Answer:
False
Explanation:
You wouldn't want to jump on a rocking uneven area where you could fall and hurt yourself would you? No, so you'd check for a flat surface
The odometer of a car reads 57321 km when the clock shows the time 8.30 am. What is the distance moved by the car, if at 8.50 am, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time.
Answer:
0.75km/min
Explanation:
I haven't learnt physics at all but I'll try
57336 - 57321 = 15km (Difference)
8.50 am - 8.30 am = 20 minutes (Difference)
If the car odometer adds up 15km every 20 minutes...
20 mins = 15km
1 min = 15 ÷ 20 = 0.75km
if you wanna make it easier you can number them going down 1,2,3, or 4 & just tell me the number
the number is 1 I hope this help
You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a building that is 20.0 m above the ground.
a)How long after it is launched does the walnut reach the ground?
b)How far does the walnut travel horizontally from launch point to landing point?
c) What are the horizontal and vertical components of the walnut’s velocity just before it reaches the ground? Suppose that the +y-axis is directed upward and the +x-axis is directed horizontally from the launch point toward the landing point.
Answer:
a.3.51s
b.33.8m
c. 9.64,-22.9
Explanation:
(a) The time taken be "3.5083 sec".
(b) The distance will be "33.82 m".
(c) The horizontal and vertical components be "9.64 m/s and -22.89 m/s".
Velocity and DirectionAccording to the question,
Speed, V₀x = 15 Cos (50.0°)
= 9.64 m/s
V₀y = 15 Sin (50.0°)
= 11.49 m/s
Vertical displacement = -20.0 m
(a) We know the relation between displacement, time and acceleration
→ y = vt + [tex]\frac{1}{2}[/tex]at²
By substituting the values,
→ -20.0 = 11.49 t - 4.9 t²
4.9 t² - 11.49 t - 20.0 = 0
t = [tex]\frac{11.49 + \sqrt{132.02+392} }{9.8}[/tex]
= [tex]\frac{11.49 + 22.89}{9.8}[/tex]
= 3.5083 sec
(b) We know the formula,
Distance = Speed × Time
or,
→ X = 9.64 t
= 9.64 × 3.5083
= 33.82 m
(c) Again by using the above relation, we get
Vx = V₀x
= 9.64 m/s
Vy = V₀y - gt
By substituting the values,
= 11.49 - 9.8 × 3.5083
= 11.49 - 34.38
= -22.89 m/s
Thus the response above is correct.
Find out more information about velocity here:
https://brainly.com/question/2456181
What is the best example of a compound machine A ax. B ramp. C car D screw
Answer: I believe the answer is C
Explanation:
Cars are composed of hundreds of simple machines
A boat has a porthole window, of area 0.00849 m^2, 6.25 m below the surface. The density of sea water is 1027 kg/m^3. The air inside the boat is at 1 atm. What is the net force on the window?
Answer:
[tex]325.65\ \text{N}[/tex] outward.
Explanation:
[tex]\rho[/tex] = Density of water = [tex]1027\ \text{kg/m}^3[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
h = Height of the water = 6.25 m
A = Area of the window = [tex]0.00849\ \text{m}^2[/tex]
[tex]P_i[/tex] = Internal pressure of the boat = [tex]1\ \text{atm}=101325\ \text{Pa}[/tex]
Pressure by the water on the window
[tex]P=\rho gh\\\Rightarrow P=1027\times 9.81\times 6.25\\\Rightarrow P=62967.9375\ \text{Pa}[/tex]
Net pressure on the window
[tex]P_n=P-P_i=62967.9375-101325=-38357.0625\ \text{Pa}[/tex]
Force is given by
[tex]F=P_nA\\\Rightarrow F=-38357.0625\times 0.00849\\\Rightarrow F=-325.651460625\ \text{N}[/tex]
Net force on the window is [tex]325.65\ \text{N}[/tex] outward.
Answer: 534.6 N
Explanation:
This answer works for Acellus!
