The equilibrium constant of the system is 11.3.
What is the value of Keq?We know that the equilibrium constant shows the extent to which reactants are converted into products.
Now;
2NO2 ⇄ N2O4
[NO2] = 0.500 mol /1 L = 0.500 M
[N2O4] = 0.186 mol /1 L = 0.186 M
The ICE table is;
2NO2 ⇄ N2O4
I 0.5 0
C -2x +x
E 0.5 - 2x 0.186
The concentration of NO2 at equilibrium = 0.5 - 2(0.186) = 0.128
Keq = 0.186/( 0.128)^2
Keq = 11.3
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Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:
CH4 + NH3 + O2 à HCN + H2O
You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer the following questions:
· What is the balanced equation for this reaction?
· Which reagent is limiting? Explain why.
· How many grams of hydrogen cyanide will be formed? Show your work.
Answer:
-----> 2 CH₄ + 2 NH₃ + 3 O₂ -----> 2 HCN + 6 H₂O
-----> CH₄ = Whichever reactant produces the smaller amount of product is the limiting reagent. This is because the limiting reagent runs out before all of the other reactant is completely used. Because CH₄ produces the smaller amount of product, it is the limiting reagent.
-----> 13.5 grams HCN
Explanation:
Part 1:
An equation is balanced when there is an equal amount of each reactant on both sides of the reaction. These amounts can be modified by adding coefficients in front of the molecules.
The unbalanced equation:
CH₄ + NH₃ + O₂ -----> HCN + H₂O
Reactants: 1 carbon, 7 hydrogen, 1 nitrogen, 2 oxygen
Products: 1 carbon, 3 hydrogen, 1 nitrogen, 1 oxygen
The balanced equation:
2 CH₄ + 2 NH₃ + 3 O₂ -----> 2 HCN + 6 H₂O
Reactants: 2 carbon, 14 hydrogen, 2 nitrogen, 6 oxygen
Products: 2 carbon, 14 hydrogen, 2 nitrogen, 6 oxygen
Part 2:
You can determine the limiting reactant by converting each reactant mass (besides O₂) to a product mass. Whichever reactant produces the smaller amount of product is the limiting reagent. This is because the limiting reagent runs out before all of the other reactant is completely used.
Let's convert to HCN because Part 3 also wants to know how much HCN is produced. To find this amount, you need to (1) convert grams reactant to moles reactant (via their molar masses), then (2) convert moles reactant to moles HCN (via the mole-to-mole ratio from equation coefficients), and then (3) convert moles HCN to grams HCN (via its molar mass).
Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)
Molar Mass (CH₄): 16.043 g/mol
Molar Mass (NH₃): 14.009 g/mol + 3(1.008 g/mol)
Molar Mass (NH₃): 17.033 g/mol
Molar Mass (HCN): 1.008 g/mol + 12.011 g/mol + 14.009 g/mol
Molar Mass (HCN): 27.028 g/mol
8 g CH₄ 1 mole 2 moles HCN 27.028 g
-------------- x ---------------- x ---------------------- x ---------------- = 13.5 g HCN
16.034 g 2 moles CH₄ 1 mole
10 g NH₃ 1 mole 2 moles HCN 27.028 g
--------------- x ---------------- x ----------------------- x ---------------- = 15.9 g HCN
17.033 g 2 moles NH₃ 1 mole
Because CH₄ produces the smaller amount of product, it is the limiting reagent. Therefore, the actual amount of HCN produced is 13.5 g.
Which state of matter is being described below? it can be squashed easily, spreads out slowly, has low density,
Answer:
liquid
Explanation:
Gas has very low density but spreads fast. Solid has high density.
The number of π molecular orbitals in a molecule is always equal to the number of ________. a. p orbitals used to construct the π bonds b. hydrogen atoms in the molecule c. π bonds
The number of π molecular orbitals in a molecule is always equal to the number of p orbitals used to construct the π bonds.
An electron's position and wave-like behavior within a molecule are described by a mathematical function called a molecular orbital. Chemical, as well as physical properties like the probability of locating an electron in a particular area, can be determined using this function.
A molecular orbital would be created when two atomic orbitals cross one other along the internuclear axis. A molecular orbital is created when two atomic orbitals cross each other sideways.
Therefore, the number of π molecular orbitals in a molecule is always equal to the number of p orbitals used to construct the π bonds.
Hence, the correct answer will be option (a).
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What is the formula mass of copper(ii) fluoride?
a. 146.10
b. 165.10
c. 101.55
d. 90.00
e. none of the above
The correct option is (c) 101.55.
Copper fluoride (CuF) -Copper(II) Fluoride Dihydrate is slightly soluble in water and has uses in ceramics and in fluxes used for brazing and soldering.Iodide ions are strong reducing agents. Therefore, Copper (II) Iodide reduces to insoluble copper (I) iodide. Thus making CuI2, CuI. CuI is not stable, so it doesn't exist in solution.Copper(II) fluoride is an inorganic compound with the chemical formula CuF2. It is a white crystalline, hygroscopic solid with a rutile-type crystal structure, similar to other fluorides of chemical formulae MF2 (where M is a metal).What is copper fluoride used for?
Copper fluoride is used in ceramics and in fluxes for brazing and soldering. It is only marginally soluble in water. Fluoride compounds have a wide range of uses in modern science and technology, from etching and oil refining to synthetic organic chemistry and the production of medications.Learn more about copper fluoride
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During an experiment, the percent yield of calcium chloride from a reaction was 82.38%. theoretically, the expected amount should have been 105 grams. what was the actual yield from this reaction? caco3 hcl → cacl2 co2 h2o 105.3 grams 101.1 grams 95.6 grams 86.5 grams
The actual theoretically yield from this reaction is 86.5 grams.
What is theoretically yield?
Theoretical yield is the quantity of a product obtained from the complete conversion of the limiting reactant in a chemical reaction. It is the amount of product resulting from a perfect (theoretical) chemical reaction, and thus not the same as the amount you'll actually get from a reaction in the lab.∵ The percentage yield = (actual yield/theoretical yield) * 100.
To calculate the theoretical yield from the balanced reaction:
CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,
It is clear that 1 mole of CaCO₃ reacts with 2 mole of HCl to produce 1 mole of CaCl₂, 1 mole of CO₂, and 1 mole H₂O.
to calculate the no. of moles of 95.0 g CaCO₃
n = mass/molar mass = (95.0 g)/(100.0869 g/mole) = 0.95 mol.
Using cross multiplication:
1 mole of CaCO₃ produce → 1 mole of CaCl₂, from stichiometry.
∴ 0.95 mole of CaCO₃ produce → 0.95 mole of CaCl₂.
∴ The mass of CaCl₂ (theoretical yield) = (no. of moles) * (molar mass) ⇒(0.95 mole)*(110.98 g/mole) = 105.34 g.
∵ The percentage yield = (actual yield/theoretical yield)*100.
The percentage yield = 82.15%, theoretical yield = 105.34 g.
∴ The actual yield of CaCl₂ = (The percentage yield)(theoretical yield)/100
= (82.15%)(105.34 g)/100 = 86.53 g ≅ 86.5 g.
So, the actual theoretically yield from this reaction is 86.5 grams.
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Which reason best explains why both venus' and mars' atmospheres are primarily carbon dioxide, but the earth's is much less than 1arbon dioxide?
Because carbon dioxide dissolves in water and is transported by rain to the surface where it combines with rocks to generate carbonates, the Earth's atmosphere contains significantly less carbon dioxide than Venus's atmosphere.
Why does Earth's atmosphere have so much less carbon dioxide compared to Venus?Since Venus' atmosphere is around 100 times thicker than the earth's and extremely dense. Venus must be sufficiently close to the Sun for the little carbon dioxide in its early atmosphere to have heated the surface and released additional carbon dioxide into the atmosphere. Nitrogen makes up 79% of the atmosphere on Earth, along with oxygen (20%) and a trace amount of other gases including carbon dioxide and water vapor. On Venus and Mars, however, carbon dioxide makes up the majority of the atmosphere.
