To solve this question, follow the steps below.
Step 01: Solve the operation inside the parentheses.
[tex]\begin{gathered} \frac{\mleft(14+16\mright)}{2}-10 \\ \frac{30}{2}-10 \end{gathered}[/tex]Step 02: Solve the division.
[tex]15-10[/tex]Step 03: Solve the subtraction.
[tex]5[/tex]Answer: 5.
Mrs. Gomez has two kinds of flowers in her garden. The ratio of lillies to daisies is the garden is 5:2 If there are 20 lillies, what is the total number of flowers in her garden? If there are 20 lillies, what is the total number of flowers in her garden?A. 8B. 10C. 15D. 28
The ratio of lilies to daisies is the garden is 5:2
20 Lillies
That means per every 4 lilies there are 2 daisies
4* 5 = 20 lilies
So
2*4 = 8 daisies
_________________
total number of flower are 20 lillies + 8 daisies = 28.
____________________________________
Answer
Option D) 28
A cubical tank with sides 6 feet is to be painted. It costs $2 per square feet to paint. Find the total cost to paint all the six sides.
We have that the surface area of a cube is given by
[tex]SA=6s^2[/tex]where s is the measure of the side
s= 6 ft
[tex]SA=6\cdot6^2=6\cdot36=216ft^2[/tex]If the square feet cost $2 the total cost will be
[tex]TC=216\cdot2=432[/tex]the total cost is $432
is the prime factorization of what composite number? 91 point
Answer: The question isn't clarified, what are you looking for?
Step-by-step explanation:
Answer:
The Prime Factors of 91 are 1, 7, 13, 91
Step-by-step explanation:
what is the rate of change of the cube’s surface area when its edges are 50 mm long?
The first thing we are going to do is identify the volume and surface of the cube and their respective derivatives or rate of change
[tex]\begin{gathered} V\to\text{volume} \\ S\to\text{surface} \\ l=\text{side of a square} \end{gathered}[/tex][tex]\begin{gathered} V=l^3\to(1) \\ \frac{dV}{dt}=3l^2\frac{dl}{dt}\to(2) \end{gathered}[/tex][tex]\begin{gathered} S=6l^2\to(3) \\ \frac{dS}{dt}=12\cdot l\cdot\frac{dl}{dt}\to(4) \end{gathered}[/tex]From the exercise we know that:
[tex]\begin{gathered} \frac{dV}{dt}=300\frac{\operatorname{mm}^3}{s}\to(5) \\ 3l^2\frac{dl}{dt}=300\frac{\operatorname{mm}^3}{s}\to(2)=(5) \\ \frac{dl}{dt}=\frac{300}{3l^2}\frac{\operatorname{mm}^3}{s}\to(6) \end{gathered}[/tex]The exercise asks us to calculate the rate of change of the surface (4) so we substitute the differential of length (6) in (4)
[tex]\begin{gathered} \frac{dS}{dt}=12\cdot l\cdot(\frac{300}{3l^2}\frac{\operatorname{mm}^3}{s}) \\ \frac{dS}{dt}=\frac{1200}{l}\frac{\operatorname{mm}}{s} \end{gathered}[/tex]what is the rate of change of the cube’s surface area when its edges are 50 mm long?
[tex]\begin{gathered} l=50\operatorname{mm} \\ \frac{dS}{dt}=\frac{1200}{50\operatorname{mm}}\frac{\operatorname{mm}^3}{s} \\ \frac{dS}{dt}=24\frac{\operatorname{mm}^2}{s} \end{gathered}[/tex]The answer is 44mm²/sYou are designing a rectangda garden for the city park. The gardien is to have an area of 250 S feet, but you want to theamount of fending that you need to surround the garden. One length of the garden will not have a fence How many fees of lenong to you needto Surround the garden?
Consider the following picture
This is a sketch of the rectangular garden. We are given that the area of this rectangle is 200. Recall that the area of a rectangle is base * height. IN this case, we have the equation
[tex]\times\cdot\text{ y = 200}[/tex]Now, note that we want to minimize the amount of fence we use. This means, that we want to minimize the perimIn this case we are told that we are not putting fence on one side of the rectangle. Since we want the less amount of fence to be used, and since y is the lenght of the longest side, we will assume that we are not fencing one of the y sides. So the perimeter of this rectangle is sum of the three remaining sides. Hence the function we want to minimize is
[tex]y\text{ + 2x }[/tex]From the first equation, we can replace the value of y with 200/x. So the function we want to minimize is
[tex]\frac{200}{x}+2x[/tex]Since we want to find the minimum of this function, we proceed by calculating its' derivative, make it equal to zero and the find the value of x that makes the equation true.
