Is it true or false?

Answer:

Group 2

Explanation:

Magnesium is the eighth most abundant element in the earth's crust although not found in it's elemental form. It is a Group 2 element (Group IIA in older labelling schemes). Group 2 elements are called alkaline earth metals. Magnesium metal burns with a very bright light.

Answer:

mass CO = 0.12166 g

Explanation:

Mass of CO = 0.12 grams

Explanation

Volume of CO gas = 117 mL = 0.117 L

Temperature of CO = 55.0 oC = 328 K

Assumption : Pressure of CO = atmospheric pressure = 1.0 atm

According to ideal gas law,

moles of CO = [(Pressure of CO) * (Volume of CO gas)] / [(R) * (Temperature of CO)]

where R = gas constant = 0.0821 L-atm/mol-K

moles of CO = [(1.0 atm) * (0.117 L)] / [(0.0821 L-atm/mol-K) * (328 K)]

moles of CO = 0.004345 mol

mass CO = (moles of CO) * (molar mass CO)

mass CO = (0.004345 mol) * (28.0 g/mol)

mass CO = 0.12166 g

Answer:

.00352mol/L

Explanation:

molarity (concentration) = number of moles / volume of solvent (in L)

M = .99g / 56.108‬g/mol / .5L

M = .0176mol / .5L

M = .00352mol/L

Answer:

Magma

Explanation:

Magma is the hot liquid under earths surface

Answer:

[tex]m_{nitrogen}=14g[/tex]

Explanation:

Hello,

In this case, since we are talking about a chemical reaction in which a compound having nitrogen and chlorine is decomposed into chlorine and nitrogen, we must remember that the law of conservation of mass must be obeyed, for that reason, we notice that the mass of the whole reactants must equal the mass of the whole products, as shown below:

[tex]m_{reactants}=m_{products}[/tex]

Next, we know there is only one single reactant and products are constituted by both chlorine and nitrogen:

[tex]m_{reactant}=m_{chlorine}+m_{nitrogen}[/tex]

In such a way, we can compute the mass of nitrogen as shown below:

[tex]m_{nitrogen}=m_{reactant}-m_{chlorine}=120.4g-106.4g\\\\m_{nitrogen}=14g[/tex]

Best regards.

Answer:

The energy changes form

Explanation:

As the Law of Conservation of energy states, energy can neither be crated nor destroyed. But, it can change form, whether that change is potential to kinetic or energy into heat or entropy, which is to us unusable as it is the energy of disorder.

Answer:

.2mol/L

Explanation:

Answer:

2mol/l

Explanation:

Answer:

132.5 ATPs

Explanation:

We are Given, gadoleic acid has 20 carbons with one unsaturation at carbon number 9.

And we know that For a saturated fatty acid, one beta oxidation cycle results in 1 acetyl CoA molecule, 1 NADH + H+ and 1FADH2. this cycle occurs in 4 steps:

1. Fatty acyl CoA to trans-enoyl CoA: This step produces 1 FADH2

2. trans-enoyl CoA to beta-hydroxyacyl CoA: No reducing power or ATP is produced, Only hydrolysis of trans alkene takes place.

3. beta-hydroxyacyl CoA to beta-ketoacylCoA: This step produces 1 NADH+ H+

4. Release of one Acetyl CoA and fatty acyl CoA chain short of two carbon atoms.

Now, the cycle of gadoleic acid runs in same way till three acetyl CoA molecules are lost forming three FADH2 and three NADH + H+.

After loss of 3 acetyl CoA molecules, carbon number 7 (of actual chain) becomes acyl CoA and so, isomerase comes into action which converts cis double bond between carbon number 9 and Carbon number 10 to trans bond between Carbon number 8 and Carbon number 9. This isomerization then undergoes hydrolysis (as in step 2 of beta oxidation cycle) and step 3 and 4 take place as usual.

The above changes result in release in one acetyl CoA molecule and 1 NADH + H+ but FADH2 is not formed (because step 1 did not occur)

Remaining fatty acyl CoA containing 12 carbons undergoes 5 cycles of beta oxidation to form 6 acetyl CoA, 5 FADH2 and 5 NADH +H+.

