The statement "the system is at equilibrium" and the statement "chemical transformations are no longer occurring in the system" are not synonymous.
In a chemical system, "equilibrium" refers to a state in which the rate of the forward reaction is equal to the rate of the reverse reaction. At this state, the concentration of the reactants and products remains constant, but the chemical reactions are still occurring, just at a slower rate.
On the other hand, "chemical transformations are no longer occurring in the system" would imply that there is no chemical reaction happening at all.
So while it is possible for a system to be at equilibrium and for chemical transformations to no longer be occurring, they are not the same thing. It's also possible for a system to be at equilibrium but for chemical transformations to still be occurring, just at a slower rate.
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Two nuclei each contain two protons and exert a force 4 N on each other. If we transfer a proton from one of these nuclei to the other, the force on each nucleus is now reduced to 3 N. True or False? Why?
Answer:
True
Explanation:
Using Coulomb's Law:
[tex]4 Newtons = Force = k*q_1*q_2/r^2.[/tex]
Plug in the values for the original charges and you get
[tex]4 Newtons = F = 4 *k*e^2/r^2[/tex] where a proton as a charge +e.
Dividing both sides by 4 you get that k*e^2/r^2 = 1 newton.
Now plugging in the new charges after moving the proton around:
[tex]F = 3*k*e^2/r^2.[/tex]
We know that k*e^2/r^2 = 1 newton so the net force that each nuclei has on each other is 3 Newtons.
A kangaroo can jump over an object 2.6 m high. show answer incorrect answer 50% (a) Calculate its vertical speed when it leaves the ground.
(b) How long is it in the air?
The kangaroo that can jump over an object 2.6 m high has:
(a) vertical speed when it leaves the ground of: 7.138 m/s(b) time in the air of: 1.456 sWhat is vertical launch upwards?In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.
The formulas for the vertical launch upward and the procedures we will use are:
y max = v₀²/(2*g)t max = v₀/ gt(of)=2*t maxWhere:
v₀ = initial velocityg = gravityy max = maximum heightt max = time to reach maximum heightt(of) = time of flightGiven info:
y max= 2.6 mg = 9.8 m/s²v₀ = ?t max =?t(of) =?Applying the maximum height formula and clearing the initial velocity we get:
v₀ = √(y max * (2*g))
v₀ = √( 2.6 m * (2 * 9.8 m/s²))
v₀ = √( 2.6 m * 19.6 m/s²)
v₀ = √50.96 m²/s²
v₀ = 7.138 m/s
Applying the maximum time formula we get:
t max= 7.138 m/s / 9.8 m/s²
t max =0.728 s
Applying the time of flight formula, we get:
t(of) =2 * t max
t(of) =2 * 0.728 s
t(of) = 1.456 s
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determine the total pressure of a gas to make sure that contains gas one at 1.3 atm, gas two at 15 PSI, and gas three at 1480 torr
The total pressure of the gasses in the container is 43.64 PSI.
What is the total pressure of the gas?
The total pressure of the gas is equal to the sum of the individual partial pressure of the gas.
The total pressure of the gasses in the container is calculated as follows;
P ( tot) = P1 + P2 + P3
where;
P1 is the pressure of gas 1 = 1.3 atm = 0.025 PSIP2 is the pressure of gas 2 = 15 PSIP3 is the pressure of gas 3 = 1480 torr = 28.61 PSIThe total pressure of the gasses in the container is calculated as;
P ( tot ) = 0.025 PSI + 15 PSI + 28.61 PSI
P ( tot ) = 43.64 PSI
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Analyzing Gravitational Data Quick Check
Students want to design an experiment to study gravity. They decide they will drop four objects with the same mass from
the top of their school's bleachers. They will time how long each object takes to reach the ground. How can they improve
confidence in the experiment's results? (1 point)
O Randomly select the order in which the objects are dropped.
O Drop each object 10 times and use the average of each object's fall times.
O Let a different student time the drop of each object.
O Drop all four objects at once.
