It is possible to travel faster than the speed of sound

Answers

Answer 1
no it’s not mabooks because no means of transport can beat the speed of sound
Answer 2
Yes, humans have also travelled faster than sound on some scientific experiments and also some fast supersonic planes


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when landing after a spectacular somersault, a 25.0 kg gymnast decelerates by pushing straight down on the mat. calculate the force (in n) she must exert if her deceleration is 9.00 times the acceleration of gravity. (enter a number.)

Answers

The force exerted by the 25 kg gymnast after a spectacular somersault is 2940 N.

Given,

Mass of the gymnast, m = 25 kg

The deceleration experienced by the gymnast, a = 9×g (acceleration due to gravity)

Now, according to Newtons second law of motion, the net force on the gymnast will be:

[tex]F_{net}[/tex] = F - W = ma

Where F is the force on the gymnast, W is the weight and a is the acceleration experienced.

So, we can also rewrite the above equation as

F = ma +W

= ma + mg

= m(a + g)

= 30 kg( 9×9.8 + 9.8)

= 30 (88.2+9.8)

= 30×98

=2940 N

Hence, the force exerted by the gymnast is 2940 N.

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A 0. 0035 m aqueous solution of a particular compound has ph = 2. 46. The compound is.

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A 0.0035 M aqueous solution of a certain substance has a pH of 2.46. The compound is a strong acid.

How does pH determine a solution's acidity or basicity?

The pH of water indicates how acidic or basic it is. The scale runs from 0 to 14, with 7 being neutral. pHs less than 7 indicate acidity, while pHs greater than 7 imply baseness. The pH of water is a measure of the relative number of free hydrogen and hydroxyl ions. Water with a higher concentration of free hydrogen ions is acidic, whereas water with a higher concentration of free hydroxyl ions is basic. Because chemicals in water can influence pH, pH is a significant indicator of chemically changing water. pH is expressed in "logarithmic units." Each value reflects a 10-fold increase or decrease in the acidity/basicity of the water. Water with a pH of 5 is ten times as acidic as water with a pH of 6.

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a gym consists of a rectangular region with a semi-circle on each end. if the perimeter of the room is to be a 200 m running track, find the dimensions that will make the area of the rectangular region as large as possible.

Answers

The dimensions of the rectangle are:

l = 50 m

b = [tex]100/\pi[/tex] m

What is a perimeter in math?

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

How do we find a perimeter of a rectangle?

The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.

Given:

As per the question:

Perimeter of the room is given as P = 200 m

The region is rectangular having a semicircle at each end.

Now,

Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.

Then, Area of the given rectangle, A = lb

Perimeter of the room, P is =[tex]\pi r+l+\pi r+l=2\pi r+2l=\pi b+2l[/tex]

Therefore,  [tex]\pi b+2l=200[/tex]

[tex]b=(200-2l)/\pi[/tex]

Now,

Area, A = [tex]l(200-2l)/\pi=(200l-2l^{2} )/\pi[/tex]

Now, differentiate A w.r.t l:

Again differentiating w.r.t 'l', we get:

[tex]d^{2} A/dl^{2} =-4l/\pi[/tex]< 0

Thus we get maximum are when [tex]dA/dl=0[/tex]

Therefore,

[tex](200-4l)/\pi=0[/tex]

l = 50 m

Now, from

[tex]\pi b+2l=200[/tex]

[tex]\pi b=200-2*50[/tex]

[tex]b=100/\pi[/tex]

[tex]r=b/2=50/\pi[/tex]

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how many orbiting satellites at any given moment are there keeping a watchful eye on our planet? what altitudes do these satellites operate?

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Most operate at altitudes ranging from a few hundred miles above the surface of the planet to as high as 25,000 miles. Each one of these Earth-observing satellites reveals a different piece of the puzzle.

What is satellites ?