So, a total of 10 acetyl CoA, 8 FADH2 and 9 NADH +H+ are formed in beta oxidation of gadoleic acid.

Now, each acetyl CoA on entering citric acid cycle forms 3 NADH + H+, 1 FADH2 and 1 GTP ( = 1ATP)

So, total 10 acetyl CoA from citric acid cycle will form 30 NADH + H+, 10 FADH2 and 10 GTP ( = 10 ATP)

Overall, complete oxidation of gadoleic acid will form, 39 NADH + H+, 18 FADH2 and 10 GTP ( = 10 ATP)

On ETC, assuming 1NADH + H+ to form 2.5 ATP and 1 FADH2 to form 1.5 ATP,

total ATPs formed will be 97.5 ATP (39 NADH + H+), 27 ATP (18 FADH2) and 10 ATP (10 GTP) = 134.5 ATPs

On the beginning of first cycle of beta oxidation, 2 ATPs are used for activation of fatty acid molecule. (these have to be subtracted)

So, net ATP yield = 134.5 - 2 = 132.5 ATPs

The ATP yield of complete oxidation of Gadoleic acid has been 132.5 ATP.

Beta oxidation of fatty acid has been a catalytic process for breaking of fatty acid molecules into acetyl Co A and NADH and FADH that enters the citric acid cycle for the generation of ATP.

The overall reaction for beta-oxidation can be stated as:

[tex]\rm C_n-acyl\;CoA\;+\;FAD\;+\;NAD^+\;+\;H_2O\;+\;CoA\;\rightarrow\;C_n_-_2acyl\;CoA\;+\;FADH_2\;+\;NADH\;+\;H^+\;+\;acetyl-CoA[/tex]

The complete oxidation of saturated even carbon fatty acid will result in :

ATP yield = 7n -6

Where n is the number of carbon

The complete oxidation of saturated odd carbon fatty acid will result in :

ATP yield = 7n - 19

The unsaturated fatty acid having a double bond at odd carbon results in a less [tex]\rm FADH_2[/tex] molecule production, resulting in the formation of 1.5 ATP less than the saturated fatty acid.

The ATP yield of 20 carbon chain Gadoleic acid :

n = 20

ATP yield = 7n - 6

ATP yield = 7 (20) - 6

ATP yield = 140 - 6

ATP yield = 134

Due to unsaturation at C9, there has been a reduction of 1.5 ATP.

ATP yield = 134 - 1.5

ATP yield = 132.5.

The ATP yield of complete oxidation of Gadoleic acid has been 132.5 ATP.

For more information about beta-oxidation, refer to the link:

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Answer:

1.

[tex]A=69.8\frac{bar}{m^6}\\\\ B=0.00302bar*m^6[/tex]

2. [tex]W=-8.2kPa[/tex]

Explanation:

Hello,

1. In this case, for the given p-V equation, one could use the two states to form a 2x2 linear system of equations in terms of A and B:

[tex]\left \{ {{0.1^2A+0.1^{-2}B=1} \atop {0.04^2A+0.04^{-2}B=2}} \right.[/tex]

[tex]\left \{ {{0.01A+100B=1} \atop {0.0016A+625B=2}} \right[/tex]

Whose solution by any method for solving 2x2 linear system of equations (elimination, reduction or substitution) is:

[tex]A=69.8\frac{bar}{m^6}\\\\ B=0.00302bar*m^6[/tex]

2. Now, for us to compute the work, we must first compute n, as the power relating the pressure and volume for this process:

[tex]P_1V_1^n=P_2V_2^n\\\\\frac{P_1}{P_2}=(\frac{V_2}{V_1} )^n\\\\\frac{1bar}{2bar}= (\frac{0.04m^3}{0.1m^3} )^n\\\\0.5=0.4^n\\\\n=\frac{ln(0.5)}{ln(0.4)} =0.7565[/tex]

Now, we compute the work:

[tex]W=\frac{P_2V_2-P_1V_1}{1-n} =\frac{2bar*0.04m^3-1bar*0.1m^3}{1-0.7565} \\\\W=-0.082bar*m^3*\frac{1x10^2kPa}{1bar}\\ \\W=-8.2kPa[/tex]

Regards.

