Based on the stem and leaf plots given, the correct stem and leaf plot for the first table on per capita income is the third stem and leaf diagram.
For the table on the basketball tornament, the correct stem and leaf plot would be the last one.
How are stem and leaf plots used?First look at the key to the bottom right of the plot to see how to interpret the data.
The key on the third stem and lead plot says 1 I 2 = 12,000. This means that every steam and lead pairing is in thousands.
Based on the income per capita being in thousands, this is the most likely stem and lead plot for the first table on income per capita.
The second table about basketball tornament appearances is on single and double digits. Only a small stem and leaf key will do.
Look at the number of appearances. The minimum is 1. On a stem and leaf, this is shown as 0 I 1. Options A and B don't have this so we go to Options C and D.
As established, Option C is for data in their thousands so it is out. The correct stem and leaf plot is therefore Option D.
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The perimeter of a square is 72 inches. What is the length of each side
value of element a23
Answer:
2
Step-by-step explanation:
a23
2 is column and 3 is row
NO LINKS! Please help me with this problem
Answer:
x=70, y=55
Step-by-step explanation:
Since the angle "y" and 2x-15 form a straight line, that means the sum of the angles, must be 180 degrees.
So using this we can derive the equation: [tex]y+2x-15=180[/tex]
The next thing you need to know is that the sum of interior angles of a triangle is 180 degrees, so if we add all the angles, we should get 180.
So using these we can derive the equation: [tex]x+2y=180[/tex]
So, in this case we simply have a systems of equations. We can solve this by solving for x in the second equation (sum of interior angles), and plug that into the first equation.
Original Equation:
[tex]x+2y = 180[/tex]
Subtract 2y from both sides
[tex]x = 180-2y[/tex]
Now let's plug this into the first equation
[tex]y+2x-15=180[/tex]
Plug in 180-2y as x
[tex]y+2(180-2y)-15=180[/tex]
Distribute the 2
[tex]y+360-4y-15=180[/tex]
Combine like terms
[tex]-3y + 345 = 180[/tex]
Subtract 345 from both sides
[tex]-3y = -165[/tex]
Divide both sides by -3
[tex]y=55[/tex]
So we can plug this into either equation to solve for x
[tex]x+2y=180[/tex]
Substitute in 55 as y
[tex]x+2(55)=180[/tex]
[tex]x+110=180[/tex]
Subtract 110 from both sides
[tex]x=70[/tex]
Answer:
x = 70°
y = 55°
Step-by-step explanation:
The angle sum theorem and the definition of a linear pair can be used to write two equations in the two unknowns. Those can be solved for the angle values.
Setupx + y + y = 180° . . . . . . angle sum theorem
y + (2x -15) = 180° . . . . definition of linear pair
SolutionWe can use the first equation to write an expression for x that can be substituted into the second equation:
x = 180 -2y
y +(2(180 -2y) -15) = 180 . . . . substitute for x
345 -3y = 180 . . . . . . . . . . . collect terms
115 -y = 60 . . . . . . . . . . . . .divide by 3
y = 55 . . . . . . . . . . . . . . add (y-60)
x = 180 -2(55) = 70
The values of the variables are ...
x = 70°
y = 55°
exterior angle = 125°
QUESTION IS DOW BELOW 5 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP
WILL GIVE BRAINLIEST FOR ACCURATE ANWSER
The length of segment XY is 52 units and the length of segment HD is 26 units
How to determine the lengths?Secant lines (a)
To do this, we make use of the following intersecting secant theorem
VZ * VW = VY * VX
Substitute the known values in the above equation
12 * 40 = VY * 8
Divide by 8
12 * 5 = VY
Evaluate the product
VY = 60
The length VX is
XY = VY - VX
Substitute the known values in the above equation
XY = 60 - 8
Evaluate
XY = 52
Hence, the length of segment XY is 52 units
Secant lines (b)
To do this, we make use of the following intersecting secant theorem
GH^2 = HC * HD
Substitute the known values in the above equation
13^2 = 6.5 * HD
Divide by 6.5
13^2/6.5 = HD
Evaluate the quotient
26 = HD
The length HD is
HD = 26
Hence, the length of segment HD is 26 units
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4. A store has 152 bottles of
water. This is 2 times the
number of sodas they
have. How many sodas
does the store have?