So, recall that the derivative of a term x^n is n x ^(n-1). In the case of 1/x, the value of n is n=-1. Also, recall that the derivative of a sum is the sum of the derivatives. So, applying this rule we get that the derivative of the function is
[tex]200(-1)x^{^{\text{ -2}}}+2x^0=2\text{ - }\frac{200}{x^2}[/tex]No, we will make it equal to 0 and find the value of x that makes the equation true. So we get the equation
[tex]2\text{ - }\frac{200}{x^2}\text{ = 0 = }\frac{2x^2\text{ -200}}{x^2}[/tex]Since we have an equation of the form a/b =0 It must happen that a is 0. Then, we have the equation
[tex]2x^2\text{ -200 =0}[/tex]If we add 200 on both side, we get
[tex]2x^2\text{ = 200}[/tex]If we divide on both sides by 2, we get
[tex]\times^2\text{ = 100}[/tex]By taking the square root on both sides we get
[tex]\text{ x = 10 or x = -10}[/tex]Since x is a lenght, it should be positive. So we must have x = 10.
In this case, by replacing in the expression of y, we get that y = 200/10 = 20.
So we will need 2*10 + 20 = 40 feets long to surround the garden.
aSuppose you want to buy a new car that costs $32,600. You have no cash-only your old car, which is worth $5000 as a trade-in. The dealer says theinterest rate is 5% add-on for 4 years. Find the monthly paymentThe monthly payment is $(Type an integer or decimal rounded to the nearest cent as needed.)
Given:
Cost of a new car = $32,600
Trade-in old car cost = $5,000
Rate, r = 5% or 0.05
Time, t = 4 years
Asked: Find the monthly payment.
Solution:
[tex]PMT=\frac{P_O(\frac{r}{n})}{(1-(1+\frac{r}{n})^{-nt})}[/tex]where:
PMT = Loan Payment
Po = Loan Amount
r = Annual Interest Rate
n = Number of Compounds per year
t = Length of the Loan in years
Now that we have the formula, we will substitute the values.
Po = $32,600 - $5,000 = $27,600
r = 5% or 0.05
n = 12 (There are 12 months in 1 year)
t = 4 years
[tex]\begin{gathered} PMT=\frac{P_O(\frac{r}{n})}{(1-(1+\frac{r}{n})^{-nt})} \\ PMT=\frac{27600(\frac{0.05}{12})}{(1-(1+\frac{0.05}{12})^{-12\cdot4})} \\ PMT=\frac{115}{(1-0.8190710169^{})} \\ PMT=\frac{115}{0.1809289831} \\ PMT=635.6085026 \end{gathered}[/tex]ANSWER:
The monthly payment is $636. (Rounded to the nearest cent.)
give an example of a positive tempature and a negative tempature that have a diffrence of 5 fedagree
We can think of temperatures above zero F and below zero F. For example weather conditions in cold places like Alaska.
In the morning, the temperature could be 2 degrees F (above zero)), but later towards the night, the temperature could be below zero in three units : -3 degrees F.
So the difference is the distance from zero to 2 (above) and the distance to zero from below 3 (below the zero mark. so these two differences from zero add up as 2 + 3 = 5
The way to do such in one go with math is to write the "difference" (normally associated with a SUBTRACTION, of the form: 2 - (-3), and therefore use that the negative (or opposite) of a negative number is a positive number:
- (-3) = +3
The same happens when we want to compare the difference between
9 - (-15) = 9 + 15 = 24
with the difference:
-15 - 9 = -24
The important thing is to consider the absolute value if we just want to find the number of units between the values, how many units they are separated.
And if we need to find what needs to be added or subtracted to one of them, at that point the sign of the difference is critical. This is because in one case we will need to add to get to the other number, while in the other case we need to subtract.
