if the force on the ball increases linearly for 4.00 ms, holds constant for 20.0 ms, and then decreases linearly to zero in another 4.00 ms, what is the maximum force (in n) on the ball?

Answers

Answer 1

The maximum force on the ball is  280 N if the force on the ball increases linearly for 4.00 ms

The maximum force on the ball will be the average of the initial and final forces, which is half of the total force applied. The total force applied over the 28.0 ms time period is the area of the triangle formed by the linear increase, constant force, and linear decrease.

The area of the triangle can be found by calculating its height and width, and then multiplying them together. The height of the triangle is the maximum force applied over the 20.0 ms period, and the width of the triangle is 28.0 ms.

Therefore, the maximum force on the ball is (20.0 ms)(28.0 ms)/2 = 280 N.

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Related Questions

why do your hands not get warm when rubbing them with soapy water?

Answers

Answer:

Explanation:

because you are rubbing the soap not your hands so the soap takes up the energy rahter than the hands

the net electric flux crossing an open surface is never zero. true or false?

Answers

The given statement that net electric flux crossing an open surface is never zero, is false.

The net electric flux of an electric field through a closed surface is equal to the enclosed charge, divided by the permittivity of the free space. Where charge is taken in the unit of coulombs.

The net electric flux cross an open surface can also be zero if the is perpendicular to the direction of the field. In other word if the field lines are parallel to the surface. Electric flux is a scaler quantity. The SI unit of electric flux is N-m²/C.

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triton, the largest moon of neptune, has a retrograde orbit. what does that mean?

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Retrograde orbit means triton orbiting around the neptune in the direction opposite to the direction in which the neptune is rotating.

Retrograde orbit or retrograde motion is that motion of a planet/moon or any other celestial body, in which they rotate opposite to their prime's rotational direction. On the other hand, prograde motion of a moon or object is the rotational motion in the same direction of its primary.

In our solar system, all the planets and other objects, except many comets, prograde around the sun in the same direction in which the sun rotates around its own axis, except Venus and Uranus. However both of the planets' planetary rotational around their own axes are also prograde.

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in a collision between 2 and equal masses, how does the impulse imparted to the smaller mass by the larger mass compare with the impulse imparted to the larger mass by the smaller one? compared to magnitudes of impulses only.

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The impulse imparted to the smaller mass by the larger mass will be equal to the impulse imparted to the larger mass by the smaller mass.

Impulse is the change in momentum. We know the time rate of change of momentum is defined as the force. And force times change in time is impulse. Mathematically,

[(m₁v₁ + m₂v₂) - (m₃v₃ + m₄v₄)]/Δt = F

Impulse = FΔt = (m₁v₁ + m₂v₂) - (m₃v₃ + m₄v₄)

According to Newton's third law, every action has an equal reaction but in the opposite direction. So the force and thereby impulse imparted by the smaller mass to the larger mass will be equal to the impulse imparted by the larger mass to the smaller mass. However after collision velocity will be different for both the masses to conserve the momentum.

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Three protein molecules make up the thin filament.
a. Which molecule has a binding site for myosin heads?_______________________
b. Which molecule covers this binding site?___________________________________
c. Which molecule has a binding site for calcium ions?________________________

Answers

Actin molecule has a binding site for myosin heads, tropomyosin molecule covers this binding site, and troponin molecule has a binding site for calcium ions.

Each globular actin molecule in the thin filaments has a myosin-binding site. The actin molecules are arranged in two long chains and coiled around one another. The myosin binding sites are covered by the tropomyosin protein, which coils itself around the fine filaments.

There is a myosin-binding site on each globular actin molecule in the thin filaments. Actin is composed of two lengthy chains that are coiled around one another. The tropomyosin protein, which coils itself around the tiny filaments, covers the myosin binding sites.

Troponin is a key player in the regulation of muscle contraction by calcium: The only component of the fine filaments in striated muscles that can bind calcium is troponin.

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if an astronaut throws a ball in space with the initial velocity of 3.0 meters per second to the west, what will the ball's velocity be in a year?

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In a vacuum, the velocity of an object thrown in space remains constant unless acted upon by an external force. Thus, the ball's velocity will still be 3.0 meters per second to the west after a year.

