Is the proportion A, B, D, or D?

Is The Proportion A, B, D, Or D?

Answers

Answer 1

Answer:

C.)

Step-by-step explanation:

4/20=8/x


Related Questions

What is the value of h(−2) when h(x)=3x+1

Answers

Answer:

h(-2) = -5

Step-by-step explanation:

Step 1: Define

h(x) = 3x + 1

h(-2) is x= -2

Step 2: Substitute and Evaluate

h(-2) = 3(-2) + 1

h(-2) = -6 + 1

h(-2) = -5

Which expression is equivalent to 174 :
(17")(17)
17-2
17-5
017-1
o 173
0 174

Answers

174 is equal to 174 if thats what the last one means

Answer:

174

Step-by-step explanation:

the option c is your answer

[tex]I \: hope \: it's \: help \: you \\ dear[/tex]

Express 4/10 as a decimal number, and identify another decimal number that is equal to it.

4/10 expressed as a decimal number is ___, which is equal to ___.

Answers

Answer:

0.4 or 0.40 or 0.400

Step-by-step explanation:

I am not sure what they are asking, but 4/10 is the same as 40%, which is the same as 0.4 or 0.40 or 0.400

6th grade math teehee​

Answers

Answer:

78 41/50 :)

Step-by-step explanation:

Shanghai Company sells glasses, fine china, and everyday dinnerware. It uses activity-based costing to determine the cost of the shipping and handling activity. The shipping and handling activity has an activity rate of $13 per pound. A box of glasses weighs 2 pounds, a box of fine china weighs 4 pounds, and a box of everyday dinnerware weighs 6 pounds.

a Determine the shipping and handling activity cost to be allocated to each unit of product.

Glasses $
Fine China $
Everyday dinnerware $
b Determine the total shipping and receiving costs to be allocated to the fine china if 5,100 boxes are shipped.
$

Answers

Answer:

glasses 13 times 2 =26 China 13times4=52 dinnerware 13 times 6= 78 fine China 5100 times 4 pounds =20400 pounds times 13 a pound =265200.

Consider the following argument. If there are as many rational numbers as there are irrational numbers, then the set of all irrational numbers is infinite.
The set of all irrational numbers is infinite. ∴
There are as many rational numbers as there are irrational numbers. Let p = "there are as many rational numbers as there are irrational numbers," and let q = "the set of all irrational numbers is infinite."
Is the argument valid or invalid?
Choose the answer that shows the symbolic form of the argument and justifies your conclusion.
a. form: q ∧ p valid, specialization p ∴ q
b. form: p → q invalid, converse error q ∴ p
c. form: q ∧ p invalid, converse error p ∴ q
d. form: p ∨ q invalid, inverse error q ∴ p
e. form: q → p valid, generalization p ∴ q

Answers

Answer:

b. form: p → q invalid, converse error q ∴ p

Step-by-step explanation:

Let

p = "there are as many rational numbers as there are irrational numbers,"

let

q = "the set of all irrational numbers is infinite."

We can write the above argument as:

If there are as many rational numbers as there are irrational numbers, then the set of all irrational numbers is infinite

p → q

The set of all irrational numbers is infinite

q

There are as many rational numbers as there are irrational numbers

p

So collectively it can be written as:

p → q

 q

∴p

So it looks like

if p then q

q

therefore p

This is a fallacious argument.  This means the conclusion can be false even when the premises are true. This type of argument is invalid.

Suppose we know that “If there are as many rational numbers as there are irrational numbers, then the set of all irrational numbers is infinite” is a true conditional statement. We also know that "the set of all irrational numbers is infinite" is true. This is not enough to say that "there are as many rational numbers as there are irrational numbers," is true. The reason for this is that there is nothing logically about “If p then q” and “q” that means p must follow. So this is a converse error and since converse error is an invalid method of inference rule so this argument is invalid.

Let us prove this argument is invalid with a truth table:

p   q   p → q   q   p

T   T      T       T   T

T   F      F       F   T

F   T      T       T   F

F   F      T       F   F

Since we know that the premises are:

p → q   and  q

and the conclusion is p

and an argument is valid if and only if all of its premises are true, then the conclusion is true. We should check that whenever both p → q   and  q are true then p is true but the third row fails. Thus this is an invalid argument.