Answer:

a) 2Al + 3Cl2 ⇆ 2AlCl3

b) Cl2 is the limiting reactant.

c)  2.0 moles AlCl3

d) There will remain  3.2 moles Al

Explanation:

Step 1: Data given

Number of moles Al = 5.3 moles

Number of moles Cl2 = 3.0 moles

Step 2: The balanced equation

2Al + 3Cl2 ⇆ 2AlCl3

Step 3: Calculate the limiting reactant

For 2 moles Al we need 3 moles Cl2 to produce 2 moles AlCl3

Cl2 is the limiting reactant. It will completely be consumed. (3.0 moles)

Al is in excess. There will react 2/3 * 3.0 = 2.0 moles

There will remain 5.2 - 2.0 = 3.2 moles

Step 4: Calculate moles AlCl3

For 2 moles Al we need 3 moles Cl2 to produce 2 moles AlCl3

For 3.0 moles Cl2 we'll have 2/3 * 3.0 = 2.0 moles AlCl3

Answer:

being stationary relative to a particular frame of reference or another object; when the position of a body with respect to its surroundings does not change with time it is said to be at rest

Explanation:

Been stationary is the normal resting position of an object

When an object is at rest ( normal resting position ) it is stationary ( i.e. the position of the object does not change with time in relation to its environment or another object/reference  )

When an object is at rest it posses its' highest potential energy and its least kinetic energy. therefore been stationary is the normal resting position of an object.

Hence we can conclude that Been stationary is the normal resting position of an object.

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Answer:

The answer is e - Negative, Exothermic

Explanation:

Kono Dio Da!!

hard because it has calcium and magnesium

Answer:

[tex]m_{PbI_2}=18.2gPbI_2[/tex]

Explanation:

Hello,

In this case, we write the reaction again:

[tex]Pb(NO_3)_2(aq) + 2 KI(aq)\rightarrow PbI_2(s) + 2 KNO_3(aq)[/tex]

In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:

[tex]n_{Pb(NO_3)_2}=\frac{0.14gPb(NO_3)_2}{1g\ sln}*\frac{1molPb(NO_3)_2}{331.2gPb(NO_3)_2} *\frac{1.134g\ sln}{1mL\ sln} *96.7mL\ sln\\\\n_{Pb(NO_3)_2}=0.04635molPb(NO_3)_2\\\\n_{KI}=\frac{0.12gKI}{1g\ sln}*\frac{1molKI}{166.0gKI} *\frac{1.093g\ sln}{1mL\ sln} *99.8mL\ sln\\\\n_{KI}=0.07885molKI[/tex]

Next, as lead (II) nitrate and potassium iodide are in a 1:2 molar ratio, 0.04635 mol of lead (II) nitrate will completely react with the following moles of potassium nitrate:

[tex]0.04635molPb(NO_3)_2*\frac{2molKI}{1molPb(NO_3)_2} =0.0927molKI[/tex]

But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:

[tex]m_{PbI_2}=0.07885molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gPbI_2[/tex]

Best regards.

Answer:

A = 1.2L

B = 506.6 torr

C = 13.5 °C

Answer:

A = 1.2L B = 506.6 torr and C = 13.5 °C

have a nice day :)

Answer:

1.2 atm

Explanation:

Given data

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

[tex]P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm[/tex]

Answer:

Homeostasis is defined as the process by which the internal body system maintains a suitable environment for its proper functions and survival.

When a person temperature drops a signal is sent to the brain which results in a reflex action being observed. The shiver makes the individual warmer and helps in the regulation of the body heat.

Answer:

a)

[H₂O] = 0.0455M

[Cl₂O] = 0.0130M

[HOCl] = 0.0200M

b) Kc = 0.676

c) [H₂O] = [Cl₂O] = 0.177M

Explanation:

Based on the reaction:

H₂O(g) + Cl₂O(g) ⇄ 2HOCl(g)

Kc is defined as:

Kc = [HOCl]² / [H₂O][Cl₂O] For molar concentrations in equilibrium

As volume of the flask is 1.00L, the initial molar concentrations of H₂O and Cl₂O is 0.0555M and 0.0230M, respectively.