In the absence of external forces, the velocity of an object remains constant according to the law of conservation of momentum. This applies to objects in space, where there is no friction or air resistance to slow it down. Therefore, if an astronaut throws a ball with an initial velocity of 3.0 meters per second to the west, it will continue to move in that direction with the same velocity, 3.0 meters per second, one year later. This is assuming no other external forces, such as gravitational forces from nearby celestial bodies, are acting upon the ball.

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Going downhill a driver applies brakes to keep a constant speed. The potential energy of the car is decreasing while the kinetic energy is constant. Explain where the energy is going?

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The potential energy of a car moving with constant speed during downhill converts into heat energy or sound energy during braking.

What is law of conservation of energy?

Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another.

When a car goes downhill, its potential energy decreases but as the driver applied braking, the gain in potential energy lost during work against the frictional force applied by the brake and converts into  heat energy or sound energy during braking.

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explain why only a handful of solids exhibit ferromagnetic or ferrimagnetic behavior

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Ferromagnetic or ferrimagnetic behavior is exhibited by only few solids because of the strong exchange interaction and high concentration of unpaired electrons required, as well as low temperature to prevent thermal disruptions.

Ferromagnetic or ferrimagnetic behavior is a rare phenomenon that is only exhibited by a few solids. This is due to a number of conditions that must be met in order for the material to exhibit this behavior, such as a strong exchange interaction, a high concentration of unpaired electrons, and low temperature to prevent thermal disruptions.

All of these conditions need to be met in order for the ferromagnetic or ferrimagnetic behavior to be present. Therefore, it is important to understand the physics and materials behind this behavior in order to better understand and utilize this phenomenon.

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if light from one star is 15.8 times brighter (has 15.8 times more flux) than light from another star, what is their difference in magnitudes?

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The difference in magnitude of the two stars where one star has 15.8 times more flux than the other star is 2.975.

Luminosity of a star is the rate at which the star radiates energy into the space. Apparent brightness is the rate at which a star's radiated energy into the space reaches an observer on the Earth. Apparent brightness depends on both the luminosity of the star and distance from the star.

Difference in magnitude of stars in terms of luminosity is given by

m₂ - m₁ = -2.5 log (I₂/ I₁)

m₂ - m₁ = -2.5 log (1/ 15.8)

m₂ - m₁ = -2.5(log 1 - log 15.8)

m₂ - m₁ = -2.5 (0 - 1.19)

m₂ - m₁ = -2.5 (-1.19)

m₂ - m₁ = -2.5 × -1.19

m₂ - m₁ = 2.975

Therefore, the difference in magnitude of the two stars is 2.975.

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what would be the escape speed from an object with the mass of the sun, but with a radius of 8,000 meters?

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The sun's escape velocity is roughly 618 km/s.

What is the Sun's escape velocity? It is important to keep in mind that the Sun's escape velocity, which was estimated above, is 615 km/sec, which is more than 50 times faster than the average velocity of H at the Sun's surface. The equation for the escape velocity, vesc, is given by: vesc = Square root of 2GMr, where G is the gravitational constant, M is the mass of the attracting mass, and r is the distance from its center.Deflection Speed.Energy conservation is used to determine the escape velocity:I + k = u + kf.The potential energy of a mass m object at the surface of a planet with radius R and mass M is given by the equation U=-G m M/R.The escape velocity can be calculated using the formula vesc = 2GM/R, where vesc is the escape velocity, G is the gravitational constant, M is the object's mass, and R is the distance from the object's center.

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a light bulb requires a current of 0.70 a to emit a normal amount of light. if the light is left on for 1.0 h, what is the number of electrons that pass through the bulb?

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The number of electrons that pass through the bulb is 0.4375 x 10^19C when a light bulb requires a current of 0.70 a to emit a normal amount of light.

Given the current required for a light bulb (I) = 0.7A

Time for which light is left on (t) = 1h = 3600s

Let the number of electrons that pass through the bulb = n

We know that I = Q/t where Q is the charge flowing through the bulb.

Current is expressed as charge per unit time.

So, Q = I x t = 0.7 x 3600s = 2520C

We know that the charge on an electron (qe) = 1.6X10^-19C

Then, n = I/ 1electron charge = 0.70 / 1.6X10^-19

n = 0.4375 x 10^19C

Hence, the number of electrons that pass through the bulb is 0.4375 x 10^19C.

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A gas with initial state variables p1, V1, and T1 expands isothermally until V2=2V1.By what factor does the temperature change?By what factor does the pressure change?

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The pressure changes by a factor of 2. The initial pressure (p1) is twice the final pressure (p2).

