Answer:
B. The candidate received at least 250 votes in half of the 6 towns.
This is because the median number of votes is the middle value when all the vote counts are put in order. This means that at least three towns gave the candidate more than 250 votes, and at least three towns gave the candidate fewer than 250 votes. So, the candidate received at least 250 votes in half of the 6 towns. The total number of votes the candidate received in the election cannot be determined from this information. Similarly, the number of votes received in individual towns cannot be determined.
A sale transaction on rental property closes on December 10th. The landlord received the December rent of $4,400 on December 1. Assuming the closing day is the seller's, and that the 360-day method is used for prorating, how much will the seller owe the buyer?
The seller will owe the buyer an amount of $2,933.40.
How much will the seller owe the buyer?To be able to compute the owed amount, first, we have to compute the daily rate per day which is shown below:
= Rent received / number of days in a month
= $4,400 / 30 days
= 146.67 per day
Data:
Number of days in a month = 30 days
Landlord received a rent on December 10
The remaining days would be = 30 days - 10 days = 20 days
Now, the owed amount would be calculated as:
= Remaining days × per day rate
= 20 days × 146.67
= $2,933.40
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I don’t understand how to solve and find the system here. Please help, I need it to be done in three hours.
The system of equations in the context of this problem is given as follows:
5h + 3c = 340.2h + 6c = 400.The solution is given as follows:
h = 35, c = 55.
How to model the system of equations?The variables used for the system of equations are given as follows:
Variable h: Amount earned with a haircut.Variable c: Amount earned with a color treatment.Considering the Monday's earnings, the equation is given as follows:
5h + 3c = 340.
Considering the Wednesday's earnings, the equation is given as follows:
2h + 6c = 400.
Hence the system is:
5h + 3c = 340.2h + 6c = 400.Simplifying the second equation by 2, we have that:
h + 3c = 200.
Subtracting the first equation by the second, we can obtain the value of h as follows:
4h = 140
h = 140/4
h = 35.
Hence the value of c is given as follows:
c = (200 - 35)/3
c = 55.
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Determine which function is represented by the graph. Do not use a calculator. (a) f ( x ) = 4 cos ( x + π ) (b) f ( x ) = 4 cos 4 x (c) f ( x ) = 4 sin ( x − π ) (d) f ( x ) = − 4 cos ( x + π ) (e) f ( x ) = 1 − sin x 2
Answer:
The graph of the function appears to be a cosine function that has been shifted to the left by π/2 units, and has an amplitude of 4.
Option (a) is a cosine function that has been shifted to the left by π units, but does not have the amplitude of 4.
Option (b) is a cosine function that has a period of π/2, which is much shorter than the period of the graph.
Option (c) is a sine function that has been shifted to the right by π units, but does not have the amplitude of 4.
Option (d) is a cosine function that has been shifted to the left by π units and has the correct amplitude of 4.
Option (e) is not a cosine or sine function, so it cannot be the correct answer.
Therefore, the function represented by the graph is:
f(x) = -4 cos(x + π)
which is Option (d).
Step-by-step explanation:
Which of the following is not a characteristic of both experiments and
surveys?
O A. Data are collected about a population.
B. Subjects should be randomly selected.
OC. The data collected might be studied for patterns.
OD. The researcher exercises direct control over at least one variable.
SUBMIT
"Data are collected about a population," is not a characteristic of both experiments and surveys. Option A
What is the difference between survey and experiment?A survey is a technique for gathering data about a study variable from the respondents of the population. An experiment is a technique used in science to isolate the problem being examined and test a theory.
Options B, C, and D are characteristics obtained in the case of the experiments and surveys. In both types of research, subjects may be randomly selected (option B), the data collected may be studied for patterns (option C).
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Solve the following system of equations. If there is no solution, write DNE in each coordinate of the ordered triplet. If there are an infinite number of solution, write each coordinate in terms of z
x+3=y+12
z+13=x+8
y-7=z-11
PLS
Use the numbers in the multiplication equation 28 times 1/7 = 4 to write a division equation involving divison by a fraction
Changing the multiplication sign to a division sign, we will have 28 ÷ 7
Multiplication and division rule :-
Given the product of 28 and 1/7, we are to write a division equation involving division by a fraction.
