal to 3.

Based on the information provided, the local truncation error in the Runge-Kutta method is given as O(h^3). The global truncation error is generally one order lower than the local truncation error. Therefore, in this case, the global truncation error in the Runge-Kutta method can be determined as O(h^2), where the value of n is 2.

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, the probability of one person randomly picking a cherry popsicle and another person selecting a grape popsicle from the box is 1/15.

The probability of one person randomly picking a cherry popsicle is 4/16 (since there are 4 cherry popsicles out of a total of 16 popsicles in the box), and the probability of another person selecting a grape popsicle from the remaining popsicles is 4/15 (since there are only 4 grape popsicles left out of 15 popsicles after one cherry popsicle has been selected).

The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In this case, the probability of one person randomly picking a cherry popsicle is 4/16 because there are 4 cherry popsicles in the box out of a total of 16 popsicles. After one cherry popsicle has been selected, there are only 15 popsicles left in the box, of which 4 are grape popsicles. Therefore, the probability of another person selecting a grape popsicle from the remaining popsicles is 4/15.

To find the overall probability of both events happening (one person picking a cherry popsicle and another person picking a grape popsicle), we multiply the two probabilities together:

(4/16) x (4/15) = 1/15

Therefore, the probability of one person randomly picking a cherry popsicle and another person selecting a grape popsicle from the box is 1/15.

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To divide the polynomial p(x) by d(x), we can use long division or synthetic division. Let's say we choose to use long division.

First, we need to write the polynomials in descending order of degree, with any missing terms filled in with zeros. Let's say the polynomials are:

p(x) = 3x^3 - 5x^2 + 2x + 4
d(x) = x - 2

Then, we set up the long division like this:

         3x^2 + x + 4
   x - 2 | 3x^3 - 5x^2 + 2x + 4

We divide the first term of p(x) by the first term of d(x), which gives us 3x^2. We write this above the division bar and multiply it by d(x), which gives us 3x^3 - 6x^2. We subtract this from p(x), bringing down the next term:

         3x^2 + x + 4
   x - 2 | 3x^3 - 5x^2 + 2x + 4
         - 3x^3 + 6x^2
             ----------
              -11x^2 + 2x

We repeat the process with the next term, dividing -11x^2 by x to get -11x, writing this above the division bar, and multiplying it by d(x) to get -11x + 22. We subtract this from -11x^2 + 2x, bringing down the next term:

         3x^2 + x + 4 - 11/(x-2)
   x - 2 | 3x^3 - 5x^2 + 2x + 4
         - 3x^3 + 6x^2
             ----------
              -11x^2 + 2x
              + 11x^2 - 22
              ----------
                     -20

Since we have no more terms to bring down, our remainder is -20. Therefore, the quotient p(x)/d(x) is:

p(x)/d(x) = 3x^2 + x + 4 - 11/(x-2) - 20/(x-2)^2

We can express this in the form p(x) d(x) by multiplying both sides by d(x):

p(x) = d(x) (3x^2 + x + 4 - 11/(x-2) - 20/(x-2)^2)
To answer your question, we'll first need the specific polynomials for p(x) and d(x) that you'd like to divide. However, I can still guide you through the general steps to perform the division and express the quotient.

1. Choose either synthetic or long division, depending on your preference and the complexity of the polynomials.
2. Divide p(x) by d(x) using the chosen method. Make sure to follow the steps of the division process carefully to obtain the correct quotient and remainder.
3. Once the division is complete, express the quotient p(x)/d(x) in the form p(x) = d(x) * q(x) + r(x), where q(x) is the quotient and r(x) is the remainder.

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There is not enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 13 years.

What is the mean and standard deviation?

The standard deviation is a summary measure of the differences of each observation from the mean. If the differences themselves were added up, the positive would exactly balance the negative and so their sum would be zero. Consequently, the squares of the differences are added.

To find the standardized test statistic (Z-score), we need to first calculate the sample mean and standard error of the mean.