A satellite, also known as an artificial satellite, is a spacecraft that has been put into orbit on purpose. With the exception of passive satellites, most satellites have a means of generating electricity for the equipment they carry, such as radioisotope thermoelectric generators or solar panels.

For a full view of the Earth's disc and to keep the satellites in their geostationary orbit, they are 22,300 miles above the planet's surface. In order to keep their geostationary orbit, geostationary satellites move at a speed of roughly 7000mph.

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A 25-cm rod moves at 5.0 m/s in a plane perpendicular to a magnetic field of strength 0.25 T. The rod, velocity vector, and magnetic field vector are mutually perpendicular, as indicated in the accompanying figure. Calculate (a) the magnetic force on an electron in the rod, (b) the electric field in the rod, and (c) the potential difference between the ends of the rod. (d) What is the speed of the rod if the potential difference is 1.0 V?

Answers

Magnetic force on an electron is  2 X 10⁻¹⁹ N,the electric field in the rod is 1.25 V/ m,potential difference between the ends of the rod  0.3 1 V and peed of the rod if the potential difference is 1.0 V is 16m.

By using the formula of motional

Here ,

E Induced emp B - magnetic field,

L Is length of conductor V- velocity

Also, the force Son a positive charge moving in magnetic field is given ask

F = QV*B - -> 2

Here

f - force acting on positively charged

particle V - velocity, 9 7 charge

and B - magicbe freed

(a) The velocity of elections and lode is

same .

By using Eg (2, ie f = q vB sung

by putting the Given value, INengel

f = ( 1 .6022 x 10 ).( 5 * 0.25 ).

= 2 X 10⁻¹⁹ N

(b) In the Equilibrium system the electric force is equals to Magnetic force by putting the values-

E = ( 5 . 0 ) ( 0 25 ) = 1.25 V/ m

( c) By using - E= (0 25 m ) (5m/s )

e = 0. 3 1 V

d )

Again By using EQ1

V=E/BL

=1/( 0 . 25 ) ( 0. 25 )= 16m

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the electronic circuitry in an ultrasonic receiver measures the transit time and calculates the distance from the receiver to the surface of material.

Answers

It is true that electronic circuitry in an ultrasonic receiver measures the transit time and calculates the distance from the receiver to the surface of material.

What is ultrasonic receiver?

Ultrasonic sensors works by sending out a sound wave at frequency above the human hearing range. Transducer of the sensor acts as microphone to receive and send the ultrasonic sound. Ultrasonic sensors use a single transducer to send a pulse and to receive the echo.

Ultrasonic receivers and transmitters detect and transmit high frequency sound waves, respectively and are characterized by frequency, rated voltage, and beam angle.

Ultrasonic transducers and ultrasonic sensors are devices that generate or sense ultrasound energy and can be divided into three: transmitters, receivers and transceivers.

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At the bow of a ship on a stormy sea, a crew member conducts an experiment by standing on a bathroom scale.
In calm waters, the scale reads 755 . During the storm, the crew member observer a maximum reading of 920 and a minimum reading of 555 .
A) Find the maximum upward acceleration experienced by the crew member.
B) Find the maximum downward acceleration experienced by the crew member.

Answers

2.14 m/s² is the maximum upward acceleration experienced by the crew member. 3.53 m/s² is the maximum downward acceleration experienced by the crew member.

How to calculate the maximum upward acceleration ?

To calculate the maximum upward acceleration experienced use this formula

[tex]a = \left(\frac{W_{2} - W_{1}}{W_{1}} \right ) g[/tex]

where,

W₁ = Scale reading in calm water

W₂ = Maximum reading in the storm

g = acceleration due to the gravity

Now put the values in above formula we get the acceleration as

[tex]a = \left(\frac{W_{2} - W_{1}}{W_{1}} \right ) g[/tex]

  [tex]= \left(\frac{920\ lb - 755\ lb}{755\ lb} \right ) (9.8\ m/s^2)[/tex]

  [tex]= \frac{165\ lb}{755\ lb} \times (9.8\ m/s^2)[/tex]

  = 2.14  m/s²

How to calculate the minimum downward acceleration ?

