Answer:
Mix
Explanation:
A battery has two electrodes at both of its end terminals namely the anode which is the negatively charged electrode and the anode which is the positively charged electrode.
Now, Electrons usually travel through the battery circuit from the anode to the cathode, and this motion of travel is the propelling force that makes electricity flow through the circuit.
Now, the anode will need to have a low electron affinity because it needs to easily release electrons during discharge while the cathode needs to have a high electron affinity because it normally readily accept electrons during discharge.
Thus, for a battery to be strong, it is a combination of high electron affinity and low electron affinity.
The speed of the incoming water is 25 cm/s and the cross-sectional area of the hose carrying the water is 2.0 cm2. 1) Determine the time required for a 25-L container to be filled with water. (Express your answer to two significant figures.)
Answer:
The time taken is [tex]t = 500 \ s[/tex]
Explanation:
From the question are told that
The speed of the incoming water is [tex]v = 25 cm/s[/tex]
The cross-sectional area of the host pipe is [tex]a = 2.0 cm^2[/tex]
Generally the rate at which the container is been filled is mathematically represented as
[tex]\r V = v * a[/tex]
=> [tex]\r V = 25 * 2[/tex]
=> [tex]\r V = 50\ cm^3/s[/tex]
Generally [tex]2.5 L = 25000 cm^3[/tex]
Generally the time taken is mathematically represented as
[tex]t = \frac{25000}{50}[/tex]
=> [tex]t = 500 \ s[/tex]
The time required for a 25-L container to be filled with water is 8.3 min.
The given parameters;
speed of the water, v = 25 cm/sarea of the hose, A = 2 cm²volume of the container, V = 25 L = 25,000 cm³The volumetric flow rate of the water is calculated as follows;
Q = Av
where;
Q is volumetric flow rate v is the speed of the waterA is the area of the hose[tex]Q = Av\\\\\frac{V}{t}= Av\\\\t = \frac{V}{Av} \\\\t = \frac{25,000}{2 \times 25} \\\\t = 500 \ s\\\\t = 8.3 \min[/tex]
Thus, the time required for a 25-L container to be filled with water is 8.3 min.
Learn more here:https://brainly.com/question/13254954
how do animals get the nitrogen they need
Answer:
Animals get the nitrogen they need by eating plants or other animals that contain nitrogen.
Explanation:
Answer:
They eat plants or other animals that contains nitrogen
Explanation:
Animals get the nitrogen they need by eating plants or other animals that contain nitrogen. When organisms die, their bodies decompose bringing the nitrogen into soil on land or into ocean water. Bacteria alter the nitrogen into a form that plants are able to use.
1. On this graph, what is the change in velocity between 5 seconds and 8 seconds?
A man stands on roof of a house and drops a ball of mass M (from rest) from a height of 10 m above the ground. Its speed just before it hits the ground is?
Answer:
Vf = 14 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics, which is independent of the mass of the object.
[tex]v_{f} ^{2} =v_{o} ^{2} +(2*g*x)[/tex]
where:
Vf = final velocity [m/s]
Vo = initial velocity = 0
g = gravity acceleration = 9.81 [m/s²]
x = distance = 10 [m]
Now replacing:
Vf² = 0 + (2*9.81*10)
Vf = 14 [m/s]
easy>>>>>>Define or explain the ways heat can transfer from one object to another (conduction, convection, radiation). In each explanation, list an example.
who plays among us?????
Answer:
i do
Explanation:
A car mass 600kg starts from rest moving uniform acceleration 0.2 m/s^2 after 60 seconds collides with stationary pick up van of mass 400kg gets locked with it and moves together with velocity 7.2 m/s
a) DOES THE PHENOMENON OF THE STEM SUPPORT THE PRINCIPLE OF CONSERVATION OF MOMENTUM? GIVE YOUR OPINION BY MATHEMATICAL ANALYSIS.
Answer:
the phenomenon of the system supports the principle of conservation of momentum.
Explanation:
The law of conservation of momentum says that:
Initial Momentum = Final Momentum
So, first we calculate initial momentum of the system:
Initial Momentum = m₁u₁ + m₂u₂
where,
m₁ = mass of car = 600 kg
m₂ = mass of van = 400 kg
u₁ = Initial Speed of Car
For initial speed of car, we use:
Vf = Vi + at
Vf = 0 m/s + (0.2 m/s²)(60 s)
Vf = u₁ = 12 m/s
u₂ = Initial Speed of Van = 0 m/s
Therefore,
Initial Momentum = (600 kg)(12 m/s) + (400 kg)(0 m/s)
Initial Momentum = 7200 Ns --------------- equation (1)
Now, for the final momentum:
Final Momentum = m₁v₁ + m₂v₂
where,
v₁ = v₂ = Final Speed of Car and van (both are locked) = 7.2 m/s
Therefore,
Final Momentum = (600 kg)(7.2 m/s) + (400 kg)(7.2 m/s)
Final Momentum = 7200 Ns ------------- equation (2)
Comparing equation (1) and (2):
Initial momentum = Final Momentum
Hence, the phenomenon of the system supports the principle of conservation of momentum.
1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the magnitude of the acceleration of the car?
A- 0.1 m/s^2
B- 1 m/s^2
C- 10 m/s^2
D- 100 m/s^2
Answer: B. 1m/s^2
Explanation:
A proton traveling due west in a region that contains only a magnetic field experiences a vertically upward force (away from the surface of the earth). What is the direction of the magnetic field?
a. east
b. north
c. down
d. west
e. south
Answer:
D
Explanation:
Answer:d
Explanation:
An airplane needs to reach a forward velocity of 56.4 m/s to take off. On a 2000 meter runway, what is the minimum uniform acceleration necessary for the plane to take flight if it starts from rest? SHOW WORK OR GET REPORTED!!
What is the displacement of the airplane?
What is the initial velocity of the airplane?
What is the final velocity of the airplane?
Write the equation you will use to solve the problem.
What was your acceleration?
1.0 m/s^2
0.95 m/s^2
0.87 m/s^2
0.80 m/s^2
Answer:
What was your acceleration?
1.0 m/s^2
0.95 m/s^2✔
0.87 m/s^2
0.80 m/s^2
Debbie touches the metal doorknob to her bedroom at 7 a.m. and feels a static electric shock. In the afternoon, Debbie comes back and touches the doorknob again, but she experiences no shock.
Answer:
she had socks one and was shuffeling so she had static
Explanation:
The equation below can be used to find the specific heat capacity of a substance. What is the specific heat capacity if it takes 1000 J of energy to heat 25 g of this substance by 100°C? Give your answer in J/kg°C.
Answer:
400J/kg°C
Explanation:
The specific heat capacity will be 400 J/kg °C. Specific heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.
What is specific heat capacity ?The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.
Similarly
Mathematically, specific heat capacity is given by;
[tex]\rm C = \frac{E}{m \times \theta }[/tex]
The given data in the problem is;
The specific heat of the substance is,C in J/kg °C.
The energy is,E =1000 JIs
The mass is,m= 25 g
[tex]\rm \theta[/tex] Is the temperature difference = 100 °C.
On substituting the given data;
[tex]\rm C = \frac{E }{m \times \theta } \\\\ C = \frac{1000}{25\times 10^{-3} \times 100 } \\\\ C = 400 \ J/kg^0C.[/tex]
Hence, the specific heat capacity will be 400 J/kg °C.
To learn more about the specific heat capacity, refer to the link https://brainly.com/question/2530523
#SPJ2
Q18: A cube of aluminum has an edge length of 20 cm. Aluminum has a
density of 2.7 g/cm and a specific heat of 0.217 cal/ g.°С. When
the internal energy of the cube increases by 47000 cal its temperature
increases by:
A
B
C
D
E
5 °C
10 °C
20 °C
100 °C
200 °C
Answer:
10 °C
Explanation:
From the question given above, the following data were obtained:
Egde length (L) of aluminum = 20 cm
Density of Aluminum = 2.7 g/cm³
Specific heat capacity (C) of aluminum = 0.217 cal/ g°С
Heat (Q) energy = 47000 cal
Change in Temperature (ΔT) =?
Next, we shall determine the volume of the aluminum. This can be obtained as follow:
Egde length (L) of aluminum = 20 cm
Volume (V) of aluminum =?
V = L³
V = 20³
V = 8000 cm³
Thus, the volume of the aluminum is 8000 cm³
Next, we shall determine the mass of the aluminum. This can be obtained as follow:
Density of Aluminum = 2.7 g/cm³
Volume of Aluminum = 8000 cm³
Mass of aluminum =.?
Density = mass/volume
2.7 = mass /8000
Cross multiply
Mass of aluminum = 2.7 × 8000
Mass of Aluminum = 21600 g
Finally, we shall determine the change in temperature of the aluminum as follow:
Specific heat capacity (C) of aluminum = 0.217 Cal/g°С
Heat (Q) energy = 47000 Cal
Mass (M) of Aluminum = 21600 g
Change in Temperature (ΔT) =?
Q = MCΔT
47000 = 21600 × 0.217 × ΔT
47000 = 4687.2 × ΔT
Divide both side by 4687.2
ΔT = 47000 / 4687.2
ΔT = 10 °C
Therefore, the increase in the temperature of the aluminum is 10 °C.
The change in temperature of this cube of aluminum is equal to: B. 10°C
Given the following data:
Edge length, L = 20 cm.Density of Aluminum = 2.7 g/cmSpecific heat capacity (C) of aluminum = 0.217 Cal/g°СInternal energy = 47000 calories.To find the change in temperature of this cube of aluminum:
First of all, we would determine the volume of this cube of aluminum.
[tex]Volume \;of \;a \;cube = L^3\\\\Volume \;of \;a \;cube = 20^3\\\\Volume \;of \;a \;cube = 8000\; cm^3[/tex]
Next, we calculate the mass of this cube of aluminum:
[tex]Mass = Density \times Volume\\\\Mass = 2.7 \times 8000[/tex]
Mass = 21,600 grams.
Now, we can find the change in temperature of this cube of aluminum:
Mathematically, the quantity of heat energy is given by the formula;
[tex]Q = mc\theta[/tex]
Where:
Q represents the quantity of heat energy. m represents the mass of an object. c is the specific heat capacity. ∅ is the change in temperature.Substituting the parameters into the formula, we have;
[tex]47000 = 21600 \times 0.217 \times \theta\\\\47000 = 4687.2 \theta\\\\ \theta =\frac{47000}{4687.2} \\\\ \theta = 10.03[/tex]
Change in temperature = 10°C
Read more: https://brainly.com/question/18877825
A cement truck when filled weighs 42 000 N. Calculate its mass
Answer:
Mass = 4281.35 kg
Explanation:
From Newton's law of motion, the weight of an object is given by the formula;
W = mg
Where;
W is weight
m is mass
g is acceleration due to gravity which has a constant value of 9.81 m/s².
We are given weight W = 42000 N.
Thus;
42000 = m × 9.81
m = 42000/9.81
m ≈ 4281.35 kg
The acceleration of gravity on the
Moon is 1.62 m/s2. The mass of the
Moon is 7.35 x 1022 kg. From this
information, what is the radius of the
Moon?
Answer:
1.74 x 10^6
Explanation:
Brainliest :)
The approximate radius of the Moon is [tex]1.736 * 10^7[/tex] meters, or 17,360 kilometers.
To find the radius of the Moon, we can use Newton's law of universal gravitation, which relates the acceleration due to gravity (g) to the mass of the celestial body (M) and the distance (radius, r) between the center of the body and the object experiencing the gravitational force.
The formula for the acceleration due to gravity on the surface of a celestial body is:
[tex]g = G * (M / r^2),[/tex]
where:
g = acceleration due to gravity on the Moon's surface ([tex]1.62 m/s^2[/tex]),
G = universal gravitational constant (approximately[tex]6.67430 * 10^{-11[/tex] m^3/kg/s^2),
M = mass of the Moon ([tex]7.35 * 10^{22[/tex] kg), and
r = radius of the Moon (what we want to find).
Let's rearrange the formula to solve for the radius (r):
[tex]r^2[/tex] = G * (M / g).
Now, we can plug in the known values:
[tex]r^2 = (6.67430 * 10^{-11} m^3/kg/s^2) * (7.35 * 10^{22} kg / 1.62 m/s^2)[/tex].
Calculate the value of [tex]r^2[/tex]:
[tex]r^2[/tex] ≈ [tex]3.018 * 10^{14} m^2.[/tex]
Finally, take the square root of both sides to find the radius (r):
r ≈ [tex]\sqrt{(3.018 * 10^{14} m^2)[/tex]≈ [tex]1.736 * 10^7[/tex] meters.