Answer:
76 sodas
Step-by-step explanation:
152 divided by 2
Answer: 76 sodas
Step-by-step explanation:
To find the sodas, use the data you see. Bottles of water are twice the sodas. So divided water by 2 to get the sodas.
152 ÷ 2 = 76 ( sodas ) . Hope it helps !
Suppose that Andrea told you that “Blake and I started out with the same number of marbles, but I gave him one of mine. Now Blake has one more marble than me.” Is Andrea’s reasoning incorrect? If so, how can you help Andrea identify her misunderstanding?
Step-by-step explanation:
i know this but i don't have time now
Andrea has one less than she started with , Blake has one more than he started with. Therefore , Blake has two more than he started with. Therefore, the correct answer is option B.
Andrea told that 'Blake and I started out with the same number of marbles, but I gave him one of mine. Now Blake has one more than me. '
Here Andrea is wrong with her conclusion. Let's understand this by taking some values.
Let's consider that Andrea and Blake both have 4 marbles(Since it is given that 'they have equal number of marbles). And Andrea gave one of her marbles to Blake. So number of marbles of Andrea will become 4-1=3. And number of marbles of Blake = 4+1 =5. If we compare them , Blake has 2 more marbles than Andrea.
Therefore, the correct answer is option B.
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"Your question is incomplete, probably the complete question/missing part is:"
Suppose that Andrea told you that “Blake and I started out with the same number of marbles, but I gave him one of mine. Now Blake has one more marble than me.” Is Andrea’s reasoning incorrect? If so, how can you help Andrea identify her misunderstanding?
A. Blake needs to take one of his marbles away first. Then, Andrea can give him one of hers. Thus, Blake will have one more than Andrea.
B. Andrea has one less than she started with Blake has one more than he started with. Therefore, Blake has two more than Andrea.
C. Andrea meant to say that after giving Blake one of her marbles, show would have one less than Blake.
D. Andrea meant to say that she took one of her marbles away and not give it to Blake. Therefore, Blake would only have one more than her.
cual es el valor de v-15=-2
Let f(x) = cxe−x2 if x ≥ 0 and f(x) = 0 if x < 0. For what value of c is f a probability density function? for that value of c find P(1
The value of c such that the function f is a probability density function is 2
How to determine the value of c?The density function is given as:
f(x) = cxe^(−x^2) if x ≥ 0
f(x) = 0 if x < 0.
We start by integrating the function f(x)
∫f(x) = 1
This gives
∫ cxe^(−x^2) = 1
Next, we integrate the function using a graphing calculator.
From the graphing calculator, we have:
c/2 * (0 + 1) = 1
Evaluate the sum
c/2 * 1 = 1
Evaluate the product
c/2 = 1
Multiply both sides of the equation by 2
c = 2
Hence, the value of c such that the function f is a probability density function is 2
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Mr. Smith borrowed $22,000 to purchase stock for his baseball card shop. He repaid the simple interest loan after four years. He paid interest of $6.260. What was the interest rate?
Based on the calculations, the interest rate on the stock in four (4) years is equal to 7.1%.
Given the following data:
Amount borrowed (Principal) = $22,000.
Simple interest, I = $78.40.
Time = 4 year.
To determine the interest rate on the stock in four (4) years:
How to calculate simple interest?Mathematically, simple interest can be calculated by using this formula:
I = PRT
Where:
S.I is the simple interest.P is the principal or starting amount.R is the interest rate.T is the time measured in years.Making R the subject of formula, we have:
R = I/PT
Substituting the given parameters into the formula, we have;
R = 6260/(22,000 × 4)
R = 6260/(88,000)
Interest rate = 0.071 = 7.1%.
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Question
3x² + 25x - 18
Which of the following is a factor of the polynomial above?
Ox-9
O x + 3
O 3x - 2
O 3x + 1
The factors of polynomial [tex]3x^{2} +25x-18[/tex] is (3x-2)(x+9) that's why the correct option is (3x-2) which is option c.
Given a polynomial [tex]3x^{2} +25x-18[/tex].
We are required to find the factors of polynomial given as [tex]3x^{2} +25x-18[/tex].
Polynomial is a combination of algebraic terms which is formed by using algebraic operations.
Factors are those numbers which when divided gives the number whose factors they are.
