In this puzzle you have a list of n pitchers, with known capacities, c1, c2, ... cn, of holding water in gallons. You have a faucet that can be used as often and as much as the player needs. The goal is to measure exactly g gallons of water, using nothing other than these pitchers. Suppose the current amounts of water that these pitchers hold is w1, w2, ... wn,. These numbers are assumed to be 0 initially. The puzzle is solved as soon as wi = g for any i. A player can perform the following operations:

 Fill pitcher i (from the faucet). The precondition of this operation is: ci > wi ≥ 0. The effect is: wi = ci.

 Empty pitcher i. The precondition of this operation is: ci ≥ wi > 0. The effect is: wi = 0.

 Pour pitcher i to pitcher j. The precondition of this operation is: (ci ≥ wi > 0) and (cj > wj ≥ 0). In words, pitcher i must have some water to pour, and pitcher j must have some unused capacity to receive it. The (partial) effect is: (wi = 0) or (wj = cj) or both. In words, the pour operation must continue until pitcher i becomes empty (and its content is added to pitcher j's content), or pitcher j becomes full (and pitcher i retains the remainder), whichever occurs first. They may occur simultaneously.

A Sample Run

Select the puzzle to solve:

1. Pitchers

2. Eight puzzle

Your selection: 1

Enter the number of pitchers: 3

Enter the capacities of the 3 pitchers (gallons): 2, 5, 10

Enter the goal (gallons): 1

Current configuration: [0, 0, 0]

Please select your next move from the following choices:

1. Fill pitcher 1

2. Fill pitcher 2

3. Fill pitcher 3

Your selection: 2

Current configuration: [0, 5, 0]

Please select your next move from the following choices:

1. Fill pitcher 1

2. Fill pitcher 3

3. Empty pitcher 2

4. Pour pitcher 2 to 1

5. Pour pitcher 2 to 3

Your selection: 4

Current configuration: [2, 3, 0]

Please select your next move from the following choices:

1. Fill pitcher 2

2. Fill pitcher 3

3. Empty pitcher 1

4. Empty pitcher 2

5. Pour pitcher 1 to 2

6. Pour pitcher 1 to 3

7. Pour pitcher 2 to 3

Your selection: 3 Current configuration: [0, 3, 0]

Please select your next move from the following choices:

1. Fill pitcher 1

2. Fill pitcher 2

3. Fill pitcher 3

4. Empty pitcher 2

5. Pour pitcher 2 to 1

6. Pour pitcher 2 to 3

Your selection: 5 Current configuration: [2, 1, 0]

Great! You have reached the goal in 4 moves. Bye.

Answer:

The primary intention of writing this article is to give you an overview of how we can entertain multiple client requests to a server in parallel. For example, you are going to create a TCP/IP server which can receive multiple client requests at the same time and entertain each client request in parallel so that no client will have to wait for server time. Normally, you will get lots of examples of TCP/IP servers and client examples online which are not capable of processing multiple client requests in parallel.  

Explanation:

hope i helped

Answer:

(a) the number of times the value is performs is up to four cycles. and as such the integer i is executed up to 5 times.  (b)The point version of the floating point can have CPE of 3.00, even when the multiplication operation required is either 4 or 5 clock.

Explanation:

Solution

The two floating point versions can have CPEs of 3.00, even though the multiplication operation demands either 4 or 5 clock cycles by the latency suggests the total number of clock cycles needed to work the actual operation, while issues time to specify the minimum number of cycles between operations.

Now,

sum = sum + udata[i] * vdata[i]

in this case, the value of i performs from 0 to 3.

Thus,

The value of sum is denoted as,

sum = ((((sum + udata[0] * vdata[0])+(udata[1] * vdata[1]))+( udata[2] * vdata[2]))+(udata[3] * vdata[3]))

Thus,

(A)The number of times the value is executed is up to 4 cycle. And the integer i performed up to 5 times.

Thus,

(B) The floating point version can have CPE of 3.00, even though the multiplication operation required either 4 or 5 clock.

Answer:

250 wpm for almost an hour straight. This was recorded by Barbara Blackburn in 1946.

Answer:

Struck by rolling object is commonly defined as Struck-By Rolling Object Hazard because it was caused by rolling objects or any objects that moves in circular motion that could cause an injury or accident.

