Tom must accelerate at a constant rate of 0.25 m/s2 in order to finish the race in a dead heat with Joe.
What is accelerate?Accelerate is an action or process of speeding up or increasing in rate or amount. It is commonly used to describe an increase in the rate of change of velocity, or the rate of change of a variable such as time, speed, or distance. Acceleration can be generated by a variety of forces and factors, such as gravity, electrical current, centrifugal force, friction, and aerodynamic drag.
Tom must have a constant acceleration of 0.25 m/s2 in order to finish the race in a dead heat with Joe. This can be calculated using the equation for average velocity, vavg = (v1 + v2)/2, where v1 is Joe's velocity and v2 is Tom's velocity. If Joe and Tom both have the same final velocity, then their average velocity must be equal.
50 m / 10 m/s + 51 m / (9.75 m/s + a) = (10 m/s + a)
Solving for a, we get a = 0.25 m/s2. Therefore, Tom must accelerate at a constant rate of 0.25 m/s2 in order to finish the race in a dead heat with Joe.
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object a, which has been charged to 4.0 nc is at the origin. object b, which has been charged to − 8.0 nc , is at (x,y)=( 0.0 cm , 2.0 cm).
Part A) What is the magnitude of the electric force on object A?
Part B) What is the magnitude of the electric force on object B?
Part C) What is the direction of the electric force on object A?
Part D) What is the direction of the electric force on object B?
The magnitude of the electric force on object A and on object B is -7.23 × 10⁻⁴ N, and the direction of the electric force on object A is towards the charge B, and the direction of the electric force on the object B is towards the charge A.
Charge A, q₁ = 4.0 × 10⁻⁹ C
Charge B, q₂ = -8.0 × 10⁻⁹ C
Distance between the charge, r² = (0 - 0)² - (2 - 0)²
r = √(4)
r = 2 cm = 0.02 m
Permittivity of free space ε₀ = 8.8 × 10⁻¹² Far/m
The force between two charge object, F = q₁q₂/(4πε₀r²)
F = (4.0 × 10⁻⁹ × -8.0 × 10⁻⁹)/(4 × 3.14 × 8.8 × 10⁻¹² × 0.02²)
F = -7.2 × 10⁻⁴ N
Since opposite charges attracts each other, so the direction of force will be towards each other.
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in a 100-m race, the winner is timed at 10.7 s. the second-place finisher's time is 12.1 s. how far is the second-place finisher behind the winner when she crosses the finish line? assume the velocity of each runner is constant throughout the race.
The second place finisher is 39.6 m behind the winner in the race when the winner crosses the finishing line.
In the 100m race, the time for winner is 10.7s and the time for second finisher is 12.1s.
Because the velocity is constant,
Now, we know,
Velocity = Distance/Time
Velocity of winner = 100/10.7
Velocity of winner = 9.34 m/s.
Velocity of the person at second place finisher = 100/12.1
Velocity of the person at second place finisher = 8.26 m/s.
Now, the difference in time period is,
Time difference = 12.1-10.7
Time difference = 1.4 s.
Now, the distance between the runner is given by,
Distance = Velocity of second finisher x time difference
Distance = 8.26 x 1.4
Distance = 39.6 m.
So, the second finisher is 39.6 m behind the winner when she crosses the finish line.
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A circuit contains a 10 Ohm heater and six 240 Ohm lamps,
each containing a 60 Watt bulb, all connected in series. The
voltage across the circuit is 120 V. What is the current in the
circuit when only 4 lamps are turned on? What is the current in
the circuit when all the lamps are turned on? What is the
current in the circuit when all six lamps and the heater are
turned on? If the circuit has a fuse which will melt if the current
exceeds 12 A, will the fuse melt?
Answer -
1. Since the circuit is connected in series, the current in the circuit will be 0 if all the components of the circuit are not turned on. This is because of the single path that a series circuit has. So here, when only 4 lamps are turned on, the current in the circuit will be 0.
2. In this case as well, the current passing through the series circuit will be 0 as the heater which is connected to the circuit through series connection is not switched on.