[tex]3x^{2} +25x-18[/tex]
To find the factors we need to break the middle term of the polynomial so that the broken parts when multiplied gives the product of both the first term and last term.
[tex]3x^{2}[/tex]+27x-2x-18
3x(x+9)-2(x+9)
(3x-2)(x+9)
Hence the factors of polynomial [tex]3x^{2} +25x-18[/tex] is (3x-2)(x+9) that's why the correct option is (3x-2) which is option c.
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divide the difference of 20 and 6 by the product of 7 and 2
Step-by-step explanation:
Vocabulary (what the words mean):Divide, the same as ÷
divide 6 by 3
by is the same as the symbol
6 ÷ 3 = 2
Difference, This is another way of saying take away or minus
the difference of 6 and 3 is
6 - 3 = 3
Product, This is another word for multiply or times
the product of 2 and 3 is
2 × 3 = 6
Write as an equationdivide (÷) the difference of 20 and 6 (20 - 6) by the product of 7 and 2 (7 × 2)
so
(20 - 6) ÷ (7 × 2)
can you do the rest???
three subtracted from the product of two and a number n
Answer:
(2+n)-3
That's how you write if that is what you want.
What is the value of the expression shown below?
8 + (7 + 1)2 + 4
07
9
021
24
Answer: 28
Step-by-step explanation:
[tex]8+(7+1)2+4\\\\8+(8)2+4\\\\8+16+4\\\\24+4\\\\28[/tex]
50 Points!!
Select the reason that best supports statement 3 in the given proof
Answer:
Step-by-step explanation:
Comment and Answer
This is a very well laid out proof. It would good for you to see how carefully this this proof has been set up.
Step Three says
DE = DF ÷ 2
The problem is that at least 2 of the choices will work. I think the best reason is that it is the definition of bisect. The previous statement says in language what statement three says in algebraic notation. So statement 2 is the given statement. Statement 3 tells us that DE is 1/2 DF because it is bisected.
Answer A
Heyy i just need some help with questions 5,7,9 if anyone could help me and show the work that would be amazing thank you!!
Step-by-step explanation:
5)f(g(8))
from the table g(8)=4
f(4) =4 from the table
7)g(f(5))
from the table f(5)=0
g(0)=9 from the table
9)f(f(4))
from the table f(4)=4
f(4)=4 from the table
A person draws a card from a hat. Each card is one color, with the following probabilities of being drawn: 1/10 for white, 1/15 for pink, 1/20 for green, and 1/5 for red. What is the probability of pulling a red or green card, written as a reduced fraction?
The probability of pulling a red or green card, written as a reduced fraction is 1/4
How to determine the probability of pulling a red or green card, written as a reduced fraction?From the question, we have the following probabilities:
P(White) = 1/10
P(Pink) = 1/5
P(Green) = 1/20
P(Red) = 1/5
The probability of pulling a red or green card, written as a reduced fraction is the calculated as:
P(Red or Green card) = P(Red card) + P(Green card)
Substitute the known values in the above equation
P(Red or Green card) = 1/5 + 1/20
Express 1/5 as 4/20
P(Red or Green card) = 4/20 + 1/20
Take the LCM
P(Red or Green card) = (4+1)/20
Evaluate the sum
P(Red or Green card) = 5/20
Simplify the fraction
P(Red or Green card) = 1/4
Hence, the probability of pulling a red or green card, written as a reduced fraction is 1/4
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Please help, type your answers in order .
Step-by-step explanation:
we know from the laws of motion that in the equation
h = 20t - 1.86t²
the gravitational acceleration is in the factor of the t² term.
h = v0t + 1/2 × g × t²
v0 being the initial velocity (20 m/s).
and we can therefore see, that the gravitational acceleration "a" on Mars is 2×1.86 = 3.72 m/s²
(a)
the velocity v after 2 seconds is (first law of motion)
v = v0 + at = 20 - 3.72×2 = 12.56 m/s
gravity pulling down, so negative acceleration.
(b)
first we need the time when the rock is at 25 m.
