February is the month that the Milky Way galaxy system begins to develop.
What is milky way galaxy?
The Milky Way is a massive cluster of stars, gas, and dust. Because it would appear to be a whirling pinwheel from the top or bottom, this galaxy is a spiral galaxy. About 25,000 light-years from the galactic center, on one of the spiral arms, is where the Sun can be found.
What is the Big Bang hypothesis?
According to the Big Bang hypothesis, the universe originated from a single, unfathomably hot, and dense point (also known as a "singularity") more than 13 billion years ago. It didn't happen at a location that was previously there. Instead, it was the one who started space's expansion and cooling.
Therefore, February is the month to be considered as the formation of the Milky way galaxy.
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consider a neutron star with a mass equal to the sun, a radius of 11 km , and a rotation period of 1.0 s . what is the speed of a point on the equator of the star?express your answer with the appropriate units.
At equator line the speed of the star is 69115 m/s
When a big star runs out of heat and collapses, neutron stars are created. Every proton and electron in the star's core, or most central region, fuse into neutrons as it falls. These freshly generated neutrons can stop the collapse, leaving a neutron star behind, if the core of the collapsing star is between one and three solar masses.
Radius is 11 km
Period of rotation is 1 second
Converting radius to meters:
11 km = 11 x 10^3 = 11000m
We know that the velocity relation is v = 2πr/T
v = 2 x π x r / 1
v = 2π x 11000
v = 69115 m/s
Hence the speed of the star at the equator is 69115 m/s
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Ryan scores during his Waterpolo match by throwing the water polo ball hard. If the water polo bairs mass is 0.45 kg, the ball’s weight is ___N
The ball accelerates at a rate of 5.0 m/a^2 after Ryan throws it The net force on the ball is ___N.
The friction between the ball and the air is 2.65 N. To throw the ball at 5.0 m/a^2. Ryan has to apply a force of ___N
Ball’s weight is 4.4129925 N , net force on the ball is 2.25 N , Ryan has to apply a force of 4.9 N.
What is force ?
Whenever there is an interaction between two objects, there is a force acting on each object. When the interaction stops, the two objects no longer receive forces. Forces arise only through interactions , describes the technique of rocks converting their bodily houses with out converting their simple composition.
What is acceleration ?
Acceleration is a vector quantity defined as the rate at which an object's velocity changes. An object accelerates when its velocity changes.
What is friction ?
Friction is the resistance to movement of 1 item transferring relative to another. According to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab), it isn't always handled as a essential force, like gravity or electromagnetism. Instead, scientists accept as true with it's miles the end result of the electromagnetic appeal among charged debris in touching surfaces.
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a 3 kg block starts from rest at the top of a 30 degree incline and slides a distance of 2 m down the incline in 1.50 seconds. find the magnitude of the acceleration of the block. find the coefficient of kinetic friction between the block and the ramp.
The magnitude of the acceleration of the block is 1.78m/s².
The coefficient of kinetic friction between the block and the ramp is 0.368.
How can I calculate the coefficient of kinetic friction?The resistive force of friction (Fr), which pushes the objects together, is divided by the normal or perpendicular force (N), which pushes them apart, to produce the coefficient of friction (fr), which is a numerical value. The following formula represents it: fr = Fr/N.
Given,
m=3.00kg, θ=30° ,
x= 2.00m, t=1.50s.
constant rate of acceleration,
[tex]X_{f} = v_{i} t[/tex] + 1/2at²
solving,
a = 2([tex]X_{f}[/tex]-[tex]v_{i} t[/tex])/t²
a = 2(2-0)/(1.5)²
a = 1.78m/s².
We have neither a burrowing-in nor a taking-off action when Newton's law is applied in the y direction, which is perpendicular to the inclination. The y component of acceleration is then equal to zero:
∑ [tex]F_{y}[/tex]=n–mgcosθ=0
Thus n=mgcosθ
Because f=[tex]\mu_{k}[/tex]n
[tex]\mu_{k}[/tex] = f/mgcosθ
[tex]\mu_{k}[/tex] = 9.37/3×9.8×cos30°
[tex]\mu_{k}[/tex] = 0.368.
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the hydrogen in a star emits light at 484 nm as observed by an astronomer. which describes the motion of the star if the laboratory value of this spectral line of hydrogen is measured at 486 nm? question 9 options: approaching at 6.17 105 m/s moving away at 6.17 105 m/s approaching at 1.23 106 m/s moving away at 1.23 106 m/s
If the laboratory value of this hydrogen spectral line is detected at 486 nm, the star is moving toward us at a speed of 6.17 105 m/s.
How might Bohr's theory explain the hydrogen spectrum?In less than a year, Niels Bohr had a hydrogen atom model that "explained" the spectral lines. The energy level was a novel idea that Bohr introduced. Sharp spectral lines were released when an electron in hydrogen moved from one of its permitted energy levels, which were defined by the hydrogen atom.The wavelengths, measured from the scale, are 435 nm (purple), 486 nm (blue), and 657 nm (red).Hydrogen has numerous different energy levels while having just one electron. A photon is released when an electron in an object jumps from one energy level to another. Due to the various levels, those photons produce light with various colors and wavelengths.To learn more about Hydrogen atom model refer to:
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four resistors having a value of 100 ohms each are connected in parallel. what is the total resistance of the circuit?
The total resistance of the circuit is 25 ohms.
How can the resistance of a circuit with four resistors in parallel be determined?In the same way, if three or more resistors of the same value are connected in parallel, the equivalent resistance will be equal to R/n, where R is the resistor's value and n is the total number of resistors in the arrangement.
How do you calculate a parallel resistor's total resistance?The total current flowing from the source is the sum of the currents through each of the paths. Using the following formula, you can get the overall resistance in a parallel circuit: 1/Rt = 1/R1 + 1/R2 + 1/R3 +... Even if one of the parallel channels breaks, current will still flow.
[tex]R_{total}[/tex] = 100/4 = 25ohms
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what is the purpose of the frets on a guitar. in terms of the frequency of the vibration of the strings
To learn frequency to known frequency and frets of guitar.
What is frequency?
The number of waves that pass a fixed point in a unit of time is referred to as frequency in physics. It also describes how many vibrations or cycles a body in periodic motion makes in a given amount of time.
What is the purpose of frets?
Frets, which determine the positions for the proper notes, make it much simpler for a player to achieve an acceptable standard of intonation. Furthermore, playing chords accurately is made simpler by a fretted fingerboard.
Frequency of the vibrations of the strings.
f=2LnmT, where T is the tension in the string, L is the length, and n is the number of harmonics, gives the frequency of vibration of a string.
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3. The average human walks at a speed of 5 km per hour. If your PE teacher asks you to
walk for
40 minutes in
gym class, how far would you walk (km)?
The average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.
What is Average speed?
The average speed is the displacement of a particle divided into a time in which the displacement occurs. Instead, instantaneous speed is the limit of the average speed as the time interval approaches zero.
Usually,
Speed = Distance/ Time
Assuming you also walk with the average human walking speed of 5 km/h. We know the above formula of speed and now making distance the subject, distance is a product of speed and time.
Here, time is 40 minutes and if expressed in hours can be converted as,
40/60 = 0.6 hours.
Distance = 5 × 0.6
= 3 km
Thus,the average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.
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a circular platform of radius 4.0 m is initially spinning with an angular velocity of 8.0 rad/s. the platform accelerates for 2.0 s while passing through a displacement of 10. rad. what is the angular acceleration of the system.
0.5rad/s^2 is the value of angular velocity. Angular velocity can be defined as the speed at which an item rotates or revolves around an axis.
What is angular velocity?The rotation rate, which refers to how quickly an item rotates or circles in relation to another point, is measured vectorially by angular velocity. Angular velocity can be defined as the speed at which an item rotates or revolves around an axis.
The speed at which the angular position or orientation of an object changes over time is depicted in physics by the terms "angular velocity" or "rotational velocity" ( or ), also known as "angular frequency vector,"[1] and "angular frequency vector vector." The pseudovector's direction is normal to the instantaneous plane of rotation or angular displacement, and its magnitude corresponds to the object's angular speed, or the rate at which it rotates or revolves.
Angular velocity=Δw/Δt
=w2-w1/t2-t1
=8.0-4.0/10-2.0
=0.5 rad/s^2
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If the man pulls the sled with a 10 N
force, what is the horizontal component
of force? Refer to chapter 4, mechanics if
you do not remember how to resolve a
force into its components.
Answer:
Explanation:
The horizontal component of force is Fcosθ if the man pulls the sled with a 10 N force. Force has both a magnitude and a direction since it is a vector quantity.