3. If all the components of the series circuit is turned on,
Equivalent Resistance,
Rn = R1 + R2 + R3 + R4 + R5 + R6 + R7
Rn = 10Ω + 240Ω + 240Ω + 240Ω + 240Ω + 240Ω + 240Ω
∴ Rn = 1450Ω.
Then, current flowing through the circuit will be V/Rn.
I = V/Rn
I = 120V / 1450Ω
I = 0.08275 A
I ≈ 0.083.
4. The fuse will not melt as it is of 12A and the current flowing through the series circuit is 0.083, which is less that 12A.
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why is benzaldehyde not soluble in water
Benzaldehyde is not soluble in water because it is a non-polar molecule and water is a polar solvent.
Non-polar substances tend to dissolve in other non-polar substances, while polar substances dissolve in polar solvents. This is due to the fact that the polar water molecules form hydrogen bonds with each other, and the non-polar benzaldehyde molecule is unable to interact with these hydrogen bonds. As a result, benzaldehyde remains separate from the water molecules and does not dissolve in water. A non-polar substance is a chemical substance that does not have a charged distribution of electrons, meaning it does not have distinct positive and negative regions. These substances have a uniform distribution of electrons, resulting in a symmetrical molecule that does not have any polar bonds.
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name the phenomenon in which the colors of light depend on the viewing angle
Iridescence is the name of the phenomena in which the colors of light depend on the viewing angle.
Iridescence is also known as goniochromism. It is an optical phenomenon in which color of the surface appears to change with the different angle of observation. In this certain types of surfaces that appear to gradually change their colors as the viewing angle or the angle of illumination changes.
Some examples of iridescence include feathers, soap bubbles, seashell nacre, and butterfly wings and minerals such as opal. This effect takes place due to the wave interference of light in microstructures or thin films.
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a 0.30-kg ball is attached at the end of a 0.90-m-long stick. the ball and stick rotate in a horizontal circle. because of air resistance and to keep the ball moving at constant speed, a continual push must be exerted on the stick, causing a 0.036 nm torque. determine the magnitude of the resistive force that the air exerts on the ball opposing its motion.
The applied torque = air resistance torque =0.036 (N/M)
What is the magnitude of the resistive force?In order for the ball to rotate at constant speed, the total torque on it should be zero (from Newton’s second law).
Then, the applied torque = air resistance torque =0.036 (N/M)
The equation F=arv+br2v2 expresses the amount of the resistive force (in newtons) exerted by a stream of air traveling at speed v (in meters per second) on a sphere of radius r (in meters), where a and b are constants with suitable SI units.
The resistive force exerted on a body moving with velocity V through a fluid at rest is given by F = CoV2 Ap, where CD denotes the coefficient of drag and A denotes the area of cross-section perpendicular to the direction of motion.
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two squirrels are eating on the same tree branch. one squirrel is eating an apple and the other squirrel is eating an acorn. if both squirrels accidently drop their food, will the apple or the acorn have the greater speed when it hits the ground? (assume air resistance is negligible.)
The speeds of the apple and the acorn when they hit the ground will be: the same
What is gravity?In physics, gravity is the force of attraction that the earth exerts on all bodies possessing mass by pulling them toward its center.
When an object is dropped (in the absence of air resistance) it has a positive acceleration equal to the gravity.
Therefore, no matter in which instant of the movement the apple and the acorn are, their acceleration will always be equal to the acceleration of gravity 9.8 m/s², and their speeds will be the same when they hit the ground
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two forces act on an object , one force is 7N west and other force is 12N north find the magnitude and direction of the resultant force by accurate construction and measurement
By careful construction and measurement, -5N is the magnitude and direction of the resulting force.
How do you calculate the sum of the effects of two forces on a point?Calculate the resultant force by deducting the larger force's size from the smaller force's magnitude. The direction of the smaller force and the resulting force are identical.
When two forces apply on an object 20N to the north and 12N to the south, the resultant force will act towards the north with a magnitude of 8N.
Create coordinate axes on the free-body diagram. It is best to separate the X and Y components from the forces acting on the item. The x and y components of the final force are obtained by adding the x and y components of each force.
