In a moment of Inertia vs r (radius) graph what are the units of the coefficient ? What does this coefficient represent? Also how can the conditions of equilibrium were applied to these investigations of a newton's second of rotation lab.

The problem involves a ball being thrown vertically upward with an initial speed of 18 m/s. The task is to determine: a) the time taken to reach a height of 10m, b) the speed of the ball at a height of 10m, and c) the position of the ball after 2 seconds.

To solve this problem, we can use the equations of motion for vertical motion under constant acceleration. The key parameters involved are time, speed, and position.

a) To find the time taken to reach a height of 10m, we can use the equation: h = u*t + (1/2)*g*t^2, where h is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time. By substituting the given values, we can solve for t.

b) To find the speed of the ball at a height of 10m, we can use the equation: v = u + g*t, where v is the final velocity. We can substitute the known values of u, g, and the previously calculated value of t to find the speed.

c) To find the position of the ball after 2 seconds, we can again use the equation: h = u*t + (1/2)*g*t^2. By substituting the known values of u, g, and t = 2s, we can calculate the position of the ball after 2 seconds.

In summary, we can determine the time taken to reach 10m by solving an equation of motion, find the speed at 10m using another equation of motion, and calculate the position after 2 seconds using the same equation.

Learn more about speed:

https://brainly.com/question/17661499

#SPJ11

(a) The friction force f has a magnitude of 50 N.

(b) The force acting on block B from block A also has a magnitude of 50 N.

(c) Force on block B from block A is equal to pushing force F = 50 N due to equal masses and inertia.

To solve this problem, we need to consider the forces acting on each block and apply Newton's second law of motion.

(a) To determine the magnitude of the friction force f, we need to consider the equilibrium condition where the blocks do not accelerate. Since the force F = 50 N is pushing horizontally to the right on block A, the friction force f acts in the opposite direction.

Therefore, the magnitude of the friction force f is also 50 N.

(b) The force acting on block B from block A can be determined by considering the interaction between the two blocks. Since the blocks are touching and there is a friction force f acting between them, the force exerted by block A on block B is equal in magnitude but opposite in direction to the friction force f.

Hence, the magnitude of the force acting on block B from block A is also 50 N.

(c) The force on block B from block A being equal to the pushing force F = 50 N is consistent with the concept of inertia. Inertia refers to an object's resistance to changes in its motion. In this case, since block B is in contact with block A and they are both at rest, the force required to keep block B stationary (the friction force f) is equal to the force applied to block A (the pushing force F). This is because the force needed to move or stop an object is proportional to its mass.

Therefore, since the two blocks have the same mass and are at rest, the force required to stop block B (friction force f) is equal to the applied force on block A (pushing force F).

The complete question should be:

A force F = 50 N is pushing horizontally to the right on block A. Block A and B are touching and arranged left to right on a flat table. The same friction force f acts back on both blocks and stops things from accelerating.

(a) What is the magnitude of this friction force f in Newtons?

(b) What is the magnitude of the force (in Newtons) that acts on block B from block A?

(c) Does this make sense that the force on block B from block A is greater than, less than, or equal to the pushing force F = 50 N? Relate your answer to the concept of inertia: that is that heavy things are hard to move; heavy things are hard to stop; inertia is now measured by what we call mass.

To learn more about Inertia, Visit:

https://brainly.com/question/1140505

#SPJ11

When performing Young's double slit experiment, at 6132.64 angle

(in degrees) is the first-order maximum for 638 nm wavelength light

falling on double slits if the separation distance is 0.0560

mm.

In Young's double-slit experiment, the angle for the first-order maximum can be determined using the formula:

θ = λ / (d * sin(θ))

Where:

θ is the angle for the first-order maximum,

λ is the wavelength of light,

d is the separation distance between the slits.

Given:

λ = 638 nm = 638 × 10^(-9) meters

d = 0.0560 mm = 0.0560 × 10^(-3) meters

Let's calculate the angle θ:

θ = (638 × 10^(-9)) / (0.0560 × 10^(-3) * sin(θ))

To solve this equation, we can make an initial guess for θ and then iteratively refine it using numerical methods. For a rough estimate, we can assume that the angle is small, which allows us to approximate sin(θ) ≈ θ (in radians). Therefore:

θ ≈ (638 × 10^(-9)) / (0.0560 × 10^(-3) * θ)

Simplifying the equation:

θ^2 ≈ (638 × 10^(-9)) / (0.0560 × 10^(-3))

θ^2 ≈ (638 / 0.0560) × (10^(-9) / 10^(-3))

θ^2 ≈ 11428.6

Taking the square root of both sides:

θ ≈ √11428.6

θ ≈ 106.97 radians (approximately)

To convert this angle from radians to degrees, we multiply by the conversion factor:

θ ≈ 106.97 * (180 / π)

θ ≈ 6132.64 degrees

Therefore, the approximate angle for the first-order maximum in Young's double-slit experiment with 638 nm wavelength light falling on double slits with a separation distance of 0.0560 mm is approximately 6132.64 degrees.

