if the first term of the sequence is 3 and the common difference is -2, then the correct sequence is

The amount Evan receives in commission by selling these three homes is $14275

From the question, we have the following parameters that can be used in our computation:

Selling price = $125,500, another for $75,000 and a third house for $85,000

So, the total is

Total = $125,500 + $75,000 + $85,000

Evaluate

Total = $285500

Next, we have

Commission = 5% * $285500

Evaluate

Commission = $14275

Hence, the commission received is $14275

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The expression 18c - 4c is simplified by combining like terms. After simplification, the number multiplied by c is 14.

In the given expression, we have two terms: 18c and -4c. To simplify, we combine these like terms by subtracting their coefficients. The coefficient of c in the first term is 18, and in the second term is -4. Subtracting -4 from 18 gives us 14. Therefore, the simplified expression becomes 14c, indicating that the number multiplied by c is 14.

This simplification is possible because we are adding or subtracting terms with the same variable, c. By combining the coefficients, we determine the new coefficient that represents the simplified expression.

To further understand the process, it is recommended to review the concept of combining like terms in algebraic expressions.

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a. The antiderivative of −2sin(2x) is cos(2x).

b. The antiderivative of 4sin(x) is -4cos(x).

c. The antiderivative of sin(2x)−4sin(4x) is -cos(2x) + (1/4)cos(4x).

In calculus, an antiderivative, inverse derivative, primitive function, primitive integral or indefinite integral of a function f is a differentiable function F whose derivative is equal to the original function f. This can be stated symbolically as F' = f.

When C equals 0, the antiderivative of a function represents the most general antiderivative or the family of functions that differ by a constant.

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The 100 containers that the quality control division of Rothschild's Blueberry Farm randomly inspects.

Population: The containers of blueberries that are being sent to Stop and Shop.

Sample: The 100 containers that the quality control division of Rothschild's Blueberry Farm randomly inspects.

Therefore, the 100 containers that the quality control division of Rothschild's Blueberry Farm randomly inspects.

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Answer: A. (-7, 4)

Step-by-step explanation: just because

The Taylor polynomial of degree n = 4 for x near the point a = π/3 for the function cos(3x) is P4(x) = -1 - (9/2)(x - π/3)² - (81/24)(x - π/3)⁴

To find the Taylor polynomial of degree n = 4 for the function cos(3x) near the point a = π/3, we need to compute the derivatives of the function at point a and evaluate them.

First, let's find the derivatives of cos(3x):

f(x) = cos(3x)

f'(x) = -3sin(3x)

f''(x) = -9cos(3x)

f'''(x) = 27sin(3x)

f''''(x) = 81cos(3x)

Next, let's evaluate these derivatives at the point a = π/3:

f(π/3) = cos(3π/3) = cos(π) = -1

f'(π/3) = -3sin(3π/3) = -3sin(π) = 0

f''(π/3) = -9cos(3π/3) = -9cos(π) = -9

f'''(π/3) = 27sin(3π/3) = 27sin(π) = 0

f''''(π/3) = 81cos(3π/3) = 81cos(π) = -81

Now, let's write the Taylor polynomial of degree n = 4 using the derivatives at the point a = π/3:

P4(x) = f(a) + f'(a)(x - a) + (f''(a)/2!)(x - a)² + (f'''(a)/3!)(x - a)³ + (f''''(a)/4!)(x - a)⁴

Substituting the evaluated derivatives, we have:

P4(x) = -1 + 0(x - π/3) + (-9/2)(x - π/3)² + 0(x - π/3)³ + (-81/4!)(x - π/3)⁴

Simplifying further:

P4(x) = -1 - (9/2)(x - π/3)² - (81/24)(x - π/3)⁴

The Taylor polynomial of degree n = 4 for x near the point a = π/3 for the function cos(3x) is:

P4(x) = -1 - (9/2)(x - π/3)² - (81/24)(x - π/3)⁴

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The correct answer is (d) 27.