7N - 12N = -5N.
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Question:
A 385 kg car is parked on a 10.0-degree inclined road with the handbrake disengaged. With what acceleration would the car slide down, assuming the road is frictionless?
Weight:
When an object is placed on an inclined surface then its weight acts downwards. For ease of calculations, we can resolve the weight vector into the components, along the plane, and perpendicular to the plane.
The perpendicular component is balanced by the normal reaction from the plane.
The acceleration with which the car would slide down a frictionless 10.0-degree inclined road is 9.8 m/s^2.
The weight of the car acts downwards, and when placed on an inclined surface, we can resolve it into two components - one along the plane and the other perpendicular to the plane.
The component perpendicular to the plane is balanced by the normal reaction from the plane. The component along the plane is given by the equation W * sin(θ), where W is the weight of the object and θ is the angle of inclination.
In this case, the weight of the car is 385 kg, and the angle of inclination is 10.0 degrees, so W * sin(10) = 385 * sin(10) = 63.4 kg. This is the component of the weight acting along the plane.
Since the road is frictionless, the only force acting on the car is its weight along the plane, and this force will cause the car to accelerate downwards. Using Newton's second law, we can calculate the acceleration as follows:
F = ma, where F is the force acting on the car, m is its mass, and a is its acceleration.
Since F = W * sin(θ), substituting the values we have,
a = F / m = (63.4 kg) / (385 kg) = 9.8 m/s^2.
So, the acceleration with which the car would slide down the frictionless 10.0-degree inclined road is 9.8 m/s^2.
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First come first serve, solve it properly and get points.
Explanation:
Solubility is the ability to dissolve within a solvent to form a mixture called a solution
If a substance is soluble, it dissolves in water
If a substance is insoluble in water - it does not dissolve
Boling point - the temperature at which a substance in its liquid state
converts into the same substance in its gas state.
Water boils at 100 degree centigrade.
Melting point - the temperature at which a substance in its solid state
converts into the same substance in a liquid state.
Ice melts at 0 degree centigrade.
Water freezes at 0 degree centigrade.
How much matter (mass) is packed into a specific space (volume).
Answer:La verdad no tengo conocimiento alguno pero solo te puedo decir que las opciones que te dan en la hoja te pueden ayudar
Explanation:
which of the visual elements can best be described as ""the path of a moving point""? group of answer choices motion time line light
The visual elements can best be described as "the path of a moving point"
(c). line is correct option.
The two most fundamental visual signals for suggesting depth on a flat surface are used in the Indian picture from the 18th century depicting Maharana Amar Singh and others watching musicians and acrobats.
The following is the appropriate response to the question that was previously posed: "Line." The line that represents "the route of a moving point" is the best way to express the visual components. Depending on the direction you are pointing, a line may be vertical or horizontal.
The two most fundamental visual signals for suggesting depth on a flat surface are used in the Indian picture from the 18th century depicting Maharana Amar Singh and others watching musicians and acrobats. Chiaroscuro and hatching are what they are.
The complete question is,
Which of the visual elements can best be described as "the path of a moving point"? - motion - time - mass - line - light
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Samantha builds a lever to lift objects in a science experiment. The load arm is 0.4 meters. If she wants the lever to have a mechanical advantage of 8, how long should the effort arm be?
The effort arm of the lever should be 3.4 meter long to have a mechanical advantage of 8.
What is mechanical advantage?The force amplified by utilizing a tool, mechanical device, or machine system is known as mechanical advantage.
To achieve the desired output force amplification, the gadget trades off input forces against movement. The law of the lever serves as a paradigm for this.
mechanical advantage of a lever = 8
Hence,
mechanical advantage of a lever = effort arm/load arm
Effort arm of a lever = Mechanical advantage × load arm
= 8 × 0.4 m
= 3.2 m.
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the scientist, who invented the first incandescent light bulb and who, at one point, had a monopoly on the electrical power delivery was ______.
1. Wilhelm Roentgen
2. George Westinghouse
3. Thomas Edison
4. Relay Switch
Thomas Edison invented the first incandescent light bulb and, at one point, had a monopoly on the electrical power delivery. Correct option is 3.