To learn more about angle follow the given link below

https://brainly.com/question/25716982

#SPJ11

The energy released in the alpha decay of 220 Rn is approximately 3.720 x 10^-11 Joules.

To find the energy released in the alpha decay of 220 Rn (220.01757 u), we need to calculate the mass difference between the parent nucleus (220 Rn) and the daughter nucleus.

The alpha decay of 220 Rn produces a daughter nucleus with two fewer protons and two fewer neutrons, resulting in the emission of an alpha particle (helium nucleus). The atomic mass of an alpha particle is approximately 4.001506 u.

The mass difference (∆m) between the parent nucleus (220 Rn) and the daughter nucleus can be calculated as:

∆m = mass of parent nucleus - a mass of daughter nucleus

∆m = 220.01757 u - (mass of alpha particle)

∆m = 220.01757 u - 4.001506 u

∆m = 216.016064 u

Now, to calculate the energy released (E), we can use Einstein's mass-energy equivalence equation:

E = ∆m * c^2

where c is the speed of light in a vacuum, approximately 3.00 x 10^8 m/s.

E = (216.016064 u) * (1.66053906660 x 10^-27 kg/u) * (3.00 x 10^8 m/s)^2

E ≈ 3.720 x 10^-11 Joules

Learn more about alpha decay at https://brainly.com/question/1898040

#SPJ11

The magnitude of the magnetic field at a point 16 mm from the center of the hollow cylinder is 0.0625 T.

To calculate the magnitude of the magnetic field at a point 16 mm from the center of the hollow cylinder, we can use Ampere's law.

Ampere's law states that the magnetic field around a closed loop is directly proportional to the current passing through the loop.

The formula for the magnetic field produced by a current-carrying wire is:

B = (μ₀ * I) / (2π * r)

where B is the magnetic field, μ₀ is the permeability of free space (4π × 10^-7 T·m/A), I is the current, and r is the distance from the center of the wire.

In this case, the current I is 5.0 A, and the distance r is 16 mm, which is equivalent to 0.016 m.

Plugging the values into the formula, we have:

B = (4π × 10^-7 T·m/A * 5.0 A) / (2π * 0.016 m)

B = (2 × 10^-6 T·m) / (0.032 m)

B = 0.0625 T

To learn more about Ampere's law: https://brainly.com/question/32676356

#SPJ11

Answer:

Mass = density * volume = ρ V

Mass of wood = Mass Water + Mass Oil   (multiply by g to get weight)

Vw ρw = 3/7 V (1000 kg/m^3) + 4/7 V 300 kg/m^3)

Let V be 1

ρw = (3000 + 1200) kg/m^3/ 7 = 600 kg/m^3

Density = 600 kg/m^3

The question asks for the actual depth of a fish when the apparent depth is given, and it suggests using Snell's law and the law of refraction to solve the problem.

Snell's law relates the angles of incidence and refraction of a light ray at the interface between two media with different refractive indices. In this scenario, the fisherman is observing the fish through the interface between air and water. The apparent depth is the perceived depth of the fish, and it is different from the actual depth due to the refraction of light at the air-water interface.

To find the actual depth, we can use Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the speeds of light in the two media. By knowing the angle of incidence and the refractive indices of air and water, we can determine the angle of refraction and calculate the actual depth.

The law of refraction, also known as the law of Snellius, states that the ratio of the sines of the angles of incidence and refraction is equal to the reciprocal of the ratio of the refractive indices of the two media. By applying this law along with Snell's law, we can determine the actual depth of the fish based on the given apparent depth and the refractive indices of air and water.

Learn more about Depth:

https://brainly.com/question/31260615

#SPJ11

The wavelength of the earthquake with a frequency of 11.5 Hz is 7.6 km.

The frequency of the earthquake = 11.5 Hz

Velocity of earthquake waves = 6000 m/s

We know that,

v = λf  where,

λ is the wavelength of the earthquake.

f is the frequency of the earthquake.

Therefore,λ = v / f = 6000 / 11.5 = 521.73 m

We can convert the value from meters to kilometers by dividing it by 1000.

Thus,λ = 0.52173 km

Now, the earthquake travels 87 km in 15 s.

Hence, its speed is 87 / 15 = 5.8 km/s.

The wavelength of the earthquake when it reaches another city is,

v/f = (5.8 x 10^3 m/s) / (11.5 Hz) = 504.35 m

This can also be expressed in kilometers, as 0.50435 km or 504.35 meters or 7.6 km.

Learn more about wavelength https://brainly.com/question/10750459

#SPJ11

To determine the frequency at which you will hear the sound from the fast-moving vehicle, we need to consider the Doppler effect. we will hear the sound from the fast-moving vehicle at approximately 12.13 Hz. this intensity is enough to damage your hearing depends on the duration of exposure.  Prolonged exposure to high-intensity sound levels can potentially damage hearing.

The formula to calculate the observed frequency (f') is:

f' = f * (v + v_o) / (v + v_s)

where f is the source frequency (given as X Hz), v is the speed of sound (approximately 343 m/s), v_o is the observer's velocity (0 m/s since you are standing still), and v_s is the source's velocity (given as Y m/s).

