I’m stuck on this problem

Answer:

27/30

Step-by-step explanation:

9/10 x3 to both sides = 27/30

Answer:

[tex]\dfrac{27}{30}[/tex]

Explanation:

In a normal fraction such as [tex]\frac{a}{b}[/tex], a is the numerator and b is the denominator.

Here the given fraction is [tex]\frac{9}{10}[/tex], to rewrite the fraction with a denominator of 30. Multiply both the numerator and denominator by 3.

[tex]\rightarrow \dfrac{9}{10}[/tex]

[tex]\rightarrow \dfrac{9\:\times\:3}{10 \:\times \: 3}[/tex]

[tex]\rightarrow \dfrac{27}{30}[/tex]

Both the fractions are equivalent to each other.

we conclude that the linear equation in the graph is:

y = -2*x + 30

We can define the variables:

On the graph we can see two points:

(0, 30) and (15, 0).

Remember that a linear equation is of the form:

y = a*x + b

For the first point, we have:

30 = a*0 + b

30 = b

Then the line is:

y = a*x + 30

Now we can use the point (15, 0) to write:

0 = a*15 + 30

-30 = a*15

-30/15 = a = -2

Then we conclude that the linear equation in the graph is:

y = -2*x + 30

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Answer: A

Step-by-step explanation:

We can rewrite the expression as

[tex]\frac{\log_{3} 3}{\log_{3} m}[/tex]

Using the change of base formula, we get [tex]\log_{m} 3\[/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\text{Keep in mind that \boxed{of} means multiplication in mathematics and}\\\large\text{percentages run out of 100.}[/tex]

[tex]\mathsf{3\%\ of\ x = 10}[/tex]

[tex]\mathsf{\dfrac{3}{100}\ of\ x = 10}[/tex]

[tex]\mathsf{\dfrac{3}{100}\times x = 10}[/tex]

[tex]\mathsf{\dfrac{3}{100}x = 10}[/tex]

[tex]\textsf{Find the reciprocal of }\mathsf{\dfrac{3}{100}}\textsf{ and multiply that particular number on both sides.}[/tex]

[tex]\mathsf{\dfrac{3}{100}= \dfrac{100}{3}}[/tex]

[tex]\textsf{So, that means we have multiply by }\mathsf{\dfrac{100}{3}}\textsf{ to both of your sides.}[/tex]

[tex]\mathsf{\dfrac{100}{3}\times\dfrac{3}{100}x = 10\times \dfrac{100}{3}}[/tex]

[tex]\textsf{Cancel out: }\mathsf{\dfrac{100}{3}\times\dfrac{3}{100}}\textsf{ because it gives you 1}[/tex]

[tex]\textsf{Keep: }\mathsf{10\times\dfrac{100}{3}}\textsf{ because it gives you the value of x or simply understanding of}\\\textsf{the \boxed{\mathsf{x-value}}\ .}[/tex]

[tex]\mathsf{x = \dfrac{100}{3}\times10}[/tex]

[tex]\mathsf{x = \dfrac{100}{3}\times\dfrac{10}{1}}[/tex]

[tex]\mathsf{x = \dfrac{100\times10}{3\times1}}[/tex]

[tex]\mathsf{x = \dfrac{1,000}{3}}[/tex]

[tex]\mathsf{x\approx 333 \dfrac{1}{3}}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{x = }\frak{\dfrac{1,000}{3}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

The expression for 3(5 - 2) + (5 - 1) is 13.

Given: 3(x-2) + (x-1)

           3x-3(2)+x-1

           3x - 6 + x - 1

Compared 3(x -2) + (x - 1) with 3(5 - 2) + (5 - 1), the value of x is 5.

Substitute x = 5 into the result

           3x - 6 + x - 1

           3(5) - 6 + 5 - 1

           15 - 1 - 1

           15 - 2 = 13

The expression for 3(5 - 2) + (5 - 1) is 13.

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Answer:

With algebraic expressions, you can’t add and subtract any terms like you can add and subtract numbers. Terms must be like terms in order to combine them. So, you can’t always simplify an algebraic expression by following the order of operations. You have to use the distributive property to rewrite the expression and then combine like terms to simplify. With numeric expressions, you can either simplify inside the parentheses first or use the distributive property first.

Step-by-step explanation:

had it correct in edg

Answer:

13

Step-by-step explanation:

We can multiply both the whole equation by [tex]c^2-7c-18[/tex]. This is the LCM of all of the denominators. Notice that when [tex]c^2-7c-18[/tex] is factored, we obtain [tex](c - 9)(c+2)[/tex].