In Venus's original ocean drained, water vapor molecules were dispersed by ultraviolet light, and hydrogen was released into space. There was no longer any surface water, and the amount of carbon dioxide increased.
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Calculate the kf of ag(nh3)2 from ag (aq) e- ⇋ ag(s) e0= 0. 81 v ag(nh3)2 (aq) e- ⇋ ag(s) 2nh3(aq) e0= 0. 39 v enter number as e notation (e. g. 2. 34e6 or 4. 56e-4)
The kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.
What is kf value?kf value can be calculated by dividing the molal concentration with the freezing point of depression.
The reaction are given:
Ag+(aq) + e- ⇋ Ag(s) E0= 0.81 V
Ag(NH₃)₂ +(aq) + e- ⇋ Ag(s) + 2NH₃(aq) E0= 0.37 V
To get Kf of Ag(NH₃)₂ we will rearrange the above written equations
a. Ag +(aq) + e- ⇋ Ag(s) E0= 0.81 V
b. Ag(s) + 2NH₃(aq) ⇋ Ag(NH₃)₂ +(aq) + e- E0= - 0.37 V
Adding equation (a) and equation (b) we will get
Ag +(aq) + 2NH₃(aq) ⇋ Ag(NH₃)₂ + (aq) Eo = 0.81 -0.37 = 0.44 V
By the Ernst equation,
E = E° - 0.0591 logkf
Now Kf is calculated at equilibrium and at equilibrium E = 0,
The number of transfer of electron is 1 ( 1 e-) , n=1
E° = 0.44 V
Substituting all the values in Ernst equation
0 - 0.44 - 0.0591/ 1 logkf
logkf = 0.44/ 0.0591
kf = 10 (0.44/ 0.0591)
Kf = 2.786 x 10⁷
Hence, Kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.
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Benzoic acid is a common food preservative. the pka of benzoic acid is 4. 20. what is true of the relative strengths of benzoic acid (ba) and its conjugate base (b-)?
Here BA is benzoic acid and B- is conjugate base;
BA is weaker than B- because the Ka < Kb
--> BA is stronger than B- because the Ka > Kb
BA is stronger than B- because the Ka < Kb
BA is weaker than B- because the Ka > Kb
A conjugate acid-base pair, according to the Brnsted-Lowry definition of acids and bases, consists of two substances that are distinct only in that they contain a proton (H+). When a proton is supplied to a base, a conjugate acid is created, and vice versa when a proton is taken away from an acid, a conjugate base is created. Yuki Jung was the creator.
The power of an acid (or base) is inversely proportional to the power of its conjugate base (or conjugate acid): The conjugate base of an acid is weaker the stronger it is. The conjugate base of a weaker acid has a stronger base. A pair of chemical species known as conjugate acid and conjugate base exhibit opposing chemical behaviors.
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When nahco3 completely decomposes, it can follow this balanced chemical equation: 2nahco3 → na2co3 h2co3 determine the theoretical yields of each product using stoichiometry if the mass of the nahco3 sample is 3.80 grams. (show work for both) in an actual decomposition of nahco3, the mass of one of the products was measured to be 2.36 grams. identify which product this could be and justify your reasoning. calculate the percent yield of the product identified in part b. (show your work)
Theoretical yield = 2.397
The product could be sodium carbonate
percent yield = 98.456%
When nahco3 completely decomposes, it can follow this balanced chemical equation:
2nahco3 → na2co3 h2co3
If the mass of the NaHCO3 sample is 3.80 g, we must use stoichiometry to calculate the theoretical yields of each of the products.
mass of NaHCO₃ = 3.80 g
molar mass of NaHCO₃ = 84 g/mol
so the no of moles of NaHCO₃ = 3.80/84 = 0.0452 mol
You see, one mole of sodium carbonate and one mole of hydrogen carbonate are produced from two moles of sodium bicarbonate.