Given,
28 * 1/7 = 4
Changing the multiplication sign to a division sign, we will have:
28 * 1/7 = 28/7
This can also be written as 28 ÷ 7
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Highschool geometry please answer questions 8-10 in the attachment added
On a coordinate plane, a parabola opens down. It has an x-intercept at (negative 5, 0), a vertex at (negative 1, 16), a y-intercept at (0, 15), and an x-intercept at (3, 0).
The function f(x) = –x2 − 2x + 15 is shown on the graph. What are the domain and range of the function?
The domain is all real numbers. The range is {y|y < 16}.
The domain is all real numbers. The range is {y|y ≤ 16}.
The domain is {x|–5 < x < 3}. The range is {y|y < 16}.
The domain is {x|–5 ≤ x ≤ 3}. The range is {y|y ≤ 16}
The domain is all real numbers.
The range is {y|y ≤ 16}.
Option B is the correct answer.
We have,
The given parabola opens downwards and has a vertex at (-1,16).
So,
The parabola has a maximum value at y = 16.
Also, the y-intercept of the parabola is (0,15), which is below the vertex, and the parabola intersects the x-axis at (-5,0) and (3,0).
We can use the factored form of the equation of a parabola to find its equation in this case.
The factored form is:
y = a(x - h)² + k
where (h,k) is the vertex and "a" determines whether the parabola opens upwards or downwards.
Since the parabola opens downwards, "a" is negative.
Also, we know that the vertex is (-1,16), so we have:
y = a(x + 1)² + 16
To find "a", we can use one of the x-intercepts, say (-5,0).
Substituting these values into the equation gives:
0 = a(-5 + 1)² + 16
0 = 16a
a = 0
This indicates that the parabola is actually a line passing through (0,15) and (3,0). Therefore, the equation of the parabola is:
y = -x² - 2x + 15
The domain of this function is all real numbers because there are no restrictions on the values of x that can be plugged into the equation.
However, the range of the function is limited by the maximum value of y, which is 16.
Since the parabola opens downwards, all y values less than or equal to 16 are attainable.
Therefore, the domain is all real numbers, and the range is {y | y ≤ 16}.
Therefore,
The domain is all real numbers.
The range is {y|y ≤ 16}.
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From a group of 10 people, you randomly select 2 of them. What is the probability that they are the 2 oldest people in the group?
The probability that they are the 2 oldest people in the group is 0.011
Understanding probabilityProbability is a measure of the likelihood or chance of an event occurring. It is expressed as a number between 0 and 1, where 0 indicates that the event is impossible, and 1 indicates that the event is certain.
The probability of an event A is denoted by P(A)
From the question above, let us calculate the probability.
The probability that the first person selected is the oldest is 1/10.
Then, the probability that the second person selected is the second oldest is 1/9, since there are only 9 people left to choose from.
Therefore, the probability of selecting the two oldest people in the group is:
1/10 * 1/9 = 1/90
So, the probability of selecting the two oldest people in the group is 1/90 or approximately 0.011 or 1.1%.
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Question 1 نت You are interested in constructing a 99% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 369 randomly selected caterpillars observed, 45 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 99% confidence the proportion of all caterpillars that lived to become a butterfly is between and b. If many groups of 369 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion. Hint: Hints Video [+]
a) The 99% confidence interval for the proportion of all caterpillars that lived to become a butterfly is between 0.078 and 0.166.
b) About 99% of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
What is a confidence interval of proportions?A confidence interval of proportions has the bounds given by the rule presented as follows:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which the variables used to calculated these bounds are listed as follows:
[tex]\pi[/tex] is the sample proportion, which is also the estimate of the parameter.z is the critical value.n is the sample size.The confidence level is of 99%, hence the critical value z is the value of Z that has a p-value of [tex]\frac{1+0.99}{2} = 0.995[/tex], so the critical value is z = 2.575.
The sample size and the estimate for this problem are given as follows:
[tex]n = 369, \pi = \frac{45}{369} = 0.122[/tex]
The lower bound of the interval is given as follows:
0.122 - 2.575 x sqrt(0.122 x 0.878/369) = 0.078.
The upper bound of the interval is given as follows:
0.122 + 2.575 x sqrt(0.122 x 0.878/369) = 0.166.
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What is the solution to this system?
