It cost Ximena $3.40 to send 68 text messages. How
many text messages did she send if she spent $2.45?

Answers

Answer 1

Answer:

49 text messages

Step-by-step explanation:

3.49/68 = 0.05 oer text

we can use this unit rate for text sent $2.45

$2.45/.05 per text message = 49 text messages


Related Questions

A storage locker measures 8 feet wide, 12 feet deep, and 9 feet high. The monthly rental price for the locker is $3.60 per cubic yard. How much does is cost to rent the locker each month? Complete the explanation to show your answer.

Answers

Answer:

The cost is $115.20

Step-by-step explanation:

The locker is 8ft by 12ft by 9ft.

The volume is:

V = 8 × 12 × 9

V = 864 cubic feet

But the price is given by cubic yards so we need to find that first. (we have cubic feet)

A cubic yard is

1yd × 1yd × 1yd

And a yard is 3 feet, so that is the same as:

3ft × 3ft × 3ft

= 27cubic feet

Divide:

864/27

= 32

The locker is 32 cubic yards.

The price is $3.60 per cubic yard. Multiply.

32 × 3.60

= 115.2

The cost of the locker will be $115.20.

What is the value of x in the right triangle below?
Show your work and round your answer to the nearest hundredth.

Answers

Answer:

[tex]x = \sqrt{ {28.46}^{2} - {27}^{2} } = \sqrt{80.9716} = 9.00[/tex]

You have ​$11. 40 to buy drink boxes for the football team. Each drink box costs ​$0. 40 How many drink boxes can you​ buy? Should you expect to get change when you pay for the drink​ boxes? If​ so, how​ much?

Answers

The total number of boxes purchased using $11.40 and the remaining expected changed money received is 28 boxes and $0.20 respectively.

Total amount of money to buy drink boxes = $11.40

Cost of each drink box = $0.40

Number of drink boxes bought

= $11.40 ÷ $0.40/drink box

= 28.5 drink boxes

Since you cannot buy a fractional part of a drink box.

Round down to the nearest whole number.

Here,  28 drink boxes can be bought with the available money.

To determine expect change,

Subtract the total cost of the drink boxes from the amount of money available.

$11.40 − ($0.40/drink box × 28 drink boxes)

= $11.40 − $11.20

= $0.20

The amount of change is $0.20.

Therefore,  the number of boxes bought with given amount is 28 boxes and the remaining expected amount of money received is $0.20 .

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Multiplying a whole number by a proper fraction, results in a ___ product.


A. larger

B. smaller

Answers

Answer:

The answer to your problem is, A. Larger

Step-by-step explanation:

First in order to know to the answer lets learn about different types of fractions:

For example, 1/4, 3/4, 3/8, are all proper fractions.

4/3, 5/2, are all improper fractions.

When we have to multiply a whole number with fractions less than 1, then the resulting number will be less the number originally

Example; 3 x [tex]\frac{3}{4}[/tex]

If we then multiplying numerators together and the denominators together.

3 x [tex]\frac{3}{4}[/tex] = [tex]\frac{3}{1}[/tex] x [tex]\frac{3}{4}[/tex] = [tex]\frac{9}{4}[/tex] = 2[tex]\frac{1}{4}[/tex] < 3

Example /\

Thus the answer to your problem is, A. Larger OR Multiply.

Question 8 (1 point ) Classify the system as consistent independent, inconsistent, or coincident. 3x-6y=-12 x-2y=-4

Answers

Equations in the system are accurate and coincident.

Solve the system using any approach, such as elimination or substitution, and then categorize the equations as consistent independent, inconsistent, or coincident.

Using the substitution technique:

x - 2y = -4 => x = 2y - 4

Substituting x = 2y - 4 into the first equation:

3x - 6y = -12

3(2y - 4) - 6y = -12

6y - 12 - 6y = -12

-12 = -12

Identity -12 = -12 is a constant. Since the two equations represent the same line and have an infinite number of solutions, the system of equations is consistent and coincident.

