In the similar triangles below , what is the measure of D

In The Similar Triangles Below , What Is The Measure Of D

Answers

Answer 1

In the given similar triangles below, we have to find the measure of Dwrite. Triangle 1, ABC, is similar to Triangle 2, DEF. The two triangles are similar because their corresponding angles are congruent and their sides are proportional.

In order to find the measure of Dwrite, we can use the concept of proportionality. The sides of similar triangles are proportional to each other.

This means that if we know the ratio of the sides of one triangle, we can use that ratio to find the corresponding sides of the other triangle. We can use this property to find the value of Dwrite.

To start, let's write down the ratio of the sides of Triangle 1 and Triangle 2. We can choose any two corresponding sides to do this, but we'll choose AB and DE because they are easiest to measure: AB/DE = 6/8.5We know that the measure of AB is 6, so we can solve for the measure of DE: DE = AB x (DE/AB)DE = 6 x (8.5/6)DE = 8.5Now we know that the measure of DE is 8.5.

We can use this to find the measure of Dwrite. We know that DE and Dwrite are corresponding sides of Triangle 2 and Triangle 1, respectively.

So we can write a proportion using the ratio of DE to Dwrite: DE/Dwrite = 8.5/xWe know that DE is 8.5, so we can substitute that in:8.5/Dwrite = 8.5/Now we can solve for x by cross-multiplying:8.5x = 8.5Dwrite = 1Therefore, the measure of Dwrite is 1.

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Related Questions

The table shows how many children and adults prefer each of two different fruits. How would you find the joint relative frequency of being an adult who prefers watermelon?%0D%0A%0D%0AWatermelon%09Grapes%09Total%0D%0AChild%09132%0985%09217%0D%0AAdult%09111%09117%09228%0D%0ATotal%09243%09202%09445%0D%0A%0D%0AA.%0D%0ADivide 111 by 228.%0D%0A%0D%0AB.%0D%0ADivide 111 by 243.%0D%0A%0D%0AC.%0D%0ADivide 111 by 445.%0D%0A%0D%0AD.%0D%0ADivide 243 by 445.

Answers

The joint relative frequency is calculated by dividing the frequency of a specific subset (in this case, the number of adults who prefer watermelon) by the total number of data points.

Here, the specific subset is adults who prefer watermelon, which is 111. The total number of data points is the sum of all children and adults, regardless of fruit preference, which is 445.

So, to find the joint relative frequency of being an adult who prefers watermelon, you would divide 111 by 445.

Hence, the correct answer is:

C. Divide 111 by 445.

tanx(1+cos2x)=sin2x prove the identity

Answers

Using double angle identity, we are able to prove tan(x)(1 + cos(2x)) = sin(2x).

What is the prove of the given identity?

To prove the identity tan(x)(1 + cos(2x)) = sin(2x), we can start by using trigonometric identities to simplify both sides of the equation.

Starting with the left-hand side (LHS):

tan(x)(1 + cos(2x))

We know that tan(x) = sin(x) / cos(x) and that cos(2x) = cos²(x) - sin²(x). Substituting these values, we get:

LHS = (sin(x) / cos(x))(1 + cos²(x) - sin²(x))

Next, we can simplify the expression by expanding and combining like terms:

LHS = sin(x) / cos(x) + sin(x)cos²(x) / cos(x) - sin³(x) / cos(x)

Simplifying further:

LHS = sin(x) / cos(x) + sin(x)cos(x) - sin³(x) / cos(x)

Now, let's work on the right-hand side (RHS):

sin(2x)

Using the double angle identity for sine, sin(2x) = 2sin(x)cos(x).

Now, let's compare the LHS and RHS expressions:

LHS = sin(x) / cos(x) + sin(x)cos(x) - sin³(x) / cos(x)

RHS = 2sin(x)cos(x)

To prove the identity, we need to show that the LHS expression is equal to the RHS expression. We can combine the terms on the LHS to get a common denominator:

LHS = [sin(x) - sin³(x) + sin(x)cos²(x)] / cos(x)

Now, using the identity sin²(x) = 1 - cos²(x), we can rewrite the numerator:

LHS = [sin(x) - sin³(x) + sin(x)(1 - sin²(x))] / cos(x)

    = [sin(x) - sin³(x) + sin(x) - sin³(x)] / cos(x)

    = 2sin(x) - 2sin³(x) / cos(x)

Now, using the identity 2sin(x) = sin(2x), we can simplify further:

LHS = sin(2x) - 2sin³(x) / cos(x)

Comparing this with the RHS expression, we see that LHS = RHS, proving the identity.

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I’m struggling a bit help please!

Answers

The second approximation x2 is 2.875

and the third approximation x3 is 2.806

How do we calculate?