Substituting the given values, we have:

f' = X * (343 + 0) / (343 + Y)

Using Y = 78.15 m/s and X = 15 Hz, we can calculate the observed frequency:

f' = 15 * (343) / (343 + 78.15) ≈ 12.13 Hz

Therefore, we will hear the sound from the fast-moving vehicle at approximately 12.13 Hz.

[d] To calculate the intensity in watts per square meter (W/m²) corresponding to a given sound level in decibels (Y dB), we use the formula:

I = 10^((Y - Y₀) / 10)

where Y₀ is the reference sound level of 0 dB, which corresponds to an intensity of 1 x 10^(-12) W/m².

Substituting the given value Y = 78.15 dB, we have:

I = 10^((78.15 - 0) / 10) = 10^7.815

Calculating this value, we find:

I ≈ 6.31 x 10^7 W/m²

Whether this intensity is enough to damage your hearing depends on the duration of exposure. Prolonged exposure to high-intensity sound levels can potentially damage hearing. It is important to take appropriate precautions and limit exposure to loud sounds.

To learn more about, Doppler effect, click here, https://brainly.com/question/14833267

#SPJ11

Two people are fighting over a 0.25 kg stick. One person pulls to the right with a force of 24 N and the other person pulls to the left with 25 N.  The magnitude of the acceleration is 4 m/s², and the direction is to the left (negative direction). Therefore, the stick accelerates to the left with an acceleration magnitude of 4 m/s².

It is assumed that the positive direction is to the right, and the negative direction is to the left.

Force to the right (F[tex]_r[/tex]) = 24 N

Force to the left (F[tex]_l[/tex]) = -25 N (negative sign indicates the opposite direction)

The net force (F[tex]_n_e_t[/tex]) is given by:

F[tex]_n_e_t[/tex] = F[tex]_r[/tex] + F[tex]_l[/tex]

F[tex]_n_e_t[/tex] = 24 N + (-25 N)

F[tex]_n_e_t[/tex] = -1 N

The net force acting on the stick is -1 N to the left. Since force is equal to mass multiplied by acceleration (F = ma), we can calculate the acceleration (a) using Newton's second law of motion.

F[tex]_n_e_t[/tex] = ma

-1 N = 0.25 kg × a

Solving for acceleration:

a = -1 N / 0.25 kg

a = -4 m/s²

Hence, the magnitude of the acceleration is 4 m/s². The stick accelerates to the left with an acceleration magnitude of 4 m/s².

Learn more about the calculation of acceleration here.

https://brainly.com/question/390784

#SPJ4

A biological material's length is expanded by 1301%, it will have a tensile strain of 1.301 and a Young's modulus of 3.301 GPa. The nail needs to be bent by 100 micrometres with a force of 20 N. The stress of 10⁸ Pa is equivalent to a pressure of 100 MPa.

(a.) The equation: gives the substance's tensile strain.

strain equals (length changed) / (length at start)

The length change in this instance is X = 1301% of the initial length.

The strain is therefore strain = (1301/100) = 1.301.

A material's Young's modulus indicates how much stress it can tolerate before deforming. The Young's modulus in this situation is Y = 3.301 GPa. Consequently, the substance's stress is as follows:

Young's modulus: (1.301)(3.301 GPa) = 4.294 GPa; stress = (strain)

The force per unit area is known as the stress. As a result, the amount of force needed to deform the substance is:

(4.294 GPa) = force = (stress)(area)(area)

b.) The equation: gives the amount of force needed to bend the nail.

force = young's modulus, length, and strain

In this instance, the nail's length is L = 10 cm, the Young's modulus is Y = 200 GPa, and the strain is = 0.001.

Consequently, the force is:

force equals 20 N (200 GPa) × 10 cm × 0.001

The nail needs to be bent by 100 micrometres with a force of 20 N.

(c)The force per unit area at a depth of w = 1000 meters is given by the equation:

stress = (weight density)(depth)

In this case, the weight density of water is ρ = 1000 kg/m³, and the depth is w = 1000 meters.

Therefore, the stress is:

stress = (1000 kg/m³)(1000 m) = 10⁸ Pa

The stress of 10⁸ Pa is equivalent to a pressure of 100 MPa.

To know more about young's modulus:

https://brainly.com/question/33261312

#SPJ4

The amplitude of the oscillation is 0.35 meters.

When a block is attached to a spring and released, it undergoes oscillatory motion with a period of 0.40 seconds. To find the amplitude of this oscillation, we need to use the energy conservation principle and the formula for the period of oscillation.

