In ΔUVW, w = 1. 4 cm, m m∠W=63° and m m∠U=29°. Find the length of v, to the nearet 10th of a centimeter

If the survey had a 4% margin of error, 602 people were surveyed for a recent survey of randomly selected smokers indicating that 34% had tried to quit.

To solve this problem, we can use the margin of error formula:

Margin of error = z × √(p × (1-p) / n)

where z is the z-score corresponding to the desired level of confidence (let's assume 95% confidence, so z = 1.96), p is the proportion of smokers who tried to quit (p = 0.34), and n is the sample size.

We can rearrange the formula to solve for n:

n = (z / margin of error)² × p × (1-p)

Plugging in the values, we get:

n = (1.96 / 0.04)² × 0.34 × (1 - 0.34) = 601.96

Rounding up to the nearest whole number, the sample size is 602. Therefore, the survey included 602 adult smokers.

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Answer:

First, we need to convert all the measurements to the same unit. Let's convert everything to inches, since the formula for the volume of a cylinder uses inches:

12 in = 12 in

14 in = 14 in

12 in = 12 in

4 in = 4 in

The object consists of a cylinder with a radius of 4 inches and a height of 12 inches, and a hemisphere with a radius of 4 inches. To find the volume of the object, we need to find the volume of the cylinder and the hemisphere, and then add them together.

Volume of the cylinder:

V_cyl = πr^2h

V_cyl = π(4 in)^2(12 in)

V_cyl = 192π in^3

Volume of the hemisphere:

The volume of a hemisphere is given by:

V_hemi = (2/3)πr^3

Since the radius is 4 inches, we have:

V_hemi = (2/3)π(4 in)^3

V_hemi = (2/3)π(64 in^3)

V_hemi = 128π/3 in^3

Total volume:

V_total = V_cyl + V_hemi

V_total = 192π in^3 + 128π/3 in^3

V_total = (576π + 128π)/3 in^3

V_total = 704π/3 in^3

Now we can substitute the value of π (3) to get the final answer:

V_total = 704π/3 in^3

V_total = 704(3)/3 in^3

V_total = 704 in^3

Therefore, the volume of the object is 704 cubic inches.

The cost of 1 dou of corn is 9 coins and the cost of 1 dou of sesame is 3 coins.

Let x be the cost of 1 dou of corn and y be the cost of 1 dou of sesame.

Using the first set of information, we can create the following equation

4x + 12y = 72

Simplifying this equation by dividing by 4, we get

x + 3y = 18

Using the second set of information, we can create another equation

5x + 10y = 75

Simplifying this equation by dividing by 5, we get

x + 2y = 15

Now we have two equations with two variables

x + 3y = 18

x + 2y = 15

Subtracting the second equation from the first, we get

y = 3 coins

Substituting this value of y back into either of the two equations, we get

x + 3(3) = 18

x + 9 = 18

x = 9 coins

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Answer:

m = 6

Step-by-step explanation:

We have the proportion:

12/m = 18/9

To solve for m, we can cross-multiply the terms in the proportion:

12 × 9 = 18 × m

Simplifying both sides of the equation, we get:

108 = 18m

Dividing both sides by 18, we get:m = 6

Therefore, the solution to the proportion 12/m = 18/9 is m = 6.

Answer: m = 6

Step-by-step explanation:

First, we will rewrite this proportion:

     [tex]\displaystyle \frac{12}{m} =\frac{18}{9}[/tex]

Next, we will cross-multiply:

     12 * 9 = 18 * m

     108 = 18m

Lastly, we will divide both sides of the equation by 18:

     m = 6

We can also solve this proportion another way.

     We know that 18/9 = 2, so 12/m must equal 2 as well.

     12/6 = 2, so m = 6.

The algebraic expression that can be factored by real algebra properties are 4 · x³ + 4 · x² - 3 · x - 3, 25 · x² - 27 and 27 · x³ - 75 · x.