Any value of y can be chosen, and x = 2y - 4 can be used to calculate the equivalent value of x.

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An ice field is melting at the rate M (t)=4-(sin t)³ acre-feet per day, where t is measured in
days. How many acre-feet of this ice field will melt from the beginning of day 1 (t = 0) to the
beginning of day 4 (t = 3) ?
(A) 10.667
(B) 10.951
(C) 11.544
(D) 11.999

Answers

A 11.544 acre-feet of this ice field will melt from the beginning of day 1 (t = 0) to the beginning of day 4 (t = 3). So, correct option is C.

To solve the problem, we need to integrate the given rate of melting with respect to time over the interval [0,3] to find the total amount of ice that melts during this time.

First, we can simplify the given rate of melting by using the identity: sin³(t) = (3sin(t) - sin(3t))/4

So, M(t) = 4 - (3sin(t) - sin(3t))/4 = 16/4 - 3sin(t)/4 + sin(3t)/4 = 4 - 0.75sin(t) + 0.25sin(3t)

Integrating this expression with respect to t over the interval [0,3], we get:

[tex]\int\limits^3_0[/tex] M(t) dt = [tex]\int\limits^3_0[/tex] (4 - 0.75sin(t) + 0.25sin(3t)) dt

= [4t + 0.75cos(t) - (1/3)cos(3t)]|[0,3]

= (12 + 0.75cos(3) - (1/3)cos(9)) - (0 + 0.75cos(0) - (1/3)cos(0))

= 11.544

Therefore, the answer is (C) 11.544.

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The circle graph describes the distribution of preferred transportation methods from a sample of 300 randomly selected San Francisco residents.

circle graph titled San Francisco Residents' Transportation with five sections labeled walk 40 percent, bicycle 8 percent, streetcar 15 percent, bus 10 percent, and cable car 27 percent

Which of the following conclusions can we draw from the circle graph?

Bus is the preferred transportation for 25 residents.
Bicycle is the preferred transportation for 48 residents.
Together, Streetcar and Cable Car are the preferred transportation for 42 residents.
Together, Walk and Streetcar are the preferred transportation for 165 residents.

Answers

The correct conclusions which can we draw from the circle graph is,

⇒ Together, Walk and Streetcar are the preferred transportation for 165 residents.

Given that;

The circle graph describes the distribution of preferred transportation methods from a sample of 300 randomly selected San Francisco residents.

And, Circle graph titled San Francisco Residents Transportation with five sections labeled walk 40 percent, bicycle 8 percent, streetcar 15 percent, bus 10 percent, and cable car 27 percent.

Hence, For Walk and Streetcar;

(40 + 15)% of 300

55% of 300

55/100 x 300

55 x 3

165

Thus, The correct conclusions which can we draw from the circle graph is,

⇒ Together, Walk and Streetcar are the preferred transportation for 165 residents.

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What is the area of this figure?

Answers

Answer: 288

Step-by-step explanation:

2 × 6 × 2 × 4 × 3=288

that is a very good question i think it is 21

Write a linear function f with the values f(10)=5 and f (2) =-3

Answers

The linear function f with the values f(10) = 5 and f(2) = -3 is f(x) = x - 5.

Write a linear function f with the values f(10) = 5 and f(2) = -3

The formula for equation of line is expressed as;

y = mx + b

Where m is slope and b is y-intercept.

hence, to write a linear function f with the values f(10) = 5 and f(2) = -3, we need to find the slope and y-intercept of the function.

The slope of a linear function can be found by using the formula:

Slope m = (y2 - y1) / (x2 - x1)

Using the values of f(10) = 5 and f(2) = -3,

we can find the slope:

Slope m = (5 - (-3)) / (10 - 2)

= 8 / 8

= 1

Now that we have the slope, we can use the point-slope form to find the equation of a line:

y - y1 = m(x - x1)

Where m is the slope and (x1, y1) is one of the points on the line.

Using the point (10, 5) and slope m = 1, we have:

y - y1 = m(x - x1)

y - 5 = 1(x - 10)

Simplifying, we get:

y - 5 = x - 10

y = x - 5

f(x) = x - 5

Therefore, the linear function is f(x) = x - 5.