Thomas Edison was an American inventor and businessman who is best known for his development of the incandescent light bulb. He began working on the light bulb in 1878 and by 1879, he had developed a bulb that could burn for several hours. Edison went on to improve the design of the bulb and also developed a system for delivering electrical power to homes and businesses, which he called the Edison Electric Light Company.
At its height, the Edison Electric Light Company held a monopoly on the electrical power delivery industry, which allowed Edison to control the distribution of electrical power to homes and businesses. This monopoly lasted for several years until the arrival of competitors, such as George Westinghouse, who developed an alternative system for delivering electrical power.
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a steel ball of mass 0.50 kg is fastened to a cord 70 cm long and is released when the cord is horizontal. at the bottom of its path, the ball strikes a 2.5 kg steel block initially at rest on a frictionless surface. the collision is elastic. find (a) the speed of the ball and (b) the speed of the block, both just after the collision.
a) The final speed of the ball is 2.47 m/s.
b) The final speed of the block is 1.23 m/s.
Given,
The mass of the steel ball (m) = 0.5 Kg
The length of the cord or the height at which the ball is (h) = 0.7 m
The mass of steel block (M) = 2.5 Kg.
To find,
a) The speed of the ball just after the collision(v₁)
b) The speed of the block just after the collision(v₂).
Now from the conservation of energy:
Decrease in potential energy (mgh) = increase in kinetic energy (1/2 mv²)
mgh = 0.5mv²
⇒ 10 × 0.7 = 0.5 v²
⇒ 14 = v²
⇒ v = 3.7 m/s
a) Now we know that the velocity of ball v₁ is
[tex]v_1 = \frac{m - M}{m + M}v[/tex]
⇒ [tex]v_1 = \frac{0.5 - 2.5}{0.5 + 2.5} \times 3.7[/tex]
⇒ v₁ = -2.47 m/s
Hence, the final speed of the ball is 2.47 m/s
b) Now for the velocity of the block v₂ is:
[tex]v_2 = \frac{2m}{m+M}v[/tex]
⇒ [tex]v_2 = \frac{2\times 0.5}{0.5 + 2.5} \times 3.7[/tex]
⇒ v₂ = 1.23 m/s
Therefore, the final speed of the block is 1.23 m/s.
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suppose and 46 mm, then what is the value of ? express your answer in milli-coulombs per square meter (10-3 c/m2) to one place after the decimal. don't forget the minus sign if the answer is negative.
The electric field strength is 0.046 C/m2, or 0.046 x 10-3 C/m2, or 0.046 mC/m2, at a distance of 46 mm (to one place after the decimal).
Calculate the electric field strength (E) at a distance of 46 mm using the formula
E=V/d, where V is the voltage and d is the distance.
E = V/d = (46 mm)/(1000 mm)
E = 0.046 V/m
Convert this electric field strength to milli-coulombs per square meter (10-3 c/m2) using the formula E=q/A, where q is the charge and A is the area.
We can assume that the area is 1 m2, and q is the electric field strength (0.046 V/m) multiplied by one coulomb, which is 1 C.
Therefore, q = (0.046 V/m) x (1C) = 0.046 C.
Calculate the electric field strength using the formula E = q/A.
E = q/A = (0.046 C)/(1 m2) = 0.046 C/m2
Convert the electric field strength to milli-coulombs per square meter (10-3 c/m2).
The electric field strength at a distance of 46 mm is 0.046 C/m2, which is equivalent to 0.046 x 10-3 C/m2, or 0.046 mC/m2 (to one place after the decimal).
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the apparatus represented in the (figure 1) consists of five identical balls mounted on elastic rods. each elastic rod is connected to a base. the (unlabeled) ball and rod on the far left are pulled towards the screen (that is, toward you) and released. which of the ball-and-rod combinations will have the largest amplitude of oscillation?
The correct option is D. This is due to the fact that the rod in D has the same length as the vibrating rod (unlabeled), making it more likely for it to enter into resonance and generate a more pronounced oscillation.
In a complex mixture of chemical compounds that are reacting, a chemical oscillator is one in which the concentration of one or more components changes on a regular basis.