The root of the equation = [tex]4x^7 + 5x^4 + 3 = 0[/tex]

using Newton's method.

The initial approximation x1 = 3.

Calculate the function value and derivative at x1:

[tex]f(x1) = 4(3)^7 + 5(3)^4 + 3 = 4083\\f'(x1) = 4(7)(3)^6 + 5(4)(3)^3 = 32640[/tex]

We then apply Newton's method formula to find x2:

[tex]x_2 = x_1 - f(x_1)/f'(x1)\\x_2 = 3 - 4083/32640 = 2.875[/tex]

[tex]f(x2) = 4(2.875)^7 + 5(2.875)^4 + 3 \\f(x2) = 46.48\\f'(x2) = 4(7)(2.875)^6 + 5(4)(2.875)^3 \\f'(x2) = 603.75[/tex]

x3 = x2 - f(x2)/f'(x2)

x3 = 2.875 - 46.48/603.75

= 2.806

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The graph below shows the line y=[x]. If the line y=|x|*2 were graphed on the same grid, hc would it compare to the line shown in the graph below. ​

Answers

The graph of the function y = 2|x| is a vertical stretch by a factor of 2 of the parent function y = |x|.

How to identify the transformation?

The functions for this problem are defined as follows:

Parent function: y = |x|.Transformed function: y = 2|x|.

When a function is multiplied by 2, we have that it is vertically stretched by a factor of 2.

Hence the graph of the function y = 2|x| is a vertical stretch by a factor of 2 of the parent function y = |x|.

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Find the missing angles.
with solution

Answers

Hello!

y = 88° (opposite are equal)

z = 180° - 128° = 52° (straight angle = 180°)

x = 180° - 140° = 40° (straight angle = 180°)

Answer:

x=40°

y=88°

z=52°

Step-by-step explanation:

Solution Given:

x+140°=180°

Since the sum of the angle of a linear pair or straight line is 180°.

solving for x.

x=180°-140°

x=40°

[tex]\hrulefill[/tex]

y°=88°

Since the vertically opposite angle is equal.

therefore, y=88°

[tex]\hrulefill[/tex]

z+128°=180°

Since the sum of the angle of a linear pair or straight line is 180°.

solving for z.

z=180°-128°

z=52°

Prove the following this?

Answers

Our initial assumption that S is non-empty must be false. Therefore, for every x ε W, f(x) < x.

To prove the given statement, let's assume that (W, <) is a well-ordered set and f: WW is an increasing function. We need to show that f(x) < x for each x ε W.

Since (W, <) is a well-ordered set, every non-empty subset of W has a minimum element. Let's consider the set S = {x ∈ W | f(x) ≥ x}. Suppose S is non-empty.

By the well-ordered property of (W, <), S has a minimum element, let's call it a. Since a is the minimum element of S, it implies that for all x < a, f(x) < x, because if f(x) ≥ x for any x < a, then x would be an element of S smaller than a, contradicting the assumption that a is the minimum element of S.

Now, let's consider f(a). Since f is an increasing function, f(a) ≥ f(x) for all x < a. But we also know that f(x) < x for all x < a. Combining these two inequalities, we get f(a) < x for all x < a, which means f(a) is an element of S smaller than a, contradicting the assumption that a is the minimum element of S.

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How many moles of water would be produced by the reaction of 5.5 moles of oxygen
C5H12 O2=CO2+H2O

Answers

Step-by-step explanation:

First, you have to balance the equation :

C5 H12  +   8  O2   ====>   5 CO2   + 6 H2 O

so    

  O2 : H2 O  is   8/6         (assumong there is enough...or excess of C5 H 12)

             5.5 / X = 8/6

        X = 5.5 * 6/8 = 4  1/8  MOLES H2O

A survey was taken of children between the ages of 3 and 7. Let A be the event that the person has 2 siblings, and let B be the event that the person does not have a pet.

A 6-column table has 3 rows. The first column has entries has a pet, does not have a pet, total. The second column is labeled 0 siblings with entries 29, 31, 60. The third column is labeled 1 sibling with entries 84, 45, 129. The fourth column is labeled 2 siblings with entries 27, 18, 45. The fifth column is labeled 3 or more siblings with entries 10, 6, 16. The sixth column is labeled Total with entries 150, 100, 250.

Line ST and point V are shown on the graph.

On a coordinate plane, line S T goes through (negative 5, 0) and (5, 2). Point V is at (0, negative 2).

Line VW is to be drawn on the graph such that it is perpendicular to line ST. If the coordinates of point W are (−1, y), what is the value of y?

−7
−5
2
3

Answers

The value of y for point W is 3.

To find the value of y for point W on line VW, which is perpendicular to line ST, we need to determine the slope of line ST and then use the negative reciprocal of that slope to find the slope of line VW.

Given that line ST passes through the points (-5, 0) and (5, 2), we can calculate the slope using the formula:

slope = (y2 - y1) / (x2 - x1)

Using the coordinates (-5, 0) and (5, 2):

slope of ST = (2 - 0) / (5 - (-5))

= 2 / 10

= 1/5

The negative reciprocal of 1/5 is -5. Therefore, the slope of line VW is -5.

Since point V is at (0, -2) and we know the slope of line VW is -5, we can use the point-slope form of a linear equation to find the equation of line VW:

y - y1 = m(x - x1)

Substituting the values of point V (0, -2) and the slope -5:

y - (-2) = -5(x - 0)

y + 2 = -5x

To find the value of y when the x-coordinate is -1, we substitute x = -1 into the equation:

y + 2 = -5(-1)

y + 2 = 5

y = 5 - 2

y = 3

Therefore, the value of y for point W is 3.

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Please solve and explain these two asap!

Answers

A) A and B are neither mutually exclusive nor exaustive.

B) A and C are neither mutually exclusive nor exaustive.

C) A and D are neither mutually exclusive nor exaustive.

D) B and C are neither mutually exclusive nor exaustive.

Which events are exhaustive and which ones are exclusive?

Two events are exhaustive if at least one of them must happen, and two events are mutually exclusive if only one of them can happen.

In this problem we have the sample set:

S = {1, 2, 3, 4, 5, 6}

A = {1, 3, 5}

B= {1, 2, 3, 5, 6}

C = {3, 5}

D = {3, 4, 5}

a) Events A and B:

These have common elements, so these arent exclusive, and there is an outcome (4) that is not in either set, so the sets aren't exhaustive.

b) A and C.

Similar to the previous case, neither mutually exclusive nor exhaustive.

c)  A and D

Now we have, again, common elements, 3 and 5, but there is an element missing (2), so  neither mutually exclusive nor exhaustive.

d) B and C.

Again, we have common elements (so these are not mutually exclusive) and the element 4 is not in neither of the sets, so these arent exhaustive.

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What’s is the inverse of function f?
F(x)=3-x/7

Answers

[tex]y = 3 - \frac{x}{7} \\ x = 3 - \frac{y}{7} \\ \frac{y}{7} = 3 - x \\ y = 7(3 - x) \\ y = 21 - 7x \\ y = - 7x + 21 \\ {f}^{ - 1} (x) = - 7x + 21[/tex]

PLEASE GIVE BRAINLIEST

how much would a school save by using company b instead of company a to server 200 students

Answers

If the school were to switch from Company A to Company B to serve 200 students, they could potentially make savings of around $250 to $350.

Based on the graph provided, the cost of serving school lunches from Company B for 200 students is approximately $1500. As for Company A, the graph shows that the cost starts at $1500 and increases linearly as the number of students served increases.

The graph does not provide an exact data point for 200 students, but based on the trend of the line, the cost for Company A at 200 students would likely fall between $1750 and $1850.

Therefore, if the school were to switch from Company A to Company B to serve 200 students, they could potentially save around $250 to $350. However, these estimates are based on interpolation and the assumption of a linear relationship.

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1.Chords AC, CB, AE, AD and DE are drawn. D=50°.
1.1 Calculate, with reasons, the size of the following angles:
(a) Ô₁
(b) с Ê₁
1.2 Prove that AE || CB. ​

Answers

(a) Ô₁ = 40° (b) с Ê₁ = 80°

AE || CB is proved using alternate interior angles.

1.1 To calculate the size of the angles:

(a) Ô₁: Since D = 50° and AD is a chord, Ô₁ is the central angle of chord AD. According to the properties of a circle, the measure of a central angle is equal to twice the measure of the inscribed angle it intercepts. Therefore, Ô₁ = 2D = 2 * 50° = 100°.

(b) с Ê₁: Angle с Ê₁ is an inscribed angle that intercepts chord CB. According to the inscribed angle theorem, the measure of an inscribed angle is equal to half the measure of the intercepted arc. In this case, the intercepted arc is AD. Since Ô₁ = 100° and the intercepted arc AD is opposite to Ô₁, с Ê₁ = 180° - Ô₁ = 180° - 100° = 80°.

1.2 To prove that AE || CB:

To prove that AE || CB, we need to show that the corresponding angles are equal.

Let's consider angle AED and angle BDC. Both angles are inscribed angles that intercept the same arc AD. According to the inscribed angle theorem, the measure of an inscribed angle is equal to half the measure of the intercepted arc. Since angle AED and angle BDC intercept the same arc AD, they are equal: AED = BDC.

Additionally, angle AED and angle с Ê₁ are alternate interior angles formed by a transversal (AD) intersecting two parallel lines (AE and CB). According to the alternate interior angle theorem, when two parallel lines are intersected by a transversal, the alternate interior angles are congruent. Therefore, angle AED = с Ê₁.