Tim had 267 dollars to spend on 9 books. After buying them he had $15. How much did each book cost

Answers

$28

267-15=252

252/9=28

Answer:

28$

Step-by-step explanation:

(267-15)/9

I need help with questions 17 and 18, I don't understand them, if you could give a nice explanation ill give you brainliest.

Answers

Answer :

Part 17: The value of x is 5.

Part 18: The value of x is 2°.

Step-by-step explanation :

Part 17:

Given:

Length SR = 2x - 9

Length RQ = x + 6

Length SQ = 12

Now we have to determine the value of x.

Length SQ = Length SR + Length RQ

12 = (2x - 9) + (x + 6)

12 = 2x - 9 + x + 6

12 = 3x - 3

3x = 15

x = 5

The value of x is 5.

Part 18:

Given:

∠MLK = 81x - 2

∠HLK = 54x + 2

∠MLH = 50°

Now we have to determine the value of x.

∠MLK = ∠HLK + ∠MLH

81x - 2 = 54x + 2 + 50°

81x - 2 - 54x - 2 = 50°

27x - 4 = 50°

27x = 54°

x = 2°

The value of x is 2°

A researcher wants to estimate the relationship between years of educational attainment ​(X​) and the average yearly earnings of individuals ​(Y​). For​ this, he collects data from a random sample of individuals. From this​ data, he calculates the sample variances ​(​, ​) and the sample covariance ​(​). If ​, ​, and ​, then the sample correlation coefficient will be nothing. ​(Round your answer to two decimal places​). Which of the following statements can be inferred from the value of the sample correlation coefficient calculated​ above? ​(Check all that apply.​) A. There is a weak linear association between X and Y. B. There is a strong linear association between X and Y. C. The points in the scatterplot lie very close to a straight line. D. The points in the scatterplot have a steep slope. Could the researcher make general inferences about the correlation between X and Y from the sample correlation​ value? A. ​Yes, because the sample correlation is a consistent estimator for the population correlation. B. ​No, because the sample correlation is not an efficient estimator for the population correlation. C. ​Yes, because the sample correlation is an unbiased estimator for the population correlation. D. ​No, because the sample correlation value changes from sample to sample.

Answers

Answer:

The answer is "Option a and Option b".

Step-by-step explanation:

In the given question, the data value is missing which is defined in the attached file, please find it.

We have variance sample =[tex](S^2x, S^2y)[/tex]  and the carariance sample = [tex]Sxy[/tex].  

if "[tex]S^2x = 85.27, S^2y = 175.76, and \ \ Sxy = 116.25[/tex]"  its sample coefficient correlation will be defined as follows:

[tex]\bold{r= \frac{Sxy}{\sqrt{S^2x \times S^2 y}} }\\\\[/tex]

  [tex]= \frac{116.25}{\sqrt{85.23}  \times \sqrt{175.76}} \\\\= \frac{116.25}{ 9.23  \times 13.25}\\\\= \frac{116.25}{122.29}\\\\=0.95[/tex]

what is the Measure of <X <Y and <Z​

Answers

Answer:

<x=60

z= 90

<y = 30

Step-by-step explanation:

<x=60 cause 180-120=60

z= 90 cause it is a right angle

<y = 30 cause 180-150 =30.

Forty percent of seeds from maize (modern-day corn) ears carry single spikelets, and the other 60% carry paired spikelets. A seed with single spikelets will produce an ear with single spikelets 29% of the time, whereas a seed with paired spikelets will produce an ear with single spikelets 26% of the time. Consider randomly selecting ten seeds.

a. What is the probability that exactly five of these seeds carry a single spikelet and produce an ear with a single spikelet?

b. What is the probability that exactly five of the ears produced by these seeds have single spikelets? What is the probability that at most five ears have single spikelets?

Answers

Answer:

a)P ( A∩S) =  0.116

b) P (x= 5) =0.272

c)  P (at most 5) = 0.950647

Step-by-step explanation:

Let A be an event that the  maize (modern-day corn) ears carry single spikelets and B be an event that the  maize carry paired spikelets.

Then P (B) = 60% = 0.6

P (A) = 1-P (b) = 0.4

Let S be the event that seed with single spikelets will produce an ear with single spikelets and Q be the event that seed with  paired spikelets will produce an ear with single spikelets .

