Jayden created a monthly budget based on his net income. If he earns $3,080 each month, how much money can he allocate to eating at restaurants?

The task requires performing a horizontal percent of base year analysis on WestJet's income statement and balance sheet, considering 2013 as the base year. This analysis will help identify the trends and changes in financial figures over the specified period.

To conduct a horizontal percent of base year analysis, we compare the financial figures of subsequent years to the base year and calculate the percentage change. Here's how the analysis can be performed:

a. Income Statement Analysis:

Calculate the percentage change in each line item of the income statement by comparing it to the corresponding figure in the base year (2013).

For example, if the revenue in 2013 is $100 and it increases to $120 in 2014, the percentage change would be [(120 - 100) / 100] * 100 = 20%.

Perform this calculation for each line item in the income statement to determine the percentage change for each year.

b. Balance Sheet Analysis:

Similar to the income statement analysis, calculate the percentage change in each line item of the balance sheet by comparing it to the corresponding figure in the base year (2013).

For example, if the total assets in 2013 are $500 and they increase to $600 in 2014, the percentage change would be [(600 - 500) / 500] * 100 = 20%.

Perform this calculation for each line item in the balance sheet to determine the percentage change for each year.

Using the analyses prepared in part (a), we can identify the trends and changes in WestJet's income statement and balance sheet over the specified period. By comparing the percentage changes, we can determine which line items have shown significant growth or decline compared to the base year. This analysis helps in assessing the company's financial performance, identifying areas of strength or weakness, and making informed decisions based on the observed trends.

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The probability of rolling an odd number is 1/2, assuming that the number cube is fair.

The sample space is the set of all possible outcomes of an experiment. In this case, the experiment is rolling a number cube once and recording the outcome. Since the number cube has six faces labeled from 1 to 6, the sample space can be represented as:

S = {1, 2, 3, 4, 5, 6}

The event of rolling an odd number consists of the outcomes 1, 3, and 5.

Therefore, the set of all outcomes for the event of rolling an odd number is: {1, 3, 5}

The probability of rolling an odd number can be found by adding the probabilities of the individual outcomes in the event:

{P(odd)} = P(1) + P(3) + P(5) = 1/6 + 1/6 + 1/6 = 3/6 = 1/2

Therefore, the probability of rolling an odd number is 1/2.

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Answer:

5/6

Step-by-step explanation:

-3/4 * - 10/9

A negative times a negative is a positive

3/4 * 10/9

Rewriting

3/9 * 10/4

1/3 * 5/2

Multiplying across

5/6

Answer:

9997.46

Step by step Explanation

Answer:

11 music lessons.

Step-by-step explanation:

We know that membership costs $165 and members pay $25 per music lesson.

So, we can write the following expression:

[tex]165+25m[/tex]

The 165 represents the one-time membership fee and the 25m represents the cost for m music lessons.

We know that non-members pay no membership fee but their cost per lesson is $40. So:

[tex]40m[/tex]

Represents the cost for non-members for m music lessons.

We want to find how many music lessons would have to be taken for the cost to be the same for both members and non-members. So, we can set the expressions equal to each other:

[tex]165+25m=40m[/tex]

And solve for m. Let's subtract 25m from both sides:

[tex]165=15m[/tex]

Now, divide both sides by 15:

[tex]m=11[/tex]

So, at the 11th music lesson, members and non-members will pay the same.

Further Notes:

This means that if a person would only like to take 10 or less lessons, the non-membership is best because there is no initial fee.

However, if a person would like to take 12 or more lessons, than the membership is best because the membership has a lower cost per lesson than the non-membership.

And we're done!

Answer:

5.  This question is hard to explain, sorry.

For every matrix A in the space of linear transformations from [tex]R^n[/tex] to [tex]R^1[/tex], there exists a unique vector y such that Ax = x.y

The norm of A is equal to the absolute value of y. This is proven using the Schwarz inequality.

Let A be a matrix in the space of linear transformations from [tex]R^n[/tex]  to [tex]R^1[/tex]. For any vector x in [tex]R^n[/tex], we can define Ax as a dot product between A and x. Let y be a vector in [tex]R^1[/tex] such that Ax = x.y for all x in [tex]R^n[/tex] . This means that the dot product of A and x yields a scalar multiple of x, where the scalar is y.