Sample mean:

x = (17.8 + 21.1 + 19.7 + 9.5 + 18.5 + 13.2 + 13.6 + 10.7 + 19.1 + 7.5 + 11.3 + 7.6 + 21.8 + 9.2 + 21.6 + 9.8 + 19.3 + 21.9 + 22.6 + 15.5 + 12.4 + 9.5 + 14.9 + 7.7 + 12.9 + 17.6 + 14.1 + 19.4 + 17.1 + 17.3 + 15.4 + 22.5) / 32

x = 15.91875

Standard error of the mean:

SE = σ /√(n)

SE = 6.1 / √(32)

SE = 1.0823

Now we can calculate the Z-score:

Z = (x - μ) / SE

Z = (15.91875 - 13) / 1.0823

Z = 2.5707

we can find that the p-value associated with a Z-score of 2.5707 is approximately 0.0051.

Since the significance level (α) is 0.06, which is larger than the p-value, we fail to reject the null hypothesis.

Therefore, there is not enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 13 years.

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The simplified form of expression [tex]\sqrt[4]{\frac{3}{2x} }[/tex] is  [tex]\frac{\sqrt[4]{24 x^3}}{2x }[/tex]

The correct answer is an option (B)

Consider an expression [tex]\sqrt[4]{\frac{3}{2x} }[/tex]

Multiply the fraction by an expression to form a perfect square in the denominator.

[tex]\sqrt[4]{\frac{3}{2x} }[/tex]

[tex]=\sqrt[4]{\frac{3\times 2^3\times x^3}{2x\times 2^3\times x^3} }[/tex]

We know that the cube of 2 is 8. So, substitute 2³ = 8

[tex]=\sqrt[4]{\frac{3\times 8\times x^3}{2x\times 8\times x^3} }[/tex]

Now, we multiply the monomials.

[tex]=\sqrt[4]{\frac{24\times x^3}{16\times x^4} }[/tex]

We know that the exponent rule [tex](a\times b)^m=a^m\times b^m[/tex]

[tex]=\frac{\sqrt[4]{24\times x^3}}{\sqrt[4]{16\times x^4} }[/tex]

We know that 2⁴ = 16

[tex]=\frac{\sqrt[4]{24\times x^3}}{\sqrt[4]{2^4\times x^4} }\\\\=\frac{\sqrt[4]{24\times x^3}}{\sqrt[4]{2^4}\times \sqrt[4]{x^4} }[/tex]        ............(using the exponent rule [tex](a\times b)^m=a^m\times b^m[/tex])

[tex]=\frac{\sqrt[4]{24\times x^3}}{2x }[/tex]           .......(Simplify the radical expressions)

Here, [tex]\frac{\sqrt[4]{24 x^3}}{2x }[/tex] is the simplified form of expression.

Therefore, the correct answer is an option (B)

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Find the complete question below.

According to the given information, the series Σ(sin(1/n)) diverges.

What is the convergence and divergence of the sequence?

Convergence: A sequence approaches a fixed number as the number of terms increases.

Divergence: A sequence does not approach a fixed number as the number of terms increases.

We have:

aₙ = sin(1/n)

bₙ = 1/n

Note that both aₙ and bₙ are positive for n > 0.

We will use the limit comparison test to determine if the series converges or diverges. To do this, we will compare the given series to a known series whose convergence or divergence is already known. We will choose the series Σ(1/n) as our comparison series since it is a p-series with p = 1, which is known to diverge.

Taking the limit as n approaches infinity of aₙ/bₙ, we get:

lim n→∞ (sin(1/n)/(1/n))

We can evaluate this limit using L'Hopital's rule:

lim n→∞ (cos(1/n) * (-1/n²)) / (-1/n²)

= lim n→∞ cos(1/n)

Since the cosine function is continuous, we can substitute the limit as m = 1/n:

lim m→0 cos(m)

cos(m) is continuous at m=0, and cos(0) = 1, so

lim m→0 cos(m) = 1

Since the limit of aₙ/bₙ is a finite, positive value, we conclude that the series Σaₙ and the series Σbₙ have the same behavior; that is, either they both converge or they both diverge. Since the series Σbₙ diverges, the series Σaₙ also diverges.

Therefore, the series Σ(sin(1/n)) diverges.

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If the alternative hypothesis is that the proportion of items in population 1 is larger than the proportion of items in population 2, then the null hypothesis should be that there is no significant difference in the proportion of items between population 1 and population 2.

Based on the information provided, the null hypothesis should be:

The null hypothesis is that the proportion of items in population 1 is less than or equal to the proportion of items in population 2.

This is denoted as H₀: P₁ ≤ P₂. The alternative hypothesis, as you mentioned, is that the proportion of items in population 1 is larger than the proportion of items in population 2, which is represented as H₁: P₁ > P₂.

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Answer:

-√36

Step-by-step explanation:

The first (approx. 3.567) is obviously irrational, as it continues forever; the decimal values do not end.

The next (√18) is approx. 4.243 and is irrational.

The next (π/3) is irrational because it involves an irrational number, π.

The last (-√36) is -6 and is therefore rational.

To prove that for some n > 0, xi > 0 for all i > n, we can use the fact that (xi) is a sequence that converges to x.

This means that given any ε > 0, there exists an N such that |xi - x| < ε for all i > N.  we can use the fact that (xi) is a sequence that converges to x.

Let's choose ε = x/2. Since x > 0, ε > 0 as well. Then there exists an N such that |xi - x| < ε = x/2 for all i > N. Rearranging this inequality, we get:

x - xi < x/2

xi > x/2

Since xi > x/2 and x > 0, we have shown that for some N > 0, xi > 0 for all i > N.

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Answer: 121/209= 57.89% rounded

Step-by-step explanation:

total golf balls are 209

add red +  yellow balls = 121

121/209= 57.89% rounded

A triangle is a closed figure with three sides, and the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

This is known as the triangle inequality theorem. Using this theorem, we can determine whether the given segments can form a triangle.

In this case, the segments measuring 34 cm, 13 cm, and 38 cm can form a triangle if and only if:

- 34 + 13 > 38
- 34 + 38 > 13
- 13 + 38 > 34

We can simplify these inequalities to:

- 47 > 38
- 72 > 13
- 51 > 34

All of these inequalities are true, so the given segments can form a triangle.

Now, we need to determine how many triangles can be formed using these segments. To do this, we can use the formula:

number of triangles = (n-2)

where n is the number of sides (or segments, in this case). Plugging in n=3, we get:

number of triangles = (3-2) = 1

In conclusion, using the triangle inequality theorem, we determined that the given segments can form a triangle. However, only one triangle can be formed using these segments.

The theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. In this case:

1. 34 cm + 13 cm > 38 cm (47 > 38)
2. 34 cm + 38 cm > 13 cm (72 > 13)
3. 13 cm + 38 cm > 34 cm (51 > 34)

Since all three conditions are satisfied, only one triangle can be formed using these segments.

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For estimating the average number of miles per gallon of gasoline a car,

a)About 68% of possible sample means will be in the range between 24.711 and 25.288.

b) About 95% of possible sample means will be in the range between 24.422 and 25.578.

c) About 99.7% of possible sample means will be in the range between 24.133 and 25.867.

Let's we are interested in estimating average number of miles per gallon of gasoline a car. Firstly, sample size, n = 12

mean = 25 miles per gallon

standard deviation = 1

Shape of distribution is bell-shaped. Using Empirical rule,

Standard error =[tex] \frac{ \sigma}{\sqrt{n}}[/tex]

[tex] = \frac{ 1}{\sqrt{12}}[/tex]

= 0.289

a) The 68% of observed data points will lie inside one standard deviation of the mean, i.e [tex]\mu ± \sigma [/tex]

= 25 ± 0.289

= ( 24.711, 25.288)

b) 95% will fall within two standard deviations,i.e., [tex]\mu ± 2 \sigma [/tex]

= 25 ± 2×0.289

= (24.422, 25.578)

c) 99.7% will occur within three standard deviations.i.e., [tex]\mu ± 3 \sigma [/tex]

= 25 ± 3×0.289

= (24.133, 25.867)

Hence, required value is (24.133, 25.867)

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Complete question:

Suppose that you are interested in estimating the average number of miles per gallon of gasoline your car can get. You calculate the miles per gallon for each of the next twelve times you fill the tank. Suppose that in truth, the values for your car are bell-shaped, with a mean of 25 miles per gallon and a standard deviation of 1. Find the possible sample means you are likely to get based on your sample of twelve observations. Consider the intervals into which 68%, 95%, and almost all of the potential sample means will fall, using the Empirical Rule. (Round all answers to the nearest thousandth.)

a) About 68% of possible sample means will be in the range between ____ and ____ .

b) About 95% of possible sample means will be in the range between ____ and ____ .

c) About 99.7% of possible sample means will be in the range between ____ and ____ .

1. The surface areas of the cones are;

1)  56.52 in²  2) 565.20ft²  3) 235.50 yd² 4) 898.04ft²   5) 942.00yd²

6) 75.36 in²   7) 1306.24yd²   8) 405.04in²  9. 339.12 ft²

2. The volumes of the cones are;

1) 84.78 in³  2). 564.15ft³  3) 4710yd³  4) 2712.96in³  5) 20.93ft³  6) 870.82yd³  7)  7846.86in³

3.  The volume of the cone-shaped Santa hat is 75.36in³.

For the normal cones, we use the formula  πr² + πrl to calculate the surface area.

(3.14 x 25) + (3.14x10x5) =  235.50 yd²

(3.14 x 121) + (3.14x15x11) = 898.04ft²

However, for cones like the ones in 6 and 8, we use a slightly different formula. √H² + r² = L first and then  π x r x (r + L).

For example  6.  H= 4in r=3in

⇒ √(4^2 + 3^2) =5

⇒  3.14 x 3 x (3 + 5) =75.36

To calculate the volume, we use the formula (V) = (1/3) x π x r² x H

For example,  H= 9in   r=3in ⇒

(1/3) x 3.14 x 3² x 9 = 84.78in³

The answers provided are based on the information in the picture;

1. Find the surface area of each cone. Round your answer to two decimal places ( use π = 3.14)

1. L = 7in  r=2in   2. L=11ft  r=9ft   3. L=10yd r=5yd   4. L=15ft  r=11ft

5. L=20yd  r=10yd   6.  L= 4in r=3in   7. L=19yd  r= 13yd   8. H=14in  r= 8in

9. L=12ft  r=6ft

2. Find the volume of each cone. Round to 2 decimal places. ( use π = 3.14).

1. H= 9in   r=3in     2. H= 11ft   r= 7ft     3. H=20yd   r=15yd  4. H=18in  r= 12in 5. H=5ft  r=2ft    6. H=13yd  r=8yd  7. H= 17in  r= 21

3. For Christmas, Lily make paper cones santa hat. If the height and radius of the cone are 8 inches and 3 inches respectively, what is the volume of the hat? ( use π = 3.14)

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The length of IKE is 2x - 12.

A condition on a variable that is true for just one value of the variable is called an equation.

Since KITE is a kite, we know that KT = IT and KE = IE. Let's call the length of these diagonals d. Then we have:

KT + TI = d

KE + EI = d

Substituting in the given values, we get:

x + 6 + 2x = d

2x + IE = d

Solving for d in the first equation, we get:

3x + 6 = d

Substituting this into the second equation, we get:

2x + IE = 3x + 6

Solving for IE, we get:

IE = x + 6

Therefore, IKE is equal to:

IKE = IT - IE

IKE = (d - KT) - (x + 6)

IKE = (3x + 6 - x - 6) - (x + 6)

IKE = 2x - 12

So, the length of IKE is 2x - 12.

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