So, the approximate radius of the Moon is[tex]1.736 * 10^7[/tex] meters, or 17,360 kilometers.
To know more about gravitational force, here
brainly.com/question/32609171
#SPJ2
The mass of a piece of metal is 1200 g. A measuring cylinder contains 150 cm^3 of water. The volume of the metal is 100cm^3. What is the density of the metal
Answer:
12g/cm³
Explanation:
Given parameters:
Mass of the metal = 1200g
Volume of water in the measuring cylinder = 150cm³
Volume of the metal = 100cm³
Unknown:
Density of the metal = ?
Solution:
Density is the mass per unit volume of a substance;
Density = [tex]\frac{mass}{volume}[/tex]
Now insert the parameters and solve;
Density = [tex]\frac{1200}{100}[/tex] = 12g/cm³
what is your target heart rate
Answer:
6%
Explanation:
6% it id heat rate 6% fornhight
A 53 kg person is being dragged in their sleeping bag to the lake by a 401 N force at an angle of 30°
If the person accelerates at a rate of 0.59 m/s2, how much resistive force (force of friction) is acting
on them?
In the horizontal direction, the forces acting on the person are
• friction with magnitude f, opposing motion, and
• the horizontal component of the pulling force (itself with mag. p ) with mag. p cos(30º), in the direction of motion.
There is no friction in the vertical direction, so we omit any discussion of the vertical forces.
By Newton's second law, we then have
p cos(30º) - f = m a cos(30º)
where m is the person's mass, and a is their acceleration so that a cos(30º) is the magnitude of the horizontal component of acceleration. The person is pulled by a force of p = 401 N, so solve for f :
(401 N) cos(30º) - f = (53 kg) (0.59 m/s²) cos(30º)
f ≈ 320 N
(ii) A second drill is used with the extension lead. The power of this drill is
1200 W.
The instructions for using the extension lead include the following information.
When in use the lead may get hot:
DO NOT go over the maximum power
lead wound inside the case: 820 watts
lead fully unwound outside the case: 3100 watts
It would not be safe to use this drill with the extension lead if the lead was left wound
inside the plastic case.
Explain why
A bowling sphere is sitting on the ground. One of your classmates
takes a mallet and gives a bowling sphere a brief push. A moment
after the push, which of the following forces act on the bowling
sphere? (choose all that apply)
- the force of gravity
- a normal force
- inertia
- the force of the push
normal force because it is perpendicular to the surface
what is the importance of gravitional force?write any two points.
Explanation:
Gravity is a very important force. Every object in space exerts a gravitational pull on every other, and so gravity influences the paths taken by everything traveling through space.
It is the glue that holds together entire galaxies. It keeps planets in orbit.
1. A ball is kicked horizontally at 8 m/s from a cliff that is 80m high. It takes 3.1 s for the ball to hit the
ground. What is the horizontal displacement of the ball?
There is redundant data in this question. We only need to know the speed and height. We'll ignore the time, as it can be calculated from the two data above.
Answer:
d=32.32 m
Explanation:
Horizontal Motion
It describes the situation when an object is thrown horizontally with a speed v from a height h.
The range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
The ball is kicked horizontally with v=8 m/s from a cliff at h=80 m, thus the maximum horizontal distance is:
[tex]\displaystyle d=8\cdot\sqrt{\frac {2(80)}{9.8}}[/tex]
d=32.32 m
What acceleration will a 1000-kg car experience if a force of 500 N is applied?
Answer:
the answer is 0.5m/s..... see the image for explanation
You are holding an apple. It is probably a Honeycrisp apple. Maybe it is a Braeburn apple. Anyway, if you are holding an apple, how could you increase its potential energy
Answer:
You can hold it at a higher level. This creates more tension between the apple and gravity. Creating a higher level of potential energy
a truck of mass 150kg is released from rest at point A and moves along a frictionless truck as shown below
Answer:
Vmax = 34.3[m/s]
Explanation:
We must remember that the definition of energy transformation, which tells us that potential energy is transformed into kinetic energy and vice versa.
Potential energy is defined as the product of mass by gravity by height.
[tex]E_{p}=m*g*h[/tex]
where:
m = mass = 150 [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 60 [m]
[tex]E_{p}=150*9.81*60\\E_{p}=88290 [J][/tex]
When the height is zero, all the potential energy will have been transformed into kinetic energy, with this kinetic energy we can calculate the velocity.