25 = 20t - 1.86t²
0 = -1.86t² + 20t - 25
the solution to a quadratic equation is always
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
x = t
a = -1.86
b = 20
c = -25
t = (-20 ± sqrt(400 - 4×-1.86×-25))/(2×-1.86) =
= (-20 ± sqrt(214))/-3.72
t1 = (-20 + 14.62873884...)/-3.72 =
= 1.443887409... s ≈ 1.44 s
t2 = (-20 - 14.62873884...)/-3.72 =
= 9.308800763... s ≈ 9.31 s
that means, on its way up the rock reached 25m after
1.44 s.
on its way down the rock reached 25 m after
9.31 s.
velocity 0 (the rock came to a stop before falling back down) was after
0 = 20 - 3.72t
3.72t = 20
t = 20/3.72 = 5.376344086... s
that means the rock was falling after this point back to the ground and was gaining speed again.
that accelerating phase until the rock was again at 25 m was
9.308800763... - 5.376344086... = 3.932456677... s
long
the velocity at these points was
v-up = 20 - 3.72×1.443887409... = 14.62873884... m/s ≈
≈ 14.63 m/s
v-down = 0 + 3.72×3.932456677... = 14.62873884... m/s ≈
≈ 14.63 m/s
as expected : the rock did a perfectly symmetric flight path between the two 25 m marks.
so time and speed on both sides had to be identical.
but we have proven it.
Answer:
a) 12.56 m/s
b) up: 14.63 m/s (2 d.p.)
down: -14.63 m/s (2 d.p.)
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{9 cm}\underline{The Constant Acceleration Equations (SUVAT)}\\\\s = displacement in m (meters)\\u = initial velocity in m s$^{-1}$ (meters per second)\\v = final velocity in m s$^{-1}$ (meters per second)\\a = acceleration in m s$^{-2}$ (meters per second per second)\\t = time in s (seconds)\\\\When using SUVAT, assume the object is modeled\\ as a particle and that acceleration is constant.\end{minipage}}[/tex]
The average gravitational acceleration on Mars is 3.721 m/s² (about 38% of that of Earth). The fact that the rock is thrown from the surface of Mars rather than the surface of Earth is of no consequence when using the equations of constant acceleration (SUVAT equations) as long as acceleration is not used in the calculations.
Part (a)Given:
[tex]s=20t-1.86t^2, \quad u=20, \quad t=2[/tex]
[tex]\begin{aligned}\textsf{Using }\: s&=\dfrac{1}{2}(u+v)t\\\\\implies 20(2)-1.86(2)^2 & = \dfrac{1}{2}(20+v)(2)\\\\32.56 & = 20+v\\\\v & = 32.56-20\\\\v & = 12.56\:\: \sf m/s\end{aligned}[/tex]
Therefore, the velocity of the rock after 2 s is 12.56 m/s.
Part (b)Find the time when the height of the rock is 25 m:
[tex]\begin{aligned}20t-1.86t^2 & = s\\\implies 20t-1.86t^2 & = 25\\1.86t^2-20t+25 & = 0\end{aligned}[/tex]
Quadratic Formula
[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]
Therefore:
[tex]a=1.86, \quad b=-20, \quad c=25[/tex]
[tex]\implies t=\dfrac{-(-20) \pm \sqrt{(-20)^2-4(1.86)(25)} }{2(1.86)}[/tex]
[tex]\implies t=\dfrac{20 \pm \sqrt{214}}{3.72}[/tex]
[tex]\implies t=9.308800763..., 1.443887409...[/tex]
Therefore, the height of the rock is 25 m when:
t = 9.31 s (2 d.p.)t = 1.44 s (2 d.p.)To find the velocity (v) of the rock at these times, substitute the found values of t into the equation, along with s = 25 and u 20 m/s:
[tex]\begin{aligned}\textsf{Using }\: s&=\dfrac{1}{2}(u+v)t\\\\\implies v & = \dfrac{2s}{t}-u\\\\v & = \dfrac{2(25)}{t}-20\\\\v & = \dfrac{50}{t}-20\\\\\end{aligned}[/tex]
When t = 1.443887409...s
[tex]\implies v=\dfrac{50}{1.443887409...}-20=14.63\:\: \sf m/s \: \:(2\:d.p.)[/tex]
When t = 9.308800763...s
[tex]\implies v=\dfrac{50}{9.308800763...}-20=-14.63\:\: \sf m/s \: \:(2\:d.p.)[/tex]
Therefore, the velocity of the rock when its height is 25 m is:
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What are the major requirements for a group of individuals and organizations to be a market? How does a consumer market differ from a business-to-business market?
