the correct answer is "electron cloud"
Which of the following statements is the best description of the nature of light?
The nature of light is best described as a dualistic phenomenon, encompassing both wave-like and particle-like properties, as demonstrated by its behavior in various experimental contexts.
The nature of light is best described as a dualistic phenomenon, exhibiting properties of both particles and waves. This concept, known as wave-particle duality, arises from the observation that light behaves as both discrete particles, called photons, and as a wave-like disturbance in the electromagnetic field.
From a wave perspective, light exhibits characteristics such as diffraction, interference, and polarization. These phenomena suggest that light propagates as a wave, with properties such as wavelength, frequency, and amplitude. The wave model successfully explains various optical phenomena, including the bending of light around obstacles and the formation of colorful interference patterns.
On the other hand, light also displays particle-like behavior. This is evident in the photoelectric effect, where light transfers discrete amounts of energy to electrons, behaving as discrete particles called photons. The energy of each photon is directly proportional to its frequency, as described by Max Planck's quantum theory.
Moreover, the behavior of light can be further understood through the framework of quantum mechanics, where photons are described by wavefunctions and exhibit probabilistic behavior. This probabilistic nature is captured by the wave-particle duality concept, which acknowledges that light can exhibit wave-like or particle-like characteristics depending on the experimental setup.
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satellites equipped with ultraviolet telescopes gather data about galaxies .
TRUE OR FALSE?
Answer:
True.
Explanation:
Here is an example: Hubble Space Telescope's launch in 1990 sped humanity to one of its greatest advances in that journey. Hubble is a telescope that orbits Earth. Its position above the atmosphere, which distorts and blocks the light that reaches our planet, gives it a view of the universe that typically far surpasses that of ground-based telescopes.
Hubble is one of NASA's most successful and long-lasting science missions. It has beamed hundreds of thousands of images back to Earth, shedding light on many of the great mysteries of astronomy. Its gaze has helped determine the age of the universe, the identity of quasars, and the existence of dark energy.
11.16 (a| Which is generally stronger; intermolecular tions Or intramolecular interactions? (b) intetac Which kinds of interactions are broken when a liquid is hey 'gas? converted toa
Intermolecular interactions are generally weaker than intramolecular interactions. When a liquid is converted to a gas, intermolecular interactions are broken.
Intermolecular interactions refer to the forces of attraction between molecules, while intramolecular interactions are the forces holding atoms within a molecule together. Intramolecular interactions, such as covalent or ionic bonds, are generally stronger because they involve the sharing or transfer of electrons between atoms.
On the other hand, intermolecular interactions, such as van der Waals forces (London dispersion forces, dipole-dipole interactions, and hydrogen bonding), are weaker in comparison. These interactions occur between neighboring molecules and are responsible for determining many physical properties of substances, such as boiling points, melting points, and solubilities.
When a liquid is converted to a gas, the intermolecular interactions between the molecules need to be overcome. This requires an input of energy to break these intermolecular forces, allowing the molecules to move freely and form a gas. The energy provided, typically in the form of heat, increases the kinetic energy of the molecules, causing them to overcome the attractive forces and transition into the gaseous state.
In summary, intramolecular interactions are generally stronger than intermolecular interactions. When a liquid is converted to a gas, the intermolecular interactions are broken as the molecules gain enough energy to overcome these forces and transition to the gaseous state.
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Which compound forms a powerful acid and also contains a halogen?
Answer:
B)HBr forms a powerful acid
Explanation:
The compound that forms a powerful acid and also contains a halogen is HBr. The correct option is b.
What are halogens?Halogens are the elements that are present in group 7 A. There are five elements in this group. These elements are fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At) elements in the periodic table.
The compounds that are given are H₂S, HBr, Li₂O, and LiBr. Every compound contains a halogen, but not every compound is a powerful acid.
The acid which is strongest has the ability to dissociate fully into protons. So out of these, the strongest acid is HBr. It is a colorless gas, and reducing agent, and it also acts as a catalyst. It is a powerful acid and is formed by dissolving in water.
Thus, the correct option is b, HBr.
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The question is incomplete. Your most probably complete question is given below:
H₂S
HBr
Li₂O
LiBr
the concentration of ammonia increases from 0.257 m to 0.815 m in 15.0 min. calculate the average rate of reaction over this time interval'
The average rate of reaction is the change in the concentration of reactants or products over a specified time interval. The average rate of reaction can be calculated from the initial and final concentrations of the reactants or products. To find the average rate of reaction between two concentrations, the formula is:
Average rate of reaction = Δ concentration / Δ timeIn the given problem, the concentration of ammonia increases from 0.257 m to 0.815 m in 15.0 min. To calculate the average rate of reaction over this time interval, we can use the above formula as follows:Δ concentration = (0.815 - 0.257) m = 0.558 mΔ time = 15.0 minAverage rate of reaction = Δ concentration / Δ time= 0.558 m / 15.0 min= 0.0372 m/minTherefore, the average rate of reaction over this time interval is 0.0372 m/min.
The rate of a chemical reaction is defined as the change in concentration of a reactant or product with respect to time. The rate of reaction is expressed in units of concentration per unit time, typically moles per liter per second (mol/L/s). The average rate of reaction is the change in concentration of reactants or products over a specified time interval. This is calculated by finding the slope of the concentration versus time graph during the specified time interval. If the reaction rate is constant over the specified time interval, the average rate of reaction will be equal to the instantaneous rate of reaction at any point in time during that interval.In the given problem, the concentration of ammonia increases from 0.257 m to 0.815 m in 15.0 min. The average rate of reaction over this time interval can be calculated using the formula:Average rate of reaction = Δ concentration / Δ timewhere Δ concentration is the change in concentration of ammonia, and Δ time is the time interval over which the concentration changes. In this case, Δ concentration = (0.815 - 0.257) m = 0.558 m and Δ time = 15.0 min. Substituting these values into the formula, we get:Average rate of reaction = Δ concentration / Δ time= 0.558 m / 15.0 min= 0.0372 m/minTherefore, the average rate of reaction over this time interval is 0.0372 m/min.
The average rate of reaction can be calculated from the change in the concentration of reactants or products over a specified time interval. In this problem, the average rate of reaction was calculated using the formula Δ concentration / Δ time, where Δ concentration was the change in concentration of ammonia and Δ time was the time interval over which the concentration changed. The average rate of reaction was found to be 0.0372 m/min.
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Which diagram illustrates that matter is always conserved during a chemical reaction?
A
B
C
D
Answer:
the photography is the C) is the correct
According to conservation of mass, the total mass in a chemical reaction is always conserved. Thus atoms lost or gained. In diagram D the number of atoms in the reactant side is equal to the number of atoms in the product side. Thus option D is correct.
What is mass conservation?Mass conservation is same as the law of conservation of energy. Thus total mass of a system is conserved. Therefore, mass can neither be created nor be destroyed.
According to mass conservation, for a chemical reaction, mass in the reactant side will be equal to the mass in the product side. Hence, no mass new atoms are created or existing atoms are lost.
The total number of atoms or molecules in the reactant side will be equal to total number of atoms in the product side in a balanced reaction, where all the elements are given in perfect stoichiometric proportions.
Only diagram D shows equal number of atoms in product side and reactant side and thus it is correct according to law of conservation of mass. Hence, option D is correct.
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the half-life of barium-131 is 12.0 days. how many grams of 131ba remain after 60.0 days if the initial 131ba sample had a mass of 10.0 g?
As per the given question, this means that 0.156 grams of 131Ba remain after 60.0 days if the initial 131Ba sample had a mass of 10.0 g.
In order to calculate the number of grams of 131Ba remaining after 60.0 days, we must first determine the number of half-lives that have passed during this period.
The time period divided by the half-life will give the number of half-lives that elapsed during this time.
(60.0 days)/(12.0 days/half-life)
= 5.00 half-lives
After that, we will use the fact that after each half-life has elapsed, the quantity of the original material is divided by 2. Therefore, after 5 half-lives have passed, the amount remaining is
10.0 g × (1/2)5 = 0.156 g.
This means that 0.156 grams of 131Ba remain after 60.0 days if the initial 131Ba sample had a mass of 10.0 g.
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Calculate the solubility of mg(oh)2 in 0. 50m nh4cl
The solubility of Mg(OH)2 in 0.50 M NH4Cl is calculated below: What is solubility? Solubility is the amount of solute that dissolves in a solvent at a specific temperature and pressure. Solubility is typically expressed as grams per litre (g/L) or moles per litre (mol/L).
Solubility is a chemical property that varies with temperature, pressure, and the presence of other substances (solutes) in a solution. What is Mg(OH)2? Magnesium hydroxide is a white solid that is odorless and non-volatile. It has a low solubility in water (12 mg/L at 25°C), making it a weak base that is primarily used as an antacid and laxative. Calculation: The reaction for Mg(OH)2 dissolving in water is: Mg(OH)2(s) ⇌ Mg2+(aq) + 2OH-(aq)Ksp = [Mg2+][OH-]2We'll need to calculate the concentrations of Mg2+ and OH- ions to calculate the solubility of Mg(OH)2 in 0.50 M NH4Cl. First, let's write the dissociation equation for NH4Cl:NH4Cl(s) ⇌ NH4+(aq) + Cl-(aq).
Since NH4Cl is a strong electrolyte, it completely dissociates into NH4+ and Cl- ions. When NH4+ ions interact with OH- ions from the Mg(OH)2 dissociation equation, they produce NH3 and water:NH4+(aq) + OH-(aq) ⇌ NH3(aq) + H2O(l). This reaction depletes the concentration of OH- ions in the solution, making it more difficult for Mg(OH)2 to dissolve. Because NH3 is a weak base, it does not significantly impact the concentration of OH- ions in the solution. To calculate the solubility of Mg(OH)2 in 0.50 M NH4Cl, we must first determine the concentration of OH- ions in the solution. To do so, we must first find the concentration of NH4+ ions in the solution.
Using the dissociation equation for NH4Cl, we know that [NH4+] = [Cl-] = 0.50 M (since NH4Cl is a strong electrolyte, it completely dissociates into NH4+ and Cl- ions).Using the equilibrium constant expression for the NH3 reaction, we can write the following expression for [OH-]:Kb = [NH3][H2O]/[NH4+] = 1.8 × 10-5pOH = 1/2(pKb - log([NH3]/[NH4+])) = 1/2(4.74 - log(0.50/0.50)) = 2.37[OH-] = 10-pOH = 4.47 × 10-3 M. Solving for [Mg2+] using the Ksp expression for Mg(OH)2 and the concentration of OH- ions, we obtain:[Mg2+] = Ksp/[OH-]2 = (5.6 × 10-12)/(4.47 × 10-3)2 = 2.47 × 10-7 M. Therefore, the solubility of Mg(OH)2 in 0.50 M NH4Cl is 2.47 × 10-7 M.
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why is 1,2-dichloroethane a better solvent for this extraction than water?
1,2-dichloroethane is a better solvent for this extraction than water due to its non-polarity and ability to dissolve nonpolar compounds.
The choice of solvent for an extraction process depends on the nature of the substances involved. In this case, if the compound being extracted is nonpolar, using a nonpolar solvent like 1,2-dichloroethane would be advantageous. Water, on the other hand, is a polar solvent.
To further support this claim, we can look at the solubility parameters of 1,2-dichloroethane and water. The solubility parameter measures the compatibility between solvents and solutes. The solubility parameter of 1,2-dichloroethane is around 9.2 (cal/cm^3)^0.5, while water has a solubility parameter of around 23.1 (cal/cm^3)^0.5. The lower solubility parameter of 1,2-dichloroethane suggests better solubility for nonpolar compounds compared to water.
In summary, 1,2-dichloroethane is a better solvent for this extraction than water due to its non-polarity and better solubility for nonpolar compounds. The choice of solvent should be based on the nature of the substances involved, and in this case, a nonpolar solvent is more suitable.
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☆please help due in 1 hour!☆
How is the isotope of hydrogen different from the non isotopic form of hydrogen?
how many moles of aluminum oxide are produced according to the reaction below given that you start with 40.0 grams of al and 19.0 grams of o2? reaction: 4al 3o2 --> 2al2o3
approximately 0.396 moles of aluminum oxide (Al2O3) are produced in the given reaction.
To determine the number of moles of aluminum oxide produced, we need to calculate the moles of aluminum (Al) and oxygen (O2) first, and then use the stoichiometry of the reaction to determine the moles of aluminum oxide (Al2O3).
Given:
Mass of aluminum (Al) = 40.0 grams
Mass of oxygen (O2) = 19.0 grams
Step 1: Convert the masses to moles using the molar masses.
Molar mass of Al = 26.98 g/mol
Molar mass of O2 = 32.00 g/mol
Moles of Al = Mass of Al / Molar mass of Al
= 40.0 g / 26.98 g/mol
≈ 1.48 mol
Moles of O2 = Mass of O2 / Molar mass of O2
= 19.0 g / 32.00 g/mol
≈ 0.594 mol
Step 2: Determine the limiting reactant.
To determine the limiting reactant, we compare the moles of Al and O2 based on their stoichiometric coefficients in the balanced equation.
From the balanced equation:
4 mol Al : 3 mol O2
Moles ratio Al:O2 = 4 mol Al / 3 mol O2
≈ 1.33
Since the moles ratio of Al to O2 is greater than 1, it indicates that there are more moles of Al than O2. Therefore, O2 is the limiting reactant.
Step 3: Calculate the moles of Al2O3 produced.
Based on the stoichiometry of the balanced equation:
4 mol Al produces 2 mol Al2O3
Using the moles of O2 as the limiting reactant, we can determine the moles of Al2O3.
Moles of Al2O3 = (Moles of O2) * (2 mol Al2O3 / 3 mol O2)
= 0.594 mol * (2/3)
≈ 0.396 mol
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molality of 0.465 mol/kg. when the temperature of this solution is 100oc, what is its vapor pressure?
The vapor pressure of a solution can be calculated using the Raoult's law. Raoult's law is a law that states that the partial pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component multiplied by its mole fraction in the mixture.
This law is valid only for ideal mixtures, i.e., mixtures that obey Raoult's law themselves. Here, the given solution is an ideal mixture. The molality of the given solution is 0.465 mol/kg. The boiling point of a solvent is defined as the temperature at which its vapor pressure is equal to the external pressure. The given solution is an ideal solution, and its boiling point is higher than that of the pure solvent. The boiling point elevation depends on the molality of the solution and the nature of the solute.
The boiling point elevation, ΔTb, is given by: ΔTb = Kb x molality. Here, Kb is the molal boiling point elevation constant of the solvent. The boiling point of the solvent is T0. The boiling point of the solution, Tb, is given by: Tb = T0 + ΔTbUsing the above formulas, the vapor pressure of the solution can be calculated. At 100 °C, the vapor pressure of the pure solvent is given by the Antoine equation. The vapor pressure of the solution can be calculated using the Raoult's law: P = P0A XA + P0B XB Where, P0A and P0B are the vapor pressures of the pure solvent A and the solute B, respectively. XA and XB are the mole fractions of A and B, respectively. At the boiling point of the solution, P = P0A XA. Using the given data, we can find the vapor pressure of the solution. Therefore, the vapor pressure of the given solution is P = 0.11 atm at 100°C.
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Which of the following information is primarily obtained from infrared spectroscopy? Select one: O a. arrangement of carbon and hydrogen atoms in a compound b. molecular weight of a compound O c. any conjugated n system present in a compound O d. functional groups present in a compound e. all of these Check
Answer: A
Explanation:
need help 1-5 test please quick
The thing that occurs in a single, polar covalent bond c. Two atoms unequally share two electrons.
How to explain the informationThe thing that occurs in a triple, nonpolar covalent bond is b. Two atoms equally share six electrons.
The bond that requires the most energy to break the bond is c. Triple covalent bond.
A molecule of hydrogen monochloride is polar because d. The chlorine attracts the shared electrons more strongly than does the hydrogen atom.
Diatomic iodine (I) has a higher boiling point than diatomic bromine (Br₂) because diaton has a. Larger molecule.
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The Ksp of beryllium hydroxide, Be(OH)₂, is 6.92 x 10-22. Calculate the solubility of this compound in grams per liter. solubility: 5.57 X10-8 Incorrect
The solubility of beryllium hydroxide, Be(OH)₂, can be calculated using the given Ksp value of 6.92 x 10⁻²².
Solubility is the maximum amount of a compound that can dissolve in a given solvent. To find the solubility in grams per liter (g/L), we use the Ksp equation and consider the concentration of Be(OH)₂ in moles per liter.
The Ksp expression becomes 4x³, where x represents the concentration of OH⁻ ions. Solving for x gives approximately 1.78 x 10⁻⁸ mol/L.
Multiplying this by the molar mass of Be(OH)₂ (43.03 g/mol) yields a solubility of around 7.66 x 10⁻⁷ g/L.
Therefore, the solubility of beryllium hydroxide is approximately 7.66 x 10⁻⁷ grams per liter.
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if the rate appearance of O2 in the reaction 2O3g-->3O2 is 0.25M/s over the first 5.5s how much oxygen will form during this time
During the first 5.5 seconds, a total of 1.375 moles of oxygen (O2) will form in the given reaction.
The balanced equation for the reaction is 2O3(g) → 3O2(g), which indicates that 2 moles of ozone (O3) produce 3 moles of oxygen gas (O2).
The rate of appearance of O2 is given as 0.25 M/s, which means that 0.25 moles of O2 are formed per second.
To calculate the amount of oxygen formed during the first 5.5 seconds, we can multiply the rate by the time:
Amount of O2 formed = rate × time = 0.25 mol/s × 5.5 s = 1.375 moles
Therefore, during the first 5.5 seconds, a total of 1.375 moles of oxygen will form in the reaction.
Note: The given rate of appearance is in moles per second, so the result is also in moles.
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concentrated sulfuric acid is 98.0% h2so4 by mass and has a density of 1.83 g/ml. calculate the molarity of concentrated sulfuric acid. .01 m calculate the molality of concentrated sulfuric acid. m
As per the given question, the molarity of concentrated sulfuric acid is 18.288 M and the molality of concentrated sulfuric acid is 1.826 m
According to the definition, the molarity (M) of a solution is defined as the number of moles of solute (n) divided by the volume of the solution in liters (V).
Molarity = (Number of moles of solute) ÷ (Volume of the solution in liters)
A solution that is 98% pure by mass contains 98 g of H2SO4 in 100 g of solution. As a result, the amount of H2SO4 in 1 L of solution will be: (0.98) × (1830 g/L)
= 1793.4 g/L
To calculate the number of moles of H2SO4 in 1 L of solution, use the molecular weight of H2SO4, which is 98.08 g/mol.
Number of moles of H2SO4 = (Mass of H2SO4) ÷ (Molecular weight of H2SO4)
Number of moles of H2SO4 = (1793.4 g) ÷ (98.08 g/mol)
Number of moles of H2SO4 = 18.288 mol/L
The molarity of concentrated sulfuric acid is 18.288 M. The molality of concentrated sulfuric acidMolality is defined as the number of moles of solute (n) per kilogram of solvent (m).
Molality = (Number of moles of solute) ÷ (Mass of solvent in kilograms)
One kilogram of sulfuric acid contains (98/1000) 1000 g = 98 g of H2SO4.
To calculate the number of moles of H2SO4 in one kilogram of solvent, use the molecular weight of H2SO4.
Number of moles of H2SO4 = (Mass of H2SO4) ÷ (Molecular weight of H2SO4)
Number of moles of H2SO4 = (98 g) ÷ (98.08 g/mol)
Number of moles of H2SO4 = 0.9979 mol
One liter of sulfuric acid has a mass of 1.83 kg, so one kilogram of sulfuric acid is 1/1.83 L = 0.546 kg.
The molecular weight of concentrated sulfuric acid is:
Molality = (Number of moles of solute) ÷ (Mass of solvent in kilograms)
Molality = (0.9979 mol) ÷ (0.546 kg)
Molality = 1.826 m
Thus, the molarity of concentrated sulfuric acid is 18.288 M and the molality of concentrated sulfuric acid is 1.826 m.
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75 mL of water is added to a 360 mL solution of acetic acid with a concentration of 0.87 M. Determine the molarity of the new solution. 1.05 M O 10.5 M 0 4.2 M O 0.72 M
The molarity of the new solution after adding 75 mL of water to the 360 mL solution of acetic acid with a concentration of 0.87 M is approximately 0.72 M.
To determine the molarity of the new solution after adding water to the acetic acid solution, we can use the equation:
M1V1 = M2V2
Where:
M1 = initial molarity of the acetic acid solution
V1 = initial volume of acetic acid solution
M2 = final molarity of the new solution
V2 = final volume of the new solution
M1 = 0.87 M
V1 = 360 mL
V2 = 360 mL + 75 mL = 435 mL
Substituting the values into the equation, we have:
(0.87 M)(360 mL) = M2(435 mL)
Solving for M2:
M2 = (0.87 M)(360 mL) / (435 mL)
M2 ≈ 0.72 M
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Please answer fast! The density of aluminum is 2.70 g/cm? The volume of a solid piece of aluminum is 1.50 cm? Find its mass.
Answer:
19.3 g/cm3
Explanation:
is the best answer
why is water an excellent solvent for most ionic compounds and polar covalent molecules but not for non-polar compounds?
Water is an excellent solvent for most ionic compounds and polar covalent molecules but not for non-polar compounds because of its content loaded with certain chemical properties that make it a highly effective solvent. Water molecules are polar, and due to their dipolar nature, the oxygen atom carries a negative charge while the hydrogen atoms carry a positive charge.
The polarity of the water molecule allows it to interact with and dissolve other polar and ionic substances.When an ionic compound is dissolved in water, the ions of the compound dissociate into individual charged species (cations and anions), and these charged species are solvated by water molecules. The polarity of the water molecule allows it to interact with the ions by attracting the positively charged ions to the negative end of the water molecule and vice versa.
The same is true for polar covalent molecules, which have a net dipole moment. Water molecules can interact with these molecules, forming a solvation layer around them. On the other hand, non-polar compounds lack a net dipole moment, so they don't interact with the water molecules. Instead, non-polar compounds interact with each other via van der Waals forces, making it more challenging for them to dissolve in water.
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Methanol, ethanol, and n-propanol are three common alcohols. When 1.00 g of each of these alcohols is burned in air, heat is liberated as shown by the following data: (a) methanol (CH3OH), –22.6 kJ/g; (b) ethanol (C2H5OH), –29.7 kJ/g; (c) n-propanol (C3H7OH), –33.4 kJ/g. Calculate the heats of combustion of these alcohols in kJ/mol.
The heat of combustion of n-propanol is approximately -0.555 kJ/mol.To calculate the heats of combustion of these alcohols in kJ/mol, we need to convert the given data from kJ/g to kJ/mol.
The molar masses of methanol, ethanol, and n-propanol are 32.04 g/mol, 46.07 g/mol, and 60.10 g/mol, respectively. By dividing the given heat of combustion values by the molar mass of each alcohol, we can determine the heats of combustion in kJ/mol.
(a) For methanol:
Heat of combustion = -22.6 kJ/g
Molar mass of methanol = 32.04 g/mol
Heat of combustion per mole of methanol = (-22.6 kJ/g) * (1 g/mol) / (32.04 g/mol) = -0.706 kJ/mol
Therefore, the heat of combustion of methanol is approximately -0.706 kJ/mol.
(b) For ethanol:
Heat of combustion = -29.7 kJ/g
Molar mass of ethanol = 46.07 g/mol
Heat of combustion per mole of ethanol = (-29.7 kJ/g) * (1 g/mol) / (46.07 g/mol) = -0.645 kJ/mol
Therefore, the heat of combustion of ethanol is approximately -0.645 kJ/mol.
(c) For n-propanol:
Heat of combustion = -33.4 kJ/g
Molar mass of n-propanol = 60.10 g/mol
Heat of combustion per mole of n-propanol = (-33.4 kJ/g) * (1 g/mol) / (60.10 g/mol) = -0.555 kJ/mol
In summary, the heats of combustion for methanol, ethanol, and n-propanol are approximately -0.706 kJ/mol, -0.645 kJ/mol, and -0.555 kJ/mol, respectively. These values represent the amount of heat released per mole of alcohol when burned in air.
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how many grams of nacl are needed to prepare 0.500 l of a 4.00 m nacl solution?select one:a.2.00 grams naclb.4.00 grams naclc.117 grams nacld.58.5 grams nacl
To determine the number of grams of NaCl required to prepare a 0.5 L of 4.00 M NaCl solution, we need to use the following formula;M = (mol / L)mol = M × Lmol = 4.00 mol/L × 0.5 Lmol = 2 mol. We have determined that we need 2 moles of NaCl for this solution.
To convert moles to grams, we need to use the following formula;moles = mass / molar massmass = moles × molar massThe molar mass of NaCl is 58.44 g/mol. Therefore;mass = 2 mol × 58.44 g/mol = 116.88 g
From the calculation above, the number of grams of NaCl required to prepare 0.5 L of a 4.00 M NaCl solution is 116.88 grams. Therefore, the correct option is option (c) 117 grams NaCl.The formula to calculate molarity (M) is M = mol/L, and the formula to calculate mass is mass = moles × molar mass. We can use these two formulas to calculate the grams of NaCl required for this solution.The first step is to determine the number of moles required. We were given a 0.5 L of a 4.00 M NaCl solution. Therefore, we will use M = mol/L to determine the number of moles.M = (mol / L)4.00 M = mol / 0.5 Lmol = 4.00 M × 0.5 Lmol = 2 molThe second step is to convert the number of moles to grams by using the formula;mass = moles × molar massThe molar mass of NaCl is 58.44 g/mol.mass = 2 mol × 58.44 g/molmass = 116.88 gTherefore, the answer is option (c) 117 grams NaCl.
Therefore, the number of grams of NaCl required to prepare a 0.500 L of a 4.00 M NaCl solution is 116.88 g or 117 g.
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How many grams does 0.500 moles of CuBr weigh
Answer:
72 grams
Explanation:
n=m/mr
so
m=n*mr
0.500*144
=72 g
There are 71.725 grams of CuBr is present in 0.500 moles of CuBr. It is required to know the substance's molar mass in order to calculate its weight given its number of moles.
The atomic masses of copper (Cu) and bromine (Br) in the compound may be added to determine the molar mass of CuBr.
The atomic mass of Cu = 63.55 grams/mol, and
The atomic mass of Br = 79.90 grams/mol.
Molar mass of CuBr = (atomic mass of Cu) + (atomic mass of Br)
= 63.55 g/mol + 79.90 g/mol
= 143.45 g/mol
Now, find the weight of 0.500 moles of CuBr:
Weight of CuBr = Number of moles × Molar mass
= 0.500 moles × 143.45 g/mol
= 71.725 grams
Thus, 0.500 moles of CuBr weighs 71.725 grams.
Learn more about moles, here:
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True or False:
The vertical mixing rate in the stratosphere is larger than in
the troposphere.
Maricopa County (Arizona) is non-attainment for the Hazardous
Air Pollutant benzene.
A secondary NAAQS s
Answer:
true
Explanation:
36) What is the mass of a 4.259 g/cm substance which takes up 250.00 cm of space?
Answer:
The answer is 1064.75 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volumeFrom the question
volume of substance = 250 cm³
density = 4.259 g/cm³
We have
mass = 4.259 × 250
We have the final answer as
1064.75 gHope this helps you
I WILL GIVE THE BRAINLIEST
all i need to for these to be filled in and i have more pages Thank you.
please upload a clear picture
A block of concrete has a density of 9 kg/m^3 and a volume of 210 000 cm^3 What is its mass
Answer:
The answer is 1.89 kgExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volumeFrom the question
density = 9 kg/m³
1 cm³ = 0.000001 m³
210,000 cm³ = 0.21 m³
So we have
mass = 9 × 0.21
We have the final answer as
1.89 kgHope this helps you
(ik this isn’t chemistry) if i had a neutral atom of oxegyn and removed an electron from it, what kind of ion would i get?
1)anion
2)cation
3)dogion
4)mouseion
Answer:
Cation
Explanation:
I'm pretty sure the last two options are a joke, but electrons are negative so losing one gives a positive charge.
Hurry please!!! Lithospheric plates move because of the movement of the ___________________ under them.
a. lower mantle
b. asthenosphere
c. outer core
d. inner core
Answer:
A. Lower mantle
Explanation:
Answer:
lower mantle
Explanation:
True or False. A force is a push or pull exerted on an object.
Answer:
TRUE
Explanation:
remember newtons laws of motion. Every action has an equal and opposite reaction. LOL
Answer:
True.
Explanation:
