If two triangles have equal perimeters, then they could also have which of the following? Select all that apply.

equal heights
equal bases
equal volumes
equal areas

Answers

Answer 1

Answer:

Equal heights, equal bases, and equal areas.

Step-by-step explanation:


Related Questions

write an equation in slope-intercept form of the line that passes through the points (-2,3) and (2,7)

Answers

your equation is y= x + 5

Data were collected on the ages, in years, of the men and women enrolled in a large sociology course. Let the random variables M and W represent the ages of the men and women, respectively. The distribution of M has mean 20.7 years and standard deviation 1.73 years. The distribution of W has mean 20.2 years and standard deviation 1.60 years. Of all of those enrolled in the course, 54 percent are men and 46 percent are women. What is the mean age of the combined distribution of both men and women in the course? (A) 20.2 years (B) 20.43 years (C) 20.45 years (D) 20.47 years (E) 40.9 years

Answers

The answer is  20.45 years. The mean age of the combined distribution of both men and women in the course is approximately 20.45 years.(Option-c)

Since we know the percentages of men and women enrolled in the sociology course, we can use them to calculate the weighted average of the mean ages for men and women.

Let the combined distribution of both men and women be represented by the random variable X. We know that X is a weighted average of the mean ages for men and women, with weights equal to their respective percentages. That is:

X = 0.54*M + 0.46*W

We're asked to find the mean age of X. To do that, we need to find the expected value of X, which is the same as the mean of X. So we need to calculate E(X):

E(X) = E(0.54*M + 0.46*W)

By linearity of expectation, we know that:

E(aX + bY) = aE(X) + bE(Y)

So we can simplify E(X) as:

E(X) = 0.54*E(M) + 0.46*E(W)

We're given the mean ages for M and W, so we can substitute these values into the equation:

E(X) = 0.54*20.7 + 0.46*20.2

Simplifying, we get:

E(X) = 20.45 years (option-c)

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Which classification describes the following system of equations?

inconsistent and dependent
consistent and dependent
consistent and independent
inconsistent and independent

Answers

Step-by-step explanation:

take the 1st eqn n divide it throughout by 3, the 3rd eqn n divide throughout by 4, all 3 equations will be the same as the 2nd one

The classification which best describes the system of equations is; Consistent and dependent

Discussion:

A linear or nonlinear system of equations as the case may be is termed consistent if there is at least one set of values for the unknowns that satisfies each equation in the system. In essence, when substituted into each of the equations, they make each equation hold true.

Additionally, the system of equations is dependent because the value of each variable is dependent on the others.

Therefore, when equation 1 and 3 are divided by 3 and 4 respectively; the equations become similar to equation 2.

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Suppose M is the midpoint of PQ. If PM=6x-49 and MQ=47-2x, find PQ
Please halp

Answers

Answer:

PQ = 46

Step-by-step explanation:

PM = 6x - 49

MQ = 47 - 2x

6x - 49 = 47 - 2x

8x - 49 = 47

8x = 96

x = 12

PM = 6x - 49

      = 6(12) - 49

      = 23

MQ = 47 - 2x

      = 47 - 2(12)

      = 47 - 24

      = 23

PQ = PM + MQ

     = 23 + 23

     = 46

What’s the equation for

3/9 + 2/3

Answers

Answer:

1

Step-by-step explanation:

3/9 + 2/3

Simplify the first fraction by dividing the top and bottom by 3

1/3 + 2/3

Since the denominators are the same, add the numerators

3/3

1

Some people advise that in very cold​ weather, you should keep the gas tank in your car more than half full. ​'s car had5.4 gallons in the ​12-gallon tank on the coldest day of the year. Filled the tank with gas that cost ​$3.60 per gallon. How much did spend on​ gas?

Answers

Answer:

$19.44

Step-by-step explanation:

5.4 gallons in the ​12-gallon tank on the coldest day of the year.

1 gallon = $3.60

5.4 gallons = x

Cross Multiply

x = 5.4 gallons × $3.60 /1 gallon

x = $19.44

Therefore, you spent $19.44 on gas

a salesperson contacts eight potential customers per day. from past experience, we know that the probability of a potential customer making a person is 0.10. what is the probability the saelesperson will make exactly two sales in a day

Answers

In this problem, the salesperson contacts 8 potential customers per day and the probability of a potential customer making a purchase is 0.10.

