the probability of obtaining a sample mean within 500 of the population mean is approximately 0.6827.
To solve this problem, we need to use the central limit theorem which states that the distribution of the sample means will be approximately normal with mean equal to the population mean and standard deviation equal to the population standard deviation divided by the square root of the sample size.
Given that the population mean is 51800 and the population standard deviation is 4000, we can calculate the standard error of the mean as follows:
Standard error of the mean = 4000 / sqrt(64) = 500
We want to find the probability of obtaining a sample mean within 500 of the population mean. This can be written as:
P(51800 - 500 < X < 51800 + 500)
where X is the sample mean.
We can standardize this interval using the standard error of the mean:
P(-1 < Z < 1)
where Z is a standard normal variable.
Using a standard normal table, we find that the probability of Z being between -1 and 1 is approximately 0.6827.
Therefore, the probability of obtaining a sample mean within 500 of the population mean is approximately 0.6827.
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URGENT WHAT'S THE ANSWER TO B I NEED AN EXPLANATION TOO PLEASE
Answer: y=3x-18
Step-by-step explanation:
So the first line that goes through (0,2) and (6,0) is y=(-1/3)x+2
You can calc the slope between (0,2) and (6,0) and the (0,2) gives you the intercept of 2.
Now for line B - - - The slope of the perpendicular line is negative inverse: =3. (-1/3) ----> take the negative of negative 1/3 and it's positive 1/3, and now the inverse is 3.
The general equation for any perpendicular line through the equation we figured out in part A is y=3x+c, where c is your constant (y intercept) which is labeled R.
We can plug in the known point (6,0) in that equation y=3x+c and solve for C to figure out R.
0=3*6+c
0=18+c , so c must equal -18.
Now try out -18 in the equation to see if it works:::
y=3x-18
0=3*6-18
0=18-18
0=0
The side length of a triangle are 6,8 and 10 is this a right triangle
Answer:
Yes
Step-by-step explanation:
if a is a stochastic matrix, then its 1-eigenspace must be a line.true/false
Answer: True.
By definition, a stochastic matrix is a square matrix where each entry is a non-negative real number and the sum of each row is 1.
If A is a stochastic matrix and v is a vector in its 1-eigenspace, then we have:
Av = λv
where λ = 1 is the corresponding eigenvalue.
Multiplying both sides by 1/λ = 1, we get:
v = A v
This means that the vector v is also in the range of A, which is a subspace of the vector space R^n.
Since A is a stochastic matrix, the rows of A sum to 1, and therefore the columns of A also sum to 1. This implies that the vector of all 1's, which we denote by u, is also in the range of A.
Since v is a nonzero vector in the 1-eigenspace and u is a nonzero vector in the range of A, the span of v and u is a two-dimensional subspace of R^n.
Moreover, since A is a stochastic matrix, we have:
Au = u
This means that the vector u is also in the 1-eigenspace.
Therefore, the 1-eigenspace of A is a line spanned by the vector u, which is a nonzero vector in the range of A.
if a is a stochastic matrix, then its 1-eigenspace must be a line: True.
A stochastic matrix is a square matrix with non-negative entries where each row sums to one. The 1-eigenspace of a matrix is the set of all eigenvectors with eigenvalue 1.
Let v be an eigenvector of a stochastic matrix A with eigenvalue 1. Then we have Av = 1v.
Multiplying both sides by the transpose of v, we get v^T Av = v^T v.
Since A is a stochastic matrix, its columns sum to 1 and therefore, its transpose has rows that sum to 1. Thus, v^T Av = 1 and v^T v = 1.
This implies that v^T (A-I) = 0, where I is the identity matrix. Since A is stochastic, I is also stochastic and has a unique 1-eigenspace, which is a line spanned by the vector (1,1,....1)^T.
Therefore, v must be a scalar multiple of (1,1,....1)^T, which implies that the 1-eigenspace of A is a line.
Therefore, the statement "if a is a stochastic matrix, then its 1-eigenspace must be a line" is true.