Calculate the spring constant (k)

To find the amplitude, we first need to determine the spring constant. The energy supplied to stretch the spring can be written as:

E = (1/2)kx^2

where E is the energy, k is the spring constant, and x is the displacement from the equilibrium position. We know that the energy supplied is 15 J, and the block's mass is 3.0 kg. Rearranging the equation, we have:

k = (2E) / (m * x^2)

Substituting the given values, we get:

k = (2 * 15 J) / (3.0 kg * x^2)

k = 10 / x^2

Calculate the angular frequency (ω)

The period of oscillation (T) is given as 0.40 seconds. The period is related to the angular frequency (ω) by the equation:

T = 2π / ω

Rearranging the equation, we find:

ω = 2π / T

ω = 2π / 0.40 s

ω ≈ 15.7 rad/s

Calculate the amplitude (A)

The angular frequency is related to the spring constant (k) and the mass (m) by the equation:

ω = √(k / m)

Rearranging the equation to solve for the amplitude (A), we get:

A = √(E / k)

Substituting the given values, we have:

A = √(15 J / (10 / x^2))

A = √(15x^2 / 10)

A = √(3/2)x

Since we want the amplitude in meters, we can calculate it by substituting the given values:

A = √(3/2) * x

A ≈ √(3/2) * 0.35 m

A ≈ 0.35 m

Therefore, the amplitude of the oscillation is approximately 0.35 meters.

Learn more about amplitude

brainly.com/question/9525052

#SPJ11

The correct answer is that the activity of the sample after 15 years is approximately 34.198 Bq.

The activity of a radioactive sample can be determined by using a formula that relates the number of radioactive nuclei present to the elapsed time and the half-life of the substance.

A = A0 * (1/2)^(t / T1/2)

where A0 is the initial activity, t is the time elapsed, and T1/2 is the half-life of the radioactive material.

In this case, we are given the initial activity A0 = 35.0 kBq, and the half-life T1/2 = 432 years. We need to calculate the activity after 15 years.

By plugging in the provided values into the given formula, we can calculate the activity of the radioactive sample.

A = 35.0 kBq * (1/2)^(15 / 432)

Calculating the value, we get:

A ≈ 35.0 kBq * (0.5)^(15 / 432)

A ≈ 35.0 kBq * 0.97709

A ≈ 34.198 Bq

Therefore, the correct answer is that the activity of the sample after 15 years is approximately 34.198 Bq.

Learn more about activity at: https://brainly.com/question/28570637

#SPJ11

The answer is e. 2.5A, the current in the 15-V emf is 2.5A. This is because the voltage across the circuit is 15 volts and the resistance of the

is 6 ohms.

The current is calculated using the following equation: I = V / R

where:

In this case, the voltage is 15 volts and the resistance is 6 ohms, so the current is: I = 15 / 6 = 2.5A

The current in a circuit is the amount of charge that flows through the circuit per unit time. The voltage across a circuit is the difference in electrical potential between two points in the circuit. The resistance of a circuit is the opposition to the flow of current in the circuit.

The current in a circuit can be calculated using the following equation:

I = V / R

where:

In this case, the voltage is 15 volts and the resistance is 6 ohms, so the current is: I = 15 / 6 = 2.5A, Therefore, the current in the 15-V emf is 2.5A.

To know more about circuit click here

brainly.com/question/24430575

#SPJ11

The linear distance (Δx) between the seventh order maximum and the second order maximum on the screen is approximately 1.6656 meters.

To find the linear distance (Δx) between the seventh order maximum and the second order maximum on the screen in a double-slit interference experiment, we can use the formula for the location of the maxima:

[tex]\Delta x=(m_2-m_7)\frac{\lambda D}{d}[/tex]

where [tex]m_2[/tex] is the order number of the second order maximum, [tex]m_7[/tex] is the order number of the seventh order maximum, λ is the wavelength, D is the distance between the slits and the screen, and d is the slit separation.

Given:

Wavelength (λ) = 727 nm = [tex]727 \times 10^{-9}[/tex] m

Slit separation (d) = 0.110 mm = [tex]0.110 \times 10^{-3}[/tex] m

Distance to screen (D) = 40.0 cm = [tex]40.0 \times 10^{-2}[/tex] m

Order number of second maximum ([tex]m_2[/tex]) = 2

Order number of seventh maximum ([tex]m_7[/tex]) = 7

Substituting the values into the formula:

[tex]\Delta x=(7-2)\times\frac{(727\times10^{-9})(40.0\times10^{-2})}{(0.110\times10^{-3})}[/tex]

Simplifying the calculation:

Δx = [tex]\frac{5\times727\times40.0}{0.110}[/tex]

Δx ≈ 1.6656 m

Therefore, the linear distance (Δx) between the seventh order maximum and the second order maximum on the screen is approximately 1.6656 meters.

Learn more about distance here: brainly.com/question/114551

#SPJ11

In problem 5.1, a thermodynamic system with N spatially separated subsystems has non-degenerate energy levels of 0, €, 2€, and 3€. The system is in thermal equilibrium with a heat reservoir at a temperature of e/k. Therefore:

Problem 5.1: The partition function is [tex]Z = 1 + 2e^(-e/kT) + 4e^(-2e/kT) + 4e^(-3e/kT)[/tex]. The mean energy is <E> = e/2, and the entropy is [tex]S = k ln(1 + 2e^(-e/kT) + 4e^(-2e/kT) + 4e^(-3e/kT))[/tex]