Since angle AED = с Ê₁ and AED = BDC, we can conclude that с Ê₁ = BDC. This equality of corresponding angles proves that AE is parallel to CB, and thus, AE || CB.

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What is the equation of the line in slope intercept form?

Answers

Answer:

y = x + 60

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (20, 80) and (x₂, y₂ ) = (40, 100) ← 2 points on the line

m = [tex]\frac{100-80}{40-20}[/tex] = [tex]\frac{20}{20}[/tex] = 1

the line crosses the y- axis at (0, 60 ) ⇒ c = 60

y = x + 60 ← equation of line

Given:

p: Angles XYZ and RST are vertical angles.
q: Angles XYZ and RST are congruent.

Which statement is logically equivalent to p → q?

If angles XYZ and RST are congruent, then they are vertical angles.
If angles XYZ and RST are not vertical angles, then they are not congruent.
If angles XYZ and RST are not congruent, then they are not vertical angles.
If angles XYZ and RST are vertical angles, then they are not congruent.

Answers

Answer:

    Hence, OPTION (C): If angles XYZ and RST are not congruent, then they are not vertical angles.

Step-by-step explanation:

Analysis:  p → q  is  ~ q → ~ p

To find the Statement that is logically equivalent to p → q, We need to understand the contrapositive of a conditional statement.

The contrapositive of a statement  p → q  is  ~ q → ~ p, In  this case, p is "Angles XYZ and RST are vertical angles."  and q is angles XYZ and RST are congruent."

Identify the Contrapositive:

The Contrapositive of  p → q  is  ~ q → ~ p

Replace p and q with their respective statements:

The Contrapositive of "IF angles XYZ and RST are Vertical angles, Then they are Congruent" is "IF angles XYZ and RST are NOT Congruent, Then They are NOT VERTICAL ANGLES."

Compare the Contrapositive with the given options:

The statement that is logically equivalent to p → q is "IF angles XYZ and RST are not congruent, then they are not vertical angles.

Draw a conclusion:

 Hence, OPTION (C): The statement that is logically equivalent to p → q is "IF angles XYZ and RST are not congruent, then they are not vertical angles.

I hope this helps you!

Final answer:

The logically equivalent statement to 'If angles XYZ and RST are vertical angles, then they are congruent' is 'If angles XYZ and RST are not congruent, then they are not vertical angles.'

Explanation:

In logic and mathematics, the concept of 'if p then q' refers to a specific directional relationship between two statements where 'p' is the hypothesis (or antecedent) and 'q' is the conclusion (or consequent). The statement 'p implies q' can also be logically equivalent to 'If not q, then not p'.

Applying this to your given statements,

p: Angles XYZ and RST are vertical angles. q: Angles XYZ and RST are congruent.

The logically equivalent statement to 'If p then q' is 'If not q, then not p'. So, in the context of these statements, 'If angles XYZ and RST are not congruent, then they are not vertical angles' would be the logically equivalent statement. This statement basically means that if the two angles are not equal in measurement, then you cannot call them vertical angles.

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The mean of 10positive numbers is 16 when another number is added the mean is 18 . Find the number added?

Answers

Answer:

number added is 38

Step-by-step explanation:

mean is calculated as

mean = [tex]\frac{sum}{count}[/tex]

when the count is 10 the mean is 16 , then

[tex]\frac{sum}{10}[/tex] = 16 ( multiply both sides by 10 )

sum = 160

let the number added be x then mean is 18 when count is 11, so

[tex]\frac{160+x}{11}[/tex] = 18 ( multiply both sides by 11 )

160 + x = 198 ( subtract 160 from both sides )

x = 38

the number added is 38

Cual es la pendiente de la recta qué pasa por los puntos (-2,4) y (1,7)

Answers

The slope of the line passing through the points (-2,4) and (1,7) is 1.

To find the slope of a line passing through two points, we can use the formula:

slope (m) = (y2 - y1) / (x2 - x1)

Given the points (-2,4) and (1,7), we can substitute the coordinates into the formula:

m = (7 - 4) / (1 - (-2))

= 3 / 3

= 1

Therefore, the slope of the line passing through the points (-2,4) and (1,7) is 1.

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Use substitution rule
1. Integral (cos x) e^sin(x) dx

Re write using the double angle formula
2. Integral cos^2 (x) dx

3. Integral cos square root x / square root x dx

4. Integral 1/ cube root (1-7x) dx

5. Integral 1/ 2+5x dx

Answers

Answer:

1. The integral of [tex]\(\cos(x) e^{\sin(x)} dx\)[/tex] is [tex]\(e^{\sin(x)} + C\)[/tex], where [tex]\(C\)[/tex] is the constant of integration.

2. The integral of [tex]\(\cos^2(x) dx\)[/tex] can be rewritten using the double-angle formula as [tex]\(\frac{x}{2} + \frac{\sin(2x)}{4} + C\).[/tex]

3. The integral of [tex]\(\frac{\cos(\sqrt{x})}{\sqrt{x}} dx\)[/tex] is [tex]\(2\sin(\sqrt{x}) + C\)[/tex].

4. The integral of [tex]\(\frac{1}{\sqrt[3]{1-7x}} dx\)[/tex]is [tex]\(-\frac{3(1 - 7x)^{2/3}}{14} + C\)[/tex].

5. The integral of [tex]\(\frac{1}{2+5x} dx\)[/tex] is [tex]\(\frac{\ln|2+5x|}{5} + C\)[/tex].

Step-by-step explanation:

Let's break down each integral:

1. Integral of [tex]\(\cos(x) e^{\sin(x)} dx\)[/tex]

  This is a case of a simple substitution. We can let [tex]\(u = \sin(x)\)[/tex], then [tex]\(du = \cos(x) dx\)[/tex]. Substituting these into the integral, we get [tex]\(\int e^u du\)[/tex], which is simply [tex]\(e^u + C\)[/tex]. Substituting back for [tex]\(u\)[/tex], we get [tex]\(e^{\sin(x)} + C\)[/tex].

2. Integral of [tex]\(\cos^2(x) dx\)[/tex]

  The double-angle formula is used here. We know that [tex]\(\cos^2(x) = \frac{1 + \cos(2x)}{2}\)[/tex]. Substituting this into the integral, we get [tex]\(\int \frac{1 + \cos(2x)}{2} dx\)[/tex], which can be separated into two simpler integrals: [tex]\(\frac{1}{2} \int dx + \frac{1}{2} \int \cos(2x) dx\)[/tex]. The integral of [tex]\(dx\) is \(x\)[/tex], and the integral of [tex]\(\cos(2x)\)[/tex] is [tex]\(\frac{1}{2}\sin(2x)\)[/tex]. So, the result is [tex]\(\frac{x}{2} + \frac{\sin(2x)}{4} + C\)[/tex].

3. Integral of \(\frac{\cos(\sqrt{x})}{\sqrt{x}} dx\)

  This is another case of simple substitution. We can let [tex]\(u = \sqrt{x}\)[/tex], then [tex]\(du = \frac{1}{2\sqrt{x}} dx\), or \(2 du = \frac{dx}{\sqrt{x}}\)[/tex]. Substituting these into the integral, we get [tex]\(2 \int \cos(u) du\), which is \(2\sin(u) + C\)[/tex]. Substituting back for [tex]\(u\)[/tex], we get [tex]\(2\sin(\sqrt{x}) + C\)[/tex].

4. Integral of [tex]\(\frac{1}{\sqrt[3]{1-7x}} dx\)[/tex]

  Here, we can let [tex]\(u = 1 - 7x\)[/tex], then [tex]\(du = -7 dx\)[/tex], or [tex]\(-\frac{1}{7} du = dx\)[/tex]. Substituting these into the integral, we get [tex]\(-\frac{1}{7} \int u^{-1/3} du\)[/tex], which is [tex]\(-\frac{3}{7}u^{2/3} + C\)[/tex]. Substituting back for [tex]\(u\)[/tex], we get [tex]\(-\frac{3(1 - 7x)^{2/3}}{14} + C\)[/tex].

5. Integral of [tex]\(\frac{1}{2+5x} dx\)[/tex]

  This is a standard form of integral that results in a natural logarithm. The integral of [tex]\(\frac{1}{a+bx} dx\)[/tex] is [tex]\(\frac{1}{b} \ln |a+bx| + C\)[/tex]. So, the result is [tex]\(\frac{\ln|2+5x|}{5} + C\)[/tex].


Hope This Helps!

Write down the augmented matrix corresponding to the system of equations shown below.

Note: Write an equation in each answer field and do not solve the system.

Answers

The augmented matrix corresponding to the system of equations in this problem is given as follows:

[-6 -5 -4 7].

[7 -9 -1 -7].

[-9 -3 -6 7].

How to construct the augmented matrix?

The first row is constructed according to the coefficients of the first equation, hence it is given as follows:

[-6 -5 -4 7].

The second row is constructed according to the coefficients of the second equation, hence it is given as follows:

[7 -9 -1 -7].

The third row is constructed according to the coefficients of the third equation, hence it is given as follows:

[-9 -3 -6 7].

Hence the matrix is given as follows:

[-6 -5 -4 7].

[7 -9 -1 -7].

[-9 -3 -6 7].

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Martin ordered a pizza with a 16-inch diameter. Ricky ordered a pizza with a 20-inch diameter. What is the approximate difference in the area of the two pizzas?

Answers

Answer: 4 inches

Step-by-step explanation:

you would take the 20 and minis the 16

Find the volume of the region bounded above by the paraboloid z= x2 + y2 and below by the square R: -1 < x < 1, -1 < y < 1

Answers

The volume of the region bounded above by the paraboloid z = [tex]x^2 + y^2[/tex]and below by the square R: -1 < x < 1, -1 < y < 1 is 4/3 cubic units.

To find the volume of the region bounded above by the paraboloid z = [tex]x^2 + y^2[/tex] and below by the square R: -1 < x < 1, -1 < y < 1, we need to integrate the function z = x^2 + y^2 over the given region.

The volume can be calculated using a double integral over the region R. The integral can be set up as follows:

V = ∬R [tex](x^2 + y^2) dA[/tex]

Here, dA represents the infinitesimal area element on the xy-plane.

To evaluate the integral, we need to perform the double integration over the given limits. The limits of integration for x are -1 to 1, and the limits for y are also -1 to 1.

V = ∫(-1 to 1) ∫(-1 to 1) [tex](x^2 + y^2) dy dx[/tex]

Integrating with respect to y first:

V = ∫(-1 to 1) [tex][(x^2)y + (y^3)/3][/tex]evaluated from -1 to 1 dx

V = ∫(-1 to 1) [tex][(x^2 + 1/3) - (x^2 - 1/3)] dx[/tex]

V = ∫(-1 to 1) (2/3) dxV = (2/3) [x] evaluated from -1 to 1

V = (2/3) [(1) - (-1)]

V = (2/3) * 2

V = 4/3

Therefore, the volume of the region bounded above by the paraboloid z = x^2 + y^2 and below by the square R: -1 < x < 1, -1 < y < 1 is 4/3 cubic units.

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Task 3 add
3/4+1/4
2/3+1/3
5/6+2/6
7/8+1/8
4/5+3/5

Answers

The answer for the given questions are:

1. 3/4 + 1/4 = 1

2. 2/3 + 1/3 = 1

3. 5/6 + 2/6 = 7/6

4. 7/8 + 1/8 = 1

5. 4/5 + 3/5 = 1 2/5

To solve the addition problems involving fractions, let's approach each one step by step:

1. 3/4 + 1/4:

When adding fractions with the same denominator, you simply add the numerators while keeping the denominator the same. In this case, since both fractions have a denominator of 4, you can add the numerators, which gives us 3 + 1 = 4. Therefore, the sum is 4/4. However, 4/4 is equivalent to the whole number 1. So, the answer to 3/4 + 1/4 is 1.

2. 2/3 + 1/3:

Similar to the previous problem, these fractions have the same denominator, which is 3. Adding the numerators, we have 2 + 1 = 3. Therefore, the sum is 3/3, which simplifies to 1. So, 2/3 + 1/3 equals 1.

3. 5/6 + 2/6:

Again, the denominators are the same, so we can add the numerators: 5 + 2 = 7. The sum is 7/6. However, 7/6 cannot be simplified any further, so that is the final answer.

4. 7/8 + 1/8:

Both fractions have a denominator of 8. Adding the numerators, we get 7 + 1 = 8. Therefore, the sum is 8/8. Similar to the first example, 8/8 is equivalent to the whole number 1. So, 7/8 + 1/8 equals 1.

5. 4/5 + 3/5:

These fractions share a denominator of 5. Adding the numerators, we have 4 + 3 = 7. Hence, the sum is 7/5. However, 7/5 can be simplified as a mixed number, which is 1 2/5. Therefore, 4/5 + 3/5 equals 1 2/5.

In summary, the solutions to the addition problems are as follows:

1. 3/4 + 1/4 = 1

2. 2/3 + 1/3 = 1

3. 5/6 + 2/6 = 7/6

4. 7/8 + 1/8 = 1

5. 4/5 + 3/5 = 1 2/5

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Identify the equation of the translated graph in general form x^2 + y^2 = 7 for T (-8,4)

Answers

The equation of the translated graph from x² + y² = 7  is (x - 8)² + (y + 4)² = 7

Identifying the equation of the translated graph

from the question, we have the following parameters that can be used in our computation:

x² + y² = 7

The translation is given as

T (-8,4)

This means that

(x, y) = (x - 8, y + 4)

Using the above as a guide, we have the following equation

(x - 8)² + (y + 4)² = 7

Hence, the equation of the translated graph is (x - 8)² + (y + 4)² = 7

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The table shows three unique functions.
x f(x) g(x) h(x)
-2
4
6
-3
-1
1
2
1
4-
2
1
1
55 752
6
8
1
Hit
6:
Mark this and return
-25
Which statements can be used to compare the
characteristics of the functions? Select two options.
Of(x) has an all negative domain.
g(x) has the greatest maximum value.
All three functions share the same range.
Oh(x) has a range of all negative numbers.
All three functions share the same domain.

Answers

Answer:

The statements that can be used to compare the characteristics of the functions are:

1. g(x) has the greatest maximum value.

2. All three functions share the same domain.

Explanation:

- The table shows the values of three functions - f(x), g(x), and h(x) - evaluated at different values of x.

- We cannot determine the domain of f(x) or h(x) from the given table but we can see that g(x) has a domain of all real numbers.

- We can see that g(x) has the highest maximum value among the three functions, which is 8.

- We cannot determine the range of f(x) or g(x) from the given table but we can see that h(x) has a range of all negative numbers.

- We cannot say anything about the domain or range of f(x) based on the given table.

- Therefore, the two statements that can be used to compare the characteristics of the functions are: g(x) has the greatest maximum value and all three functions share the same domain.

please calculate (-3a-5b)+(7a-2b)

Answers

The final expression is 4a - 7b.

To calculate (-3a - 5b) + (7a - 2b), we need to combine like terms.

First, let's combine the terms with the variable 'a':

-3a + 7a = 4a

Next, let's combine the terms with the variable 'b':

-5b - 2b = -7b

Now, we have 4a - 7b.

This expression represents the sum of (-3a - 5b) and (7a - 2b) simplified by combining like terms. It is important to note that no further simplification can be done unless there is additional information or specific values assigned to the variables 'a' and 'b'. The result is a simplified expression that involves both variables 'a' and 'b'.

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The EPA is also interested in controlling the local population of deer. This could be done
by expanding or reducing the duration of each year's hunting season. After collecting
decades of data, a team of researchers developed a quadratic model relating the local
deer population to the duration of each year's hunting season.

P = -10h² + 30h + 237

Here P is the population of deer at the end the year while h is the length of that year's
hunting season that year, measured in months. What is the maximum amount of deer this
model predicts? What does the model predict the population of deer would be if the
government allowed year-round? What would this actually mean?

Answers

The model predicts a negative population (-843) if the hunting season lasts the entire year.

To find the maximum amount of deer predicted by the quadratic model, we need to determine the vertex of the quadratic function. The vertex of a quadratic function in the form of [tex]y = ax^2 + bx + c[/tex] can be found using the formula x = -b / (2a). In this case, the quadratic model is [tex]P = -10h^2 + 30h + 237.[/tex]

Using the formula, we can calculate the value of h at the vertex:

[tex]h = -30 / (2\times(-10)) = 1.5[/tex]

Substituting this value back into the equation, we can find the maximum population of deer:

[tex]P = -10(1.5)^2 + 30(1.5) + 237\\P = -22.5 + 45 + 237\\P = 259.5[/tex]

Therefore, the model predicts that the maximum population of deer would be 259.5 at the end of the year if the hunting season duration is optimized based on the quadratic model.

If the government allowed year-round hunting, we can assume the hunting season duration (h) would be 12 months. Substituting this value into the equation, we can find the predicted population of deer:

[tex]P = -10(12)^2 + 30(12) + 237\\P = -1440 + 360 + 237\\P = -843[/tex]

However, in practical terms, a negative population is not meaningful. It suggests that the quadratic model might not accurately represent the population dynamics in the case of a year-round hunting season. This could be due to various factors, such as migration patterns, breeding habits, or the influence of other ecological factors not considered in the model.

Further research and data analysis would be needed to develop a more accurate model or understand the population dynamics under different hunting scenarios.

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What is the present value of R13 000 p.a. invested at the beginning of each year for 8years at 10%p.a. compound interest? (NB Use the compound interest tables provided or work to three decimal places only.)​

Answers

Given statement solution is :- The present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.

To calculate the present value of an investment with compound interest, we can use the formula for the present value of an annuity:

PV = A *[tex](1 - (1 + r)^(-n)) / r[/tex]

Where:

PV = Present value

A = Annual payment or cash flow

r = Interest rate per period

n = Number of periods

In this case, the annual payment (A) is R13,000, the interest rate (r) is 10% per year, and the investment is made for 8 years (n).

Using the formula and substituting the given values, we can calculate the present value:

PV = [tex]13000 * (1 - (1 + 0.10)^(-8)) / 0.10[/tex]

Calculating this expression:

PV = [tex]13000 * (1 - 1.10^(-8)) / 0.10[/tex]

= 13000 * (1 - 0.46318) / 0.10

= 13000 * 0.53682 / 0.10

= 6977.66 / 0.10

= 69776.6

Therefore, the present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.

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Each circle counts as one whole.

Write a mixed number giving the amount shaded.
Then, write this amount as an improper fraction

Answers

A mixed number giving the amount shaded is: 3³/₅

The fraction as an improper fraction is: 18/5

How to find the fraction?

Fractions are used to represent the parts of a whole or perhaps the collection of objects. A fraction is seen to have primarily two parts. The number on the top of the line is referred to as the numerator while the number below the line is referred to as denominator.

There are different types of fractions such as:

Mixed Fraction

Proper Fraction

Improper Fraction

Now, we are told that Each circle represents a whole and a such we see that we have 3 whole circles.

However, the last circle is only ³/₅ whole and as such the complete expression of all the circles as a mixed fraction is: 3³/₅

Converting it to improper fraction will give us: 18/5

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The table shows values of a force function f(x), where x is measured in meters and f(x) in newtons.
x 2 4 6 8 10 12 14 16 18
f(x) 5 5.6 7.3 8.8 9.6 8 6.6 5 3.9
Use the midpoint rule with
n = 4
to estimate the work W (in J) done by the force in moving an object from
x = 2
to
x = 18.

Answers

Therefore, using the midpoint rule with n = 4, the estimated work done by the force in moving the object from x = 2 to x = 18 is approximately 109.6 J.

To estimate the work done by the force in moving an object from x = 2 to x = 18 using the midpoint rule with n = 4, we divide the interval [2, 18] into 4 subintervals of equal width.

The width of each subinterval is given by Δx = (18 - 2) / 4 = 4.

Next, we calculate the midpoint of each subinterval and evaluate the force function at those midpoints.

The midpoints are: x = 4, 8, 12, 16.

Evaluating the force function at the midpoints, we get: f(4) = 5.6, f(8) = 8.8, f(12) = 8, f(16) = 5.

Now, we can calculate the work done in each subinterval by multiplying the force by the width of the subinterval:

W₁ = f(4) * Δx = 5.6 * 4 = 22.4 J

W₂ = f(8) * Δx = 8.8 * 4 = 35.2 J

W₃ = f(12) * Δx = 8 * 4 = 32 J

W₄ = f(16) * Δx = 5 * 4 = 20 J

Finally, we sum up the individual work values to get the total work done:

W = W₁ + W₂ + W₃ + W₄ = 22.4 + 35.2 + 32 + 20 = 109.6 J

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PLEASE HELPP TRIANGLE THEOREMS QUIZ

Triangle MAB and triangle MNP MN=67.2m AM=32m MP=81.9 MB=X enter you answer as a decimal

Answers

Triangle MAB and triangle MNP MN=67.2m AM=32m MP=81.9. The length of MB is approximately 39.4 units.

To find the length of MB, we can use the triangle proportionality theorem.

The triangle proportionality theorem states that if a line is drawn parallel to one side of a triangle, it divides the other two sides proportionally.

In this case, we can consider line NP as the line drawn parallel to side AB. Therefore, we can set up the following proportion:

MN/MA = MP/MB

Substituting the given values:

67.2m/32m = 81.9/MB

To solve for MB, we can cross multiply:

(67.2m)(MB) = (32m)(81.9)

Dividing both sides by 67.2m:

MB = (32m)(81.9)/67.2m

Simplifying:

MB ≈ 39.4

Therefore, the length of MB is approximately 39.4 units.

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Calculate the surface area and volume for each cylinder.
Surface Area = (² x 2) + (nd x h)
2 x h
Volume
2.
r = 1.75 in h = 2.2 in
Surface Area =
Volume=
d=4.3 mm h= 2 mm
Surface Area =
Volume=
Find the volume

Answers

The surface area and volume of the second cylinder are given in square millimeters and cubic millimeters, V =

The given dimensions for cylinders are:

r = 1.75 in, h = 2.2 in Surface Area of Cylinder:

S = 2πr² + 2πrh

The surface area formula of a cylinder is  S = (2 * pi * [tex]r^2[/tex]) + (2 * pi * r * h).

S = (2 * 3.14 * 1.75²) + (2 * 3.14 * 1.75 * 2.2)

= 44.33 + 38.49

= 82.82 square inches.

Volume of Cylinder: V = πr²h

The formula to calculate the volume of a cylinder is given by V = pi * [tex]r^2[/tex] * h.

Volume = 3.14 * 1.75² * 2.2 = 20.28 cubic inches.

Volume = π(1.75)²(2.2)

Volume ≈ π(3.0625)(2.2)

Volume ≈ 6.7375π cubic inches

The given dimensions for cylinders are: d = 4.3 mm, h = 2 mm

Surface Area of Cylinder: S = 2πr² + 2πrhS = (2 * 3.14 * 2.15²) + (2 * 3.14 * 2.15 * 2) = 67.65 square millimeters.

Volume of Cylinder: V = πr²hV = 3.14 * 2.15² * 2 = 28.33 cubic millimeters.

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