Explanation:

Answer:

A. 0.0450

B. 4

C. 0.25

D. 37.68

E. 6Hz

F. -0.523

G. 1.5m/s

H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

I. -1.67m/s.

Explanation:

Given the equation:

y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)

Standard wave equation:

y(x, t)=Asin(kx−ωt+ϕ)

a.) Amplitude = 0.0450

b.) Wave number = 1/ λ

λ=2π/k

From the equation k = 25.12

Wavelength(λ ) = 2π/25.12 = 0.25

Wave number (1/0.25) = 4

c.) Wavelength(λ ) = 2π/25.12 = 0.25

d.) Angular frequency(ω)

ωt = 37.68t

ω = 37.68

E.) Frequency (f)

ω = 2πf

f = ω/2π

f = 37.68/6.28

f = 6Hz

f.) Phase angle(ϕ) = -0.523

g.) Wave propagation speed :

ω/k=37.68/25.12=1.5m/s

h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.

Answer:

15 seconds

Explanation:

A presentation slide is supposed to be on for 15 seconds and stop to ask if anyone has any questions, if you are explaining something or reading alond with the slide it could be as long as you want it to be.

Answer:

4 slides per minute

Explanation:

Answer:A TPS focusing on production and manufacturing to keep production costs low while maintaining quality, and for communicating with other possible vendors. The TPS would later be used to feed MIS and other higher level systems.

Explanation:

Answer:

YOUR NAME

YOUR CITY, STATE, AND ZIP CODE

YOUR PHONE NUMBER

YOUR EMAIL

Professional Summary

Reliable, top-notch sales associate with outstanding customer service skills and relationship-building strengths. Dedicated to welcoming customers and providing comprehensive service. In-depth understanding of sales strategy and merchandising techniques. Dependable retail sales professional with experience in dynamic, high-performance environments. Skilled in processing transactions, handling cash, using registers and arranging merchandise. Maintains high-level customer satisfaction by smoothly resolving customer requests, needs and problems. Seasoned Sales Associate with consistent record of exceeding quotas in sales environments. Delivers exceptional customer service and product expertise to drive customer satisfaction ratings. Proficient in use and troubleshooting of POS systems.

Skills

Returns and Exchanges

Adaptable and Flexible

Excellent Written and Verbal Communication

Meeting Sales Goals

Strong Communication and Interpersonal Skills

Time Management

Cash Handling

Reliable and Responsible

Work History

March 2020 to September 2021

Goodwill OF YOUR STATE

Retail Sales Associate    

Helped customers complete purchases, locate items and join reward programs.

Checked pricing, scanned items, applied discounts and printed receipts to ring up customers.

Folded and arranged merchandise in attractive displays to drive sales.

Greeted customers and helped with product questions, selections and purchases.

Organized store merchandise racks and displays to promote and maintain visually appealing environments.

Monitored sales floor and merchandise displays for presentable condition, taking corrective action such as restocking or reorganizing products.

Balanced and organized cash register by handling cash, counting change and storing coupons.

Trained new associates on cash register operations, conducting customer transactions and balancing drawer.

Answered questions about store policies and addressed customer concerns.

Issued receipts and processed refunds, credits or exchanges.

Maintained clean sales floor and straightened and faced merchandise.

Education

YOUR HIGH SCHOOL THAT YOU ATTEND  

Languages

Spanish

Explanation:

THIS IS MY RESUME IF YOU HAVE MORE WORK EXPERIENCE THEN ADD IT AFTER THE GOODWILL. I GOT A 100% ON EDGE.

Answer:

Following are the code to this question:

def pairSum(a,x): #find size of list

   s=len(a) # use length function to calculte length of list and store in s variable

   for x1 in range(0, s):  #outer loop to count all list value

       for x2 in range(x1+1, s):    #inner loop

           if a[x1] + a[x2] == x:    #condition check

               print(x1," ",x2) #print value of loop x1 and x2  

pairSum([12,7,8,6,1,13],13) #calling pairSum method

Output:

0   4

1   3

Explanation:

Description of the above python can be described as follows:

Answer:

The program in csharp for the given scenario is shown.

using System;

class ScoreGrade {

static void Main() {

//variables to store score and corresponding grade

double score;

char grade;

//user input taken for score

Console.Write("Enter the score: ");

score = Convert.ToInt32(Console.ReadLine());

//grade decided based on score

if(score>=90)

grade='A';

else if(score>=80 && score<90)

grade='B';

else if(score>=70 && score<80)

grade='C';

else if(score>=60 && score<70)

grade='D';

else

grade='F';

//score and grade displayed  

Console.WriteLine("Score: "+score+ " Grade: "+grade);

}

}

OUTPUT1

Enter the score: 76

Score: 76 Grade: C

OUTPUT2

Enter the score: 56

Score: 56 Grade: F

Explanation:

1. The variables to hold the score and grade are declared as double and char respectively.

int score;

char grade;

2. The user is prompted to enter the score. The user input is not validated and the input is stored in the variable, score.