Problem 5.2: The partition function is extended with additional terms. The mean energy is <E> = e/2 + γ, and the entropy is [tex]S = k ln(1 + 2e^(-e/kT) + 4e^(-2e/kT) + 4e^(-3e/kT) + 1 + 2e^(-(e-2γ)/kT) + 4e^(-(2e-4γ)/kT) + 4e^(-(3e-6γ)/kT))[/tex]

Problem 5.1

The partition function for a system of N spatially separated subsystems, each with non-degenerate energy levels of energy 0,€, 2€, and 3€, in thermal equilibrium with a heat reservoir of absolute temperature T equal to e/k is given by:

[tex]Z = 1 + 2e^(-e/kT) + 4e^(-2e/kT) + 4e^(-3e/kT)[/tex]

The mean energy of the system is given by:

[tex]< E > = -kT \frac{d ln Z}{dT} = e/2[/tex]

The entropy of the system is given by:

[tex]S = k ln Z = k ln(1 + 2e^(-e/kT) + 4e^(-2e/kT) + 4e^(-3e/kT))[/tex]

Problem 5.2

The partition function for a system of N spatially separated subsystems, each with degenerate energy levels of energy 0,€, 2€, and 3€, in thermal equilibrium with a heat reservoir of absolute temperature T equal to e/k is given by:

[tex]Z = 1 + 2 * exp(-e / (k * T)) + 4 * exp(-2 * e / (k * T)) + 4 * exp(-3 * e / (k * T)) + 1 + 2 * exp(-(e - 2 * γ) / (k * T)) + 4 * exp(-(2 * e - 4 * γ) / (k * T)) + 4 * exp(-(3 * e - 6 * γ) / (k * T))[/tex]

where γ is the energy gap between the ground state and the first excited state.

The mean energy of the system is given by:

[tex]< E > = -kT * d(ln Z) / dT = e/2 + γ[/tex]

The entropy of the system is given by:

[tex]S = k * ln(Z)S = k * ln(1 + 2 * exp(-e / (k * T)) + 4 * exp(-2 * e / (k * T)) + 4 * exp(-3 * e / (k * T)) + 1 + 2 * exp(-(e - 2 * γ) / (k * T)) + 4 * exp(-(2 * e - 4 * γ) / (k * T)) + 4 * exp(-(3 * e - 6 * γ) / (k * T)))[/tex]

To know more about the thermodynamic system refer here,

https://brainly.com/question/30076665#

#SPJ11

There are six unique combinations: (2, 0, 0), (0, 2, 0), (0, 0, 2), (1, 1, 0), (1, 0, 1), and (0, 1, 1). Therefore, the order of degeneracy is 6. The pattern continues, with the order of degeneracy increasing as the energy level increases.

The eigenvalues and eigenfunctions for a three-dimensional identical harmonic oscillator can be obtained by solving the Schrödinger equation for the system. The eigenvalues represent the energy levels of the oscillator, and the eigenfunctions represent the corresponding wavefunctions.

The energy eigenvalues for a three-dimensional harmonic oscillator can be expressed as:

E_n = (n_x + n_y + n_z + 3/2) ħω

where n_x, n_y, and n_z are the quantum numbers along the x, y, and z directions, respectively. The quantum number n represents the energy level of the oscillator, with n = n_x + n_y + n_z. ħ is the reduced Planck's constant, and ω is the angular frequency of the oscillator.

The order of degeneracy (d) for a given energy level can be calculated by finding all the unique combinations of quantum numbers (n_x, n_y, n_z) that satisfy the condition n = n_x + n_y + n_z. The number of such combinations corresponds to the degeneracy of that energy level.

For the ground state (n = 0), there is only one unique combination of quantum numbers, (n_x, n_y, n_z) = (0, 0, 0), so the order of degeneracy is 1.

For the first excited state (n = 1), there are three unique combinations: (1, 0, 0), (0, 1, 0), and (0, 0, 1). Hence, the order of degeneracy is 3.

For the second excited state (n = 2), there are six unique combinations: (2, 0, 0), (0, 2, 0), (0, 0, 2), (1, 1, 0), (1, 0, 1), and (0, 1, 1). Therefore, the order of degeneracy is 6.

The pattern continues, with the order of degeneracy increasing as the energy level increases.

Learn more about degeneracy from the given link

https://brainly.com/question/14439838

#SPJ11

So the answer is c. 450W. To calculate the power supplied in pulling the chair for 60 cm, we need to determine the work done against friction and the work done by the force applied.

The power can be calculated by dividing the total work by the time taken. Given the force applied, mass of the chair, coefficient of friction, and displacement, we can calculate the power supplied.

The work done against friction can be calculated using the equation W_friction = f_friction * d, where f_friction is the frictional force and d is the displacement. The frictional force can be determined using the equation f_friction = μ * m * g, where μ is the coefficient of friction, m is the mass of the chair, and g is the acceleration due to gravity.

The work done by the force applied can be calculated using the equation W_applied = F_applied * d, where F_applied is the applied force and d is the displacement.

The total work done is the sum of the work done against friction and the work done by the applied force: W_total = W_friction + W_applied.

Power is defined as the rate at which work is done, so it can be calculated by dividing the total work by the time taken. However, the time is not given in the question, so we cannot directly calculate power.

