In order to estimate the population size of the woodlice in her garden, Jessica used the mark-recapture method: she trapped, marked and released 20 woodlice. Three days later, she trapped 15 woodlice and observed that 10 had marks. Use the following formula to estimate the woodlice population size: population size = 1st sample × 2nd sample ÷ 2nd sample that had been marked.



NEED HELP ASAP!!!!!!

Answers

Answer 1

To determine the size of the entire population: In the equation N = M, replace the variables of M solutions, R (number all marked recaptured), with T (total recaptured during second visit). T R = frac M T R N = RMT.

What is the mark-recapture method's formula?

In order for the mark-recapture method to function, it must be assumed that the proportion the marked organisms that are recaptured inside the second sample corresponds to that of the original marked in the entire population. This equation R(recaptured)/C(captured in second sample)=M(marked initially)/N) illustrates this (total number in population).

Why do people employ the capture-recapture technique?

It has been suggested that capture-recapture techniques be used to gauge a register's degree of completeness. These techniques were initially created to determine how big a confined animal colony was. The process aims to capture, tag, and release as many animals is possible in a given region all at once. This is known as the "capture" stage.

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Related Questions

12. What is the most common source of pollution?
• nuclear
• gas
• coal
O oil

Answers

It really depends on the country you live in but I think the most common overall is oil

Which of the following is true for a volatic cell constructed in the first part of the experiment?

Answers

B, Electrons flow from the anode to the cathode is true for a voltaic cell constructed in the first part of the experiment.

What is a voltaic cell?

A voltaic cell, also known as a galvanic cell, is an electrochemical cell that converts chemical energy into electrical energy. It consists of two half-cells, each with an electrode and an electrolyte solution. The two half-cells are connected by a wire and a salt bridge.

During operation, the electrons flow from the anode (the electrode where oxidation occurs) to the cathode (the electrode where reduction occurs) through the wire, while ions flow through the salt bridge to balance the charges in the two half-cells. This generates an electric current that can be used to power electrical devices.

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Complete question:

Which of the following is true for a voltaic cell constructed in the first part of the experiment?

Electrons flow from higher potential energy to lower potential energy.

Electrons flow from the anode to the cathode.

Electrons flow from the more negatively charged electrode to the more positively charged electrode.

All of the above

2. Consider the combustion of ethylene,
C₂Ha(g) + 3 O₂(g) → → 2 CO2(g) + 2 H₂O(g)
a)If the concentration of C₂H4 is decreasing at the rate of 0.036 M/s, what are the rates of change
in the concentrations of CO₂ and H₂O?
b) Smol C₂H4 is placed in a 2.0L container, after 1minute, 2mols of C₂H4 remained. What is the
rate of consumption of C₂H4? What is the rate of O₂ in the reaction?

Answers

(a). The rate of change in the concentration of [tex]H_{2}O[/tex] and the rate of change in the concentration of [tex]CO_{2}[/tex] is: 0.072 M/s.

(b). The rate of consumption of [tex]O_{2}[/tex] is: 0.10 mol  [tex]O_{2}[/tex] per second.

What is concentration?

a) To determine the rates of change in the concentrations of  [tex]CO_{2}[/tex]  and [tex]H_{2}O[/tex] , we first need to determine the stoichiometric coefficients of each reactant and product in the balanced chemical equation.

From the balanced chemical equation:

1 mol  [tex]C_{2}H_{4}[/tex] reacts to form 2 mol  [tex]CO_{2}[/tex] and 2 mol [tex]H_{2}O[/tex].

Therefore, the rate of change in the concentration of [tex]CO_{2}[/tex]  is:

(0.036 M/s) x (2 mol [tex]CO_{2}[/tex] /1 mol  [tex]C_{2}H_{4}[/tex]) = 0.072 M/s

The rate of change in the concentration of [tex]H_{2}O[/tex]  is also:

(0.036 M/s) x (2 mol [tex]H_{2}O[/tex] /1 mol [tex]C_{2}H_{4}[/tex]) = 0.072 M/s

What is consumption?

b) To find the rate of consumption of  [tex]C_{2}H_{4}[/tex], we can use the formula:

rate = Δ[ [tex]C_{2}H_{4}[/tex]]/Δt

Initially, the concentration of  [tex]C_{2}H_{4}[/tex] is:

n/V = 2 mol / 2.0 L = 1.0 M

After 1 minute, the concentration of  [tex]C_{2}H_{4}[/tex] is:

n/V = 2 mol / 2.0 L = 1.0 M

(change in concentration is 0)

Therefore, the rate of consumption of  [tex]C_{2}H_{4}[/tex] is:

rate = Δ[ [tex]C_{2}H_{4}[/tex]]/Δt = (1.0 M - 1.0 M) / 60 s = 0 M/s

The rate of [tex]O_{2}[/tex] consumption can be found by using the stoichiometric ratio between  [tex]C_{2}H_{4}[/tex] and [tex]O_{2}[/tex] in the balanced chemical equation:

1 mol  [tex]C_{2}H_{4}[/tex] reacts with 3 mol  [tex]O_{2}[/tex] .