(1, 0)
(1, 6)
(8, 26)
(8, –22)
x = –2
Answer:
Step-by-step explanation:The system of equations represented by the given points is:1x + 0y = 1 (equation 1)
1x + 6y = 1 (equation 2)
8x + 26y = 1 (equation 3)
8x - 22y = 1 (equation 4)
We can use the first equation to solve for x in terms of y:1x + 0y = 1
1x = 1
x = 1
Then we can substitute x=1 into equations 2-4 to obtain three equations in terms of y:1(1) + 6y = 1 => 6y = 0 => y = 0
8(1) + 26y = 1 => 26y = -7/8 => y = -7/208
8(1) - 22y = 1 => -22y = -7/8 - 7 => y = 15/44
Therefore, the solution to the system is x = 1 and y = -7/208 or y = 0 or y = 15/44.
However, we are given that x = -2, which contradicts our solution of x = 1. Therefore, there is no solution to the system with the given values.
a principle has given a class 75 dollars to help pay for a field trip to the zoo
Answer:
5p + 75> 386
Step-by-step explanation:
principal has given $75
Total cost of trip = $386
price of a pie = $5
5p + 75 ≥ 386
rancher wants to enclose a rectangular plot of land, but have a divider in the middle. There is 240 feet of fencing available. What dimension will produce the largest area the rancher can make? What is the max area? Dimensions: __________________ Area:___________ --------------------------------------------------------------------------------------------------------- 2. (10 points) From a thin square piece of cardboard 20 in. per side, square corners (x) are cut out so that the sides can be folded up to make a box. What dimensions will yield a box of maximum volume? What is the maximum volume? Dimensions: __________________ Volume:___________ ----------------------------------------------------------------------------------------------------------- 3. (10 points) During a recent oil spill in the gulf, the radius of the spill was increasing at a rate of 10 feet per second. How fast is the circular area of the spill increasing at the moment that the radius is 80 feet? dA = dt __________
The solution is, the two dimensions will be 2121.32 by 1414.2.
Here, we have,
let X and Y be the two dimensions.
Area will be X times Y.
XY = 3000000
Y = 3000000 / X
Perimeter = 2x + 3y
substituting the values:
Perimeter = 2x + 3*3000000 / x
= 2x + 9000000 / x
so, we get,
2 = 9000000 / x^2
x^2 = 9000000 / 2 = 4500000
x = sqrt(4,500,000)
= 2121.32
= 1000 sqrt (4.5)
y = 3000000 / 2121.32
= 1414.2
= 1000 sqrt(2)
so the dimensions will be 2121.32 by 1414.2 .
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complete question:
A rancher wants to fence in an area of 3000000 square feet in a rectangular field and then divide it in half with a fence down the middle parallel to one side. What is the shortest length of fence that the rancher can use?
Please help me i need the answer and im so confused just tell me if its a b c or d please
Answer:
The answer would be option A
Step-by-step explanation:
-14 times 8=-122
Use the graph of g(x) to answer the following question. The graph of g(x) is a translation of f(x)=x^2 Write the equation for g(x) in vertex form.
The equation for g(x) in vertex form is g(x) = (x - 2)^ + 3
Writing the equation for g(x) in vertex form.From the question, we have the following parameters that can be used in our computation:
The graph of g(x)
Also, we have
The graph of g(x) is a translation of f(x)=x^2
From the graph, we can see that
Using the above as a guide, we have the following:
g(x) = f(x - 2) + 3
Substitute the known values in the above equation, so, we have the following representation
g(x) = (x - 2)^ + 3
Hence, the equation for g(x) in vertex form is g(x) = (x - 2)^ + 3
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geometry pls help fast 13 and 14
Answer:
13: (2,3) 14: A. Yes, 90, 180, 270 B. No C. No
Step-by-step explanation:
13. Right: -2+4, Down: 5-2
14. If it can be rotated and be similar, it has rotational.
The vertices of a quadrilateral are listed below.
The strongest classification of the quadrilateral with the given vertices is rhombus.
The vertices of the quadrilateral is given as,
E(5, 4), F(9, 2), G(5, 0) and H(1, 2).
Find the adjacent sides EF and FG whether they are equal.
Using the distance formula,
EF = √(9 - 5)² + (2 - 4)² = √(16 + 4) = √20
FG = √(5 - 9)² + (0 - 2)² = √(16 + 4) = √20
Adjacent sides are equal.
So they are either square or rhombus.
Find the lengths of the diagonals whether they are equal.
EG = √(5 - 5)² + (0 - 4)² = √(0 + 16) = 4
FH = √(1 - 9)² + (2 - 2)² = √(64 + 0) = 8
Diagonals are not equal.