What is force?A force is an external cause that, when applied, alters or has the potential to alter a body's condition. The body comes to rest while it is moving, and it moves when it is at rest.
The body's orientation, form, size, etc. may also alter as a result. An illustration would be to push or forcefully shove a door. Force has both a magnitude and a direction since it is a vector quantity. If the man pulls the sled with a 10 N force then the horizontal component of force is Fcosθ. Your training at this level should place a major emphasis on the idea that a push or even a pull was referred to as an force.
Therefore, the horizontal component of force is Fcosθ if If the man pulls the sled with a 10 N force.
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a horizontal spring with spring constant 250 nv/m is compressed 12 cm and used to launch a 250 g box across the floor. the coefficient of kinetic friction between the box and the floor is 0.23. what is the box's launch speed?
Therefore, the lunch speed of the box is 3.72m/s
What is kinetic friction ?
Kinetic friction is a force that exists between moving surfaces. A body moving on the surface is subjected to a force that is directed in the opposite direction of its movement. The size of the force is determined by the kinetic friction coefficient of the two materials.
Friction is simply the force that holds a sliding object back. Kinetic friction is present in everything and interferes with the motion of two or more objects. The force acts in the opposite direction of the object's desire to slide.
The integration of force due to spring with respect to spring is equal to the potential energy of the spring.
U=∫-Fdx
Here, U is the potential energy.
U= 1/2k[tex]x^{2}[/tex]
U= 1.8J
The final kinetic energy of the box is,
K= 1/2m[tex]v^{2}[/tex]
v=3.72m/s
The system's total potential energy equals the work done owing to kinetic friction. Using the law of conservation of energy, the sum of the energies obtained before compressing the spring equals the sum of energies obtained after expanding the spring.
Therefore, the lunch speed of the box is 3.72m/s
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Stan argues that momentum cannot be conserved when a collision is not a head-on collision. Rachel insists it is conserved because each body receives an impulse of equal magnitude. Rachel is correct because.
Rachel is correct because she said that is body receive equal magnitude of impulse which completely satisfy the law of conservation of linear momentum.
According to law Conservation of Linear Momentum, if there is no external force working on the system, then the linear momentum remains conserved before and after the collision.
We know that,
Momentum is nothing but the product of force and the time taken for the contact period of the colliding bodies.
We assume that during the head on collision of the body, the body is remain in contact for such a short period of time that there is no external force all the impulse created due to the external force is neglected.
So, because the impulse imparted on both the bodies are equal to each other.
We know that impulse is nothing but the change in momentum.
So, from here we conclude that bodies received equal magnitude of impulse.
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what would her speed be at 490 m ? (in reality, the air resistance will restrict her speed to perhaps 150 km/h .)
She will pull her ripcord 22.9 s after the dive and her speed at 490 m will be 112.66 m/s.
What is free-fall?Free fall, any motion of a object where gravity is the only force acting upon it. In the context of general relativity, where gravity is reduced to the curvature of spacetime, there are no forces acting on bodies in free fall.
For the given case,
s = ut + 1/2 at²
s = Displacement (3000 - 420 = 2580 m) it is the distance she will free fall
a = Acceleration due to gravity (9.8 m/s²)
u = Initial velocity (0 m/s)
t = Time taken
2580 = 0×t + 1/2 9.8 t²
2580 = 4.9 t²
t = 22.9 s
Now her speed at 490 m will be
v = d/t
v = speed
d = 2580 m
t = 22.9 s
v = 2580/22.9
v = 112.66 m/s
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The given question is incomplete so the complete question is as follows:
"if there were no air resistance, how long would it take a free-falling skydiver to fall from a plane at 3100 m to an altitude of 490 m , where she will pull her ripcord? what would her speed be at 490 m ? (in reality, the air resistance will restrict her speed to perhaps 150 km/h)"
a migrating robin flies due north with a speed of 12 m/s relative to the air. the air moves due east with a speed of 6.3 m/s relative to the ground.what is the robin's speed relative to the ground?
The robin's speed relative to the ground 62.3 degrees north of east, or tan(12/6.3).
How to calculate the speed relative to the ground?Think about the X-east-west axis's direction and the Y-north-south axis's direction.
V ra = 12 j m/s is the speed of a migratory robin relative to the air.