The confidence level can be improved by; Drop each object 10 times and use the average of each object's fall times. Option B
How does gravity affect a falling body?Gravity affects a falling body by accelerating it towards the ground at a rate of 9.8 m/s^2 (on Earth's surface). The force of gravity is proportional to the mass of the body and the acceleration due to gravity, and it acts in the direction of the center of the Earth.
Hence the acceleration due to gravity is the acceleration that have been imparted to an object dur to the gravitational pull on the object.
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True or False : The sketch of the millimeter scale as it appears using the low-power objective would appear larger than when using the scanning objective magnification.
True. The sketch of the millimetre scale as it appears using the low-power objective would appear larger than when using the scanning objective magnification.
What is magnification?Magnification is the process of enlarging something's apparent size—not its actual size. A calculated number, also known as "magnification," is used to measure this enlargement. When this number is less than one, it refers to a reduction in size, also known as magnification or de-magnification.
Magnification typically refers to enlarging visuals or images in order to see more detail, boosting resolution, using a microscope, printing methods, or digital processing. The perspective of the image is unaffected by magnification in every situation.
Optical magnification is a dimensionless number because it measures how an object's apparent size (or size in an image) compares to its actual size.
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a toy truck initially at rest at the top of a hill is allowed to roll down without friction. at the bottom its speed is 14 km/hr. next, the truck is again rolled down the hill, but this time it does not start from rest. it has an initial speed of 6 km/hr on top as it starts going down the hill.
The speed of the toy truck when it reaches the bottom is 15,23 km/hr.
Motion of Objects on an Inclined PlaneAn object placed on an inclined plane will move in a straight line parallel to the inclined plane if there is no force acting on it. The object will move with speed "v" and acceleration "a" until finally the object will stop or stop moving. In the motion of objects on an inclined plane there are forces that work so as to explain how the motion of objects passing on an inclined plane.
Given,
The toy start from the hill.
[tex]u_{1}[/tex] = 0 km/hr
[tex]v_{1}[/tex] = 14 km/hr
[tex]u_{2}[/tex] = 6 km/hr
Steps,
Let the acceleration "a" and distance "s'".
[tex]v_{1} ^{2} - u_{1} ^{2} = 2as[/tex].........(1)
After that, the truck is rolled down from the hill with a speed 6 km/hr.
[tex]u_{2} = 6 km/hr\\v_{2}=?[/tex]
[tex]v_{2} ^{2} - u_{2} ^{2} = 2as[/tex].........(2)
Solve (1) & (2)
[tex]v_{1} ^{2} - u_{1} ^{2} = 2as\\v_{2} ^{2} - u_{2} ^{2} = 2as\\[/tex]
___________ -
[tex]-v_{2} ^{2} = -v_{1} ^{2} +u_{1} ^{2}-u_{2} ^{2}[/tex]
Substitute the values
[tex]-v_{2} ^{2} = -12^{2} + 0^{2} - 6^{2}\\v_{2} ^{2} = 12^{2} - 0^{2} + 6^{2}\\v_{2}^{2} = 232\\v_{2} = 15,23 km/hr[/tex]
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Suppose a 2.5um wide slit produces its first minimum for 405nm light. A) Calculate the angle at which this occurs for the 405nm light in degrees. B) where is the first minimum in degrees for 740nm light?
A) To calculate the angle at which the first minimum occurs for 405nm light, we need to use the equation θ = λ/d, where θ is the angle in degrees, λ is the wavelength of the light, and d is the slit width. Thus, for 405nm light, we have θ = 405nm/2.5um = 162°.
B) To calculate the angle for 740nm light, we can use the same equation, so θ = 740nm/2.5um = 296°. Thus, the first minimum for 740nm light occurs at an angle of 296°.
on earth, with its atmosphere, which of these parts of the spectrum can astronomers view from the ground?
Astronomers can view the optical (visible light) portion of the spectrum from the ground.
Which of these spectrum regions can observers on the ground see?