To calculate the minimum downward acceleration experienced use this formula

[tex]a = \left(\frac{W_{1} - W_{3}}{W_{3}} \right ) g[/tex]

where,

W₁ = Scale reading in calm water

W₃ = Minimum reading in the storm

g = acceleration due to the gravity

Now put the values in above formula we get the acceleration as

[tex]a = \left(\frac{W_{1} - W_{3}}{W_{3}} \right ) g[/tex]

  [tex]= \left(\frac{755\ lb - 555\ lb}{555\ lb} \right ) (9.8\ m/s^2)[/tex]

  [tex]= \frac{200\ lb}{555\ lb} \times (9.8\ m/s^2)[/tex]

  = 3.53  m/s²

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a ball is held at rest at the top of a hill. the ball is then released and starts rolling down the hill. at the bottom, it reaches level ground and keeps rolling along the ground. consider the level ground at the bottom of the hill as zero height. select the type or types of energy the ball has at the top of the hill.

Answers

Gravitational Potential Energy is the type of energy the ball has at the top of the hill.

What is meant by Gravitational Potential Energy ?The energy that an item has due to its location in a gravitational field is known as gravitational potential energy. For an object close to the surface of the Earth, when the gravitational acceleration may be considered to remain constant at around 9.8 m/s, gravitational potential energy is most frequently used.Gravitational potential energy may be defined as an energy that has a connection to gravitational force or gravity.If an item is placed at a height above (or below) the zero height, it has gravitational potential energy. If an item is not in its equilibrium position on an elastic material, it has elastic potential energy.

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Compressed gases aren't ideal. Let's consider a gas that's non-ideal only because the volume available to each of the N molecules is reduced because each other molecule occupies volume v. Instead of pV=NkT, we get: p(V-Nb)=NkT. Let b=7 × 10^-29 m3. Let's look at 3 moles of this gas at T=300K starting in 0.001 m3 volume

Answers

Work done is given by

dw=Pdv, w=∫₁²(NkT/V-Nb)dv

The amount of work is 5708.00923 J.

What sort of moles are cancerous?

border that is erroneous Frequently, the edges are jagged, serrated, or blurry in outline. It's possible for the pigment to penetrate the nearby skin. unbalanced color: There could be various tones of tan, brown, and black. There may also be white, black, red, pink, and blue patches.

What is the quickest method for eliminating moles?

Using traps or bait with in spring or fall will increase your chances of successfully eliminating moles from your yard. The primary runway, or active runway, should be used for both goods. Usually, these are the vertical tunnels in your grass or the ones that round the outside of your property.

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What is the wavelength of a 500 Hz wave?.

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The correct answer is 0.6 x 10⁶.

Wavelength is the distance between the start of the wave and the end of the wave which is also the start of the next wave.

This wavelength describes how long the wave is.

Given,

Frequency = 500 Hz

Wavelength = λ = ?

c = speed of light = 3 x 10⁸

To find wavelength, we apply a formula,

Wavelength = speed of light / frequency

λ = 3 x 10⁸ / 5 x 10²

λ = 0.6 x 10⁶ m

Wavelength = 6 x 10⁵ m

Therefore, the wavelength of a 500 Hz is 6 x 10⁵ m.

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a particle moves along the x axis. it is initially at the position 0.340 m, moving with velocity 0.210 m/s and acceleration -0.210 m/s2. suppose it moves with constant acceleration for 6.00 s. (a) find the position of the particle after this time.

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a particle moves along the x axis. it is initially at the position 0.340 m.the position of the particle after this time is 2.52 metres towards negative x direction.

what is displacement?

