In parallel RLC circuits, the voltage is the same and is in-phase across all branches and is used as the main reference for calculations.
In a parallel RLC circuit, the current is determined by the resistance, inductance, and capacitance. The maximum current and the maximum voltage occur simultaneously because the voltage and current through the resistor are in phase. This is so that there is no phase shift between the voltage and the current caused by the resistance.
On the other hand, the voltage is 90 degrees behind the current passing through the capacitor, and the voltage is 90 degrees ahead of the current going through the inductor. As a result, the resistive current and voltage are in phase, which means that when the voltage is at its highest, the resistive current likewise reaches its peak and vice versa.
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Although frequently referred to a galvanized rigid conduit (GRC), the NEC® identifie thi wiring method a rigid metal conduit (RMC). Where trade ize 11/2 RMC i threaded (crewed wrenchtight) together between boxe or encloure, the maximum ditance permitted between trap (upport) i ___ feet. The ditance between the boxe for thi traight run of conduit i almot 200 feet
The National Electric Code (NEC) identifies rigid metal conduit (RMC) as a wiring method, even though it is often referred to as galvanized rigid conduit (GRC).
If 11/2 RMC is threaded (screwed wrench-tight) together between boxes or enclosures, the maximum distance allowed between supports is 130 feet. This straight run of the conduit is almost 200 feet, so it would require additional support to ensure proper electrical performance and safety.
When determining the proper support spacing for a straight run of conduit, it is important to consider factors such as the weight of the conduit, the conductors inside, and the number of bends in the conduit. Too few supports can create sagging and tension, which can damage the insulation of the conductors and potentially cause a short circuit.
Too many supports can be costly and difficult to install. Therefore, it is important to understand the proper support spacing requirements and follow the NEC guidelines.
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suppose you are on a strange planet and observe, at night, that the stars do not rise and set, but circle parallel to the horizon. next, you walk in a constant direction for 8000 km, and at your new location on the planet, you find that all stars rise straight up in the east and set straight down in the west, perpendicular to the horizon. how could you determine the circumference of the planet without any further observations? what is the circumference of the planet?
Answer:
Explanation:
2πr²
a student must conduct an experiment to verify the conservation of momentum. cart x and cart y travel toward each other and eventually collide, as shown in the figure. the student has access to the two carts, one mass balance, and two motion detectors. if the mass of each cart is known, how should the student arrange one or both motion detectors so that the student can collect enough information about the motion of the carts, in order to verify the conservation of momentum of the system?
The student should arrange the motion detectors in a way that allows them to measure the velocity of both carts before and after the collision.
The student could place one detector at the start of the collision and one at the end of the collision. This would allow them to measure the velocity of each cart before and after the collision. The mass of each cart can be measured using the mass balance.
With this information, the student can calculate the momentum of each cart before and after the collision and verify that the total momentum of the system is conserved.
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A geosynchronous moon appears to remain
over one spot on a planet similar to Earth
with a day the same length of time but with a
different density.
PART 1
If the moon has an orbital radius of
5.17 × 10⁷ m , find its speed in orbit.
The value of the gravitational constant is
6.67259 × 10⁻¹¹ N · m²
/kg² .
Answer in units of m/s. Answer in units of
m/s.
PART 2
What is the mass of the planet if the mass
of the moon is 2.4 × 10²⁰ kg. ?
Answer in units of kg. Answer in units of
kg.
(1) The orbital speed of the moon is 463.3 m/s.
(2) The mass of the planet is 2.055 x 10²² kg.
What is the speed of the Moon?