We must multiply the number of options for each independent category to get the number of outcomes in the sample space for the various possible outcomes.

There are nine distinct topping options.

There are three options for crust types: thin crust, thick crust, and deep dish.

9 (topping choices) * 3 (crust choices) = 27

Therefore, there are 27 different outcomes in the sample space for the possible outcomes.

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(1)Laurent series expansion for $z$ in the annulus $0 < |z| < 1$:[tex]\( \frac{1}{{z^2 - z}} \):\[\frac{1}{{z^2 - z}} = \frac{1}{z(z-1)} = \frac{A}{z} + \frac{B}{z-1} = \frac{1}{z} - \frac{1}{z-1}\][/tex]

(2)Laurent series expansion for $z$ in the annulus $1 < |z| < \infty$:

[tex]\( \frac{{z+1}}{{z-1}} \):\[\frac{{z+1}}{{z-1}} = 1 + \frac{2}{z-1}\][/tex]

(3)Laurent series expansion for $z$ in the annulus $1 < |z| < 2$:[tex]\( \frac{1}{{(z^2 - 1)(z^2 - 4)}} \):\[\frac{1}{{(z^2 - 1)(z^2 - 4)}} = \frac{{A}}{{z+1}} + \frac{{B}}{{z-1}} + \frac{{C}}{{z+2}} + \frac{{D}}{{z-2}}\][/tex]

What are Laurent series expansions?

Laurent series expansions are a way to represent a complex function as an infinite series in the complex plane. They are a generalization of Taylor series expansions, allowing for both positive and negative powers of the variable.

A Laurent series expansion of a function f(z) around a point z = a is given by:

f(z) = ∑[n = -∞ to ∞] cn (z - a)^n

Here, cn represents the coefficients of the series, and (z - a)^n represents the powers of the variable centered at a.

(1) For the function $\frac{1}{z^2 - z}$:

The function has a simple pole at $z = 0$ and a removable singularity at $z = 1$.

Laurent series expansion for $z$ in the annulus $0 < |z| < 1$:[tex]\( \frac{1}{{z^2 - z}} \):\[\frac{1}{{z^2 - z}} = \frac{1}{z(z-1)} = \frac{A}{z} + \frac{B}{z-1} = \frac{1}{z} - \frac{1}{z-1}\][/tex]

(2) For the function $\frac{z + 1}{z - 1}$:

The function has a simple pole at $z = 1$ and a removable singularity at $z = -1$.

Laurent series expansion for $z$ in the annulus $1 < |z| < \infty$:

[tex]\( \frac{{z+1}}{{z-1}} \):\[\frac{{z+1}}{{z-1}} = 1 + \frac{2}{z-1}\][/tex]

(3) For the function $\frac{1}{{(z^2 - 1)(z^2 - 4)}}$:

The function has simple poles at $z = \pm 1$ and $z = \pm 2$.

Laurent series expansion for $z$ in the annulus $1 < |z| < 2$:[tex]\( \frac{1}{{(z^2 - 1)(z^2 - 4)}} \):\[\frac{1}{{(z^2 - 1)(z^2 - 4)}} = \frac{{A}}{{z+1}} + \frac{{B}}{{z-1}} + \frac{{C}}{{z+2}} + \frac{{D}}{{z-2}}\][/tex]

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When P(X = 0) = 0.05, the value of p for a binomial distribution with 12 trials is approximately 0.422. and when variance of 1.92, the possible values of p are approximately 0.15 and 0.85.

(a) Given P(X = 0) = 0.05, the value of p for a binomial distribution with 12 trials is approximately 0.422.

Using the probability mass function (PMF) of the binomial distribution and plugging in the values, we find that p = 1 - (0.05)^(1/12) ≈ 0.422.

(b) For a binomial distribution with 12 trials and a variance of 1.92, the possible values of p are approximately 0.15 and 0.85.

Using the variance formula for the binomial distribution and solving the quadratic equation, we find p ≈ 0.15 and p ≈ 0.85 as the possible values.

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The usual time taken by the train to cover the same distance is 45 minutes.

To find the usual time taken by the train to cover the distance, we can set up an equation based on the given information.

Let's denote the original speed of the train as "s" and the original time taken as "t" minutes.

The reduced speed of the train is 1/3 of its usual speed, so the reduced speed is (1/3)s.

We are also given that it takes an extra 30 minutes to reach the destination compared to its usual time. Therefore, the current time taken is t + 30.

We can set up the following equation based on the principle that the distance covered is the same:

Original Speed / Original Time = Reduced Speed / Current Time

s / t = (1/3)s / (t + 30)

To solve for the usual time taken, we can cross-multiply:

3s(t + 30) = s(t)

3st + 90s = st

3t + 90 = t

2t = 90

t = 45

Therefore, the usual time taken by the train to cover the same distance is 45 minutes.

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A 3³ factorial design with two replicates was conducted. The data will be analyzed to determine the main effects and interaction effects of the factors on the enzyme levels.

To analyze the data from this experiment, we will examine the main effects and interaction effects of the factors: lidocaine brand (A), dosage levels (B), and dogs (C). The enzyme levels observed in the two replicates will be analyzed to determine the significance of these factors.

First, we will calculate the average enzyme levels for each combination of factors (A, B, C). This will allow us to assess the main effects of the factors individually. We can then perform an analysis of variance (ANOVA) to determine if the main effects are statistically significant.

Next, we will investigate the interaction effects between the factors. This involves examining how the combination of factors (A, B, C) influences the enzyme levels. Interaction effects occur when the effects of one factor depend on the levels of another factor. We can assess these effects through ANOVA as well.

By analyzing the data using factorial analysis, we will be able to identify the significant factors and their effects on the enzyme levels in the heart muscle of beagle dogs. This information can provide insights into the impact of lidocaine brands and dosages on enzyme activity and help guide further research or medical decisions.

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5 represents the  number of years the fixed interest rate will be applied to the loan.

In the context of an Adjustable Rate Mortgage (ARM), the 5/1 ARM refers to the specific terms of the loan. The first number, in this case, 5, represents the initial period during which the interest rate remains fixed. This means that for the first five years of the loan, the borrower will have a consistent and unchanged interest rate.

After the initial fixed period, the loan transitions into the adjustable phase. The second number, in this case, 1, represents the frequency of adjustments to the interest rate.

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Supercomputers are the most powerful computers at any given time, but are built especially for assignments that require arithmetic speed.

The supercomputers, which are the most advanced and high-performance computers available, are specifically constructed to handle assignments that demand rapid arithmetic processing.

These machines are optimized for executing complex mathematical operations and simulations, enabling them to tackle problems that require immense computational power.

By harnessing parallel processing, massive memory capacities, and specialized architectures, supercomputers excel in solving scientific, engineering, and research challenges that necessitate exceptional arithmetic speed.

Their capabilities contribute to advancements in various fields, including weather forecasting, molecular modeling, astrophysics, and cryptography.

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256x + 256y + 16z = 1024  is the equation of the tangent plane to the surface represented by the vector-valued function r(u, v) at the given point (-4, 0, 2).

We are given a vector-valued function r(u, v) and a point (-4, 0, 2). The task is to find the equation of the tangent plane to the surface represented by the function at that point.

To find the equation of the tangent plane, we need two vectors that lie in the plane. One vector is the partial derivative of r with respect to u, and the other vector is the partial derivative of r with respect to v. We evaluate these partial derivatives at the given point (-4, 0, 2) to obtain the direction vectors of the tangent plane.

Taking the partial derivative of r(u, v) with respect to u gives the vector

2 cosh(v)i + 4u sinh(v)j + 2u^2k. Substituting u = -4 and v = 0, we get the vector -2i + 0j + 32k.