Initially, we have 6 mol [tex]O_{2}[/tex] in the container.

After 1 minute, 2 mol  [tex]C_{2}H_{4}[/tex] are consumed, which corresponds to the consumption of 6 mol  [tex]O_{2}[/tex] :

6 mol  [tex]O_{2}[/tex] / 2 mol  [tex]C_{2}H_{4}[/tex] = 3 mol  [tex]O_{2}[/tex] / 1 mol  [tex]C_{2}H_{4}[/tex]

Therefore, the rate of consumption of [tex]O_{2}[/tex] is:

rate = (3 mol  [tex]O_{2}[/tex]  / 1 mol  [tex]C_{2}H_{4}[/tex]) x (0.0333 mol  [tex]C_{2}H_{4}[/tex]/s) = 0.10 mol  [tex]O_{2}[/tex]  per second.

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Does anyone know how to solve this? (Picture Provided)

Answers

For chemical reaction (3), the standard enthalpy change is 279.0 kJ.

How to calculate enthalpy change?

To find the standard enthalpy change for reaction (3), use Hess's Law which states that the overall enthalpy change of a reaction is independent of the pathway between the initial and final states.

Obtain the required reaction by subtracting the enthalpy change of reaction (2) from that of reaction (1) as follows:

(1) 2C(s) + H₂(g) → C₂H₂(g) ΔH° = 226.7 kJ

(2) 2C(s) + 2H₂(g) → C₂H₄(g) ΔH° = 52.3 kJ

(3) C₂H₂(g) + H₂(g) → C₂H₄(g) ΔH° = ?

To get the enthalpy change for reaction (3), flip the reaction (2) and multiply by 1/2 so that the reactants match those in reaction (1):

(2) C₂H₄(g) → 2C(s) + 2H₂(g) ΔH° = -52.3 kJ

Now write the reaction (3) as the difference between (1) and (2):

(1) 2C(s) + H₂(g) → C₂H₂(g) ΔH° = 226.7 kJ

(2) C₂H₄(g) → 2C(s) + 2H₂(g) ΔH° = -52.3 kJ

(3) C₂H₂(g) + H₂(g) → C₂H₄(g) ΔH° = 279.0 kJ

Therefore, the standard enthalpy change for reaction (3) is 279.0 kJ.

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Which state of matter - solid, liquid, or gas- tends to have unique factors (different from the other two) to consider when discussing solubility

Answers

The state of matter that tends to have unique factors to consider when discussing solubility compared to the other two states (solid and gas) is the liquid state.

Which state has unique factors?

Solubility refers to the ability of a substance (solute) to dissolve in a particular solvent to form a homogeneous mixture (solution). Various factors can affect the solubility of a substance, including temperature, pressure, and the nature of the solute and solvent.

In the case of liquids, the unique factor to consider when discussing solubility is often temperature. The solubility of many solid solutes in liquids generally increases with increasing temperature. This is because higher temperatures provide more energy to break the intermolecular forces between solute particles, allowing them to disperse more evenly throughout the solvent.

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Question 5(Multiple Choice Worth 3 points)
(07.02 LC)

The substances below are listed by increasing specific heat capacity value. Starting at 30.0 °C, they each absorb 100 kJ of thermal energy. Which one do you expect to increase in temperature the least?

a) Cadmium, 0.230 J/(g °C)
b) Sodium, 1.21 J/(g °C)
c) Water, 4.184 J/(g °C)
d) Hydrogen, 14.267 J/(g °C)

Answers

Component form of the vector v is as follows: 4 3 1.5 1 Using the standard basis vectors I and j), express the vector w as follows: 3 two 1 4 pp . 1 3 w 3.5 C. V plus w= d. Determine the vector v's magnitude

What does "vector" mean?

