JUST NEEDDD A BIT OF HELPPP PLSS

[tex]g(x)=5cos((\pi )/(2)x-(3\pi )/(2))-2[/tex]

generate by:  Amplitude:5    Period:4

                      Phase shift:(3 to the right)    Vertical shift:-2

x=3,g(x)= 3

x=4,g(x)= -2

x=5,g(x)= -5

x=6,g(x)= -2

x=7,g(x)= 3

the graph is like cos(x)

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Answer:

Wayne used 2/5 more flour than sugar

Step-by-step explanation:

If you add 2/5 to 2/5 you get 4/5

Answer:

Graph b.

Step-by-step explanation:

B is not a function because it fails the vertical line test.
To be a function any vertical line drawn must pass through the graph at one point only. That is not true for graph B - a line can pass through 2 points on this graph.

1

Anything raised to the power of zero is 1, other than zero itself.

However, as it is given that x is not equal to zero, the answer must be 1.

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation: }[/tex]

[tex]\mathsf{(4x^2)^0}[/tex]

[tex]\huge\textbf{Simplifying:}[/tex]

[tex]\mathsf{(4x^2)^0}\\\\\mathsf{= (4 \timesx^2)^0}\\\\\mathsf{= 4(x \times x)^0}\\\\\mathsf{= (4x^2)^0}\\\\\mathsf{= 1}[/tex]

[tex]\huge\textbf{Therefore, your answer should:}[/tex]

[tex]\huge\boxed{\frak{1}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Mya would have both lessons on the same day again on the 12th day.

In order to determine when they would have the both lessons on the same day, the common multiple of 6 and 4 has to be determined. A multiple of a number is the product of an integer and that number. A common multiple is the multiple that is common to two or more numbers.

Multiple of 6 = 6, 12, 28, 24, 30, 36,

Multiple of 4 = 4, 8, 12, 16, 20, 24, 28

Common multiple = 12

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Using the normal distribution, the probability that x is less than 110 is:

A. 0.975.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given as follows:

[tex]\mu = 98, \sigma = 6[/tex]

The probability is the p-value of Z when X = 110, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{110 - 98}{6}[/tex]

Z = 2

Z = 2 has a p-value of 0.975.

Hence option A is correct.

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Answer:

[tex] - 0.2026[/tex]

Step-by-step explanation:

I hope it is the right answer

An inequality greater than (-3) but less than or equal to 3 is as follows:

- 3 < x ≤ 3

An inequality compares two values, showing if one is less than, greater than, or simply not equal to another value.

An inequality have the following signs:

Therefore, an inequality greater than (-3) but less than or equal to 3 can be represented as follows:

Note the value we are comparing is x.

Hence,

- 3 < x ≤ 3

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Answer:

no solution

Step-by-step explanation: because if it has no variables that are the same it has no solution.

Answer: 4.5

Step-by-step explanation:

2 + 0.5x

x = 5

2 + 0.5 ( 5 )

2 + 2.5

2 + 2.5 = 4.5

Hope this helps!

Answer: C, 93m^2

Step-by-step explanation:

first step is to find the surface area of the base. it's 3x3, so that would be 9m^2. the sides of the rectangular prism are 5x3, so one side is 15m^2. there are 4, so 15x4=60m^2. now for the top, which is a triangular prism. each side has a height of 4 and a base of 3. the area of a triangle is 1/2bh, so 1/2(3)(4), which is 6. 4 of these makes 24 m^2. add up all of final numbers to get 9+60+24. this comes to 93m^2, or C.

Answer:  25 pounds

Step-by-step explanation: 100% - 20% = 80%

20 divided by 80% = 25

[tex]f(1)[/tex] is [tex]81.[/tex]

To find  f(1):

f(n 1) = one-half(n).

f(3) = 9.

