Answer:
The translation is;
[tex]T(x,y)=(x-5,y-6)[/tex]Explanation:
Given the translation rule;
[tex]T(x,y)=(x+5,y+6)[/tex]when P' is the image of P.
For the inverse, when P is the image of P', the Translation rule would become;
[tex]\begin{gathered} x=x^{\prime}+5 \\ x^{\prime}=x-5 \\ y=y^{\prime}+6 \\ y^{\prime}=y-6 \\ So,\text{ the translation rule becomes;} \\ T(x,y)=(x-5,y-6) \end{gathered}[/tex]The translation is;
[tex]T(x,y)=(x-5,y-6)[/tex]Find the missing value. X 5 3 3 6 equal
Similar triangles
The image provided with the question shows 3 similar triangles. The lines of length a, m, and 5 are parallel, so the lengths are proportional
The proportionality can be written as:
[tex]\frac{3}{2}=\frac{3+6}{2+4}=\frac{3+6+3}{x+4+2}[/tex]Operating:
[tex]\frac{3}{2}=\frac{9}{6}=\frac{12}{x+6}[/tex]The first two parts of the equalities are the same fraction (when simplified). We can use the last and the first one to find x:
[tex]\frac{3}{2}=\frac{12}{x+6}[/tex]Cross-multiplying:
3(x + 6) = 2*12
Dividing by 3:
x + 6 = 8
Subtracting 6:
x = 2
On Tuesday d dollars worth of merchandise was sold. On Wednesday the amount of merchandise sold was $150 less than twice the amount of merchandise sold on Tuesday
Answer:
2d-150
Explanation:
The worth of Merchandise sold on Tuesday = d dollars.
On Wednesday the amount of merchandise sold was $150 less than twice the amount of merchandise sold on Tuesday .
• Twice the amount of merchandise sold on Tuesday = 2d
,• 150 less than 2d = 2d-150.
An expression for the amount of merchandise sold on Wednesday is:
[tex]2d-150[/tex]The third option is correct.
This is a two part question just need help figuring out what exactly it is I need to mark up for the first section up on top and also on the second part of it I need help figuring out if both triangles are congruent and if they are need help stating the congruency
Given the triangles CDE and JLM
For the triangles we have the following:
1) CD = JL
2) CE = JM
3) DE = LM
So, there 3 pairs of congruent sides
So, the triangles are congrurent by S.S.S ( Side-Side-Side) postulate
C is corresponding to J
D is corresponding to L
E is corresponding to M
So,
[tex]\triangle\text{CDE}\cong\triangle\text{JLM}[/tex]For marking the triangles, see the following figure:
How many terms are inthe followingexpression?3x + 4 + a + 6y
When talking about algebraic expressions, each term is limited by + or - signs. It means a term is located between two addition or substraction signs, except for the first and the last ones.
In the given expression there are 4 terms:
3x
4
a
6y
Each one is separated from another for + signs.
pls answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer: -49
Step-by-step explanation: 7 x 7 = 49, but since it has the (-) symbol it will be -49.
your grade must be at least 64 to pass this class g least 64 g least or equal to 64 g greater 64 g greater equal 64
The given statement is your grade must be at least 64 to pass this class.
The inequality that represents this situation is
[tex]g\ge64[/tex]Question 1-4
Rectangle ABCD is dilated into rectangle AB'C'D', as shown.
B'
B
A
3
6
C
2
D
C'
D'
What is the scale factor of dilation? Enter the answer as a whole number or a simplified fraction in the box. Use "/" for the fraction bar.
A C, С B, AC = 10 BC = 15 What is the length of AB? Round your answer to the nearest tenth, if necessary. Figure is not drawn to scale
You have a right triangle and the length of the legs, use Pythaorean theorem to find the length of the hypotenuse (AB)
[tex]\begin{gathered} AB^2=AC^2+BC^2 \\ \\ AB=\sqrt[]{AC^2+BC^2} \\ AB=\sqrt[]{10^2+15^2} \\ AB=\sqrt[]{100+225} \\ AB=\sqrt[]{325} \\ AB=18 \end{gathered}[/tex]Then, the length of AB is 18Identify all pairs of congruent corresponding parts. Then write another congruence statement for the triangles.
..
SOLUTION
[tex]\begin{gathered} \Delta FED\cong\Delta CBA \\ \angle F\cong\angle C \end{gathered}[/tex][tex]\begin{gathered} \Delta EFD\cong BCA \\ \angle E\cong\angle B \\ \bar{DE}\cong\bar{AB} \end{gathered}[/tex][tex]\begin{gathered} \bar{EF}=\bar{BC} \\ \angle D=\angle A \\ \bar{DF}=\bar{AC} \end{gathered}[/tex]g(x)=3x^2-4 if the graph of g is translated vertically upward by 7 units it becomes the graph of a function f. Find the expression for f(x).