Taking the partial derivative of r(u, v) with respect to v gives the vector -2u sinh(v)i + 2u cosh(v)j + 0k. Substituting u = -4 and v = 0, we get the vector 8i - 8j + 0k.

These two vectors (-2i + 0j + 32k) and (8i - 8j + 0k) lie in the tangent plane at the point (-4, 0, 2). Now, we can use these vectors to find the equation of the tangent plane.

Using the point-normal form of a plane equation, where the normal vector is the cross product of the two direction vectors, we have:

(-2i + 0j + 32k) x (8i - 8j + 0k) = -256i - 256j - 16k.

The equation of the tangent plane is -256(x + 4) - 256y - 16(z - 2) = 0, which can be simplified to 256x + 256y + 16z = 1024. Thus, this is the equation of the tangent plane to the surface represented by the vector-valued function r(u, v) at the given point (-4, 0, 2).

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The area of the indicated region bounded by y=7 and y=7/25x^2 is XXX square units.

To calculate the area using Green's Theorem, we need to express the region in terms of a curve. Green's states that closed the line Theorem line integral integral of over a a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region bounded by the curve.

In this case, we can rewrite the given equations in terms of x and y to define the boundary of the region. The upper boundary is y=7, and the lower boundary is y=7/25x^2. To find the points of intersection between these two curves, we can equate them:

7 = 7/25x^2

Solving this equation, we find x = ±5. Now we have the boundaries of the region in terms of x values.

To express the region in terms of a line integral, we need to define a vector field F = (M, N). In this case, we can take M = 0 and N = x. Now we can apply Green's Theorem:

Area = ∬ D dA = ∮ C N dx = ∮ C x dx

To calculate the line integral, we need to parameterize the curve C that encloses the region. Since the region is bounded by two curves, we need to split the curve into two parts. Let's consider the upper curve C1: y = 7.

Parameterizing C1, we have:

x = t

y = 7, for t ∈ [5, -5]

Now we can calculate the line integral over C1:

∮ C1 x dx = ∫[5,-5] t dt = [t^2/2] evaluated from -5 to 5 = 25/2 - 25/2 = 0

Next, let's consider the lower curve C2: y = 7/25x^2.

Parameterizing C2, we have:

x = t

y = 7/25t^2, for t ∈ [-5, 5]

Now we can calculate the line integral over C2:

∮ C2 x dx = ∫[-5,5] t dt = [t^2/2] evaluated from -5 to 5 = 25/2 - 25/2 = 0

Since both line integrals are zero, the area of the region bounded by y=7 and y=7/25x^2 is 0 square units.

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Symmetry is the property of a geometric figure such that when the figure is transformed, the image coincides with the preimage.

In other words, symmetry refers to a balanced arrangement or structure that remains unchanged or looks the same after a specific transformation.

When a geometric figure possesses symmetry, there are certain transformations that can be applied to it without altering its overall appearance.

These transformations include reflections, rotations, and translations. Each of these transformations preserves the shape, size, and orientation of the figure.

For example, if a figure exhibits reflectional symmetry, it means that it can be divided into two equal parts along a line called the axis of symmetry.

When the figure is reflected over the axis of symmetry, the image coincides with the preimage, creating a mirror-like effect.

Similarly, rotational symmetry refers to a figure that can be rotated around a central point by a certain angle, and after the rotation, the image aligns perfectly with the original shape.

The angle of rotation corresponds to the degree of rotational symmetry.

Overall, symmetry is a fundamental concept in geometry that describes the balance and invariance of a figure under specific transformations, ensuring that the image coincides with the preimage.

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The maximum-likelihood estimate (MLE) of the parameter θ in the Pareto distribution, based on the given data (5, 10, 8), is θ = 1 / (log 5 + log 10 + log 8).

To find the MLE, we maximize the likelihood function by taking the logarithm and differentiating it with respect to θ. Solving the resulting equation, we determine that the MLE of θ is equal to 1 divided by the sum of the logarithms of the data points.

Substituting the specific data values (5, 10, 8) into the equation, we can calculate the numerical value of the MLE of θ.

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To solve this problem, we can use algebraic equations. Let's say that the number of weeks it takes for Ted and Carly to have the same account balance is "w".

Ted's account balance after "w" weeks can be represented by:

300 + 4w

Carly's account balance after "w" weeks can be represented by:

16w

We want to find out when their account balances will be equal, so we can set these two equations equal to each other:

300 + 4w = 16w

Simplifying this equation, we get:

300 = 12w

Dividing both sides by 12, we get:

25 = w

Therefore, it will take 25 weeks for Ted and Carly to have the same account balance.

To determine the domain of the function f(x) = x^2 - 6x + 1, we need to identify the values of x for which the function is defined.

In this case, since the function represents Anna's speed relative to land, it is reasonable to assume that Anna's speed cannot be negative since speed is typically measured as a positive value. Therefore, we can eliminate the options that involve x being less than 0.

Now let's examine the given equation f(x) = x^2 - 6x + 1. There are no square roots or denominators in the equation, so we don't need to worry about dividing by zero or taking the square root of negative numbers. Therefore, the function is defined for all real numbers.

Hence, the correct answer is:

d) All real numbers.

[tex]\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}[/tex]

♥️ [tex]\large{\textcolor{red}{\underline{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}[/tex]

The function g(x) = (-2 + √(1 + x)) / 2 is the inverse function of f(x) = 2x^2 + 4x, denoted as f^(-1)(x). It satisfies the composition property, meaning that (g∘f)(x) = (f∘g)(x) = x

To find the function g(x) such that (g∘f)(x) = (f∘g)(x) = x, we are looking for an inverse function of f(x) = 2x² + 4x.

To find the inverse function, let's follow the steps:

Replace f(x) with y.

y = 2x² + 4x

Swap the roles of x and y.

x = 2y² + 4y

Now solve the equation for y.

Rearranging the equation, we get:

2y² + 4y - x = 0

To solve this quadratic equation for y, we can use the quadratic formula:

y = (-4 ± √(4² - 4(2)(-x))) / (2(2))

y = (-2 ± √(1 + x)) / 2

Now, we have two potential solutions for g(x):

g(x) = (-2 - √(1 + x)) / 2

(f∘g)(x) = f(g(x))

= 2(g(x))² + 4(g(x))

= x

(g∘f)(x) = g(f(x))

= g(2x² + 4x)

≠ x

As we can see, (g∘f)(x) ≠ x, but (f∘g)(x) = x.

This means that g(x) = (-2 + √(1 + x)) / 2 is the inverse function of f(x), denoted as f⁻¹(x), but g(x) = (-2 - √(1 + x)) / 2 is not the inverse function.

So, g(x) = f⁻¹(x) is true only for g(x) = (-2 + √(1 + x)) / 2.

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The one-sample chi-square test is used to determine whether the distribution of a single categorical variable significantly differs from what would be expected by chance. The statement is True.

The one-sample chi-square test is a statistical test used to determine if there is a significant difference between the observed frequency and the expected frequency in a single categorical variable. It compares the observed frequency distribution of a variable to the expected frequency distribution, assuming that the null hypothesis is true.

This test compares observed frequencies to expected frequencies and calculates a chi-square statistic to assess the significance of the difference.

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Using an addition/subtraction formula, the exact value of the given expression is 0.8503.

To use an addition or subtraction formula, we need to rewrite the given expression in terms of sine and cosine functions. We can use the formula:

tan(x) = sin(x) / cos(x)

Applying this formula to the given expression, we get:

(tan(42°) - tan(12°)) / (1 + tan(42°) tan(12°))
= (sin(42°) / cos(42°) - sin(12°) / cos(12°)) / (1 + sin(42°) / cos(42°) * sin(12°) / cos(12°))
= (sin(42°) cos(12°) - cos(42°) sin(12°)) / (cos(42°) cos(12°) + sin(42°) sin(12°))
= sin(42° - 12°) / cos(42° + 12°)
= sin(30°) / cos(54°)

Using the values of sine and cosine for 30° and 54° from a trigonometric table, we get:

sin(30°) / cos(54°) = 1/2 / 0.5878
= 0.8503 (rounded to four decimal places)

Therefore, the exact value of the given expression is 0.8503.