In equilibrium, the concentrations are:

[H₂O] = 0.0555M - X

[Cl₂O] = 0.0230M - X

[HOCl] = 2x = 0.0200M → X = 0.0100M

Where X is reaction coordinate

a) Concentrations in equilibrium are:

[H₂O] = 0.0455M

[Cl₂O] = 0.0130M

[HOCl] = 0.0200M

b) Replacing in Kc:

Kc = [0.0200]² / [0.0455][0.0130] = 0.676

c) Initial concentration of HOCl is 1.0mol / 2.0L = 0.50M. In equilibrium concentrations are:

[H₂O] = X

[Cl₂O] = X

[HOCl] = 0.50M - 2X

Replacing in Kc formula:

0.676 = [0.50-2X]² / [X][X]

0.676X² = 4X² - 2X + 0.25

0 = 3.324X² - 2X + 0.25

Solving for X:

X = 0.177M

X = 0.425M → False answer, produce negative concentrations.

As X = [H₂O] = [Cl₂O]; equilibrium concentrations of both compounds is 0.177M

Answer:

SO₂: 0.39atm

O₂: 3.645atm

Explanation:

Based on the reaction:

2 SO₂(g) + O₂(g) → 2 SO₃(g)

2 moles of sulfur dioxide react per mole of oxygen to produce 2 moles of sulfur trioxide.

When the reaction occurs an comes to equilbrium, the partial pressure of each gas is:

SO₂: 1.3atm - 2X

O₂: 4.1atm -X

SO₃: 2X

Where X is the reaction coordinate.

As pressure at equilibrium of SO₃ is 0.91 atm:

0.91atm = 2X

Thus: X = 0.455atm.

Replacing, pressures at equilibrium of the gases are:

SO₂: 1.3atm - 2×0.455atm = 0.39 atm

O₂: 4.1atm -0.455atm = 3.645 atm

Answer:

A) 84 mL

Explanation:

use general gas equation P1×V1 / T1 = P2×V2/T2

rearrange the formula and solve for V2,it should give you V2= 84mL

Answer:

[tex]\large \boxed{\text{B) 84 mL}}[/tex]

Explanation:

We can use the Combined Gas Laws to solve this problem .

[tex]\dfrac{p_{1}V_{1} }{T_{1}} = \dfrac{p_{2}V_{2}}{T_{2}}[/tex]

Data

p₁ = 0.75 atm; V₁ = 120.0 mL; T₁ = 295 K  

p₂ = 1.25 atm; V₂ = ?;              T₂ = 345 K

Calculations

[tex]\begin{array}{rcl}\dfrac{p_{1}V_{1} }{T_{1}} & = & \dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{\text{0.75 atm $\times$ 120.0 mL}}{\text{295 K}} & = & \dfrac{\text{1.25 atm} \times V_{2}}{\text{345 K}}\\\\\text{0.305 mL} & = & \text{0.003 523V}_{2}\\V_{2}& =& \dfrac{\text{0.305 mL}}{0.003523}\\\\& = & \textbf{84 mL}\\\end{array}\\\text{The new volume of the gas is $\large \boxed{\textbf{84 mL}}$}[/tex]

Answer: Learning is essential to our existence. Just like food nourishes our bodies, information and continued learning nourishes our minds. ... Today, continuous learning forms a necessary part in acquiring critical thinking skills and discovering new ways of relating to people from different cultures.

Explanation: Learning is essential to our existence. Just like food nourishes our bodies, information and continued learning nourishes our minds. ... Today, continuous learning forms a necessary part in acquiring critical thinking skills and discovering new ways of relating to people from different cultures.

A valid hypothesis is one that is testable and falsifiable by experimental findings. Thus, A would be the right option.

Hypotheses are general statements with no experimental tests. They can be tested using experiments and be falsifiable if found wanting.

Food security refers to constant access to food of adequate nutritional value by the populace of a place. The access must be both in terms of availability and economic affordability.