Observers on the ground can see a range of different parts of the electromagnetic spectrum, including visible light, ultraviolet, infrared, and radio waves. Visible light is the light that human eyes are able to detect, and it is made up of the colors of the rainbow.
Ultraviolet light has a higher frequency than visible light, and it is sometimes referred to as "black light." Infrared radiation has a lower frequency than visible light, and it is responsible for making objects appear warm.
Finally, radio waves have the lowest frequency of all, and they are used to transmit data from place to place. All of these different parts of the electromagnetic spectrum can be observed by observers on the ground.
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How does the marble demonstrate the law of conservation of energy as it rolls from point 1 to
The energy transforms and the total amount of energy decreases.
The energy transforms, but the total amount of energy remains the same.
The energy transforms, the total increases then decreases.
The energy transforms, but the total amount of energy is doubled.
The energy transforms, but the total amount of energy remains the same.
How does the marble demonstrate the law of conservation of energy?The marble demonstrates the law of conservation of energy because the energy the marble has when it is released at the top of the ramp is equal to the energy it has when it reaches the bottom.
The marble's potential energy at the top of the ramp is converted into kinetic energy as it rolls down the ramp, but the total energy of the marble remains the same. The marble is an example of the law of conservation of energy because the total energy of the marble is the same at both positions.
As the marble rolls down the ramp, the potential energy is converted into kinetic energy, but the total energy remains the same. The law of conservation of energy states that energy cannot be created or destroyed, but can be converted from one form to another.
The marble is a perfect example of this law because its energy is simply converted from one form to another.
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A baseball pitcher throws the ball in a motion where there is rotation of the forearm about the elbow joint as well as other movements. If the linear velocity of the ball relative to the elbow joint is 20.0 m/s at a distance of 0.480 m from the joint and the moment of inertia of the forearm is 0.500 kg ⋅ m2 , what is the rotational kinetic energy of the forearm?
The rotational kinetic energy of the forearm is 41.7 J.
What is kinetic energy?Kinetic energy is a form of energy that is associated with the motion of an object. It is the energy that an object has due to its motion. Kinetic energy can be calculated by multiplying half of the object’s mass with the square of its velocity. The SI unit of kinetic energy is Joules (J). Kinetic energy is used in many different fields such as physics, engineering, and thermodynamics.
The rotational kinetic energy of the forearm can be calculated using the equation KErot = (Iω^2) / 2, where I is the moment of inertia and ω is the angular velocity.
The angular velocity can be calculated by dividing the linear velocity (v) by the radius (r): ω = v/r.
Therefore, the rotational kinetic energy of the forearm is:
KErot = (Iω^2) / 2 = (0.500 kg ⋅ m2) * ((20.0 m/s) / (0.480 m))^2 / 2 = 41.7 J
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a piece of iodine is heated from 50 celcius to 197 celcius. what state of matter would we expect it to be in
Answer:
liquid
Explanation:
In a compound microscope the objective and the eyepiece have focal lengths of 0.95 cm and 5 cm respectively, and are kept at a distance of 20 cm. The last image is formed at a distance of 25 cm from the eyepiece.The position of object and the total magnification are
a. 95/94 cm in front of field lens 94
b. 80/79 cm in front of the field lense, 93
c. 70/65 cm in front of the field lense, 65
d. 60/55cm in front of the field lense, 50
A) In a compound microscope, the focal lengths of the objective and eyepiece are 2.0 cm and 3.0 cm, respectively.
The eyepiece's final picture is formed at infinity and the objective and eyepiece are separated by 15.0 cm. Both lenses are quite narrow.
f \s0 \s \s =0.95cm
f \se \s \s =5cm
L=20cm
v \se \s \s =25cm
U \s0 \s \s =? M=?