A trustworthy point level sensor for high and low level indication or plugged chute detection is a vibrating rod, also known as a vibrating level switch. Bulk densities of as little as 1.25 lb/ft3 can be used for their use in light, fluffy powders and flakes.
Therefore, option (d) is correct-This is because, the rod in D has same length as the vibrating rod (unlabeled) so its more likely to get in resonance with that that's why it oscillates more vigorously.
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a ball is thrown in a horizontal direction from the roof of a building with an initial speed of 20 m/s. the ball strikes the ground 120 m from the base of the building as shown. how high is the building?
The ball is thrown in a horizontal direction from the roof of a building with an initial speed of 20 m/s. The ball strikes the ground 120 m from the base of the building. The height of the building is 180m.
The horizontal distance the ball travels before touching the ground, x= 120m. The initial speed with which the ball is thrown is u=20 m/s. So the time is taken by the ball to reach the ground, t= x/u =120/20 =6 secs.
Now, t=6 secs is the time taken by the ball to reach the ground. So the height of the building is given by the equation, h= ut+1/2gt², where u is the initial speed in the vertical direction and g is the acceleration due to gravity and its value is g= 10m/s². The initial speed in the vertical direction is 0m/s. So, h= 1/2gt² , =1/2×10×6×6 =180m.
So the height of the building is 180m.
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a stationary object explodes, breaking into piece three pieces with the masses m, m, and 3m. the two pieces of the mass m move off at right angles to each other with the same magnitude of velocity. what are the magnitude and direction of the velocity of the piece having a mass 3 m.
The magnitude of the velocity of the piece having mass 3m is three times the velocity of the pieces having mass m.
The direction of the velocity of the piece having mass 3m is at an angle of 90 degrees to the direction of velocity of the pieces having mass m.
When the two pieces of mass m move off at right angles to each other, their momentum vectors cancel each other out. This means that the total momentum of the system must remain the same, so the third piece of mass 3m must move in a direction at 90 degrees to the direction of the two pieces of mass m.
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[OU.04]Two stars, Star 1 and Star 2, are at almost equal distances from Earth. The table below shows the masses of the two stars.
Name of Star Mass of Star (in million solar masses)
Star 1 3.61
Star 2 11.73
I am lost on this question HELP
Which of these statements is most likely correct about the stars?
Earth exerts a greater gravitation force on Star 1 than on Star 2.
Earth exerts a greater gravitation force on Star 2 than on Star 1.
Star 1 attracts Star 2 with a greater gravitational force than Star 2 attracts Star 1.
Star 2 attracts Star 1 with a greater gravitational force than Star 1 attracts Star 2.
Answer: Which of these statements is most likely correct about the stars?
Star 2 attracts Star 1 with a greater gravitational force than Star 1 attracts Star 2.
No, because Third Newton Law states that both forces are equal in magnitude.
Earth exerts almost equal gravitation force on both the stars.
No, because the Universal Gravitational Law, estblished by Newton, states the atraction force to two masses is proportional to the product of the masses.
Star 1 attracts Star 2 with a greater gravitational force than Star 2 attracts Star 1.
No (same reason for the first statement)
Earth exerts greater gravitation force on Star 2 than on Star 1.
Right. This is the correct statement. Given the mass of Star 2 is greater than the mass of Star 1, by the Universal Gravitational Law, the earth exerts greater gravitational attraction on Star 2.
Explanation:
:)
if an element has 30 protons and 33 neutrons , what is the mass?
Answer: 63
Explanation: That would be 30 Plus the number of neutrons, that is 33. So let's write 33 and we add we get 63. So the mass number of this item is 63.
a 1.6-cm-diameter brass sphere has been given a charge of 2 nc. what is the electric field strength at the surface of the sphere?
The electric field strength at the surface of the sphere is calculated to 45 × 10⁴ C.
The diameter of the conducting sphere is d = 1.6 cm.