The major requirements for a group of individuals and organisations to be a market as evident from the definition big a market is that; there must be an exchange of goods or services in which case, there are sellers and buyers.
Which requirements ascertain that a group of individuals are a market?The occurrence of the exchange of goods and services represents the qualifying requirement for a market.
The distinctive property between a consumer market and a business-to-business market is the that former, involves the end user of the good or service while the latter involves the use of the good or service exchanged to facilitate the production of other goods.
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Somebody help me with this please
Answer: 9 units
Step-by-step explanation: R is at -7 and is at 2. Think of how far away -7 is from 2. -7+9=2.
Answer:
9 units
Step-by-step explanation:
Length of a segment RV is a difference of values of V and R. According to the number line, R is -7 and V is 2.
The difference or change in two values is 2 - (-7) = 2 + 7 = 9 units.
Henceforth, the segment RV is 9 units.
Solve the quadratic equations in questions 1 – 5 by factoring.
1. x2 – 49 = 0
2. 3x3 – 12x = 0
3. 12x2 + 14x + 12 = 18
4. –x3 + 22x2 – 121x = 0
5. x2 – 4x = 5
The solutions for the given equations are:
x² - 49 = 0; x = {-7, 7}3x³ - 12x = 0; x = {-2, 0, 2}12x² + 14x + 12 = 18; x = {-3/2, 1/3}-x³ + 22x² - 121x = 0; x = {0, 11, 11}x² - 4x = 5; x = {-1, 5}What is factorization?Writing a number or an equation as a product of its factors is said to be the factorization.
A linear equation has only one factor, a quadratic equation has 2 factors and a cubic equation has 3 factors.
Calculation:1. Solving x² - 49 = 0; (quadratic equation)
⇒ x² - 7² = 0
This is in the form of a² - b². So, a² - b² = (a + b)(a - b)
⇒ (x + 7)(x - 7) =0
By the zero-product rule,
x = -7 and 7.
2. Solving 3x³ - 12x = 0
⇒ 3x(x² - 4) = 0
⇒ 3x(x² - 2²) = 0
⇒ 3x(x + 2)(x - 2) = 0
So, by the zero product rule, x = -2, 0, 2
3. Solving 12x² + 14x + 12 = 18; (quadratic equation)
⇒ 12x² + 14x + 12 - 18 = 0
⇒ 12x² + 14x - 6 = 0
⇒ 2(6x² + 7x - 3) = 0
⇒ 6x² + 9x - 2x - 3 = 0
⇒ 3x(2x + 3) - (2x + 3) = 0
⇒ (3x - 1)(2x + 3) = 0
∴ x = 1/3, -3/2
4. Solving -x³ + 22x² - 121x = 0
⇒ -x³ + 22x² - 121x = 0
⇒ -x(x² - 22x + 121) = 0
⇒ -x(x² - 11x - 11x + 121) = 0
⇒ -x(x(x - 11) - 11(x - 11)) = 0
⇒ -x(x - 11)² = 0
∴ x = 0, 11, 11
5. Solving x² - 4x = 5; (quadratic equation)
⇒ x² - 4x - 5 = 0
⇒ x² -5x + x - 5 = 0
⇒ x(x - 5) + (x - 5) = 0
⇒ (x + 1)(x - 5) =0
∴ x = -1, 5
Hence all the given equations are solved.
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If AC=24, what is AB?
Write an equation and solve for x first.
Answer:
AB = 6
Step-by-step explanation:
from the diagram
AB + BC = AC , that is
x + 3x = 24
4x = 24 ( divide both sides by 4 )
x = 6
then
AB = x = 6
The length of AB calculated is 6 units
What is Algebraic expression ?
Algebraic expressions are the idea of expressing numbers using letters or alphabets without specifying their actual values. The basics of algebra taught us how to express an unknown value using letters such as x, y, z, etc. These letters are called here as variables. An algebraic expression can be a combination of both variables and constants. Any value that is placed before and multiplied by a variable is a coefficient.
