Given a regular hexagon
At first we should know that, the angle of rotation between any two consecutive two points will be 360/6 = 60
So,
So, the point q after rotation of 120 degree clockwise will be point S
The answer is option A. Point S
I Need Help Please This Will Only Take 1min…
The (C) solution of the equation is the value of the variable that causes an equation to be a true statement.
What are equations?A mathematical statement that has two expressions with equal values separated by the symbol "equal to" is called an equation. Consider the formula 3x + 5 = 15. Different types of equations exist, including linear, quadratic, cubic, and others.So, the Root or solution of the equation is the value of the variable that turns an equation into a true statement.
An equation that compares two mathematical expressions is a sentence or mathematical statement.The value of the variable that makes the equation true or satisfies it is referred to as the equation's root or solution.For instance,
"x + 2 = 0"The equation's solution in this case is x = - 2.
x² - 1 = 0Here, the equation's roots or solutions are x = 1 and -1.
Therefore, the (C) solution of the equation is the value of the variable that causes an equation to be a true statement.
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The complete question is given below:
The value of the variable which makes an equation a true statement is called the ________ of the equation.
A. Coefficient
B. Equation
C. Solution
D. Algebraic expression
E. Constant
F. Variable
10. Find the value of k such that the line through (5, 1) and (k, 7) is parallel to the line
y = 3x.
Answer:
k = 7
Step-by-step explanation:
y = 3x
The slope is 3
Parallel lines have the same slope so a line parallel will have a slope of 3
Using the slope formula
m = (y2-y1)/(x2-x1)
3 = ( 7-1)/(k-5)
3 = 6/(k-5)
Multiply each side by k-5)
3 * (k-5) = 6
Divide each side by 3
k-5 = 6/3
k-5 = 2
Add 5 to each side
k = 7
PLEASE HELP ME I WAS SICK AND I DONT UNDERSTAND.DUE IN 1 HOUR!!!!
Answer:
x = 11
Step-by-step explanation:
(3x + 12) + (7x + 15) = 137 (exterior angle: angle KFG = angle g + angle h)
10x + 27 = 137
10x = 110
x = 11
Given: 3x + 16 = 4x - 9
Prove: x = 25
Answer:
x=16
Step-by-step explanation:
Simplifying
3x + 16 = 4x
Reorder the terms:
16 + 3x = 4x
Solving
16 + 3x = 4x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-4x' to each side of the equation.
16 + 3x + -4x = 4x + -4x
Combine like terms: 3x + -4x = -1x
16 + -1x = 4x + -4x
Combine like terms: 4x + -4x = 0
16 + -1x = 0
Add '-16' to each side of the equation.
16 + -16 + -1x = 0 + -16
Combine like terms: 16 + -16 = 0
0 + -1x = 0 + -16
-1x = 0 + -16
Combine like terms: 0 + -16 = -16
-1x = -16
Divide each side by '-1'.
x = 16
Simplifying
x = 16
Write an inequality and make a number line that shows the situation. 1. A cruise ship can carry up to 3000 passengers. How much passengers might be in the cruise ship?2. Rafael drinks more than 3 pints of water a day. How many pints of water might Rafael drink?
1. Variable
• x: number of passengers
From the description of the problem, the number of passengers must be at most 3000. Mathematically:
x ≤ 3000
This inequality can be represented in a number line as follows:
Can someone help me asap
Answer:
A) 670
B) 192 and 670
C) 670
Answer:
a) 670
b) 192, 670
c) 670
Step-by-step explanation:
670 is divisible by 5 because 670/5=134, also because 670 ends in 0
192 and 670 is divisible by 2 because they both end in even numbers, and also 192/2=96, 670/2=335
670 is divisible by 10 because 670/10=67, and it ends in a 0 as well
5. A. How do we know if an ordered pair is an x-intercept? Explain with specific detail.B. How do we know if an ordered pair is a y-intercept? Explain with specific detail.C. In the table, which order pair is the x-intercept, and which is the y-intercept?х4XNOу-10-24123
a) x-intercept: the y coordinate will be zero while the x coordinate will have a value different from zero.
b) y-intercept: the x coordinate will have a value of zero while the y-coordinate will have a value that is non-zero.
c) The x-intercept: (2, 0)
The y-intercept: (0, 1)
Explanation:5) a) x-intercept is the value of x when the value of y is zero.