To prove uniqueness, assume there are two vectors [tex]y_{1}[/tex] and [tex]y_{1}[/tex] in [tex]R^1[/tex] such that Ax = x.[tex]y_{1}[/tex] and Ax = x.[tex]y_{2}[/tex] for all x in [tex]R^n[/tex]. Then, x.[tex]y_{1}[/tex] = x.[tex]y_{2}[/tex] for all x in [tex]R^n[/tex], which implies [tex]y_{1}= y_{2}[/tex]. Therefore, there exists a unique vector y such that Ax = x.y.

To prove that ||A|| = |y|, we can use the Schwarz inequality. The Schwarz inequality states that for any vectors u and v in [tex]R^n[/tex], |u.v| ≤ ||u|| * ||v||, with equality holding if and only if u and v are linearly dependent. Applying this inequality to the vectors A and x, we have |Ax.x| ≤ ||Ax|| * ||x||. Since Ax = x.y and ||Ax|| = ||x.y|| = |y| * ||x||, the inequality becomes |x.y.x| ≤ |y| * [tex]||x||^2[/tex]. Since the dot product x.y.x is equal to y * (x.x) = y * [tex]||x||^2[/tex], we have |y| *[tex]||x||^2[/tex] ≤ |y| * [tex]||x||^2[/tex], which holds with equality. Hence, ||A|| = |y|.

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Answer: x ≥ 5

---------------------

To land the drone on the roof of the building, it would need to fly approximately 1505.35 feet in a straight line. The angle between the ground and the drone's flight path would be approximately 5.74 degrees.

To determine the distance the drone needs to fly, we can use the Pythagorean theorem. The horizontal distance between your current position in the park and the building is given as 1500 feet, and the height of the building is 150 feet. We can consider this as a right-angled triangle, with the horizontal distance as the base and the height of the building as the perpendicular side.

Using the Pythagorean theorem, we can find the hypotenuse (flight distance) of the triangle, which represents the straight-line distance the drone needs to travel. The equation is:

hypotenuse^2 = base^2 + perpendicular^2

Substituting the values, we get:

hypotenuse^2 = 1500^2 + 150^2

hypotenuse^2 = 2250000 + 22500

hypotenuse^2 = 2272500

Taking the square root of both sides, we find:

hypotenuse ≈ √2272500 ≈ 1505.35 feet

Therefore, the drone would need to fly approximately 1505.35 feet in a straight line to reach the roof of your building.

To determine the angle of the flight path, we can use trigonometry. The angle (θ) can be calculated using the tangent function:

tan(θ) = perpendicular/base

Substituting the values, we get:

tan(θ) = 150/1500

tan(θ) = 0.1

Taking the inverse tangent (arctan) of both sides, we find:

θ ≈ arctan(0.1) ≈ 5.74 degrees

Hence, the drone should take an angle of approximately 5.74 degrees in its flight path to reach the roof of your building.

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(a) The matrix polynomial P(x) = x² can be evaluated by substituting the given 2 by 2 matrix A = [-1, 0; -2, 1] into P(x).

(b) To calculate A^-, where k is any integer, we need to find the inverse of the matrix A. Additionally, P(A) can be obtained by substituting matrix A into the matrix polynomial P(x) = x².

(a) To evaluate the matrix polynomial P(x) = x² using the given 2 by 2 matrix A = [-1, 0; -2, 1], we substitute A into P(x):

P(A) = A² = [-1, 0; -2, 1]² = [(-1)(-1) + (0)(-2), (-1)(0) + (0)(1); (-2)(-1) + (1)(-2), (-2)(0) + (1)(1)] = [1, 0; 0, -3].

(b) To calculate A^-, where k is any integer, we need to find the inverse of the matrix A = [2, -2; -2, 4]. The inverse of a 2 by 2 matrix can be found using the formula:

A^-1 = (1/det(A)) * adj(A),

where det(A) is the determinant of A and adj(A) is the adjugate of A. Calculating the determinant and adjugate of A, we have:

det(A) = (2)(4) - (-2)(-2) = 12 - 4 = 8,

adj(A) = [4, 2; 2, 2].

Therefore, A^-1 = (1/8) * [4, 2; 2, 2] = [1/2, 1/4; 1/4, 1/4].