Consider a point charge qqq in three-dimensional space. Symmetry requires the electric field to point directly away from the charge in all directions. To find E(r)E(r)E(r), the magnitude of the field at distance rrr from the charge, the logical Gaussian surface is a sphere centered at the charge. The electric field is normal to this surface, so the dot product of the electric field and an infinitesimal surface element involves cos(0)=1cos(0)=1. The flux integral is therefore reduced to ∫E(r)dA=E(r)A(r)∫E(r)dA=E(r)A(r), where E(r)E(r)E(r) is the magnitude of the electric field on the Gaussian surface, and A(r)A(r)A(r) is the area of the surface.
Answer:
E = [tex]\frac{1}{4\pi \epsilon_o } \ r^2[/tex]
Explanation:
For this exercise let's use Gauss's law. The Gaussian surface that follows the symmetry of the charges is a sphere
Ф = ∫ E. dA = [tex]\frac{x_{int} }{\epsilon_o}[/tex]
the bold are vectors, the radii of the sphere and the electric field are parallel therefore the scalar product reduces to the algebraic product
Ф = ∫ E dA = \frac{x_{int} }{\epsilon_o}
E ∫ dA = \frac{x_{int} }{\epsilon_o}
E A = \frac{x_{int} }{\epsilon_o}
the area of a sphere is
A = 4π r²
the charge inside the sphere is q = + q
we substitute
E 4π r² = \frac{x }{\epsilon_o}
E = [tex]\frac{1}{4\pi \epsilon_o } \ r^2[/tex]
How would you describe impulse in the simplest way possible
Answer:
Explanation:
impulse is a sudden force or desire — this could be an electrical impulse, or an impulse to get some pizza.
If you act on a sudden feeling or thought, you’re following an impulse.
That's like a whim: an impulse isn't something you've given a lot of thought. Another meaning of impulse is an electrical charge or pulse. Electrical impulses are coursing through wires all through your house every day. Both kinds of impulses make things happen. The electrical impulse keeps the refrigerator going, and then you have an impulse to eat all the ice cream in the fridge.
PLEASE THANK, RATE AND FOLLOW ME,
AND PLEASE MARK ME AS "BRAINLIEST" ANSWER
HOPE IT HELPS YOU
I NEED HELP AS SOON AS POSSIBLE PLEASEEE!!
DO NOT ANSWER IF YOU DON'T KNOW IT PLEASE!
Use The Kinetic Theory To Explain:
•Boyle's Law
•Charles' Law
•Pressure Law
Answer:
Kinetic theory is based on the kinetic energy of moving particles. In Boyle's Law the temperature is helped constant, so the kinetic energy of the molecules is a constant. The pressure and the volume are inversely related in Boyle's Law. In Kinetic theory pressure is created by the collision of particles.
plz mark me as brainly
Explanation:
A piece of equipment belonging to an astronaut has a mass of 2 kg on the surface of the Moon. What is its weight on the Moon?
Answer:
brainliest plss
Explanation:
on what mass will a force 16N produce an acceleration of 160N
Answer:
m = 0.1 [kg]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.
[tex]F =m*a[/tex]
where:
F = force = 16[N]
a = acceleration = 160 [m/s²]
m = mass [kg]
Now replacing:
[tex]m=F/a\\m = 16/160\\m = 0.1 [kg][/tex]
PLS ANSWER FAST WILL GIVE BRAINLEST!!!
What is the force of a 3 kg skateboard accelerating at a rate of 4m/s2?
Plug in the numbers: Force= mass x acceleration
Answer:
F = 12 N
Explanation:
F = m × a
F = 3 × 4
F = 12 kg m/s²
F = 12 N
Absolute Zero is when energy / molecules stop moving.
Answer:
yes
Explanation:
When all of the molecules (or atoms) in a system stop moving completely, that's as cold as they can get
A tennis ball is dropped from a height of 1.21m above the ground. Calculate its velocity when it is 0.27m from the ground.
