It is not important to check for a safe, flat surface prior to jumping rope

True
False

Answers

Answer 1
The answer is false because you always need to be safe before doing a physical activity around other people
Answer 2

Answer:

False

Explanation:

You wouldn't want to jump on a rocking uneven area where you could fall and hurt yourself would you? No, so you'd check for a flat surface


Related Questions

Which guideline best reflects how private information should be protected when using social networks? All social media users are screened and safe to engage with. Protect your private information by setting your account to private and only adding people you actually know. Only share your passwords with close friends that you trust. It is safe to share personal information with companies on social networking sites.

Answers

Answer:

hescorrect i just took the test and that was the awnser

Explanation:

if u need i can give the other awnsers

Answer:

(A. 1.) Protect your private information by setting your account to private and only adding people you actually know.

Explanation:

A steam governor uses negative feedback to control the speed of a steam engine. Suppose a steam governor has two balls that are each rotating with a tangential speed of 3.7 m/s. The balls are 0.10 m from the rotation axis, and the centripetal force on each ball is 670 N. What is the mass of one of the balls? Pls help

Answers

Answer:

no lo se

Explanation:

Supposing a steam governor has two balls that are each rotating with a tangential speed of 3.7 m/s. The balls are 0.10 m from the rotation axis, and the centripetal force on each ball is 670 N. Then the mass of one of the balls is 4.89 kg.

What is Centripetal force ?

''Centripetal force is force acting on a body performing circular motion, which is along radius of the circle and directed towards the center of circle"

since centripetal force acts at right angle to the tangential velocity of the body, there is no displacement in the direction of the force, hence no work done. It has newton(N) as Si unit.

centripetal force is given by,

F= mv²÷r

Where m is mass of the body

v is velocity of the body

r is radius of circle at which body is moving.

Given

velocity v = 3.7 m/s

radius r = 0.10 m

centripetal force F = 670N

mass = ?

from formula we can write,

670 = m(3.7)²÷0.10

m= (670×0.10)÷(3.7)²

m = 4.89 kg

Hence mass of one of the balls is 4.89 kg

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At what point does the ball have the most gravitational potential energy?

Answers

Point C. at this point, which is the highest point, all of the ball’s energy is gravitational potential energy.

Two free charges +q and +4q are a distance l apart. A third charge is placed so that the entire system is in equilibrium. Find the location, magnitude and sign of the third charge.

Answers

Answer:

the value of the charge is   q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position  x= l/3

Explanation:

The forces in this system are given by Coulomb's law

           F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]

As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .

Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge

Let's find the location of charge 3 so that it is in balance

               ∑ F = F₁₃ - F₂₃ = 0

               F₁₃ = F₂₃

we seek every force

              F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]

              F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]

the distances are

              x₁₃ = x-0 = x

              x₂₃ = l -x

we substitute

              k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}

           

we solve

             (l-x)² = [tex]\frac{q_2}{q_1}[/tex]   x²

               

              l² - 2lx + x² = \frac{4q}{q} x²

              3x² + 2l x - l² = 0

we solve the quadratic equation

              x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)

              x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6

              x₁ = -l

              x₂ = l / 3

as charge 3 must be between the two charges the correct answer is

              x = l / 3

with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.

now let's analyze the force on the other charges

charge 1 so that it is in balance

           ∑F = F₁₃ - F₁₂ = 0

           F₁₃ = F₁₂

          [tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]

           l² q₃ = q₂ (l/3)²

           q₃ = q₂ / 9

            q₃ = 4q / 9

            q₃ = [tex]\frac{4}{9} q[/tex]

in summary the value of the charge is   q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q

in the position  x= l/3

A body at rest is given an instal
uniform acceleration of 8.0m/s² for 30
seconds after which the acceleration is
reduced at 50m/s² for the next 20
second the body maintains the speed
attain for 60 seconds after which it is
brought to rest in 20 seconds​