In this expression we need to determine what algebraic expression can be factored by real algebra properties:

Case A:

x⁶ + 343

(x³ + i 3√3) · (x³ - i 3√3)

This expression cannot be reduced by real algebra properties since its roots are complex numbers.

Case B:

4 · x³ + 4 · x² - 3 · x - 3

4 · x² · (x + 1) - 3 · (x + 1)

(4 · x² - 3) · (x + 1)

(2 · x - √3) · (2 · x + √3) · (x + 1)

Case C:

25 · x² - 27

(5 · x - 3√3) · (5 · x + 3√3)

Case D:

27 · x³ - 75 · x

3 · x · (9 · x² - 25)

3 · x · (3 · x + 5) · (3 · x - 5)

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The number of bacteria after 5 hours is approximately 1013.8.

We can use the formula for exponential growth to solve this problem. If a population grows at a rate proportional to its size, then we can writ

N(t) = N₀ × e^(rt),

where N(t) is the size of the population at time t, N₀ is the initial size of the population, r is the growth rate, and e is the mathematical constant approximately equal to 2.71828.

We know that the culture starts with 40 bacteria, so N₀ = 40. We also know that after 2 hours, the size of the population is 180. We can use this information to solve for r:

180 = 40 × e^(2r)

180/40 = e^(2r)

ln(180/40) = 2r

r = ln(180/40)/2

r ≈ 0.6931

Now we can use the formula to find the size of the population after 5 hours:

N(5) = 40 × e^(0.6931×5)

N(5) ≈ 1013.8

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When two coins are repeatedly flipped, the probability of getting two heads is 1/4, the probability of getting a head and a tail is 1/2, and the probability of getting two tails is also 1/4.

Therefore, the expected ratio of two heads : heads/tails : tails/heads : two tails is 1:2:2:1, respectively. This means that out of every six flips, we would expect to see one outcome of two heads, two outcomes of heads/tails and tails/heads each, and one outcome of two tails.

However, it is important to note that this is only a prediction and the actual results may differ due to chance.

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The average value of the function f(x,y) = sin(x+y) over the rectangle 0 ≤ x ≤ π/3, 0 ≤ y ≤ 5π/3 is -27√(3) / (40π^2).

To find the average value of the function ​f(x,y)=sin(x+y) over the given rectangle, we need to integrate the function over the rectangle and then divide by the area of the rectangle.

So, we have:

average value of f(x,y) = (1/Area of rectangle) × double integral of f(x,y) over the rectangle

where the limits of integration are

0 ≤ x ≤ π/3

0 ≤ y ≤ 5π/3

The area of the rectangle is

Area = (π/3 - 0) × (5π/3 - 0) = 5π^2 / 9

Now, we can integrate the function f(x,y) over the rectangle

double integral of f(x,y) over the rectangle = integral from 0 to π/3 of integral from 0 to 5π/3 of sin(x+y) dy dx

= [tex]\int\limits^{\pi /3}_0[/tex] [-cos(x+y)] evaluated from y=0 to y=5π/3 dx

= [tex]\int\limits^{\pi /3}_0[/tex] [-cos(x+5π/3) + cos(x)] dx

= [tex]\int\limits^{\pi /3}_0[/tex]  [-1/2cos(x) - 1/2cos(x+π/3)] dx

= [-1/2sin(x) - 1/4sin(x+π/3)] evaluated from x=0 to x=π/3

= [-1/2sin(π/3) - 1/4sin(2π/3)] - [-1/2sin(0) - 1/4sin(π/3)]

= (-√(3)/4) - (1/4 × √(3)/2) = -3sqrt(3)/8

Therefore, the average value of f(x,y) over the rectangle is

average value of f(x,y) = (1/Area of rectangle) × double integral of f(x,y) over the rectangle

= (-3sqrt(3)/8) / (5π^2 / 9)

= -27sqrt(3) / (40π^2)

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The given question is incomplete, the complete question is:

Find the average value of ​f(x,y)=sin(x+y) over the rectangle 0≤x≤π/3​, 0≤y≤5π/3.

Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.

Inequality refers to the state of being unequal, uneven, or unfair in terms of social, economic, political, or other factors. It can be the result of various factors such as discrimination, prejudice, systemic biases, and unequal distribution of resources, opportunities, and power. Inequality can manifest itself in many forms, including income and wealth disparities, unequal access to education, healthcare, and housing, unequal treatment under the law, and marginalization of certain groups based on their race, gender, sexual orientation, religion, or other characteristics. Addressing inequality is an important challenge in creating a more just and equitable society.

to write an absolute value inequality with a solution set of 5 < x < 7, we need to use the form |x - b| < c, where b is the center of the solution set and c is the distance from the center to the edge of the solution set.

In this case, the center of the solution set is (5 + 7)/2 = 6, and the distance from the center to the edge is (7 - 5)/2 = 1.

Therefore, we can write the absolute value inequality as:

[tex]| x - 6 | < 1[/tex]

Alternatively, we can use the form |x - b| > c and write the absolute value inequality as:

[tex]x < 5 or x > 7[/tex]

Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.

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Answer:

2.50 + 9.50h

Step-by-step explanation:

Sky Launch Trampoline Park charges customers $9.50 per hour they spend jumping. Each customer must also pay $2.50 for grip socks.

Let the number of hours be h.

The equation will be:

= 2.50 + (9.50 × h)

= 2.50 + 9.50h

Answer: 42

Step-by-step explanation: you have to add 9 18 and 15.

The Waffleskate campaign's claim that less than 34% of registered voters wish to see her defeated is not supported by the data, as the 98% confidence interval (0.236 to 0.336) for the proportion of voters who want her to lose does not include 0.34.

To determine if the 98% confidence interval supports the Waffleskate campaign's claim that no more than 34% of registered voters wish to see her defeated, we need to construct the confidence interval and see if 34% falls within the interval.

The sample proportion of registered voters who wished to see Waffleskate lose her next election is 133/464 ≈ 0.286. To construct the 98% confidence interval for the true proportion, we can use the formula p ± Z√(pq/n), where p is the sample proportion, q is the complement of p, n is the sample size, and Z is the standard normal value corresponding to the desired confidence level.

Plugging in the values, we get:

p ± Z√(pq/n) = 0.286 ± 2.33√((0.2860.714)/464) ≈ 0.236 to 0.336

Therefore, the 98% confidence interval for the proportion of registered voters who wish to see Waffleskate lose her next election is 0.236 to 0.336. Since this interval does not include 0.34, the Waffleskate campaign's claim that no more than 34% of registered voters wish to see her defeated is not supported by the 98% confidence interval for the proportion.

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so in the template above for a conic, the defining components are the coefficients A and C

If either A=0 or C=0, then the equation is a parabola

if A=C, then we have a Circle

if either A or C is negative, and A≠C, then we have a hyperbola

if A and C are both positive or both negative, and A≠C, then we have an ellipse.

Part - A: For Sky View School has a mean is 50.8, a median is 50 and a mode is 25.

Riverside School has a mean is 9.93, a median is 20.5 and a mode is 20.

Part B: For Sky View School has a 1,298.16 is variance and For Riverside School has a variance is 477.0

Part C: Riverside School is a better choice because it has a higher maximum class size 57 compared to Sky View School 69.

Given that,

In the stem-and-leaf plot, information gathered about the composition of 15 classes at two separate schools is in the picture.

We know that,

Part - A:

For Sky View School has

The mean is  = 50.8.

The median is  = 50.

The mode is 25.

For Riverside School has

The mean is  = 9.93.

The median is  = 20.5.

The mode is 20.

Part B:

For Sky View School:

The range is 96 - 12 = 84.

The 25th percentile is the 4th value when the data is arranged in ascending order, which is 20. The 75th percentile is the 12th value, which is 60.

So, the IQR is 60 - 20 = 40.

Square of mean = -38.8, -33.8, -28.8, -25.8, -25.8, -25.8, -23.8, -20.8, -9.8, -7.8, 11.2, 11.2, 14.2, 21.2, and 45.2.