Then

P (S) = 29% = 0.29

P (Q ) = 26% = 0.26

n= 10

We want to find out that exactly 5 single spikelets  seeds produce single spikelets .

P ( A∩S) = P(A) *P(S) = 0.4 * 0.29= 0.116

Now we have to find that exactly five of the ears produced by these seeds have single spikelets.

b) P (x= 5) =  P(A) *P(S)+  P(B) *P(R)

= 0.4 * 0.29 + 0.6 * 0.26

= 0.116+ 0.156= 0.272

At most five ears have single spikelets.This follows a binomial distribution where n is fixed and also p and q are same.

P ( x= at most 5) = 10C5 ( 0.116)^ 5(0.884)^5 +10C4 ( 0.116)^ 4(0.884)^6+10C3 ( 0.116)^ 3(0.884)^7+10C2 ( 0.116)^ 2(0.884)^8 +10C9 ( 0.116)^ 1(0.884)^9+10C10 ( 0.116)^ 0(0.884)^10    

=0.002857+0.018145+ 0.0000234+0.2558+ 0.3824+ 0.29144

= 0.950647

Evaluate the following.

Answers

4, then 13. Since the 4 is positive it doesn’t need to change, and 13 is negative therefore it will be positive

12. Which of the following is the value of x needed to make the equation
true? *
10 poin
-18 + 3x + x = -4x + 50
A. X = 11.3
B. X = 4.5
C. X = 8.5
D. X = -4.5
Back
Next
Page 3 of 11

Answers

Answer:

it will be c, x=8.5

Step-by-step explanation:

-18+4x=-4x+50

4x+4x=18+50

8x=68

x=8.5

joe and mark each make a number pattern joe starts with 18 and uses the rule add 3 mark starts with 28 and uses the rule 3 which statement about corresponding terms in the pattern is true Each term in marks pattern is 3 more than the corresponding term in joes pattern? each term in marks pattern is 10 more than the corresponding term in joes pattern ? (C) the difference between a term in marks pattern and the corresponding term in joes patter is always a multiple of 4 ? D) the difference between a term in marks pattern and the corresponding term in joes pattern is always a multiple of 5?

Answers

Answer:

Each term in marks pattern is 10 more than the corresponding term in joes pattern

Step-by-step explanation:

Given

Joe

[tex]Start = 18[/tex]

[tex]Additional = 3[/tex]

Mark

[tex]Start = 28[/tex]

[tex]Additional = 3[/tex]

Required

Determine which option answers the question

From the question, we have that Mark and Joe have the same additional rule of increment.

This implies that, the difference of each term is the same as the difference of the starting number of both:

Since Mark started at a higher number than Joe, the difference can be said to be.

[tex]Difference = Start_{Mark} - Start_{Joe}[/tex]

[tex]Difference = 28 -18[/tex]

[tex]Difference = 10[/tex]

Hence:

Option B answers the question

Please Subtract the Following Fractions.

12/16 − 2/4
Question 4 options:

10/12


10/16


4/16

Answers

¡Hola!

Your answer to the question is 10/12.

Step-by-step explanation:

By using the y^2-y^1/x^2-x^1

12-2= 10

16-4= 12

So your answer is 10/12.

Hope this Helps!

five more than a certain number is 4 less than one-half that number. what is the number.

Answers

The answer should be 8

The number which is represented by the expression "five more than a certain number is 4 less than one-half that number" is -2/3

let

the unknown number = x

x + 5 = 4 - 1/2x

x + 1/2x = 4 - 5

1 1/2x = -1

x = -1 ÷ 3/2

= -1 × 2/3

= -2/3

Therefore, the number which is represented by the expression "five more than a certain number is 4 less than one-half that number" is -2/3

Learn more about equation:

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The following data represent the weights​ (in grams) of a random sample of 50 candies.