Displacement (symbolized d or s ), also called length or distance, is a one-dimensional quantity representing the separation between two defined points. The standard unit of displacement in the International System of Units ( SI ) is the meter

Displacement is the change in position by a body. It's defined as shortest distance between initial and final position of the body. It's a vector quantity. Hence, it has both magnitude and direction. To understand the magnitude and direction of displacement, consider a body moving from position A to position B.

s=ut+1/2at².

on solving the eqn we get displacement as -2.52 metres

which means the body is 2.52 metre towards negative x.

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which statement is not a postulate of the kinetic molecular theory? which statement is not a postulate of the kinetic molecular theory? the attractive or repulsive forces between the gas molecules resulting in collisions that involve a slight loss of energy. the pressure of a gas in a container results from collisions between the gas molecules and the walls of the container. the volume of the gas molecules are negligibly small compared to the volume of the container. the root mean square speed of the gas molecules increases as the kelvin temperature of the gas increases.

Answers

According to kinetic molecular theory, there is no attractive and repulsive forces between the gas molecules.

The kinetic molecular theory is based on the following postulates:

Gases are made up of a large number of particles which behave like hard, spherical objects in a state of constant, random motion.These particles move in a straight path until they collide with another particle or the walls of the container.These particles are very smaller than the distance between particles. Most of the volume of a gas is hence empty space.There is no force of attraction between gas particles or between the particles and the walls of the container.Collisions between gas particles or collisions with the walls of the container are perfectly elastic. None of the energy of a gas particle is lost when it collides with another particle or with the walls of the container.The average kinetic energy of a collection of gas particles depends on the temperature of the gas and nothing else.

So, correct option is 1 which states attractive or repulsive force between the gas molecules resulting in collisions that involve a slight lose of energy.

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describe the resultant chromosome number of the two daughter cells. indicate the genetic make-up of each cell.

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Two identical daughter cells are produced during mitosis, and both of these cells have the same number of chromosomes as their parent cell. meiosis results in the production of four different daughter cells.

As a result, mitosisproduces four haploid daughter cells, each of which has a unique genetic makeup and half the DNA of the parent cell (Figure below). The parent cell of a human cell contains 46 chromosomes (23 pairs), hence the meiotic cells created have 23 chromosomes. They will develop into gametes. At this time, nuclear division starts, dividing the parent cell in half to create two daughter cells. Each daughter cell will contain 23 chromosomes, or half of the initial 46 chromosomes. Two sister chromatids make up each chromosome. The sister chromatids of each chromosome then separate during mitosis, resulting in one chromatid being received by each daughter cell from each chromosome. Two daughter cells with the same genetic makeup as the original cell are produced as a result of mitosis, and they all have two N chromosomes.

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A horizontal section of narrow pipe is filled with water whose flow speed is negligible
(v1 ≈0)
. The gauge pressure inside the pipe is P gauge =4.0 atm
. There is a pinhole-sized leak in the wall of the pipe, and water exits the hole with speed
v2
. What is
v2

? For the limit check, investigate what happens to
v2

if the gauge pressure inside the pipe drops to zero
(Pgauge →0)

Answers

Consequently, if the pipe is extended by two times its original length, the gauge pressure would be 2.234 ×10⁴ Pa.

How does gauge pressure work?

Gauge pressure is the measurement of pressure in respect to the surrounding atmosphere. With one side of the textile exposed to the took shape that has to be measured the other accessible to the outside air density, a diaphragm sensor is able to measure gauge pressure.

Briefing:

By using the continuity equation

A ₁V₁ = A₂V₂

When the area is doubled from what it was originally,

A ₁V₁ = 2A₁V₂

V₂ =V₁/2

By using Bernoulli's equation

P₁ + 1/2 ρV₁² = P₂ + 1/2 ρV₂²

P₂ =  2×10⁴ + 1/2 ×1000×(2.5² -1.25²)

   = 2×10⁴ + 2343.75

   =22343.75 Pa

   =2.234 ×10⁴ Pa

Consequently, if the pipe is extended by two times its original length, the gauge pressure would be 2.234 ×10⁴ Pa.