So it is a rhombus.
Hence the quadrilateral is a rhombus.
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Here is question 5 of 6. Thank you for the help
The critical value for a two-tailed test at the 0.05 significance level is 1.96.
The null hypothesis is that there is no difference in the proportion of men and women intending to vote for Donald Trump, and the alternative hypothesis is that there is a difference.
The test statistic is given by:
z = (p1 - p2) /√[(p×(1-p)×(1/n1 + 1/n2),
where p = (x1 + x2) / (n1 + n2) and x1 and x2 are the number of successes in samples 1 and 2 respectively, and n1 and n2 are the sample sizes of samples 1 and 2 respectively.
In this case, x1 = 120, x2 = 132, n1 = 250, and n2 = 240.
Plugging these values into the equation gives us z = 0.906.
Since the test statistic does not exceed the critical value, we fail to reject the null hypothesis. That is, there is not convincing evidence that there is a difference in the proportion of all men and the proportion of all women in this city who intended to vote for Trump at the 0.05 significance level.
Therefore, the critical value for a two-tailed test at the 0.05 significance level is 1.96.
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a robotic vacum cleanervacumsonehotelroomin 3/10 hour. at this rate, how many rooms of the same size will it vaccum in 3 hours
The number of rooms of the same size it willl vaccum in 3 hours is 10
How many rooms of the same size will it vaccum in 3 hoursFrom the question, we have the following parameters that can be used in our computation:
Unit rate = 3/10 hour per room
Time = 3 hours
using the above as a guide, we have the following:
Number of rooms = Time/Unit rate
Substitute the known values in the above equation, so, we have the following representation
Number of rooms = 3/(3/10)
Evaluate the quotient
Number of rooms = 10
Hence, the number of rooms is 10
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find the distance between the two points in simplest radical form (9,2) (4,-7)
Answer:
√50
Step-by-step explanation:
To solve, use distance formula.
√(9-4)^2 + (2-(-7))^2=
√5^2+5^2=
√50
The entries in Table I are the probabilities that a random variable having the standard normal distribution will take on a value between 0 andz. They are given by the area of the gray region under the curve in the figure. TABLET NORMAL-CURVE AREAS 2 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.0 0.1 0.2 0.3 0.4 0.5 0.0000 0.0398 0.0793 0.1179 0.1554 0.1915 0.0080 0.0478 0.0871 0.1255 0.1628 0.1985 0.0120 0.0517 0.0910 0.1293 0.1664 0.2019 0.2357 0.2673 0.2967 0.3238 0.3485 0.0160 0.0557 0.0948 0.1331 0.1700 0.2054 0.2389 0.2704 0.2995 0.3264 0.3508 0.0199 0.0596 0.0987 0.1368 0.1736 0.2088 0.0239 0.0636 0.1026 0.1406 0.1772 0.2123 0.0279 0.0675 0.1064 0.1443 0.1808 0.2157 0.0319 0.0714 0.1103 0.1480 0.1844 0.2190 0.0359 0.0753 0.1141 0.1517 0.1879 0.2224 0.2549 0.2852 0.3133 0.3389 0.3621 0.2257 0.0040 0.0438 0.0832 0.1217 0.1591 0.1950 0.2291 0.2611 0.2910 0.3186 0.3438 0.3665 0.3869 0.4049 0.4207 0.4345 0.4463 0.4564 0.4648 0.4719 0.4778 0.6 0.7 0.8 0.9 1.0 0.2580 0.2881 0.3159 0.3413 0.2324 0.2642 0.2939 0.3212 0.3461 0.2422 0.2734 0.3023 0.3289 0.3531 0.2454 0.2764 0.3051 0.3315 0.3554 0.2517 0.2823 0.3106 0.3365 0.3599 0.2486 0.2794 0.3078 0.3340 0.3577 0.3790 0.3980 0.4147 0.4292 0.4418 1.1 1.2 1.3 1.4 1.5 0.3749 0.3944 0.4113 0.4265 0.4394 0.3770 0.3962 0.4131 0.4279 0.4406 0.3810 0.3997 0.4162 0.4306 0.4429 0.3643 0.3849 0.4032 0.4192 0.4332 0.4452 0.4554 0.4641 0.4713 0.4772 