For an isothermal process, the temperature remains constant. Therefore, the factor by which the temperature changes is 1. There is no change in temperature (T2 = T1).

To determine the factor by which the pressure changes, we can use the ideal gas law equation:

pV = nRT

Where:

p = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

Since the process is isothermal, we can rearrange the equation as:

p1V1 = p2V2

Given that V2 = 2V1, we can substitute this into the equation:

p1V1 = p2(2V1)

Simplifying the equation:

p1 = 2p2

Therefore, the pressure changes by a factor of 2. The initial pressure (p1) is twice the final pressure (p2).

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when the motorcyclist is at a , he increases his speed along the vertical circular path at the rate of v˙=(0.04s)ft/s2 where s is in ft . take rho = 300 ft . determine the magnitude of his velocity when he reaches B. Also, what is his initial acceleration?

Answers

The magnitude of his velocity when he reaches at B is 15 ft/s, and his initial acceleration of the motorbike is 0.00013333 ft/s^2.

Given that :-

The radius of the circular path is r = 300 ft,

and the rate of increase of speed is v˙ = 0.04s ft/s^2.

The initial acceleration a_0 of the motorcyclist can be determined by using the formula:-

=> a = v˙ / r,

Hence,

=> a_0

= v˙ / r

= 0.04 s ft/s^2 / 300 ft

= 0.00013333 ft/s^2

At point B, the magnitude of velocity v can be determined by using the formula:-

v = sqrt(v_0^2 + 2 x a_0 x r),

here v_0 is initial velocity.

Since the initial velocity is not given,

let's assume,

v_0 = 0.

Hence,

=> v = sqrt(v_0^2 + 2 x a_0 x r)

= sqrt(0^2 + 2 x 0.00013333 x 300)

= 15 ft/s

Therefore, the magnitude of the velocity at point B is 15 ft/s, and the initial acceleration of the motorcyclist is 0.00013333 ft/s^2.

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Determine the magnitude of the Coulomb force on the tape using the value of tan θ and your equation from the previous exercise for FCoulomb.FCoulomb = .40 x 10^-3 N

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The magnitude of the Scotch tape is 13 0.05 cm, and the linear mass density (d) is 1.44 0.01 g/m.

Given that the length of the Scotch tape is 13 0.05 cm and the linear mass density (d) is 1.44 0.01 g/m, the answers to the following questions calculate the coulomb force, the number of atoms, and the elementary charges.

where r is the distance between the charges, Q1 and Q2 are the magnitudes of the charges on the two pieces of tape, and k is Coulomb's constant. Given that F Coulomb is equal to 0.40 x 10-3 N, we can use the following equation to find the charge, Q: where is the static friction coefficient, which was determined in the preceding exercise.

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how does the distribution of the home voltage compare to the distribution of the generator voltage? in other words, address uniformity, skewness, normality, etc.

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The current is transmitted as an alternating current with a frequency of 50 Hz. The voltage when it arrives at your house is 240 volts. Portable generators provide a current (amps or amperes) at 120 and 240 volts.

Portable generators can supply 12 volts DC, 120 volts AC, or 240 volts AC power, but not all models can supply all three, and some can only supply 120 volts AC. Duplex (twin) outlets are common on portable generators, each supplying 120 volts. Electricity delivered to your home from the power company is 120 and 240 volts. This is called "nominal voltage". This is the voltage measured at the main transformer outside the house. The nominal voltage varies plus or minus 5% under ideal conditions.

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a lightning bolt strikes a tree, moving 23.36 c of charge through a potential difference of 142 mv. what energy was dissipated? 1mv

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Without knowing t, we cannot calculate the current, and thus the energy dissipated.

When a current of I coulombs per second flows across a potential difference of V volts, the rate of energy dissipation is IV, which may alternatively be represented as I2R or V2/R (using Ohm's law).

The energy dissipated by a lightning bolt can be calculated using the equation P = IV,

where P is the power (energy per unit time),

I is the current, and

V is the potential difference.

Given that the lightning bolt moved 23.36 coulombs of charge through a potential difference of 142 millivolts,

we can calculate the current as follows:

I = Q / t

where t is the time it takes for the charge to flow, which is not specified.

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Which one does NOT force air parcels to rise? orographic processes advection frontal movement convection

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Orographic processes  are the ones which does not force the air parcels to rise up.