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what value of fmaxfmax gives an impulse of 9.0 nsns ? express your answer with the appropriate units.

Answers

F-MAX is short for Frequency Max. This is the widest range of frequencies that can be utilized to record vibration data on a spectrum.

Explain about the F-MAX?

The highest frequency at which a design can operate is known as the unrestricted F - MAX. Restricted F-MAX is the highest frequency a design can operate at while taking into account device restrictions like the maximum toggling rate. parent subject.

The design clock's maximum clock frequency is the highest speed it can operate at without going over internal setup and hold time constraints. When performing timing analysis on single or many clock designs, the Quartus program can report a design's internal and system F-MAX.

The resolution of each line is easily determined by dividing the overall frequency (F-max) by the number of lines. Each line will cover a range of frequencies. For instance, a resolution of 300 CPM per line is achieved with a F-max of 120,000 CPM and 400 lines.

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g the parallel axis theorem relates icm, the moment of inertia of an object about an axis passing through its center of mass, to ip, the moment of inertia of the same object about a parallel axis passing through point p. the mathematical statement of the theorem is ip

Answers

The moment of inertia of the rod with respect to a parallel axis through one end of the rod is I = M L²/3.

Given that, Icm is the moment of inertia of the object about an axis passing through its centre of mass

Ip is the moment of inertia of the object about a parallel axis passing through point p.

d is the perpendicular distance from the centre of mass to the axis that passes through the point p

Using parallel axis theorem, we can write, I = Icm + Md² ------(1)

The moment of inertia of the rod with respect to centre of mass is

Icm = ∫x² M/L dx = M/3 (L² -3Ld + 3d²) = M L²/12 (as d=L/2)

The distance from the centre of mass that coincides its geometric centre to the ends of the rod is d = L/2, substituting in (1), we have

I = 1/12 ML²+ M(L/2)² = ML² (1/12 + 1/4) = 1/3 ML²

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A square wire loop with 2.4 m sides is perpendicular to a uniform magnetic field, with half the area of the Ioop in the field as shown in the figure. The loop contains an ideal battery with emf 824 V If the magnitude of the field varies with time according to B = 0.035-0.81 t, with B In teslas and t in seconds, what are (a) the net emf in the circuit and (b) the direction of the (net) current around the loop? (b counterclockwise

Answers

This statement about distance is proved.

What is distace?

It is length of space between two points.

Okay so the first three parts of this problem is more mathematics and physics. Um So part A were given Ds equals R. D. Data. We're required to find S. So we just integrate both sides then as equals integration of R. D. Data. Our data is given. So the upon integration over our data is simply R zero santa plus one half beta zeta squared for part B. We'll fix that S equals V. T. Um And using as equals dis above equation we combine these two. We see this is Justin equation for data so we can suffer it to get to roots once positive. The other negative of course which is a positive one because it has the correct physical meaning a negative data would mean that uh the direction of rotation is in the opposite direction.

standard uh standard unit is zero point 247 times turn to the negative six nature radio. And we're also given the time 74 minutes or equivalently 4440 seconds. So plugging all this. So plugging data mm hmm and R zero into the expression of um data. So we plug in better Data. V is also given. So everything is known. We can safely find data to be um 1.337 Times 10-5 brilliant. Or in terms of revolutions is 2.13 times 10 to 4 revolution. Okay. In the last part of the problem, we simply well plugging again the numbers for beta, tr zero V to the previous expressions for omega and alpha. You can enjoy the using mathematical or even by hand or maybe he looks like this shape while um the alpha t looks more like this.

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g suppose that a rigid cylinder of gas with initial states p, v, and t is placed on top of a stove and heated for some period of time. it is known that the final temperature of the gas is three times that of its initial temperature. 1. which of the state variables (pressure, volume, or temperature) is held constant in this process? briefly explain.