We have to find the probability that the salesperson will make exactly two sales in a day. This is a binomial probability problem. The binomial probability distribution is a discrete probability distribution that is used when the outcome of an experiment is binary, i.e., it can take only two values. The binomial probability distribution is characterized by two parameters: n and p. The parameter n is the number of trials in the experiment, and p is the probability of success in each trial. In this problem,

n = 8, and p = 0.10.

To find the probability of exactly two successes in 8 trials, we can use the formula:

P(X = k) = nCk * p^k * (1 - p)^(n-k)

where X is the random variable that represents the number of successes in n trials, k is the number of successes we want to find, nCk is the number of combinations of n items taken k at a time, and p is the probability of success in each trial.Using this formula, we get:

P(X = 2) = 8C2 * (0.10)^2 * (0.90)^(8-2)= 28 * 0.01 * 0.43046721= 0.0120936

Therefore, the probability that the salesperson will make exactly two sales in a day is 0.0120936 or about 1.21%.

Thus, the salesperson will make exactly two sales in a day with a probability of 0.0120936 or about 1.21%.

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If Taylor uses 1 3/4 tablespoons of coffee to make 5 cups of coffee, how much would he need to make one cup of coffee?

Answers

.35 or 7/20 is your answer

Solve the formula for the indicated variable.
The formula for the perimeter P of a triangle with sides of length a,b, and c is P=a+b+c. Solve the formula for b.

Answers

Answer: b = p - a -c  

Step-by-step explanation:

p= a + b + c  Solving for b means getting b on one side by itself.

p = a + b + c    To solve for b first subtract a from both sides to get,

-b         -b

p - a =  b + c   Now subtract  c from both sides   to get

-c              -c

p - a - c = b

b = p - a -c

Answer:

b = P - a - c

Step-by-step explanation:

Perimeter P = a + b + c

find b

P - a - c = b

b = P - a - c

A number p, when truncated to 1 decimal place, is equal to 14.3
Find the upper and lower bound of p.
Lower bound =
Upper bound=
Submit Answer

Answers

The lower bound of [tex]\(p\) is \(14.25\)[/tex] and the upper bound is [tex]\(14.35\).[/tex]

The given truncated number is [tex]\(14.3\)[/tex]. To find the upper and lower bounds of [tex]\(p\)[/tex], we need to consider the possible range of values that could round to [tex]\(14.3\)[/tex] when truncated to 1 decimal place.

Lower bound: To find the lower bound, we need to consider the greatest number that rounds down to [tex]\(14.3\)[/tex]. This is obtained by subtracting 0.05 from the given truncated number:

[tex]\(\text{{Lower bound}} = 14.3 - 0.05 = 14.25\)[/tex]

Upper bound: To find the upper bound, we need to consider the smallest number that rounds up to [tex]\(14.3\)[/tex]. This is obtained by adding 0.05 to the given truncated number:

[tex]\(\text{{Upper bound}} = 14.3 + 0.05 = 14.35\)[/tex]

Therefore, the lower bound of [tex]\(p\) is \(14.25\)[/tex] and the upper bound is [tex]\(14.35\).[/tex]

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Solve two and one-third times two and three fourths.

A four and three twelfths
B six and five twelfths
C seven and five twelfths
D eight and three twelfths
E nine and 8 twelfths

Answers

the answer is B, 6 and 5/12

Answer:

B

Step-by-step explanation:

Hope this helps

DonaldandLauracompetedina1kmrace.DonaldcompletedtheraceinCCVII seconds and Laura completed it in CCCXLVIII seconds. By how many seconds (in Roman numerals) was Donald ahead of Laura?
a. DLV b. CXLIV c. CXL d. CXLI

Answers

Answer: D

Steps: CXLI = 141 seconds

Plz mark brainliest:)

what is the radius of a circle in which the distance from the center of the circle to the edge of the circle is 4

Answers

The distance from the center of a circle to the edge is called the radius of the circle. In this case, the distance is given as 4 units.

Therefore, the radius of the circle is 4 units.