so, the no of moles of sodium carbonate = 0.0452/2 = 0.0226 mol
∴ mass of sodium carbonate ( Na₂CO₃) = no of moles of Na₂CO₃ × molar mass of Na₂CO₃
= 0.0226 × 106 ≈ 2.397 g
no of moles of hydrogen carbonate = 0.0452/2 = 0.0226 mol
mass of the hydrogen carbonate ( H₂CO₃) = no of moles of H₂CO₃ × molar mass of H₂CO₃
= 0.0226 × 62 g = 1.401 g
mass of one of the products was measured to be 2.36 g , from above data, we can say it must be sodium carbonate because value is the nearest of 2.397 g.
percentage yield = experimental yield/theoretical yield × 100
here experimental yield of Na₂CO₃ = 2.36 g
and theoretical yield of Na₂CO₃ = 2.397 g
∴ % yield = 2.36/2.397 × 100 ≈ 98.456%
Therefore the percentage yield of the product is 98.456%
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THEIR ANSWER IS RIGTH, ALL THREE PARTS
Theoretical yeild is 2.397, sodium bicarbonate is the possible product I chose, and percent yeild is 98.456
In what ways would adding the nabh4 too early would interfere with your reaction?
NaBH4 is blind + will reduce other functional groups.
Functional groups:
The aldehyde group in o-vanillin would be converted to alcohol if it had been added during step one (imine production). Because the carbon is not sufficiently nucleophilic, p-toluidine would not attack and imine would not form in the maximum yield.
Regardless of the other atoms in the molecule, a functional group is a collection of atoms that have specific chemical characteristics. Covalent bonds bind the atoms in a functional group to the other molecules in the molecule as well as to one another. Examples: Alcohol, Aldehyde, Ketone, Carboxylic acid, Halogens, Double & Triple covalent bonds.
A carbonyl in which the carbon atom is linked to at least one hydrogen atom is called an aldehyde. An R-group or a hydrogen atom could be the other group joined to the carbonyl. Aldehydes are a highly reactive form of carbonyl because of the tiny size of the hydrogen atom, which makes it relatively simple for other molecules to approach the partial positive charge on the carbonyl carbon. Aldehydes are adaptable reactants used in numerous different organic synthesis processes. Numerous aldehydes also have unique tastes and odors.
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What are the hybridization states of the carbon atoms involved in the conversion of trans to cis retinal?
The hybridization states of the carbon atoms involved in the conversion of trans to cis retinal is sp2.
What is Hybridization?
In the process of hybridization, the orbitals of different elements come together to create new orbitals for the atoms. The only characteristics that distinguish the new orbitals from the old orbitals are their energy and shape. It is used to learn about the various bond types, bond lengths, and bond energies that an element may produce.Cis to trans conversion takes place between the double-bonded carbons. Tetrahedral carbons in a single bond are designated as sp3, trigonal planar carbons in a double bond are designated as sp2, and linear carbons are designated as sp.Learn more about the Hybridization of carbon with the help of the given link:
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Please help,
How could you tell a Ca(NO3)2 solution from a Zn(NO3)2 solution?
Answer:
you better give me brainliest
Explanation:
Zinc nitrate and calcium nitrate solution can be distinguished by reaction with ammonium hydroxide. Zinc forms a white gelatinous ppt. whereas there is no precipitation of calcium hydroxide even with excess of ammonium hydroxide
A student sets up the following equation to convert a measurement.
(The ? stands for a number the student is going to calculate.)
Fill in the missing part of this equation.
Note: your answer should be in the form of one or more fractions multiplied together.
Answer:
[tex]\frac{1,000 g}{1 kg}[/tex] · [tex]\frac{100 cm}{1 m}[/tex]Explanation:
The final answer has a different set of units. In particular, kilograms (kg) changes to grams (g) and meters (m) changes to centimeters (cm). To make this change, you need to multiply the first value by proportions.
When writing these proportions, it is important that they are arranged in a way that allows for the cancellation of units. For instance, since both kg and m are located in the numerator, they must be located in the denominators of the conversions.