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Find the surface area of the square pyramid shown below with base edge lengths of 4 units and a side height of 3 units.

Answers

Answer:

The surface area of the square pyramid is approximately 28.2 square units.

Explanation:

The base area and the areas of each triangle face must be determined to calculate the surface area of a square pyramid.

Since the base is a square with four units for each edge, its area is:

The base area equals 42 to 16 square units.

We must determine the length of the slant height, which is the height of each triangular face, to get the area of each triangle.

The Pythagorean theorem may be used to get the slant height: a2 + h2 = s2,

where an equals half the base's length (2 units), h is similar to the pyramid's size (3 units), and s is the slant height.

Inputting the values, we obtain:

2^2 + 3^2 = s^2

4 + 9 = s^2

13 = s^2 s = √13

Using the following formula, we can now get the area of each triangle face:

The area of the triangular face equals 0.5 base height, where the base is the slant height (13 units), and the size is the square base's edge length (4 units).

The triangular face area equals 0.5 x 4 x 13 = 213 square units.

Given that there are four triangular faces, their combined area is:

Units of area: 4 x 2 x 13 = 8 x 13

The total surface area is then calculated by summing the base and triangle face areas:

Base area plus triangle face area equals total surface area.

Surface area total = 16 + 8 x 13

28.2 square units total surface area (rounded to the nearest decimal point)

Therefore, the square pyramid's surface area is around 28.2 square units.

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Which function is shown in the graph below?

Answers

The function that is shown in the graph is y = √(2x - 6) + 1

Which function is shown in the graph?

From the question, we have the following parameters that can be used in our computation:

The graph

The parent function of the graph is

y = √2x

The graph is shifted right by 6 units

So, we have

y = √(2x - 6)

The graph is shifted up by 1 unit

So, we have

y = √(2x - 6) + 1

hence, the function is y = √(2x - 6) + 1

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does anybody understand this problem? please help i’ll award whatever the things are

Answers

In the triangle the value of JL is 14.

Let us find the value of KJ which is hypotenuse

8²+6²=KJ²

64+36=KJ²

KJ=10

From the triangle KLM

tan 45= opposite side/adjacent side

1=6/ML

ML=6

So JL = 8+6

=14

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Express the function graphed on the axes below as a piecewise function.​

Answers

The piecewise function in the graph is:

f(x) = 3   if -8 < x < - 2

f(x) = -0.5x + 5 for -2 < x - 6

How to define the piecewise function?

First we can see a constant segment at y = 3 that starts at x = -8 and ends at x = -2

So we have:

f(x) = 3   if -8 < x < - 2

Then we have a line that starts at x = -2, and ends at x = 6

We can see that the y-intercept is 5, then we can write:

y = ax + 5

It also passes through (4, 3), replacing that:

3 = a*4 + 5

3 - 5 = a*4

-2 = a*4

-2/4 = a

-0.5 = a

Then the second part is:

f(x) = -0.5x + 5 for -2 < x - 6

The piecewise function is:

f(x) = 3   if -8 < x < - 2

f(x) = -0.5x + 5 for -2 < x - 6

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I NEED HELP ASAP
i am in need of help quickly

Answers

Answer:

25ft

Step-by-step explanation:

your summer job pays you $20 an hour (y=20x) and work every week between 5 to 20 hours

Answers

The solution is: y = 30x, is the equation for total pay (y) as a function of total hours worked (x).

Here, we have,

Because we are talking about over 8 hours.

The question states that you get 30$ per hour for overtime hours.

That means if you work over 8 hours your dollars per hour increases to 30.

So because the amount of dollars increases to 30 you can infer that all you have to do is make the same equation as the 20 dollar's per hour equation.

Except you put 30 making it y = 30x.

Hence, The solution is: y = 30x, is the equation for total pay (y) as a function of total hours worked (x).