Answers

The final temperature of the gas is three times that of its initial temperature then the control variables are constant.

A manage variable is any variable it's held regular in a research examine. It is no longer a variable of interest within the examine, but it's controlled because it is able to influence the outcomes.

in case you don't control applicable extraneous variables, they'll impact the effects of your examine, and you may not be able to demonstrate that your consequences are virtually an impact of your independent variable.

A manipulate variable is something this is held constant or confined in a research examine. it's a variable that is not of interest to the look at objectives, however is controlled due to the fact it may have an effect on the outcomes.

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how much work is required to move it at constant speed 5.0 m along the floor against a friction force of 230 n .\

Answers

(a) To move the crate, you need to exert 7150 J of energy.

(b) The Vertical Movement of the Crate Will Take 6000 J of Work.

Determine a constant speed?

A frictional force is one that tends to oppose the motion of two bodies in contact.

The crate must be moved using both effort against resistance and effort across a distance of 5.0 meters.

Wr = Wf plus Wd.

Where Wr = work needed to move the crate, Wf = work done to overcome friction, and Wd = work needed to move the crate 5.0 meters.

Given are the following values: Wf = friction force distance = 2305 = 1150 J and Wd = force distance = 12005.0 = 6000 J.

Wr = 6000 + 1150 Wr = 7150 J when these values are substituted into equation 1.

The amount of effort needed to move the crate is therefore 7150 J.

(b) The amount of labor necessary to lift the crate vertically: mgh or

Vertically moving the crate requires the following amount of work: Wh. Equation 2 h = vertical height, W = weight of the block

Provided:W = 1200 N, h = 5.0 m

Equation 2 can be solved by substituting these numbers as follows: Vertical movement of the crate: work required = 12005

Moving the box upward will require 6000 J of work.  

The complete question is,

On the ground is a crate weighing 1200 N. How much effort is needed to move it (a) 5.0 m along the floor while battling a 230 N friction force; and (b) 5.0 m vertically?

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If two objects generate a gravitational force of 3 x 1019 N and are 2 x 105 meters apart, and one of the objects has a mass of 2.4 x 107 kg, what is the mass of the second object?

Answers

The mass of the second object, that is  2×10⁵ m apart with the first object  is 7.49×10²² kg.

What is mass?

Mass is the quantity of matter contained in a body.

To calculate the mass of the second object, we use the formula below.

Formula:

m = Fr²/(GM)........... Equation 1

Where:

m = Mass of the second objectM = Mass of the second objectr = Distance between the two objectsG = Universal constant.

From the question,

Given:

F = 3×10⁹ NM = 2.4×10⁷ kgr = 2×10⁵ mG = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

m = 3×10⁹×(2×10⁵)²/ (2.4×10⁷×6.67×10⁻¹¹)m = 7.49×10²² kg

Hence, the mass of the second object is 7.49×10²² kg.

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A piece of wood is floating in a tub of water. A second piece of wood rest on top of the first piece; it does not touch the water. If the second piece is removed from the first and placed in the water, what happens to the water level in the tub?.

Answers

If the second piece is removed from the first and placed in the water, then the water level remains unchanged.

The water level is the water level reached in the container.

Initially, the weight of the pieces of wood was balanced by the buoyancy provided by the water, which depended on the volume of the first piece of wood that was inside the water (which was equal to the volume of water displaced).

Now, when the other piece was placed in the water, then again the weight of both blocks individually (which does not change) would be balanced by the lift of the total volume (coming from the contribution from both blocks), which would be the same. as before.

The water level would thus remain unchanged.

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Provided following are stages that occurred during the formation of our solar system. Rank these stages from left to right based on when they occurred, from first to last.
large cloud of gas and dust
contraction of solar nebula
condensation of solid particles
accreition of planetesimals
clearing the solar nebula

Answers

The correct order for the stages that occurred during the formation of our solar system from left to right are large cloud of gas and dust > contraction of solar nebula > condensation of solid particles > accretion of planetesimals > clearing the solar nebula.