Proportions:
1 kg = 1,000 g
1 m = 100 cm
The full expression:
[tex]-4.3*10^4 \frac{kg*m}{s}[/tex] · [tex]\frac{1,000 g}{1 kg}[/tex] · [tex]\frac{100 cm}{1 m}[/tex] = [tex]?\frac{g*cm}{s}[/tex] ^ ^As you can see, the old units cancel out and you are left with g and cm in the numerator.
Nh4cl is sometimes preferred instead of hcl or h2so4 for "acid" work-up after grignard reactions, particularly when the expected and desired product is a tertiary alcohol. Why?
Nh4cl is sometimes preferred instead of hcl or h2so4 for "acid" work-up after grignard reactions, particularly when the expected and desired product is a tertiary alcohol because NH4+ is a much milder acid than HCl or H2SO4, which achieve the protonation of
the oxyanion to yield the alcohol while minimizing the risk of dehydration.
Ammonium chloride (NH4Cl) is the used as reagent that quenches the magnesium alkoxide product of the Grignard addition.
It is a proton source without being acidic as in acidic medium the protonation of the tertiary alcohol product and elimination to the alkene.
In the presence of HCl or any other strong acid protonation proceed and form alkene but not with ammonium chloride.
Thus from above we concluded that Nh4cl is preferred instead of hcl or h2so4 for "acid" work-up after grignard reactions.
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A pharmaceutical company wants to test the efficiency of its new drug production techniques so they run 3 shifts of production for 4 hours each and collect the product at the end of each shift. Their chemical engineers predict a maximum of 7000 grams of product can be created each shift. Shift one produces 4562 grams. Shift two produces 5783 grams. Shift three produces 5247 grams. What is the average percent yield for this new production technique?
The percentage yield of the new production technique is 82.8%
What is the percentage yield?Production is the procedure by which finished products are obtained form the raw materials. The production process involves the passing of raw materials through a certain procedure that involves the use of certain machines and equipment to give us the required products.
We are told in the question that there are three shifts;
Shift 1 produces 4562 grams
Shift 2 produces 5783 grams
Shift 3 produces 5247 grams
Average production from the three shifts = 4562 grams + 5783 grams + 5247 grams/3 = 5197 grams
The theoretical average yield is = 7000 grams + 7000 grams + 7000 grams/3 = 7000 grams
Now the percentage yield = actual yield/ theoretical yield * 100/1
percentage yield = 5197 grams/7000 grams * 100/1
percentage yield = 82.8%
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Calculate the ph at the equivalence point for the titration of 0. 22 m hcn with 0. 22 m naoh. (ka = 4. 9 × 10^–10 for HCN).
The pH at the equivalence point for the titration of 0. 22 m HCN with 0. 22 m NaOH is 11.17
Calculation,
Concentration of NaCN = 0. 22 m/ 2 = 0.11 M ( at equal volumes of acid and base will be used).
The equilibrium is ,
HCN +[tex]H_{2} O[/tex] → [tex]H^{+} + CN^{-}[/tex]
C(1-x) Cx Cx
Where x , is the degree of hydrolysis and
[tex]K_{h}[/tex] = C[tex]x^{2}[/tex]/(1-x)
We know that [tex]K_{h}[/tex] = [tex]K_{w}/K_{a}[/tex] = 1 ×[tex]10^{-14}[/tex]/4. 9 ×[tex]10^{-10}[/tex] = 2.04×[tex]10^{-5}[/tex]
[tex]K_{h}[/tex] = C[tex]x^{2}[/tex] = 2.04×[tex]10^{-5}[/tex] = 0.11 M×[tex]x^{2}[/tex]
[tex]x^{2}[/tex] = 2.04×[tex]10^{-5}[/tex]/0.11 M
x = 1.36×[tex]10^{-2}[/tex]
[tex][OH^{-} ][/tex] = Cx = 1.36×[tex]10^{-2}[/tex] × 0.11 M = 0.15×[tex]10^{-2}[/tex]
[tex][H^{+} ][/tex] = 1 ×[tex]10^{-14}[/tex]/ 0.15×[tex]10^{-2}[/tex] = 6.66×[tex]10^{-12}[/tex]
pH = -㏒[tex][H^{+} ][/tex] = -㏒6.66×[tex]10^{-12}[/tex] = 11.17
The pH at the equivalence point for the titration is 11.17.