Orographic processes refer to how mountains and hills affect regional and global weather patterns. Mountains can considerably increase precipitation locally and produce a wide range of intricate flows, a few of which are accompanied by dangerous winds and violent turbulence.

Advection is the movement of a fluid in a bulk manner to transfer a substance or amount in the fields of physics, engineering, and earth sciences. It carries the characteristics of that substance with it. The bulk of the advected substance is often a fluid as well.

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Which is the formula that describes the magnitude of an
momentum?
object's

Answers

Answer:

The magnitude of the momentum of an object is p = mv.

Explanation:

Here, m is the mass of the object and v is the velocity of the object. This quantity attributes both quantities, and is defined by Newton as the product of them.

a car is traveling at a speed of 34 m/s. (a) what is its speed in kilometers per hour? km/h

Answers

The car is traveling at a speed of 34 m/s. Its speed in kilometres per hour is calculated to be 122.4 km/h.

Speed is the rate at which an object's position shifts in any direction.

By dividing the distance by the time, one may calculate speed. Calculating the units for speed requires knowledge of the units for both time and distance. The units in this example will be meters per second (m/s), due to the fact that the distance is expressed in metres (m) and the time is expressed in seconds (s).

1 h = 3600 s

1 km = 1000 m

s₂ = (34 m/s) × (60×60)/1000

⇒ 122.4 km/h

s₂ = 122.4 km/h

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Which would the community health nurse be least likely to include when designing a community-based program within the context of a global framework?
A) Population
B) Provider
C) Procedure
D) Physician

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Physician community health nurse be least likely to include when designing a community-based program within the context of a global framework. Correct option is A.

The community health nurse, when designing a community-based program within the context of a global framework, is least likely to include the physician. Community health nurses work with individuals, families, and communities to promote health and prevent disease. They focus on educating and empowering people to make informed health decisions, and engage in activities such as disease screening, health promotion, and environmental health assessments. Community health nurses may collaborate with other healthcare providers, including public health departments, community organizations, and schools, but physicians are typically not involved in the design and implementation of community-based health programs. The focus of a community health nurse's work is on the community, not individual medical care.

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Show how to balance 3 masses hanging from a force table. (There is not a fourth mass to add). The masses are 3 kg, 4 kg, and 6 kg. You need to indicate the angles between the strings that will cause all of the masses to be all be in equilibrium.

Answers

Assuming the force table is set up so that the masses are placed at the vertices of an equilateral triangle, the angles between the strings should be 60 degrees.

How to balance 3 masses hanging from a force table?This will cause all of the masses to be in equilibrium.The angles between the strings can be calculated using the following formula:Angle = arccos ((m1*m2) / (m3*(m1+m2))) For this problem, the angles between the strings will be:Angle 1 = arccos ((3*4) / (6*(3+4))) = arccos (0.8) = 61.93° Angle 2 = arccos ((3*6) / (4*(3+6))) = arccos (0.75) = 56.31°Angle 3 = 180° - (Angle 1 + Angle 2) = 180° - (61.93° + 56.31°) = 61.76°Assuming the force table has four support points, the three masses can be balanced by adjusting the angles between the strings. To do this, the three masses must be arranged as far as possible from one another, with the 3 kg mass in the center and the other two masses, 4 kg and 6 kg, on the outside. To begin, the 4 kg mass should be suspended to the left of the 3 kg mass, and the 6 kg mass should be suspended to the right. The angle between the strings should be adjusted so that the 4 kg mass is suspended at an angle of 25 degrees, and the 6 kg mass is suspended at an angle of 155 degrees. This will ensure that the three masses are balanced, with the force exerted by the 4 kg mass equal to the force exerted by the 6 kg mass. To achieve equilibrium, the 3 kg mass should be suspended at an angle of 90 degrees from the 4 kg mass, and the 6 kg mass should be suspended at an angle of 90 degrees from the 3 kg mass. This will ensure that the forces acting on the 3 kg mass are equal, and the forces acting on the 4 kg and 6 kg masses are equal. This will result in a balanced system.

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an airplane flies eastward and always accelerates at a constant rate. at one position along its path, it has a velocity of 33.3 m/s . it then flies a further distance of 49700 m , and afterwards, its velocity is 43.5 m/s . find the airplane's acceleration. acceleration: m/s2 calculate how much time elapses while the airplane covers those 49700 m.