The orbital speed of the moon is calculated by applying the following equation as shown below.
v = √ ( GM / r )
where;
M is the mass of the moonr is the radius of the moonv = √ ( 6.67 x 10⁻¹¹ x 2.4 x 10²⁰ / 5.17 x 10⁷ )
v = 17.6 m/s
The orbital speed of the planet is calculated as;
V = 2πr / T
since the planet is similar to earth, period of one complete rotation = 24 hours.
radius of planet = radius of earth = 6,371 km = 6,371,000 m
V = ( 2π x 6371000) / ( 24 x 60 x 60 s )
V = 463.3 m/s
The mass of the planet is calculated as follows;
V = √(GM/r)
V² = ( GM/r )
M = ( V²r ) / ( G )
M = ( 463.3² x 6371000) / ( 6.67 x 10⁻¹¹ )
M = 2.055 x 10²² kg
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calculate the ratio of the mass of an electron to its rest mass coi 2a when it is moving with a kinetic energy of20 mev. (rest mass i / of electron= 0.51mev)
The ratio of the mass of an electron to its rest mass when it is moving with a kinetic energy of 20 MeV can be calculated using the equation of special relativity and assuming that the speed of the electron is much less than the speed of light. The result is that the mass of the electron is 39.22 times its rest mass.
The ratio of the mass of an electron to its rest mass can be calculated from its kinetic energy using the equation of special relativity, which states that the total energy of an object is equal to its rest mass multiplied by the square of the speed of light, plus its kinetic energy.
The rest mass of an electron is 0.51 MeV, so its total energy is given by:
[tex]E[/tex] = [tex]0.51 MeV*c^{2} + KE[/tex]
Where c is the speed of light, and KE is its kinetic energy.
Since the kinetic energy of the electron is 20 MeV, we have:
[tex]E = (0.51 MeV) * (c²) + 20 MeV[/tex]
And the total energy can be divided by the rest mass of the electron and the square of the speed of light to obtain the ratio of its mass to its rest mass:
[tex]m/m0[/tex] = [tex]\frac{E}{0.51 MeV * c^{2} }[/tex]
[tex]m/m0[/tex] = [tex]\frac{0.51 MeV*c^{2} + 20 MeV}{0.51 MeV }[/tex]
We can simplify the calculation by assuming that the speed of the electron is much less than the speed of light, so that we can ignore the term (0.51 MeV * c^2).
In that case, we have:
[tex]m/m0[/tex] = [tex]\frac{20MeV}{0.51MeV}[/tex]
[tex]m/m0 = 39.22[/tex]
So the ratio of the mass of an electron to its rest mass when it is moving with a kinetic energy of 20 MeV is 39.22.
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a 0.15 kg baseball is thrown with a speed of 46 m/s. it is hit striaght back at the pitcher with a speed of 78 m/s. what is the magnitude of the impulse exerted on the ball by the bat?
The impulse exerted on the ball by the bat is 4.8 Ns. The result is obtained by using the Impulse-Momentum Theorem.
What is Impulse-Momentum Theorem?The Impulse-Momentum Theorem states that impulse of an object equals to the change of the momentum. It can be expressed as
I = Δp
I = mΔv
Where
I = Impuls (Ns or kg m/s)Δp = change of momentum (Ns or kg m/s)m = mass of an object (kg)Δv = change of velocity (m/s)A baseball is thrown with
m = 0.15 kgv₀ = 46 m/sv₁ = 78 m/sFind the magnitude of the impulse exerted on the ball by the bat!
The impulse exerted by the bat is
I = mΔv
I = m(v₁ - v₀)
I = 0.15(78 - 46)
I = 0.15(32)
I = 4.8 Ns
Hence, the bat exerts the impulse of 4.8 Ns.
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A man of mass 60 kg runs up a flight of 30 steps in 40 seconds. If each step is 20 cm high, calculate the power of the man
Answer:
the answer is and would be 90w or 24w
Please help meeee i’m very confused
The amount of force is referred to as the magnitude of a force. Hence, option B is correct.
What is Force?A force is an action that has the ability to alter an object's motion. An object can be caused by a force, which can also accelerate an item. To describe force, a push or a pull, makes intuitive sense. Forces have had both direction and magnitude, since they are vector quantities. It is measured in newtons that use the SI system (N). The symbol for force is the letter F.An entity's net force equals the rate at which its momentum is changing over time, according to the original formulation of Newton's second law.Objects' velocities can be changed by the concepts of push, drag, and torque. Thrust causes an item to move faster, whereas torque allows an object to move slower. Each part of an extended body typically exerts forces on its adjacent sections; the internal mechanical stress in the body is the result of the distribution of these forces.To learn more about force refer
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A uniform line of charge with length 20.0 cm is along the x-axis, with its midpoint at x= 0. Its charge per length is +5.80 nC/m. A small sphere with charge -2.00 μC is located at x = 0, y = 5.00 cm. What is the magnitude of the force that the charged sphere exerts on the line of charge?
The magnitude of the force that the charged sphere exerts on the line of charge is zero.
What is electric force?Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so.
The the magnitude of the force is = kQ₁Q₂/r²
= (9×10⁹) × 2.00 × 10⁻⁶ × 5.80 × 10⁻⁹ × dl/x²
But these forces are equal and in opposite direction, the magnitude of the force that the charged sphere exerts on the line of charge is zero.
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1) if a quantity you calculated has units of a ∙ s, what is that quantity? a) capacitance b) charge c) potential d) resistance e) resistivity
if a quantity you calculated has units of a ∙ s, the quantity is a) capacitance.
Capacitance is the measure of a body's ability to store electric charge. The unit of capacitance is the Farad (F), which is defined as the amount of charge stored per volt of electric potential across a conductor.
Capacitance is directly proportional to the charge stored on a conductor and inversely proportional to the voltage applied to it. When a voltage is applied to a capacitor, it stores charge, and the capacitance of the capacitor determines the amount of charge that can be stored per unit of voltage.
This stored charge can then be used to perform work, such as powering an electronic circuit. In summary, capacitance is a measure of the ability of a material to store electric charge, and its units are Farads (F).
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which is not true about geothermal energy? it is only available in limited areas. it cannot be used for cooling. it can be locally depleted due to heavy use. ground source heat pumps require an additional source of energy.
The statement which is not correct regarding geothermal energy is that it can be locally depleted due to heavy use.
Geothermal energy is the energy in the form of heat, which is generated inside the earth. Temperature inside the earth increases at the rate of 25°C/km. When temperature reaches 700-1300°C, the rock becomes magma. This magma comes in the mantle or upper core layer.
Due to the high temperature magma heats up the attached rock and thereby water inside the permeable layers of the Earth. This warm water is utilized to run the turbine and generate electricity. It is a renewable source of energy which cannot be depleted by anyone. So the statement C is not true.
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nuclear power is an important source of energy around the world. some countries, such as france and ukraine, generate more than 50 50 percent of their electricity from nuclear power plants. however, generating electricity from nuclear power plants can lead to environmental problems. (a) describe one potential negative environmental consequence from using nuclear power.
One potential negative environmental consequence from using nuclear power is the risk of radioactive contamination from an accident or improper disposal of nuclear waste.
One potential negative environmental consequenceRadioactive materials released into the environment can cause long-term health problems such as cancer and birth defects.In addition, nuclear waste can take thousands of years to decay, leading to long-term storage and disposal issues.One potential negative environmental consequence from using nuclear power is the risk of nuclear radiation. Nuclear radiation is caused by the release of radioactive particles emitted during a nuclear reaction, such as those that occur in a nuclear power plant. These particles can be spread through the air, water and land. This radiation can be harmful to humans, animals, plants and the environment as a whole.In addition to causing direct health risks to those exposed to it, nuclear radiation can also cause long-term contamination of the environment. This can include contamination of soil, water, and air by radioactive particles, as well as contamination of the food chain by bioaccumulation. As a result, this can lead to increased risk of cancer and other diseases, as well as reduced fertility in humans and animals. In some cases, these effects can last for generations.To learn more about One potential negative environmental consequence refer to:
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1.1.3-4) Use the Energy-Interaction Model to explain whether the following statement is true or false: "A quantity of ice at 0°C must contain less total energy than the same quantity of water at 0°C. 1.1.3-5) According to the definition of heat in your textbook (pages 8 & 16), can an energy system contain a certain amount of heat? Explain.Previous question
The Energy-Interaction Model states that energy can be transferred between systems as heat or work, but the total energy of a closed system remains constant.
Therefore, the statement "A quantity of ice at 0°C must contain less total energy than the same quantity of water at 0°C" is false. Heat is a form of energy transfer between systems and is not a property of a system in isolation. A system can contain a certain amount of heat energy, but this energy is not necessarily the total energy of the system, as the total energy of a system also includes potential and kinetic energy. In the case of a system of ice and water at 0°C, the ice has a lower temperature and therefore contains less thermal energy (heat energy) compared to the water. However, this does not necessarily mean that the ice contains less total energy, as the ice also has potential energy due to its elevated height above the reference level, for example. Therefore, the total energy of the ice and the water at 0°C would be the same, according to the Energy-Interaction Model.
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john has 200 joules of gravitational potential energy when he is standing still on a diving board. john jumps off the diving board. what is his gravitational potential energy when he is halfway to the water? (answer 100j)
His gravitational potential energy when he is halfway to the water is 100 joules.
What is potential energy?Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.
The gravitational potential energy of an item, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field are examples of potential energy.
Initial potential energy of John is 200 joules.
Hence, his gravitational potential energy when he is halfway to the water is = (200/2) joules = 100 joules.
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a car travels 95 km to the north at 70.0 km/h, then turns around and travels 21.9 km at 80.0 km/h. what is the difference between the average speed and the average velocity on this trip?
The average speed of the car on this trip is 76.4 km/h, which is the total distance travelled divided by the total time taken.
The average velocity, on the other hand, is 0 km/h, as the car has travelled in a straight line and has not changed direction. Therefore, the difference between the average speed and the average velocity is 76.4 km/h.
It is important to note that the average speed and velocity are two different measures of the same quantity. The difference between them can be seen in terms of the direction of the car's displacement. While the average speed gives the total distance travelled, the average velocity gives the direction in which the car has been travelling, and its magnitude.
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a helicopter rotor slows down at a constant rate from 350 revs/min to 260 revs/min in 1.5 minutes. (a) find the angular acceleration (i.e. change in rev/min) during this time interval. what are the units of this acceleration?
The angular acceleration is - 60 revs/min² or - π /30 rad/s². The result is obtained by using the formula for acceleration.
What is angular acceleration?An angular acceleration or rotational acceleration is the rate of change in angular velocity per unit time. It can be expressed as
α = Δω/t
Where
α = angular accelerationΔω = change in angular velocityt = timeRevs/min is read revolutions per minute. It is equal to 2π/60 rad/s.
A helicopter rotor slows down at a constant rate.
ω₁ = 350 revs/minω₂ = 260 revs/mint = 1.5 minFind the angular acceleration and the units of this acceleration!
The angular acceleration is
α = Δω/t
α = (ω₂ - ω₁)/t
α = (260 - 350)/1.5
α = (-90)/1.5
α = - 60 revs/min²
The unit of the acceleration can be changed in rad/s².
α = - 60 revs/min²
α = - 60 × 2π rad × 1/360 /s²
α = - π /30 rad/s²
Hence, the angular acceleration is - 60 revs/min² or - π /30 rad/s².
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A projectile is projectile has a maximum horizontal range of 40 m. Calculate (g = 10 m s-1):
(i) Speed of projection of the projectile.
(ii) The maximum height reached by the projectile.
Speed of projection of the projectile is 20 m/s.
The maximum height reached by the projectile is 10 m.
What is projectile?When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's center . Such a particle's route is referred to as a projectile.
Acceleration due to gravity = 10 m/s²
maximum horizontal range = 40 m.
Hence, Speed of projection of the projectile = √(40×10) m/s = 20 m/s.
The maximum height reached by the projectile = 20²/(4×10) m = 10 m.
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If a moon feels an attractive force 1191 N from a planet, how much force will the moon feel if the distance between the planet and the moon is doubled?
Answer:
Explanation:
i don’t know
3. Two identical balls of mass 1.8 kg hit head on and rebounded from each other. One ball was traveling at 9.2 m/s and the other ball at 8.7 m/s in the opposite direction. After collision, the second ball rebounded at a speed of 9.1 m/s. What is the speed of the first ball?
Answer:
8.7 m/s.
Explanation:
The speed of the first ball after the collision can be found using the conservation of momentum. The principle of conservation of momentum states that the total momentum of a closed system remains constant if no external forces act upon it.
Initially, the momentum of the first ball is 1.8 kg * 9.2 m/s = 16.56 kgm/s, and the momentum of the second ball is 1.8 kg * -8.7 m/s = -15.66 kgm/s. The total initial momentum is 0.9 kg*m/s
After the collision, the momentum of the second ball is 1.8 kg * 9.1 m/s = 16.38 kg*m/s.
Since the total momentum must remain constant, the momentum of the first ball after the collision is equal to the total initial momentum minus the final momentum of the second ball.
0.9 kgm/s = 16.56 kgm/s + final momentum of the first ball
final momentum of the first ball = 16.56 kgm/s - 0.9 kgm/s = 15.66 kg*m/s
To find the speed of the first ball after the collision, we can divide its final momentum by its mass:
15.66 kg*m/s / 1.8 kg = 8.7 m/s
So the speed of the first ball after the collision is 8.7 m/s.
what is the fundamental frequency (in hz) of a 0.548 m long tube, open at both ends, on a day when the speed of sound is 344 m/s?
The fundamental frequency (in hz) of a 0.548 m long tube is: 627.73 Hz
What is frequency?It can be said that it is the physical quantity that measures the number of times or cycles in which a wave is repeated over time in seconds. Its unit of measurement is the Hertz (Hz).
To solve this exercise the frequency formula we will use is:
λ = v / f
Where:
f= frequencyv= wave velocityλ= wavelengthGiven info
f=? HZv= 344 m/sλ = 0.548 m1 Hz = s˄ -1Applying the wavelength formula and clearing frequency we have:
f= 344 m/s / 0.548 m
f = 627.73 Hz
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increase the temperature to 400k by dragging the slider of the heater located on the bottom of the simulator. what changes have you noticed now?
Several changes will occur by increasing temperature to 400k by dragging slider in simulator like temperature increase, simulated material behavior, their appearance, and simulation processes will also alter.
As the temperature is increased to 400K by dragging the slider of the heater located on the bottom of the simulator, several changes may occur. Firstly, the temperature reading on the simulator will increase, reflecting the change in temperature.Secondly, the behavior of any simulated materials in the system may change. For example, if a gas or a liquid is being simulated, its pressure and volume may increase as the temperature rises. The particles of the simulated material will move faster and collide more frequently, leading to an increase in pressure.Thirdly, the appearance of the simulated materials may change. For example, if a solid is being simulated, it may begin to melt or deform as the temperature increases, changing its appearance. Similarly, if a liquid is being simulated, its viscosity may decrease, making it appear more fluid.Lastly, any simulated reactions or processes taking place in the system may be affected by the change in temperature. Reactions may become faster or slower as the temperature changes, and the rate of reaction can be directly proportional to the temperature.Learn more about simulator here:
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3. a 60 kg woman is in an elevator cab whose upward acceleration is 2 m/s2. what force does she exert on the floor of the cab? (a) 588 n (b) 708 n (c) 0 n (d) 294 n
Answer:
B
Explanation:
F = ma 'a' in this case is the acceleration of gravity (9.81 m/s^2) PLUS the acceleration of the elevator (2 m/s^2 )
F = 60 kg ( 9.81 + 2 ) m/s^2 = 708.6 N
The women exerts a force of 294N on the floor of cab which is moving upwards with an acceleration of 2 m/s2.
"the question is asking force exerted by woman on the floor of cab and not the net force"
The force exerted by a woman on the floor of the cab is equal to her weight, which is the force of gravity acting on her mass. According to Newton's second law of motion, this force is equal to the product of her mass and acceleration.
So, the force exerted by the woman is given by:
F = m * a = 60 kg * 2 m/s^2 = 120 N
Therefore, the answer is (d) 294 N.
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the lowest note on a grand piano has a frequency of 27.5 hz . the entire string is 2.00 m long and has a mass of 400 g . the vibrating section of the string is 1.90 m long. part a what tension is needed to tune this string properly? express your answer in newtons.
The tension needed to properly tune a grand piano string can be calculated using the equation T = (μL2f2)/(4L2), which is 130.31N.
μ is the mass per unit length of the string, L is the length of the string's vibrating section, and f is the string's frequency. Therefore, to calculate the tension, we need to first calculate the mass per unit length, which is equal to the mass of the string divided by the length of the vibrating section.
In this case, the mass per unit length is 400g divided by 1.90m, which equals 210.53 g/m.
Now we can calculate the tension.
Plugging in the values to the equation, the tension is (210.53g/m×1.90m2×275Hz2)/(4×1.90m2)
=130.31N.
Therefore, the tension needed to tune this string properly is 130.31 N.
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a pulse has a 3 cycles each with a wavelength of .25 mm. what is the spatial pulse length in mm
The spatial pulse length is 0.75 mm, if the pulse has 3 cycles each with a wavelength of 0.25 mm.
Spatial pulse length in ultrasound imaging is used to determine for how much time an ultrasound wave exists in space. It is equal to the number of cycle times the wavelength of the pulse. A higher axial resolution is due to the shorter spatial length. Spatial pulse length can be decreased by using the higher frequency transducer or by heavier damping.
Spatial pulse length(SPL) = Number of cycle in each pulse × wavelength
Spatial pulse length(SPL) = 3 × 0.25 = 0.75 mm
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4. A cup is made of an experimental material that can hold hot liquids. The 0.75 kg cup has an initial temperature of 36.5°C when it is submerged in 1.25 kg of water with an initial temperature of 20.0°C. What is the cup's specific heat capacity if the final temperature is 24.4°C?
The cup's specific heat capacity if the final temperature is 24.4°C is 2.54J/kg°C.
How to calculate specific heat capacity?Specific heat capacity of a substance can be calculated using the following expression:
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperaturemc∆T (water) = - {mc∆T} (metal)
1.25 × 4.184 × 4.4 = - (0.75 × c × -12.1)
23.012 = 9.075c
c = 2.54J/kg°C
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An automobile accelerates 2 m/s2 over 6.00 s to reach freeway speed at the end of an entrance ramp. If the car’s final speed is 30.0 m/s, what was its initial speed when it began accelerating?
The initial velocity of the automobile so, that it can reach 30 m/s in the time period of 6 seconds is 18 meters per second.
What is Acceleration?Acceleration is the rate at which the change in velocity occurs in an object. The acceleration is a vector quantity because of presence of both the magnitude and direction.
Acceleration = rate of change of velocity of an object
a = (v-u)/t
a = 2m/s²
v = 30m/s
t = 6 seconds
u = ?
at = v - u
u = v - at
u = 30 - 2 × 6
u = 30 - 12
u = 18m/s
Therefore, the initial velocity of the object will be 18 m/s.
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A boat moves a distance of 3.0 km east and then 7.0 km north. What is the boat's displacement?
Answer:
Explanation:
sketch figure we will see the right triangle3^2 + 7^2 = 58 => displacement sqrt(58) =7.61 (km)3. an archer puts a .30 kg arrow to the bowstring. an average force of 201 n is exerted to draw the string back 1.3 m. a. assuming no frictional loss, with what speed does the arrow leave the bow? b. if the arrow is shot straight up, how high does it rise?
(a) The arrow will leave the bow with a velocity 29.51 m/s. (b) The distance covered by the arrow is 44.44 m.
(a)
Let us assume that, the initial velocity of the arrow is v m/s.
It is given that,
The mass of the arrow, m = 0.3 kg.
The average force exerted on the string, F = 201 N.
The distance that the string pulled back, x = 1.3 m.
Let us consider the spring constant is k N/m.
It is known that, the force on the spring, F = kx.
[tex]\Rightarrow k=\frac{F}{x}[/tex]
[tex]\Rightarrow k=\frac{201}{1.3} N/m[/tex]
[tex]\Rightarrow k=154.62 N/m[/tex]
The kinetic energy of any system can be given by, 1/2 mv²
The kinetic energy of a spring system can be given by, [tex]\frac{1}{2}kx^2[/tex].
Therefore, [tex]\frac{1}{2}mv^2=\frac{1}{2}kx^2[/tex]
[tex]\Rightarrow mv^2=kx^2\\\Rightarrow v=\sqrt{\frac{kx^2}{m}}\\\Rightarrow v=\sqrt{\frac{(154.62)(1.3)^2}{0.3}} m/s\\\Rightarrow v=\sqrt{871.026} m/s[/tex]
⇒ v = 29.51 m/s
Hence, the arrow will leave the bow with a velocity 29.51 m/s.
(b)
It is known that,
The initial velocity of the arrow, u = 29.51 m/s.
The final velocity of the arrow, v = 0.
The acceleration due to gravity is g = -9.8 m/s² (Negative sign signifies it is acting opposite to the initial force).
Let us assume that the distance covered by the arrow is s m.
It is known that,
v² = u² + 2as
⇒ (0)² = (29.51)² + 2 (-9.8) s
⇒ 0 = 871.026 - 19.6s
⇒ 19.6s = 871.026
⇒ s = 871.026 / 19.6 m
⇒ s = 44.44 m
Hence, the distance covered by the arrow is 44.44 m.
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lada 10 how does the planet's distance from its star compare to the distance the 51 pegasi planet is from its star?
The first extrasolar planet to orbit a sun-like star has been identified as 51 distance Pegasi b. 48 light-years from Earth, in the constellation Pegasus, the planet revolves around the fifth-magnitude star 51 Pegasi.
In 1995, Swiss astronomers Michel Mayor and Didier Queloz announced the discovery of a planet circling 51 Pegasi, a star with physical characteristics (such as luminosity and temperature) strikingly comparable to those of the Sun. (For their finding, Mayor and Queloz received the 2019 Nobel Prize in Physics.) Although 51 Pegasi b, an extrasolar planet, cannot be seen from Earth, its existence has been inferred from the wobble that its gravity causes in the parent star's motion over a 4.23-day period. Its mass is 46%
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A 650 KW power engine of a vehicle of
mass 1.5 * 105 Kg is rising on an inclined plane of inclination
1 in 100 with a constant speed of 60 km/hr. Find the frictional
force between the wheels of the vehicle and the plane.
the frictional force between the wheels of the vehicle and the plane is 24000 N.
Power of engine (P) = 650 KW = 6,50,000 W
Mass of vehicle (m) = [tex]1.5[/tex] × [tex]10^{5}[/tex]
SinФ Inclination = 1/100
Speed (V) = 60 km/hr = 60 x 5 / 18 = 50 / 3 m/s
To find the frictional force between the wheels of the vehicle and the plane
F = f + mg SinФ
As, P = F V
P/V = f + 1.5 x [tex]10^{5}[/tex] x 10 x 1/100
6,50,000 x 3 / 50 = f + 15000
39,000 – 15,000 = f
Or f = 24,000 N
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