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The table gives a set of outcome and their probabilities. Let A be the event "the outcome is a divisor of 2. " Let B be the event the outcome is prime. Find P(A | B)
The table is not provided in the question. However, we can use some general probability principles to solve this problem.
We are given two events:
A: The outcome is a divisor of 2.
B: The outcome is prime.
We want to find the conditional probability of A given B, denoted by P(A | B).
The formula for conditional probability is:
P(A | B) = P(A and B) / P(B)
We need to find the probability of the intersection of A and B, i.e., P(A and B), and the probability of event B, i.e., P(B).
Since 2 is the only even prime number, we know that A is equivalent to the event "the outcome is 2". Therefore, we have:
P(A) = P(the outcome is 2)
We also know that the outcome is either prime or composite, and that the prime numbers less than 10 are 2, 3, 5, and 7. Therefore, we have:
P(B) = P(the outcome is 2, 3, 5, or 7)
To find P(A and B), we note that A and B are mutually exclusive events. Therefore, if the outcome is prime, it cannot be a divisor of 2. Thus, we have:
P(A and B) = P(the outcome is 2 and the outcome is prime) = 0
Using the above equations and applying the formula for conditional probability, we get:
P(A | B) = P(A and B) / P(B) = 0 / P(B) = 0
Therefore, the conditional probability of A given B is 0. This means that if the outcome is prime, the probability that it is a divisor of 2 is 0.
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There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the result is a multiple of 6 and a multiple of 4?
The probability of the spinner landing on a multiple of 6 and a multiple of 4 is 1/7.
To find the probability that the spinner will land on a multiple of 6 and a multiple of 4, we need to find the numbers that are multiples of both 6 and 4, which are the multiples of their least common multiple, 12. These numbers are 12 and 24.
Therefore, there are two possible outcomes that satisfy the condition: landing on 12 or landing on 24. Since there are 14 equal areas on the spinner, the probability of landing on 12 or 24 is:
P(12 or 24) = 2/14 = 1/7
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Describe the transformation from the graph of f(x)=3(x-4)^2+6 to the graph of g(x)=f(x+2)-1
The transformation from the graph of graph of f(x)=3(x-4)²+6 to the graph of g(x)=f(x+2)-1 is :
The function g is of the form y = f(x-h) + k where h = horizontal shift and k = the vertical shift.
So the graph of g is a horizontal translation of h units and a vertical translation k unit(s) of the graph of f.
To arrive at g(x) from f(x), three alterations are executed. Initially, a horizontal shift occurs resulting in two units moving towards leftward direction: this change can be denoted through converting instances of "f(x)" into "f(x+2)".
Following that, we observe a vertical drop occurring one unit down. This change is instantaneously made through appending "-1" at end.
Subsequently, there's an upwards vertical stretching effect achieved with use of multiplication by factor three while manipulating existing coefficient value for squared term inside original function.
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Choose the option that best describes the limiting values of T and a under the conditions given. Choose the option that best describes the limiting values of and under the conditions given.
A T=0 and a=0
B T=[infinity] and a=0
C T=mg and a=0
D T=[infinity] and a=g
E T=0 and a=[infinity]
F T=[infinity] and a=[infinity]
Option C best describes the limiting values of T and a under the conditions given. In this case, T represents tension and a represents acceleration.
Without the specific conditions mentioned, it is impossible to determine the exact limiting values of T and a. However, certain options can be ruled out based on common sense and physical laws. For example, option C (T=mg and a=0) is not possible as the tension in a string cannot be equal to the weight of an object. Option E (T=0 and a=[infinity]) is also not possible as a mass cannot have zero tension and infinite acceleration.
Based on these eliminations, the most reasonable options are A (T=0 and a=0) and D (T=[infinity] and a=g). In the former case, the object is not moving and there is no tension in the string. In the latter case, the object is in free fall and the tension in the string is negligible compared to the weight of the object.