Answers

The acceleration of the airplane is [tex]7.88\times 10^{-3} m/s^2[/tex] and the time elapsed while the airplane covers [tex]49700[/tex] [tex]m[/tex] is [tex]1294.42s[/tex].

Let us consider the value of acceleration is [tex]a[/tex] [tex]m/s^2[/tex] and the time elapsed while the airplane covers [tex]49700[/tex] [tex]m[/tex] is [tex]t[/tex] [tex]s[/tex].

It is given that,

The initial velocity of the airplane, [tex]u=33.3 m/s[/tex].

The final velocity of the airplane, [tex]v=43.5m/s[/tex].

The distance covered by the airplane, [tex]s=49700 m[/tex].

It is known that, [tex]v^2=u^2+2as[/tex].

[tex]\Rightarrow (43.5)^2=(33.3)^2+2a(49700)[/tex]

[tex]\Rightarrow 1892.25=1108.89+99400a[/tex]

[tex]\Rightarrow 1892.25-1108.89=99400a[/tex]

[tex]\Rightarrow 783.36=99400a[/tex]

[tex]\Rightarrow a=\frac{783.36}{99400}[/tex]

[tex]a=7.88\times 10^{-3} m/s^2[/tex]

Hence, the acceleration of the airplane is [tex]7.88\times 10^{-3} m/s^2[/tex].

It is known that, [tex]v=u+at[/tex].

[tex]\Rightarrow 43.5=33.3+(7.88\times10^{-3})t[/tex]

[tex]\Rightarrow 43.5-33.3=(7.88\times10^{-3})t[/tex]

[tex]\Rightarrow 10.2=(7.88\times10^{-3})t[/tex]

[tex]\Rightarrow t=\frac{10.2}{7.88\times10^{-3}}[/tex]

[tex]\Rightarrow t=1294.42 s[/tex]

Hence, the time elapsed while the airplane covers [tex]49700[/tex] [tex]m[/tex] is [tex]1294.42s[/tex].

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A baseball is thrown up in the air from an initial height of 6 feet. Its height above the ground (in feet) t seconds after being thrown is given by the function h(t)=-16t²+46t+6. How long will it take (in seconds) for the baseball to hit the ground? a) 4 seconds b) 5/2 seconds
c) 2 seconds
d) 3 seconds

Answers

From a starting height of six feet, a baseball is hurled upward. Its height above the ground (in feet) t seconds after being thrown is given by the function h(t)=-16t²+46t+6. It take 2 seconds for the baseball to hit the ground. Hence, the correct option is (c).

The baseball hits the ground when the height is 0. Thus, solving h(t)=-16t^2 + 46t + 6 = 0:

-16t^2 + 46t + 6 = 0

Using the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / 2a

Where a = -16, b = 46, c = 6

t = (-46 ± √(46^2 - 4 x -16 x 6)) / 2 * -16

t = (-46 ± √(46^2 + 384)) / -32

t = (-46 ± 2√190) / -32

t = (46 ± 2√190) / 32

t ≈ 2 seconds

So, the baseball will hit the ground approximately 2 seconds after it was thrown.

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a 12-volt electric motor has 1,000 watts input and 1 horsepower output. maintaining the same efficiency, how much input power will a 24-volt, 1-horsepower electric motor require? (note: 1 horsepower

Answers

The electric motor will require 1,000 watts input power. The result is obtained by comparing the formula for efficiency.

What is efficiency?

Efficiency of an engine can be expressed as

η = P out/ P in

Where

P out = output powerP in = input power

Power is the amount of energy per unit of time.

An electric motor has

V = 12 VoltP₁ in = 1,000 wattsP₁ out = 1 horsepower

With the same efficiency, the electric motor has

V = 24 voltP₁ out = 1 horsepower

Find output power! (P₂ in = ?)

1 horsepower = 746 watts

The efficiency is the same

η₁ = η₂

P₁ out/ P₁ in = P₂ out/ P₂ in

1 hp/ 1,000 watts = 1 hp/ P₂ in

P₂ in = 1,000 watts

Hence, the required input power of the electric motor is 1,000 watts.

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explain the arrangements of molecular magnets in a magnet and in a magnetic substance ​

Answers

: Molecular magnet can refer to : molecular based magnet . An unconventional magnetic material that consists of organic molecules cordination compounds and combination

determine the proper units for momentum using dimensional analysis. (b) the unit of force is the newton n, where 1 n 5 1 kg ? m/s2 . what are the units of momentum p in terms of a newton and another fundamental si unit?

