If the 5th term in a geometric sequence is 162, and the common ratio is 3. What is the first term in the sequence?

Answer:

Step-by-step explanation:

1) nth therm = dn + (a - d)

-10n + (11+10)

-10n + 21

t11 = -110 + 21 = -89

2) nth therm = 3n + (-66 - 3)

3n - 69

t16 = 48 - 69 = -21

Answer:

x > 23/5

Step-by-step explanation:

2x+ 3(x+2)>17

2x + 3x + 6 >17

5x >23

x > 23/5

Given:

Total number of gym members = 685

257 said they use the treadmill, 157 said they use the elliptical, and 85 said they use both.

To find:

a. The venn diagram.

b. The probability that a member uses the treadmill only?

Solution:

(a)

We have,

Total number of gym members = 685

Treadmill user = 257

Elliptical user = 157

Who use both = 85

Only treadmill user is:

[tex]257-85=172[/tex]

Only Elliptical used

[tex]157-85=72[/tex]

Therefore, the venn diagram for the given situation is shown below.

(b)

The member who use treadmill only = 172

Total user = 685

The probability that a member uses the treadmill only is:

[tex]P(\text{Only treadmill})=\dfrac{\text{Only treadmill users}}{\text{Total users}}[/tex]

[tex]P(\text{Only treadmill})=\dfrac{172}{685}[/tex]

Therefore, the probability that a member uses the treadmill only is [tex]\dfrac{172}{685}[/tex].

Answer:

3x - y +5=0

Step-by-step explanation:

Slope:-

=> m = 2-8/-1-1 = -6/-2

=> m = 3

Using point slope form :-

=> y - 2 = 3 ( x - (-1))

=> y - 2 = 3x + 3

=> 3x - y +5 = 0

Answer:

y=3x+5

Step-by-step explanation:

first find the gradient

m=y2-y1/x2-x1

from the coordinates you are given x one is -1,x two is1,y one is 2,y two is 8

8-2/1-(-1)

=3

therefore the gradient is 3

after finding the gradient use the equation

y-y1=m(x-x1)

substitute x1,y1 and the gradient..y and x are constant

y-2=3(x-(-1))

y-2=3x+3

y=3x+3+2

y=3x+5

Answer:

1/9

You are being asked to "complete the square"

you need to find a value to make the quadratic a "perfect square:

the focus is -2/3 you need to "add" one half of -2/3 squared to the

equation (1/2 * -2/3)^2 .... (-2/6)^2 .... 4/36 .... 1/9

Step-by-step explanation:

Answer:

Let's define the high temperature as T.

We know that:

"four times T, was more than 2*T plus 66°C"

(i assume that the temperature is in °C)

We can write this inequality as:

4*T > 2*T + 66°C

Now we just need to solve this for T.

subtracting 2*T in both sides, we get:

4*T - 2*T > 2*T + 66°C - 2*T

2*T > 66°C

Now we can divide both sides by 2:

2*T/2 > 66°C/2

T > 33°C

So T was larger than 33°C

Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.

Then the range of possible temperatures is:

(33°C, ...)

Where we do not have an upper limit, so we could write this as:

(33°C, ∞°C)

(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)

Answer:

[tex]x\approx 49.6^{\circ}[/tex]

Step-by-step explanation:

In any right triangle, the tangent of an angle is equal to its opposite side divided by its adjacent side.

For angle [tex]x[/tex]:

Therefore, we have:

[tex]\tan x^{\circ}=\frac{40}{34}[/tex]

Take the inverse tangent of both sides to solve for [tex]x[/tex]:

[tex]\tan^{-1}(\tan x)=\tan^{-1}(\frac{40}{34}),\\x=\tan^{-1}(\frac{40}{34}),\\x=49.63546343\approx \boxed{49.6^{\circ}}[/tex]

*Recall [tex]\tan^{-1}(\tan x)=x\text{ for } x\in (-90^{\circ}, 90^{\circ})[/tex]

Answer:

This is the expression:

4*x+4*9

Answer:

A≈102.79

Step-by-step explanation:

The formula for area of a circle is πr² so we need to substitute the r by 5.72.

π×5.7² = 102.79 m²

Answer:

Approximately 102.79 meters squared

Step-by-step explanation:

pi times 5.72 meters squared

Hope this helps!