The velocity of hitting the ground is 4.86 m/s and the velocity after hitting the ground is 4.53 m/s.
What is Velocity?Velocity can be defined as the direction of movement of the body or object. Velocity is a vector quantity. It is the rate of change of displacement.
Given data,
Initial velocity when dropped(u)=0 m/s
Distance traveled(s)=1.21 m/s
Distance traveled after leave the ground(s1) = 1.05 ms
According to third law of motion,
v² = u² + 2gs
Initial velocity u=0
v² = 2gs or v = [tex]\sqrt{2gs}[/tex]
by putting the value of s
v (hitting) = √(2 × 9.8 × 1.21) = [tex]\sqrt{23.71}[/tex] = 4.86m/s
After leaving ground at 1.21 m final velocity will be zero
So, velocity just after left the ground will be
2 = √(2 × 9.8 × 1.05) = [tex]\sqrt{20.58}[/tex] = 4.53m/s
So, velocity of hitting the ground is 4.86 m/s and after hitting is 4.53 m/s.
Learn more about Velocity here:
https://brainly.com/question/18084516
#SPJ2
A steam governor uses negative feedback to control the speed of a steam engine. Suppose a steam governor has two balls that are each rotating with a tangential speed of 3.7 m/s. The balls are 0.10 m from the rotation axis, and the centripetal force on each ball is 670 N. What is the mass of one of the balls? Pls help
Answer:
no lo se
Explanation:
Supposing a steam governor has two balls that are each rotating with a tangential speed of 3.7 m/s. The balls are 0.10 m from the rotation axis, and the centripetal force on each ball is 670 N. Then the mass of one of the balls is 4.89 kg.
What is Centripetal force ?''Centripetal force is force acting on a body performing circular motion, which is along radius of the circle and directed towards the center of circle"
since centripetal force acts at right angle to the tangential velocity of the body, there is no displacement in the direction of the force, hence no work done. It has newton(N) as Si unit.
centripetal force is given by,
F= mv²÷r
Where m is mass of the body
v is velocity of the body
r is radius of circle at which body is moving.
Given
velocity v = 3.7 m/s
radius r = 0.10 m
centripetal force F = 670N
mass = ?
from formula we can write,
670 = m(3.7)²÷0.10
m= (670×0.10)÷(3.7)²
m = 4.89 kg
Hence mass of one of the balls is 4.89 kg
To know more about centripetal force, click
https://brainly.com/question/14249440
#SPJ3
Planets A and B have the same mass, but planet A is half the size of planet B. Which statement correctly explains the weight you would experience on each planet? O A. You would weigh more on planet A because the distance between you and the planet's center of gravity would be smaller. B. You would weigh the same on both planets because the masses of the planets are the same. 2 C. You would weigh the same on both planets because your mass would be the same on both. D. You would weigh less on planet A because the distance between you and the planet's center of gravity would be smaller.
Answer:
I would say A
Explanation:
the closer you are to a planets center of gravity i feel you would weigh more.
A student that just received their driver’s license decides to buy a new car. He remembers from physics class that heat engines have a thermal efficiency that can be calculated. He asks the car dealer for a car that has a high thermal efficiency rating. The car dealer says he has a car that is 100% efficient.
Which law of thermodynamics best describes why the car cannot be 100% efficient?
Answer:
Second law of thermodynamics.
Explanation:
The second law of thermodynamics states that: "in all energy exchanges, if there is no energy entering or leaving the system, then it means the potential energy of that particular state will definitely be less than the potential energy it had at it's initial state."
Now, for a car to be 100% efficient, it means that there must be some form of heat transfer to the environment. However, this is a violation of the second law of thermodynamics and as such it can't be 100% efficient.
The law that best describes why the car cannot be 100% efficient is the second law of thermodynamics.
Thermodynamics is the study of heat. Heat is a form of energy that exists as a result of temperature difference between bodies.