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Which combination of properties would be expected to lead to the most viscous liquid?
The combination of properties would be expected to lead to the most viscous liquid include:
Low temperatureStrong intermolecular forceWhat is Viscosity?This is defined as the resistance of a liquid to flow and is characterized by its sticky nature.
This is as a result of the strong intermolecular forces which holds the atoms together and low temperature keeps them in shape thereby making it the most appropriate c hoice.
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Aluminum sulfate reacts with barium iodide to produce aluminum iodide and barium sulfate
Al₂(SO₄)₃ + 3BaI₂ → 2AlI₃ + 3BaSO₄
At 2525 °c, what is the hydroxide ion concentration, [oh−][oh−] , in an aqueous solution with a hydrogen ion concentration of [h ]=1. 5×10−6[h ]=1. 5×10−6 m?
The hydroxide ion concentration [OH-] in an aqueous solution is 6.66 x 10⁻⁹ M
Experimental measurements of the pKw of water at 25ºC yielded a result of 14.0. The same method used to determine the pKa of all other water-soluble compounds that can function as acids in aqueous solution can also be used to determine this value from the examination of thermodynamic or electrochemical data for these aqueous solutions.
Water has a pkw=14
So it can be represented as,
[H+] [OH-] = 1×10^-14
Given [H+] = 1. 5×10^−6
So, [OH-] = (1*10^-14) / ( 1.5*10^-6)
= 6.66 x 10⁻⁹ M
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There are TWO isotopes of chlorine. Under normal conditions, chlorine exists as diatomic molecule, Cl₂. The mass of the Cl₂ molecule is the sum of masses of the two atoms in the molecule. The mass spectrum of Cl₂ has three peaks, as shown below. From this data, what is the mass of the heavier isotope of chlorine (in amu)?
Peak 1- 69.938 amu
Peak 2- 71.935 amu
Peak 3- 73.932 amu
The the mass of the heavier isotope of chlorine (in amu) is 73.932 amu.
What are isotopes?The term isotopes refers atoms that have the same atomic number but different mass number. We must know that all these atoms belong to the same element an differ only in the number of neutrons present in the atom of the element. Hence isotopes are different atoms of the same element hence they have the same chemical properties or reactivity. The mass spectrum is able to show the masses of each of the isotopes according to their order of relative abundance in nature.
Looking at the peaks, we know that the heaviest isotope is the one whose mass will have the highest peak as shown in the mass spectrum of the element as shown. Thus, the the mass of the heavier isotope of chlorine (in amu) is 73.932 amu. The mass spectrum of element also shows this fact.
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Assuming an experimental value of enthalpy of –655 kj/mol and a true value of –603, what is the percent error of the experiment? use a calculator and round to the nearest hundredth as well as the absolute value of the percentage. %
8.62%
8.62% is the percent error of the experiment.
Rounding to the nearest hundredth value will be 8.620.
Determine the difference between the figures provided and divide by the actual value to find the percent error.(-655 - -603)/(-603) = 0.0862
Multiply by 100%,
(0.0862) x 100% = 8.62%
What is percent error?The percent error is the difference between the estimated value and the actual value in relation to the actual value.
What does percent error enable us to establish?Error margins are easily understood when expressed as a percentage. It reveals the size of the inaccuracy. A 3-percent error value, for example, indicates that your measured number is quite near to the true amount. A 50% margin, however, indicates that your measurement is far from the true number.The significance of percentage errorWhen you measure something in an experiment, the percentage of mistakes indicates the size of your errors. Greater proximity to the accepted or genuine value is indicated by smaller values.To learn more about percent error visit:
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How many electrons are present in the nonbonding π molecular orbital of the allyl anion? a. 2 b. 1 c. 3 d. 0
The number of electrons, which are present in the nonbonding π molecular orbital of the allyl anion is "0".