[tex]\frac{5}{c-9}\times(c^2-7c-18)=\frac{5}{c-9}\times(c-9)(c+2)=5(c+2)=5(c)+5(2)=5c+10[/tex]

An easier approach is to multiply each individual fraction like so:

[tex]\frac{5c-2}{c^2-7c-18}\times(c^2-7c-18)=5c-2[/tex]

[tex]\frac{3}{c+2}\times(c^2-7c-18)=\frac{3}{c+2}\times(c-9)(c+2)=3(c-9)=3c-27[/tex]

Then, we add them:

[tex]5c-2+(3c-27)=5c-2+3c-27=8c-29[/tex]

Therefore the whole equation is now:

[tex]5c+10=8c-29[/tex]

Subtract 5c from both sides:

[tex]10=3c-29[/tex]

Add 29 to both sides:

[tex]39=3c[/tex]

Divide both sides by 3

[tex]c=13[/tex]

[tex]\frac{5}{13-9}=\frac{5(13)-2}{169-91-14}+\frac{3}{13+2}\\\\\frac{5}{4}=\frac{63}{60}+\frac{3}{15}\\\\\frac{5}{4}=\frac{21}{20}+\frac{1}{5}\\\\\frac{5}{4}=\frac{21}{20}+\frac{1}{5}\\\\\frac{5}{4}=\frac{21}{20}+\frac{4}{20}\\\\\frac{5}{4}=\frac{25}{20}\\\\\frac{5}{4}=\frac{5}{4}\Rightarrow Correct![/tex]

Therefore,

c = 13

[tex]f(x) = y \: \: \ \: \: \: \: \: \: \: \: \: {normal \: function} \\ f(x) = y - 1 \: \: \: \: \: \: \: func\: shifted \: down[/tex]

[tex]f(x) = \frac{ - 1}{3} x {}^{2} \\ f(x) = \frac{ - 1}{3} x {}^{2} - 1[/tex]

Answer: F(x)= -1/3x2-1

Step-by-step explanation:

Answer:

7+21+15+19+.....+79

Here 21 be replaced by 11.

Now., common diffrence btw terms , d = 11-7 = 4

first term , a = 7

Last term , l = 79

number of terms = ( a + l ) ÷ d

=( 7 + 79 ) ÷ 4 = 86 ÷ 4 = 21.5 { It cannot be in decimal }

There's some mistake in the terms you provided please check your question again...

Answer:

301.5936 cubic ft

Step-by-step explanation:

Formula for the volume of a cylinder is V = pi*r*r*h, where r represents the radius and h represents the height of the cylinder. Since radius is half the length of diameter, the pipe has a radius of 4/2 = 2 ft.

V = pi*r*r*h = 3.1416*2*2*24 = 301.5936 cubic ft

The information given that A, B, and C are equal in length; each one is 4.47 units long illustrates that the angle is an equilateral triangle.

Secondly, when two of its sides are congruent, then the triangle is an isosceles triangle.

It should be noted that an equilateral triangle simply means the triangle tht had equal shape and angles. Here, since A, B, and C are equal in length; each one is 4.47 units long illustrates that the angle is an equilateral triangle.

Secondly, when two of its sides are congruent, then the triangle is an isosceles triangle. On such triangle, two out of the three sides are equal.

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See attachment for the graph of cell phone plan 1: y= 7.5x and cell phone plan 2: y= 5.5x + 10.1

Linear equations are equations that have constant average rates of change, slope or gradient

The cell phone plans are given as:

Cell phone plan 1: y= 7.5x

Cell phone plan 2: y= 5.5x + 10.1

To plot the graph of both plans, we make use of the following domain for both cell phone plans

Domain: x >= 0

Next, we set x = 0, 1, 2, 3, 4 and 5 for both plans

So, we have:

Cell phone plan 1

y= 7.5x

When x = 0, y = 7.5 * 0 = 0

When x = 1, y = 7.5 * 1 = 7.5

When x = 2, y = 7.5 * 2 = 15

When x = 3, y = 7.5 * 3 = 22.5

When x = 4, y = 7.5 * 4 = 30

When x = 5, y = 7.5 * 5 = 37.5

Cell phone plan 2

y= 5.5x + 10.1

When x = 0, y = 5.5*0 + 10.1 = 10.1

When x = 1, y = 5.5 * 1 + 10.1 = 15.6

When x = 2, y = 5.5 * 2 + 10.1 = 21.1

When x = 3, y = 5.5 * 3 + 10.1 = 26.6

When x = 4, y = 5.5 * 4 + 10.1 = 32.1

When x = 5, y = 5.5 * 5 + 10.1= 37.6

Next, we plot both graphs on the domain x >= 0

See attachment for the graph of cell phone plan 1: y= 7.5x and cell phone plan 2: y= 5.5x + 10.1

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Answer:

the triangle is a right angle triangle. I can't see the correct explanation here so I will explain

Step-by-step explanation:

to work out whether triangles are right angle you do :

square root of (5² + 12²) so it would be 25 + 144 =169 and the square root of 169 is 13 . we do this because the square root of both of the side lengths squares should make ths longer side in this case it makes 13 so it is a right angled triangled

i hope this helps . if you need any more help pls ask :)

Answer:

Step-by-step explanation:

RM 280 = 40% of 8 months

RM 700= 100% of 8 months

RM 700/8= 8 months

RM 87.5 = 1 month

Answer = 87.5

Farid's monthly salary is approximately RM 87.5. He spends 40% of his total 8-month expenditure on house rent, which amounts to RM 280 per month.