Answers

Hrhhfbfbjfjfh high rn fbfhhfhfh gg f

v=u+at

v=0+8.0×30

v=240

Consider a point charge qqq in three-dimensional space. Symmetry requires the electric field to point directly away from the charge in all directions. To find E(r)E(r)E(r), the magnitude of the field at distance rrr from the charge, the logical Gaussian surface is a sphere centered at the charge. The electric field is normal to this surface, so the dot product of the electric field and an infinitesimal surface element involves cos(0)=1cos⁡(0)=1. The flux integral is therefore reduced to ∫E(r)dA=E(r)A(r)∫E(r)dA=E(r)A(r), where E(r)E(r)E(r) is the magnitude of the electric field on the Gaussian surface, and A(r)A(r)A(r) is the area of the surface.

Answers

Answer:

 E = [tex]\frac{1}{4\pi \epsilon_o } \ r^2[/tex]

Explanation:

For this exercise let's use Gauss's law. The Gaussian surface that follows the symmetry of the charges is a sphere

           Ф = ∫ E. dA = [tex]\frac{x_{int} }{\epsilon_o}[/tex]

the bold are vectors, the radii of the sphere and the electric field are parallel therefore the scalar product reduces to the algebraic product

           Ф = ∫ E dA = \frac{x_{int} }{\epsilon_o}

           E ∫ dA = \frac{x_{int} }{\epsilon_o}

           E A = \frac{x_{int} }{\epsilon_o}

the area of ​​a sphere is

            A = 4π r²

the charge inside the sphere is q = + q

           

we substitute

           E 4π r² = \frac{x }{\epsilon_o}

           E = [tex]\frac{1}{4\pi \epsilon_o } \ r^2[/tex]

Hari drag a load of 60 kg along a distance of 12 metre what amount of work does he do also mention the type of work​

Answers

Answer:

W = 7056  J

Explanation:

Given that,

Mass of a load, m = 60 kg

Distance moved, d = 12 m

We need to find the amount of work. The work done by an object is given by :

W = Fd

So,

W = mg×d

W = 60 kg × 9.8 m/s²×12 m

W = 7056  J

So, the amount of work done is 7056  J.

Who thinks this a ufo? The following images are from a rare footage.

Answers

Answer:

That might be a sled ngl but it looks like a ufo but it's definitely not

Answer:

the reptilians gave there tech to the nazis and the reptilians are currently living underground in Antarctica but id'k about that pic

Explanation:

A weight of 4.0 N is used to extend a spring. The extension of the spring is 0.06 m. (i) Calculate the spring constant, k, of the spring.

(ii) State what measurements should be made to determine the extension of the spring produced by the 4.0 N weight.

Answers

Answer:

See explanation

Explanation:

Hookes law states that; the displacement due to a stretching force is directly proportional to the magnitude of the deforming force.

F = ke

F = deforming force

k = force constant

e = extention

k = F/e

k = 4N/0.06 m= 66.67 Nm^-1

To determine the extension of the spring produced by the 4.0 N weight

1) We measure the original length of the spring

2) We measure the length after hanging the 4 N mass

3) Subtract the new length from the original length to determine the extention.

You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a building that is 20.0 m above the ground.


a)How long after it is launched does the walnut reach the ground?

b)How far does the walnut travel horizontally from launch point to landing point?

c) What are the horizontal and vertical components of the walnut’s velocity just before it reaches the ground? Suppose that the +y-axis is directed upward and the +x-axis is directed horizontally from the launch point toward the landing point.

Answers

Answer:

a.3.51s

b.33.8m

c. 9.64,-22.9

Explanation:

(a) The time taken be "3.5083 sec".

(b) The distance will be "33.82 m".

(c) The horizontal and vertical components be "9.64 m/s and -22.89 m/s".