(In which "j" denotes a unit vector in the Y direction)
V ag = air speed in relation to the ground = 6.3 I m/s
(Where I is an X-direction unit vector)
V rg = speed of migratory robin in relation to the ground =
utilizing the formula
V rg = V ra + V ag
= 12 j + 6.3 I
= 6.3 I + 12 j
magnitude: (13.6 m/s = sqrt[tex](6.3)^{2}[/tex] + ([tex](12)^{2}[/tex])
direction: 62.3 degrees north of east, or tan(12/6.3).
The robin's speed relative to the ground 62.3 degrees north of east, or tan(12/6.3).
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a 1500 kg vehicle is traveling on a curved, icy road. the road is banked at an angle of 10.0 degrees and has a radius of curvature of 400 m. the velocity of the car necessary to travel on the icy road without sliding is .
The vehicle speed required to drive on an icy road without sliding is 28.3 m/s.
The weight of the car is m = 1500 kg
The angle at which the road is inclined is θ = 10
The radius of curvature is r = 400m
The expression for the speed of the car required to travel on the road without sliding is V =[tex]\sqrt{rgtan}[/tex]
V =[tex]\sqrt{400*9.8*tan10}[/tex]
V = 28.3 m/s
Velocity is the rate of change in direction of an object in motion measured by a specific time standard and observed from a specific reference point (for example, 60 km/h north). A key idea in kinematics, the branch of classical mechanics that studies the motion of bodies, is velocity.
The definition of velocity requires both its magnitude and its direction, since it is a physical vector quantity. Velocity is a coherently derived unit that is measured in the SI (metric system) as meters per second (m/s or m/s1). Velocity is a scalar absolute value (magnitude) of speed.
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everyday application: suppose a yo-yo has a center shaft that has a 0.250 cm radius and that its string is being pulled. (a) if the string is stationary and the yo-yo accelerates away from it at a rate of , what is the angular acceleration of the yo-yo? (b) what is the angular velocity after 0.750 s if it starts from rest? (c) the outside radius of the yo-yo is 3.50 cm. what is the tangential acceleration of a point on its edge?
If it starts at rest, the angular velocity after 0.750 is 5.1. The symbol for angular velocity in SI units is s1.
Explain about the angular velocity?When an object rotates or circles around an axis, its angular velocity is the rate at which the angle between the two bodies changes. The angle that is made by a line on one body and a line on the other in the illustration represents this displacement.
Examples of angular velocity include a roulette ball on a wheel, a race car travelling in a circle, and a Ferris wheel. In addition, the object's angular displacement with respect to time is represented by the angular velocity of the object.
Since the radian is a dimensionless quantity and the SI unit of angular velocity is radians per second.
Angular acceleration
a = a /r
= 1.7/0.250
a =6.8
Angular velocity
omega = a*t
= 6.8 *0.75
=5.1
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the frequency content of an analog signal to be digitized has a range roughly covering the range of the auditory system of a young child: 200 hz to 20,000 hz. for accurate sampling, what is the minimal sampling rate necessary for an a/d convertor?
For accurate sampling, -44.1khz is minimum sampling rate for an a/d convertor.
What is sampling rate?The number of samples per second (or other unit) taken from a continuous signal to form a discrete or digital signal. The sample rate or sample rate specifies the number of samples per second (or other unit). of a continuous signal to form a discrete or digital signal..
The sampling rate can be thought of as the audio version of frames per second. This is the number of "clips" taken from an analogue sound wave to make a digital file. In addition, the sample rate also controls the highest frequency that can be accurately reproduced by a digital file.
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if we could put all the asteroids in the asteroid belt together, their total mass would be .
If we could place all the asteroids collectively, their general mass would be much less than the mass of any terrestrial planet.
The whole mass of the asteroid belt is expected to be 2.39×1021 kg, which is just three% of the mass of the Moon. The 4 biggest items, Ceres, Vesta, Pallas, and Hygiea, account for perhaps 62% of the belt's total mass, with 39% accounted for by way of Ceres on my own. Gravitational tugs from Jupiter avoided fabric from accumulating collectively to shape a planet.
The 4 biggest asteroids inside the belt are known as Ceres, Vesta, Pallas, and Hygiea. these huge asteroids make up about half of the mass of the complete asteroid belt. Scientists like to mention that in case you blended all of those rocky asteroids collectively, it might make a planet a piece smaller than Earth's moon.
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Find the magnitude and direction of (a) the resultant (b) the equilibriant of two forces, 10 N acting in the direction N 30 East and 15 N acting in the easterly direction, if both forces act at a point.