0.87 0.88 0.82 0.90 0.90 0.84 0.84
0.91 0.94 0.86 0.86 0.86 0.88 0.87
0.89 0.91 0.86 0.87 0.93 0.88
0.83 0.95 0.87 0.93 0.91 0.85
0.91 0.91 0.86 0.89 0.87 0.84
0.88 0.88 0.89 0.79 0.82 0.83
0.90 0.88 0.84 0.93 0.81 0.90
0.88 0.92 0.85 0.84 0.84 0.86


Required:
a. Determine the sample standard deviation weight.
b. Use the Empirical Rule to determine the percentage of M&Ms with weights between 0.803 and 0.947 gram. Hint: = 0.875.
c. Determine the actual percentage of M&Ms that weigh between 0.803 and 0.947 gram, inclusive.
d. Use the Empirical Rule to determine the percentage of M&Ms with weights more than 0.911 gram.
e. Determine the actual percentage of M&Ms that weigh more than 0.911 gram.

Answers

Answer:

a)0.03558

b) 95%

c) 95.6985%

d) 16%

e)15.58%

Step-by-step explanation:

a) Determine the sample standard deviation weight.

Step 1

We find the Mean

Sum of terms/ Number of terms

Number of terms = 50

= 43.73/50

= 0.8746 grams

≈ 0.875 grams

Formula for sample standard deviation = √(x - Mean)²/n - 1

= √0.062042/50 - 1

= √0.001266163265

= 0.03558318796 grams

The empirical rule formula:

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

b. Use the Empirical Rule to determine the percentage of M&Ms with weights between 0.803 and 0.947 gram. Hint: = 0.875.

95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

μ – 2σ

0.875 - 0.03558 × 2

= 0.80384

μ + 2σ

= 0.875 + 0.03558 × 2

= 0.94616

Hence, 95% of M&Ms with weights between 0.803 and 0.947 gram.

c. Determine the actual percentage of M&Ms that weigh between 0.803 and 0.947 gram, inclusive.

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

For x = 0.803

= 0.803 - 0.875/0.03558

= -2.02361

Probability value from Z-Table:

P(x = 0.803) = 0.021505

For x = 0.947

= 0.947 - 0.875/0.03558

= = 2.02361

Probability value from Z-Table:

P(x = 0.947) = 0.97849

Hence,

P(x = 0.947 ) - P(x = 0.803)

= 0.97849 -0.021505

= 0.956985

Converting to percentage

= 0.956985 × 100

= 95.6985%

d. Use the Empirical Rule to determine the percentage of M&Ms with weights more than 0.911 gram.

68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

=Mean = 0.875

Standard deviation = 0.03558

μ + σ

0.875 + 0.03558

= 0.91058

≈ 0.911

Hence, 68% of M&Ms with weights more than 0.911 gram.

Therefore, percentage of M&Ms with weights more than 0.911 gram, is on the right hand side(one side of the distribution)

=( 100 - 68)%/2

= 32%/2

= 16%

e. Determine the actual percentage of M&Ms that weigh more than 0.911 gram

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean = 0.875

Standard deviation = 0.03558

x = 0.911

= 0.911 - 0.875/0.03558

= = 1.0118

Probability value from Z-Table:

P(x<0.911) = 0.84418

P(x>0.911) = 1 - P(x<0.911) = 0.15582

Converting to percentage =

0.15582 × 100

= 15.58%

Lauder Company had fixed costs of $282,500, variable costs of $645,000, and actual sales amounted to $1,100,000. If the company has a break-even point at $750,000 in sales revenue.a. determine the margin of safety expressed in dollars
b. determine the margin of safety expressed as a percentage of sales. Enter percentage amount as a whole number.
____%
c. Determine contribution margin ratio
_____%
d. Determine the operating income
$______

Answers

The Operating income is $172,500.

To calculate the margin of safety, contribution margin ratio, and operating income, we need to use the given information.

a. Margin of Safety:

Margin of Safety = Actual Sales - Break-even Sales

Given that the break-even point is at $750,000 in sales revenue and actual sales are $1,100,000, we can calculate the margin of safety:

Margin of Safety = $1,100,000 - $750,000 = $350,000

Therefore, the margin of safety is $350,000.

b. Margin of Safety as a Percentage of Sales:

Margin of Safety Percentage = (Margin of Safety / Actual Sales) * 100

Using the values from the previous calculations:

Margin of Safety Percentage = ($350,000 / $1,100,000) * 100 = 31.82%

Therefore, the margin of safety expressed as a percentage of sales is approximately 31.82%.

c. Contribution Margin Ratio:

Contribution Margin Ratio = (Contribution Margin / Sales) * 100

To calculate the contribution margin, we need to subtract variable costs from sales:

Contribution Margin = Sales - Variable Costs = $1,100,000 - $645,000 = $455,000

Using the values, we can calculate the contribution margin ratio:

Contribution Margin Ratio = ($455,000 / $1,100,000) * 100 = 41.36%

Therefore, the contribution margin ratio is approximately 41.36%.

d. Operating Income:

Operating Income = Sales - Variable Costs - Fixed Costs

Using the values provided:

Operating Income = $1,100,000 - $645,000 - $282,500 = $172,500

Therefore, the operating income is $172,500.

For more questions on Operating .

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Solve the triangle. Round to the nearest tenth.
Find c aswell

Answers

Answer:

Set your calculator to Degree mode.

a² = 17² + 20² - 2(20)(17)cos(89°)

a² = 677.13236

a = 26.0 in.

sin(89°)/26.02177 = (sin B)/17

sin B = 17sin(89°)/26.02177

B = 40.8°

C = 50.2°

This model represents an equation

•write an equation that could be used to solve x

•solve the equation x.​

Answers

Answer:

[tex] 5x - 1 = -6 [/tex]

[tex] x = -1 [/tex]

Step-by-step explanation:

The model above shows a weigh balance which can be represented by an equation have two sides, of which must be equal to each other.

On the right of the equation, we have 5 "x" and 1 "-", which can be represented as: [tex] 5x - 1 [/tex].

On the other side, we have 6 "-1", which can be represented as: -6.

The equation that can be used to solve x is:

[tex] 5x - 1 = -6 [/tex]

Solve for x. Add 1 to both side

[tex] 5x - 1 + 1 = -6 + 1 [/tex]

[tex] 5x = -5 [/tex]

Divide both sides by 5

[tex] \frac{5x}{5} = \frac{-5}{5} [/tex]

[tex] x = -1 [/tex]

Answer:

Equation: 5x - 1 = -6

x = -1

Step-by-step explanation:

Hello!

The equation is 5x - 1 = -6.

Solve for x by isolating the variable.

Solve for x5x - 1 = -65x = -5x = -1

The value of x is -1.

a large bag contains 11/12 pound of nails how many 1/3 pound bags can be filled with this amount of nails​

Answers

Answer:

2 with a left over 3/12

Step-by-step explanation:

1/3 translates to 4/12 which can go into 11/12 twice, leaving 3/12 left over.

k-2km =1. Solve for m. Show steps. Simplify as much as possible

Answers

Step-by-step explanation:

-km = 1

M = 1

-k

That is the answer

Is the ratio 5 6 equivalent to 3 4

Answers

Answer:

No, it is not

Step-by-step explanation:

5 cant be simplified even down further unless it is a decimal or a fraction

Classify the four angles of the quadrilateral

Answers

Answer:

<A= right

<B= acute

<C= obtuse

<D=  right

Step-by-step explanation:

what is the opposite 3.78

Answers

-3.78 the opposite of positive numbers is always negative.

Answer:

-3.78

Step-by-step explanation:

The opposite of a positive number will always be negative, and the opposite of a negative number will always be positive.

Clara has a package of six cookies she wants to share equally among her friends if Claire make sure that each piece of cookie will be 3/5 of a cookie she can share cookies among blank friends

Answers

Answer:

Clara can feed 10 friend

I may be wrong, but I tried :P

Will give brainliest if they answer

Answers

Answer:

Y=3

Step-by-step explanation:

Bc im right

hey uh guys i need help pls thanks

Answers

i don’t know for sure but i just figured it out....

Describe fully the single transformation that maps shape A onto shape B.
y

Answers

Answer:

The single transformation in this figure is reflection through the y axis at 2 y axis

If my answer helped, please mark me as the brainliest!!

Thank You!!

Michelle already owns 26 hair bands, and additional hair bands are priced 1 for a dollar With $21 to spend on new hair bands how many total hair bands can Michelle own

Answers

Answer:

47

Step-by-step explanation:

starts off with 26 and has $21 to spend, if there each $1 then she can buy 21 more so the answer is 26+21 which = 47

Other Questions
Find the slope and the y-intercept of the line: 6x + 7y = 52 Q5. Is the Capital Asset Pricing Model now irrelevant given thatother factors have been developed? Island Novelties, Inc., of Palau, makes two products, Hawaiian Fantasy and Tahitian Joy. Present revenue, cost, and sales data for the two products as follow:Hawaiian FantasyTahitian JoySelling price per unit$15$100Variable expenses per unit$9$20Number of units sold annually20,0005,000Fixed expenses total $475,800 per year.Required:Assuming the sales mix given above, do the following:A. Prepare a contribution format income statement showing both dollar and percent columns for each product and for the company as a whole.B. Compute the break-even point in dollar sales for the company as a whole and the margin of safety in both dollars and percent. Start with the journal papers tab, record the May transactions that occurred they are listed below in B. Each transaction does require an entry. Refer to the pages of t-accounts for a list of the company's accounts. B. The following transactions describe business activity for Tommy's Boat & Tackle during May of 2021: May 1: The company generated $35,000 from the sale of its common stock. May 4: $9,800 of equipment was purchased with a $800 cash down payment. The balance should be paid within the next 90 days. May 6: Tommy, on behalf of the company, signed a 5-year note, borrowing $24,750 from the local bank. May 7: Tommy's crew completed a fishing boat customization job for the Smiths; a bill for $24,000 was sent to the customer. May 9: The company paid its workers May wages of $5,615. May 11: Tommy's Boat & Tackle purchased $15,250 of supplies on account. May 14: One of Tommy's employees completed $15,400 of repairs on fishing gear and received payment immediately. May 16: The company paid half of the amount owed on the equipment purchased on May 4. May 22: Tommy's Boat & Tackle paid cash dividends of $10,500 to its shareholders. May 25: The Smiths paid Tommy's one-half of the amount described in the May 7 transaction. May 29: A bill in the amount of $520 for the company's May electric service arrived but was not immediately paid. It was not paid until the following month. May 31: One of Tommy's employees completed $7,500 of repairs on account. Think of an activity you did today. Describe at least five different parts of your brain and how they were involved in that activity. 1. What did the Chinese typically accept when trading their goods If Hal multiplies one side of the equation below by 7, what does he need to do to balance the equation? 56 + 124 = 180 A Add 7 to the other side. B Subtract 7 from the other side. C Divide each side by 7. D Multiply the other side by 7. Nathan BrownsonBrownson was born in Woodbury, Connecticut, in 1742, to Abigail and Timothy Brownson. After he graduated from Yale University in New Haven, Connecticut, in 1761, Brownson studied to become a physician and went on to practice medicine in Connecticut. He appears to have married three times: first, in 1769, to Elizabeth Lewis; then to Elizabeth Dunham (or Donnom) in 1774; and finally to Elizabeth McLean in 1776. There were two children from his marriage to McLean.In 1774 Brownson moved from Connecticut to Riceboro, Georgia, just south of Midway, in Liberty County. He quickly became a leader of the resistance to British tyranny. Brownson was one of the representatives from St. Johns Parish to the second full Provincial Congress, which met in Savannah in July 1775. On October 9, 1776, Georgians chose him as a delegate to the Continental Congress and reelected him to a second term on June 7, 1777.The Georgia patriots were deeply divided. Economic status, family ties, politics, religion, geography, and the tensions generated by the defeats on the battlefield and British occupation of Georgia all contributed to the rise of two factions, one radical and one conservative, among the Georgia patriots during the Revolutionary War. At times it seemed that these two Georgia factions fought more with each other than they did with the British. In spite of his strong conservative beliefs, Brownson showed by his voting record in Congress that he was willing to consider the views of his political opponents. His proven ability to work with people of varying political beliefs probably helped to elect him governor in 1781.After the British were driven out of Augusta in June 1781, however, the future of Georgia as an independent and free state depended on bringing these two warring factions together to reconstitute the states government. To lead them in this effort, the people of Georgia turned to Brownson, the physician and statesman, in the hope that he could begin the process of healing the wounds caused by the strife between the radical and conservative factions. On August 17, 1781, Brownson was unanimously elected speaker of the assembly, which then elected him governor.Governor Brownson immediately set out to secure Georgia "against the machinations of Public and Private Enemies" and to take measures designed to restore peace, tranquility, and prosperity to the state. During his brief term of office the government of Georgia implemented measures to encourage the return of citizens who had fled the state because of the hardships of the war, and it passed legislation designed to obtain food and clothing for those whose farms and businesses were ruined by the war. The state also had to provide a defense against the continued threat of British troops and bands of armed Tories. On January 2, 1782, John Martin was elected to succeed Brownson as governor of Georgia.Brownsons career in public service continued after his term as governor. In June 1782 he was appointed deputy purveyor for southern hospitals. In the 1780s he served as a representative in the Georgia House of Assembly. He was a member of the Georgia convention that ratified the U.S. Constitution in 1788. In 1789 he served in the convention that rewrote Georgias constitution. He became the first president of the new Georgia senate and served in that office from 1790 to 1791. He joined with Abraham Baldwin, another Yale graduate, in working for the creation of a state-supported institution of higher education, which would become known as the University of Georgia.On October 18, 1796, Nathan Brownson died at his home in Riceboro.Question: briefly discuss Nathan Brownson's role in the American Revolution in Georgia. david wants to get attention from college football scouts to get a scholarship. which is the best way to give them the information? Define the problem k-independent set. b) Explain why the brute force method for solving k-clique runs in polytime if k is constant but in (2 n ) time when k=n/2. c) Give a polytime answer-preserving transformation T from k-clique to k-independent set (so T takes as input an instance of k-clique and gives as output an instance of k-independent set). Prove that T is polytime. Prove that T is answer-preserving. Evaluation methods are not equally suited to all designquestions.Question 16 options:TrueFalse Josh is about to open an American inspired food truck making a variety of lunch options, drinks and even selling coffee. He is planning to operate it around Adelaide CBD, relocating as needed. Josh already created a social media presence for his upcoming launch and is really eager to get it off the ground. He is a little nervous however since he invested quite a bit of money and wants to make sure he is successful. He has asked you for advice since you are studying marketing. Explain to Josh the benefits and disadvantages of his distribution channel (while also explaining other options). Do you think Josh made the right call by selecting this particular distribution channel/option (explain your reasoning)? Convert the polar coordinate to Cartesian coordinates. Easy with a lot of points Help me solve these three problems!! Question Completion Status: A Moving to another question will save this response. Question 5 The cost of land improvements includes fencing paving parking areas and lighting True False & Moving to ano Which of the following statements about high-status individuals is FALSE? A. High-status individuals disregard pressure from lower-ranking members of other groups. B. High-status people resist conformity pressures more than their lower-status peers. C. High-ranking individuals need and care about the group's social rewards. D. Bringing high-status members into a group may improve performance. E. High-status individuals may deviate from norms when they have low identification with the group. Plz help me and solve step by stepThank you. Jorgen Von Strangle brings a copy of the book holeswith him everywhere; he really cant put it down. Situation I On January 1, 2020, Marin, Inc. signed a fixed-price contract to have Builder Associates construct a major plant facility at a cost of $4,145,000. It was estimated that it would take 3 years to complete the project. Also on January 1,2020 , to finance the construction cost, Marin borrowed $4,145,000 payable in 10 annual installments of $414,500, plus interest at the rate of 10%. During 2020, Marin made deposit and progress payments totaling $1,554,375 under the contract; the weighted-average amount of accumulated expenditures was $829,000 for the year. The excess borrowed funds were invested in short-term securities, from which Marin realized investment income of $256,600. What amount should Marin report as capitalized interest at December 31, 2020? Capitalized interest \$ eTextbook and Media Attempts: 0 of 3 used Situation II During 2020, Headland Corporation constructed and manufactured certain assets and incurred the following interest costs in connection with those activities. All of these assets required an extended period of time for completion. Assuming the effect of interest capitalization is material, what is the total amount of interest costs to be capitalized? The total amount of interest costs to be capitalized $ eTextbook and Media Attempts: 0 of 3 used Part 3 Situation III Sage, Inc. has a fiscal year ending April 30. On May 1, 2020, Sage borrowed $9,766,000 at 11% to finance construction of its April 30, 2021, weighted-average accumulated expenditures were $3,418,100. Interest earned on the unexpended portion of the loan amounted to $634,790 for the year. How much should be shown as capitalized interest on Sage's financial statements at April 30, 2021? Capitalized interest on Sage's financial statements $ the language processing centers of the brain are activated when a person listens to and processes music, even when the music contains no words.