Velocity and Direction

According to the question,

Speed, V₀x = 15 Cos (50.0°)

                   = 9.64 m/s

            V₀y = 15 Sin (50.0°)

                   = 11.49 m/s

Vertical displacement = -20.0 m

(a) We know the relation between displacement, time and acceleration

→  y = vt + [tex]\frac{1}{2}[/tex]at²

By substituting the values,

→ -20.0 = 11.49 t - 4.9 t²

  4.9 t² - 11.49 t - 20.0 = 0

                                   t = [tex]\frac{11.49 + \sqrt{132.02+392} }{9.8}[/tex]

                                     = [tex]\frac{11.49 + 22.89}{9.8}[/tex]

                                     = 3.5083 sec

(b) We know the formula,

Distance = Speed × Time

or,

→ X = 9.64 t

      = 9.64 × 3.5083

      = 33.82 m

(c) Again by using the above relation, we get

    Vx = V₀x

          = 9.64 m/s

    Vy = V₀y - gt

By substituting the values,

          = 11.49 - 9.8 × 3.5083

          = 11.49 - 34.38

          = -22.89 m/s

Thus the response above is correct.

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(ii) Electromagnetic waves transfer energy.
Give 6 examples of the transfer of energy by EM waves, 3 which are useful and 3 which are a nuisance.

Answers

Explanation:

6 examples

radio wave

infrared ray

visible light ray

ultraviolet ray

microwave

gamma ray

3 which are useful

infrared ray

radio waves

gamma ray

A student that just received their driver’s license decides to buy a new car. He remembers from physics class that heat engines have a thermal efficiency that can be calculated. He asks the car dealer for a car that has a high thermal efficiency rating. The car dealer says he has a car that is 100% efficient.

Which law of thermodynamics best describes why the car cannot be 100% efficient?

Answers

Answer:

Second law of thermodynamics.

Explanation:

The second law of thermodynamics states that: "in all energy exchanges, if there is no energy entering or leaving the system, then it means the potential energy of that particular state will definitely be less than the potential energy it had at it's initial state."

Now, for a car to be 100% efficient, it means that there must be some form of heat transfer to the environment. However, this is a violation of the second law of thermodynamics and as such it can't be 100% efficient.

The law that  best describes why the car cannot be 100% efficient is the second law of thermodynamics.

Thermodynamics is the study of heat. Heat is a form of energy that exists as a result of temperature difference between bodies.

According to the second law of thermodynamics, the conversion of energy  from one form to another is not 100% efficient. As such, the thermal efficiency of the engine can be calculated.

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Scientists treat the number of stars in a given volume of space as a Poisson random variable. The density of our galaxy in the vicinity of our solar system is 3 stars per 10 cubic light-years. What is the probability of one or more stars in 10 cubic light-years? Round your answer to 4 decimal places.

Answers

Answer:

[tex]P(X\ge 1) = 0.9502[/tex]

Explanation:

Given

Density = 3 starts in 10 cubic light years.

Required

Determine the probability of 1 or more in 10 cubic light years

Since the number of stars follow a Poisson distribution, we make use of:

[tex]P(X=k) = f(x) = (\lambda T)^k\frac{ e^{-\lambda T}}{k!}[/tex]

[tex]\lambda = density[/tex]

[tex]\lambda = \frac{3}{10}[/tex]

[tex]\lambda = 0.3[/tex]

T = the light years

[tex]T = 10[/tex]

Calculating [tex]P(X \ge 1)[/tex]

In probability:

[tex]P(X \ge 1) = 1 - P(X = 0)[/tex]

Calculating P(X=0)

Substitute 0 for k and the values for [tex]\lambda[/tex] and T in

[tex]P(X=k) = f(x) = (\lambda T)^k\frac{ e^{-\lambda T}}{k!}[/tex]

[tex]P(X=0) = (0.3* 10)^0 * \frac{ e^{-0.3 * 10}}{0!}[/tex]

[tex]P(X=0) = (3)^0 * \frac{ e^{-0.3 * 10}}{1}[/tex]

[tex]P(X=0) = (3)^0 * e^{-0.3 * 10}[/tex]

[tex]P(X=0) = 1 * e^{-0.3 * 10}[/tex]

[tex]P(X=0) = 1 * e^{-3}[/tex]

[tex]P(X=0) = e^{-3}[/tex]

[tex]P(X=0) = 0.04979[/tex]

Substitute 0.04979 for P(X=0) in [tex]P(X \ge 1) = 1 - P(X = 0)[/tex]

[tex]P(X\ge 1) = 1 - 0.04979[/tex]

[tex]P(X\ge 1) = 0.95021[/tex]

[tex]P(X\ge 1) = 0.9502[/tex] ---  approximated

Hence, the required probability is 0.9502

how heat is produced from alcohol

Answers

The alcohol combustion reaction releases heat energy and is an example of an exothermic reaction.