Let's assume Farid's monthly salary is RM x.

Given that he spends 40% of his total 8 monthly expenditure on house rent, and the amount he spends on house rent is RM 280, we can set up the following equation:

0.40 × 8x = 280

Now, let's solve for x:

0.40 × 8x = 280

3.2 × x = 280

x = 280 / 3.2

x ≈ 87.5

So, Farid's monthly salary is approximately RM 87.5.

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The average of the values from that average of 6 is 0

We have the numbers to be

0 2 4 10 14 and have an average of 6

To find their distances, we should substract each from the given average

We have;

6 - 0 =6

6 -2 = 4

6 -4 = 2

6 - 10 = -4

6 - 14 = -8

The average of this distances is

= pro

= [tex]\frac{0}{6}[/tex]

= 0

Thus, the average of the values from that average of 6 is 0

The complete question is

These values have an average of 6. What is the average distance of those values from that average of 6?

0 2 4 10 14

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Answer:

C

Step-by-step explanation:

Let's review some sets of numbers.

Natural numbers: 1, 2, 3, 4, ...

The natural numbers are the counting numbers. You normally start counting with 1, not 0, and you only count whole numbers.

Whole numbers: 0, 1, 2, 3, 4, 5, ...

The whole numbers are the counting numbers with the addition of zero. There are no negative numbers in the whole numbers.

Integers: ..., -3, -2, -1, 0, 1, 2, 3, ...

The integers are the natural numbers, plus zero, plus the negatives of the natural numbers. All numbers are whole with no decimal part.

Rational numbers

The rational numbers are all numbers that can be written as a fraction of integers. For example, 1 can be written as 3/3, so 1 is a rational number. All natural numbers, whole numbers, and integers are rational numbers. Other rational numbers are numbers that are not whole, such as 2.5, 7/8, 1/4, etc. These numbers can be written as fractions of integers. Rational numbers written as decimal numbers will either be an integer, a terminating decimal, or a non-terminating, repeating decimal.

Up to here, each new set includes the previous set.

Now things change. If a number is rational, it is not irrational.

If a number is irrational, it is not rational.

Irrational numbers

Irrational numbers are always non-terminating, non-repeating decimals. They cannot be written as fractions of integers. Examples: √2, π

Now let's look at this problem.

We have a negative decimal number. The bar above the 12 means the digits 12 are repeating. This number can also be written as -0.121212...

Since our number is a non-terminating, repeating decimal, it is a rational number.

Answer: C

The numbers which are a part of the domain for the graph are: 6, 1 and 2.

The domain of a graph is a set of all possible input, x-values. Consequently, since the domain of the graph given ranges over intergers, 1 to 10, it follows that numbers which are part of the domain are; 6, 2, and 1.

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The average view of the dress code is that this dress is not good

For Rashad's sample to be a random sample gotten from the population, the following must be considered.

To do this, we simply create a bar graph.

The response would go into the x-axis, while the number of people would go into the y-axis

See attachment for bar graph

The average view of the dress code is that this dress is not good

It is considered the average view of the dress code because it is the opinion with the most frequency

The number of students that do not like the dress as:

210 + 206 + 770 = 1186

Their percentage is

Percentage = 1186/(210 + 206 + 770 + 358)

Percentage = 77%

This means that

Yes, the dress will change

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Answer:

Step-by-step explanation:

Beatrice's conclusion is wrong

All of these points are not on the same line, because are different parallel lines

The slope between (-2,-1) and (1,0) is equal to 1/2

Answer:

Beatrice is incorrect. All of these points are not on the same line because the slope between (-2,-1) and (1,0) which are coordinates fr each of the pairs above, are equal to 1/2

Step-by-step explanation:

Let m1 be first slope

[tex]m1 \: = \frac{y2 - y1}{x2 - x1}= \frac{0 - ( - 2)}{4 - ( - 2)}= \frac{0 + 2}{4 + 2} \\ = \frac{2}{4} = \frac{1}{2} [/tex]

Let m2 be second slope

m2 = (y2 - y1)/ (x2 - x1)

= (2-(-1)) / (4-(-2)

= (2+1) / (4+2)

= 3/6 =1/2

Thus, the slopes are different parallel lines because m1 =m2

Answer:

linear

Step-by-step explanation:

This is a line with slope  m = 8  and y-axis intercept of 10

Answer:

linear

Step-by-step explanation:

y = 8x + 10

is an equation in the form y = mx + b.