The expression for f(x) when moving the graph vertically up by 7 units is f(x)=3x²- 6/2.3.
What are expressions?An expression, also known as a mathematical expression, is a finite combination of symbols that are well-formed in accordance with context-dependent rules. An expression in mathematics is made up of numbers, variables, and functions (such as addition, subtraction, multiplication or division, etc.) You can think of expressions as being similar to phrases. You must substitute a number for each variable and carry out the arithmetic operations in order to evaluate an algebraic expression.So, the expression for f(x):
We have, g(x)=3x²-4Moving the graph upwards by 7 units vertically, we get the expression for f(x) as:
f(x)=3x²- 6/2.3(Refer to the graph attached below)
Therefore, the expression for f(x) when moving the graph vertically up by 7 units is f(x)=3x²- 6/2.3.
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Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –6x + 15 < 10 – 5x
Answer:
Step-by-step explanation:
A student argued that a pizza cut into 12 pieces was more than a pizza cut into 6 pieces. How would you respond?
Answer:
i say a pizza with six has more for less people but twelve is for more people so equally they are both a lot.
Step-by-step explanation:
The statements below represent some possible deposits and withdrawals from Rachel's bank account Match each statement with the total amount that Rachel's account would change. -47.50 -22.50 22.50 She deposits $35 to her account. Then spends $12.50 from her account on lunch. She withdraws $35 from her account. Then spends $12.50 from her account on lunch. She spends $35 from her account on clothes. Then she deposits $12.50 to her account 17 Pause Previous
ok, If she did not initially have anything on the account, this is the process
[tex]\begin{gathered} +35 \\ -12.5 \\ -35 \\ -12.50 \\ -35 \\ +12.50 \\ -------- \\ -47.50 \end{gathered}[/tex]his bank account is at -47.50 dollars
Consider functions f and g.
The correct option regarding the multiplication of the functions f(x) and g(x) is given by:
C. [tex](f \times g)(x) = \frac{x^2 + 6x + 8}{x^2 + 2x - 15}, x \neq -5, x \neq 3[/tex]
Multiplication of functionsTo multiply two rational functions, we multiply the numerators of each function and the denominator of each function to generate the rational functions.
In the context of this problem, before multiplying the functions, we can simplify them.
Function f(x) is given by:
[tex]f(x) = \frac{x^2 - 16}{x^2 + 3x - 10}[/tex]
The numerator and the denominator can be simplified as follows:
Numerator: (x + 4)(x - 4): applying subtraction of perfect squares.Denominator: (x + 5)(x - 2): due to it's roots.Function g(x) is given by:
[tex]g(x) = \frac{x^2 - 4}{x^2 - 7x + 12}[/tex]
The numerator and the denominator can be simplified as follows:
Numerator: (x + 2)(x - 2): applying subtraction of perfect squares.Denominator: (x - 3)(x - 4): due to it's roots.Then the multiplication function is:
[tex](f \times g)(x) = \frac{(x + 4)(x - 4)}{(x + 5)(x - 2)} \times \frac{(x + 2)(x - 2)}{(x - 3)(x - 4)}[/tex]
The common terms (x - 4) and (x - 2) are simplified, hence the function is given by:
[tex](f \times g)(x) = \frac{x + 4}{x + 5} \times \frac{x + 2}{x - 3} = \frac{x^2 + 6x + 8}{x^2 + 2x - 15}[/tex]
Hence option C is correct, with x = -5 and x = 3 being removed from the function due to the fact that they are the zeros of the denominator.
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Hi guys.I was sick today and I’m still not feeling good.I missed out on class and I’ll be giving 25 points to whoever helps me.Thank you
Answer:
x = 11
Step-by-step explanation:
(9x - 5) + (6x + 20) = 180
15x + 15 = 180
15x + 15 -15 = 180 -15
15x = 165
15x/15 = 165/15
x = 11
For which intervals is the function negative?Select each correct answer. (4,∞)(−1.5,4.2)(1,4)(−2.5,2.5)(−3,1)(−∞,−3)
Answer:
(−∞,−3)
(1,4)
Explanation:
To find the interval where the function is negative, we would look at the regions on the graph where the values of y are negative. The required intervals are the values of x in those regions. Looking at the graph,
On the left, the values of y are negative between x = - infinity and x = - 3
On the right, the values of y are negative between x = 1 and x = 4
Thus, the correct options are
(−∞,−3)
(1,4)
Answer:
(−3, 1) and (4, ∞)
Step-by-step explanation:
76 cm57 cmWhat is the length of the hypotenuse?C=centimeters
Using pythagoras Theory which is:
(Hypotenuse)^2 = (opposite)^2 + (Adjacent)^2
C^2 = 76^2 + 57^2
C^2 = 7776 + 3249
C^2 = 11025
C = SQUAREROOT(11025)
C = 105cm
Help me out please please
The statement that the graph y = 2x² - 4x - 2 has a y-intercept of (0, 2) is false.