(a) The magnitude of the resultant of the forces is 24.2 N.
(b) The direction of the forces is 12⁰.
(c) The equilibrant of two forces is -24.2 N.
What is the resultant of the forces?
The resultant of the forces is calculated by resolving the forces into x and y components as follows;
The x-component of the forces is calculated as follows;
x-component of the first force = 10 N x cos(30) = 8.66 N x-component of the the second force = 15 N x cos(0) = 15 Nsum of x - component of the forces, X = 8.66 N + 15 N = 23.66 N
The y-component of the forces is calculated as follows;
y-component of the first force = 10 N x sin(30) = 5 N y-component of the the second force = 15 N x sin (0) = 0 Nsum of y - component of the forces, Y = 5N + 0 N = 5 N
The resultant of the forces is calculated as;
F = √(X² + Y²)
F = √(23.66² + 5²)
F = 24.2 N
The direction of the forces is calculated as;
θ = arc tan (Y/X)
θ = arc tan (5 / 23.66)
θ = 11.9⁰ ≈ 12⁰
An equilibrant force is equal in magnitude both opposite in direction to the resultant force.
Thus, the equilibrant of two forces is -24.2 N.
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you are in bed and wish to shut your bedroom door without getting up. you happen to have some play dough(clay) and a bouncy ball on hand, both with the same mass. the play dough will stick to the door, the ball will bounce off. which one would be more effective to throw at your door to close it?
Using the concepts of momentum, we got that bouncy ball will be more effective as to throw at my door to close it when both with the same mass. the play dough will stick to the door, the ball will bounce off.
The momentum of an object is equal to the product of its mass and its velocity. The momentum of the system is conserved even if the collision is inelastic.
When the bouncy ball or the blob of clay actually hits the door, their momentum changes. Since momentum is conserved, the door would move in the opposite direction so that the total momentum stays at zero.
Let the mass of each object be . Suppose that both of the objects hit the door at a speed of in the same direction.
The bouncy ball will actually bounce back at about the same speed (in the opposite direction, away from the door.) The magnitude of the change in velocity will be at most . The magnitude of the change in momentum will be at most .However, when the blob of clay hits the door, its shape would change (and it would potentially stick to the door.) In other words, its velocity becomes almost after the collision. The magnitude of the change in its momentum will only be around , which is only about the momentum change due to the bouncy ball.By Newton's Second Law, the net force on the door is proportion to the rate of change in its momentum.
Hence, when I am in bed wish to shut my bedroom door without getting up and have some play dough(clay) and a bouncy ball on hand, both with the same mass. the play dough will stick to the door, the ball will bounce off, the more effective ball to throw at my door to close it is the bouncy ball.
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The rising concern among athletic trainers and health advocates (and parents) regarding concussions and multiple concussions among high school football players has prompted numerous studies of the effectiveness of protective head gear and the forces and accelerations experienced by players. One study suggested that there is a 50% chance of concussions for impacts rated at 75 g's of acceleration (i.e., 75 multiplied by 9.8 m/s/s). The average head impact in football results in 22 to 24 g's of acceleration ... but not all head impacts are equal.
If a player's head mass (with helmet) is 5.41 kg and considered to be a free body, then what net force would be required to produce an acceleration of 75 g's?
Answer:
Explanation:
Given:
m = 5.41 kg
g = 9.8 m/s² - acceleration of gravity
a = 75·g = 75·9.8 ≈ 735 m/s²
__________________
F - ?
Newton's second law:
F = m·a
F = 5.41·735 ≈ 3 980 N
what is the speed of the 0.100 kg sphere when it has moved 0.400 m to the right from its initial position?
6.01 × 10⁻⁵ m/s is speed of 0.100 kg sphere when it has moved 0.400 m to right from its initial position.
What is conservation of energy?The conservation of energy principle states that in a closed system, the energy of interacting objects or particles remains constant. Kinetic energy, sometimes known as the energy of motion, was the first type of energy to be identified. The sum of the kinetic energy of the particles before collision and the sum of the kinetic energy of the particles after collision are equal in some particle collisions, known as elastic collisions. Progressively, more types of energy were added to the definition of energy.