Now summation of the square of mean is 19,472.4

Now, dividing by 15 we have

= 1,298.16 is variance

For Riverside School:

The range is 25 - 2 = 23.

The 25th percentile is the 4th value when the data is arranged in ascending order, which is 5. The 75th percentile is the 11th value, which is 21.

So, the IQR is 21 - 5 = 16.

The deviations from the mean are: -19.7, -9.7, -9.7, -9.7, -9.7, -9.7, -9.7, -9.7, 0.3, 0.3, 10.3, 20.3, 20.3, 20.3, 27.3.

The sum of squared deviations is 6678.7.

Variance =  = 477.0

Part C:

Riverside School is a better choice because it has a higher maximum class size of 57 compared to Sky View School 69.

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Answer:

Step-by-step explanation:

I'm sorry, but you have not provided any image about the quadrilateral in your question, so I cannot give you its most specific name. Quadrilaterals are a broad class of polygons with four sides, and they can have various specific names depending on their properties and characteristics, such as square, rectangle, parallelogram, trapezoid, kite, rhombus, etc. Please provide more information about the quadrilateral you are referring to.

Answer: the student spends 24 minutes on their art project and 32 minutes on their science project.

Step-by-step explanation:

Answer:

The student spends 24 minutes on their art project, and 32 minutes on their science project

Step-by-step explanation:

To solve this problem, we can utilise the unitary method, a process by which we find the value of a single unit, from the value of multiple units and thus, the value of multiple units from the value of a single unit.

If the total number of units in the ratio is (3+4)=7, then 7 units = 56 mins.

If 7 units = 56 mins,

then 1 unit = 56/7 mins = 8 mins.

Therefore, 3 units = 8×3 = 24 mins,

and 4 units = 8×4 = 32 mins.

Thus, the student spends 24 minutes on their art project, and 32 minutes on their science project

The pounds of marbles that Marco will need will be 357 pounds.

Ratio refers to the quantitative relationship between two or more values or quantities. It expresses the proportion of one quantity to another, typically using a colon or a slash to separate the two values. For example, a ratio of 2:1 would indicate that one value is twice as large as the other.

Ratios are often used in mathematics, finance, and other fields to compare values and make decisions based on their relationships.

The pounds of marbles that Marco will need will be:

= 21 + 56 + 77 + 98 + 105

= 357

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The correct statements are c and d i.e. the vertex of f(x) = -x²  + 2x + 5 is a maximum, while the vertex of f(x) = -2x²  - 8x - 11 is a minimum & the graph of f(x) = -x²  + 2x + 5 has a higher y-intercept than the graph of f(x) = -2x²  - 8x - 11.

What is a function?

A function is a mathematical rule that distributes a unique output value to each input value. It describes the relationship between the input (also called the independent variable) and the output (also called the dependent variable).

To compare the two functions, let's first find their vertices:

The vertex of f(x) = -x² + 2x + 5 can be found by completing the square:

f(x) = -(x - 1)² + 6, so the vertex is (1, 6).

The vertex of f(x) = -2x² - 8x - 11 can be found by using the formula x = -b/2a (where a is the coefficient of x²  and b is the coefficient of x) for the axis of symmetry: x = -(-8)/(2*(-2)) = 2. Then, plugging in x = 2, we get f(2) = -23, so the vertex is (2, -23).

a. The absolute value of the leading coefficient of f(x) = -2x²  - 8x - 11 is greater than the absolute value of the leading coefficient of f(x) = -x² + 2x + 5. This means that the graph of f(x) = -2x^2 - 8x - 11 is narrower than the graph of f(x) = -x²  + 2x + 5. So, this statement is false.

b. The maximum value of f(x) = -x²  + 2x + 5 occurs at the vertex, which is (1, 6). The maximum value of f(x) = -2x²  - 8x - 11 also occurs at its vertex, which is (2, -23). These vertices have different y-coordinates, so the two functions do not have the same maximum value. So, this statement is false.

c. Both functions share the same x-coordinate for their vertices, which is x = 1. However, their y-coordinates are different: f(1) = 6 for f(x) = -x²  + 2x + 5, and f(2) = -23 for f(x) = -2x²  - 8x - 11. Since the leading coefficient of the quadratic term is negative for both functions, the vertex of f(x) = -x²  + 2x + 5 is a maximum, while the vertex of f(x) = -2x²  - 8x - 11 is a minimum. So, this statement is true.

d. To find the y-intercept of f(x) = -x²  + 2x + 5, we can plug in x = 0: f(0) = 5. So, the y-intercept is (0, 5). To find the y-intercept of f(x) = -2x²  - 8x - 11, we can set x = 0: f(0) = -11. So, the y-intercept is (0, -11). Since 5 > -11, the graph of f(x) = -x²  + 2x + 5 has a higher y-intercept than the graph of f(x) = -2x²  - 8x - 11. So, this statement is true.

Therefore, the correct statements are c and d.

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The optimal measure of variability is the IQR, which equals 4. The proper measure of variability for the data is C.

The difference among the third and the first quartile is defined by the interquartile range. The entire series is divided into four equally sized pieces by the partitioned values referred to as quartiles. Three quartiles are present.

The spread of the middle 50% of the data, which is less susceptible to outliers than the range, is measured by the interquartile range (IQR), which is the best measure of variability for these data.

The IQR is calculated by deducting the third quartile ([tex]Q_3[/tex]) from the first quartile ([tex]Q_1[/tex]). We can see from the box plot that [tex]Q_1[/tex] is roughly

17 and [tex]Q_3[/tex] is roughly 21.

Therefore,

[tex]IQR=Q_3-Q_1\\\\IQR=21-17\\\\IQR=4[/tex]

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The number of hits would Rico get in 56 at-bats is 21 hits if he maintains the same rate of hits per at-bat.

To determine how many hits Rico would get in 56 at-bats, we can use a proportion based on the information given:

Hits / At-bats = Hits / At-bat

We know that Rico got 12 hits in 32 at-bats, so we can plug those values into the proportion:

12 / 32 = Hits / 56

We can then solve for Hits by cross-multiplying:

12 * 56 = 32 * Hits

672 = 32 * Hits

Hits = 672 / 32

Hits = 21

Therefore, if Rico maintains the same rate of hits per at-bat, he would be expected to get approximately 21 hits in 56 at-bats.

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The mood of the syllogism is AEA-2 (All F are C, No R are F, therefore No R are C). The figure is 1, as both premises share the middle term C.

The Venn diagram would have three circles: one for F (fossil fuels), one for R (renewable forms of energy), and one for C (combustible gases). The F circle would be fully contained within the C circle, indicating that all fossil fuels are combustible gases. The R circle would be completely outside of the F circle, indicating that no renewable forms of energy are fossil fuels. The area where the C and F circles overlap would be shaded, indicating that some combustible gases are fossil fuels. However, the R circle would not overlap with the C circle, indicating that no combustible gases are renewable forms of energy. Overall, the diagram visually represents the syllogism and its conclusion that some combustible gases are not renewable forms of energy.

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It is true that a linear programming problem can have an optimal solution that is not a corner point.

In linear programming, the optimal solution represents the point where the objective function is optimized while still satisfying all the constraints.

In some cases, the optimal solution may occur at a corner point of the feasible region, where two or more of the constraints intersect.

However, it is possible for the optimal solution to occur at a point that is not a corner point, but rather lies on an edge or a line segment of the feasible region.

This can occur when the objective function is parallel to one of the constraint lines or when there are redundant constraints that limit the feasible region.

Therefore, it is true that a linear programming problem can have an optimal solution that is not a corner point.

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Answer:

$ 1644500

Step-by-step explanation:

The statement an assumption underlying the t-distribution is that the population from which we are sampling comes from an exponential distribution is false.

The t-distribution assumes that the population from which we are sampling follows a normal distribution, not an exponential distribution.

The t-distribution is used when the population standard deviation is unknown and is estimated from the sample standard deviation, and when the sample size is small (typically less than 30).