A box weighing 2.4 x 10^2 Newton's is lifted at a constant speed to a shelf 1.2 meters high in 4.0 seconds. What power is required to lift the box

Answers

Answer:

72Watts

Explanation:

Power = Force * distance/Time

Given the following

Force = 2.4 x 10^2 = 240N

distance = 1.2m

Time = 4.0secs

Substitute

Power = 240*1.2/4

Power = 60 * 1.2

Power = 72watts

Hence the power required to lift the box is 72Watts

A piece of equipment belonging to an astronaut has a mass of 2 kg on the surface of the Moon. What is its weight on the Moon?

Answers

Answer:

brainliest plss

Explanation:

A tennis ball is dropped from a height of 1.21m above the ground. Calculate its velocity when it is 0.27m from the ground.

Answers

9.81m/s^2 x .27 = 2.6487m/s

The velocity of hitting the ground is 4.86 m/s and the velocity after hitting the ground is 4.53 m/s.

What is Velocity?

Velocity can be defined as the direction of movement of the body or object. Velocity is a vector quantity. It is the rate of change of displacement.

Given data,

Initial velocity when dropped(u)=0 m/s

Distance traveled(s)=1.21 m/s

Distance traveled after leave the ground(s1) = 1.05 ms

According to third law of motion,

v² = u² + 2gs

Initial velocity u=0

v² = 2gs or v = [tex]\sqrt{2gs}[/tex]

​by putting the value of s

v (hitting) = √(2 × 9.8 × 1.21) = [tex]\sqrt{23.71}[/tex] = 4.86m/s

After leaving ground at 1.21 m final velocity will be zero

So, velocity just after left the ground will be

2 = √(2 × 9.8 × 1.05) = [tex]\sqrt{20.58}[/tex] = 4.53m/s

So, velocity of hitting the ground is 4.86 m/s and after hitting is 4.53 m/s.

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if you wanna make it easier you can number them going down 1,2,3, or 4 & just tell me the number

Answers

the number is 1 I hope this help

The odometer of a car reads 57321 km when the clock shows the time 8.30 am. What is the distance moved by the car, if at 8.50 am, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time.

Answers

Answer:

0.75km/min

Explanation:

I haven't learnt physics at all but I'll try

57336 - 57321 = 15km (Difference)

8.50 am - 8.30 am = 20 minutes (Difference)

If the car odometer adds up 15km every 20 minutes...

20 mins = 15km

1 min = 15 ÷ 20 = 0.75km

40 mi/hr south is:
a displacement
a speed
a velocity

Answers

Answer:

Velocity

Explanation:

Since velocity is magnitude and direction, 40mph south is velocity.

What is the best example of a compound machine A ax. B ramp. C car D screw

Answers

Answer: I believe the answer is C

Explanation:

Cars are composed of hundreds of simple machines

The answer to this question is C.) Car,
hopes this helps, and if you can, pls mark me brainliest :D

How would you describe impulse in the simplest way possible

Answers

Answer:

Explanation:

 impulse is a sudden force or desire — this could be an electrical impulse, or an impulse to get some pizza.

If you act on a sudden feeling or thought, you’re following an impulse.

That's like a whim: an impulse isn't something you've given a lot of thought. Another meaning of impulse is an electrical charge or pulse. Electrical impulses are coursing through wires all through your house every day. Both kinds of impulses make things happen. The electrical impulse keeps the refrigerator going, and then you have an impulse to eat all the ice cream in the fridge.

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What is the force of a 3 kg skateboard accelerating at a rate of 4m/s2?

Plug in the numbers: Force= mass x acceleration

Answers

Answer:

F = 12 N

Explanation:

F = m × a

F = 3 × 4

F = 12 kg m/s²

F = 12 N

on what mass will a force 16N produce an acceleration of 160N





Answers

Answer:

m = 0.1 [kg]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.

[tex]F =m*a[/tex]

where:

F = force = 16[N]

a = acceleration = 160 [m/s²]

m = mass [kg]

Now replacing:

[tex]m=F/a\\m = 16/160\\m = 0.1 [kg][/tex]

A boat has a porthole window, of area 0.00849 m^2, 6.25 m below the surface. The density of sea water is 1027 kg/m^3. The air inside the boat is at 1 atm. What is the net force on the window?

Answers

Answer:

[tex]325.65\ \text{N}[/tex] outward.

Explanation:

[tex]\rho[/tex] = Density of water = [tex]1027\ \text{kg/m}^3[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

h = Height of the water = 6.25 m

A = Area of the window = [tex]0.00849\ \text{m}^2[/tex]

[tex]P_i[/tex] = Internal pressure of the boat = [tex]1\ \text{atm}=101325\ \text{Pa}[/tex]

Pressure by the water on the window

[tex]P=\rho gh\\\Rightarrow P=1027\times 9.81\times 6.25\\\Rightarrow P=62967.9375\ \text{Pa}[/tex]

Net pressure on the window

[tex]P_n=P-P_i=62967.9375-101325=-38357.0625\ \text{Pa}[/tex]

Force is given by

[tex]F=P_nA\\\Rightarrow F=-38357.0625\times 0.00849\\\Rightarrow F=-325.651460625\ \text{N}[/tex]

Net force on the window is [tex]325.65\ \text{N}[/tex] outward.

Answer: 534.6 N

Explanation:

This answer works for Acellus!

Absolute Zero is when energy / molecules stop moving.

Answers

Answer:

yes

Explanation:

When all of the molecules (or atoms) in a system stop moving completely, that's as cold as they can get

Planets A and B have the same mass, but planet A is half the size of planet B. Which statement correctly explains the weight you would experience on each planet? O A. You would weigh more on planet A because the distance between you and the planet's center of gravity would be smaller. B. You would weigh the same on both planets because the masses of the planets are the same. 2 C. You would weigh the same on both planets because your mass would be the same on both. D. You would weigh less on planet A because the distance between you and the planet's center of gravity would be smaller.​

Answers

Answer:

I would say A

Explanation:

the closer you are to a planets center of gravity i feel you would weigh more.

The air pressure inside a car tire is

3.00 atm, and it creates 41,500 N

of force pushing out on the tire.

What is the surface area of the

inside of the tire?

Answers

Answer:

0.137m²

Explanation:

Pressure = Force/Area

Given

Force = 41,500N

Pressure = 3.00atm

since 1atm = 101325.00 N/m²

3atm = 3(101325.00)

3atm = 303,975N/m²

Pressure = 303,975N/m²

Get the area

Area = Force/Pressure

Area = 41500/303,975

Area = 0.137m²'

Hence the surface area of the  inside of the tire is 0.137m²

We are running late for school and we want to make our 0.5 kg tea (it’s at 90 C) colder. Let’s assume we can drink tea when it’s 50 C. We decided that it would be more convenient to drop an ice (0 C) since it will get cold soon. What mass of ice needs to be put in for this to happen?

Answers

Answer:

x=0.154kg

Explanation:

(x*L)+(0.5kg*4200*50)+(x*4200*(-50)=0

(x*333 000J/kg*c)+(0.5kg*4200J/kg*C*(-40C))+(x*4200J/kg*C*50C)=0

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Use The Kinetic Theory To Explain:
•Boyle's Law
•Charles' Law
•Pressure Law​

Answers

Answer:

Kinetic theory is based on the kinetic energy of moving particles.  In Boyle's Law the temperature is helped constant, so the kinetic energy of the molecules is a constant. The pressure and the volume are inversely related in Boyle's Law. In Kinetic theory pressure is created by the collision of particles.

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Explanation:

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