The radius of the conducting sphere will be
r = d/2 = (1.6 × 10⁻²)/2 = 0.8× 10⁻² m
The charge on the sphere is q = 4 nC = 4 × 10⁻⁹ C
The force on the surface due to the charge is,
F = 1/(4π∈₀) × q/r² = [(9×10⁹)× 4 × 10⁻⁹]/(0.8 × 10⁻⁴) = 45 × 10⁴ C
So, the surface electric field strength will be 45 × 10⁴ C
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Peak values for a neodymium-glass laser are 600 joules for 1 nanosecond. If the cross-section of the laser beam is 1 cm2, what are the maximum values of E and B? (µ0 = 4p ´ 10-7 T-m/A)
The energy of a laser is described by two parameters: the peak value and the pulse duration. The peak value of a neodymium-glass laser is 600 joules for 1 nanosecond. In this case, the cross-section of the laser beam is 1 cm2.
A laser is a device that produces a concentrated beam of light with a very high energy density. To find the maximum values of E and B, we need to use the relationship between these quantities and the electromagnetic field generated by the laser. The electric field E is proportional to the rate of change of the magnetic field B, which in turn is proportional to the current flowing through the laser.
So, the maximum values of E and B can be calculated from the peak value and the pulse duration of the laser. To do this, we first calculate the peak current in the laser using the peak value and the cross-section of the beam. The peak current is given by I = E/R, where R is the resistance of the laser. In this case, we assume that R is very small, so the peak current is equal to the peak value divided by the cross-section of the beam.
Next, we use Faraday's law of induction to calculate the maximum value of the magnetic field B. Faraday's law states that the rate of change of the magnetic field is proportional to the current flowing through the laser. So, B = μ0I/2πr, where μ0 is the permeability of free space and r is the distance from the centre of the beam.
Finally, we use the relationship between the electric and magnetic fields to find the maximum value of the electric field E. The electric field is proportional to the rate of change of the magnetic field, so E = dB/dt. Since the pulse duration of the laser is 1 nanosecond, we can calculate the maximum value of E by taking the derivative of B with respect to time.
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what is the magnitude of the net force on q3 from q1 and q2 if q1=q2=q3=5.67×10−8c , and d = 60.0 cm ?
Q 1 equals 4 Q 3 because Q 2 equals Q 3. The sum of the forces acting on q2 determines its magnitude. F = k q a q b r 2 is the formula we use to compute each individual force.
The right answer is D) Q 2 and Q 3 have the same magnitude but the opposite sign.∴
Due to their mutual attraction, Q 2 and Q 3 feel an attractive force. Now, Q 1 must have a sign from Q 3 to repel it so that the net force on Q 3 is zero r 2.
−kQ \s2 \s \s Q \s3
\s = \s(2r) \s2
k(Q \s1 \s \s )Q \s3
⇒Q \s1 \s \s =−4Q \s2
Q 1 equals 4 Q 3 because Q 2 equals Q 3.
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how long does it take for the top to complete the first five revolutions? the string is long enough that it is wrapped around the top more than five turns.
Top requires 0.57 s to complete its first five revolutions.
How long does it take for the top to complete the first five revolutions?
A toy top with a spool of diameter 5.0 cm has a moment of inertia of 3.0×1025 kg⋅m2 about its rotation axis. To get the top spinning, its string is pulled with a tension of 0.30 N.A spinning top, or simply a top, is a toy with a squat body and a sharp point at the bottom, designed to be spun on its vertical axis, balancing on the tip due to the gyroscopic effect.Once set in motion, a top will usually wobble for a few seconds, spin upright for a while, then start to wobble again with increasing amplitude as it loses energy, and finally tip over and roll on its side.Tops exist in many variations and materials, chiefly wood, metal, and plastic, often with a metal tip. They may be set in motion by twirling a handle with the fingers, by pulling a rope coiled around the body, or by means of a built-in auger (spiral plunger).To learn more about top refers to:
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thermal energy is added to 150 g of water at the rate of 55 j/s for 2.5 min. how much does the temperature of the water increase ?
If thermal energy is added to 150 g of water at a rate of 55 J/s for 2.5 minutes, the temperature of the water will increase by 6.58°C, as calculated using the equation for specific heat capacity.