Mrs. Thornton asked her students to draw a figure with a perimeter of 4x + 4. Shown below are 4 drawings madeby her students. (They are not drawn to scale.) Which one is NOT correct?А2x+11B2x2C.X + 4XDX+ 1X+ 1сdba
The perimeter is 4x+4
the formula of the perimeter of a rectangle is
[tex]P=2l+2w[/tex]for the first drawing
[tex]P=2(2x+1)+2(1)=4x+2+2=4x+4[/tex]It is correct
for the second drawing
[tex]P=2(2x)+2(2)=4x+4[/tex]It is correct
for the third drawing
[tex]P=2(x+4)+2x=2x+8+2x=4x+8[/tex]It is not correct
for the fourth drawing
[tex]P=2(x+1)+2(x+1)=2x+2+2x+2=4x+4[/tex]it is correct
As we can see the incorrect draw is C.
Apply the distributive property to simplify the expression 8(12x – 20)
Answer:
[tex]\boxed{\bf {96x-160}}[/tex]
Step-by-step explanation:
[tex]\sf 8(12x - 20)[/tex]
Apply the Distributive Property :-
[tex]\boxed{\sf \:a\left(b-c\right)=ab-ac}[/tex]
[tex]\sf 8(12x - 20)[/tex]
[tex]\sf 8\times \:12x-8\times\:20[/tex]
[tex]\sf 8 \times 12x=\bf 96x[/tex]
[tex]\sf 8\times 20=\bf 160[/tex]
[tex]\bf 96x-160[/tex]
________________
Hope this helps!
Have a great day! :)
Answer:
96x - 160
Step-by-step explanation:
Given expression,
→ 8(12x - 20)
Let's simplify the expression,
→ 8(12x - 20)
→ (8 × 12x) - (8 × 20)
→ 96x - 160
Hence, answer is 96x - 160.
Mary is 4 years older than Sue. If the sum of their ages is 16. How would you set up the equations?
Answer:
A. x=y-4, x+y=16
C. x=y-4, x+y=16
Explanation:
• Let Sue's age = x
Mary is 4 years older than Sue, therefore:
• Mary's age, y = x+4
[tex]\begin{gathered} y=x+4 \\ \implies x=y-4 \end{gathered}[/tex]Next, the sum of their ages is 16. This gives:
[tex]x+y=16[/tex]Therefore, the equation is:
[tex]\begin{gathered} x=y-4 \\ x+y=16 \end{gathered}[/tex]The correct choices are A and C.
A metallurgist has One alloy containing 49% copper and another containing 62% copper. How many pounds of each alloy must he used to make 51 pounds of a third alloy containing 56% copper?
Explanation
Step 1
a)
Let
x represents the pounds of the 49 % copper alloy
y represents the pounds of the 62 % copper alloy
then,
if we want to make a 51 pounds of a new alloy,
[tex]x+y=51\rightarrow equation(1)[/tex]b)this new allo contains 56% of copper , so
total of cooper = pounds of alloy * percentage
[tex]\begin{gathered} 0.49x+0.62y=51\cdot0.56 \\ 0.49x+0.62y=28.56\rightarrow equation\text{ (2)} \end{gathered}[/tex]Step 2
Solve the equations
a) isolate x in equation (1) and replace in equation(2)
[tex]\begin{gathered} x+y=51\rightarrow equation(1) \\ \text{subtract y on both sides} \\ x+y-y=51-y \\ x=51-y\rightarrow equation(3) \end{gathered}[/tex]Now, replace in equation (2)
[tex]\begin{gathered} 0.49x+0.62y=28.56\rightarrow equation\text{ (2)} \\ 0.49(51-y)+0.62y=28.56 \\ 24.99-0.49y+0.62y=28.56 \\ \text{add like terms } \\ 24.99+0.13y=28.56 \\ \text{subtract 24.99 on both sides} \\ 24.99+0.13y-24.99=28.56-24.99 \\ 0.13y=3.57 \\ \text{divide both sides by 0.13} \\ \frac{0.13y}{0.13}=\frac{3.57}{0.13} \\ y=27.46 \\ \end{gathered}[/tex]now, replace the y value into equation (3) to get x
[tex]\begin{gathered} x=51-y\rightarrow equation(3) \\ x=51-y \\ x=51-27.46 \\ x=23.54 \\ \end{gathered}[/tex]therefore, the answer is
23.54 lb of the 49% copper alloy
27.46 lb of the 62% copper alloy
Use a composite figure to estimate the area of the figure. the grid has squares with side lengths of 1 cm. Please help.
