(ii) Given instead that G=0 and the forces are in equilibrium, find the values of F and alpha

When you climb a ladder, your potential energy increases as you move upwards against gravity. Therefore, the energy transformation that takes place when you climb a ladder is:

Potential energy transforms into kinetic energy.

So, the correct answer is C.

The height of the luggage with work done of 100J with a mass of 10.5 kg is 0.97m.

Work done equals the product of force and displacement. The energy that gets transferred by the force to move a object is called work done. Work done is equal to the potential energy of the object.

Work done = potential energy

                   = m×g×h

m is the mass of the luggage = 10.5 kg

g is the acc. due to gravity = 9.8 m/s

W is the work done = 100J

h (height) = W / (m×g)

               = 100 / ( 10.5×9.8)

              = 0.97 m

Thus, the luggage rises above the ground with a height of 0.97 m.

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Answer:

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Explanation:

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Gravity does 62.72 J of work on the block during this process.

What is work done?

Work is defined as the energy transferred to or from an object by the application of a force over a distance. In other words, work is done when a force acts on an object to cause it to move in the direction of the force.

To calculate the work done by gravity on the block, we need to find the change in the gravitational potential energy of the block as it moves down the incline. We can do this by using the formula:

ΔU = mgh

where ΔU is the change in potential energy, m is the mass of the block, g is the acceleration due to gravity, and h is the height change of the block.

The height change of the block is equal to the vertical distance it moves down the incline, which can be found using trigonometry:

h = d sin θ

where d is the distance the block moves down the incline and θ is the angle of the incline.

We are given that the block moves a distance of 1.6 m down the incline, but we are not given the angle of the incline. However, we can use the given information about the block's velocity to find the angle.

The block starts from rest and acquires a velocity of 4.0 m/s after moving a distance of 1.6 m in 0.80 s. We can use the kinematic equation:

v2 = v1 + 2ad

where v1 is the initial velocity (which is zero), a is the acceleration, and d is the distance.

Rearranging this equation gives:

a = (v2 - v1) / (2d) = 5.0 m/s^2

The acceleration of the block is equal to the component of gravity parallel to the incline, which is g sin θ, where g is the acceleration due to gravity (9.8 m/s^2). So we have:

g sin θ = a

sin θ = a / g = 0.51

Taking the inverse sine of both sides gives:

θ = 30°

Now we can calculate the height change of the block:

h = d sin θ = 1.6 m * sin 30° = 0.8 m

Finally, we can calculate the work done by gravity:

ΔU = mgh = (8.0 kg) * (9.8 m/s^2) * (0.8 m) = 62.72 J

Therefore, gravity does 62.72 J of work on the block during this process.

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The basic machine in the question has a mechanical advantage of 4.9, B.

To determine the mechanical advantage of the simple machine, use the formula:

Mechanical Advantage (MA) = output force / input force

Use the formula for the lever arm:

lever arm = distance from pivot to point of force

For the input force, the lever arm is 0.7 meters. For the output force, the lever arm is 3.4 meters.

So, the mechanical advantage is:

MA = output force / input force = lever arm of output force / lever arm of input force = 3.4 / 0.7 = 4.9

Therefore, the mechanical advantage of the simple machine shown in the question is 4.9.

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