AC = 24
Here, from the number line the data given are :
AB = x
BC = 3x
CD = 4x-13
Now calculating length AB or x by adding AB and BC and equating to 24 :
AC = AB+BC
24 = x+3x
4x = 24
x = 24/4
x = 6
Therefore, the length of AB calculated is 6 units
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If AB = 58, and BC = 46, find the length of the radius to the nearest tenth. Assume BC is tangent to Circle A.
Applying the Pythagorean theorem, the length of the radius is: 35.3 units.
How to Apply the Pythagorean Theorem?According to the Pythagorean theorem, the sum of the squares of the shorter sides of a right triangle equals the square of the longest side. For example, if a and b are two smaller legs of a right triangle, and c is the longest leg (hypotenuse) of the right triangle, then the Pythagorean theorem states that:
a² + b² = c².
Given the following parameters of the right triangle:
Triangle ABC is a right triangle with angle ACB as the right angle according to the tangent theorem since segment BC is tangent to Circle A
Segment AB = 58 (hypotenuse of the right triangle)
Segment BC = 46 (small leg of the right triangle)
Radius = AC (small leg of the right triangle)
Using the Pythagorean theorem, we have:
AC = √(AB² - BC²)
AC = √(58² - 46²)
AC = 35.3 units (to the nearest tenth).
Therefore, by using the Pythagorean theorem, the length of the radius of the circle, which is segment AC, to the nearest tenth is: 35.5 units.
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Function and Reasoning:
There are 60 calories in 5 ounces of a certain brand of soda.
Part A: Represent the relationship between the number of calories and the number of ounces of soda as a line in the coordinate plane below.
Part B: What is the number of calories per ounce of soda?
Part C: How does the unit rate relate to the slope of the line in the graph above? Explain your answer.
The number of calories per ounce of soda is 10
Part A: Represent the relationship between the number of calories and the number of ouncesThe given parameters are:
Calories = 50
Ounces = 5
Let the number of calories be y and the ounces be x.
So, we have:
y = kx
Substitute y = 50 and x = 5
50 = 5k
Divide by 5
k = 10
Substitute k = 10 in y = kx
y = 10x
See attachment for the graph of the relationship between the number of calories and the number of ounces
Part B: What is the number of calories per ounce of soda?In (a), we have:
k = 10
This means that the number of calories per ounce of soda is 10
Part C: How does the unit rate relate to the slope of the line in the graph above?The unit rate and the slope represent the same and they have the same value
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How do you solve 1.023 x 3.5 ?
Answer:
Step-by-step explanation:
3.5805
List all elements of B that belong to specified set B={10, square root of 5, -14, 2/3, square root of 16, 0.81
The irrational number on set B is given by: [tex]\sqrt{5}[/tex]
What are irrational numbers?Irrational numbers are numbers that cannot be represented by fractions. The two most common examples are:
Non-exact roots.Non-terminating decimal.In the set B given in this problem, the only number that is irrational is [tex]\sqrt{5}[/tex], as it is a non-exact root.
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Steve took a 300 mile business trip and decided to travel by car. He drove the speed limit for half the trip until an accident occurred and he had to stop for a few hours in traffic. Steve then decided to drive slower than the speed limit the rest of the way to be safe. This situation models which type of function?
Based on the fact that Steve was originally driving the speed limit and then stopped a few hours and drove slower, the situation models a piecewise defined function.
What is a piecewise defined function?This is a type of function where there are two or more parts joined together. In other words, there are two equations to represent the different parts of the function.
In this case, Steve was driving at a certain speed. This is one function. Then he stopped for a couple of hours which is another function. Then the last function has him driving slower than the speed limit.
In conclusion, this is a defined piecewise function.
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What is 3/2+ t = 1/2
Answer:
t=-1Step-by-step explanation:
To find the value of t, isolate it on one side of the equation.
[tex]\sf{\dfrac{3}{2}+t=\dfrac{1}{2}}[/tex]
First, you subtract by 3/2 from both sides.
[tex]\Longrightarrow: \sf{\dfrac{3}{2}+t-\dfrac{3}{2}=\dfrac{1}{2}-\dfrac{3}{2}}[/tex]
Solve.
1/2-3/2
1-3/2
1-3=-2
-2/2
Divide.
-2/2=-1
[tex]\Longrightarrow: \boxed{\sf{t=-1}}[/tex]
Therefore, the solution is t=-1, which is our answer.