0.3686 0.3888 0.4066 0.4222 0.4357 0.4474 0.4573 0.4656 0.4725 0.4783 0.3708 0.3907 0.4082 0.4236 0.4370 0.4484 0.4582 0.4664 0.4732 0.4788 0.3729 0.3925 0.4099 0.4251 0.4382 0.4495 0.4591 0.4671 0.4738 0.4793 0.3830 0.4015 0.4177 0.4319 0.4441 0.4545 0.4633 0.4706 0.4767 0.4817 1.6 1.7 1.8 1.9 2.0 0.450S 0.4599 0.4678 0.4744 0.4798 0.4515 0.4608 0.4685 0.4750 0.4803 0.4525 0.4616 0.4692 0.4756 0.4808 0.4535 0.4625 0.4699 0.4761 0.4812 2.1 2.2 2.3 2.4 2.5 0.4826 0.4864 0.4896 0.4920 0.4940 0.4830 0.4868 0.4898 0.4922 0.4941 0.4834 0.4871 0.4901 0.4925 0.4943 0.4850 0.4884 0.4911 0.4932 0.4949 0.4854 0.4887 0.4913 0.4934 0.4951 0.4857 0.4890 0.4916 0.4936 0.4952 0.4821 0.4861 0.4893 0.4918 0.4938 0.4953 0.4965 0.4974 0.4981 0.4987 0.4838 0.4875 0.4904 0.4927 0.4945 0.4959 0.4969 0.4977 0.4984 0.4988 0.4842 0.4846 0.4878 0.4881 0.4906 0.4909 0.4929 0.4931 0.4946 0.4948 0.4960 0.4961 0.4970 0.4971 0.4978 0.4979 0.4984 0.4985 0.4989 0.4989 2.6 2.7 2.8 2.9 3.0 0.4955 0.4966 0.4975 0.4982 0.4987 0.4956 0.4967 0.4976 0.4982 0.4987 0.4957 0.4968 0.4977 0.4983 0.4988 0.4962 0.4972 0.4979 0.4985 0.4989 0.4963 0.4973 0.4980 0.4986 0.4990 0.4964 0.4974 0.4981 0.4986 0.4990 Also, for 3 - 4.0, 5.0 and 6.0, the areas are 0.49997, 0.4999997, and 0.499999999. ^ The entries in Table II are values for which the area to their right under the 1 distribution with given degrees of freedom (the gray area in the figure) is equal toa. TABLE II VALUE OF d.f. Fo.050 os 0.005 d.. 63.657 9.925 1 2 3 4 6.314 2.920 2.353 2.132 2.015 12.706 4.303 3.182 2.776 2.571 0.010 31.821 6.965 4.541 3.747 3.365 1 2 3 4 5.841 4.604 4.032 S S 6 7 6 7 8 1.943 1.895 1.860 1.833 1.812 2.447 2.365 2.306 2.262 2.228 3.143 2.998 2.896 2.821 2.764 3.707 3.499 3.355 3.250 3.169 8 9 9 10 10 11 12 1.796 1.782 1.771 1.761 1.753 13 14 15 2.201 2.179 2.160 2.145 2.131 2.718 2.681 2.650 2.624 2.602 3.106 3.055 3.012 2.977 2.947 11 12 13 15 16 16 17 18 19 20 1.746 1.740 1.734 1.729 1.725 2.120 2.110 2.101 2.093 2.086 2.583 2.567 2.552 2.921 2.898 2.878 2.861 2.845 17 18 19 2.539 2.528 20 21 22 23 24 25 1.721 1.717 1.714 1.711 1.708 2.080 2.074 2.069 2.064 2.060 2.518 2.508 2.500 2.831 2.819 2.807 2.797 2.787 21 22 23 24 25 2.492 2.485 2.056 2.052 26 27 28 29 Inf. 1.706 1.703 1.701 1.699 1.645 2.479 2.473 2.467 2.462 2.326 2.779 2.771 2.763 2.048 26 27 28 29 Inf. 2.045 2.756 2.576 1.960 Question 2 (20 marks) A tutorial school has been running IELTS mock examination for many years. Below is the summary presented by the tutorial school related to the IELTS mock examination in one of the many online classes selected randomly in year 2022. IELTS score in mock examination Number of students <4 0 5 2 6 7 5 15 8 10 3 9 A report presented by this tutorial school 5 years ago indi that the population mean score of IELTS mock examination was 7.05 points and the population proportion of students got 7 points or above was 0.67. (a) Construct a 95% confidence interval estimate of population mean score a student get in the IELTS mock examination in 2022. (b) Test, at 1% level of significance, if the population proportion of students get 7 points or above in 2022 is higher than that in year 2017. (The report must include the (i) null hypothesis and alternative hypothesis, (ii) rejection region(s), (iii) calculation of test statistics, and (iv) conclusion.) (c) If the confidence interval estimate in part (a) is constructed at 99% instead of 95%, would the interval be (1) wider, (II) narrower, or (III) no change in width? (State your answer, no explanation is needed in part (C).)