According to the second law of thermodynamics, the conversion of energy from one form to another is not 100% efficient. As such, the thermal efficiency of the engine can be calculated.
Learn more about thermodynamics: https://brainly.com/question/1301963
A body at rest is given an instal
uniform acceleration of 8.0m/s² for 30
seconds after which the acceleration is
reduced at 50m/s² for the next 20
second the body maintains the speed
attain for 60 seconds after which it is
brought to rest in 20 seconds
v=u+at
v=0+8.0×30
v=240
Who thinks this a ufo? The following images are from a rare footage.
Answer:
That might be a sled ngl but it looks like a ufo but it's definitely not
Answer:
the reptilians gave there tech to the nazis and the reptilians are currently living underground in Antarctica but id'k about that pic
Explanation:
how heat is produced from alcohol
(ii) Electromagnetic waves transfer energy.
Give 6 examples of the transfer of energy by EM waves, 3 which are useful and 3 which are a nuisance.
Explanation:
6 examples
radio wave
infrared ray
visible light ray
ultraviolet ray
microwave
gamma ray
3 which are useful
infrared ray
radio waves
gamma ray
Two free charges +q and +4q are a distance l apart. A third charge is placed so that the entire system is in equilibrium. Find the location, magnitude and sign of the third charge.
Answer:
the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position x= l/3
Explanation:
The forces in this system are given by Coulomb's law
F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]
As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .
Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge
Let's find the location of charge 3 so that it is in balance
∑ F = F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
we seek every force
F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]
F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]
the distances are
x₁₃ = x-0 = x
x₂₃ = l -x
we substitute
k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}
we solve
(l-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
l² - 2lx + x² = \frac{4q}{q} x²
3x² + 2l x - l² = 0
we solve the quadratic equation
x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)
x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6
x₁ = -l
x₂ = l / 3
as charge 3 must be between the two charges the correct answer is
x = l / 3
with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.
now let's analyze the force on the other charges
charge 1 so that it is in balance
∑F = F₁₃ - F₁₂ = 0
F₁₃ = F₁₂
[tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]
l² q₃ = q₂ (l/3)²
q₃ = q₂ / 9
q₃ = 4q / 9
q₃ = [tex]\frac{4}{9} q[/tex]
in summary the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q
in the position x= l/3
A box weighing 2.4 x 10^2 Newton's is lifted at a constant speed to a shelf 1.2 meters high in 4.0 seconds. What power is required to lift the box
Answer:
72Watts
Explanation:
Power = Force * distance/Time
Given the following
Force = 2.4 x 10^2 = 240N
distance = 1.2m
Time = 4.0secs
Substitute
Power = 240*1.2/4
Power = 60 * 1.2
Power = 72watts
Hence the power required to lift the box is 72Watts
The air pressure inside a car tire is
3.00 atm, and it creates 41,500 N
of force pushing out on the tire.
What is the surface area of the
inside of the tire?
Answer:
0.137m²
Explanation:
Pressure = Force/Area
Given
Force = 41,500N
Pressure = 3.00atm
since 1atm = 101325.00 N/m²
3atm = 3(101325.00)
3atm = 303,975N/m²
Pressure = 303,975N/m²
Get the area
Area = Force/Pressure
Area = 41500/303,975
Area = 0.137m²'
Hence the surface area of the inside of the tire is 0.137m²
40 mi/hr south is:
a displacement
a speed
a velocity
Answer:
Velocity
Explanation:
Since velocity is magnitude and direction, 40mph south is velocity.
Scientists treat the number of stars in a given volume of space as a Poisson random variable. The density of our galaxy in the vicinity of our solar system is 3 stars per 10 cubic light-years. What is the probability of one or more stars in 10 cubic light-years? Round your answer to 4 decimal places.
Answer:
[tex]P(X\ge 1) = 0.9502[/tex]
Explanation:
Given
Density = 3 starts in 10 cubic light years.