Answer:

A ; 21

Step-by-step explanation:

Here, the side facing the right angle is the hypotenuse and it has a measure of length 42

The side facing the missing angle is the opposite and it has a length of 15

The trigonometric ratio that connects the hypotenuse and the opposite is the sine

The sine of an angle is the ratio of the opposite to the hypotenuse

Thus;

sine ? = 15/42

sine ? = 0.357

? = arc•sim 0.357

? = 21 degrees

Answer:

A. 4x² + 9x/4 - 7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

f(x) = x/4 - 3

g(x) = 4x² + 2x - 4

(f + g)(x) is f(x) + g(x)

Step 2: Find

Answer:

10-5=5 answer is 8^5

Step-by-step explanation:

Answer:

[tex]8^{5}[/tex]

Step-by-step explanation:

[tex]\frac{8^{10} }{8^{5} }[/tex]

Where are there more 8's ?

top

How many more?

5

Then they stay on top of fraction.

Another way :

[tex]x^{a}[/tex] ÷ [tex]x^{b}[/tex] = [tex]x^{a-b}[/tex]

[tex]8^{10}[/tex]  ÷ [tex]8^{5}[/tex] = [tex]8^{10-5}[/tex] = [tex]8^{5}[/tex]

[tex]\color{red}{==========================}[/tex]

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✍︎ꕥᴄᴀʀʀʏᴏɴʟᴇᴀʀɴɪɴɢꕥ

Answer:

17311, 17315  

Step-by-step explanation:

Explanation,

List Of CPT Codes For Mohs Surgery

CPT Code 17311 and CPT Code 17313 are the base codes for the range of this surgery. CPT Code 17312, CPT Code 17314, and CPT Code 17315 are the add-on codes for this range.

Description Of CPT Code 17311

Description Of CPT Code 17315 (addon)

CPT Code 17315 may be used to report each block after the first 5 blocks for any single-stage.

Extras

Description Of CPT Code 17312 (addon)

Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure)

Description of CPT Code 17313

Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), of the trunk, arms, or legs; first stage, up to 5 tissue blocks

Description Of CPT Code 17314 (addon)

Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure).

Answer:

4(x - [tex]\frac{1}{2}[/tex] )² = 0

Step-by-step explanation:

Given

4x² - 4x + 1 = 0 ( factor out 4 from the first 2 terms )

4(x² - x) + 1 = 0

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² - x

4(x² + 2(- [tex]\frac{1}{2}[/tex] )x + [tex]\frac{1}{4}[/tex] - [tex]\frac{1}{4}[/tex] ) + 1 = 0

4(x - [tex]\frac{1}{2}[/tex] )² - 1 + 1 = 0

4(x - [tex]\frac{1}{2}[/tex] )² = 0

Answfirst one

Step-by-step explanation:

hope it helps thank u

Answer:

first one

Step-by-step explanation:

2 students have the same age but different heights.

since age is the input and height is the output. in order to be a function one must have exact one output for one input.

since the heights of students in Tessa 's class are not a function of their ages (one input must have two outputs) two students of same age must have different heights.

Answer:

4 pounds

Step-by-step explanation:

take 20% off the original price. 20(0.20)= 4

So that's a discount of 4 pounds and the sale price is 16 pounds.

The savings is 4 pounds on 1 shirt.

Answer:

y=[tex]\frac{-3x}{2}[/tex]

Step-by-step explanation:

Hi there!

We need to find the equation of the line that passes through the origin (the point (0,0)) and (-2,3)

There are 3 ways to write the equation of the line, although the most common way is slope-intercept form.

Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

So we need to find the slope of the line first

The formula for the slope (m) calculated from two points [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] where ([tex]x_{1}[/tex],[tex]y_{1}[/tex]) and ([tex]x_{2}[/tex], [tex]y_{2}[/tex]) are points

We have the needed information to calculate the slope, but let's label the values of the points to avoid any confusion

[tex]x_{1}[/tex]=0

[tex]y_{1}[/tex]=0

[tex]x_{2}[/tex]=-2

[tex]y_{2}[/tex]=3

Now substitute their values into the equation and find m

m=[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

m=[tex]\frac{3-0}{-2-0}[/tex]

subtract

m=[tex]\frac{3}{-2}[/tex]

so the slope of the line is [tex]\frac{3}{-2}[/tex]. It can also be rewritten as [tex]\frac{-3}{2}[/tex]

Here is the equation of the line so far:

y=[tex]\frac{-3x}{2}[/tex]+b

we need to find b

As the equation passes through both (0,0) and (-2,3), we can use either one of them to solve for b

Let's take (0,0) for this case

Substitute 0 as x and 0 as y

0=-[tex]\frac{3}{2}[/tex](0)+b

multiply

0=0+b

add 0 to both sides

0=b

So b is 0

The equation of the line therefore is y=[tex]\frac{-3x}{2}[/tex]

Hope this helps!

Answer:

From left to right, fill in 3.5 and 6.5

Step-by-step explanation:

Use the given formula to calculate y for the given values of x.

When x = 0.5, y = 3(0.5) + 1/0.5

y = 1.5 + 2

y = 3.5 if x = 0.5

When x = 2, y = 3(2) + 1/2

y = 6 + 0.5

y = 6.5 if x = 2

Answer:1. = 4x+8  

2. 2a²-a+1

Step-by-step explanation:

1. ((x+2)+3x+6.  2. 2a(a-1)-a+1​

((x+2)+3x+6

= x+2+3x+6

= 4x+8

2a(a-1)-a+1

2a²-2a-a+1

2a²-a+1

Answer:

a. 18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Distributive Property

Algebra I

Calculus

Integrals

Integration Rule [Reverse Power Rule]:                                                                      [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                        [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                             [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                           [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^2_0 {x(4x^2 + 1)} \, dx[/tex]

Step 2: Integrate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

Answer:

Step-by-step explanation:

The area is:

We can find the area,

→ 2(3.5 × 2)+ (7 × 2) + 2(1.8 × 2)

→ 14 + 14 + 7.2

→ 35.2 cm²

Thus, the area is 35.2 cm².

Answer:

[tex]x^2 + y^2 + 2x - 2y - 7 = 0[/tex]

Step-by-step explanation:

Given

See attachment for circle

Required

The circle equation

First, we get the radius of the circle.

From the attachment, we have:

[tex]r = 3[/tex]

Next, the center of the circle

[tex](h,k) = (-1,1)[/tex]

The equation of the circle is:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

This gives:

[tex](x - -1)^2 + (y - 1)^2 = 3^2[/tex]

[tex](x +1)^2 + (y - 1)^2 = 3^2[/tex]

Expand

[tex]x^2 + 2x + 1 + y^2 - 2y + 1 = 9[/tex]

Collect like terms

[tex]x^2 + y^2 + 2x - 2y + 1 + 1 - 9 = 0[/tex]

[tex]x^2 + y^2 + 2x - 2y - 7 = 0[/tex]

Hence, the equation in general form is:

[tex]x^2 + y^2 + 2x - 2y - 7 = 0[/tex]

Answer:

(1.6, 6)

Step-by-step explanation:

[tex] ln({e}^{5 - 2x} = 6)[/tex]

[tex]5 - 2x = ln(6) [/tex]

[tex]2x = 5 - ln(6) [/tex]

[tex]x = \frac{5 - ln(6) }{2} [/tex]

y = 6

Answer:

a = 1000, p = 10

Step-by-step explanation:

Given

y = - 3lg x + lg a

in the form y = mx + c ( m is the slope and c the y- intercept )

From the graph

(a)

c = 3 , then

lg a = 3 , that is

a = 10³ = 1000

(b)

Replace x by p and y = 0 in the equation

0 = - 3lg p + 3 ( subtract 3 from both sides )

- 3 = - 3lg p ( divide both sides by - 3 )

1 = lg p

p = 10 [ [tex]log_{10}[/tex] 10 = 1 ]

Answer is x=50.1

Step 1

Tanx=opposite/adjacent

Step2

Tanx=6.1/5.1

x=arctan(6.1/5.1)

x=50.1

Answer in degrees as required

Answer:

x + 2

Step-by-step explanation:

im sure its the right answe

Answer:

x = 10.7

Step-by-step explanation:

We have:

[tex]\frac{x}{sin 90}[/tex] = [tex]\frac{9.2}{sin59}[/tex]

=> x × sin59 = 9.2 × sin90

=> x × sin59 = 9.2

=> x = 9.2 ÷ sin59

=> x = 10.733027...

=> x = 10.7 (Round to the nearest tenth)

<3 Have a nice day!!

Answer:

0.054, 0.405, 0.45, 0.54

Answer:

0.054, 0.405, 0.45, 0.54

Step-by-step explanation:

1. The 0 after the decimal point makes it the smallest

2. 405/1000 < 45/100

3. 45/100 < 54/100