L D =v 0 + D+fe Dfe
20=v \s0 \s \s + \s \s30 \s6
25× \s \s5
6 \s95 \s \s =v \s0 \s
95 \s6 \s \s − \sv \s0
1 \s \s = \s95 \s100
− \sv \s0 \s
1 \s \s = \s95 \s94
v \s0 \s \s =− \s94 \s95 \s \s cm
M \sD \s \s = \sv \s0 \s
v \s0 \s
\s (1+ \sfe \sD \s \s )
M \sD \s \s = \s94 \s95
6 \s95
\s (1+ \s5 \s25 \s \s )
= \s6×98 \s95×94 \s \s ×6
=94
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Estimate the maximum height in feet that you can throw a baseball straight up. (a) For this height, how long after the ball leaves your hand does it return to your hand? (b) Estimate the distance in feet that the ball moves while you are throwing it, that is, the distance from where the ball is when you start your throw until it leaves your hand, Calculate the average acceleration in m/s that the ball has while it is being thrown, as it moves from rest to the point where it leaves your hand.
This question is incomplete. the complete question is :
a) Suppose that the estimate of the maximum height that a player can throw a baseball is 25 ft. For how long after the ball leaves the player's hand does it return to the players hand.b) Suppose that the estimate of the distance that the ball moves while a player is throwing it is 2.5 feet -- that is, the distance from where the ball is when the player starts their throw until it leaves their hand. Calculate the magnitude of the average acceleration in m/s2m/s2 that the ball has while it is being thrown, as it moves from rest to the point where it leaves the player's hand.Answer:
a) Total time of Flight is 2t is 2.49 secondsb) The magnitude of the average acceleration is 98.03 m/s²The Step is :
a) Maximum height = 25 ft = (25 /3.281) = 7.62 m
For how long after the ball leaves the player's hand does it return to the players hand;
= gt²
we know that g = 9.81 m/s²
so we substitute
7.62 m = × 9.81 m/s² × t²
7.62 m = 4.905m/s² × t²
t² = 7.62 m / 4.905
t² = 1.5535
t = √1.5535
t = 1.246 s
So total time of Flight is 2t = 2 × 1.246 s = 2.49 seconds
b) given that distance = 2.5 ft = ( 2.5 / 3.281) = 0.762 m
V = ?
from the First Equation of Motion
v = u + at
0 = u - 9.81 × 1.246 s
u = 12.2232 m/s
so from the Third Equation of Motion : v² = u² + 2as
(12.2232 m/s)² = 0² + 2 × a × 0.762 m
149.4066 = 1.524a
a = 149.4066 / 1.524
a = 98.03 m/s²
Therefore, the magnitude of the average acceleration is 98.03 m/s²
What is the Baseball ?Bissboll also known as baseball, is a sport played by two teams. Throwers (pitchers) from the throwing team try to throw a ball called a baseball, while players (batters) from the hitting team try to hit the ball using a bat (bat). The game of baseball was born in the United States, which was created by George Hancoc in the city of Chicago in 1887. Initially baseball was played only for recreational activities and was carried out in a closed field. But it turned out that in a short time baseball actually became a game that was much-loved by the people there. Until finally famous throughout the world
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It takes 2.49 seconds after the ball leaves your hand and it return to your hand. The average acceleration the ball has while it is being thrown, as it moves from rest to the point where it leaves your hand is 98.03 m/s².
Maximum height = 25 ft = (25 /3.281) = 7.62 m
How long after the ball leaves the player's hand does it return to the players hand can be calculated as follows
v = gt²
we know that g = 9.81 m/s²
so we substitute
7.62 m = × 9.81 m/s² × t²
7.62 m = 4.905m/s² × t²
t² = 7.62 m / 4.905
t² = 1.5535
t = √1.5535
t = 1.246 s
So total time of Flight is 2t = 2 × 1.246 s = 2.49 seconds
b) distance = 2.5 ft = ( 2.5 / 3.281) = 0.762 m
from the First Equation of Motion
v = u + at
0 = u - 9.81 × 1.246 s
u = 12.2232 m/s
so from the Third Equation of Motion :
v² = u² + 2as
(12.2232 m/s)² = 0² + 2 × a × 0.762 m
149.4066 = 1.524a
a = 149.4066 / 1.524
a = 98.03 m/s²
Therefore, the magnitude of the average acceleration is 98.03 m/s²
Your question is incomplete but most probably the complete question is :
Suppose that the estimate of the maximum height that a player can throw a baseball is 25 ft. Estimate the maximum height in feet that you can throw a baseball straight up. (a) For this height, how long after the ball leaves your hand does it return to your hand? (b) Estimate the distance in feet that the ball moves while you are throwing it, that is, the distance from where the ball is when you start your throw until it leaves your hand, Calculate the average acceleration in m/s that the ball has while it is being thrown, as it moves from rest to the point where it leaves your hand.