Required
Determine the probability of 1 or more in 10 cubic light years
Since the number of stars follow a Poisson distribution, we make use of:
[tex]P(X=k) = f(x) = (\lambda T)^k\frac{ e^{-\lambda T}}{k!}[/tex]
[tex]\lambda = density[/tex]
[tex]\lambda = \frac{3}{10}[/tex]
[tex]\lambda = 0.3[/tex]
T = the light years
[tex]T = 10[/tex]
Calculating [tex]P(X \ge 1)[/tex]
In probability:
[tex]P(X \ge 1) = 1 - P(X = 0)[/tex]
Calculating P(X=0)
Substitute 0 for k and the values for [tex]\lambda[/tex] and T in
[tex]P(X=k) = f(x) = (\lambda T)^k\frac{ e^{-\lambda T}}{k!}[/tex]
[tex]P(X=0) = (0.3* 10)^0 * \frac{ e^{-0.3 * 10}}{0!}[/tex]
[tex]P(X=0) = (3)^0 * \frac{ e^{-0.3 * 10}}{1}[/tex]
[tex]P(X=0) = (3)^0 * e^{-0.3 * 10}[/tex]
[tex]P(X=0) = 1 * e^{-0.3 * 10}[/tex]
[tex]P(X=0) = 1 * e^{-3}[/tex]
[tex]P(X=0) = e^{-3}[/tex]
[tex]P(X=0) = 0.04979[/tex]
Substitute 0.04979 for P(X=0) in [tex]P(X \ge 1) = 1 - P(X = 0)[/tex]
[tex]P(X\ge 1) = 1 - 0.04979[/tex]
[tex]P(X\ge 1) = 0.95021[/tex]
[tex]P(X\ge 1) = 0.9502[/tex] --- approximated
Hence, the required probability is 0.9502
Hari drag a load of 60 kg along a distance of 12 metre what amount of work does he do also mention the type of work
Answer:
W = 7056 J
Explanation:
Given that,
Mass of a load, m = 60 kg
Distance moved, d = 12 m
We need to find the amount of work. The work done by an object is given by :
W = Fd
So,
W = mg×d
W = 60 kg × 9.8 m/s²×12 m
W = 7056 J
So, the amount of work done is 7056 J.
A weight of 4.0 N is used to extend a spring. The extension of the spring is 0.06 m. (i) Calculate the spring constant, k, of the spring.
(ii) State what measurements should be made to determine the extension of the spring produced by the 4.0 N weight.
Answer:
See explanation
Explanation:
Hookes law states that; the displacement due to a stretching force is directly proportional to the magnitude of the deforming force.
F = ke
F = deforming force
k = force constant
e = extention
k = F/e
k = 4N/0.06 m= 66.67 Nm^-1
To determine the extension of the spring produced by the 4.0 N weight
1) We measure the original length of the spring
2) We measure the length after hanging the 4 N mass
3) Subtract the new length from the original length to determine the extention.
We are running late for school and we want to make our 0.5 kg tea (it’s at 90 C) colder. Let’s assume we can drink tea when it’s 50 C. We decided that it would be more convenient to drop an ice (0 C) since it will get cold soon. What mass of ice needs to be put in for this to happen?
Answer:
x=0.154kg
Explanation:
(x*L)+(0.5kg*4200*50)+(x*4200*(-50)=0
(x*333 000J/kg*c)+(0.5kg*4200J/kg*C*(-40C))+(x*4200J/kg*C*50C)=0
Which guideline best reflects how private information should be protected when using social networks? All social media users are screened and safe to engage with. Protect your private information by setting your account to private and only adding people you actually know. Only share your passwords with close friends that you trust. It is safe to share personal information with companies on social networking sites.
Answer:
hescorrect i just took the test and that was the awnser
Explanation:
if u need i can give the other awnsers
Answer:
(A. 1.) Protect your private information by setting your account to private and only adding people you actually know.
Explanation:
At what point does the ball have the most gravitational potential energy?