The work done in pulling the chair is:

Work = Force * Distance = 115 N * 0.6 m = 69 J

The power you supplied is:

Power = Work / Time = 69 J / (60 s / 60 s) = 69 J/s = 69 W

The frictional force acting on the chair is:

Frictional force = coefficient of friction * normal force = 0.33 * 5.5 kg * 9.8 m/s^2 = 16.4 N

The net force acting on the chair is:

Net force = 115 N - 16.4 N = 98.6 N

The power you supplied in pulling the crate for 60 cm is:

Power = 98.6 N * 0.6 m / (60 s / 60 s) = 450 W

So the answer is c.

Learn more about power here: brainly.com/question/29883444

#SPJ11

This equation relates the average vertical velocity to the temperature and the mass of the gas molecules.

In an ideal gas contained in a cube, the average vertical component of the velocity of the gas molecules is given by the equation \( v = \sqrt{\frac{3kT}{m}} \), where \( k \) is the Boltzmann constant, \( T \) is the temperature, and \( m \) is the mass of the gas molecules.

The average vertical component of the velocity of gas molecules in an ideal gas can be determined using the kinetic theory of gases. According to this theory, the kinetic energy of a gas molecule is directly proportional to its temperature. The root-mean-square velocity of the gas molecules is given by \( v = \sqrt{\frac{3kT}{m}} \), where \( k \) is the Boltzmann constant, \( T \) is the temperature, and \( m \) is the mass of the gas molecules.

This equation shows that the average vertical component of the velocity of the gas molecules is determined by the temperature and the mass of the molecules. As the temperature increases, the velocity of the gas molecules also increases.

Similarly, if the mass of the gas molecules is larger, the velocity will be smaller for the same temperature. The equation provides a quantitative relationship between these variables, allowing us to calculate the average vertical velocity of gas molecules in a given system.

Learn more about velocity here: brainly.com/question/30559316

#SPJ11

The pressure at the bottom of the container is given to be 120 kPa. The atmospheric pressure is given to be 1.013 x 10⁵ Pa.

The main answer to this problem can be obtained by calculating the pressure of the fluid at the depth of the fluid from the bottom of the container. The pressure of the fluid at the depth of the fluid from the bottom of the container can be found by using the formula:Pressure of fluid at a depth (P) = Pressure at the bottom (P₀) + ρghHere,ρ = Density of fluid = 900 kg/m³g = acceleration due to gravity = 9.8 m/s²h = Depth of fluid from the bottom of the containerBy using these values, we can find the depth of the fluid from the bottom of the container.

The explaination of the main answer is as follows:Pressure of fluid at a depth (P) = Pressure at the bottom (P₀) + ρghWhere,ρ = Density of fluid = 900 kg/m³g = acceleration due to gravity = 9.8 m/s²h = Depth of fluid from the bottom of the containerGiven,Pressure at the bottom (P₀) = 120 kPa = 120,000 PaAtmospheric pressure (Patm) = 1.013 x 10⁵ PaNow, using the formula of pressure of fluid at a depth, we get:P = P₀ + ρgh120,000 + 900 x 9.8 x h = 120,000 + 8,820h = 12.93 mThe depth of the fluid from the bottom of the container is 12.93 m.

To know more about atmospheric pressure visit:

https://brainly.com/question/31634228

#SPJ11

The heat conducted through the glass is 11,812.5 W.

On either side of a pane of window glass, temperatures are 15°C and -2°C. How fast is heat conducted through such a pane of area 0.25 m2 if the thickness is 2 mm? (Conductivity of glass = 1.05 W/m.K)

The formula for calculating the heat conducted through a material is as follows:

Q = KAT ΔT/Δx Q is the amount of heat, A is the surface area of the material, ΔT is the temperature gradient across the material, Δx is the thickness of the material, and K is the material's conductivity.

ΔT = 15 - (-2) = 17 K Δx = 2 mm = 0.002 mA = 0.25 m²K = 1.05 W/m.K

Therefore,Q = KAT ΔT/Δx = 1.05 × 0.25 × 17/0.002 = 11,812.5 W

Hence the required answer is given as the heat conducted through the glass is 11,812.5 W.

Learn more about heat conducted here https://brainly.com/question/13253422

#SPJ11

To calculate the energy required to boost the space shuttle to the new orbit, we can use the concept of gravitational potential energy. The energy required to boost the space shuttle to the new orbit is approximately -7.405 x 10⁹ Joules.

The change in gravitational potential energy (ΔPE) is given by the equation:

ΔPE = -GMm × (1/ri - 1/rf)

Where:

G = Universal gravitational constant (6.67430 x 10⁻¹¹ m³ kg^-1 s⁻²)

M = Mass of the Earth (5.972 x 10²⁴ kg)

m = Mass of the space shuttle (50,000 kg)

ri = Initial radius of the orbit (250 km + radius of the Earth)

rf = Final radius of the orbit (610 km + radius of the Earth)

Let's calculate the energy required:

ri = 250 km + 6,371 km (radius of the Earth)

ri = 6,621 km = 6,621,000 meters

rf = 610 km + 6,371 km (radius of the Earth)

rf = 6,981 km = 6,981,000 meters

ΔPE = -(6.67430 x 10⁻¹¹) × (5.972 x 10²⁴) × (50,000) × (1/6,621,000 - 1/6,981,000)

Calculating ΔPE:

ΔPE ≈ -7.405 x 10⁹ Joules

Therefore, the energy required to boost the space shuttle to the new orbit is approximately -7.405 x 10⁹ Joules. Note that the negative sign indicates that energy is required to move to a higher orbit.