When the test measure is expansive (regularly more noteworthy than 30), the t-distribution gets to be exceptionally comparative to the standard typical dispersion. 

therefore, an assumption underlying the t-distribution is that the population from which we are sampling comes from an exponential distribution is false.

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Since we know that the distance between the origin and A' should be d, which is 7/3 times the distance between the origin and A.

Therefore, the correct answer is D.

What is Pentagon?

A pentagon is a geometric shape that has five sides and five angles. It is a two-dimensional polygon, which means it is a flat shape with straight sides.

To find the coordinates of the dilated pentagon A'B'C'D'E', we need to multiply the coordinates of each vertex of pentagon ABCDE by the scale factor. Since the origin is the center of dilation, we can use the formula:

(x', y') = k(x, y)

where (x, y) are the original coordinates of a vertex, k is the scale factor, and (x', y') are the new coordinates of the corresponding vertex.

To find the scale factor, we can use the distance formula to find the distance between the origin and any one of the vertices. Let's use vertex A for convenience:

Distance OA = sqrt((-1-0)² + (1-0)²) = sqrt(2)

Distance OA' = k * Distance OA

We want to find the scale factor that will result in a dilation centered at the origin, so we want OA' to be the desired distance between the origin and A'. Let's say that distance is d. Then:

d = k * sqrt(2)

Solving for k, we get:

k = d / sqrt(2)

We are not given the desired distance between the origin and A', so we cannot determine the exact value of k. However, we can still determine which answer choice represents the correct dilation.

Let's try answer choice A:

(x', y') = (3/7x, 3/7y)

This represents a dilation with a scale factor of 3/7. But we already know that the scale factor should be d / sqrt(2). Since d could be any value, we cannot say for sure whether 3/7 is the correct scale factor.

Answer choice B:

(x', y') = (x + 3/7, y + 3/7)

This represents a translation, not a dilation. Therefore, it cannot be the correct answer.

Answer choice C:

(x', y') = (x + 7/3, y + 7/3)

This represents a dilation with a scale factor of 1. This is not the correct scale factor, since we know that the distance between the origin and A' should be greater than the distance between the origin and A.

Answer choice D:

(x', y') = (7/3x, 7/3y)

This represents a dilation with a scale factor of 7/3. This is the correct scale factor, since we know that the distance between the origin and A' should be d, which is 7/3 times the distance between the origin and A.

Therefore, the correct answer is D.

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Answer:

This is a linear equation.

Graph the points (-10, -2), (0, 0), and (10, 2). Then draw a line through all three points.

The required width of the flower garden is 6 feet.

The area of a rectangular flower garden is 132 square feet.

Let us assume the length of the flower garden is l and its width is w (in feet).

The length of the flower is 10 feet more than twice the width of the garden.

That is, l = (10 + 2w ) feet

Thus the area of the flower garden is ,

length * width = 132 sq ft

⇒ (10+ 2w) w = 132

⇒2w^2 + 10w -132 = 0

⇒ w^2 + 5w - 66 = 0

⇒ w^2 + 11w - 6w - 66 = 0

⇒ w( w+ 11) - 6( w + 11) = 0

⇒ (w - 6)(w + 11) = 0

⇒ w = 6 and = -11

Since length or width of any garden can not be in negative, hence ignoring the negative value of w.

Thus, width of the flower garden is w=6  feet.

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This data would be considered "paired" data.

The population of ferrets from which our sample was drawn, represented as μd, where μd = μend - μstart, and μ represents the population mean.

       We are dealing with "paired" data since we are comparing the weights of the same ferrets at two different points in time.

      The parameter we are trying to estimate is the mean difference in weight between the start and end of the study for the population of ferrets from which our sample was drawn.

This mean difference in weight can be represented as μd, where μd = μend - μstart, and μ represents the population mean. To estimate this parameter, we would need to calculate the difference in weight for each ferret and then take the average of these differences. This estimate would then provide us with an understanding of how much, on average, the ferrets in the population have gained or lost weight over the course of the study.  

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