How to find y-intercept of a graph?The y-intercept is the point where a graph crosses the y-axis.
In simple terms, it is the value of y when x = 0.
Therefore, the graph is express as follows:
y = 2x² - 4x - 2
Let's check when x = 0
Therefore,
y = 2x² - 4x - 2
y = 2(0)² - 4(0) - 2
y = 2(0) - 4(0) - 2
Therefore,
y = 0 - 2
y = -2
The statement is false that the y-intercept of the graph is (0, 2)
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Which of the following equations below is a linear inequality?
Inequality occurs when a non-equal comparison is made between two mathematical expressions or two numbers.
Linear inequalities are inequalities that involve at least one linear algebraic expression, that is, a polynomial of degree 1 is compared with another algebraic expression of degree less than or equal to 1.
Of the options, the only one that represents a linear inequality is:
[tex]yThe FIRST OPTION is correct.the first answer is correct
There is one number that is neither crossed out nor circled. Why is it treated differently?
r is the character which is not treated
Does someone mind helping me please?
The proportion used to find the missing side is RS/QS = RO/PQ, the value of y = 12ft
First we need to see whether triangle RQS is similar with triangle RPO
Angle QRS = Angle PRQ (common angle)
Angle RSQ = ROP (Given, that they are right angles)
So, triangle RQS is similar with triangle RPO
Now the sides of one triangle is in proportion with the other
RS/RO = RQ/RP = QS/PQ
RS/RO = QS/PQ
RS/QS = RO/PQ
9/12 = y/16
3/4 = y/16
3/y = 4/16
3/y = 1/4
y = 4 x 3
y = 12
To find the missing side the proportion used is RS/QS = RO/PQ, the value of y = 12ft
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I need help with my scale project is there anyway you could make me two similar figures with this and it also has the proportions.
To make a similar figure, we measure the lengths of each component of the figure - for example, the leg of the figure is 2 units - and then multiply each measured length by a number. This number could be any number - could be 2, 3, 4 ... but we will choose a small enough number that will give us a figure that can fit inside the graph.
Now here are the measurements of the figure.
The legs = 1 units
bottom = 2 units
top = 2 units
sides = 2 units
nose = 0 units (it is a point)
eyes - 0.5 units
Now let's multiply the measurements above by 3, which gives
The legs = 3 units
bottom = 6 units
top = 6 units
sides = 6 units
nose = 0 units (it is a point)
eyes - 1.5 units.
Finally, we draw a figure with these measurements.
4. (02.05 MC)
Which statement is true if the quantity demanded of a good decreases by 10% while consumer incomes increase by 2 %? (5 points)
O The income elasticity of demand is -20, and the good is inferior.
The income elasticity of demand is -5, and the good is inferior.
The income elasticity of demand is 0.2, and the good is normal.
The income elasticity of demand is 5, and the good is inferior.
The income elasticity of demand is 20, and the good is normal.
Based on the decrease in the quantity demanded and the increase in income, the true statement is The income elasticity of demand is -5, and the good is inferior.
How to find the income elasticity?The income elasticity of a good can be found by the formula:
= Change in quantity demanded / Change in income
= -10% / 2%
= - 5
When the income elasticity of demand for a good is negative, it means that it is an inferior good. This is because people only buy them because its what they can afford but if income rises, people stop buying them.
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Solve for z-p(d + z) = -2+59
Answer
[tex]z=-(\frac{57}{p}+d)[/tex]Explanation
The question ask us to solve for z in the equation
-p (d + z) = -2 + 59
-p (d + z) = 57
Divide both sides by -p
[tex]\begin{gathered} \frac{-p(d+z)}{-p}=\frac{57}{-p} \\ d+z=\frac{-57}{p} \\ \text{Subtract d from both sides} \\ d+z-d=\frac{-57}{p}-d \\ z=\frac{-57}{p}-d \\ z=-(\frac{57}{p}+d) \end{gathered}[/tex]Hope this Helps!!!