[tex]E_{k}=\frac{1}{2} *m*v^{2}\\E_{k}=\frac{1}{2}*150*v^{2}\\88290=0.5*150*v^{2}\\v=\sqrt{\frac{88290}{0.5*150} }\\v=34.3[m/s][/tex]
The maximum kinetic energy is reached in B
Giving brainliest someone help pls
Answer: Metalloids
Explanation:
hope this helps!
If a ball is thrown up at an initial speed of 40. m/s, how many seconds does it take to reach the top of its path?
Answer:
Time, t = 4.08 secs
Explanation:
Given the following data;
Initial velocity, U = 40m/s
To find the time, we would use the first equation of motion;
[tex] V = U + at[/tex]
Where;
V is the final velocity. U is the initial velocity. a is the acceleration. t is the time measured in seconds.Making time, t the subject of formula, we have;
[tex] t = \frac{V - U}{a}[/tex]
We know that acceleration due to gravity, g is 9.8m/s².
a = g = - 9.8m/s² because the ball is thrown in the opposite direction.
Also, the final velocity is equal to zero (0) because the ball reached its maximum height.
Substituting into the equation, we have;
[tex] t = \frac{0 - 40}{-9.8}[/tex]
[tex] t = \frac{-40}{-9.8}[/tex]
Time, t = 4.08 secs
Therefore, it will take the ball 4.08 seconds to reach the top.
how much time does it take the shock wave arrive
Answer: It could take 15 minutes to 36 hours.
Explanation: It depends on the intensity.
2. In a tug of war contest, one person pulls with a force of 5 Newtons. Another person on the same team pulls with a force of 3 Newtons. In order for the force of the rope to be balanced, what force would the other team need to be pulling with?
a. 5 Newtons
b. 2 Newtons
c. 15 Newtons
d. 8 Newtons
Pls
Answer:
8 newtons
Explanation:
Balanced forces have an equal amount of newtons. 5+3=8, so the other team will need 8 newtons.
In a tug of war contest, one person pulls with a force of 5 Newtons. Another person on the same team pulls with a force of 3 Newtons. In order for the force of the rope to be balanced,force would the other team need to be pulling with is 8 newtons.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
A resultant force vector is described as a single vector that has the same consequence as several other vectors taken together.To create the resulting force vector, two vectors facing the opposite direction are subtracted from one another. Here Net Force = 5 - (-3) = 8 N
In order for the force of the rope to be balanced, force would the other team need to be pulling with is 8 Newtons.
To learn more about force refer to the link:
brainly.com/question/13191643
#SPJ2
The Sun has a mass of 1.99x10^30 kg and a radius of 6.96x10^8 m. Calculate the acceleration due to gravity, in meters per second, on the surface of the Sun?
Answer:
[tex]g=274\ m/s^2[/tex]
Explanation:
Mass of the Sun, [tex]M=1.99\times 10^{30}\ kg[/tex]
The radius of the Sun, [tex]r=6.96\times 10^8\ m[/tex]
We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :
[tex]g=\dfrac{GM}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.99\times 10^{30}}{(6.96\times 10^8)^2}\\\\g=274\ m/s^2[/tex]
So, the value of acceleration due to gravity on the Sun is [tex]274\ m/s^2[/tex].
The acceleration due to gravity, in meters per second squared, on the surface of the Sun is [tex]296.88 \;m/s^2[/tex].
Given the following data:
Mass of Sun = [tex]1.99 \times 10^{30}[/tex] kilogramsRadius of Sun = [tex]6.69 \times 10^8[/tex] metersGravitational constant = [tex]6.67 \times 10^{-11}[/tex]
To calculate the acceleration due to gravity, in meters per second squared, on the surface of the Sun:
From the law of gravitational force, we have the formula:
[tex]g = \frac{Gm}{r^2}[/tex]
Where:
g is the acceleration due to gravity.G is the gravitational constant.m is the mass of a planet.r is the radius.Substituting the given parameters into the formula, we have;
[tex]g = \frac{6.67 \times 10^{-11} \times 1.99 \times 10^{30}}{(6.69 \times 10^8)^2} \\\\g= \frac{1.33 \times 10^{20} }{4.48 \times 10^{17}} \\\\g=296.88 \;m/s^2[/tex]
Read more: https://brainly.com/question/14369105