Find f (x) if f'(x) = 3x² + 8x + 2 and f(1) = 2.
PLEASE HELP WHAT IS 7 x 4
Answer:
THE ANSWER OF 7×4=28 !!!!!!!
Find the area and perimeter of the figure. (Hint: Don't forget your units!)
8cm
1
1
5cm
6cm
Answer:
Area of parallelogram:
8 × 5 = 40 square centimeters
Perimeter of parallelogram:
2(8 + 6) = 2 × 14 = 28 centimeters
A store sells graph paper in packages of 100 sheets. During a sale, they offer a package that has 25% more sheets for no additional cost.How many sheets are in sale package
There are 125 sheets in the sale package.
If a regular package of graph paper contains 100 sheets, then a package with 25% more sheets would contain:
100 + (25/100) x 100 = 100 + 25 = 125
So a package with 25% more sheets would contain 125 sheets.
During the sale, the store is offering a package with 25% more sheets for no additional cost.
This means that the sale package contains the same number of sheets as a regular package, plus an additional 25% of that same number of sheets.
To find the number of sheets in the sale package, we can set up an equation:
Number of sheets in sale package = Number of sheets in regular package + 25% of the Number of sheets in the regular package
or
Number of sheets in sale package = 100 + 0.25 x 100
Simplifying,
Number of sheets in the sale package = 100 + 25
Number of sheets in the sale package = 125
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NEED ANSWER ASAP PLEASE
Answer:
second one
the y intercept is 8, the slope is -6/8, reduced -3/4
Step-by-step explanation:
equation if a line in slope intercept form is y=mx+
Select all of the values of x that make the inequality -x+6 ≥ 10 true.
explicit formula for an, the nth term of the sequence 6, 0, -6, ....
Answer:
12 - 6n
Step-by-step explanation:
As this sequence decreases, rather than increases, this tell us that the nth term of this sequence will be minus. The difference from 6 and 0 is 6, telling us that the decrease is by 6 each time. So now we know the nth term of this sequence; -6n, but the sequence of -6n is -6,-12,-18 and so on. We need 6,0,-6. To find out the second part of the nth term find the difference from the sequence given and the sequence of -6n. The difference is 12 because the 6--6 = 12. So now we get the nth term of the sequence -6n + 12 which is written as 12-6n.
The table shows the results of rolling a die several times. Outcome 1 2 3 4 5 6 Number of times outcome occurred 7 4 4 5 6 4 To the nearest percent, what is the experimental probability of rolling a 6? Question 1 options: 17% 20% 13% 67%
The experimental probability of the rolling a 6 is 13%.
How to find the experimental probability of rolling a 6?Probability is the likelihood of a desired event happening. Experimental probability is a probability that relies mainly on a series of experiments.
From the table:
The total number of times all the numbers appear is:
total number of times = 7 + 4 + 4 + 5 + 6 + 4 = 30
The number six (6) occurred 4 times.
Experimental probability = (occurrence of 6 / total number of times)
Experimental probability = 4/30 * 100
Experimental probability = 13%
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Solve the following for θ, in radians, where 0≤θ<2π.
−sin2(θ)−4sin(θ)+4=0
Select all that apply:
1.1
2.52
0.98
0.69
1.43
2.17
Answer:0.98
2.17 are correct
Step-by-step explanation:
-u^2 - 4u + 4 = 0
Multiplying both sides by -1, we get:
u^2 + 4u - 4 = 0
Now we can use the quadratic formula to solve for u:
u = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 1, b = 4, and c = -4. Substituting these values, we get:
u = (-4 ± sqrt(4^2 - 4(1)(-4))) / 2(1)
u = (-4 ± sqrt(32)) / 2
u = (-4 ± 4sqrt(2)) / 2
u = -2 ± 2sqrt(2)
Therefore, either:
