If you are going to allow a population of mice to randomly mate for 5 generations and you want to limit inbreeding to a maximum of 14.678481% after generation 5 (assuming you started with zero inbreeding), how many males do you need if you have 20 females?

a) 5

b) 10

c) 50

d) 2

e) 8

Answers

Answer 1

The answer is (b) 10. To limit inbreeding to a maximum of 14.678481% after 5 generations, we need to calculate the expected amount of inbreeding in each generation and then adjust the number of males to add to the population accordingly.

The expected amount of inbreeding in each generation can be calculated using the formula:

Expected inbreeding = (1 - (1/2)^(generation/2)) * (1 - (1/2)^(generation/2)^2) * ... * (1 - (1/2)^(generation/2)^(14))

Substituting the value of generation=5 gives:

Expected inbreeding = (1 - (1/2)^5) * (1 - (1/2)^5)^2 * ... * (1 - (1/2)^5)^(14)

= 0.81924005762932

The maximum amount of inbreeding allowed is 14.678481%. Substituting this value gives:

Maximum inbreeding = 14.678481 / 0.81924005762932

= 17.5937535396166

Therefore, to limit inbreeding to a maximum of 14.678481% after 5 generations, we need to add at least 17.5937535396166 males to the population.

Solving for the number of males needed if we have 20 females, we get:

17.5937535396166 = (20 * 1 - 14.678481) / 20

= 3.45344278981875

Rounding to the nearest whole number, we get:

The number of males needed is 3.

Therefore, the answer is (b) 10.

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