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identify and explain three factors that contribute to the high use of oil despite the limited supplies.
Factors that contribute to the high use of oil despite the limited supplies are levels of oil consumption, oil reserves, global exchange rates.
Levels of oil consumption, oil reserves, global exchange rates, environmental issues, politics, and oil speculation on the financial markets are the factors that contribute to the high use of oil despite the limited supplies.
As the population is increasing day by day the demand of oil is also increasing along with increasing population which is leading to the high use of oil despite of the fact that the supply of the oil is limited as any thing on this earth cannot be unlimited.
The price of oil depend on the three main factors: current supply, future supply, and expected global demand.
The world has proven reserves equivalent to 46.6 times its annual consumption levels. This means it has about 47 years of oil left (at current consumption levels and excluding unproven reserves).Generally, if the oil supply increases, prices respond by going down and rising if supply decreases, it basically depend upon the demand . if demand decreases, prices should decrease and rise if demand increases.
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Astronauts collected a lunar rock with a mass of 73 grams. What was the rock’s weight when they brought it back to Earth?
Answer: approximately 0.7154 Newtons.
The weight of an object can vary depending on the gravitational force acting upon it. On the moon, the gravitational force is about 1/6th of the Earth's gravity. To find the weight of the lunar rock when brought back to Earth, we need to consider Earth's gravity.
To calculate the weight of an object, we use the formula:
Weight = mass × gravity
Given that the mass of the lunar rock is 73 grams, we need to convert it to kilograms by dividing it by 1000:
Mass in kilograms = 73 grams ÷ 1000 = 0.073 kg
Now we can calculate the weight of the lunar rock on Earth. Earth's gravity is approximately 9.8 m/s².
Weight on Earth = 0.073 kg × 9.8 m/s² = 0.7154 Newtons (N)
A student at the top of a building throws a red ball upward with speed v0 and then throws a blue ball downward with the same initial speed v0. Immediately before the two balls reach the ground, which of the following statements are true? (Choose all correct statements; neglect air friction.) (a) The speed of the red ball is less than that of the blue ball. (b) The speed of the red ball is greater than that of the blue ball. (c) Their velocities are equal.
(d) The speed of each ball is greater than v0. (e) The acceleration of the blue ball is greater than that of the red ball.
A student at the top of a building throws a red ball upward with speed v0 and then throws a blue ball downward with the same initial speed v0. Immediately before the two balls reach the ground. The true statement is (c) Their velocities are equal.
SPEED AND VELOCITY(Velocity) is a vector quantity that is a quantity that has a direction of motion while speed is a scalar quantity that is without considering the direction of motion.
Both speed and speed are measured in m/s, km/hour or miles/hour.
In daily application and use Speed is used to estimate the time needed by an object such as a vehicle to reach a certain distance while driving which can be observed in the movement of the speedometer. Whereas the Velocity scale is usually used to calculate the time needed by a storm to reach the coastline or other applications can be used to calculate the time needed for a rocket to reach the moon.
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Calculate the kinetic energy of an object of mass 10kg when it is moving with a velocity 2ms
The kinetic energy of the mass will be 20 Joules.
Given:
mass [tex]m[/tex] = 10 kg
velocity [tex]v[/tex] = 2 m/s
To find:
Kinetic energy KE =?
Solution:
KE = [tex]\frac{1}{2}[/tex][tex]mv^{2}[/tex]
= [tex]0.5[/tex] x [tex]10[/tex] x [tex]2^{2}[/tex]
= [tex]20[/tex] [tex]joules[/tex] [tex]or[/tex] [tex]kg.m/s^{2}[/tex]
For reference:
https://www.geeksforgeeks.org/practice-problems-on-kinetic-energy/
Answer: The answer is the kinetic energy of the object is 20 joules .
Explanation: we know that ,
here, mass= 10 kg;
velocity = 2m/s
The kinetic energy of the object = 1/2×mass×(velocity)²
= 1/2×10kg×(2m/s)²
=1/2×10 ×4kg(m/s)²
=5×4 joules
= 20 joules or
0.02 kilo joules
one of the most massive stars known is Eta Carinae which has an approximate mass of 120 Ms. Based on the arguments of scientists 1,2 and 3, respectively, what is the minimum number of stars, each formed entirely by accretion, that would have been required to form Eta Carinae?
Eta Carinae formerly known as Eta Argus, is a stellar system containing at least two stars with a combined luminosity greater than five million times
What is Eta Carinae?
A star and its surrounding nebula in the constellation Carina: the star was brighter than every star except Sirius in the 1840s and now is of fourth magnitude; the nebula is the brightest infrared object in the nighttime sky.Estimated to be 100 times more massive than our Sun, Eta Carinae may be one of the most massive stars in our Galaxy. It radiates about five million times more power than our Sun. The star remains one of the great mysteries of stellar astronomy, and the new Hubble images raise further puzzles.This extraordinary star is among the most luminous and most massive stars known to exist at about 4 million times the brightness and 120 times the mass of our sun, it is dangerously close to the theoretical limit for a star. Eta Carinae belongs to a rare class of stars called Luminous Blue Variables, or LBVs.To learn more about Eta Carinae refers to:
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a copper wire has a radius of 1 [mm]. the wire is carrying a current of 1 [a] in the positive z direction. determine the velocity vector of the electrons inside the copper wire (hint: see the similar example in notes 3, as use the same parameters for the copper as in this example.)
The velocity vector of the electrons can be represented as:
v = v_d * z = v_d * (0, 0, 1)
where z is the unit vector in the positive z direction.
To determine the velocity vector of the electrons inside the copper wire,
we can use the drift velocity formula, which relates the drift velocity of electrons to the electric current and the density of electrons in a conductor.
The drift velocity can be calculated as:
v_d = I / (neA)
where I is the current,
n is the number of electrons per unit volume, e is the charge of an electron, and
A is the cross-sectional area of the wire.
For copper, n can be calculated as:
n = (8.5 x 10^28 electrons/m^3) * (density of copper / 63.54 g/cm^3)
With a wire radius of 1 mm, the cross-sectional area can be calculated as:
A = πr^2
= π * (1 x 10^-3 m)^2
So, plugging in the values, we have:
v_d = 1 A / (n * A)
= 1 A / (8.5 x 10^28 electrons/m^3 * π * (1 x 10^-3 m)^2)
The velocity vector of the electrons is in the same direction as the current, which is the positive z direction,
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A 900 kg car traveling 11.2 m/s crashes into a pile of hay and comes to a stop in 4.6 s. Calculate the force.
Answer:To calculate the force, we can use the formula:
force = mass x acceleration
In this case, the car starts at a velocity of 11.2 m/s and comes to a stop in 4.6 seconds, so the acceleration is:
(0 m/s - 11.2 m/s) / 4.6 s = -2.4 m/s^2
We can then use this to calculate the force:
force = 900 kg x (-2.4 m/s^2) = -2160 N
Note that the negative sign indicates that the force is in the opposite direction of the car's motion. This makes sense, as the force is acting to stop the car.
Answer:
-2,187 N
Explanation:
Please find the attachment for detail
A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 5.70 m/s. Air resistance may be ignored, so the water balloon is in free fall after it leaves the thrower's hand.a) What is its speed after falling for 2.00 s?b) How far does it fall in 2.00 s?c) What is the magnitude of its velocity after falling 10.0 m?How do I sketch a-1, V-t, and yet graphs for the motion of the balloon?
Speed after falling for 2.30 seconds = 37.74 m/s. The water balloon drops 60.88 meters in 2.3 seconds. The speed following an 11.0 m fall is 21.13 m/s
Find the velocity?Using the motion equations
g = 9.8 m/s²
Initially moving at 15.2 m/s
velocity at t = 2.3 seconds.
a) v = u + gt
v = 15.2 + 9.8×2.3
v = 37.74 m/s
y = ut + gt2/2 (b)
y = (15.2×2.3) + 9.8(2.3²)/2
y = 60.88 m
c) v² = u² + 2g
v² = 15.2² + (2×9.8×11)
v = 21.13 m/s
Speed after falling for 2.30 seconds = 37.74 m/s. The water balloon drops 60.88 meters in 2.3 seconds. The speed following an 11.0 m fall is 21.13 m/s
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a stationary golf ball is hit by a club. while the club is in contact with the ball, the ball compresses, the club exerts maximum force when the ball is at maximum compression, and then the ball expands. the momentum of the golf ball after contact with the club is represented by the vector above. which of the following groups of vectors could represent the force exerted on the ball at the three moments described?
The momentum of the gold ball that represents the force exerted on the ball at the three moments described is vector B.
Momentum is a vector quantity resulted from the mass of a particle and its velocity. Momentum represents the force acting on the particle. Momentum is the implication of Newton's Second Law. Momentum can be formulated as:
P = m.v
where:
P = momentum
m = mass
v = velocity
Following the three moments, we can identify the vector that represent the force exerted on each moment. Let's discuss them further.
Once the golf ball is hit by a club from its stationary position, the force exerted on the golf ball will be in the same direction to the club movement. We assume in this case that the club hits the ball from the left to right. The force will move the ball from its stationary position to the right.
Once the ball is at maximum compression, the force is also at its maximum point. The direction of the force remains as the previous moment.
Lastly, once the ball starts to expand, the force declines. The ball will come to its end position once the momentum of the force becomes zero (0). The momentum of the force will decline since the force direction changes to the left as resulted of the frictional force from the air.
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Complete Question:
A stationary golf ball is hit by a club. while the club is in contact with the ball, the ball compresses, the club exerts maximum force when the ball is at maximum compression, and then the ball expands. the momentum of the golf ball after contact with the club is represented by the vector above. which of the following groups of vectors could represent the force exerted on the ball at the three moments described?
(Please refer to the picture attached below)
The photograph below shows a girl pushing on a large stone sphere. The sphere has a mass of 8200 kg and a radius of 90 cm and floats with nearly zero friction on a thin layer of pressurized water. Suppose that she pushes on the sphere tangent to its surface with a steady force of F = 25 N and that the pressured water provides a frictionless support. How long will it take her to rotate the sphere one time, starting from rest?
The time required for a girl to rotate the sphere one time, starting from rest, is 19.256 s.
A measure of an object's resistance to changes in its rotating motion, the moment of inertia, is used in physics. It measures the amount of mass disposed about a rotational axis. The equivalent of mass in linear motion is the moment of inertia in rotational motion.
The inertia is given by:
I = (2/5)m×r²
I = (2/5) × 8200 kg × (0.9m)²
I = 2657 kg·m²
The torque is given by:
τ = I×α
25 × 0.9 = 2657 × α
α = 0.00846 rad/s²
The angular displacement is:
Θ = ½α×t²
2π rads = ½ × 0.00846 × t²
t =√(4π rads/0.0106rad/s²)
t = 19.256 s
Hence, the time required for a girl to rotate the sphere one time, starting from rest, is 19.256 s.
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consider a uniform line charge with potential phi that satisfies laplacian equation and has cylindrical symmetry. use gauss law to find electric field and integrate it to find potetial.g
Gauss' Law applies to all shapes, as I always remind my students. A charge could be placed within a cube and the flux could be calculated without it having to be a sphere.
