if instead the same ball is used and the rope is shortened; that is, if rope 3 is half the length of rope 1, what is the tension t1 in the rope compared to the tension t3 in the shorter rope?

The swan will travel 55.15 m during uniform motion before becoming airbone.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 0 m/s

vt = 5.8 m/s

a = 0.305 m/s²

By using the second equation, we can calculate the distance before becoming airbone

vt² = vo² + 2a . s

5.8² = 0² + 2 . 0.305 . s

0.61s = 33.64

s = 55.15 m

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Answer:

the velocity of a ball at highest point is 8.5m/s

Explanation:

: The Freefall Problem

Xue,is standing on the roof of a building. Emily is standing below and tosses a ball straight upwards to Xue. It travels up past

Xue, comes back down and Xue reaches out and catches it. Xue catches the ball 6.0 m above Emily’s hands. The ball was

travelling at 12.0 m/s upwards the moment it left Emily’s hand. We would like to know how much time this trip takes.

1. Represent. Complete part A below. Indicate the y-origin for position measurements and draw a sign convention where

upwards is positive. Label the important events.

2. Represent. Complete part C below. Make sure the two graphs line-up vertically. Draw a single dotted vertical line

through the graphs indicating the moment when the ball is at its highest.

A: Pictorial Representation

Sketch, coordinate system, label givens, conversions, describe events

Event 1:

Event 2:

Event 3:

C: Physics Representation

Motion diagram, motion graphs, key events

The total length of the path traveled by an object is the distance. The change in position, from one event to another is the

displacement. Distance is a scalar quantity and displacement is a vector quantity.

3. Reason. Explain why this in this example it is relatively easy to find the displacement, but harder to find the distance.

4. Reason. The BIG 5 equations are valid for any interval of motion where the acceleration is uniform. Does the ball

accelerate uniformly during events 1 and 3? Explain D: Mathematical Representation

Describe steps, complete equations, substitutions with final statement isThere are multiple ways of solving…one

will require the use of the quadratic formula.

The other way will take additional steps.

x = -b+-under root b^2-4ac/2a

Bring mass up against the axis of rotation. Consequently, a rotating object's overall moment of inertia will decrease due to its mass. The axis and the mass narrows as the mass moves closer together.

A measure of a body's propensity to resist angular acceleration that is calculated by summing the products of each particle's mass and square of its distance from the axis of rotation moment of inertia

A line along which an item rotates is referred to as its axis of rotation (also known as its axis of revolution). That line is typically fictitious in physics and calculus. The distance from the object's outside border to the axis of rotation is known as the radius of rotation.

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Answer: Renewable

Explanation: Hope this helps.

The beat frequency is 3 beats/sec.

Beat frequency(n) can be found by using the following formula:

n=f2-f1, where f2 and f1 are the given frequencies

n= 515-512

n= 3 beats/sec

Therefore the beat frequency when 512 Hz and 512Hz tuning forks are sounded together is 3 beats/sec.

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The tension in a tow rope,

a ) If it is completely horizontal = 850 N

b ) If it is 40° above the horizontal = 1103.9 N

F = m a

F = Net force

m = Mass

a = Acceleration

m = 1700 kg

a = 0.5 m / s²

∑ [tex]F_{x}[/tex] = m a

T = m a

T = 1700 * 0.5

T = 850 N

b ) Assuming the tow rope is 40° above the horizontal,

θ = 40°

Resolving the tension force into its horizontal component,

Tx = T cos θ

∑ [tex]F_{x}[/tex] = m [tex]a_{x}[/tex]

Tx = 1700 * 0.5

T cos 40° = 850

T = 1103.9 N

Therefore, the tension in a tow rope,

a ) If it is completely horizontal = 850 N

b ) If it is 40° above the horizontal = 1103.9 N

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[tex]X=150m/s * 4.518s =677.63m[/tex] far short of the target  it will drop the package.