When a cloud of gas and dust collapsed, it formed a solar nebula which is a swirling disk of material, which is made up of hydrogen and helium. It starts collapsing under its own gravity and compresses in the centre. Then the solid particles are gas condensed into tiny dust grains. These dust grains are stuck to each other forming larger particles. This forms the accretion of planetesimals. These large particles grow and accumulate creating larger planetesimals, after a billion years of clearing the nebula, planets are formed.

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what is the angular momentum of a 0.225 kg ball rotating on the end of a thin string in a circle of radius 1.50 m at an angular speed of 10.5 rad/s ?

Answers

Angular momentum of a 0.225kg ball rotating on the end of a thin string in a circle of radius 1.50 m at an angular speed of 10.5 rad/s is 5.315 kg-m²/sec

Angular momentum is defined as the quantity of rotation of a body, which is the product of its moment of inertia and its angular velocity.

It is expressed as L = I ω for rotating body.

where, L = angular momentum, I = moment of inertia, ω = angular speed

L = ?, I =?, ω = 10.5

Moment of inertia for the string-mass system is I = mr²

I=?, m= 0.225 , r=1.50

I = 0.225(1.50)²

So, I = 0.506 kg-m²

since, L = I ω

substituting the values I= 0.506, ω= 10.5

L = 0.506 × 10.5

Therefore, L= 5.315 kg-m²/sec

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What is the frequency of a 5. 0 m wave?.

Answers

The frequency of the wave be the wavelength 5m is 6 × 10⁷ Hz.

The frequency of a wave is given by the speed of light divided by the wavelength of the wave.

In this case the wavelength of the wave is 5m.

And, as we know the speed of light is 3 × 10⁸ m/s.

So we can write the above statement in the formula as,

V = c/λ

Where,

V is frequency,  

c is speed of light and λ is the wavelength.

Putting values,

V = 3 × 10⁸/5

V = 6 × 10⁷ Hz.

So, the frequency of this wave is 6 × 10⁷ Hz.

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What are the 4 stages of the rock cycle?.

Answers

One type of rock can become another rock type through a number of procedures. Crystallization, erosion and sedimentation, and metamorphism are the main components of the rock cycle.

Rock cycle: what is it?

The changes between the three primary rock types are shown by a notion known as a "rock cycle" (metamorphic, igneous and sedimentary). The many types of rocks that make up the Earth's crust are created and altered via a series of processes.

Very brief explanation of the rock cycle.

The igneous, metamorphic, and sedimentary rock types all go through a geological process known as the rock cycle. Through erosion into sediment and cementing, or heating and pressure, or both, the three kinds of rock are changed in this process. Rocks can change from igneous to sedimentary.

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a rocket on earth experiences an upward applied force from its thrusters. as a result of this force,the rocket accelerates upward at . assume that there are no other upward forces exerted onthe rocket and that wind resistance is negligible. which of the following combinations of the rocket'smass and force from its thrusters would result in an upward acceleration of? select two answers

Answers

The motors on the rocket provide a force of 118,000N. Because of its thrusters, a rocket on earth experiences an upward applied force. The rocket accelerates upward at a rate of 2 m/s as a result of this force.

A force in physics is an effect that has the power to alter an object's motion. A force can cause an object with mass to change its velocity, or accelerate (for example, moving from a condition of rest). Intuitively, a push or a pull can also be used to describe force.

In mechanics, acceleration is the rate at which an object's velocity with respect to time changes. Vector quantities include accelerations. The direction of the net force imposed on an object determines its acceleration in relation to that force.