Latin word for "carrier" is "vector." Point A is transported to point B by vectors. The orientation of the vectors AB is the direction in which point A is moved in relation to point B, and the amplitude of the vector is the width of the line connecting the two locations A and B. The terms Euclidean vectors and spatial vectors are also used to refer to vectors.

A vector space is what?

A vector space, also known as a linear space, is a collection of things called vectors that can be added to and multiplied ("scaled") by figures called scalars in the fields of mathematics, physics, and engineering.

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35.0 ml. of a 0.250 M solution of /OH is titrated with 0.150 M HCI. After 35.0 mL of the HCl has been added, the resultant

Answers

Determine the amount of KOH present in the resulting solution. KOH was initially 0.00875 mol, then 0.00525 mol of it interacted with HCl. As a result, 0.00875 mole - 0.00525 mol (= 0.00350 mol of KOH is left. The resulting solution has a volume of 70.0 mL (35.0 mL plus 35.0 mL).

Is HCl directly titrated with NaOH?

The titrant (NaOH), which is added gradually throughout the course of a titration, is added to the unknown substance. The equivalency point is the moment at which precisely the right quantity of titrant (NaOH) has indeed been added that react to the entire analyte (HCl).

What happens when you titrate NaOH to HCl?

What took place during titration: One mole of NaOH interacts with one mole of HCl inside the reaction between the two substances. NaOH with HCl equals NaCl plus H2O. (NaOH and HCl have a mole ratio of 1:1.) • The NaOH concentration is 0.1 M, or 0.1 molecules per litre.

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A precipitation reaction involves the formation of a precipitate when aqueous solutions are mixed. Not all combinations of aqueous solutions produce precipitates, and it is important to be able to predict the ones that do.
Complete and balance the molecular equation for the reaction between aqueous solutions of lithium fluoride and potassium chloride, and use the states of matter to show if a precipitate forms.
Part 2 : Write the complete ionic equation for the reaction that takes place when aqueous solutions of lithium fluoride and potassium chloride are mixed.

Answers

In this reaction, aqueous solutions of lithium fluoride and potassium chloride are mixed, but no precipitate forms. This is because the products of the reaction (LiCl and KF) are both soluble in water, and therefore remain in the aqueous state.

What is reaction?

Reaction is a process in which a system changes in response to an external stimulus. It is a response to an action, event, or phenomenon, and it is typically expressed in the form of an observable physical or mental change. Reactions can take place in a variety of forms, including chemical reactions, physical reactions, and psychological reactions. Chemical reactions are the most common type of reaction and involve the rearrangement of atoms and molecules in order to form new substances. Physical reactions involve changes in the physical properties of a system, such as changes in temperature, pressure, or volume. Psychological reactions include changes in behavior and emotion.

The complete and balanced molecular equation for the reaction between aqueous solutions of lithium fluoride and potassium chloride is:
LiF (aq) + KCl (aq) → LiCl (aq) + KF (aq)
The complete ionic equation for this reaction is:
Li+ (aq) + F- (aq) + K+ (aq) + Cl- (aq) → Li+ (aq) + Cl- (aq) + K+ (aq) + F- (aq)

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An aqueous solution of 4mol/l nitric acid is electrolyzed in an electrolytic cell using graphite electrodes . write the chemical symbols for all the ions present in the electrolytic cell

Answers

The ions found in the acqueous solutions are:

H+, NO3-, O-

Mary claims that two Duluth Solutions will have a lower reaction rate than two concentrated Solutions which statement tells whether Mary is right and gives a correct explanation a she is right because there will be fewer successful collisions between reactants and the dilute Solutions B​ be she is right because the Duluth solution gives the molecule more space to move more quickly see she is not right because of the dilute solution gives the molecules more room to move around and align themselves well for collisions or D she is not right because there will be fewer successful collisions between reactants in the dilute Solutions.​

Answers

Statement A is correct: Mary is right because there will be fewer successful collisions between reactants in the dilute solutions.

What are reactants ?

A reactant is a substance that undergoes a chemical reaction with another substance to form a new substance. In a chemical reaction, one or more reactants are transformed into one or more products, which are the end result of the reaction.

Reactants are typically written on the left side of a chemical equation, while the products are written on the right side. For example, in the chemical equation for the reaction between hydrogen gas and oxygen gas to form water:

2H2 + O2 → 2H2O

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When a hydrogen atom is added to a polyatomic ion, the amount of negative charge . Following this pattern, we can see that hydrogen carbonate has a charge of and hydrogen sulfate has a charge of .