I hope this helps, let me know if you have any questions.
STEP BY STEP EXPLANATION;
1.To solve the equation,the least common multiple of the denominators must be found.
LCM=2
Therefore,
3/2 +t =1/2
2.Each term must be multiplied by the LCM.
i.e
2(3/2)+2(t)=2(1/2)
3+2t=1
2t=1-3 ( subtracting 3 from each side of the equation)
2t=1-3
2t/2=-2/2 (dividing both sides of the equation by the co-efficient of t)
t=-1
(1,-2) and (2,-4) exponential formula f(x)=ab^x
We conclude that the exponential function is:
f(x) = -1*(2)ˣ
How to find the exponential function?Here we know that we have an exponential function of the form:
f(x) = a*b^x
And we know two points on the function, that are:
f(1) = -2 = a*b^1 = a*b
f(2) = -4 = a*b^2
Then we have a system of equations to solve, which is:
-2 = a*b
-4 = a*b^2
From the first equation we can solve:
-2/a = b
Replacing that in the other equation we can get:
-4 = a*(-2/a)^2 = 4/a
a = 4/-4 = -1
Now that we know the value of a, we can get the value of b:
-2/a = b
-2/-1 = 2 = b
In this way, we conclude that the exponential function is:
[tex]f(x) = -1*(2)^x[/tex]
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Subtract: (c ^ 2 - 4c + 7) from (7c ^ 2 - 5c + 3)
subtracting (c ^ 2 - 4c + 7) from (7c ^ 2 - 5c + 3) would give 6c² - 9c -4
Substracting algebraic expressionsGiven the expressions as
(c ^ 2 - 4c + 7)
(7c ^ 2 - 5c + 3)
We are to substract expression 2 from expression 1
In doing this, we need to know the BODMAS rule ( bracket, of, division, multiplication, addition and subtraction). This would help in finding the solution
(7c ^ 2 - 5c + 3) - (c ^ 2 - 4c + 7)
Expand the bracket
7c² - 5c + 3 - c² - 4c + 7
collect like terms
7c²- c² - 5c - 4c + 3 - 7
Add or substract the like terms
6c² - 9c -4
Thus, subtracting (c ^ 2 - 4c + 7) from (7c ^ 2 - 5c + 3) would give 6c² - 9c -4
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Answer:6c^2-c-4
Step-by-step explanation:
(7c^2-5+3)-(c^2-4c+7)
7c^2-5c+3-c^2+4c-7
Rearrange the terms
7c^2-c^2-5c+4c+3-7
Combine like terms
6c^2-c-4
Suppose that the derivable functions x=x(t) and y=y(t) satisfy xcosy=2.
If dx/dt=−2, find dy/dt when y=π/4.
a-) -√2 / 2
b-) 4
c-) -2√2
d-) √2
e-) 2√2
Please, someone help me!
Applying implicit differentiation, it is found that dy/dt when y=π/4 is of:
a-) -√2 / 2.
What is implicit differentiation?Implicit differentiation is when we find the derivative of a function relative to a variable that is not in the definition of the function.
In this problem, the function is:
xcos(y) = 2.
The derivative is relative to t, applying the product rule, as follows:
[tex]\cos{y}\frac{dx}{dt} - x\sin{y}\frac{dy}{dt} = 0[/tex]
[tex]\frac{dy}{dt} = \frac{\cos{y}\frac{dx}{dt}}{x\sin{y}}[/tex]
Since dx/dt=−2, we have that:
[tex]\frac{dy}{dt} = -2\frac{\cos{y}}{x\sin{y}}[/tex]
When y = π/4, x is given by:
xcos(y) = 2.
[tex]x = \frac{2}{\cos{\frac{\pi}{4}}} = \frac{2}{\frac{\sqrt{2}}{2}} = \frac{4}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = 2\sqrt{2}[/tex]
Hence:
[tex]\frac{dy}{dt} = -2\frac{\cos{y}}{x\sin{y}}[/tex]
[tex]\frac{dy}{dt} = -\frac{1}{\sqrt{2}}\cot{y}[/tex]
Since cot(pi/4) = 1, we have that:
[tex]\frac{dy}{dt} = -\frac{1}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = -\frac{\sqrt{2}}{2}[/tex]
Which means that option a is correct.
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