The formula for the circumference of a circle is C = 2πr, where C is the circumference and r is the radius. If you want to find the circumference of the circle, you can use this formula by substituting the radius value.

The radius of a circle is the distance from the center of the circle to any point on the edge of the circle. If the distance from the center of the circle to the edge of the circle is 4, then the radius of the circle is 4.

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who can answer all my math questions right?

Answers

Answer:

I can

Step-by-step explanation:

i can

I might be able to :)

Learning Task 3. Solve for the variable of the following quadratic equations
A. by extracting square roots.
1. x2 = 169
4. (x - 2)2 = 16
2. 9b2 = 25
5. 2(t - 3)2 - 72 = 0
3. (3y - 1)2 = 0
B. by factoring
1. x2 + 7x = 0
3. x2 + 5x - 14 = 0
2. m2 + 8m = -16
4. 2y2 +8y - 10= 0
C. by completing the square.
1. x2 + 5x + 6= 0
2. x2 + 2x = 8
3. 2x2 + 2x = 24
D. using quadratic formula.
1. x2 + 5x = 14
2. 2x2 +8x - 10= 0
3. 2x2 + 3x = 27​

Answers

Answer:

A. By extracting square roots

1. x = 13

4. x = 6

2. b = 5/3

5. t = 9

3. y = 1/3

B. By factoring

1. x = -7

3. x = -7 or x = 2

2. m = -8 or m = -2

4. y = -5 or y = 1

C. By completing the square

1. x = 2 or x = 3

2. x = 10 or x = -8

3. x = 3 or x = -4

D. Using the quadratic formula

1. x = 2 or x = -7

2. x = 1 or x = -5

3. x = 3 or x = -4.5.

Step-by-step explanation:

A. By extracting square roots

1. x² = 169

Extracting square roots from both sides of the equation gives;

√(x²) = x and √169 = 13

∴ √(x²) = √169 = 13

x = 13

4. (x - 2)² = 16

Extracting square roots from both sides of the equation gives;

√(x - 2)²= √16 = 4

However;

√(x - 2)² = x - 2

∴ x - 2 = √16 = 4

x - 2 = 4

x = 4 + 2 = 6

x = 6

2. 9·b² = 25

√(9·b²) = √25 = 5

√(9·b²) = √9 × √(b²) = 3·b

∴ 3·b = √25 = 5

3·b = 5

b = 5/3

5. 2·(t - 3)² - 72 = 0

2·(t - 3)²  = 72

(t - 3)²  = 72/2 = 36

t - 3 = √36 = 6

t = 6 + 3 = 9

t = 9

3. (3·y - 1)² = 0

√(3·y - 1)² = √0

∴ 3·y - 1 = 0

3·y = 0 + 1 = 1

y = 1/3

B. By factoring

1. x² + 7·x = 0

By factoring, we have;

x·(x + 7) = 0

(x + 7) = 0/x = 0

x + 7 = 0

x = 0 - 7 = -7

x = -7

3. x² + 5·x - 14 = 0

Noting that 7 × (-2) = -14 and 7 + (-2) = 5, we get;

x² + 5·x - 14 = (x + 7)·(x - 2) = 0

∴ x = -7 or x = 2

2. m² + 8·m = -16

m² + 8·m + 16 = 0

Which gives;

m² + 8·m + 16 = (m + 8) × (m + 2) = 0

m = -8 or m = -2

4. 2·y² + 8·y - 10 = 0

Which gives;

2·(y² + 4·y - 5) = 0

y² + 4·y - 5 = 0/2 = 0

y² + 4·y - 5 = (y + 5) × (y - 1) = 0

y = -5 or y = 1

C. By completing the square

1. x² + 5·x + 6 = 0

x² + 5·x =  -6

Adding (5/2)² to both sides of the equation gives;

x² + 5·x + (5/2)² =  -6 + (5/2)²

Which gives;

(x + 5/2)² =  -6 + (5/2)² = 1/4

x + 5/2 = ±√(-6 + (5/2)²) = ±√(1/4)

x + 5/2 = ±1/2

x = 5/2 - 1/2 or x = 5/2 + 1/2

∴ x = 2 or x = 3

2. x² + 2·x = 8

x² + 2·x + (2/2)² = 8 + (2/2)²

2/2 = 1 and (2/2)² = 1² = 1

∴ x² + 2·x + (2/2)² = 8 + (2/2)² gives;

x² + 2·x + 1 = 8 + 1 = 9

(x + 1)² = 9

x + 1 = ±√9

x = 1 + 9 or x = 1 - 9

x = 10 or x = -8

3. 2·x² + 2·x = 24

2·(x² + x) = 24

x² + x = 24/2 = 12

x² + x = 12

x² + x + (1/2)² = 12 + (1/2)²

(x + 1/2)² = 12 + (1/2)² = 49/4

√(x + 1/2)² = √(49/4) = ±7/2 = ± 3.5

x + 1/2 = ±3.5

x = -1/2 + 3.5 or x = -1/2 - 7/2

x = -0.5 + 3.5 or x = -0.5 - 3.5

x = 3 or x = -4

D. Using the quadratic formula

1. x² + 5·x = 14

Simplifying, gives;

x² + 5·x - 14 = 0

The quadratic formula for the equation, a·x² + b·x + c = 0, is given as follows;

[tex]x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}[/tex]

Comparing with the equation in the question, we get;

[tex]x = \dfrac{-5\pm \sqrt{5^{2}-4\times 1\times(-14)}}{2\times 1} = \dfrac{-5\pm \sqrt{81}}{2} = \dfrac{-5\pm 9}{2} = \dfrac{-5+ 9}{2} \ or \dfrac{-5 - 9}{2}[/tex]

x = 4/2 or x = -14/2

x = 2 or x = -7

2. 2·x² + 8·x - 10 = 0

quest

2. 2·x² + 8·x - 10 = 0

[tex]x = \dfrac{-8\pm \sqrt{8^{2}-4\times 2\times(-10)}}{2\times 2} = \dfrac{-8\pm \sqrt{144}}{4} =\dfrac{-8+ 12}{4} \ or \dfrac{-8 - 12}{4}[/tex]

x = 4/4 or x = -20/4

x = 1 or x = -5

3. 2·x² + 3·x = 27

Rewriting the above equation in the form a·x² + b·x + c = 0, we get;

2·x² + 3·x - 27 = 0

Which gives;

[tex]x = \dfrac{-3\pm \sqrt{3^{2}-4\times 2\times(-27)}}{2\times 2} = \dfrac{-3\pm \sqrt{225}}{4} =\dfrac{-3+ 15}{4} \ or \dfrac{-3 - 15}{4}[/tex]

x = 12/4 = 3 or x = -18/4 = -4.5

x = 3 or x = -4.5.

Identify the type of function represented by the equation y = – 3.

a
absolute value
b
quadratic
c
constant

Answers

I think the answer of this question is number b. quadratic

Need help please!!!!!

Answers

Answer:

AAS

Step-by-step explanation:

Answer:

EZ 3rd one think bout it commmon since

Step-by-step explanation:

4
B
5
1
n
In Exercises 18-21,use the following information to find the distance
between the point and the line.
The distance d between the point (x,y) and the line Ax + By = Cis d =
AX, + By, - c

Answers

Icant understand that sorry
Umm are you done with it

The ages (years) of three government officials when they died in office were 56, 46, and 60. Complete parts (a) through () a. Assuming that 2 of the ages are randomly selected with replacement, list the difflerent possible samples O A. (56,56), (56,46),(56,60),(46,46),(46,60),(60,60) ○ B. (56,46),(56,60),(46,56),(46.60)·(00,56),(60A6) O C. (56,46),(56,60),(46,60) O D. (56,56), (56,46)(56,60),(46,56),(46,46),(46,60),(60,56),(60,46),(60,60) b. Find the range of each of the samples, then summarize the sampling distribution of the ranges in the format of a table representing the probability distribution Sample Range Probability Type an integer or a fraction.) c. Compare the population range to the mean of the sample ranges Choose the correct answer below

Answers

a) The different possible samples, assuming 2 ages are randomly selected with replacement, are:

A. (56, 56), (56, 46), (56, 60), (46, 46), (46, 60), (60, 60)

B. (56, 46), (56, 60), (46, 56), (46, 60)

C. (56, 46), (56, 60), (46, 60)

D. (56, 56), (56, 46), (56, 60), (46, 56), (46, 46), (46, 60), (60, 56), (60, 46), (60, 60)

b) To find the range of each sample, we subtract the minimum age from the maximum age. The sampling distribution of the ranges can be summarized in the following table representing the probability distribution:

Sample Range  Probability

2               2/9

10              3/9

14              3/9

c) To compare the population range to the mean of the sample ranges, we need the population range. Since the given information only provides the ages of the government officials when they died, the population range cannot be determined. Therefore, we cannot compare the population range to the mean of the sample ranges.