Answers

If we add one or two hydrogen ions to a polyatomic ion that has a 3-charge, as the phosphate ion (PO₄3-), it will still be a polyatomic ion. (Three H+ would entirely cancel out the 3-charge, turning it into a neutral molecule and removing it from the category of polyatomic ions.

Why does carbonate have a negative 2 charge?

As a result, the carbonate ion has 2 more electrons than protons due to its negative charge. The doubly bonded oxygen in the carbonate ion is neutral, whereas each single bonded oxygen has a negative charge. This is the cause of the total charge of "-2," then.

An essential component of the atmosphere of stars like the Sun is the hydrogen anion.

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The two possible units of molarity are

Answers

Answer: The units for molarity are moles/liter.

Similarly, the equation to find molarity is moles divided by liters.

Explanation:  

mol / L is a unit of molar concentration. These are the number of moles of dissolved material per liter of solution. 1 mol / L is also called 1M or 1molar. Mol / m3 is also a unit of molar concentration.

Molarity is expressed in units of moles per liter (mol / L). This is a very common unit, so it has its own symbol, which is the uppercase M. A solution with a concentration of 5 mmol / l is called a 5 M solution or has a concentration value of 5 mol.

The molar concentration of the solution is equal to the number of moles of the solute divided by the mass of the solvent (kilogram), and the molar concentration of the solution is equal to the number of moles of the solute divided by the volume of the solution (liter). increase.

Given the following data for water:
Heat of fusion = 334 J/g
Heat of vaporization = 2,256 J/g
Specific heat of solid = 2.09 J/g °C)
Specific heat of liquid = 4.184 J/g °C)
Specific heat of gas = 1.84 J/g °C)
Calculate how much energy is needed to change 100.0 grams of liquid water at 15.0 °C to vapor at 125.0 °C. (3 points)
Oa
O
b
44,000 J
89,400 J
104,000 J
266,000 J

Answers

The process of changing 100.0 grams of liquid water at 15.0 °C to vapor at 125.0 °C involves several steps, and we need to calculate the energy required for each step and then add them up:

1. Heating the liquid water from 15.0 °C to 100.0 °C:

q = m * Cp * ΔT
= 100.0 g * 4.184 J/g °C * (100.0 °C - 15.0 °C)
= 34,972 J

2. Vaporizing the liquid water at 100.0 °C:

q = m * Hvap
= 100.0 g * 2,256 J/g
= 225,600 J

3. Heating the water vapor from 100.0 °C to 125.0 °C:

q = m * Cp * ΔT
= 100.0 g * 1.84 J/g °C * (125.0 °C - 100.0 °C)
= 4,600 J

The total energy required is the sum of the three steps:

Q = q1 + q2 + q3
= 34,972 J + 225,600 J + 4,600 J
= 265,172 J

Therefore, the energy needed to change 100.0 grams of liquid water at 15.0 °C to vapor at 125.0 °C is approximately 265,172 J, which is closest to option (d) 266,000 J.

Calculate the pOH of a 0.000259 M HClO₄ solution at 25 ⁰C.

a.)
3.861 x 10⁻¹¹
b.)
17.587
c.)
10.413
d.)
3.587

Answers

A solution of 0.000259 M [tex]HCIO_4[/tex] at 25°C has a pOH of 10.413. The answer is option (c).

What is solution?

A solution is a method for resolving a conflict or navigating a challenging circumstance. It provides a solution to a particular issue. Solutions frequently involve many players in the problem-solving process and are creative and collaborative.

Using the HClO₄ concentration, find pH of the solution.

HClO₄ is a powerful acid.

The chemical reaction is:

HClO₄(aq) -> H⁺(aq) + ClO₄⁻(aq)

H⁺ ion concentration in the solution is equivalent to HClO₄ concentration.

pH = -log[H⁺]

substitute H⁺ values:

pH = -log[0.000259]

pH = 3.585

calculated using the following equation:

[H⁺] = Ka x [HClO₄]

where Ka is the acid dissociation constant of HClO₄,

The pOH is determined by the negative logarithm of the concentration of hydroxide ions:

pOH = 14 - pH

substitute pH value

pOH = 14 - 3.585

pOH = 10.415

Therefore, A solution of 0.000259 M HClO₄ at 25°C has a pOH of 10.415.

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Which reactions have a positive Δrxn?


o A(g)+B(g)⟶C(g)
o A(g)+B(g)⟶3C(g)
o A(s)+B(s)⟶C(g)
o 2A(g)+B(g)⟶C(g)

Answers

The reactions with a positive Δrxn are:

A(g) + B(g) ⟶ 3C(g)

A(s) + B(s) ⟶ C(g)

What is (Δrxn) of a reaction?

The entropy change (Δrxn) of a reaction indicates the change in the degree of randomness or disorder of the system during the reaction. If the number of product molecules is greater than the number of reactant molecules, the disorder of the system usually increases, resulting in a positive Δrxn. Therefore, we can determine the answer by analyzing the stoichiometry of each reaction:

A(g) + B(g) ⟶ C(g)

In this reaction, the number of product molecules is less than the number of reactant molecules, so the disorder of the system decreases. Therefore, this reaction has a negative Δrxn.

A(g) + B(g) ⟶ 3C(g)

In this reaction, the number of product molecules is greater than the number of reactant molecules, so the disorder of the system increases. Therefore, this reaction has a positive Δrxn.

A(s) + B(s) ⟶ C(g)

In this reaction, the solid reactants are combining to form a gaseous product. The disorder of the system is expected to increase, resulting in a positive Δrxn.

2A(g) + B(g) ⟶ C(g)

In this reaction, the number of product molecules is less than the number of reactant molecules, so the disorder of the system decreases. Therefore, this reaction has a negative Δ rxn.

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10. What is the molality of a solution
containing 288 g of calcium chloride
dissolved in 2.04 kg of water?

Answers

The choice of solution has a concentration of 1.144 mol/kg molality.

What exactly are molality and molarity?

Molarity corresponds to the moles of solvent divided by the amount of solution in litres, whereas molality is equal with the moles of solvent divided by the quantity of solvent in kilogrammes.

Is one molarity the same as one molality?

Since 1 mole of solute is present in 1 litre for the solution, which contains both the solute and the solvent, 1 molar aqueous solutions are more concentrated than one decays aqueous solutions.

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What is true of spontaneous reactions?
O They are indicated by a negative change in Gibbs free energy.
O They have a positive value of AS.
O They are instantaneous.
O They always release heat.

Help 20pts

Answers

1. They are indicated by a negative change in Gibbs free energy.

Explanation: Spontaneous reactions are those that occur without any external input of energy. A negative change in Gibbs free energy (ΔG) indicates that a reaction is spontaneous. The other options do not always hold true for spontaneous reactions. The value of entropy change (ΔS) can be positive or negative, spontaneous reactions are not necessarily instantaneous, and they do not always release heat.

what is the amount of power produced if 35Nm of work is done in 5 seconds

Answers

Answer:

70 watts

Explanation:

Which of these pairs of atoms would experience a polar covalent bond?


Cl and Cl

K and Br

P and S

C and O

Answers

C and O since their electronegativity differs by quite a lot

Draw both enantiomers of the following compound​

Answers

Enantiomers rotate the plane of polarized light in opposite directions, and this property is used to distinguish between them in a process called optical rotation.

What are the enantiomers of a compound?

Enantiomers are pairs of molecules that are non-superimposable mirror images of each other.

They are isomers, meaning they have the same molecular formula and connectivity but differ in their three-dimensional arrangement of atoms in space.

Enantiomers exhibit identical physical and chemical properties, except for their interaction with plane-polarized light (a type of light that oscillates in a single plane).

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sample of gas in a balloon has an initial temperature of 42 ∘C
and a volume of 1.47×103 L
. If the temperature changes to 94 ∘C
, and there is no change of pressure or amount of gas, what is the new volume, V2
, of the gas?

Answers

The new volume [tex]V_{2}[/tex]) of the gas is approximately 1710 L when the temperature changes from 42 ∘C to 94 ∘C, assuming no change in pressure or amount of gas.

What is Temperature?

Temperature is a measure of the average kinetic energy of the particles in a substance, such as a gas, liquid, or solid. It is commonly measured in Celsius (°C), Fahrenheit (°F), or Kelvin (K) scales. Temperature determines the direction of heat transfer, which is the movement of energy between substances due to a temperature difference.

To use the ideal gas law, we need to convert the temperatures to Kelvin by adding 273.15 to each:

[tex]T_{1}[/tex] = 42 + 273.15 = 315.15 K

[tex]T_{2}[/tex]= 94 + 273.15 = 367.15 K

Since the pressure, amount of gas, and ideal gas constant remain constant in this problem, we can set up the following ratio:

([tex]V_{1}[/tex] / [tex]T_{1}[/tex]) = ([tex]V_{2}[/tex]/ [tex]T_{2}[/tex])

Plugging in the values:

(1.47 ×[tex]10^{3}[/tex]L / 315.15 K) = ([tex]V_{2}[/tex] / 367.15 K)

Now we can solve for [tex]V_{2}[/tex]:

[tex]V_{2}[/tex] = 1.47×[tex]10^{3}[/tex] L * 367.15 K / 315.15 K

[tex]V_{2}[/tex]≈ 1710 L (rounded to three significant figures)

Therefore, the new volume (V2) of the gas is approximately 1710 L when the temperature changes from 42 ∘C to 94 ∘C, assuming no change in pressure or amount of gas.

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6. What is the pH of a 0.25 M solution of NH4Cl? [Kb(NH3) = 1.8  10–5

Answers

The Ammonium Chloride solution at 0.25 M has a pH of 2.67.

Why is the pH of Ammonium Chloride below 7?

As a result, the weak basic (Chlorine) in the solution is overpowered by the conjugate acid (Ammonium cation), making the solution mildly acidic. According to the equation pH =log[Hydrogen ion], an acidic solution has a pH lower than 7. Aqueous ammonium chloride solution has a pH that is less than 7.

Ammonium cation + Water ⇌ Nitrogen trihydride + Hydronium ion

Kb = [Nitrogen trihydride][Hydronium ion] / [Ammonium cation]

[Nitrogen trihydride] = [Hydronium ion] = x

[Ammonium cation] = 0.25 - x

Kb = [Nitrogen trihydride][Hydronium ion] / [Ammonium cation]

1.8 × 10–5 = x² / (0.25 - x)

1.8 × 10–5 = x² / 0.25

x² = 4.5 × 10–6

x = 2.12 × 10–3

pH = -log[Hydronium ion] = -log(2.12 × 10–3) = 2.67

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1-A tennis ball travelling at a speed of 46 m/s with a mass of 58 g. Calculate its kinetic energy Ek=0.5mv2

2-A plane at a speed of 255 m/s with a mass of 2.15 × 105 kg. calculate its kinetic energy

3-A hot air balloon with a kinetic energy of 76 550 J and a mass of 1890 kg. Calculate its velocity

Answers

The tennis ball has a kinetic energy of around 56.8 J. The aircraft has a kinetic energy of around 4.43 x 10⁹ J. The hot air balloon travels at a speed of around 9.0 m/s.

A 750 kilogramme automobile travelling at a speed of 50.0 km/h has how much kinetic energy?

How much effort must be put into slowing down a 750 kg automobile from 100 km/h to 50 km/h. We know that the of this automobile at 50.0 km/h is 72,300 Joules from the last example problem.

Ek = 0.5 x 0.058 kg x (46 m/s)²

Ek = 0.5 x 0.058 kg x 2116 m²/s²

Ek = 56.8468 J

Ek = 0.5mv²

Ek = 0.5 x 2.15 x 10⁵ kg x (255 m/s)²

Ek = 0.5 x 2.15 x 10⁵ kg x 65025 m²/s²

Ek = 4.433 x 10⁹ J

Ek = 0.5mv²

v = √(2Ek/m)

v = √(2 x 76550 J / 1890 kg)

v = √(81.011 J/kg)

v = 9.0 m/s (approx.)

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What is the molar concentration of Na+ ions in 0.0300 M solutions of the following sodium salts in water?

NaBr:
Na2SO4:
Na3PO4

Answers

NaBr is 0.0300 because the dissociation of is Na + br
Na2SO4 has 2na so 0.0300*2=0.0600
Na3PO4 has 3na so 0.0300*3=0.0900

Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Refer to the ΔG°f values. 2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g)

Answers

According to the question the standard change in Gibbs free energy is 2818.4 kJ/mol.

What is energy?

The capacity to perform work is energy. It is a characteristic of all matter and can assume many different shapes. It exists in a variety of shapes, including those of light, heat, chemical, electrical, mechanical, and nuclear. Energy is the ability to accomplish work and is measured in joules, which are equivalent to the amount of work completed when one newton of force is applied over a one metre distance.

The following equation can be used to get the reaction's standard change in Gibbs free energy (ΔG°) at 25°C:

ΔG° = [4 ΔG°f ([tex]Co_2[/tex]) + 6 ΔG°f ([tex]H_2o[/tex])] - [2 ΔG°f ([tex]C_2H_6[/tex]) + 7 ΔG°f ([tex]o_2[/tex])]

At 25°C, ΔG°f ([tex]Co_2[/tex]) = -393.5 kJ/mol, ΔG°f ([tex]H_2o[/tex]) = -237.2 kJ/mol, ΔG°f ([tex]C_2H_6[/tex]) = -85.2 kJ/mol, and ΔG°f ([tex]o_2[/tex]) = 0 kJ/mol.

As a result, the typical variation in Gibbs free energy is:

ΔG° = [-393.5 kJ/mol × 4] + [-237.2 kJ/mol × 6] - [-85.2 kJ/mol × 2] - [0 kJ/mol × 7]

ΔG° = -2818.4 kJ/mol.

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2818.4 kJ/mol is  the standard change in Gibbs free energy for the reaction at 25 °C.

What does the name Gibbs free energy mean?

Because it is readily accessible at all times, Gibb's free energy is known as free energy. If necessary, the reaction can obtain this energy without exerting any effort. Enthalpy and the system's product of temperature and entropy are added to determine the change in Gibb's free energy.

Enthalpy and entropy are combined into a single quantity known as Gibbs free energy, or G. The product of the system's temperature and entropy, added to the enthalpy, equals the change in free energy, or G.

2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g)

ΔG° = [4 ΔG°f (CO2) + 6 ΔG°f (H2O)] - [2 ΔG°f (C2H6) + 7 ΔG°f (O2)]

At 25°C, ΔG°f (CO2) = -393.5 kJ/mol,

ΔG°f (H2O) = -237.2 kJ/mol,

ΔG°f (C2H6) = -85.2 kJ/mol,

and ΔG°f (O2) = 0 kJ/mol.

ΔG° = [-393.5 kJ/mol × 4] + [-237.2 kJ/mol × 6] - [-85.2 kJ/mol × 2] - [0 kJ/mol × 7] = -2818.4 kJ/mol.

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What volume does 0.20 g methane gas (CH4) occupy at 312 K and 2.00 atm?
• Your answer should include two significant figures (round your answer to two decimal places).

Answers

0.20 g of methane gas at 312 K and 2.00 atm occupies a volume of 0.13 L (rounded to two significant figures).

What is volume?

To solve this problem, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas:

PV = nRT

where P is the pressure in atmospheres (atm), V is the volume in liters (L), n is the number of moles of gas, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin (K).

First, we need to calculate the number of moles of methane gas:

n = m/MW

where m is the mass of the gas (0.20 g) and MW is the molecular weight of methane (16.04 g/mol).

n = 0.20 g / 16.04 g/mol = 0.0125 mol

Next, we can rearrange the ideal gas law to solve for the volume:

V = nRT/P

Plugging in the values we have:

V = (0.0125 mol)(0.0821 L·atm/mol·K)(312 K)/(2.00 atm)

V = 0.128 L

Therefore, 0.20 g of methane gas at 312 K and 2.00 atm occupies a volume of 0.13 L (rounded to two significant figures).

What is molecular weight ?

Molecular weight, also known as molecular mass, is the mass of a molecule, which is the sum of the masses of all the atoms in the molecule. It is typically expressed in atomic mass units (amu) or in grams per mole (g/mol). The molecular weight is an important property of a substance in chemistry, as it is used to calculate various properties such as the molar mass, molar volume, and stoichiometric relationships in chemical reactions.

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Complete question is:  0.13 L volume does 0.20 g methane gas (CH4) occupy at 312 K and 2.00 atm.

How many grams of Aluminum Sulfate are produced when 4 g of Aluminum Nitrate react with 3 g of Sodium Sulfate?

Al(NO3)3 + Na2SO4 ---------> Al2(SO4)3 + NaNO3

Answers

3.21 grams of Aluminum Sulfate are got when 4 g of Aluminum Nitrate reacts chemcially with 3 g of Sodium Sulfate.

WHat is the balanced equation for this reaction? How many grams of Aluminum Sulfate are produced?

The equation given is not balanced. Thus,  when balanced the equation becomes:

2 Al(NO₃)₃ + 3 Na₂SO₄ → Al₂(SO₄)₃ + 6 NaNO₃

The molar mass of Al(NO₃)₃ is:

Al(NO₃)₃ = 1(Al) + 3(N) + 9(O) = 213 g/mol

The molar mass of Na₂SO₄ is:

Na₂SO₄ = 2(Na) + 1(S) + 4(O) = 142 g/mol

From the balanced equation, we can see that 2 moles of Al(NO₃)₃ react with 3 moles of Na2SO4 to produce 1 mole of Al₂(SO₄)₃. Therefore, we can calculate the number of moles of Al(NO₃)₃ and Na₂SO₄ that react:

Number of moles of Al(NO₃)₃ = 4 g / 213 g/mol = 0.0188 mol

Number of moles of Na₂SO₄ = 3 g / 142 g/mol = 0.0211 mol

From the balanced equation, we can see that 2 moles of Al(NO₃)₃ produce 1 mole of Al₂(SO₄)₃. Therefore, the number of moles of Al₂(SO₄)₃ produced is:

Number of moles of Al₂(SO₄)₃ = 0.0188 mol / 2 * 1 = 0.0094 mol

The molar mass of Aluminum Sulfate (Al₂(SO₄)₃) is:

Al₂(SO₄)₃ = 2(Al) + 3(S) + 12(O) = 342 g/mol

Therefore, the mass of Aluminum Sulfate produced is:

Mass of Al₂(SO₄)₃ = Number of moles of Al₂(SO₄)₃ * Molar mass of Al₂(SO₄)₃

= 0.0094 mol * 342 g/mol

= 3.21 g

Hence, 3.21 grams of Aluminum Sulfate are liberated when 4 g of Aluminum Nitrate change state with 3 g of Sodium Sulfate.

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what volume of SO3 would be produced by complete reaction of 100cm3 of HO2 with O2?

Answers

The volume of [tex]SO_{3}[/tex] would be produced by complete reaction of 100cm3 of [tex]H_{2}O[/tex]with [tex]O_{2}[/tex] is at STP is 60.03L.

Volume

22.4 L divided by 2.68 moles per mole yields 60.03 L [tex]SO_{3}[/tex].

describing the elements contributing to the response,

[tex]2SO_{2(g)}+ O_{2} = 2SO_{3}[/tex]

In this instance, [tex]SO_{3}[/tex] and [tex]O_{2}[/tex] have a mole ratio of 2:1. Assume the reaction takes place at STP, where 1 mole of any gas has a volume of 22.4 L. Consequently, 30 [tex]dm^{3}[/tex]of [tex]O_{2}[/tex] (1 dm3 = 1 L) equals 30 L of [tex]O_{2}[/tex] and 30 L/22.4 L times 1 mole equals 1.34 moles of [tex]O_{2}[/tex].

According to stoichiometry, when 1.34 moles of [tex]O_{2}[/tex]are reacted with [tex]SO_{2}[/tex], 2.68 moles of [tex]SO_{3}[/tex] are created, or 2/1 x 1.34 moles of [tex]SO_{3}[/tex].

This means that the amount of [tex]SO_{3}[/tex]produced will be (2.68 moles/1 mole) x 22.4 L = 60.03 L [tex]SO_{3}[/tex].

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If a reaction is reversible, what are the relative amounts of reactant and product at the end of the reaction?

Answers

In a reversible reaction, the relative amounts of reactant and product at the end of the reaction depend on the reaction conditions such as temperature, pressure, and concentration of the reactants and products.

At equilibrium, the forward and reverse reactions occur at equal rates, and the concentrations of the reactants and products no longer change over time. The position of equilibrium, that is, the relative concentrations of reactants and products at equilibrium, is determined by the equilibrium constant (K), which is specific to each reversible reaction.

If the equilibrium constant (K) is greater than 1, the equilibrium favors the products, and at equilibrium, the concentration of products will be greater than the concentration of reactants. Conversely, if the equilibrium constant is less than 1, the equilibrium favors the reactants, and at equilibrium, the concentration of reactants will be greater than the concentration of products.

Therefore, the relative amounts of reactant and product at the end of a reversible reaction depend on the equilibrium constant (K) and the reaction conditions.

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The oxides SO2 and N2O5 will form what acids?

Answers

When SO2 dissolves in water, it forms sulfurous acid (H2SO3), which can be further ionized to form bisulfite ions (HSO3-) and sulfite ions (SO32-). The reaction can be represented as follows:

SO2 + H2O → H2SO3

N2O5, on the other hand, reacts with water to form nitric acid (HNO3), which is a strong acid. The reaction can be represented as follows:

N2O5 + H2O → 2HNO3

Therefore, SO2 forms sulfurous acid (H2SO3) and N2O5 forms nitric acid (HNO3) when they react with water.
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