From the given figure we can see that there is a rectangle with 3 x 4 squares
A semi-circle at the top with about 6 squares
A semi-circle at right with about 4 squares
Then the total number of squares = 12 + 6 + 4 = 22 squares
Since the area of each square is 1 x 1 = 1 cm^2
Then the area of the figure = 22 x 1 = 22 cm^2
The area of the figure is about 22 cm^2
The percent y (in decimal form) of battery power remaining x hours after you turn on a laptop computer is y=-0.2x + 1. Graph the equation and use it to answer questions 1 and 2. a. What is the x-intercept? What does it represent? b. What is the y-intercept? What does it represent?c. After how many hours is the battery power at 75%d. what is the percentage of battery power remaining at 3 hours?
The percent y (in decimal form) of battery power remaining x hours after you turn on a laptop computer is given by
[tex]y=-0.2x+1[/tex]Let us graph the above equation
a. What is the x-intercept? What does it represent?
The x-intercept is the point where the line intersects the x-axis.
From the graph, we can see that the x-intercept is (5, 0)
The x-intercept represents that it takes 5 hours for the battery power to go to 0%
You can manually find out the x-intercept by substituting y = 0 into the given equation
[tex]\begin{gathered} y=-0.2x+1 \\ 0=-0.2x+1 \\ 0.2x=1 \\ x=\frac{1}{0.2} \\ x=5 \end{gathered}[/tex]Therefore, the x-intercept is (5, 0)
b. What is the y-intercept? What does it represent?
The y-intercept is the point where the line intersects the y-axis.
From the graph, we can see that the y-intercept is (0, 1)
The y-intercept represents that the battery power is 1 (100%) when x = 0 hours.
You can manually find out the y-intercept by substituting x = 0 into the given equation
[tex]\begin{gathered} y=-0.2x+1 \\ y=-0.2(0)+1 \\ y=1 \end{gathered}[/tex]Therefore, the y-intercept is (0, 1)
c. After how many hours is the battery power at 75%
We need to substitute y = 0.75 (that means 75%) into the equation to find out x (number of hours)
[tex]\begin{gathered} y=-0.2x+1 \\ 0.75=-0.2x+1 \\ 0.75+0.2x=1 \\ 0.2x=1-0.75 \\ 0.2x=0.25 \\ x=\frac{0.25}{0.2} \\ x=1.25\: \text{hours} \end{gathered}[/tex]Therefore, after 1.25 hours, the battery power is at 75%
d. what is the percentage of battery power remaining at 3 hours?
We need to substitute x = 3 hours into the equation to find out y (remaining battery power)
[tex]\begin{gathered} y=-0.2x+1 \\ y=-0.2(3)+1 \\ y=-0.6+1 \\ y=0.4 \end{gathered}[/tex]Therefore, the remaining battery power is 40% after 3 hours.
Please see the picture for the question and my answer is wrong
Given sentence:
Five more than half the input is the output
y is the output, x is the input
To interpret the sentence, we should break it into parts:
-half the input: we half the input
- 5 more than we add 5 to the new input
- the sum of these is the output
The equation that represents the given sentence:
[tex]y\text{ = 5 + }\frac{1}{2}x[/tex]Answer:
[tex]y\text{ = 5 + }\frac{1}{2}x[/tex]Which of the following sa rational number? [tex] \sqrt{5} [/tex][tex] - \frac {3}{4} [/tex]Pi[tex] - \sqrt{7} [/tex]
First of all, we need to remember what is a rational number.
In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.
Now, from your options we can deduce that:
[tex]\frac{3}{4}[/tex]is the rational number.
The movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. A flashlight is projecting a triangle onto a wall, as shown below. A The original triangle and its projection are similar. What is the missing length n on the projection? O 35 0224 10 40
We can see that the scale factor from the smaller triangle to the projected triangle is 2.
Multiply each length of the original triangle by the scale factor, to obtain the side lengths of the second triangle:
15 x 2 = 30
15x 2 = 30
20 x 2 = 40
answer : 40
In the first week of July, a record 1,040 people went to the local swimming pool. In the second week,125 fewer people went to the pool than in the first week. In the third week,135 more people went to the pool than in the second week. In the fourth week,322 fewer people went to the pool than in the third week. What is the percent decrease in the number of people who went to the pool over these four weeks?
By the concept of percentage there is 20% decrease in the number of people who went to the pool over these four weeks.