We have from the conservation of energy,
[tex]E_{i}[/tex] = [tex]E_{f}[/tex]
[tex]E_{i}[/tex] = [tex]\frac{-G(5*0.1)}{0.4}[/tex] - [tex]\frac{G(10*0.1)}{0.6}[/tex]
[tex]E_{i}[/tex] = [tex]\frac{-G(5*0.1)}{0.8}[/tex] - [tex]\frac{G(10*0.1)}{0.2}[/tex] + 1/2 × 0.1v²
∵ [tex]E_{i}[/tex] = [tex]E_{f}[/tex]
= 1/2 × 0.1 × v² = G (5×0.1) (1/0.8 - 1/0.4) + G (10 × 0.1) (1/0.2 - 1/0.6)
∴ v = 6.01 × 10⁻⁵ m/s
Speed of the object moved from its initial position is 6.01 × 10⁻⁵ m/s.
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An 0.8 kg cart rolls down a frictionless hill of height 0.32m. At the bottom of the holl the cart rolls on a flat surface., which exerts a frictional force if 2 n on the cart. How far does the cart roll on the flat surface before it comes to a stop
The distance travelled by the cart on the flat surface before it comes to a stop is 1.25 m.
What is the acceleration of the cart?
The acceleration of the cart is determined by applying Newton's second law of motion as shown below.
F = ma
a = F/m
a = 2 N / 0.8 kg
a = 2.5 m/s²
The velocity of the cart at the bottom of the hill is calculated as;
u = √2gh
u = √(2 x 9.8 x 0.32)
u = 2.5 m/s
The distance travelled by the cart before stopping;
v² = u² - 2as
where;
v is the final velocity of the cart = 0u is the initial velocity = 2.5 m/sa is the accelerations is the distance travelled2as = u²
s = u²/2a
s = (2.5²) / (2 x 2.5)
s = 1.25 m
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A golf ball is thrown straight up in the air at a velocity of 8.3 . Determine the maximum height of the golf ball.
(b) How long will it take the ball to reach its maximum height?
(c) How long will it take the ball to fall from its maximum height to the height from which it was initially launched?
a) The maximum height is 3.5 m
b) The time taken to reach this height is 0.85 seconds
c) The time taken to return to the original point is 0.85 seconds.
What is the maximum height?We know that the maximum height can be obtained from the use of the kinematic equations. We know that;
a) v^2 = u^2 - 2gh
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = maximum height attained
v= 0 /ms at the maximum height
u^2 = 2gh
h = u^2/2g
h = (8.3)^2/2 * 9.8
h = 68.89/10.6
h = 3.5 m
b) Time taken to reach the maximum height;
v = u - gt
v= 0 /ms at the maximum height
u = gt
t = u/g
t = 8.3/9.8
t = 0.85 seconds
c) The time taken to return is the same as the time taken to go up which is 0.85 seconds.
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Which variable is NOT shown on a velocity-time graph?
Acceleration is the variable that is NOT shown on a velocity-time graph
Velocity - time graph, evidently shows two variables, velocity on one axis and time on other . But as we know , that acceleration can be calculated by the formula which is
acceleration = change in velocity / time
hence , the derivative of velocity is acceleration
which mean that the slope of the Velocity - time graph shows the acceleration , which cannot be seen , but is hidden as the slope of that graph
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a 70 kg man is floating at rest near his spaceship. he throws a 1.5 kg wrench away from the ship at a speed of 10 m/s in order to move himself toward it. with what speed does he move toward the ship?
0.218 m/s speed does he move toward the ship.
use the formula from conservation of Momentum
mu + MV = (m-M)V'
u = o
so
MV = (m-M)V'
V' = (1.5 * 10)/(70-1.5)
V' = 0.218 m/s
What is speed?The most crucial scientific notion is measurement. Base or physical fundamental units are used to quantify a wide range of quantifiable quantities. One such measurable metric is speed, which calculates the ratio between the distance an object travels and the time needed to cover that distance. Let's explore speed in-depth in this session.
The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.
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magnus has reached the finals of a strength competition. in the first round, he has to pull a city bus as far as he can. one end of a rope is attached to the bus and the other is tied around magnus's waist. if a force gauge placed halfway down the rope reads out a constant 1550 newtons while magnus pulls the bus a distance of 2.15 meters, how much work does the tension force do on magnus? the rope is perfectly horizontal during the pull.
The Work done by tension force on Magnus is
- 3225 Joule .