However, it is important to note that the exact limiting values of T and a will depend on the specific conditions of the scenario, such as the mass of the object and the angle of the string.
Option C best describes the limiting values of T and a under the conditions given. In this case, T represents tension and a represents acceleration. When T=mg and a=0, it means that the tension in the system is equal to the gravitational force acting on the mass (mg) and the system is in equilibrium with no acceleration. This is a common scenario when an object is hanging from a rope or cable and not moving. The other options do not represent stable or realistic conditions for a physical system.
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Which rigid transformation(s) can map triangleabc onto triangledec? reflection, then rotation reflection, then translation rotation, then translation rotation, then dilation
Both reflection, then translation and rotation, then dilation are rigid transformations that can map triangle ABC onto triangle DEC.
Reflection, then translation: First, we reflect triangle ABC over the line that contains the midpoint of segment DE (the midpoint of AB) and then translate it to coincide with triangle DEC. The reflection preserves the shape and size of the triangle, and the translation moves it to the correct position. Since both of these transformations are rigid (they preserve distances and angles), the composition of the two is also rigid.
Rotation, then dilation: Alternatively, we can rotate triangle ABC counterclockwise by the angle that satisfies ADE = ABC (which is 60 degrees), and then dilate it by a factor of 2 with center D to obtain triangle DEC. The rotation preserves the shape and size of the triangle, and the dilation doubles all distances from D, preserving angles but changing sizes. Again, both of these transformations are rigid, and their composition is also rigid.
However, reflection, then rotation and rotation, then translation are not sufficient to map triangle ABC onto triangle DEC, since they can't change the orientation of the triangle (the order of its vertices) without changing its shape or size.
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The point (4, 14) is shown on the graph. Write an equation that represents this situation, where y represents the amount of macaroni, in cups, and x represents the amount of cheese in cups.
The equation that represents this situation is y= 7/2x where y represents the amount of macaroni, in cups, and x represents the amount of cheese in cups.
From the question, we have the following parameters that can be used in our solution:
Point = (4, 14)
This point can be represented as
(x, y) = (4, 14)
where y represents the amount of macaroni, in cups, and x represents the amount of cheese in cups.
From the above parameter, we can calculate the constant of variation
The constant of variation is calculated as
Constant of variation = y/x
Substitute the known values in the above equation
So, we have the following equation
Constant of variation = 14/4
Evaluate the quotient
Constant of variation = 7/2
Hence, the equation that represents this situation is y= 7/2x
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if a person has 12 pairs of pants, 18 shirts, and 4 jackets , how many different outfits are possible
Here are 864 different outfits possible with the given options of 12 pairs of pants, 18 shirts, and 4 jackets. Each outfit can be created by selecting one pair of pants, one shirt, and one jacket from their respective options. Keep in mind that this calculation assumes that each item can be combined with any other item without any restrictions or preferences.
To determine the number of different outfits possible, we need to multiply the number of options for each clothing item.
For pants, there are 12 different pairs to choose from.
For shirts, there are 18 different options available.
For jackets, there are 4 different jackets to select.
To find the total number of outfit combinations, we multiply these three numbers together:
Total outfits = Number of pants * Number of shirts * Number of jackets
= 12 * 18 * 4
= 864.
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if a cat meows at 1v v being 5 how loud is kitty
Answer: very loud
Step-by-step explanation:
Actually ask a proper question
I need to know what 22.93 is to 1 decimal place
Answer:
It's 22.9, all you need to do is round the number
Step-by-step explanation:
Answer:22.93 --> 2.293 or 229.30
Step-by-step explanation:
and then used the predict() function to make a prediction for each student's number of hours exercised per week, what value would it predict for each student?
the predict() function takes as input a linear regression model and a set of predictor variables (in this case, the students' GPA) and returns a set of predicted response values (in this case, the number of hours exercised per week) based on the fitted model.
The specific value that the predict() function would predict for each student's number of hours exercised per week would depend on the coefficients and intercept of the linear regression model that was fitted to the data. These coefficients reflect the relationship between the predictor variable (GPA) and the response variable (number of hours exercised per week) and determine how changes in the predictor variable are associated with changes in the response variable.
The intercept represents the predicted value of the response variable when the predictor variable is zero. Therefore, the predict() function would use these coefficients and intercept to predict the number of hours exercised per week for each student based on their GPA.
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find f(s). ℒ{(t − 1)?(t − 1)}
The answer for the given Laplace Transform, f(s), is e^(-s)[(1/s^2) - (1/s)].
To find f(s), we can start by applying the Laplace transform to the given function:
ℒ{(t − 1)(t − 1)} = ℒ{t^2 - 2t + 1} = 1/s^3 - 2/s^2 + 1/s
Identify the function
We have the function (t - 1)u(t - 1), where u(t - 1) is the unit step function.
Apply the Laplace Transform property for the unit step function
The Laplace Transform of u(t - a)f(t - a) is given by e^(-as)F(s), where a = 1 in our case. So, we need to find the Laplace Transform of f(t - a) = f(t - 1).
Find the Laplace Transform of f(t - 1)
Our function f(t - 1) = t - 1. The Laplace Transform of t^n is given by n!/(s^(n+1)), so for n = 1, the Laplace Transform of t is 1!/(s^2) = 1/s^2. Since we have t - 1, we find the Laplace Transform of the constant 1 as well, which is 1/s.
So, the Laplace Transform of f(t - 1) = (1/s^2) - (1/s).
Apply the Laplace Transform property
Now, we apply the e^(-as)F(s) property with a = 1:
f(s) = e^(-s)[(1/s^2) - (1/s)]
So, the answer for the given Laplace Transform, f(s), is e^(-s)[(1/s^2) - (1/s)].
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A circular rock garden has a radius of 19.5 feet. What is the approximate circumference of the rock garden?
OA. 38 feet
O B. 61 feet
O C. 123 feet
O D. 380 feet
Answer:
c. 123 feet
Step-by-step explanation:
The circumference formula is 2πr
2*19.5 = 39
39*π ≈ 123
3. Jake has two dogs, Euclid and Pythagoras. Euclid is a smaller dog and Pythagoras is larger. Jake found that Pythagoras lost 13 pounds from January to June. If Pythagoras gains 1.2 times Euclid’s weight, Pythagoras’s weight would still be pound less than he did in January. What is Euclid’s weight?
(a) Write an equation that represents the scenario. Begin by defining your variable.
(b) Solve the equation. Show your work.
(c) What is Euclid’s weight?
(d) Jake adopts a third dog, Riemann. Riemann weighs exactly twice what Euclid weighs. The combined weight of the three dogs is 60 1/2 pounds. What is Riemann’s weight, and what is Pythagoras’s weight? Show your work.
The equation that represents the scenario is P + 1.2x + 0.25 = y. Euclid's weight is 10.625 pounds, and Riemann's weight is 21.25 pounds.
(a) Let us assume that the current weight of Euclid is x and the current weight of Pythagoras is P. Let us also assume that the weight of Pythagoras in January is y. The expression that represents the given scenario will be written as;
when Pythagoras lost 13 pounds in 5 months : P = y - 13
when Pythagoras gains 1.2 times Euclid's weight: = P + 1.2x
when Pythagoras' weight is 1/4 pound less than their weight in January:
(b) Solving the given equation,
P + 1.2x + 0.25 = y
y- 13 + 1.2x + 0.25 = y
1.2x - 12.75 = 0
(c) Euclid's weight is calculated as follows;
1.2x = 12.75
x = 12.75/1.2
x = 10.625 pounds
(d) The weight of Riemann is calculated as follows;
2(Euclid's weight)
2(10.625)
21.25 pounds
weight of Pythagoras = 60.5-(21.25 + 10.62)
= 28.7
The weight of Pythagoras is 28.7 pounds.
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The complete question is "Jake has two dogs, Euclid and Pythagoras. Euclid is a smaller dog and Pythagoras is larger. Jake found that Pythagoras lost 13 pounds from January to June. If Pythagoras gains 1.2 times Euclid's weight, Pythagoras's weight would still be 1/4 pound less than he did in January. What is Euclid's weight? (a) Write an equation that represents the scenario. Begin by defining your variable (b) Solve the equation. Show your work. (c) What is Euclid's weight? (d) Jake adopts a third dog, Riemann. Riemann weighs exactly twice what Euclid weighs. The combined 60.5 pounds. What is Riemann's weight, and what is Pythagoras's weight? weight of the three dogs is Show your work."
Someone please answer for me thank you it’s geometry btw
The surface area of the prism is 462.55 in².
We have,
Slant height = 20.7 in
The perimeter of the base.
= 11 + 11 + 11 + 11
= 44 in
And,
The lateral surface area of the prism.
= Area of all sides except the base area
So,
= 3 x ( 1/2 x 11 x 20.7)
There are same three triangles.
So we add up all the 3 triangles.
= 341.55 in²
And,
Area of the base.
= 11²
= 121 in²
And,
The surface area of the prism.
= Lateral surface area + base area
= 341.55 + 121
= 462.55 in²
Thus,
The surface area of the prism is 462.55 in².
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the use of a ""thumbs-up"" gesture to symbolize the statement ""good luck""
The use of a "thumbs-up" gesture to symbolize the statement "good luck" is a common practice in many cultures. This gesture is typically used to express approval or agreement, but it can also be used to convey positive wishes, such as wishing someone good luck before an exam or a job interview.
It is believed that this gesture originated in ancient Rome, where it was used as a sign of approval in the gladiatorial arena. Today, the thumbs-up gesture has become a universal symbol of positivity and encouragement. So, if you want to wish someone good luck, a thumbs-up gesture is a great way to do it!
The use of a "thumbs-up" gesture to symbolize the statement "good luck" involves the following steps:
1. Extend your arm: To perform the thumbs-up gesture, first extend your arm in the direction of the person you want to wish good luck.
2. Make a fist: Close your fingers into a fist, with your thumb pointing upwards.
3. Show your thumb: Ensure that the thumb is clearly visible and pointing upwards. This represents the "thumbs-up" gesture.
4. Make eye contact: Look at the person you're wishing good luck to, so they know the gesture is directed at them.
By performing the thumbs-up gesture, you're using a universally recognized symbol to convey your positive sentiment and wish someone good luck in their endeavors.
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let z be the standard normal distribution. find the indicated probability. p (−0.82 ≤ z ≤ 1.2). (round your answer to four decimal places.)
The value of the required probability, that is, P(-0.82 ≤ Z ≤ 1.2) for a standard normal distribution is 0.6788.
We want to find the probability P(-0.82 ≤ Z ≤ 1.2) for a standard normal distribution, and round our answer to four decimal places.
Look up the z-scores in the standard normal distribution table.
For z = -0.82, the table gives us the value 0.2061.
For z = 1.2, the table gives us the value 0.8849.
Calculate the probability.
P(-0.82 ≤ Z ≤ 1.2) = P(Z ≤ 1.2) - P(Z ≤ -0.82)
P(-0.82 ≤ Z ≤ 1.2) = 0.8849 - 0.2061
Compute the result.
P(-0.82 ≤ Z ≤ 1.2) = 0.6788
So, the probability P(-0.82 ≤ Z ≤ 1.2) for a standard normal distribution is 0.6788, rounded to four decimal places.
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three students, with different names, line up single file. what is the probability that they are in alphabetical order from front-to-back? express your answer as a common fraction.
The probability that three students, with different names, line up in alphabetical order from front-to-back can be expressed as a common fraction.
Explanation:
There are 3! = 6 ways in which the three students can line up in a single file. However, only one of these arrangements is in alphabetical order from front-to-back. Therefore, the probability of the three students lining up in alphabetical order is:
1/6
This can be expressed as a common fraction, indicating that there is only one favorable outcome out of six possible outcomes. Therefore, the probability of the three students lining up in alphabetical order is 1/6, or approximately 0.1667.
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In which quadrant will the image lie if AB is reflected in the x-axis?
A. Quadrant I
B. Quadrant II
C. Quadrant III
D. Quadrant IV
Answer:
D. Quadrant IV
Step-by-step explanation:
Bc it IS!!!
a ball is dropped form a height of 75 feet and bouces 30% of its previous height on each bounce. how high will its 5th bounce be
The ball will bounce up to a height of approximately 2.92 feet on its 5th bounce.
When a ball is dropped from a height of 75 feet and bounces, it follows a pattern where it bounces back up to a percentage of its previous height. In this case, the ball bounces up to 30% of its previous height on each bounce.
To find out how high the ball will bounce on its 5th bounce, we can use a simple formula. We start with the original height of 75 feet and multiply it by the percentage of the bounce, which is 30%, raised to the power of the number of bounces, which is 5 in this case.
So, the formula looks like this:
75 x (0.3)^5 = 2.9245 feet
Therefore, the ball will bounce up to a height of approximately 2.92 feet on its 5th bounce. It's important to note that the height of each bounce will continue to decrease by 30% of the previous height, so the ball will eventually come to a stop.
Understanding the bounce pattern of a ball can be helpful in predicting its trajectory and height, which can be useful in various sports and scientific experiments.
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Let thetaθ be an angle in standard position. Name the quadrant in which thetaθ lies. tangent theta greater than 0 comma secant theta greater than 0tanθ > 0, secθ > 0 The angle thetaθ lies in which quadrant?
Let thetaθ be an angle in the standard position. We can conclude that the angle theta lies in the first quadrant because both tangent theta and secant theta are positive.
If tangent theta is greater than 0 and secant theta is also greater than 0, then we know that the angle theta is located in either the first quadrant or the third quadrant.
To determine which quadrant the angle lies in, we need to consider the signs of sine and cosine as well. Since tangent is positive and secant is positive, we know that sine and cosine are either both positive or both negative.
In the first quadrant, all trigonometric functions are positive. So if sine and cosine are both positive, then the angle theta must lie in the first quadrant.
In the third quadrant, only tangent and cotangent are positive. So if sine and cosine are both negative, then the angle theta must lie in the third quadrant.
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evaluate the following limit assuming that cos x ≤ f(x) ≤ 1. lim x→0 f(x)
Using the squeeze theorem, we know that if cos x ≤ f(x) ≤ 1, then 0 ≤ f(x) ≤ 1 for all x. Therefore, as x approaches 0, f(x) is bounded between 0 and 1. Since f(x) is sandwiched between two functions that approach 0 as x approaches 0, we can conclude that lim x→0 f(x) must also be equal to 0.
Given that cos x ≤ f(x) ≤ 1 and we are asked to evaluate the limit lim(x→0) f(x), we can use the Squeeze Theorem.
The Squeeze Theorem states that if g(x) ≤ h(x) ≤ k(x) for all x in an interval containing the point a, and if lim(x→a) g(x) = lim(x→a) k(x) = L, then lim(x→a) h(x) = L.
In this case, we have g(x) = cos x, h(x) = f(x), and k(x) = 1. We need to find the limits of g(x) and k(x) as x approaches 0.
lim(x→0) cos x = cos 0 = 1
lim(x→0) 1 = 1
Since both limits are equal to 1, by the Squeeze Theorem, the limit of f(x) as x approaches 0 is also 1.
Therefore, lim(x→0) f(x) = 1.
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In the analysis of variance procedure (ANOVA), factor refers to _____.
a. the critical value of F b. the independent variable c. the dependent variable d. different levels of a treatment
In the analysis of variance procedure (ANOVA), "factor" refers to the independent variable, which is manipulated in order to observe its effect on the dependent variable.
In the analysis of variance procedure (ANOVA), factor refers to:
b. the independent variable
In ANOVA, a factor is an independent variable that is manipulated or controlled to investigate its effect on the dependent variable. Different levels of a factor represent the variations in the independent variable being tested. The different levels of a treatment are often created by manipulating the factor.
In contrast, independent variables are not considered dependent on other variables in various experiments. [a] In this sense, some of the independent variables are time, area, density, size, flows, and some results before the affinity analysis (such as population size) to predict future outcomes (dependent variables).
In both cases it is always a variable whose variable is examined through a different input, statistically also called a regressor. Any variable in an experiment that can be assigned a value without assigning a value to another variable is called an independent variable.
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if you add a finite number of terms to a convergent serie, will the new series still converge?
If you add a finite number of terms to a convergent series, the new series will still converge.
1. A convergent series is a series whose sum approaches a finite limit as the number of terms increases.
2. If you add a finite number of terms to a convergent series, you are essentially adding a fixed constant value to the original sum.
3. Since the original series converges to a finite limit, adding a fixed constant value to it will simply shift the limit by that constant value.
4. As a result, the new series will still approach a finite limit, and thus, it will also converge.
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A pilot is flying over the ocean. He determines that the angles of depression to two ships are 75 and 47, as shown in the figure below. The ships are 8 miles apart. Find the distance from the plane to the ship at point A. Round your answer to the nearest tenth of a mile.
Answer:
Step-by-step explanation:
hi
How many different lengths of craft ribbon does rosie have A.6 B.10 C.12 D.13
Rosie has 6 different lengths of craft ribbons.
How do we know how many different lengths of ribbons Rosie has?In the graph provided for this question, we see that there are 2 of 1 [tex]\frac{3}{4}[/tex] yards, 3 of 2 [tex]\frac{2}{4}[/tex] yard, 2 of 3 yards, 1 of 3[tex]\frac{2}{4}[/tex] yards, 1 of 4 yards and 3 of 4 [tex]\frac{2}{4}[/tex] yards of ribbons.
If we list all this different lengths, it would look like
1. 1 [tex]\frac{3}{4}[/tex] yards 2. 2 [tex]\frac{2}{4}[/tex] yards 3. 3 yards 4. 3[tex]\frac{2}{4}[/tex] yards 5. 4yards and 6. 4 [tex]\frac{2}{4}[/tex] yards
Therefore there are only size different lengths. We were not asked for the sum total of the different lengths which would have amounted to 12.
The answer provided is in response to the question in the image attached below;
Find more exercises on calculating lengths;
https://brainly.com/question/15469997
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A rectangle with length 14ft and width 17ft
Answer:
Area:238 ft²
Perimeter: 62 ft
Step-by-step explanation:
You weren't clear on what you asked, so I can only assume that the question is asking for the area or perimeter.
To find the area, just multiply [tex]lw[/tex].
14·17
=238
To find the perimeter, add 14 and 17 then multiply by 2:
[tex]2(14+17)\\=62[/tex]
Hope this helps! :)
Which of the following is a ray as shown in the drawing?
Answer:
[tex]\overrightarrow{DA}[/tex] [tex]\overrightarrow{EB}[/tex] [tex]\overrightarrow{HK}[/tex] [tex]\overrightarrow{EF}[/tex]
Step-by-step explanation:
A ray is a part of a line that has one endpoint and extends infinitely in one direction.
A ray is named using its endpoint first, and then any other point on the ray that lies in the direction of the extension.
An arrow is placed on top, pointing in the infinite direction of the ray.
For example, the ray starting at point A and extending in the direction of point B is denoted as [tex]\overrightarrow{AB}[/tex].
There are many rays in the given diagram. For example:
[tex]\overrightarrow{DA}[/tex] [tex]\overrightarrow{EB}[/tex][tex]\overrightarrow{HK}[/tex][tex]\overrightarrow{EF}[/tex]