Anions, cations, but also allylic radicals have always been frequently mentioned as reaction intermediates. Each one has three adjacent [tex]sp^{2}[/tex]-hybridized carbon centers, and they all rely on resonance for stability. Two resonance structures would be used to present each species, with the charge as well as unpaired electron scattered across both the 1,3 and 0 positions.
The Aufbau principle states that these orbitals would fill up based on the order of stability, therefore a typical pi bond, will have 2 electrons in the Pi orbital as well as zero in the Pi* orbital.
Therefore, the correct answer will be option (d)
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The oxygen consumption rate of a 200 kg seal is 10 ml/(g h). assuming that it has oxygen stores of 2 liters, how many minutes can it dive before running completely out of oxygen?
The oxygen consumption rate of a 200 kg seal is 10 ml/(g h). If it has oxygen stores of 2 liters, then minutes can it dive before running completely out of oxygen is 0.06min.
What is meant by oxygen consumption?Oxygen is one of the most vital element of the organism which is required by almost all the cellular and for all metabolic activities to perform body function.
It is consumed by the respiratory system and passed ro each cell by circulatory system of the body.
Given,
Mass of seal = 200kg = 200000 g
Rate of oxygen consumption = 10 ml/gh
The volume of stored O2 = 2000mL
The time of consumption is calculated as
t = V/mr
t = 2000/200000×10
t = 0.001 hrs
In minutes
t = 0.06min.
Thus 0.06min is required to dive out the oxygen stores of 2 litre.
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What is the percent by volume of ethanol in gasohol when 95 ml of ethanol is added to sufficient gasoline to make 1.0 l of gasohol?
The percentage of volume of ethanol is 9.5%.
What is volume by volume percentage?Volume/volume percentage (v/v% or percent v/v) is a unit used to express how much of a material is present in a solution. It is defined as the volume of the solute divided by the sum of the volumes of the solution, multiplied by one hundred. Examples: The average alcohol concentration (v/v%) of wine is 12 percent.
The formula used to get the volume of ethanol in percentages is
Percent of volume of ethanol = (volume of solute / total volume) * 100
Percent volume of Ethanol = (volume of ethanol / total volume) * 100
= 95mL / 1000mL * 100
= 9.5%
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Student e accounted for the equivalent weight found for succinic acid by analyzing its titration with naoh(aq) and concluding that it is:________
Student e accounted for the equivalent weight found for succinic acid by analyzing its titration with [tex]NaOH[/tex] (aq) and concluding that it is diprotic.
One mole of succinic acid required two mole of base to neutralize completely. In this titration phenolphthalein indicator is used to observe the completion of the reaction. In an aqueous solution, succinic acid readily ionize to form succenate. Succinic acid undergoes two successive deprotonation reaction.
The succinic acid results in succinate ( dicarboxylic acid dianion ) which is form by removal of a proton from both carboxy groups of succinic acid.
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In addition to the use of complex metal hydrides, what other reaction can be used to reduce aldehydes and ketones to alcohols?
The reaction with H₂ & Raney Ni (Catalytic Hydrogenation) can be used to reduce aldehydes and ketones to alcohols.
What is Aldehyde ?An Aldehyde is a functional group which contains the carbonyl group that is -C = O. The structural formula for aldehyde is RCHO.
Reaction of Aldehyde with H₂ & Raney Ni gives Primary alcohol
RCHO + H₂ & Raney Ni → RCH₂OH
What is Ketone ?A Ketone is a functional group which contains the carbonyl group that is -C = O. The structural formula for ketone is RCOR.
Reaction of Ketone with H₂ & Raney Ni gives Secondary alcohol
RCOR + H₂ & Raney Ni → RCH(OH)R
Thus from the above conclusion we can say that The reaction with H₂ , Raney Ni can be used to reduce aldehydes and ketones to alcohols.