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complete question:

A company pays $20 per hour for up to 8 hours of work, and $30 per hour for overtime hours (hours beyond 8 hours). For up to 8 hours worked, the equation for total pay (y) for hours worked (x) is y = 20x. For over 8 hours worked, what is the equation for total pay (y) as a function of total hours worked (x)?

The International Space Station orbits the Earth at a height of 250 miles.
What is the height of the International Space Station in kilometres?
Use 8 kilometres equals 5 miles.
km?

Answers

Using unit conversions, the height of  the International Space Station in kilometers is 400 kilometers.

What is unit conversion?

Unit conversion enables the conversion of one unit to another.

Division and multiplication operations are heavily deployed in unit conversions.

These two basic mathematical operations help create the conversion factors for unit conversions.

The orbiting height of the International Space Station = 250 miles

5 miles = 8 kilometers

250 miles = 250 x 8/5 kilometers

= 400 kilometers

Thus, a height of 250 miles is the same as a height of 400 kilometers.

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The table shows the running time for different movies.

Create a line plot to display the data. To create a line plot, hover over each number on the number line. Then click and drag up to plot the data.

Answers

Answer:

Step-by-step explanation:

can some one help me? i'll give you my discord to help with more im failing math

Answers

Answer:

Angle BAC

Step-by-step explanation:

The actual angle letter (in this case A) is ALWAYS in the center. The first and last letters are the ends of the lines that make the angle (B and C). You can put the first and last letters as BAC OR CAB, because either way you are describing the same angle.

I hope this helps :)

Does the graph show a proportionalrelationship? Explain

Answers

Answer:

yes

Step-by-step explanation:

If the graph of a relationship is a line or a ray through the origin, then it is proportional. If it is a line or ray that does not pass through the origin, then it is not proportional. Also, if it is not linear, then it is not proportional.

Find z₁ X 2₂ for z₁ = 9 (cos 225° + i sin 225°) and z2 = 3 (cos 45° + i sin 45°). Express the product in
a + bi form.

Answers

Answer:

-3+0i

Step-by-step explanation:

have a good day :)

100 POINTS!!!
Students were asked to prove the identity (cot x)(cos x) = csc x − sin x. Two students' work is given.

Student A

Step 1: cosine x over sine x times cosine x equals cosecant x minus sine x

Step 2: cosine squared x over sine x equals cosecant x minus sine x

Step 3: 1 minus sine squared x over sine x equals cosecant x minus sine x

Step 4: 1 over sine x minus sine squared x over sine x equals cosecant x minus sine x

Step 5: csc x − sin x = csc x − sin x
Student B

Step 1: cotangent x times cosine x equals 1 over sine x minus sine x

Step 2: cotangent x times cosine x equals 1 over sine x minus sine squared x over sine x

Step 3: cotangent x times cosine x equals 1 minus sine squared x over sine x

Step 4: cotangent x times cosine x equals cosine squared x over sine x

Step 5: cotangent x times cosine x equals cosine x over sine x times cosine x

Step 6: cot x cos x = cot x cos x


Part A: Did either student verify the identity properly? Explain why or why not.

Part B: Name two identities that were used in Student A's verification and the steps they appear in.

Answers

Neither student's work properly verifies the identity and  csc x = 1/sin x,  sin² x + cos² x = 1 are the  two identities that were used in Student A's verification.

Part A:

Both Student A and Student B did not verify the identity properly. Student A started with the correct expression, but then manipulated it incorrectly.

In Step 1, multiplying cosine x over sine x times cosine x does not equal cosecant x minus sine x.

In Step 2, dividing cosine squared x by sine x also does not equal cosecant x minus sine x. Student B also started with the correct expression, but made a mistake in Step 2.

Subtracting sine squared x over sine x from 1 does not equal 1 over sine x minus sine squared x over sine x.

Therefore, neither student's work properly verifies the identity.

Part B:

Identity 1: csc x = 1/sin x

Student A uses this identity in Step 4 when they rewrite 1/sin x as csc x.

Identity 2: sin² x + cos² x = 1

Student A uses this identity in Step 3 when they rewrite cos² x as 1 - sin²x.

Hence, neither student's work properly verifies the identity and  csc x = 1/sin x,  sin² x + cos² x = 1 are the  two identities that were used in Student A's verification.

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Triangle ABC has vertices with A(x,3), B(-3,-1), C(-1,-4). Determine and state a value of x that would make triangle ABC a right triangle. Justify why trinagle ABC is a right angle

Answers

The value of x that would make triangle ABC a right triangle is x= 2. The justification is that the product of the slopes of two perpendicular lines is -1/2, and when the points are plugged into the distance formula, the sides satisfy the Pythagorean theorem.

To determine a value of x that would make triangle ABC a right triangle, we need to check if the square of the length of any two sides equals the square of the length of the third side.

We can use the distance formula to find the lengths of the sides of the triangle

AB = √((x + 3)² + 4²)

BC = √(2² + 3²)

CA = √((x + 1)² + 1²)

To make triangle ABC a right triangle, we need to find a value of x that satisfies the Pythagorean theorem

AB² + BC² = CA²

[(x + 3)² + 4²] + [2² + 3²] = [(x + 1)² + 1²]

Simplifying this equation yields

x² + 2x - 8 = 0

Solving for x, we get

x = 2 or x = -4

So, if x = 2 or x = -4, then triangle ABC is a right triangle.

To justify this, we can find the slopes of the line segments connecting the vertices of the triangle

mAB = (3 - (-1)) / (x - (-3)) = 4 / (x + 3)

mBC = (-4 - (-1)) / (-1 - (-3)) = -3/2

mCA = (3 - (-4)) / (x + 1 - (-1)) = 7 / (x + 2)

When x = 2, we get

mAB = 4/5

mBC = -3/2

mCA = 7/3

mAB * mBC = -2/5

mBC * mCA = -7/6

mCA * mAB = 14/15

when x = 2, triangle ABC is right triangle.

When x = -4, we get

mAB = 4/(-1) = -4

mBC = -3/2

mCA = 7/(-3) = -7/3

mAB * mBC = 6

mBC * mCA = 14/3

mCA * mAB = 7/2

when x = -4, triangle ABC is not a right triangle.

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a teacher surveyed his class about how many wore watches and how many wore rings. the venn diagram shows her results. if a person from the class is randomly selected, what is the probability that person wears a watch given that they wear a ring?

Answers

The probability of selecting a person who wears a watch given that they wear a ring is 2/5 or 0.4.

From the Venn diagram, we can see that there are 10 people who wear rings, 2 of whom also wear watches. This means that the probability of randomly selecting a person who wears a ring is 10 out of the total number of people in the class. That is:

P(Ring) = 10 / (10+2) = 10/12

Similarly, we can find the probability of selecting a person who wears both a watch and a ring. From the diagram, we can see that there are 4 such people. Thus,

P(Watch and Ring) = 4 / (10+2) = 4/12

Using the formula for conditional probability, we get:

P(Watch|Ring) = P(Watch and Ring) / P(Ring)

Substituting the values we obtained earlier, we get:

P(Watch|Ring) = (4/12) / (10/12) = 4/10 = 2/5 or 0.4

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Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.
lim ln(5x)/√5x
x→[infinity]

Answers

To find the limit of ln(5x)/√5x as x approaches infinity, we can use l'Hospital's Rule since it is an indeterminate form of ∞/∞.

Taking the derivative of the numerator and denominator separately, we get: lim [(1/5x) / (1/2√5x)] x→[infinity]

Simplifying this expression, we get: lim 2/5√5x x→[infinity]

Since the denominator approaches infinity as x approaches infinity, the limit is equal to 0.

Therefore: lim ln(5x)/√5x = 0 x→[infinity]

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what are the first four terms of the geometric sequence a2= 11, and a3=-121.

Answers

The first four terms of the geometric sequence are -1, 11, -121, and -1210.

We have,

To find the first four terms of the geometric sequence, we need to determine the common ratio, r, and then use it to calculate the other terms.

We can start by using the formula for the nth term of a geometric sequence:

an = a1 x r^(n - 1)

where an is the nth term, a1 is the first term, r is the common ratio, and n is the position of the term we want to find.

Since we are given a2 and a3, we can use them to form two equations:

a2 = a1 x r

a3 = a1 x r²

We can then solve for a1 and r:

a1 = a2 / r = 11 / r

r = a3 / a2 = -121 / 11

Substituting these values into the formula for the nth term, we get:

an = (11 / r) x (-121 / 11)^(n - 2)

Simplifying this expression, we get:

an = -11 x 11^(n - 2)

Now we can calculate the first four terms:

a1 = 11 / r = 11 / (-121 / 11) = -1

a2 = 11

a3 = -121

a4 = -11 x 11^(4 - 2) = -1210

Therefore,

The first four terms of the geometric sequence are:

-1, 11, -121, -1210

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Help me with this question I begg

Answers

Answer:x= 39 , y= -6

Step-by-step explanation:

we have y = -6 (1)

x = -8y-9 (2)

Let (1) replace (2)

x = -8(-6)-9

x = 48-9 = 39

So x=39 , y=-6

What is the side lengths of a a and b. What is the value of x?
(3x)^2+(6x)^2=40^2

Answers

It’s 500 bc I looked it up and i seen the answer bc I had this on my assignment too

Roger and Katy traveled 120. 75 miles and 205. 65 miles respectively. Who traveled more distance by how much?

Answers

Katy traveled more distance than Roger by 84.9 miles.

Subtraction is a basic arithmetic operation that involves finding the difference between two numbers, by taking away one number from another. It is denoted by the minus (-) sign and is the inverse operation of addition

To find out who traveled more distance, we need to calculate the difference between the distance traveled by Roger and Katy.

So, Katy traveled 205.65 miles and Roger traveled 120.75 miles.

To find out who traveled more, we subtract the distance traveled by Roger from the distance traveled by Katy

= 205.65 miles - 120.75 miles

Subtract the numbers

= 84.9 miles

Therefore, Katy traveled 84.9 miles more than Roger.

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A hiker walks at an average rate of 2 miles per hour. Write a multiplication equation to find how long it will take for the hiker to walk 11 miles. Let n represent the number hours

Answers

Answer:

This can be figured out from the equation:

2n = 11

If he walks 2 miles/hour, then you can just say "2n" to say the miles in the unknown variable for hours.  Set it to equal 11, the number of miles he will walk in n hours.

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the probability distribution for the number of automobiles lined up at a lakeside olds dealer at opening time (7:30 am) for service is numberprobability10.1520.2030.5040.15 on a typical day, how many automobiles should lakeside olds expect to be lined up at opening time? numberprobability10.0520.3030.4040.25 on a typical day, how many automobiles should lakeside olds expect to be lined up at opening time?

Answers

Lakeside Olds should expect to have approximately 3 automobiles lined up at opening time on a typical day based on the probability distribution provided.

To find the expected number of automobiles lined up at the Lakeside Olds dealer at opening time, we use the concept of expected value. The expected value is the average value we would expect to see if we repeated the experiment many times. In this case, the experiment is the number of automobiles lined up at the dealer at opening time.

We are given the probability distribution for the number of automobiles, which tells us the probability of each possible outcome. We use these probabilities to calculate the expected value as the weighted average of all possible outcomes.

Expected number of automobiles = (1 x 0.05) + (2 x 0.30) + (3 x 0.40) + (4 x 0.25)

= 0.05 + 0.60 + 1.20 + 1.00

= 2.8

≈ 3

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The given question is incomplete, the complete question is:

The probability distribution for the number of automobiles lined up at a Lakeside Olds dealer at opening time (7:30 a.m.) for service is:

how many automobiles should Lakeside Olds expect to be lined up at opening time?