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For any rational number (m)/(n) and any positive real number a, the expression [tex]a^(-(m)/(n))[/tex] is equivalent to (1)/([tex]a^(((m)/(n)))[/tex]).

Let's consider a positive real number a and a rational number (m)/(n), where m and n are integers. The expression [tex]a^(-(m)/(n))[/tex]represents the exponentiation of a by the negation of the rational number (m)/(n). This can be rewritten as 1/([tex]a^(((m)/(n)))[/tex]), which means taking the reciprocal of a raised to the power of (m)/(n).

To understand why this equivalence holds, we can use the properties of exponents. When we raise a positive number a to the power of a rational number (m)/(n), it is equivalent to taking the n-th root of [tex]a^m[/tex]. In this case, since the exponent is negated, it becomes the negation of the n-th root of [tex]a^m[/tex]. Taking the reciprocal of this result gives us 1 divided by the n-th root of [tex]a^m[/tex], which is precisely 1/([tex]a^((m)/(n))[/tex]).

Therefore, the expression[tex]a^(-(m)/(n))[/tex] is equal to (1)/([tex]a^(((m)/(n)))[/tex]), and this equivalence holds for any rational number (m)/(n) and any positive real number a.

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Answer:

-----------------

The difference of the consecutive terms is increasing:

So it is expected the next term to be 10 points greater:

The next term is 43.

Answer:

Step-by-step explanation:

(-75) x173+173x(-25)

173(-75-25)

173(-100)

-17300

To determine the score needed to get into a university that accepts only the top 10% of students, the Z-score corresponding to the 90th percentile is used.

A Z-score measures the number of standard deviations a particular data point is from the mean. In this case, the university only accepts students in the top 10%, which means the desired score would be the value corresponding to the 90th percentile. To calculate this Z-score, you would look up the corresponding value in a standard normal distribution table or use statistical software.

The Z-score represents the number of standard deviations above or below the mean a given data point falls. By finding the Z-score corresponding to the 90th percentile, you can determine the score needed to be within the top 10% of students. The Z-score table provides the critical value for a given percentile, and in this case, it would correspond to the 90th percentile. This critical value is used to convert the desired percentile into a Z-score. With the Z-score, you can then determine the score needed for admission to the university by applying it to the mean and standard deviation of the score distribution.

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The quotient in simplest form is 1/8. The problem didn't involve any variable, so there are no specific restrictions on it.

To find the quotient in simplest form, we need to divide the numerator by the denominator and simplify if possible. Let's solve the problem step by step:

We have the expression: (-3)/(+2) / (-12)

Divide the numerator (-3) by the denominator (+2):

(-3)/(+2) = -3/2

Now divide -3/2 by -12:

(-3/2) / (-12)

To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction:

(-3/2) / (-12) = (-3/2) * (1/(-12))

Simplify the expression:

(-3/2) * (1/(-12)) = (-3/2) * (-1/12)

Multiplying the numerators and denominators gives us:

(-3 * -1) / (2 * 12) = 3/24

Simplify the fraction:

3/24 can be simplified by dividing both the numerator and the denominator by their greatest common divisor (GCD), which is 3:

3/24 = (3 ÷ 3) / (24 ÷ 3) = 1/8

Therefore, the quotient in simplest form is 1/8.

Restrictions on the variable: The problem didn't involve any variable, so there are no specific restrictions on it.

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Answer:

Part A:

(a) [tex]x=-1[/tex]

(b) The vertex is [tex](-1,3)[/tex] and is a maximum

Part B: The graph is shown in part 2 attached below.

Step-by-step explanation:

The explanation is attached below. The graph is shown in part 2.