To determine if an ordered pair is an x-intercept, the y coordinate will be zero while the x coordinate will have a value different from zero.
b) y-intercept is the value of y when x is equal to zero.
To determine if an ordered pair is a y-intercept, the x coordinate will have a value of zero while the y-coordinate will have a value that is non-zero.
c) To get the x-intercept: From the table, we will check for the of x when the value of y = 0
The value of y = 0 when x = 2
The ordered pair: (x, y)
The x-intercept: (2, 0)
To get the y-intercept: we will check for the value of y when x = 0
The value of x = 0 when y = 1
The ordered pair: (x, y)
The y-intercept: (0, 1)
When 2 triangles are congruent, you can move 1 figure and it fits exactly on the other. Which transformation from Unit 1 would not result in congruent figures?
The non-rigid transformation will not result in congruent figures because they will change the size or shape.
Hence, the answer is dilation because if we dilate the figures they will not be congruent after the transformation.
Greatest common factor of 5xy+10xy^2+5x
To find the GCF of an expression, find the greatest number that every term can divide by. One way we can do this is by factoring the expression.
Solving the Question[tex]5xy+10xy^2+5x[/tex]
Here, each term has the variable x. Factor this out by dividing each term by x:
[tex]x(5y+10y^2+5)[/tex]
Now, each term has a factor of 5. Divide each term by 5:
[tex]5x(y+2y^2+1)[/tex]
Now, there are no more common factors between each term.
Therefore, the GCF is 5x.
Answer5x
Identify the quadratic function(s). (Select all that apply.) 2b(b - 7) + b = 0 (4a + 2)(2a - 1) + 1 = 0 2y + 2(3y - 5) = 0 8 - 5x = 4(3x - 1)
The quadratic equations are 2b(b - 7) + b = 0 and (4a + 2)(2a - 1) + 1 = 0 .
what is Quadratic Equation?An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term. First, there must be a term other than zero in the coefficient of x² (a ≠ 0) for an equation to be a quadratic equation. The x² term is written first when constructing a quadratic equation in standard form, then the x term, and finally the constant term.
Given:
a) 2b(b - 7) + b = 0
2b² - 14b + b = 0
2b² - 13b = 0
b) (4a + 2)(2a - 1) + 1 = 0
8a² - 4a + 4a + 1 =0
8a² 1 =0
c) 2y + 2(3y - 5) = 0
2y+ 6y- 10 = 0
8y -10=0
d) 8 - 5x = 4(3x - 1)
8- 5x= 12x- 4
Hence, the quadratic equations are 2b(b - 7) + b = 0 and (4a + 2)(2a - 1) + 1 = 0 .
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5. What is the value of the 4th term of the expansion of (y + 2z)³?
The 4th term of the expansion is 8z³.
How to expand in mathematics?The expression to be expanded is (y + 2z)³
To expand a bracket means to multiply each term in the bracket by the expression outside the bracket
Therefore,
(y + 2z)³ = (y + 2z)(y + 2z)(y + 2z)
Therefore,
(y + 2z)(y + 2z) = y² + 2yz + 2yz + 4z²
y² + 2yz + 2yz + 4z² = y² + 4yz + 4z²
Hence,
y² + 4yz + 4z² (y + 2z) = y³ + 2y²z + 4y²z + 8yz² + 4yz² + 8z³
Therefore,
(y + 2z)³ = y³ + 2y²z + 4y²z + 8yz² + 4yz² + 8z³
(y + 2z)³ = y³ + 6y²z + 12yz² + 8z³
Therefore, the 4th term is 8z³
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ANSWER PLS QUESTION ATTACHED
A parallelogram is an easy quadrilateral with two pairs of parallel aspects. the other or dealing with facets of a parallelogram are of equal length and the other angles of a parallelogram are of equal measure. Hence, proved p + q = r.
A parallelogram has four sides overall and two pairs of facets that might be parallel. A square is a parallelogram that has four equal sides. the other facets are parallel and all corners of the rectangular shape the right attitude. A rectangle is a parallelogram that has 4 contrary, parallel, congruent aspects.
proving p + q = r;
q = ∠OCD = ∠BAO ( alternate angle)
In Δ AOB
∠OAb + ∠DBA = p + q -------------------(1)
& ∠AOD + ∠BOA = 180° ------------(2)
Also,
∠OAB + ∠OBA + ∠BOA = 180° --------- some of angle in a triangle.
⇒ ( p + q) + (180° - ∠BOA) = 180° --------using 1 & 2
⇒ p + q - r = 0
⇒ p + q = r
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If angle T = x degrees and angle V = 3x + 60, then angle V = ___ degrees.
Given data:
The given circle.
The quadrilateral inside the circle is cyclic in nature, the expression for the cyclic quadrilateral is,
[tex]\begin{gathered} \angle V+\angle T=19=180^{\circ} \\ 3x+60+x=180 \\ 4x=120 \\ x=30 \end{gathered}[/tex]The value of angle V is,
[tex]\begin{gathered} \angle V=3(30^{\circ})+60^{\circ} \\ =150^{\circ} \end{gathered}[/tex]Thus, the value of angle V is 150 degrees.
PLEASE I NEED THIS REALLY REALLY BAD
The quadratic function that includes the given points is given by y = 3/5x² + 6/5x + 6.
what is a quadratic function?When a polynomial function has one or more variables and the highest exponent of any one of the variables is two, the function is said to be quadratic. A "polynomial function of degree 2," then, is a quadratic function.
The definition of a quadratic function:A quadratic function is one that has the formula f(x) = ax2 + bx + c, where a, b, and c are all integers with a not equal to zero. A parabola is the shape that makes up the graph of a quadratic function. The basic "U" shape of a parabola is the same whether it opens upward or downward, or with a different "width" or "steepness."
According to the given data:If we put the values of points in the above equation, then we get.
Putting point (0,6) we get
6 = 0 + 0 + c
=> c = 6
Putting point (2,8) we get
8 = 4a + 2b + 6
=> 2 = 4a + 2b
=> = 2a + b ......(1)
Putting point (3,-3) we get
-3 = 9a + 3b + 6
=> -9 = 9a + 3b
=> -3 = 3a + b ......(2)
From equation (1) b = 2a. Substitute the value of b in equation (2) we get
3 = 3a + 2a
=> a = 3/5
Now, b = 6/5
The quadratic function that includes the given points is given by y = 3/5x² + 6/5x + 6.
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3 × 3/2 answer as a fraction
Evaluate the value of expression.
[tex]\begin{gathered} 3\times\frac{3}{2}=\frac{3\cdot3}{2} \\ =\frac{9}{2} \\ =4\frac{1}{2} \end{gathered}[/tex]So answer is 9/2 or 4 1/2.
A professor has recorded exam grades for 10 students in his class, but one of the grades is no longer redable.if the mean score on the exam was 80 and the mean of the 9 readable scores is 84, what is the value of the unreadable score.
We have The mean of a data-set is given by the sum of all values in the data-set divided by the number of values, so:
data set has 10 values
mean data set is 80
The 9 readable scores have a mean of 84, this is: 9 x 84 = 756
the value of the unreadable score is x
Therefore, the mean is:
[tex]\frac{756+x}{10}=80[/tex]then solve for x:
[tex]\begin{gathered} 10\times\frac{756+x}{10}=80\times10 \\ 756+x=800 \\ 756+x-756=800-756 \\ x=44 \end{gathered}[/tex]Answer: the value of unreadable score is 44
The C major key, starting with the middle C, consists of seven notes (white keys on the piano) with the following frequencies.
Note
C
D
E
F
G
A
B
Frequency(Hz)
261.6
293.7
329.6
349.2
392.0
440.0
493.9
Determine the ratio of the note A to middle C.
a.
1.6818
c.
1.5348
b.
1.4983
d.
1.3654
Look at the equation.
r+ 4 = 32
For which value of r is the equation true?
a. 8
b. 28
C. 36
d. 128
Find the direction angle of v for the following vector.v=7i−2jPart 1What is the direction angle of v?
Given: the vector v
[tex]v=7i-2j[/tex]To Determine: The direction of the given vector
The vector diagram is as shown below
The direction of a vector is calculated by the formula
[tex]\theta=\tan ^{-1}(\frac{y}{x})[/tex]From the given vector, determine x and y
[tex]x=7,y=-2[/tex]Note, the vector is on the fourth quadrant
[tex]\begin{gathered} \theta=\tan ^{-1}(\frac{7}{-2}) \\ \theta=74.05+270=344.05 \\ \theta\approx344.1^0 \end{gathered}[/tex]Hence, the direction of v is 344.1⁰(nearest one decimal place)
Hi, can you help me with that please ‘cause I don’t understand what I have to do .
This is a simple question.
The run is related to the x-axis and the rise to the y-axis and the slope is the relation between the two and we can calculate in the following form:
[tex]Slope=\frac{Rise}{Run}=\frac{y_2-y_1_{}}{x_2-x_1}[/tex]To do so, we need to choose 2 different points in the line and calculate. For our explanation, we will choose points (-1,9) and (3,-3). So let's calculate:
[tex]Slope=\frac{Rise}{Run}=\frac{y_2-y_1}{x_2-x_1}=\frac{9-(-3)}{-1-3}=\frac{12}{-4}=-\frac{12}{4}[/tex]And that is our Slope.
Now we can draw it as follows:
And that is our final answer.
52
base six
Write the normal number
19770609664 is simple power of 52⁶ .
What is exponent and power?
A base number raised to an exponent is referred to as a power in mathematics, where base number is the factor that is multiplied by itself and exponent is the number of times the same base number is multiplied.Exponents and powers are two techniques for simplification of extremely big or extremely small numbers. As an illustration, we can write 3 x 3 x 3 x 3 as 34, where 4 is the exponent and 3 is the base, if we need to represent it simply. It is claimed that the entire statement 34 has power.= 52⁶
= 52 × 52 × 52 × 52 × 52 × 52
= 19770609664
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Which values of x and y would make the following expression represent a real number?
(4 + 5i)(x + yi)
x = 4, y = 5
x = –4, y = 0
x = 4, y = –5
x = 0, y =
The values of x and y that makes the expression are x = 4 and y = -5
How to determine the values of x and y?The expression is given as
(4 + 5i)(x + yi)
The above expression is a complex expression
As a general rule, complex expressions are represented as a + bi
Where a is the real part and bi is the complex part
Also, we have
i = √-1
Using the above as a guide, we have
(4 + 5i)(x + yi)
For the above expression to be a real number, then the following must be true
(4 + 5i) must be a conjugate of (x + yi)
This means that
x + yi = 4 - 5i
By comparison, we have
x = 4 and y = -5
Hence, the values are x = 4 and y = -5
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Convert the following complex number into its polar representation: 3i O A. -3(60597 +isin 37 O COS 2 2 O B. -3(cos+ i sin o) O C. 3(cos+ i sin ) O D. 3c052+isin 8
The correct option is D.
The value of r for the given complex number is calculated below:
[tex]r=\sqrt[]{0^2+3^2}=\sqrt[]{9}=3[/tex]now,
[tex]\tan \theta=\frac{3}{0}=\text{ not defined}[/tex]Since the complex number lies on the positive y-axis.
[tex]\theta=\frac{\pi}{2}[/tex]Therefore, the polar form of the given complex number is
[tex]3(\cos \frac{\pi}{2}+i\sin \frac{\pi}{2})[/tex]Please help me solve question 5 on my algebra homework
Check the answers below, please
1) Since we have this linear function:
[tex]f(x)=-\frac{1}{3}x-4[/tex]a) We can proceed to state the Domain, the set of inputs for this function as:
[tex]D=(-\infty,\infty)[/tex]Since this Linear function does not have any restraint or discontinuity.
b) The Range, i.e. the set of outputs for this function will be defined for this function as:
[tex]R=(-\infty,\infty)[/tex]c) The Zero, can be found algebraically by plugging f(x)=0
[tex]\begin{gathered} f(x)=-\frac{1}{3}x-4 \\ 0=-\frac{1}{3}x-4 \\ \frac{1}{3}x=-4 \\ x=-12 \end{gathered}[/tex]d) Y-intercept is the point in the y-axis where the line intercepts it. Looking at the rule of the function, we can state the y-intercept as:
[tex]-4[/tex]e) Slope, the measure of how steep a line of a function is, it's always the coefficient of x, in this case:
[tex]m=-\frac{1}{3}[/tex]f) Type of slope. Since the slope is -1/3 , i.e. lesser than 0, then we can classify it as decreasing
g) Evaluating f(3):
[tex]\begin{gathered} f(x)=-\frac{1}{3}x-4 \\ f(3)=-\frac{1}{3}(3)-4 \\ f(3)=-1-4 \\ f(3)=-5 \end{gathered}[/tex]h) The value of x, where f(x)= -4 Similarly to the previous item, we can plug into that f(x)= -4 like this:
[tex]\begin{gathered} f(x)=-\frac{1}{3}x-4 \\ -4=-\frac{1}{3}x-4 \\ -4+4=-\frac{1}{3}x-4+4 \\ -\frac{1}{3}x=0 \\ \mathbf{x=0} \end{gathered}[/tex]i) The graph can be traced having the zero, the y-intercept the type of the slope we can plot this:
Solve for x and round to the nearest thousandth
4*x=728
Answer:
182
Step-by-step explanation:
728 divided by 4 is 182.
What is the best estimate for this sum1/4+2/7=
Let's determine the sum of the following:
[tex]\text{ }\frac{\text{ 1}}{\text{ 4}}\text{ + }\frac{\text{ 2}}{\text{ 7}}[/tex]Step 1: Make the two fractions into similar fractions.
The LCM of 4 and 7 is 28, thus, let's convert each fraction into one with a denominator of 28.
We get,
[tex]\text{ }\frac{\text{ 1}}{\text{ 4}}\text{ = }\frac{\text{ 1 x }7}{\text{ 28}}\text{ = }\frac{7}{28}[/tex][tex]\text{ }\frac{\text{ 2}}{\text{ 7}}\text{ = }\frac{\text{ 2 x 4}}{\text{ 28}}\text{ = }\frac{\text{ 8}}{\text{ 28}}[/tex]Step 2: Add the fractions.
[tex]\text{ }\frac{\text{ 1}}{\text{ 4}}\text{ + }\frac{\text{ 2}}{\text{ 7}}[/tex][tex]\text{ }\frac{7}{28}\text{ + }\frac{8}{28}\text{ = }\frac{15}{28}[/tex]Therefore, the answer is 15/28.
What is the total surface area of a cylinder With a radious of 1 cm and a height of 12 cm.
ANSWER
SA = 26π
EXPLANATION
The total surface area is the sum of the areas of the sides of the cylinder:
In this problem r = 1cm and h = 12cm. The areas to sum are the area of the top and the base, which are identical circles, and the area of the rectangle that forms the side:
[tex]undefined[/tex]Write an absolute value inequality whose solution set is shown by the graphs. Each mark on the graph represents a whole number. (Your answers will have the absolute value symbols, | |.)
To answer this question we will use the following:
[tex]\begin{gathered} |a|\ge b\text{ if and only if} \\ a\ge b\text{ or }a\le-b. \end{gathered}[/tex]Notice that the given set consists of the real numbers that are greater than or equal to 3 or that are less than or equal to -3, the above statement in algebraic notation is:
[tex]x\geq3\text{ or }x\leq-3.[/tex]Using the first equations we get that the given set can be represented by the following absolute value inequality:
[tex]|x|\ge3.[/tex]Answer:
[tex]|x|\ge3.[/tex]interest : 40principal: xrate: 1.66%time : 4
The simple interest is given by:
[tex]I=PVrt[/tex]Where:
PV = Present value or principal
I = Interest
r = rate
t = time
Solve for PV:
[tex]\begin{gathered} PV=\frac{I}{rt} \\ so\colon \\ PV=\frac{40}{0.0166\cdot4} \\ PV=602.4 \end{gathered}[/tex]Answer:
$602.4
4. What value of c would make the function below have two real solutions? y= -3x^2 – 4x+c
The quadratic equation is,
[tex]y=-3x^2-4x+c[/tex]The value of coefficients of square term, x term and constant terms are,
a = -3
b = -4
and c = c.
For two real roots,
[tex]b^2-4ac>0[/tex]Dubstitute the values in the equation to obtain the value of c.
[tex]\begin{gathered} (-4)^2-4\cdot(-3)\cdot(c)>0 \\ 16+12c-16>0-16 \\ \frac{12c}{12}>\frac{-16}{12} \\ c>-1.333 \end{gathered}[/tex]So value of c should be greater than -1.333, and from from the options it can be observed that value more than -1.333 is only c = -1.
So answer is c = -1.