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the magnitude of pressure exerted by the gas molecules composing air depends on What is the type of sexual harassment in the workplace in which there is no link between jobs and sex? julie smelled cake baking in the oven, triggering the gastric phase of stomach regulation.a. trueb. false Which system is represent in the graph?y y> 3x+4y> x^2 + 4x-2y< 3x+4y x^2+4x-2y 3x+4y>x^2+4x-2y> 3x+4 What type of facility does the Clean Air Act affect the most? Any good pet simulator z games? A person between 13 and 18 years of age may have his/her driving privilege _____ for one year if convicted as a habitual truant.ExtendedCancelledSuspended the balance owed on your credit card doubles from $1000 to $2000 in 6 months. if your balance is growing exponentially, how much longer will it be until it reaches $8000? the balance owed on your credit card doubles from $1000 to $2000 in 6 months. if your balance is growing exponentially, how much longer will it be until it reaches $8000? 6 months PLEASE HELPwhich of the following medulla patters is represented in the image below. what characteristic did early hominins share with modern humans? I'LL MARK THE BRAINLIEST! Read the passage from Darwin's journal.The Amblyrhynchus, a remarkable genus of lizards, is confined to this archipelago; there are two species, resembling each other in general form, one being terrestrial and the other aquatic. This latter species (A. cristatus) was first characterized . . . from its short, broad head, and strong claws of equal length, that its habits of life would turn out very peculiar, and different from those of its nearest ally, the iguana. It is extremely common on all the islands throughout the group, and lives exclusively on the rocky sea beaches, being never found . . . even ten yards in-shore. It is a hideous-looking creature of a dirty black color, unintelligent and sluggish in its movements. The usual length of a full-grown one is about a yard, but there are some even four feet long; a large one weighed twenty pounds: on the island of Albemarle, they seem to grow to a greater size than elsewhere. Their tails are flattened sideways, and all four feet are partially webbed. They are occasionally seen some hundred yards from the shore, swimming about; and Captain Collnett, in his voyage says, They go to sea in herds a-fishing, and sun themselves on the rocks, and may be called alligators in miniature. It must not, however, be supposed that they live on fish. When in the water, this lizard swims with perfect ease and quickness, by a serpentine movement of its body and flattened tailthe legs being motionless and closely collapsed on its sides. A seaman on board sank one with a heavy weight attached to it, thinking thus to kill it directly, but when an hour afterward, he drew up the line, it was quite active. Their limbs and strong claws are admirably adapted for crawling over the rugged and fissured masses of lava, which are everywhere from the coast. In such situations, a group of six or seven of these hideous reptiles may oftentimes be seen on the black rocks, a few feet above the surf, basking in the sun with outstretched legs. What structural adaptation of the A. cristatus lizard helps them in the water?A} Large SizeB} Fishing In HerdsC} Flattened TailD} Strong Claws The formula =C3*D3 would be found in which cell of this spreadsheet?12 Apples3 OrangesBananas4APackageCaseCaseBox5 TomatoesCaseEggplantsEachPurple onions Each6Product78BOA. D2B. C2O C. E3D. B3CQuantity413192427CostD$30.00$35.00$29.00$40.00$1.00$0.50Value$120.00$455.00$551.00$960.00$2.00$3.50$2,091.50its e3 a.a natural but non-metric response format.b.a natural metric response format.c.a natural synthetic response format.d.a synthetic metric format. T/F: the t cell arm of protective immunity is the easiest for viral vaccines to activate. what is freud's term for the primitive, biological side of personality and the personality structure present at birth?when anna looks at some modern artwork at the museum, she often thinks she sees human figures or faces and likes to make up stories about them. when she tells the stories to her friend, her friend says that the stories reflect anna's unconscious thoughts. in psychological terms, what anna does is most similar to . what is the primary function of the ike protocol used with ipsec? I need this equation now answer this please the question is on the pic I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE the sales price of a product is $20.00 per unit; the variable cost is $7.50 per unit; and fixed costs total $10,000. how many units must be sold to break even? when comparing the $3 price for a gallon of milk to a $2.75 price for a gallon of gasoline, money functions as a group of answer choices medium of exchange. store of value. unit of accounting. standard of deferred payment.