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Please help.. I'm Giving Brainliest :)
Answer:
i think its -91.6
Explanation:
2 ( - 950.8) - (( - 1130.7) + ( - 393.5) + ( - 285.8))
The standard enthalpy change for the given reaction is approximately 91.9 kJ mol⁻¹.
The heat produced during a chemical reaction under specific conditions is known as the standard enthalpy change, abbreviated as H° (zero delta H). Standard conditions often refer to all reactants and products in their standard states, which are their most stable forms at 298 K and 1 bar (or 1 atm) pressure.
Hess's law, which states that the total enthalpy change of a reaction is equal to the sum of the enthalpy changes of its component phases, is used to calculate the standard enthalpy change of the reaction.
The following reaction is given:
[tex]\rm 2 NaHCO_3(s)--- > Na_2CO_3(s)+ CO_2(g) + H_2O(l)[/tex]
The relevant enthalpy changes of formation are:
ΔH°[NaHCO3(s)] = -950.8 kJ mol⁻¹
ΔH°[Na2CO3(s)] = -1130.7 kJ mol⁻¹
ΔH°[CO2(g)] = -393.5 kJ mol⁻¹
ΔH°[H2O(l)] = -285.8 kJ mol⁻¹
By using Hess's Law, the standard enthalpy change (ΔH°) for the reaction can be calculated as follows:
ΔH° = Σ (products) - Σ (reactants)
ΔH° = [ΔH°[[tex]\rm Na_2CO_3[/tex](s)] + ΔH°[[tex]\rm CO_2[/tex](g)] + ΔH°[H2O(l)]] - [2 × ΔH°[[tex]\rm NaHCO_3[/tex](s)]]
ΔH° = [-1130.7 kJ mol⁻¹ + (-393.5 kJ mol⁻¹) + (-285.8 kJ mol⁻¹)] - [2 × (-950.8 kJ mol⁻¹)]
ΔH° = [-1809.7 kJ mol⁻¹] - [-1901.6 kJ mol⁻¹]
ΔH° ≈ -1809.7 kJ mol⁻¹ + 1901.6 kJ mol⁻¹
ΔH° ≈ 91.9 kJ mol⁻¹
Hence, the standard enthalpy change for the given reaction is approximately 91.9 kJ mol⁻¹.
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What is the mass of 4. 00 moles of helium, the gas commonly used to fill party balloons and lighter-than-air ships?
Write out a balanced reaction equation for the reaction of hydronium ions (H3O+) with calcium carbonate
Balanced chemical equation for reaction of hydronium ions with calcium carbonate will be as follows:
2H3O+ (aq) + CaCO3 (s) => Ca2+ (s) + 3H2O (l) + CO2 (g)
In this balanced chemical equation, acidic aqueous solution of hydronium ion (H3O+) reacts with calcium carbonate salt (CaCO3) resulting in the formation of calcium cation (Ca2+) an alkali, that results in neutralization of excessive acid. It also forms liquid water (H2O) along with liberation of carbon dioxide gas (CO2). All acids stronger than hydrogen carbonate, provide their calcium salts dissolved in water yielding carbon dioxide, because a bare hydrogen ion has no chance of surviving in water.
To balance this chemical equation, 2 molecules of hydronium ions react with 1 molecule of calcium carbonate resulting in formation of 1 molecule of calcium cation, 3 molecules of water and 1 molecule of carbon dioxide. The reaction proceeds at room temperature.
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What mass of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
91.4 grams
91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
C = mol/volume
2.45M=mol/0.5L
2.45M⋅0.5L = mol
mol = 1.225
Convert no. of moles to grams using the atomic mass of K + Cl
1.225mol * [tex]\frac{39.1+35.5}{mol}[/tex]
mol=1.225
=1.225 mol . [tex]\frac{74.6g}{mol}[/tex]
=1.225 . 74.6
=91.4g
therefore, 91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
What is 1 molar solution?
In order to create a 1 molar (M) solution, 1.0 Gram Molecular Weight of the chemical must be dissolved in 1 liter of water.
58.44 g make up a 1M solution of NaCl.
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