To find P(A), we substitute A into the matrix polynomial P(x) = x²:

P(A) = A² = [2, -2; -2, 4]² = [2, -2; -2, 4] * [2, -2; -2, 4] = [4 - 4, -4 + 8; -4 + 4, 4 + 16] = [0, 4; 0, 20].

Therefore, A^-1 = [1/2, 1/4; 1/4, 1/4] and P(A) = [0, 4; 0, 20].

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Given:

Baseball is thrown at 89 miles per hour.

The ball will travel 324 feet when hit by a bat swung at 51 miles per hour.

It will travel 444 feet when hit by a boat swung at 81 miles per hour.

To find:

The addition distance travelled by the ball if the speed of bat increased by 1 unit.

Step-by-step explanation:

Let y be the number of feet traveled by the ball when hit by a bat swung at x miles per hour.  

The ball will travel 324 feet when hit by a bat swung at 51 miles per hour. So, the point is (51,324).

It will travel 444 feet when hit by a boat swung at 81 miles per hour. So, the point is (81, 444).

Equation of line passes through two points is

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-324=\dfrac{444-324}{81-51}(x-51)[/tex]

[tex]y-324=\dfrac{120}{30}(x-51)[/tex]

[tex]y-324=4(x-51)[/tex]

[tex]y-324=4x-204[/tex]

Add 324 on both sides.

[tex]y=4x-204+324[/tex]

[tex]y=4x+120[/tex]

Using the slope intercept form,  

[tex]y=mx+b[/tex]

where, m is slope.

The slope of equation [tex]y=4x+120[/tex] is 4. It means, the ball will travel 4 feet farther for each mile-per-hour increase in the speed of the bat.

Answer:

46 laps

Step-by-step explanation:

Set up a ratio:

38/95 =  s/115

cross multiply

4370  = 95s

divide both sides by 95

s= 46

Option 2 has a lower NPV and thus should be chosen as it results in less total payment and better savings. Hence, you would choose option 2 as the Net Present Value of choosing option 2 is -9,903,615.48.

Given:

Purchase price = 12.5 million baht

Down payment = 15%30-year mortgage

We have to calculate the option which is best for us.

Option 1: Mortgage rate = 7.25%

Option 2:Mortgage rate = 6.75%

(a) Monthly Payment of Option 1:

Loan Amount = 12.5 * (100-15)%

= 10,625,000 baht

n = 30 * 12

= 360

i = 7.25%/12

= 0.006042857

Yearly Interest Paid = i * 10,625,000

= 64,515.48 baht

Monthly Interest Paid = 64,515.48 / 12

= 5,376.29 baht

EMI =[tex][P x R x (1+R)^n] / [(1+R)^n-1][/tex]

where P = Loan Amount, R= Interest Rate per month, n= total number of payments.

EMI = [tex][10,625,000 x 0.006042857 x (1+0.006042857)^360] / [(1+0.006042857)^360-1][/tex]

EMI = 69,677.31 baht

(b) Monthly Payment of Option 2:

Loan Amount = 12.5 * (100-15)%

= 10,625,000 baht

n = 30 * 12 = 360

i = 6.75%/12 = 0.005625

Yearly Interest Paid = i * 10,625,000

= 59,765.63 baht

Monthly Interest Paid = 59,765.63 / 12

= 4,980.47 baht

Point cost = 4% of Loan Amount

= 10,625,000 x 4/100

= 425,000 baht

Loan Amount after Deducting Points = 10,625,000 - 425,000

= 10,200,000 baht

EMI = [tex][P x R x (1+R)^n] / [(1+R)^n-1][/tex]

where P = Loan Amount, R= Interest Rate per month, n= total number of payments.

EMI =[tex][10,200,000 x 0.005625 x (1+0.005625)^360] / [(1+0.005625)^360-1][/tex]

EMI = 66,128.92 baht

(c) We have to calculate the NPV of the payments to decide which option is better.

We use the formula to calculate NPV:-

NPV = - [tex][B + (PMT / i) * (1 - (1 + i)^-n)] / ((1 + i)^t)[/tex]

Where B = amount borrowed, PMT = monthly payment, i = interest rate, n = total number of payments, t = year.