Note: The actual range of the population would depend on the complete set of ages of government officials, which is not provided in the given information.

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What am I supposed to do? Is it subtract 180 from 56?

Answers

If BD is a bisector, then angles 1 and 2 are equal. Since they’re the only two angles within 56/2 = 28

Can you show me how to answer this question?

Answers

Answer:

Rollerskates: 9 miles/hr

Bike: 17.5 miles/hr

Step-by-step explanation:

How fast→ referring to speed

Speed= distance/ time

Rollerskates:

Distance= ¾ mile

Time= 5 mins

Since the question wants the speed to be in miles per hour, convert the time from minutes to hours.

60 mins= 1 hr

1 min= 1/60 hr

Time= 5/60 hr

Speed

[tex] = \frac{3}{4} \div \frac{5}{60} \\ = \frac{3}{4} \times \frac{60}{5} \\ = 9 \: miles/hr[/tex]

Bike:

Distance= 3.5 miles

Time

= 12 mins

= 12/60 hr

= ⅕ hr

Speed

= distance ÷ time

= 3.5 ÷ ⅕

= 3.5 ×5

= 17.5 miles/hr


Which is the equation of the graphed line written in
standard form?

Answers

Answer:

D the slope of the line is 1/2 and the y intercept is 0 so the answer is y = 1/2x + 0 or just y = 1/2x

Use Euler's method with step size 0.5 to compute the approximate y-values y1≈y(0.5),y ≈y(1),y3≈y(1.5), and y4 ≈y(2) of the so y′=2−3x+2y,y(0)=3. y1=y2=y3=y4=y-values y1≈y(0.5),y2≈y(1),y3≈y(1.5), and y4≈y(2) of the solution of the initial-value problem y′ =2−3x+2y,y(0)=3

Answers

We are given a differential equation with an initial value problem. We will be using Euler's method to compute the approximate y-values of the solution at different x-values with the given step size.

Using the given differential equation: y′ =2−3x+2y, we know that y(0) = 3.We need to compute the approximate y-values of the solution at different x-values with the given step size of 0.5. To do that we will be using Euler's method. The Euler's method is as follows:

y1 = y0 + h(y′0)

where,y0 = 3 (initial value of y at x = 0)h = 0.5 (step size)

y′0 = 2−3x0+2y0 (the differential equation at x0 = 0, y0 = 3)

y1 = 3 + 0.5(2 - 3(0) + 2(3))= 6y2 = y1 + h(y′1)

where,y1 = 6 (the value of y at x = 0.5)

y′1 = 2−3x1+2y1 (the differential equation at x1 = 0.5, y1 = 6)

y2 = 6 + 0.5(2 - 3(0.5) + 2(6))= 12y3 = y2 + h(y′2) where,y2 = 12 (the value of y at x = 1)

y′2 = 2−3x2+2y2 (the differential equation at x2 = 1, y2 = 12)

y3 = 12 + 0.5(2 - 3(1) + 2(12))= 22y4 = y3 + h(y′3)

where,y3 = 22 (the value of y at x = 1.5)

y′3 = 2−3x3+2y3 (the differential equation at x3 = 1.5, y3 = 22)

y4 = 22 + 0.5(2 - 3(1.5) + 2(22))= 36

Thus, we used the Euler's method with step size 0.5 to compute the approximate y-values of y1≈y(0.5), y2≈y(1), y3≈y(1.5), and y4 ≈y(2) of the solution of the initial-value problem y′ =2−3x+2y, y(0) = 3.

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Find the value of X.


3(4x + 8) = - 35+23​

Answers

Answer:

x = -3

Step-by-step explanation:

3(4x + 8) = - 35+23​

Combine like terms

3(4x + 8) =-12

Divide by 3

3/3(4x + 8) = -12/3

4x+8 = -4

Subtract 8 from each side

4x+8-8 = -4-8

4x = -12

Divide by 4

4x/4 = -12/4

x = -3

Answer:

x= -3

Step-by-step explanation:

first distribute 3 into the parenthesis

than it will result in 12x+24=-35+23. Than add -35+23

Than it will result in 12x+24=-12. Than subtract 24 from each sides.

This will result in 12x=-36. Than divide 12/-36 than you get -3 for x

u got snap and wanna ft breanna_8406

Answers

Answer:

hiiiii

Step-by-step explanation:

Answer:

-.-_-.- rlly dont use this just to find friends

Step-by-step explanation:

Alex and 4 of his friends are planning to split the cost of lunch. they want to spend at most $6 dollars per person. write and solve an inequality to find the maximum cost of the lunch they can order.

Answers

Answer:

They can order ≤ $24 in order for the inequality to be correct

2) Suppose the probability distribution for the one-period return of some asset is as follows: Retur Probability 0.27 0.25€ 0.18 0.25+ 0.10 0.30 0.04 0.20+ b. What is this asset's variance and stand

Answers

The asset's variance is approximately 0.0358, and its standard deviation is approximately 0.1891.



To calculate the variance and standard deviation of the asset's returns, we'll follow the steps mentioned earlier using the given probability distribution:

⇒ Calculate the expected return (μ):

μ = (0.27 * 0.25) + (0.18 * 0.25+) + (0.10 * 0.30) + (0.04 * 0.20+)

  = 0.0675 + 0.045 + 0.03 + 0.008

  = 0.1505

⇒ Calculate the variance (σ^2):

σ^2 = [(0.27 - μ)^2 * 0.25] + [(0.18 - μ)^2 * 0.25+] + [(0.10 - μ)^2 * 0.30] + [(0.04 - μ)^2 * 0.20+]

Substituting the values and simplifying:

σ^2 = [(0.27 - 0.1505)^2 * 0.25] + [(0.18 - 0.1505)^2 * 0.25+] + [(0.10 - 0.1505)^2 * 0.30] + [(0.04 - 0.1505)^2 * 0.20+]

    = [(0.1195)^2 * 0.25] + [(0.0295)^2 * 0.25+] + [(-0.0505)^2 * 0.30] + [(-0.1105)^2 * 0.20+]

    = 0.017972 + 0.00021617 + 0.0030309025 + 0.01459516

    = 0.0358141325

⇒ Calculate the standard deviation (σ):

σ = √(σ^2)

  = √(0.0358141325)

  ≈ 0.1891

Therefore, the asset's variance is approximately 0.0358 and the standard deviation is approximately 0.1891.

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The math club decided to have a car wash to raise money for competition expenses The graph below shows the relationship between cars washed and earnings (in dollars).



What is the domain of the graphed function?



Group of answer choices

A) -20≤y≤40,where x≥0

B)-20≤y≤40, where y is all integers

C)0≤x≤12, where x≥0

D)0≤x≤12, where x is all non-negative integers

Answers

Answer:

b

Step-by-step explanation:

The domain of the graph is the value on the x-axis. Domain = 0≤y≤50,where x≥0

Since we are not given the required graph. I am going to explain in a general way that is applicable to any form of a graph

Domains are input values of a function for which the function exists.

For a graph, they are values of the curve or line function along the x-axis.

Using the attached graph for instance. The domain of the graph is the value on the x-axis. Domain = 0≤y≤50,where x≥0

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Which equation has non-real solutions

Answers

Answer: bro u need to give us the answer choices not just the answer

Step-by-step explanation:

I need help ASAP please!!!!!!

Answers

Answer:

1. d

2. c

3. b

4. a

Step-by-step explanation:

Answers:

1. d

2. c

3. b

4. a

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Explanation:

For problem 1, subtracting a negative is the same as adding a positive. The two negatives cancel out

In problem 2, we can add a negative to mean we're subtracting. One way to think of it is like adding on debt to your bank balance.

Problem 3 is similar to problem 2. The first term -17 isn't changed.

Problem 4 is similar to problem 1. The only difference is that the 17 is negative this time around.

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