The form y = mx + b is called the slope-intersect form of the equation of a line.

Since it is the equation of a line, it is linear.

Answer:

  (5, 1)

Step-by-step explanation:

The vertex is the turning point on the graph. Its coordinates are read from the axes labels.

The term vertex is used in several different contexts. A vertex of a polygon is a point where edges meet. A vertex of a curve is an extreme value of the curve.

When applied to an ellipse, the vertices are the ends of the major axis. The ends of the minor axis are the co-vertices.

The vertex of a parabola is the extreme value of the parabola. When it opens downward, as here, the vertex is the point where the curve is at its maximum.

As with any point on any graph, the coordinates of the vertex are read from the labels of the axes. The horizontal coordinate is customarily listed first.

The vertex is (x, y) = (5, 1).

Answer:

5/52 i think

Step-by-step explanation:

there are 52 cards in desk ,with26red and black cards.There 2red and 2 blackthree and. 1 six of hearts .

.

.

.

.

.

.

.

The coordinates of the vertices of the preimages are A ( 3, 5) , B ( 1, 2) and C ( 7, -1)

It is important to note the following about the 90 degrees rotation about the origin

Note that

A ( x, y) is the coordinates of the preimage

A' ( -y , x) is the coordinates after the said rotation about the origin

Converting the transformed coordinates to the preimage coordinates

For vertex A

A' ( 5, 3)

Compare with A' ( -y, x)

x = 3

y = -5

Substitute the values

A ( 3, 5 )

For vertex B

B' ( -2, 1)

Compare with B' ( -y, x)

x = 1

y = 2

Substitute the values

B ( 1, 2)

For vertex C

C' ( 1, 7)

Compare with C' ( -y, x)

x = 7

y = -1

Substitute the values

C ( 7, -1)

Thus, the coordinates of the vertices of the preimages are A ( 3, 5) , B ( 1, 2) and C ( 7, -1)

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Answer:

16.8

Step-by-step explanation:

here is that kite on a graph. you can see there are 2 sides of length 5, and 2 sides of length 3, so closest perimeter is 16.8

Answer:

-15 would be the answer because if it's below sea level it would have a negative sign in front of 15

Step-by-step explanation:

Answer:

Option 2

Step-by-step explanation:

Since theta is in the third quadrant, the sine of theta is negative.

By the Pythagorean identity,

[tex]\sin \theta=-\frac{\sqrt{105}}{13}[/tex]

So, using the double angle formula for sine, we get that

[tex]\sin 2\theta=\frac{16\sqrt{105}}{169}[/tex]

Answer:

Step-by-step explanation:

The equation will be in standard form when terms are listed in order of decreasing degree, and the right side of the equation is 0.

We can subtract the right-side expression from both sides to get standard form.

  -3x² -8 -(5x -7) = 5x -7 -(5x -7)

  -3x² -8 -5x +7 = 0 . . . . . . . simplify a bit

  -3x² -5x -1 = 0 . . . . . . . . . collect terms

The standard form equation can be written ...

  -3x² -5x -1 = 0

The quadratic coefficient is the coefficient of the term with degree 2. The quadratic coefficient is -3.

The linear coefficient is the coefficient of the term with degree 1. The linear coefficient is -5.

The constant coefficient is the coefficient of the term with no variables. The constant is -1.

__

Additional comment

We can make the leading coefficient positive by multiplying the equation by -1. This gives ...

  3x² +5x +1 = 0

with quadratic, linear, and constant coefficients 3, 5, 1.

This is a legitimate answer to this question. In the case of linear equations, the "standard form" has the constant on the right side of the equal sign, and the leading coefficient is required to be positive. A negative leading coefficient can sometimes lead to errors (when the sign is overlooked), so having a positive leading coefficient is often preferred.

The value of function f(x) over g(x) is [tex]2x^{2} +4x-1-\frac{9}{4x+1}[/tex]

Given functions are:

f(x)=8[tex]x^{3}[/tex]+18[tex]x^{2}[/tex]-10

g(x)=4x+1

In mathematics, a function is an expression, rule, or law that establishes the relationship between an independent variable and a dependent variable (the dependent variable). Functions exist everywhere, and they are crucial for constructing physical links in the sciences.

In mathematics, a function is represented as a rule that produces a distinct result for each input x. A function is indicated by a mapping or transformation. The collection of all the values that the function may input while it is defined is known as the domain. The entire set of values that the function's output can produce is referred to as the range. The set of values that could be a function's outputs is known as the co-domain.

[tex]\frac{f(x)}{g(x)}=\frac{8x^{3}+18x^{2} -10 }{4x+1}[/tex]

      = [tex]2x^{2} +4x-1-\frac{9}{4x+1}[/tex]

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