What is percentage?A percentage is a statistic or ratio that is expressed as a fraction of 100 in mathematics. But even though the abbreviation "pct.", "pct.", and occasionally "pc" are also used, the percent symbol, "%," is frequently used to signify it. A % is a dimensionless number; there is no specific unit of measurement for it. %, a relative figure signifying hundredths of any amount. Since one percent (symbolized as 1%) is equal to one hundredth of something, 100 percent stands for everything, and 200 percent refers to twice the amount specified. A percentage is a figure or ratio that in mathematics represents a portion of one hundred. It is frequently represented by the sign "%" or just "percent" or "pct." For instance, the fraction or decimal 0.35 is comparable to 35%.
In July:
First week:
Number of people went to the local swimming pool
=1040
Second week:
110 fewer people went to the pool than in the first week
Number of people went to the local swimming pool
=1040 - 110
=930
Third week:
130 more people went to the pool than in the second week
Number of people went to the local swimming pool
=930 + 130
=1060
Fourth week:
228 fewer people went to the pool than in the third week
Number of people went to the local swimming pool
=1060 - 228
=832
Decrease in number of people over four week
= number of people in first week - number of people in fourth week
Decrease in number of people over four week
=1040 - 832
=208
Now, the percentage
= 20%
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Given ST is tangent to circle Q, find the value of r
Given the figure of the circle Q
As shown, ST is tangent to circle Q
So, ST is perpendicular to the radius QS
So, the triangle QST is a right-angle triangle
We can apply the Pythagorean theorem where the legs are QS and ST
And the hypotenuse is QT
The side lengths of the triangle are as follows:
QS = r
ST = 48
QT = r + 36
So, we can write the following equation:
[tex]\begin{gathered} QT^2=QS^2+ST^2 \\ (r+36)^2=r^2+48^2 \end{gathered}[/tex]Expand then simplify the last expression:
[tex]\begin{gathered} r^2+2*36r+36^2=r^2+48^2 \\ r^2+72r+1296=r^2+2304 \end{gathered}[/tex]Combine the like terms then solve for (r):
[tex]\begin{gathered} r^2+72r-r^2=2304-1296 \\ 72r=1008 \\ \\ r=\frac{1008}{72}=14 \end{gathered}[/tex]So, the answer will be r = 14
A roll of 50 dimes weighs 4 ounces. Which proportion can be used to find the weight in ounces, w, of 300 dimes?
50 dimes = 4 ounces
300 dimes = w ounces
[tex]\begin{gathered} \frac{50}{300}=\frac{4}{w} \\ \frac{1}{6}=\frac{4}{w} \\ w=24 \end{gathered}[/tex]300 dimes = 24 ounces
the proportion is 1/6 =4/w
2.Evaluate the following mixed numbers, then simplify.7 1/2 divide 1 1/8
Given the numbers : 7 1/2 and 1 1/8
We will divide them
so,
[tex]\begin{gathered} 7\frac{1}{2}\div1\frac{1}{8} \\ \\ =\frac{15}{2}\div\frac{9}{8} \\ \\ =\frac{15}{2}\times\frac{8}{9} \\ \\ =\frac{8}{2}\times\frac{15}{9}=4\times\frac{5}{3}=\frac{20}{3}=6\frac{2}{3} \end{gathered}[/tex]Find the radius and area of a circle with a circumference of 62.8.Round your answer to the nearest tenth. Use 3.14
Given:
circumference of 62.8
Required:
circumference of 62.8
Explanation:
Let r be the radius of the circle
Since the circumference of the circle is 62.8
[tex]\begin{gathered} 2\pi r=62.8 \\ \\ 2\times3.14\times r=62.8 \\ \\ 6.28r=62.8 \\ \\ r=\frac{62.8}{6.28} \\ \\ r=10 \end{gathered}[/tex]area of circle is
[tex]\begin{gathered} \pi r^2 \\ \\ 3.14\times10\times10 \\ \\ =314 \end{gathered}[/tex]Required answer:
10, 314
(a) Does f (x) have a horizontal asymptote? If so, what is it?(b) Does f (x) have any vertical asymptotes? If so, what are they?
a) Horizontal asymptotes are horizontal lines that the graph of a function approaches but never touches. To find the horizontal asymptote, we would apply one of the rules which states that
If the degree of the of the denominator is bigger than the degree of the numerator, the horizontal asymptote is the x axis of the graph. It occurs at y = 0
The degree is the largest exponent in the function. Looking at the given function, the degree of the numerator is 2 while the degree of the denominator is 3. Thus,
there is a horizontal asymptote at y = 0
b) The vertical asymptotes are vertical lines which correspond to the zeros of the denominator of rational functions. It is equal to the values of x that make the denominator to be zero. Looking at the given function, (x + 1) cancels out in the numerator and denominator. We are left with (x - 4) and (x + 5). We would equate both terms to zero and solve for x. These values of x would make the denominator to be equal to zero. We have
x - 4 = 0
x = 4
x + 5 = 0
x = - 5
Thus,
there are vertical asymptotes at x = - 5 and x = 4
The total annual sales for Herman's Hardware Store was $1,246,135 and the total accounts receivable was $41,728. What was the average collection period to the nearestwhole day?12 days14 days18 days24 daysNone of these choices are correct.
The average collection Period formula is
[tex]\text{Average collection period=}\frac{Account\text{ receivable}}{\frac{Annual\text{ sales}}{365}}[/tex][tex]\begin{gathered} \text{Annual sales=\$1,246,135} \\ \text{Account receivable =\$41,728} \end{gathered}[/tex]Substitute the values above in the average collection period
[tex]\begin{gathered} \text{Average collection period =}\frac{41728}{\frac{1246135}{365}} \\ =\frac{41728}{3414.06} \\ =12.222 \\ \approx12days \end{gathered}[/tex]Hence the average collection period to the nearest whole day is 12 days
The ratio of girls to boys on Mr.Miller's team is 4 to 5. If thereare 60 boys on his team, thenhow many students are there onhis team?
We have a ratio is 4 girls to 5 boys. There are 60 boys, then, we have:
[tex]\frac{4}{5}=\frac{x}{60}\Rightarrow x=\frac{60\cdot4}{5}\Rightarrow x=\frac{240}{5}\Rightarrow x=48[/tex]Then, we have 48 girls in the class.
Therefore, there are 60 boys + 48 girls = 108 students on Mr. Miller's team.
How would you solve this question or similar questions? It is solving for x.
Given the initial expression
[tex]\sqrt[]{2x+3}=\sqrt[]{2x}+3[/tex]Then,
[tex]\begin{gathered} \sqrt[]{2x+3}=\sqrt[]{2x}+3 \\ \Rightarrow(\sqrt[]{2x+3})^2=(\sqrt[]{2x}+3)^2 \\ \Rightarrow2x+3=2x+6\sqrt[]{2x}+9 \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} \Rightarrow3=6\sqrt[]{2x}+9 \\ \Rightarrow-6=6\sqrt[]{2x} \\ \Rightarrow\sqrt[]{2x}=-\frac{6}{6}=-1 \\ \Rightarrow\sqrt[]{2x}=-1 \\ \Rightarrow\sqrt[]{2}\sqrt[]{x}=-1 \\ \Rightarrow\sqrt[]{x}=-\frac{1}{\sqrt[]{2}} \end{gathered}[/tex]And sqrt(x)>=0 for any real number.
Therefore, there is no real solution to the equation.
Josh took 300 minutes to get to work. How many hours is this?
Problem Statement
The question tells us that it
A 20% tip on a $26.00 dinner bill ishow much money?
Mela, this is the solution:
Dinner bill = $ 26
Tip = 20% or 0.2
Tip = 26 * 0.2
Tip = $ 5.20
32. What is the rate of change of y with the respect to x for 24x - 4y = 50
The equation for the graph is given as
[tex]24x-4y=50[/tex]Let us rearrange the equation into its Slope-Intercept form given as
[tex]y=mx+c[/tex]Where
m = rate of change
c = y-intercept
Therefore, we will have
[tex]-4y=-24x+50[/tex]Divide all terms by -4 to make y a standalone variable:
[tex]\begin{gathered} \frac{-4y}{-4}=\frac{-24x}{-4}+\frac{50}{(-4)} \\ y=6x-\frac{25}{2} \end{gathered}[/tex]Comparing with the Slope-Intercept equation, the rate of change is given as 6.
Graphing with end behavior
SOLUTION
End behaviour
This describe the behaviour of the graph of a function at the end of the x-axis.
The end behavior of a function describes the trend of the graph if we look to the right end of the x-axis (as xxx approaches +∞, infinity) and to the left end of the x-axis (as x approaches -∞, negative infinity).
- 23 = -9+7(v - 3)could I please get some help
we have
- 23 = -9+7(v - 3)
apply distributive property right side
-23=-9+7v-21
combine like terms
-23=7v-30
Adds 30 both sides
-23+30=7v-30+30
7=7v
Divide by 7 both sides
7/7=7v/7
1=v
v=1