If the cost of food has a relationship with their nutritional values, this will definitely affect the food security of a place.

Thus, the only falsifiable hypothesis would be "spending more money on food results in food of higher nutritional value".

More on hypotheses can be found here: https://brainly.com/question/17173491

#SPJ2

Answer:

17202.6 years

Explanation:

Activity of the living sample (Ao) = 160 counts per minute

Activity of the wood sample (A) = 20 counts per minute

Half life of carbon-14 = 5730 years

t= age of the artifact

From;

0.693/t1/2= 2.303/t log Ao/A

Then;

0.693/ 5730= 2.303/t log Ao/A

Substituting values;

0.693/5730= 2.303/t log (160/20)

Then we obtain;

1.209×10^-4 = 2.0798/t

t= 2.0798/1.209×10^-4

Thus;

t= 17202.6 years

Therefore the artifact is 17202.6 years old.

Answer:

made regular payments to the emperor.

Explanation:

The Aztec Empire was an alliance of three states: Mexico-Tenochtitlan, Texcoco, and Tlacopan. The area in and around the Valley of Mexico was ruled by these three city-states from 1428 to 1521. The state religion of the empire was polytheistic. The tribute states of the ancient Aztec empire made regular payments to the emperor.

Answer:

B

Explanation:

Answer:

81.54 °C

Explanation:

Use the equation

q = mcΔT

348 = 20.9(0.902)(100-t)

t = 81.54 °C

*note, you don't have to convert these to kelvin since the difference will be the same

Answer:

98.3 gradius Celsius

Explanation:

This problem is solved using the Ideal Gas Equation

pV = nRT

...

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

Answer:

Option C

Explanation:

The equation for showing gravitational pull or force between two objects is as follows -

[tex]G_f = \frac{G M_1M_2}{r^2}[/tex]

Here Gf is the gravitational force

G is the gravitational constant and

M1 and M2 is the mass of the two objects

As we can see in the equation, that mass of two objects is directly proportional to the gravitational pull between them.

The higher the mass, the higher will be the force.

While on the other hand the distance between the two objects i.e "r" is inversely proportional. The higher the distance between the two objects the lower is the gravitational force between them.

Hence, option C is correct

Explanation:

This picture shows how the moon from earth when it is in position

Answer:

grams H₂O produced = 8.7 grams

Explanation:

Given 2C₂H₆(g) + 7O₂(g) => 4CO₂(g) + 6H₂O(l)

               7g           18g                             ?g

Plan => Convert gms to moles => determine Limiting reactant => solve for moles water => convert moles water to grams water

Moles Reactants

moles C₂H₆ = 7g/30g/mol = 0.233mol

moles O₂ = 18g/32g/mol = 0.563mol

Limiting Reactant => (Test for Limiting Reactant)  Divide mole value by respective coefficient of balanced equation; the smaller number is the limiting reactant.

moles C₂H₆/2 = 0.233/2 = 0.12

moles O₂/7 = 0.08

Limiting Reactant is O₂

Moles and Grams of H₂O:

Use Limiting Reactant moles (not division value) to calculate moles of H₂O.

moles H₂O = 6/7(moles O₂) = 6/7(0.562) moles H₂O = 0.482 mole H₂O yield

grams H₂O = (0.482mol)(18g·mol⁻¹) = 8.7 grams H₂O

Answer:

[tex]pOH=1.3[/tex]

Explanation:

Hello,

In this case, since pH is computed by knowing the concentration of hydrogen ions, one could compute the pOH by knowing the concentration of the hydroxyl ions as in this case which is 0.045M as shown below:

[tex]pOH=-log([OH^-])=-log([0.045])\\\\pOH=1.3[/tex]

Best regards.

Answer:

The pOH of the 0.045 M solution is 1.3

The second option (1.3) is correct

Explanation:

Step 1: Data given

Concentration [OH-] of KOH is 0.045 M

Step 2: Calculate pOH

pOH = -log[OH-]

pOH = -log (0.045)

pOH = 1.3

The answer:

The pOH of the 0.045 M solution is 1.3

The second option (1.3) is correct