First we can find the total time in order to reach the ground using the following kinematic formula:

[tex]y_{f} =y_{i}+v_{iy}+ \frac{1}{2} gt^{2}[/tex]

And replacing we have:

[tex]-100 =0+0- \frac{1}{2} (9.8)t^{2}[/tex]

And solving for t we got:

[tex]t=\sqrt{ \frac{2* (-100)}{-9.8} }=4.518 s[/tex]

And now we can find the final distance on the x axis using the formula:

[tex]D = Vxt[/tex]

The velocity on x not changes and is the same plane speed [tex]Vx=150m/s[/tex] , if we replace we got:

[tex]X=150m/s * 4.518s =677.63m[/tex]

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Electrical energy is energy that has to do with forces acting on electrically charged particles and their motion.

The ability of an atom's charged particles to initiate an activity or move an object is known as electrical energy. Electrical energy is produced by the transfer of electrons between atoms. Electrical energy powers your toaster and phone charger every time you plug them into a wall outlet.

Electrical energy is energy that has to do with forces acting on electrically charged particles and their motion.

The capacitance of a capacitor is given by the following formula

C=∑0A/d

And the electric potential energy stored in a capacitor is given by

∪[tex]Q2[/tex]/2AC

Applying these formula to the given variables, the initial potential energy becomes

∪[tex]0[/tex]=[tex]Q2/2=d/[/tex]∑A

If d becomes 2d, then potential energy becomes

∪0=[tex]Q2/2[/tex] 2D/∑A=2∪0

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The speed of the beam of light moving along the shoreline when it is 1 km from p 62.83 km/min revolution.

A revolution is the motion of 1 object around a center or some other object, a forceful overthrow of a government by using the people, or any sudden or grand trade. An example of revolution is the movement of the earth around the solar.

dθ/dt = 3 rev/min

         = 3×2π = 6π rad/min

tanθ = x/3

[tex]\frac{d}{dt}[/tex] tanθ = [tex]\frac{d}{dt}[/tex] (x/3)

sec²θ dθ/dt = 1/3 dx/dt

dx/dt = 3sec²θdθ/dt

At x = 1km; tanθ =x/3 =1/3

sec²θ = 1 + tan²θ = 1+(1/3)²

sec²θ =10/9

dx/dt = 3sec²θ dθ/dt

dx/dt = 3×10/9×6π

dx/dt = 62.83 km/min

Hence, the beam of light along the shoreline when it is 1 km away from point P is 62.83 km/min

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24.46 m/s is the speed of the arrow after passing through the target.

p=mv

Conservation of momentum: m1v1=m2v2

The target has a mometum of -(.3kg)(2.15m/s)

the arrow has a mometum of (.0225kg)(42.0m/s)

After impact the mometum of the target is 0 Ns since its velocity is zero.

After impact the velocity of the arrow can be determined with conservation of momentum calculations.

Δp(arrow)=-Δp(target)

m(arrow)v(arrow)i+m(target)v(target)i=m(arrow)v(arrow)f+m(target)v(target)f

(.0225kg)(42.0m/s)-(.3kg)(2.15m/s)=(.0225kg)vf(arrow)

the final velocity of the arrow should be equal to((.0225kg*42.0m/s)-(.3kg*2.15m/s))/.0225kg

v(arrow) final = 24.46 m/s

       m  is the mass of a body and v is the velocity  of that body, the impulse momentum  can be expressed as  p=m.v

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The total displacement would be 110m.

The total distance is 50 m + 30 m + 30 m = 110 m. The displacement is the shortest route from the starting point. It is solved using vectors.

What is Displacement?
Displacement is a vector quantity which depends on the direction of motion but distance is a scalar quantity which just sums up all the given quantity values. The displacement is simply the difference between the locations of the two markers and is unrelated to the route used to get there. It is a vector quantity that has a direction and magnitude.

Hence, the total displacement if you walk 30m East and 50m North would be 110m.

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Answer:

58.31 meters northeast

Explanation:

The displacement can be modeled into the vector equation of [tex]\displaystyle{\vec s = 30\hat x + 50\hat y}[/tex]. We can find the magnitude of displacement by applying Pythagoras Theorem. Suppose we have a two-dimensional vector equation [tex]\displaystyle{\vec v = a\hat x + b\hat y}[/tex] then the magnitude of vector is [tex]\displaystyle{|\vec v\, | = \sqrt{a^2+b^2}}[/tex].

Therefore, the magnitude of displacement is:

[tex]\displaystyle{|\vec s\, | = \sqrt{30^2+50^2}}\\\\\displaystyle{=\sqrt{900+2500}}\\\\\displaystyle{=\sqrt{3400}}\\\\\displaystyle{\approx 58.31 \ \sf m}[/tex]

Since 30 meters east and 50 meters north form northeast direction then the displacement is 58.31 meters northeast.

Given

Volume of the oxygen gas is

The temperature is

Pressure is

To find

The translational kinetic energy

Explanation

The translational kinetic energy is given by

For ideal gas,

Thus,

Conclusion

The translational kinetic energy is 113.99J

Mechanical energy of the coaster is 100 joules.

We need to know about mechanical energy to solve this problem. Mechanical energy is the sum of the potential energy and kinetic energy of an object. It can be written as

E = KE + PE

where E is mechanical energy, PE is potential energy and KE is kinetic energy.

From the question above, the given parameters are

KE = 50 J

PE = 50 J

By substituting the given parameters, we can calculate mechanical energy

E = KE + PE

E = 50 + 50

E = 100 J

The total energy is 100 joules

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Thermal energy 3. is characterized by the random motion of molecules.

In the field of physics, thermal energy can be described as the internal energy present inside an object or system.

The thermal energy present in the molecules of an object causes the molecules to move randomly. It is the energy that causes random motion in atoms.

If the thermal energy keeps on increasing, the movement of molecules also keeps on increasing.

For example, the molecules in water have lower thermal energy initially due to which they show lesser random motion. As we increase heat, the thermal energy increases causing the random motion to increase and water turns into steam as we keep on increasing the thermal energy.

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The wind velocity at 32 m above the ground is 6.39m/s when the roughness exponent of the surface is 0.23

Given in the problem is

Wind velocity at 13m above the ground v1 =5.2 m/s

Height initially h1 = 13m

height at which wind velocity is to be predicted h2= 32m

surface roughness exponent α = 0.23

Let velocity to be predicted be v2

We know that from the formula

v2= v1*(h2/h1)^α

⇒v2= 5.2 * (32/13)^ 0.23 = 6.39 m/s

Thus the wind velocity at 32m above the ground is 6.39m/s

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Current is dwindling at 0.125 , where v is the voltage in volts, i is the current in amperes, and r is the resistance in ohms

Voltage = Current * Resistance ,

The Ohm's law is given by

V = IR eq. 1

Where V is the voltage across Resistance R and I is the current flowing through the Resistance R

Taking outgrowth of eq. 1 with respect to time t yields

dV/ dt = I * dR/ dt dI/ dt * R

dI/ dt * R = - I * dR/ dt dV/ dt

dI/ dt = (- I * dR/ dt dV/ dt)/ R eq. 2

Now substitute the given values into eq. 2

dI/ dt = (-0.02 *0.04(-0.02)) 300

dI/ dt = (-0.0008-0.02)/ 300

dI/ dt = -0.0208/ 300

Charge will go via the external circuit if the two conditions of an electrical circuit are satisfied. Flow of charge is appertained to as a current. In this case, the word" current" simply means that" charge is moving," indicating that commodity is taking place in the cables. The physical property of current, still, may be measured and quantified. The quantum of charge that moves past a point on a circuit at a given time is called current as a physical volume. The quantum of charge Q travelling through a line's cross section in a given quantum of time, as shown in the illustration below, can be measured to determine the current in a circuit.

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In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies.  The acceleration is  8.

Therefore,

Acceleration = 40/5 = 8

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A) Net horizontal force:
Fx= -35 + 25 + -10N

Net vertical force
Fy= 50 - 35 = 15N

Net force
F^2 = fX^2 +Fy^2
F= 18N

B.) Acceleration of system
a=18/5=3.6m/s^2

C). Equilibriant force must be equal to the net force above
F1= 18N

D.) Acceleration becomes half
a1= a/2 =1.8m/s^2

E.) Equilibrant force also doubles
F" = 2F' = 36N

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A tourist was chased by a moose and run toward her car at a speed of 4.6 m/s. As the tourist reaches her car safely, the maximum possible value of the distance between her and the car was 34.5 m

Formula:

s = v . t

Where:

s = distance

v = velocity

t = time

The tourist reached her car safely means at minimum she had the same time with the moose to reach the car.

Tourist circumstance:

distance = d

v = 4.6 m/s

time to reach the car:

t_tourist = d / 4.6

Moose circumstance:

distance = d + 46.5

v = 10.8

time to reach the car:

t_mouse = (d + 46.5) / 10.8

t_tourist = t_mouse

d / 4.6 = (d + 46.5) / 10.8

(10.8 - 4.6) d = 46.5 × 4.6

6.2 d = 213.9

d = 34.5 m

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The nut distance from the Bullwinkle after uniform motion is 21 m.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, the parameters given are

m = 0.5 kg

s = 15 m

vx = 12 m/s

vo = 0 m/s

a = g = 9.8 m/s²

Find the time taken of the nut for landing

s = vo . t + 1/2 . a . t²

15 = 0 + 1/2 . 9.8 . t²

t² = 3.06

t = 1.75 s

Find the distance of nut in horizontal direction

vx = x / t

12 = x / 1.75

x = 12 . 1.75

x = 21 m

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Answer:

low internal resistance.

Explanation:

A lever has a high efficiency due to the fact that it has low internal resistance. The work it puts out is almost equal to the work it receives, because energy used up by friction is quite small. On the other hand, an a pulley might be relatively inefficient due to a considerably greater amount of internal friction.

Coherent light at this frequency passes through a single slit with an interval width equal to the effect of each of the following changes on the width of the central bright spot on the screen. reduce gap width

Two wave sources are coherent if they have the same frequency and waveform. Interference is an ideal property of waves that allows for fixed interference. The central bright band of the single slit diffraction pattern is generated by constructive interference from all secondary sources.

The width of the center band is inversely proportional to the slot width. Coherence is a fixed ratio between wave phases in a beam of radiation of one frequency. The wavelengths of two rays are coherent when the phase difference is constant. Inconsistent if there are random or changing phase relationships. When two waves are monochromatic and in phase, they are said to be coherent. A coherent source is one that generates those waves. With the help of these waves, you can study the properties of the light path. For this purpose, one beam is transmitted along the intended track, and the other is transmitted to the control test.

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Answer:

It would stretch about 6 inches, but it depends on the metal.

Explanation:

pls mark brainliest with the crown

2. Experiment:

We need to make a circuit to test which of the materials are conductors and insulators.

Build the circuit as shown below.

If the light bulb is on then it is a conductor otherwise it is an insulator.

Keep replacing the material one by one to test all the materials.

The load a speaker provides on an amplifier is referred to as speaker impedance. That is, in fact, the result of speaker impedance.

Speaker impedance is defined as the "resistance" a speaker provides to the current delivered by an amplifier in technical terms.

The resistance is known as impedance because an amp's output current is AC (as opposed to DC, like from a battery), not DC. To be completely technical, impedance is the result of adding any reactance present in an AC circuit to DC resistance.

Just keep in mind that speaker impedance impacts how much current is drawn from the amplifier without getting too technical.

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a) t = 4.08 s

b) Response = 20.39m

c) t = 0.991 and 3.087 seconds.

Initially, the vertical speed was 20 m/s.

(a) how long is the ball in the air?

The ball is tossed upward, rises to its highest point, and then hits the ground again.

Consequently, the end height will be equal to the starting height.

h = h o = Om

Use the equation s= ut + -at.

2764 – An = 14

Put a negative sign for g because the ball is being thrown upwards and g is acting downwards.

Om = t - 0.5 * 9.81 m/s * 20 m/s

0 = 20 *t - 0.5 * 9.81 *t

20 *t=0.5*9.81 *t

20 = 0.5 * 9.81 *t

20 0.5*9.81

Answer (a): t = 4.08 s

(b) what is the greatest height reached by the ball?

Vertical velocity for the ball decreases to zero when it reaches its highest point.

Use the equation 2-u=295

-2ghmas for - u

(20m/s - (Om/s)2) = -2 * 9.81 m/s2 *

02 – 20= -2*9.81 *

-20% = -2 *9.81 *

202 = 2 * 9.81 *  

b) RESPONSE: H = 20.39m

(c) when is the ball 15 m above the ground?

The ball will be 15 meters above the earth on two separate occasions.

1. When climbing

2. When descending

Use the equation s= ut + -at.

2,264 – fn = 4

0.5 * 9.81 m/s * 15m = 20 m/s*t

15 = 20 *t - 0.5 * 9.81 *t

15 = 20t – 4.9057

4.905 – 20t + 15 = 0

Calculator-based quadratic equation solution

(c) t = 0.991 and 3.087 seconds.

Hence the answers are,

a) t = 4.08 s

b) RESPONSE: Hmar = 20.39m

c) t = 0.991 and 3.087 seconds.

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Answer:

R = V^2 sin 2θ / g        range formula

R = 19.5^2 * 1 / 9.80 = 38.8 m

Vx = 19.5 cos 45 = 13.8 m/s       horizontal speed

t = R / Vx = 38.8 / 13.8 = 2.81 sec

v = (55 - 38.8) / 2.81 = 5.76 m/s   (about 12.9 mph)

The reaction force in this situation occur once it hits the ground, and normal force from Earth's surface will push up on the ball with 1.4 N.

The correct answer is option (C)

Newton's third law of motion states that for every action there is equal and opposite reaction.

Mathematically, this law is given as;

Fa = Fb

where;

The force applied by object is equal and opposite the reaction experienced by object B.

When an object placed on the floor, the weight of the object acts downward while the normal reaction of the object acts upwards.

Thus, if you drop a baseball and let it fall, gravity from Earth pulls down on the baseball with 1.4 N of force, the reaction force will occur once it hits the ground, as the normal force from Earth's surface will push up on the ball with 1.4 N.

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The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form. Velocity is essentially a vector quantity. It is the rate of change in distance. The displacement change rate is the issue.

The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity.

V = u + a*t

V = 2 + 0.20 * (2.5*60)

V = 32 m/s

The rate at which the speed and direction of a moving object change over time is known as acceleration. Something is said to be accelerating when it starts to move faster or slower. Motion on a circle accelerates even while the speed is constant because the direction is always changing. Due to the frequent change in direction, motion on a circle accelerates even while the speed is constant.

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If we rearrange the circuit so that the inductor and capacitor were connected in series,the impedance would be  Decreased and the resonant frequency would be unchanged.

What is capacitor ?

Frequency is the rate at which something occurs over a particular period of time or in a given sample.

Sol-An LC circuit is made up of an inductor (L) and a capacitor (C). At the resonance condition of the LC circuit, the inductive reactance XL. becomes equal to the capacitive reactance Xc.

It is defined as-

XL= 2πfL

Xc= 1/2πfC

So when reactances are equal we have-

XL=Xc

2πfL= 1/2πfC

f^2=1/4π^2LC

f=1/2π√LC

The resonance condition is the same for both the parallel and series LC circuit, so the resonance frequency will not change.

The impedance of a parallel LC circuit is:

Z(w)= jL w^2-w^2•/w

In a series LC circuit, when w

, the impedance becomes equal to 0.

Therefore the impedance of a series LC circuit will decrease and the resonant frequency will remain the same.

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