in need help
Relationships in Triangles

Answer:

It is d

Step-by-step explanation:

Answer:

B.

Step-by-step explanation:

the visible line is the defined function.

this line goes from x=1 to x=4, and has the functional results from y=1 to y=7.

the domain is the valid interval of the input variable (typically x), while the range is the valid inescapable of the result variable (typically y).

so, B is the right answer.

Answer:

[tex]y=\frac{15\sqrt{3}}{4}[/tex]

Step-by-step explanation:

We are given that

[tex]\theta_1=60^{\circ}[/tex]

[tex]\theta_2=30^{\circ}[/tex]

We have to find the missing part.

[tex]\frac{x}{15}=cos\theta_1=cos60^{\circ}[/tex]

Using the formula

[tex]\frac{base}{hypotenuse}=cos\theta[/tex]

[tex]x=15cos60^{\circ}=\frac{15}{2}[/tex]

[tex]\frac{z}{15}=sin60^{\circ}[/tex]

Using the formula

[tex]\frac{Perpendicular\;arm}{hypotenuse}=sin\theta[/tex]

[tex]z=15\times \frac{\sqrt{3}}{2}=\frac{15\sqrt{3}}{2}[/tex]

Now,

[tex]\frac{a}{x}=cos60^{\circ}[/tex]

[tex]\frac{a}{\frac{15}{2}}=\frac{1}{2}[/tex]

[tex]a=\frac{1}{2}\times 15/2=\frac{15}{4}[/tex]

[tex]y=x sin60^{\circ}[/tex]

[tex]y=\frac{15}{2}\times \frac{\sqrt{3}}{2}[/tex]

[tex]y=\frac{15\sqrt{3}}{4}[/tex]

Step-by-step explanation:

=(g-f)(n)

=4n+7-2n-3

=2n+4

Answer:

statement not complete

Answer:

6.14 m

Step-by-step explanation:

If she moves 3.65 metres to the other side of the mirror. Her spouse calculates that there are 1.55 metres between her eyes and the earth. The height of the tail post is 6.14 m.

The distance up or down a specified point of comparison, most often a reference spherical geometry, a mathematical model of the Earth's sea level as an equipotential gravitational surface, determines a physical location's elevation.

Given that, after travelling 14.45 metres from her school, she lays a flat mirror on the ground in the centre, with an x drawn on it. When she can clearly see the top of the goalpost depicted in the x.

She moves 3.65 metres to the other side of the mirror. Her spouse calculates that there are 1.55 metres between her eyes and the earth. 

Suppose the height of the tail post is x,

The geometric relation is,

1.55/3.65 = x/14.45

x=(14.45×1.55)/3.65

x=6.14 m

Thus, if she moves 3.65 metres to the other side of the mirror. Her spouse calculates that there are 1.55 metres between her eyes and the earth. The height of the tail post is 6.14 m.

Learn more about the elevation here:

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Answer:

a is correct option......

❀ [tex]\huge\underline{ \underline{Solution :-}}[/tex]

[tex]( {y}^{2} + \frac{5}{7} )( {y}^{2} - \frac{14}{5} )[/tex]

To solve, use the algebraic identity ➺

[tex]( {y}^{2} + \frac{5}{7} )( {y}^{2} - \frac{14}{5} ) \\ = ({y}^{2}) ^{2} + ( \frac{5}{7} + - \frac{14}{5} ) {y}^{2} + \frac{5}{7} \times - \frac{14}{5} \\ = {y}^{4} - \frac{73}{35} {y}^{2} - 2[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer:

2 solutions so it can be inferred that it might be a quadratic

Step-by-step explanation:

Answer:

no solutions

Step-by-step explanation:

y = 0 and y = - 7 are horizontal parallel lines.

Since they are parallel, they never intersect and so have no solutions.

Step-by-step explanation:

[tex]\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\ [/tex]

[tex]\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\ [/tex]

[tex]\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\ [/tex]

[tex]\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\ [/tex]

[tex]\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\ [/tex]

[tex]\longrightarrow \tt { 250 \times 100 = P \times 50} \\ [/tex]

[tex]\longrightarrow \tt { 25000 = P \times 50} \\ [/tex]

[tex]\longrightarrow \tt { \dfrac{25000}{50} = P } \\ [/tex]

[tex]\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\ [/tex]

Therefore principal is $500.

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

[tex]\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\ [/tex]

[tex]\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\ [/tex]

[tex]\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\ [/tex]

[tex]\longrightarrow \tt{ 31x + 1260= 35x} \\ [/tex]

[tex]\longrightarrow \tt{ 1260= 35x-31x} \\ [/tex]

[tex]\longrightarrow \tt{ 1260= 4x} \\ [/tex]

[tex]\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\ [/tex]

[tex]\longrightarrow \underline{\boxed{ \tt { 315 = x }}} \\ [/tex]

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

[tex]\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\ [/tex]

[tex]\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\ [/tex]

[tex]\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\ [/tex]

[tex]\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\ [/tex]

Answer:

A=2

B=8

C=-38

X=2.8/X=-6.8

Step-by-step explanation:

Answer:

[tex]y= \frac{1}{2} x +6[/tex]

Step-by-step explanation:

[tex]x/2-y+6=0[/tex]

[tex]x/2 +6=y[/tex]

[tex]y= \frac{1}{2} x +6[/tex]

Answer:

None of the options is true

Step-by-step explanation:

Given

[tex]y < 3x - 1[/tex]

[tex]y > -x + 4[/tex]

Required

Which makes the above inequality true

The missing options are:

[tex](4,0)\ (1,2)\ (0,4)\ (2,1)[/tex]

[tex](a)\ (x,y) = (4,0)[/tex]

Substitute values for x and y in the inequalities

[tex]y < 3x - 1[/tex]

[tex]0<3*4 - 1[/tex]

[tex]0<12 - 1[/tex]

[tex]0<11[/tex] ---- This is true

[tex]y &gt; -x + 4[/tex]

[tex]0 > -4 + 4[/tex]

[tex]0 > 0[/tex] --- This is false

[tex](b)\ (x,y) = (1,2)[/tex]

Substitute values for x and y in the inequalities

[tex]y &lt; 3x - 1[/tex]

[tex]2<3 * 1 - 1[/tex]

[tex]2<3 - 1[/tex]

[tex]2<2[/tex] --- This is false (no need to check the second inequality)

[tex](c)\ (x,y) = (0,4)[/tex]

Substitute values for x and y in the inequalities

[tex]y &lt; 3x - 1[/tex]

[tex]4< 3*0-1[/tex]

[tex]4< 0-1[/tex]

[tex]4<-1[/tex] --- This is false (no need to check the second inequality)

[tex](d)\ (x,y) = (2,1)[/tex]

Substitute values for x and y in the inequalities

[tex]y &lt; 3x - 1[/tex]

[tex]1<3*2-1[/tex]

[tex]1<6-1[/tex]

[tex]1<5[/tex] --- This is true

[tex]y &gt; -x + 4[/tex]

[tex]1 > -2+4[/tex]

[tex]1 > 2[/tex] -- This is false

Hence, none of the options is true

Answer:

44

Step-by-step explanation:

5+8/4*3

5+24/4

20+24

44

Answer:

7 cajas grandes y 3 cajas pequeñas  

Step-by-step explanatio:

c ans

...................

Step-by-step explanation:

number of bags=8bags

which is the fruits=apples and bananas

total number of apples and bananas bag = 4 bag of each

Answer:

C. 4

Step-by-step explanation:

Use the slope formula y2-y1 / x2-x1

6+2/3-1

8/2

4

So, the answer is C. 4.

Answer:

30 seconds

Step-by-step explanation:

→ Work out how many floors it's going to travel

15 - 3 = 12 floors

→ Work out how many meters 12 floors is

12 × 5 = 60 meters

→ Work out how long that will take

60 ÷ 2 = 30 seconds

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

[tex](a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x[/tex]

[tex](b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)[/tex]

[tex](c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow 3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x[/tex]

[tex](d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x[/tex]

Thus, all the identities are correct.

A. Not an identity

B. An identity

C. Not an identity

D. An identity

To check whether each expression is an identity, we need to verify if the equation holds true for all values of the variable x. If it is true for all values of x, then it is an identity. Let's check each option:

A. [tex]\((\sin x + \cos x)^2 = 1 + \sin 2x\)[/tex]

To check if this is an identity, let's expand the left-hand side (LHS):

[tex]\((\sin x + \cos x)^2 = \sin^2 x + 2\sin x \cos x + \cos^2 x\)[/tex]

Now, we can use the trigonometric identity [tex]\(\sin^2 x + \cos^2 x = 1\)[/tex] to simplify the LHS:

[tex]\(\sin^2 x + 2\sin x \cos x + \cos^2 x = 1 + 2\sin x \cos x\)[/tex]

The simplified LHS is not equal to the right-hand side (RHS) 1 + sin 2x since it is missing the sin 2x term. Therefore, option A is not an identity.

B. [tex]\(\sin 6x = 2 \sin 3x \cos 3x\)[/tex]

To check if this is an identity, we can use the double-angle identity for sine:[tex]\(\sin 2\theta = 2\sin \theta \cos \theta\)[/tex]

Let [tex]\(2\theta = 6x\)[/tex], which means [tex]\(\theta = 3x\):[/tex]

[tex]\(\sin 6x = 2 \sin 3x \cos 3x\)[/tex]

The equation holds true with the double-angle identity, so option B is an identity.

C. [tex]\(\frac{\sin 3x}{\sin x \cos x} = 4\cos x - \sec x\)[/tex]

To check if this is an identity, we can simplify the right-hand side (RHS) using trigonometric identities.

Recall that [tex]\(\sec x = \frac{1}{\cos x}\):[/tex]

[tex]\(4\cos x - \sec x = 4\cos x - \frac{1}{\cos x} = \frac{4\cos^2 x - 1}{\cos x}\)[/tex]

Now, using the double-angle identity for sine, [tex]\(\sin 2\theta = 2\sin \theta \cos \theta\),[/tex] let [tex]\(\theta = x\):[/tex]

[tex]\(\sin 2x = 2\sin x \cos x\)[/tex]

Multiply both sides by 2: [tex]\(2\sin x \cos x = \sin 2x\)[/tex]

Now, the left-hand side (LHS) becomes:

[tex]\(\frac{\sin 3x}{\sin x \cos x} = \frac{\sin 2x}{\sin x \cos x}\)[/tex]

Using the double-angle identity for sine again, let [tex]\(2\theta = 2x\):[/tex]

[tex]\(\frac{\sin 2x}{\sin x \cos x} = \frac{2\sin x \cos x}{\sin x \cos x} = 2\)[/tex]

So, the LHS is 2, which is not equal to the RHS [tex]\(\frac{4\cos^2 x - 1}{\cos x}\)[/tex]. Therefore, option C is not an identity.

D. [tex]\(\frac{\sin 3x - \sin x}{\cos 3x + \cos x} = \tan x\)[/tex]

To check if this is an identity, we can use the sum-to-product trigonometric identities:

[tex]\(\sin A - \sin B = 2\sin \frac{A-B}{2} \cos \frac{A+B}{2}\)\(\cos A + \cos B = 2\cos \frac{A+B}{2} \cos \frac{A-B}{2}\)[/tex]

Let A = 3x and B = x:

[tex]\(\sin 3x - \sin x = 2\sin x \cos 2x\)\(\cos 3x + \cos x = 2\cos 2x \cos x\)[/tex]

Now, we can rewrite the expression:

[tex]\(\frac{\sin 3x - \sin x}{\cos 3x + \cos x} = \frac{2\sin x \cos 2x}{2\cos 2x \cos x} = \frac{\sin x}{\cos x} = \tan x\)[/tex]

The equation holds true, so option D is an identity.