I need help with something
Answer:
S'(-2, 6)
Explanation:
Translating a point to the right, meaning adding to the x-coordinate
box with a square base and open top must have a volume of 171500c * m ^ 3 . We wish to find the imensions of the box that minimize the amount of material used.
step 1
Find out the equation of the volume of the box
[tex]\begin{gathered} V=x^2h \\ V=171,500\text{ cm}^3 \\ 171,500=x^2h \\ h=\frac{171,500}{x^2} \end{gathered}[/tex]step 2
Find out the expression for the surface area
The surface area is given by the expression
[tex]A=x^2+4xh[/tex]substitute the value of h
[tex]\begin{gathered} A=x^2+4x\frac{171,500}{x^2} \\ simplify \\ A(x)=x^2+\frac{686,000}{x} \\ \\ A(x)=\frac{x^3+686,000}{x} \end{gathered}[/tex]step 3
Find out the derivative A'(x)
[tex]A^{\prime}(x)=2x-\frac{686,000}{x^2}[/tex]step 4
Equate the derivative to zero
[tex]\begin{gathered} 2x-\frac{686,000}{x^2}=0 \\ 2x=\frac{686,000}{x^2} \\ \\ 2x^3=686,000 \\ x^3=343,000 \\ x=70 \end{gathered}[/tex]A'(x)=0 when x=70step 5
Find out the second derivative A''(x)
[tex]A^{\prime}^{\prime}(x)=2+\frac{1,372,000}{x^3}[/tex]Evaluate the second derivative for x=70
[tex]\begin{gathered} A^{\prime}^{\prime}(x)=2+\frac{1,372,000}{(70)^3} \\ A^{\prime}^{\prime}(x)\text{ is positive} \\ that\text{ means} \\ The\text{ value of A\lparen x\rparen i}s\text{ a maximum for x=70 cm} \end{gathered}[/tex]What is the sum of the polynomials?(8x2-9y2-4x)+(x2-3y2–7x)7x2 - 6y2 + 3x9x2 - 6y2+3x9x2 - 12y2 + 3x9x2 - 12/2 - 11x
Let's simplify the following expression:
[tex]\text{ (8x}^2-9y^2-4x)+(x^2-3y^2-7x)[/tex]We get,
[tex]\text{ (8x}^2-9y^2-4x)+(x^2-3y^2-7x)[/tex][tex]\text{ 8x}^2-9y^2-4x+x^2-3y^2-7x[/tex]Let's put like terms beside each other and proceed with the operation:
[tex]\text{ 8x}^2-9y^2-4x+x^2-3y^2-7x[/tex][tex]\text{ 8x}^2+x^2-9y^2-3y^2-7x-4x[/tex][tex]\text{ (8x}^2+x^2)+(-9y^2-3y^2)+(-7x-4x)[/tex][tex]\text{ (9x}^2^{})+(-12y^2)+(-11x)[/tex][tex]\text{ 9x}^2-12y^2-11x[/tex]Therefore, the sum of the given polynomials (8x^2-9y^2-4x)+(x^2-3y^2–7x) is 9x^2 - 12y^2 - 11x.
The answer is letter D.
Rearrange x = 3g + 2 to make g the subject.
g = 1/3 x - 2/3 is a function of g .
In the simplest terms, what is a function?
A relationship between a group of inputs and one output each is referred to as a function. A function, expressed simply, is an association between inputs where each input is connected to one and only one output. A domain, codomain, or range exists for every function.x =3g + 2
Switch sides:
3g + 2 = x
Take away 2 from both sides:
3g = x - 2
Divide both sides by 3:
g = 1/3 x - 2/3
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order the fractions from greatest to least 4/5,2/3,13/15,7/9
The fractions arranged from greatest to least are- 13/15, 4/5, 7/9, 30/45
Here, we are given 4 fractions- 4/5, 2/3, 13/15, 7/9
In order to compare them, let us equalize their denominators.
The denominators are- 5, 3, 15 and 9
The LCM of 5, 3, 15 and 9 is 45
Thus, we can write the fractions as-
4/5 = (9*4)/(5*9) = 36/45
2/3 = (2*15)/(3*15) = 30/45
13/15 = (13*3)/(15*3) = 39/45
7/9 = (7*5)/(9*5) = 35/45
Now, we can easily compare the fractions by comparing their numerators.
We see that-
39 > 36 > 35 > 30
Thus, 13/15 > 4/5 > 7/9 > 30/45
Hence, the fractions arranged from greatest to least are- 13/15, 4/5, 7/9, 30/45
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For f(x) = -6x-2, find the rate of change on the interval [-2, 4].
The most appropriate choice for rate of change will be given by -
Rate of change of f(x) = -6x -2 on the interval [-2, 4] = -6
What is rate of change of a function?
Rate of change of a function represents the rate at which the value of one quantity changes with change in the value of other quantity.
Here,
f(x) = -6x - 2
[tex]f^{'} (x) = \frac{d}{dx}(-6x - 2)\\[/tex]
[tex]= -6[/tex]
[tex]f^{'} (x)[/tex] represents rate of change
Rate of change of f(x) = -6x -2 on the interval [-2, 4] = -6
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