To determine the increase in temperature of 150 g of water when thermal energy is added at a rate of 55 J/s for 2.5 minutes, we need to calculate the amount of heat energy added to the water and use this to determine the increase in temperature.
The amount of heat energy added to the water can be calculated as follows:
Q = 55 J/s * 2.5 min * 60 s/min = 6675 J
Next, we can use the equation for specific heat capacity to determine the increase in temperature of the water:
ΔT = Q / (mass * specific heat capacity)
where ΔT is the increase in temperature, Q is the heat energy added, mass is the mass of water (150 g), and specific heat capacity is the amount of heat energy required to raise the temperature of 1 g of water by 1°C (usually around 4.18 J/g°C).
Substituting in the values, we have:
ΔT = 6675 J / (150 g * 4.18 J/g°C) = 6.58°C
So the temperature of the water would increase by 6.58°C.
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Where is the acceleration negative?
A. B-D
B. C-E
C. A-B
D. D
the answers is bce because I di that before
a total of 580 c of charge passes through a flashlight in 0.480 h. what is the average current in milliamperes? ma
A total of 580 c of charge passes through a flashlight in 0.480 h. The average current in milliamperes is 1208330 milliamperes.
The average current (I) can be calculated as the charge (Q) divided by the time (t) taken to pass that charge.
I = Q / t
Substituting the given values, we get:
I = 580 coulombs / (0.480 hours) = 1208.33 Amperes
To convert Amperes to milliamperes, we multiply by 1000:
I = 1208.33 Amperes x 1000 milliamperes/Ampere = 1208330 milliamperes
So the average current in milliamperes is 1208330 milliamperes.
Current is a measure of the flow of electric charge in a circuit. It is a scalar quantity and is typically measured in Amperes (A). The flow of electric charge is caused by the movement of electrons through a conductor, such as a wire. The direction of current is conventionally defined as the direction of flow of positive charge, even though electrons are negatively charged. The magnitude of the current depends on the number of electrons flowing past a point in a given time.
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g an inertia load of 0.04 kg m2 is accelerates from standstill with a constant torque applied. it reaches 100 rad/s in 2.0 s. what is the applied torque?
The applied torque is 800 N-m.
What is the applied torque?
This question uses the equation for torque: Torque (T) = Moment of inertia (I) × Angular acceleration (α).
This equation can be derived from Newton's second law by considering the rotational motion of an object.
The steps for calculate the applied torque as follows
Step 1: Calculate the moment of inertia.
Inertia load = 0.04 kg m2
Moment of inertia (I) = 0.04 kg m2
Step 2: Calculate the angular acceleration.
Angular acceleration (α) = (100 rad/s) / (2.0 s) = 50 rad/s2
Step 3: Calculate the applied torque.
Torque (T) = Moment of inertia (I) × Angular acceleration (α)
T = (0.04 kg m2) × (50 rad/s2)
T = 800 N-m
The applied torque is 800 N-m
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pls helpHow do scientists reduce the number of unwanted variables in an experiment?
a.by only having one scientist work on each experiment
b.by conducting multiple experiments at the same time
c.by performing experiments under laboratory conditions
d.by performing additional background research
The way scientists reduce the number of unwanted variables in an experiment is c.by performing experiments under laboratory conditions
What is an Unwanted Variable?Anything that might have an impact on the dependent variable is considered an unnecessary variable.
In addition to influencing the independent variable, a confounding variable also correlates with or has a causal relationship with the dependent variable.
With this in mind, by using a controlled method in a lab, they are able to reduce the number of unwanted variables in an experiment.
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When you enter cos(30°) into your calculator, you get the answer of 0.5 and when you enter into your calculator cos(-30°) you still get 0.5. Explain to the best of your ability why you think you get the same answer even though the angle you enters is different?
Answer:
The reason why you get the same answer when you enter cos(30°) and cos(-30°) into your calculator is because cosine is a periodic function, which means that the same value is repeated after a certain interval. In the case of cosine, the interval is always 360°, so cos(30°) and cos(-30°) are equivalent because they are both equal to 30° away from 0°. Therefore, they both have the same value, which is 0.5.