Answers

The unit of momentum is kg-m/sec, and the unit of momentum in terms of Newton is N-s.

The momentum of an object is the vector product of the mass of the object and its velocity. It is denoted by P. It is a vector quantity.

P = mv

So its unit will be (kg) × (m/s) = kg-m/s

We also know that the time rate of change of momentum is called force,

F = ΔP/Δt

ΔP = FΔt = Force × change in time

So the SI unit of momentum in terms of Newton will be, N × Sec = N-s

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They continue the discussion, and Imad makes several comments. Which of Imad's comments is false?A. "Electric field lines never cross each other."B. "At locations where electric field lines meet the surface of an object, the lines are parallel to the surface."C. "Electric field lines always extend from a positively charged object to a negatively charged object, from a positively charged object to Infinity, or from Infinity to a negatively charged object."D. "Electric field lines are most dense around objects with the greatest amount of charge."

Answers

The false statement among Imad's comments is D. "Electric field lines are most dense around objects with the greatest amount of charge." Therefore,  option D is correct.

The density of electric field lines does not indicate the amount of charge on an object. The density of electric field lines represents the strength or intensity of the electric field at a given point. Electric field lines are closer together where the electric field is stronger, and farther apart where the electric field is weaker.

The density of electric field lines depends on factors such as the magnitude of the charge and the distance from the charged object.

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pavlina does not consider the other cars that she has seen speeding when she says that people in red cars are much more likely to speed.

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Pavlina does not consider the other cars that she has seen speeding when she says that people in red cars are much more likely to speed.  This illustrate Present or Present bias.

Speed is a scalar quantity, whereas velocity, which includes both magnitude and direction definitions, is speed's vector form. Speed is expressed as either the average speed for the entire distance travelled or the instantaneous speed at that specific moment.

Speed can also be described in terms of a period of time or a distance, and it can change with time. Speed is defined as the rate at which an object's position changes.

In everyday usage, we refer to speed as the amount by which an object moves, while in science, speed is defined as the rate at which an object changes its location in relation to time.

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Complete Question:

Pavlina does not consider the other cars that she has seen speeding when she says that people in red cars are much more likely to speed. What type of bias does this illustrate?

describe how an electron can move to a higher energy state by absorbing a fixed quantum of energy. describe how an electron can move to a lower energy state by releasing a fixed quantum of energy.

Answers

Bohr proposed a concept in which electrons would move around in shells, with each shell containing a different number of electrons with a fixed amount of energy. Energy is lower in the lower shell and more in the upper shell. When an electron moves from a lower shell to a higher shell, it loses energy in the process. It must absorb energy.

The ground state is the lowest energy level an electron can have. An increased number of orbitals indicates a more excited state. The greater the electron's excitation state, the greater its energy. An electron will "jump" to a higher orbital when it absorbs enough energy. In this form, the system is said to be in an excited state. An electron in an excited state can "fall" to a less excited state by releasing energy. In doing so, it emits a photon, a discrete packet of electromagnetic energy. The energy of that photon is proportional to the gap between the electron's two states. The electron loses its ability to emit photons when it enters the ground state, but it retains the ability to absorb energy quanta and enter higher excitation states (higher orbitals).

The electron's freedom of motion is proportional to the number of energy levels it can experience. There is exactly one potential state transition between a single ground state and a single excitation state. Electrons can gain enough energy to enter the excited state by absorbing a single quantum of energy. Upon decaying from its excited state, the electron releases a photon of a constant energy equal to the energy it lost upon entering the lower orbital.

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For an infinitely large plane wall with thickness L, assuming 1D heat transfer, what can you say about the rate of heat conduction?
A. It is a constant everywhere.
B. It is a constant along the plane normal to the direction of heat transfer, but varies along the direction of heat transfer.
C. It varies in time.
D. None of the above.

Answers

None of the given option is correct about the rate of heat transfer through an infinitely large plane wall of length L.

The rate of heat transfer is directly proportional to the area of the surface and the temperature different between the two sides of the object.

Q/t = -KAdT/dx

Here K is the constant depends upon the type of material, A is the area of surface, and dT/dx is the temperature gradient. So we cannot say that it is constant everywhere, because as the heat getting transfer other side the temperature gradient will go on decreasing. In addition to this it is not constant along the plane. Also  it does not varies with time. So option D is correct.

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