F = m(2+9.8)

F = m(11.8m/s^2)

F = (10000)(11.8 m/s^2)

F = 118000N

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The complete question is -

A rocket on Earth experiences an upward applied force from its thrusters. As a result of this force, the rocket accelerates upward at 2 m/s2. Assume that there are no other upward forces exerted on the rocket and that wind resistance is negligible. Which of the following combinations of the rockets mass m. Rocket and force from its thrusters  would result in an upward acceleration of 2 m/s2? Select two answers.

You are watching an object that is moving in SHM. When the object is displaced 0.600 m to the right of its equilibrium position, it has a velocity of 2.20m/s to the right and an acceleration of 8.40m/s2 to the left.How much farther from this point will the object move before it stops momentarily and then starts to move back to the left?

Answers

The object can move as farther as 0.2m.

Using the Sine Equation,

= x(t) = Asin(ωt)

=Here, t=0, x=0,

Given that,

Distance = x(t) = 0.60 = A sin(ωt)

Velocity = v(t) = 2.20 m/s = Aωcos(ωt)

Acceleration = a(t) = 8.40 m/s² = -Aω²sin(ωt)

Using wave equation,

= x(t) / a(t) = A sin(ωt) / -Aω²sin(ωt)

= ω² = 14 rad²/s²

= ω = 3.74 rad/s

The amplitude of the motion =

=  x(t) / v(t) = A sin(ωt) / Aωcos(ωt)

= A = 0.2 m

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A potential difference of 0.090V is developed across the 10-cm-long wire of the following figure as it moves through a magnetic field perpendicular to the plane of the figure.
What is the strength of the magnetic field?

Answers

The strength of magnetic field is 0.18T.

The magnetic influence on moving electric charge, electric current and magnetic materials is described by magnetic field.

Given that, potential difference = 0.09 V

Length = 10 cm = 10/100 m = 0.1 m

Velocity = 5 m/s

We know the relation, Potential difference = B*l*v

where, B is the magnetic field strength

l is the length

v is the velocity

Potential difference = B*l*v

0.09 = B* 0.1* 5

B = 0.09/0.5 = 0.18 T

Thus, the strength of magnetic field is 0.18 T.

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show all work to identify the asymptotes and state the end behavior of the function f of x is equal to 6x divided by the quantity of x minus 36 end quantity.

Answers

An Asymptote is an instant line that constantly tactics a given curve but does no longer meet at an infinite distance.

According to the question;

asymptote: x = ±6

zero: x = 0

Explanation;

The vertical asymptotes of the function will be at the values of x where the denominator is zero. The denominator is x^2 -36, so has zeros for values of x that satisfy.

x^2 -36 = 0

x^2 = 36

x = ±√36 = ±6

The vertical asymptotes of the function are x = -6 and x = +6.

The zero of the function is at the value of x which makes the numerator zero. This will be the value of x that satisfies ...

6x = 0

x = 0 . . . . . divide by 6

The zero of the function is x=0.

A vertical asymptote of a graph is a vertical line x = a, in which the graph has a tendency in the direction of fine or bad infinity because of the inputs method a. A horizontal asymptote of a graph is a horizontal line y = b where the graph tactics the road as the inputs technique ∞ or –∞.

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which of the following statements about the use of combustible materials in type i construction is ftec

Answers

Limited use of combustible materials is permitted in Type I construction.

What is Type 1 a construction?Any structure taller than 75 feet falls under this category.All residential and commercial high-rise buildings must adhere to this. Apartment complexes, workplaces, and hotels are all included. These structures are made to sustain extreme heat for an extended period of time without collapsing. Beyond that, none of the materials used in construction can catch fire. Reinforced concrete and protected steel are used to construct the walls, floors, and roofs. These elements boost construction expenses while also giving the buildings an incredibly long lifespan.To stop flames from spreading, certain Type 1 buildings incorporate HVAC systems and self-pressurizing stairwells. Firefighters find it simpler to reach and put out fires thanks to these structural features. Their primary goal while entering a Type 1 building is to lock stairwells to guarantee a secure evacuation.

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