To know more about identity:

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Answer:

m<BAC = 60°

Step-by-step explanation:

Theorem:

In a triangle, the measure of an exterior angle equals the sum of the measures of its remote interior angles.

m<ACD = m<A + m<B

130° = m<A + 70°

m<A = 60°

m<BAC = 60°

Answer:

Gradient of A: 2

Gradient of B: -1

Step-by-step explanation:

Gradient = change in y/change in x

✔️Gradient of A using two points on line A, (2, 5) and (0, 1):

Gradient = (1 - 5)/(0 - 2) = -4/-2

Simplify

Gradient of A = 2

✔️Gradient of B using two points on line B, (0, 5) and (5, 0):

Gradient = (0 - 5)/(5 - 0) = -5/5

Simplify

Gradient of B = -1

Answer:

1. x = 54, y = 114,

missing angles => 66° and 114°

2. x = 42, y = 14,

Missing angles => 84°, 86°

3. x = 40, y = 50

Missing angles => 105°, 75°

Step-by-step explanation:

1. y° = 114° (corresponding angles are congruent)

(x + 12)° + y° = 180° (linear pair angles)

Substitute

x + 12 + 114 = 180

x + 126 = 180

Subtract 126 from each side

x = 180 - 126

x = 54

✔️Find the missing angles by plugging in the values of x and y in each case

(x + 12)° = 54 + 12 = 66°

y = 114°

2. ✔️Find x:

(2x)° + 96° = 180° (consecutive interior angles are supplementary)

Subtract 96 from each side

2x = 180 - 96

2x = 84

x = 84/2

x = 42

✔️Find y:

(3y + 44)° + 94° = 180° (consecutive interior angles are supplementary)

3y + 44 + 94 = 180

3y + 138 = 180

3y = 180 - 138

3y = 42

y = 42/3

y = 14

✔️Missing angles:

(2x)°

Plug in the value of x

= 2(42) = 84°

(3y + 44)°

Plug in the value of y

3(14) + 44 = 86°

3.

✔️Find x:

3x - 15 = 105 (corresponding angles are congruent)

3x = 105 + 15

3x = 120

x = 120/3

x = 40

✔️Find y:

(3x - 15)° + (y + 25)° = 180° (linear pair angles are supplementary)

Plug in the value of x to solve for y

3(40) - 15 + y + 25 = 180

120 - 15 + y + 25 = 180

Add like terms

130 + y = 180

y = 180 - 130

y = 50

✔️Missing angles:

(3x - 15)°

Plug in the value of x

3(40) - 15 = 105°

(y + 25)°

Plug in the value of y

50 + 25 = 75°

(x-2)(x+2) is factorize is given eq

Answer:

C)Ok i pick the point (18,4)

this point represents that if this person studied from 18 hours they got a GPA of 4.0

D) the chart below is the scatter plot

Hope This Helps!!!

Answer:

Population

Step-by-step explanation:

A population can be defined as the total number of living organisms living together in a particular place and sharing certain characteristics in common.

A sample survey is a statistical method used for the collection of data from a target population in order to draw an inference and reach a logical conclusion.

In Statistics, sampling can be defined as a process used to collect or select data (objects, observations, or individuals) from a larger statistical population using specific procedures.

In this scenario, the entire group of registered voters in Florida is an example of a population.

Answer:

C.) AA

Step-by-step explanation:

AA is a similarity theorem

hope this helps stay safe :)

Answer:

The answer would be C.

Step-by-step explanation: Hope this helps :)

Answer:

wait what

Step-by-step explanation:

Answer:

188 m

Step-by-step explanation:

[tex] \tan(12) = \frac{40}{x} \\ x = \frac{40}{ \tan(12) } \\ x = 188[/tex]

Answer:

I think that the other answer is WRONG

tan(12) = [tex]\frac{x}{40}[/tex]

x = tan(12)*40 = 8.5

Step-by-step explanation:

[tex]\frac{sin\left(78\right)}{40}=\frac{sin\left(12\right)}{x}[/tex] = 8.5