3. Using if-else-if statements, the grade is decided based on the value of the score.

if(score>=90)

grade='A';

else if(score>=80 && score<90)

grade='B';

else if(score>=70 && score<80)

grade='C';

else if(score>=60 && score<70)

grade='D';

else

grade='F';

4. The score and the corresponding grade are displayed.

5. The program can be tested for different values of score.

6. The output for two different scores and two grades is included.

7. The program is saved using ScoreGrade.cs. The .cs extension indicates a csharp program.

8. The whole code is written inside a class since csharp is a purely object-oriented language.

9. In csharp, user input is taken using Console.ReadLine() which reads a string.

10. This string is converted into an integer using Convert.ToInt32() method.

score = Convert.ToInt32(Console.ReadLine());

11. The output is displayed using Console.WriteLine() or Console.Write() methods; the first method inserts a line after displaying the message which is not done in the second method.

12. Since the variables are declared inside Main(), they are not declared static.

13. If the variables are declared outside Main() and at the class level, it is mandatory to declare them with keyword, static.

Answer:

b. Risk of a potential breach in the integrity of the data on the flash drive

Explanation:

The corrupted or unreadable file error is an error message generated if you are unable to access the external hard drive connected to the system through the USB port. This error indicates that the files on the external hard drive are no longer accessible and cannot be opened.

There are several reasons that this error message can appear:

Answer:

See explaination

Explanation:

n = int(input())

if 20 <= n <= 98:

while n % 11 != 0: // for all numbers in range (20-98) all the identical

digit numbers are divisible by 11,So all numbers that

​​​​​​ are not divisible by 11 are a part of count down, This

while loop stops when output digits get identical.

print(n, end=" ")

n = n - 1

print(n)

else:

print("Input must be 20-98")

Explanation:

See the attached image for The interface (.h file) of a class Counter

Answer:

numbers=list(range(1,11)) #creating the list

even_numbers=list(filter(lambda x: x%2==0, numbers)) #filtering out the even numbers using filter()

triples=list(map(lambda x:x*3 ,even_numbers)) #calculating the triples of each even number using map

total_triples=sum(triples) #calculatting the sum

numbers=list(range(1,11)) #creating the list

even_numbers=[x for x in numbers if x%2==0] #filtering out the even numbers using list comprehension

triples=[x*3 for x in even_numbers] #calculating the triples of each even number using list comprehension

total_triples=sum(triples) #calculating the sum.

Explanation:

Go to the page where you are going to write the code, name the file as 1.py, and copy and paste the following code;

numbers=list(range(1,11)) #creating the list

even_numbers=list(filter(lambda x: x%2==0, numbers)) #filtering out the even numbers using filter()

triples=list(map(lambda x:x*3 ,even_numbers)) #calculating the triples of each even number using map

total_triples=sum(triples) #calculatting the sum

numbers=list(range(1,11)) #creating the list

even_numbers=[x for x in numbers if x%2==0] #filtering out the even numbers using list comprehension

triples=[x*3 for x in even_numbers] #calculating the triples of each even number using list comprehension

total_triples=sum(triples) #calculating the sum

Answer:

See explaination

Explanation:

/* Heap.h */

#ifndef HEAP_H

#define HEAP_H

#include<iostream>

using namespace std;

template<class T>

class Heap

{

public:

//constructor

Heap()

{

arr = nullptr;

size = maxsize = 0;

}

//parameterized constructor

Heap(const T elements[], int arraySize)

{

maxsize = arraySize;

size = 0;

arr = new T[maxsize];

for(int i=0; i<maxsize; i++)

{

add(elements[i]);

}

}

//Remove the root from the heap and maintain the heap property

T remove() //code is altered

{

T item = arr[0];

arr[0] = arr[size-1];

size--;

T x = arr[0];

int parent = 0;

while(1)

{

int child = 2*parent + 1;

if(child>=size) break;

if(child+1 < size &&arr[child+1]>arr[child])

child++;

if(x>=arr[child]) break;

arr[parent] = arr[child];

parent = child;

}

arr[parent] = x;

return item;

}

//Insert element into the heap and maintain the heap property

void add(const T&element)

{

if(size==0)

{

arr[size] = element;

size++;

return;

}

T x = element;

int child = size;

int parent = (child-1)/2;

while(child>0 && x>arr[parent])

{

arr[child] = arr[parent];

child = parent;

parent = (child-1)/2;

}

arr[child] = x;

size++;

}

//Get the number of element in the heap

int getSize() const

{

return size;

}

private:

T *arr; //code is altered

int size, maxsize;

};

#endif // HEAP_H

///////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

/* main.cpp */

#include<iostream>

#include "Heap.h"

using namespace std;

template <typename T>

void heapSort(T list[], int arraySize)

{

Heap<T> heap(list, arraySize);

int n = heap.getSize();

for(int i=n-1; i>0; i--)

{

list[i] = heap.remove();

}

}

int main()

{

const int SIZE = 9;

int list[] = {1, 7, 3, 4, 9, 11, 3, 1, 2};

heapSort<int>(list, SIZE);

cout << "Sorted elements using heap: \n";

for (int i = 0; i < SIZE; i++)

cout << list[i] << " ";

cout <<endl;

system("pause");

return 0;

}

Answer:

True

Explanation:

There's no one law that governs internet privacy.

Answer:

The correct answer to the following question will be Option D (Interchangeable).

Explanation:

The other three solutions are not situation-ally appropriate, so option D seems to be the right choice.

Answer: Provided in the explanation segment

Explanation:

Below is the code to run this program.

we have that the

Program

import java.util.Scanner;

public class CharMatching {

  public static void main(String[] args) {

      //Scanner object for keyboard read

      Scanner scnr=new Scanner(System.in);

      //Variable for user input string

      String userInput;

      //Variable for firstletter input

      char firstLetter;

      //Read user input string

      userInput=scnr.nextLine();

      //Read first letter from user

      firstLetter=scnr.nextLine().charAt(0);

      //Comparison without case sensititvity and result

      if(Character.toUpperCase(firstLetter)==Character.toUpperCase(userInput.charAt(0))) {

          System.out.println("Found match: "+firstLetter);

      }

      else {

          System.out.println("No match: "+firstLetter);

      }

  }

}

Output

Hello

h

Found match: h

cheers i hope this helped !!!

Answer: Provided in the explanation segment

Explanation:

Below is the code to carry out this program;

/* C++ program helps prompts user to enter the size of the array. To display the array elements, sorts the data from highest to lowest, print the lowest, highest and average value. */

//main.cpp

//include header files

#include<iostream>

#include<iomanip>

using namespace std;

//function prototypes

void displayArray(int arr[], int size);

void selectionSort(int arr[], int size);

int findMax(int arr[], int size);

int findMin(int arr[], int size);

double findAvg(int arr[], int size) ;

//main function

int main()

{

  const int max=50;

  int size;

  int data[max];

  cout<<"Enter # of scores :";

  //Read size

  cin>>size;

  /*Read user data values from user*/

  for(int index=0;index<size;index++)

  {

      cout<<"Score ["<<(index+1)<<"]: ";

      cin>>data[index];

  }

  cout<<"(1) original order"<<endl;

  displayArray(data,size);

  cout<<"(2) sorted from high to low"<<endl;

  selectionSort(data,size);

  displayArray(data,size);

  cout<<"(3) Highest score : ";

  cout<<findMax(data,size)<<endl;

  cout<<"(4) Lowest score : ";

  cout<<findMin(data,size)<<endl;

  cout<<"(5) Lowest scoreAverage score : ";

  cout<<findAvg(data,size)<<endl;

  //pause program on console output

  system("pause");

  return 0;

}

/*Function findAvg that takes array and size and returns the average of the array.*/

double findAvg(int arr[], int size)

{

  double total=0;

  for(int index=0;index<size;index++)

  {

      total=total+arr[index];

  }

  return total/size;

}

/*Function that sorts the array from high to low order*/

void selectionSort(int arr[], int size)

{

  int n = size;

  for (int i = 0; i < n-1; i++)

  {

      int minIndex = i;

      for (int j = i+1; j < n; j++)

          if (arr[j] > arr[minIndex])

              minIndex = j;

      int temp = arr[minIndex];

      arr[minIndex] = arr[i];

      arr[i] = temp;

  }

}

/*Function that display the array values */

void displayArray(int arr[], int size)

{

  for(int index=0;index<size;index++)

  {

      cout<<setw(4)<<arr[index];

  }

  cout<<endl;

}

/*Function that finds the maximum array elements */

int findMax(int arr[], int size)

{

  int max=arr[0];

  for(int index=1;index<size;index++)

      if(arr[index]>max)

          max=arr[index];

  return max;

}

/*Function that finds the minimum array elements */

int findMin(int arr[], int size)

{

  int min=arr[0];

  for(int index=1;index<size;index++)

      if(arr[index]<min)

          min=arr[index];

  return min;

}

cheers i hope this help!!!

   //Method definition of words_typed

   //The return type is int

   //Takes two int parameters: typingSpeed and timeInterval

   public static int words_typed(int typingSpeed, int timeInterval) {

       //Get the number of words typed by  

       //finding the product of the typing speed and the time interval

       //and then dividing the result by 60 (since the typing speed is in "words

       // per minute"  and the time interval is in "seconds")

       int numberOfWords = typingSpeed * timeInterval / 60;

       //return the number of words

       return numberOfWords;

   }        //end of method declaration

The code above has been written in Java and it contains comments explaining each of the lines of the code. Please go through the comments.

Answer:

I am writing the program in Python.

def words_typed(typing_speed,time_interval):

   typing_speed>=0

   time_interval>0

   no_of_words=int(typing_speed*(time_interval/60))

   return no_of_words

output=words_typed(20,30)

print(output)

Explanation:

I will explain the code line by line.

First the statement def words_typed(typing_speed,time_interval) is the definition of a function named words_typed which has two parameters typing_speed and time_interval.

typing_speed variable of integer type in words per minute.

time_interval variable of int type in seconds

The statements typing_speed>=0 and time_interval>0 means that value of typing_speed is greater than or equal to zero and value of time_interval is greater than zero as specified in the question.

The function words_typed is used to return the number of words that a  person with typing speed would type in that time interval. In order to compute the words_typed, the following formula is used:

   no_of_words=int(typing_speed*(time_interval/60))

The value of typing_speed is multiplied by value of time_interval in order to computer number of words and the result of the multiplication is stored in no_of_words. Here the time_interval is divided by 60 because the value of time_interval is in seconds while the value of typing_speed is in minutes. So to convert seconds into minutes the value of time_interval is divided by 60 because 1 minute = 60 seconds.

return no_of_words statement returns the number of words.

output=words_typed(20,30) statement calls the words_typed function and passed two values i.e 20 for typing_speed and 30 for time_interval.

print(output) statement displays the number of words a person with typing speed would type in that time interval, on the output screen.

Answer:

Following are code of factorial in python language

def factorial(n): # function

   result=1 #variable

   for x in range(2,n+1): #iterating the loop

       result=result*x  #storing result

   return result #return result

for n in range(10): #iterating loop

   print(n,factorial(n)) #print factorial

Output:

Following are the attachment of output

Explanation:

Missing information :

In the question the information is missing the code is missing which we have to correct it following are the code that are mention below.

def factorial(n): # function

   result=1 #variable

   for x in range(       ): #iterating the loop

       result=  #storing result

   return  #return result

for n in range(  ): #iterating loop

   print(n,factorial(n)) #print factorial

Following are the description of code

Following are the attachment snip of code in the python language

By filling in the blanks to make the factorial function return the factorial of n, we have the following.

def factorial (n):

 result = 1

 for x in range(2, n+1):

   result = result*x

 return result

for n in range(10):

 print(n,factorial(n))

The math module in Python includes a number series of mathematical operations that may be easily done using the module. The math . factorial() function computes the factorial of a given number.

To write the code perfectly and fill in the blanks:

CODE:

def factorial (n):

 result=1

 for x in range(2, n+1):

   result = result*x

 return result

for n in range(10):

 print(n,factorial(n))

RESULT:

0 1

1 1

2 2

3 6

4 24

5 120

6 720

7 5040

8 40320

9 362880

Therefore, we can conclude that we've understood how to write the factorial function code in python.

Learn more about python coding here:

https://brainly.com/question/1351889?referrer=searchResults

Answer:

Think of DMA as a co-processor that is used to quickly transfer data between main memory and peripherals without the intervention of the CPU.

Answer:

Sew explaination foe code

Explanation:

import java.lang.*;

import java.util.*;

import java.io.*;

class Main

{

public static Boolean checkSubset(int[] list1, int[] list2)

{

int l = list2.length;

for(int i = 0; i<list1.length-l; i++)

{

Boolean flag = true;

for(int j = 0; j<list2.length; j++)

{

if(list1[i+j] != list2[j])

{

flag = false;

break;

}

}

if(flag) return true;

}

return false;

}

public static void main(String args[])

{

int[] l1 = {1,6,2,1,4,1,2,1,8};

int[] l2 = {1,2,2};

System.out.println(checkSubset(l1,l2));

}

}

Answer:

A Program was written to carry out some set activities. below is the code program in C++ in the explanation section

Explanation:

Solution

CODE

#include <iostream>

using namespace std;

int main() {

string name; // variables

int number;

cin >> name >> number; // taking user input

while(number != 0)

{

// printing output

cout << "Eating " << number << " " << name << " a day keeps the doctor away." << endl;

// taking user input again

cin >> name >> number;

}

}

Note: Kindly find an attached copy of the compiled program output to this question.

In this exercise we have to use the knowledge in computational language in C++ to describe a code that best suits, so we have:

The code can be found in the attached image.

In a very summarized way, we can describe the loop or looping in software as an instruction that keeps repeating itself until a certain condition is met.

To make it simpler we can write this code as:

#include <iostream>

using namespace std;

int main() {

string name; // variables

int number;

cin >> name >> number; // taking user input

while(number != 0)

{

// printing output

cout << "Eating " << number << " " << name << " a day keeps the doctor away." << endl;

// taking user input again

cin >> name >> number;

}

}

See more about C++ at brainly.com/question/19705654

Answer:

public class SwitchCase {

   public static void main(String[] args) {

       int num = 0;

       int a = 10, b = 20, c = 20, d = 30, x = 40;

       switch (num){

           case 102: a += 1;

           case 103: a += 1;

           case 104: a += 1;

           case 105: a += 1;

           break;

           case 208: b += 1; x = 8;

           break;

           case 209: c = c * 3;

           case 210: c = c * 3;

           break;

           default: d += 1004;

       }

   }

}

Explanation:

Answer:

There are various ways: Handing out papers/fliers to people, or presenting slides.

Answer:

Check the explanation

Explanation:

Let the population mean time on task of original website be [tex]\mu_1[/tex] and that of new prototype be [tex]\mu_2[/tex]

Here we are to test

[tex]H_0:\mu_1=\mu_2\;\;against\;\;H_1:\mu_1<\mu_2[/tex]

The data are summarized as follows:

                                                       Sample 1             Sample 2

Sample size                                        n=20                    n=20

Sample mean                                 [tex]\bar{x}_1=243.4[/tex]             [tex]\bar{x}_2=253.4[/tex]

Sample SD                                     s1=130.8901          s2=124.8199

The test statistic is obtained from online calculator as

t=-0.23

The p-value is given by 0.821

As the p-value is more than 0.05, we fail to reject the null hypothesis at 5% level of significance and hence conclude that there is no statistically significant difference between the original website and the prototype developed by the team at 5% level of significance.

Answer:

Term describes the order of arrangement of files and folders on a computer would be ORGANIZATION.

:) Hope this helps!

Answer:

The term that describes the order of arrangement of files and folders on a computer is organization.

Explanation:

Answer:

They can communicate over the phone or have meetings describing what is and isn't working for Joe. It's also very important that Darla makes eye contact and is actively listening to effectively handle their customer.

Explanation:

Program explanation:

Program code:

def sum_divisors(n):#defining a method sum_divisors that takes a parameter

   s = 0#defining a variable s that hold a value 0

   for x in range(1,n):#defining a for loop that use n variable to check range value

       if(n%x==0):#use if to check remainder value equal to 0  

           s += x#adding value in s variable

   return s#return s value

print(sum_divisors(6))#calling method

print(sum_divisors(12))#calling method

Output:

Please find the attached file.

Learn more:

brainly.com/question/14704583