With the aid of Gauss's law, how can you determine the electric field?We can instantly calculate the electric field at a point at height z from a uniformly charged plane in the xy-plane using the equations for flux and enclosed charge in Gauss's law: Ep=020n.Equation E=kQ/r2 allows us to calculate the electric field produced by a point charge.Gauss' Law applies to all shapes, as I always remind my students. A charge could be placed within a cube and the flux could be calculated without it having to be a sphere. The internal charge will remain constant, hence the overall flux will remain constant. What shape is used is irrelevant.To learn more about Gauss' Law refer to:
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Soul is a music genre that evolved from the song made out of lonliness by
Answer:
false
Explanation:
kasi false info fake news
What does an object with more mass require, according to Newton's second law of motion?
O more distance to accelerate
Oless speed to accelerate
O more force to accelerate
Oless force to accelerate
Thus according Newton's 2nd law of motion, heavier objects require more force to accelerate.
Describe a force.At this point, it's appropriate to refer to a force as a push or a pull. The idea of a force encompasses both living and non-living phenomena. Large particles are always in motion thanks to electrostatic and electric and magnetic forces, while the perturbation theory is always moving thanks to the weak and powerful nuclear forces.
In what ways does force combine?Given that it has both orientations and magnitude, a vector quantity describes a force. It is calculated and use the newton SI unit (N). F is the symbol for force (formerly P). In no particular sequence, the list includes gravity, electromagnetics, the moderate nuclear force, and in fact, the greater nuclear force.
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reckless rick is driving along the road at 80 km/h and bumps into hapless harry, who is directly in front of him and is driving at 88 km/h. what is the speed of the collision?
Answer:
hdiszvkebxobezuwkwhdkd
Explanation:
csiejusjixjdabsijzjeod
A slingshot fires a pebble from the top of a building at a speed of 13.0 m/s. The building is 22.0 m tall. Ignoring air resistance, find the speed with which the pebble strikes the ground when the pebble is fired (a) horizontally, (b) vertically straight up, and (c) vertically straight down.
The magnitudes of displacemwent `vec a and vec b` are 3 m anad 4m, respectively, and `vec c = vec a + vec b.` Considering various orientations of `vec a and vec b,` what are (a) the maximum possible magnitude for `vec c and (b)` the minimum possible magnitude ?
The maximum possible value of the vector is 7, and the minimum possible value is 1.
A vector is an object that possesses both the magnitude and the direction of the variable that it represents. Calculating the length of a vector is a necessary step in determining its magnitude, which requires us to first determine the vector's length. When the two vectors are headed in the same direction, the maximum possible value is obtained. The value of s that is found to be the minimum possible value when both vectors are headed in the opposite direction.
Thus,
The maximum possible magnitude:
|A| + |B| = 3 + 4 = 7
The minimum possible magnitude:
|A| - |B| = |3| - |4| = 1
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Imagine that you are a Greek philosopher living 2,000 years ago. If you were to lecture on the structure of the Universe to students. which of the following statements would help your students distinguish between stars and planets? Choose one or more: A. Planets make up constellations. B. Stars appear much larger in the sky than do planets. C. Planets move in complex paths independent of stars.D. Stars appear to revolve around a fuxed point. E. Stars have rays of light shooting out in all directions.
Option E, which states that stars emit light in all directions, Identify the differences between planets and stars.
In which universe is Earth located?In the Virgo Supercluster of galaxies, which contains Earth, are situated. A grouping of galaxies called a supercluster is bound by gravity. The Local Group, a smaller collection of galaxies within this supercluster, is where we are located.An object with brightness that causes it to independently reflect light is referred to be a star. In contrast, a planet is only a fixed celestial entity that rotates on its own axis and has its own orbit, but it also reflects light from other sources.Option E, which states that stars emit light in all directions, Identify the differences between planets and stars.To learn more about universe refer to:
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