To learn more about gravitational potential energy, visit:

https://brainly.com/question/3910603

#SPJ11

The coefficient of friction between the crate and the surface is 0.17.

Since the crate is moving with a constant speed, the net force acting on it must be zero.

In other words, the force of friction must be equal and opposite to the tension force applied.

The force of friction can be calculated using the following formula:

frictional force = coefficient of friction * normal force

where the normal force is the force perpendicular to the surface and is equal to the weight of the crate, which is given as 120 N.

In the vertical direction, the tension force is balanced by the weight of the crate, so there is no net force.

In the horizontal direction, the tension force is resolved into two components:

21 N * cos(20°) = 19.8 N acting parallel to the surface and

21 N * sin(20°) = 7.2 N acting perpendicular to the surface.

The frictional force must be equal and opposite to the parallel component of the tension force, so we have:

frictional force = 19.8 N

The coefficient of friction can now be calculated

:coefficient of friction = frictional force / normal force

                                   = 19.8 N / 120 N

                                   = 0.165 or 0.17 (rounded to two significant figures)

Therefore, the coefficient of friction between the crate and the surface is 0.17.

Learn more about the coefficient of friction:

brainly.com/question/13923375

#SPJ11

An individual white LED (light-emitting diode) with an efficiency of 20% and using 1.0 W of electric power converts only 20% of the electrical energy it receives into light, while the remaining 80% is wasted as heat.

This means that the LED produces 0.2 W of light. Efficiency is calculated by dividing the useful output energy by the total input energy, and in this case, it is 20%. Therefore, for every 1 W of electric power consumed, only 0.2 W is converted into light.

The efficiency of an LED is an important factor to consider when choosing lighting options. LEDs are known for their energy efficiency compared to traditional incandescent bulbs, which waste a significant amount of energy as heat. LEDs convert a higher percentage of electricity into light, resulting in less energy waste and lower electricity bills.

To know more about  electrical energy visit:-

https://brainly.com/question/16182853

#SPJ11

The impulse that the wall gave the ball is -0.3 Ns.

The impulse that the wall gave the ball when a ball of mass 0.5Kg is moving to the right at 1m/s, collides with a wall and rebounds to the left with a speed of 0.8m/s is -0.3 Ns.

Impulse is equal to the change in momentum and is given by the formula,

Impulse = Δp = m (vf - vi)

Where, Δp = change in momentum, m = mass of the object, vf = final velocity, vi = initial velocity

Now, initial momentum = m vi

Final momentum = m vf

We can find the change in momentum by the formula,

Δp = m (vf - vi)

Therefore, Initial momentum = m vi = (0.5 kg)(1 m/s) = 0.5 kg m/s

Final momentum = m vf = (0.5 kg)(-0.8 m/s) = -0.4 kg m/s

Impulse = Δp = (final momentum) - (initial momentum) = -0.4 kg m/s - 0.5 kg m/s= -0.9 kg m/s≈ -0.3 Ns

Thus, the impulse that the wall gave the ball is -0.3 Ns.

Learn more about impulse visit:

brainly.com/question/30466819

#SPJ11

When the voltage across the resistor is constant, increasing the resistance decreases the power delivered to the resistor.

To calculate the power delivered to the resistor R= 2.3 2 in the figure, use the following equation:

P = V^2 / RP

= (20 V)^2 / 1 ΩP

= 400 W

Thus, the power delivered to the resistor R= 2.3 2 in the figure is 400 W. The power is defined as the rate of energy consumption per unit of time, and it is denoted by P. When a potential difference (V) is applied across a resistance (R), electric current (I) flows, and the rate at which work is done in the circuit is referred to as power.

Power is also the product of voltage (V) and current (I), which can be expressed as P = VI. In electrical engineering, power is defined as the rate of energy transfer per unit time. Power is a scalar quantity and is represented by the letter P. The watt (W) is the unit of power in the International System of Units (SI), which is equivalent to one joule of energy per second.

A circuit's power dissipation can be calculated using Ohm's law, which states that P = IV.

Where P is the power in watts, I is the current in amperes, and V is the voltage in volts. The power dissipated by a resistor is proportional to the square of the current flowing through it, according to Joule's law. It's also proportional to the square of the voltage across the resistor.

P = I^2R = V^2/R,

where P is the power, I is the current, V is the voltage, and R is the resistance. When the voltage applied across the resistance is constant, the current through the resistance is inversely proportional to its resistance.

The potential difference across the resistor and the current passing through it can be used to calculate the power delivered to the resistor. Power is proportional to the voltage squared and inversely proportional to the resistance.

To know more about voltage visit:

https://brainly.com/question/32002804

#SPJ11

The correct answers are (a) 7.53 m/s, (b) 8.19 m/s, and (c) 5.00 m/s. The average speed is calculated as follows: v_avg = sum_i v_i / N

where v_avg is the average speed

v_i is the speed of particle i

N is the number of particles

Plugging in the given values, we get

v_avg = (4.00 m/s + 2 * 5.00 m/s + 3 * 7.00 m/s + 4 * 5.00 m/s + 3 * 10.0 m/s + 2 * 14.0 m/s) / 15

= 7.53 m/s

The rms speed is calculated as follows:

v_rms = sqrt(sum_i (v_i)^2 / N)

Plugging in the given values, we get

v_rms = sqrt((4.00 m/s)^2 + 2 * (5.00 m/s)^2 + 3 * (7.00 m/s)^2 + 4 * (5.00 m/s)^2 + 3 * (10.0 m/s)^2 + 2 * (14.0 m/s)^2) / 15

= 8.19 m/s

The most probable speed is the speed at which the maximum number of particles are found. In this case, the most probable speed is 5.00 m/s.

Learn more about rms speed here:

brainly.com/question/33262591

#SPJ11

a: each pulse has approximately 3.394 × 10^(-19) Joules of energy.

b:  the power output of the laser is approximately 7.543 × 10^(-16) Watts.

c: there is approximately 1 photon in each pulse.

Given:

Wavelength of the laser (λ) = 585 nm = 585 × 10^(-9) m

Pulse duration (t) = 450 μs = 450 × 10^(-6) s

Blood vaporized per pulse = 2.0 μg = 2.0 × 10^(-9) kg

(a) Calculating the energy in each pulse:

We need to convert the wavelength to frequency using the equation:

c = λν

where

c = speed of light = 3 × 10^8 m/s

Thus, the frequency is given by:

ν = c / λ

ν = (3 × 10^8 m/s) / (585 × 10^(-9) m)

ν ≈ 5.128 × 10^14 Hz

Now, we can calculate the energy using the equation:

Energy (E) = Planck's constant (h) × Frequency (ν)

where

h = 6.626 × 10^(-34) J·s (Planck's constant)

E = (6.626 × 10^(-34) J·s) × (5.128 × 10^14 Hz)

E ≈ 3.394 × 10^(-19) J

Therefore, each pulse has approximately 3.394 × 10^(-19) Joules of energy.

(b) Calculating the power output of the laser:

We can calculate the power using the equation:

Power (P) = Energy (E) / Time (t)

P = (3.394 × 10^(-19) J) / (450 × 10^(-6) s)

P ≈ 7.543 × 10^(-16) W

Therefore, the power output of the laser is approximately 7.543 × 10^(-16) Watts.

(c) Calculating the number of photons in each pulse:

We can calculate the number of photons using the equation:

Number of photons = Energy (E) / Energy per photon

The energy per photon is given by:

Energy per photon = Planck's constant (h) × Frequency (ν)

Energy per photon = (6.626 × 10^(-34) J·s) × (5.128 × 10^14 Hz)

Energy per photon ≈ 3.394 × 10^(-19) J

Therefore, the number of photons in each pulse is given by:

Number of photons = (3.394 × 10^(-19) J) / (3.394 × 10^(-19) J)

Number of photons ≈ 1

Hence, there is approximately 1 photon in each pulse.

Learn more about Frequency here:

https://brainly.com/question/29739263

#SPJ11

When a bar is pulled to the right in the circuit shown below with a constant magnetic field going into the screen, the induced current through the resistor will oscillate back and forth.

An induced emf is generated in the conductor by a magnetic field that changes in time. Faraday's law of induction is the principle that governs this behaviour. The induced current through the resistor will therefore oscillate back and forth when the magnetic flux that penetrates a closed circuit changes with time (i.e., the flux linking the coil in the circuit shown below changes as the bar moves).

This back and forth oscillation is due to the fact that as the bar moves to the right and out of the magnetic field, the current flows upwards. However, as the bar moves to the left and into the magnetic field, the current flows downwards. This results in the induced current oscillating back and forth through the resistor.

To know more about conductor visit:

https://brainly.com/question/14405035

#SPJ11

The magnitude of the electric field in the region, for a particle of charge +0.640 nC, is 4.566 x[tex]10^6[/tex] V/m. The direction of the electric field in this case is negative.

Step 1: The magnitude of the electric field can be calculated using the formula F = q * E, where F is the force experienced by the particle, q is the charge of the particle, and E is the magnitude of the electric field.

Step 2: Given that the particle is passing through the region undeflected, we know that the electric force on the particle must be equal and opposite to the magnetic force experienced due to the magnetic field. Therefore, we have q * E = q * v * B, where v is the velocity of the particle and B is the magnitude of the magnetic field.

Step 3: Rearranging the equation, we can solve for E: E = v * B. Substituting the given values, we have E = (5.85 x [tex]10^9[/tex] m/s) * (-1.35 T).

Learn more about magnitude

brainly.com/question/31022175

#SPJ11