NPV =[tex]- [10625000 + (69677.31 / 0.006042857) * (1 - (1 + 0.006042857)^-360)] / ((1 + 0.006042857)^30)[/tex]

= -9,892,571.85 baht

NPV = [tex]- [10200000 + (66128.92 / 0.005625) * (1 - (1 + 0.005625)^-360)] / ((1 + 0.005625)^30)[/tex]

= -9,903,615.48 baht

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Answer:

A

Step-by-step explanation:

Answer:

A.

Step-by-step explanation:

-18+-12+-6=-36

Answer:

4,6,8

Step-by-step explanation:

Let x = 1st even integer

x+2 =2nd even integer

x+4 =3nd even integer

x+ x+2 + x+4 = 18

Combine like terms

3x+6 = 18

Subtract 6 from each side

3x+6-6=18-6

3x= 12

Divide by 3

3x/3 =12/3

x = 4

x+2 = 6

x+4 = 8

During the current year, merchandise was sold for $662,100. Of this amount, $114,000 was cash sales and $548,100 was on account. The cost of goods sold was $423,700. Therefore, the gross profit was $238,400.

The gross profit is calculated by subtracting the cost of goods sold from the total sales. The cost of goods sold is the direct cost of producing the goods that were sold. It includes the cost of materials, labor, and overhead.

The gross profit is an important measure of a company's profitability. It shows how much money the company makes from its core business activities, before deducting other expenses.

In this case, the company's gross profit margin is 35.8%. This means that for every $100 of sales, the company makes $35.80 in gross profit. A high gross profit margin is generally considered to be a sign of a healthy business.

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1. the mechanical advantage of the rake is 0.5. 2. the efficiency of the blade adjuster is approximately 92.73%.

1. The mechanical advantage of a simple machine is determined by the ratio of the output force to the input force. In this case, the woman applies an input force of 32 N to the rake, and the rake exerts an output force of 16 N.

The mechanical advantage (MA) can be calculated as MA = Output Force / Input Force.

Using the given values, we can substitute them into the formula:

MA = 16 N / 32 N = 0.5.

Therefore, the mechanical advantage of the rake is 0.5.

Explanation:

The mechanical advantage represents the amplification of force achieved by using a machine. In this case, the mechanical advantage of 0.5 means that the rake reduces the input force by half to produce the output force. It indicates that for every 1 unit of input force applied by the woman, the rake generates 0.5 units of output force.

2. Efficiency is a measure of how effectively a machine converts input work to output work. It is calculated as the ratio of output work to input work, expressed as a percentage.

The efficiency (η) can be calculated using the formula: Efficiency = (Output Work / Input Work) * 100%.

Given that the input work is 55 J and the output work is 51 J, we can substitute these values into the formula:

Efficiency = (51 J / 55 J) * 100% ≈ 92.73%.

Therefore, the efficiency of the blade adjuster is approximately 92.73%.

Explanation:

Efficiency quantifies the effectiveness of a machine in converting the input energy into useful output energy. In this case, the blade adjuster converts 51 J of input work into 51 J of output work. The efficiency of approximately 92.73% indicates that the blade adjuster is relatively efficient, as a high percentage of the input work is effectively converted into useful output work.

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Answer:

1400

Step-by-step explanation

First I made a list of all of the first 7 carriages, so that's 125, 150, 175, 200, 225, 250, and 275. After adding those you get 1400.

Answer:

[tex]\frac{1}{6}[/tex]

Step-by-step explanation:

[tex]\frac{-36}{-216} \\=\frac{36}{216} \\=\frac{1}{6}[/tex]

Answer:

The answer to what?

Step-by-step explanation:

Answer: The equation would be P(t) = 100t + 2003

Step-by-step explanation: The equation for the population of snakes over time would be P(t) = 100t + 2003, where P represents the population of snakes and t represents the time in years. The initial population of snakes is 2003, and the population increases by 100 snakes per year.

Therefore, after t years, the population of snakes would be 100t more than the initial population of 2003.

Answer:  Three months after he purchased the computer, his balance was $1,350.  

Step-by-step explanation:

The equation that models the balance y after x​ months will be: y = -145x + 1600.

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that Zachary purchased a computer for ​$1600 on a payment plan.

Then two months after he purchased the​ computer, his balance was ​$1310. Three months  after  his balance was ​$1165.  