In the given question we have, one end of rope is tied around magnus waist and other attched to bus and he pulls the bus. The direction of tension force is just work done.
constant force = 1550 Newton
displacement = 2.15 meters
The direction of tension force is opposite to work done due to the tension force is reaction force to force of work done for pulling the bus.
work done by tension = W = - W₀
where W₀is horizontal work done by magnus during pulling.
so, W₀ = Fdcosθ
where , F---> force , d--> displacment and θ ---> angle between force and displacement
As we see whole work done in horizontal direction. So, angle between force and displacement is zero.
put all the vales in above formula we get ,
W₀= 1550× 2.15 cos0 = 1550×2.15 = 3225 Joule
W = - W₀ = - 3,225J
Hence, work done by tension force on Magnus is
- 3,225 Joule.
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g the triceps muscle in the back of the upper arm extends the forearm. this muscle in a professional boxer exerts a force of 2903 n with an effective perpendicular lever arm of 2.35 cm , producing an angular acceleration of the forearm of 130.0 rad / s2 . what is the moment of inertia of the boxer's forearm?
The moment of inertia of the boxer's forearm will be 0.525kg.[tex]m^{2}[/tex]
In physics, it means quantitative measure of the rotational inertia of the body. As an example, the opposition that the body exhibits to having its speed of rotation about an axis altered by the application of a torque (turning force). The axis may be internal or external and may or may not be fixed.
From the question given, the triceps muscle in the back of the upper arm extends the forearm of a professional boxer when he extends his arm,
Torque generated due to this force is,
τ = F * r
τ = torque is generated
F = force exerted = 2903n
r = the radius of the lever arm = 2.35cm = 0.0235m
Now let's use the torque formula
τ = 2903N * 0.0235m
τ = 68.2205 N.m
Next, we want to find the moment of inertia of the boxer's forearm by calculating the relation between torque and moment of inertia and angular acceleration,
τ = torque = 68.2205Nm
I = moment of inertia
α = angular acceleration = 130 rad / s²
τ = Iα
68.2205 = I*130rad/s²
I = 0.525 kg.m² (rounded)
Therefore, the value of moment of inertia is 0.525kg.m²
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If two tractors are pulling against each other at a tractor pull and the first tractor exerts 500N of force to the East and the second tractor exerts 350N of force to the west and the combined weight of the tractor is 800 kg, what is the acceleration of both tractors? In what direction?
Answer:
Explanation:
Given:
F₁ =500 N
F₂ = 350 N
m₁ = m₂ = m = 800 kg
__________
R - ?
a - ?
Resultant force:
R = 500 - 350 = 150 N
System acceleration:
a = R / (m₁ + m₂) = R / (2·m)
a = 150 / (800 + 800) = 0.094 m/s²
Direction R and a - East
a multimeter is used for? select one: a. frequency testing of coaxial cable b. general electrical measurements c. testing the bandwidth of all types of cables d. testing continuity of fiber optic cable
A multimeter is used for general electrical measurements. So, the correct option is (b)
What is a multimeter?A multimeter is an electronic measuring device that combines multiple measurement functions into one device. A typical multimeter include features such as the ability to measure voltage, current, and resistance.
Most multimeters have the ability to test circuit continuity. This makes it easier to find faults such as bad cables. It also helps to see if two points in the circuit are connected.
The typical multimeter can measure voltage, resistance, and current. In this case, the device is also called a Volt-Ohm Milliammeter (VOM), since it has the functions of a voltmeter, an ammeter, and an ohmmeter. Some of them even offer measurements of additional properties such as temperature and capacitance.
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a flight attendant pulls her 2 kg flight bag a distance of 23 m along a level airport floor at a constant velocity. the force she exerts is 8 n at an angle of 30 degrees above the horizontal. find the work she does on the flight bag.
Work done on the flight bag will be 182.20 J.
Work done defined as the product of force and distance covered due to applied force.
The mass of flight bag m = 2 kg
Therefore the weight of the bag will be 2*g = 2*10 = 20 N
(g = acceleration due to gravity = 9.81 m/s2)
The distance covered by the bag is, d = 23 m.
The magnitude of force exerted on bag is, F = 8 N.
The angle of inclination with horizontal = [tex]\alpha[/tex] = 8°
The work done on the flight bag is given by the equation:
W = F * d *Cos [tex]\alpha[/tex]
W = 8 * 23 * Cos8
W = 182.20 J
Thus, the work done by the attendant on the flight bag is 182.20 J.
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