Equation;

Month    Balance

0            1600

2              1310

3              1165

Slopes:

(1600 - 1310) / 2  = 290/ 2 = 145

Hence,

y = -145x + 1600

Therefore the equation is; y = -145x + 1600.

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Answer:

-3y2-8+5y2-1=

2y2-9

Step-by-step explanation:

Answer:

[tex]\huge{\boxed{\sf{ 2y^{2} - 9 }}}[/tex]

Step-by-step explanation:

[tex]( - 3y^{2} - 8 ) - ( - 5y^{2}+ 1 )[/tex]

While subtracting , sign of each term of the second expression changes.

⇒[tex]- 3y^{2} - 8 + 5y^{2} - 1[/tex]

Combine like terms : [tex]-3y^{2}[/tex] and [tex]5y^{2}[/tex]

Like terms are those which have the same base.

⇒[tex]2y^{2} - 8 - 1[/tex]

Remember : The negative integers are always added but posses the negative ( - ) sign.

⇒[tex]2y^{2} - 9[/tex]

Hope I helped!

Best regards !

-[tex]\sf{ TheAnimeGirl}[/tex]

Answer:

3 is the coefficient

Step-by-step explanation:

3x + 2 = -10

The coefficient is the number that is multiplied by the variable

3 is the coefficient

Answer:

3

Step-by-step explanation:

the 'a' coefficient is 3

3 is the number infront of x (the first one)

a coefficient is the number infront of the unknown value

10x+4x-1=0

10= coefficient a

4= coefficient b

-1= coefficient c

The interquartile range (IQR) of the data set is 7.To find the interquartile range (IQR) of a data set, we need to first determine the values of the first and third quartiles.

The first quartile (Q1) represents the 25th percentile of the data, while the third quartile (Q3) represents the 75th percentile of the data. We can find these values by first sorting the data set in ascending order:

0, 0, 0, 1, 2, 2, 4, 5, 7, 8, 10

Next, we can find the median (Q2) of the entire data set, which is the value that separates the lower 50% of the data from the upper 50%:

0, 0, 0, 1, 2, | 2, 4, 5, 7, 8, 10

Q2 = 2

Now we can find Q1 and Q3. To find Q1, we take the median of the lower half of the data set:

0, 0, 0, | 1, 2,

Q1 = 0

To find Q3, we take the median of the upper half of the data set:

2, 4, 5, 7, 8, 10

Q3 = 7

Finally, we can calculate the interquartile range (IQR) as the difference between Q3 and Q1:

IQR = Q3 - Q1

= 7 - 0

= 7

Therefore, the interquartile range (IQR) of the data set is 7.

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Answer: 7

Step-by-step explanation:

Answer:

x=-3.5

Step-by-step explanation:

-3x=10.5 divide both sides by -3

Answer:

x = -3.5

Step-by-step explanation:

-3x - 4.6 = 5.9 ( add 4.6 on both sides)

-3x = 10.5 (divide by -3 on both sides)

x = -3.5

Given :

Two companies offer jane sales position. Company a pays $3,000 per month plus $250 per car sold.. Company B pays 2,500 per month plus $350 per car sold.

To Find :

Which equation could be used to determine the number of cars sold in a month, x, that would result in the same total income from each company.

Solution :

Let, x car are sold for same income.

Mathematical equation of company one :

[tex]T_1 =3000+250x[/tex]

Mathematical equation of company two :

[tex]T_2 =2500+350x[/tex]

For same income :

[tex]T_1=T_2\\\\3000 + 250x = 2500 + 350x\\\\100x = 500\\\\x=5[/tex]

So, for same total income from each company the number of cars sold in a month should be 5.

Hence, this is the required solution.

Answer:

Step-by-step explanation:

Try using g(x)

Let g(x) = y

y = 2x + 4

Interchange x and y

x = 2y + 4

Subtract 4 from both sides

x - 4 = 2y

Divide by 2

x/2 - 4/2 = 2y/2

y = x/2 - 2

This is exactly what f(x) is

So g(x) and f(x) are inverses.

Answer: The side links of polygons ABCD are equal to corresponding side lengths in the translated images. this means that lengths of sides of the polygon are preserved as the figure is translated in any direction.