[tex]f(3) = 9If n = 1,f(2) = 9×3f(2) = 27If n = 0,f(1) = 27 ×3f(1) = 81[/tex]

A sequence is defined by the recursive function [tex]f(1)[/tex] is [tex]81.[/tex]

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Answer:

36

Step-by-step explanation:

Assuming I understand the question correctly

[tex]\text{one-halff(n)} = \frac{1}{2} f(n)[/tex]

We have the recursive relationship

[tex]f(n+1) = \frac{1}{2} f(n)[/tex]

[tex]f(3) = 9[/tex]

[tex]f(3) = \frac{1}{2} f(2)[/tex]

[tex]f(2) = \frac{1}{2} f(1)[/tex]

So

[tex]f(3) = \frac{1}{2} (\frac{1}{2} f(1) = \frac{1}{4} f(1) \\[/tex]

So [tex]f(1) = 4f(3) = 4(9) = 36[/tex]

Verifying

If f(1) = 36 then f(2) = (1/2)f(1) = (1/2)36 = 18

f(3) = (1/2) f(2) = (1/2)(18) = 9

The number of boys wear glasses are 156 boys.

In this question,

Total number of pupils in the school = 910

Ratio of boys = 3/7

Then, number of boys = 910 × 3/7

⇒ 130 × 3

⇒ 390

Ratio of boys wear glasses = 2/5

Then, number of boys wear glasses = 390 × 2/5

⇒ 78 × 2

⇒ 156

Hence we can conclude that the number of boys wear glasses are 156 boys.

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The conceptual and quantative relationship between  Alpha risk and Beta risk is related to the probability of accepting Null hypothesis. They are also known as Type 1 and type 2 error.

Alpha Risk:

Alpha risk is the risk that in statistical test a null hypothesis will be rejected when it is actually true. This is also known as a type I error, or a false positive. The term risk refers to chance or likelihood of making an incorrect decission.

Beta risk:

Beta risk represents the probability that a false hypothesis in a statistical test is accepted as true. Beta risk contrast with alpha risk, which measures the probability that a null hypothesis is rejected when it is actually true.

Determining the type of risk in a quantitative relationship is primarily based on sample size. The Sample Size directly affect the Alpha and Beta risk. If Sample size is larger, the Alpha and Beta risk will lower, and if the sample size is lower the risk of Beta and Alpha increases.

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The conjugate which is 3 - √7 is also a root of f(x).

The root of a polynomial function f(x) is the value of x for which f(x) = 0.

Now if a polynomial function has a root x = a + √b then the conjugate of x which is x' = a - √b is also a root of the function, f(x).

Given that the polynomial function, f(x), with rational coefficients has roots

3 + √7, then by the above, the conjugate which is 3 - √7 is also a root of f(x).

So, 3 - √7 is also a root of f(x).

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Horizontal asymptote y = 1.

Find the horizontal asymptote of the function:

Horizontal asymptotes are the lines perpendicular to the y-axis and meet the curve at infinity.

Horizontal asymptote y = 1.

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The real statement is that the closer you get to the center of the vortex, the closer the current speed approaches infinity. option C is correct.

Given the speed s of the flow in a given vortex is modeled by x=300/d, where d is the distance to the center of the vortex.

speed is defined as the rate of change of an object's position in any direction. Speed ​​is measured as the ratio of distance traveled to time traveled.

As d approaches 0, you are approaching the center of the vortex.

[tex]\begin{aligned}S&=\lim_{d\rightarrow 0}\frac{300}{d}\\ &=\frac{300}{0}\\ &=\infty\end[/tex]

Thus, if the flow in a given vortex is modeled by x = 300/d, as one approaches the center of the vortex, the speed of the flow tends to infinity.

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Answer: C- As you move closer to the center of the whirlpool, the speed of the current approaches infinity.

The line of best fit for the information in this graph is:

f(x) = 200x + 100.

To find the equation, we need to insert the points (x,y) in the calculator.

For this problem, the points (t,v) are given as follows:

(2, 500), (3, 700), (4, 900), (5, 110)

Hence, inserting these points into a calculator, the equation is given by:

f(x) = 200x + 100.

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The perpendicular bisector of a chord passes through the center of a circle.

In geometry, a chord is a straight line segment that connects two points on the circumference of a circle. It is the longest possible segment within the circle.

The perpendicular bisector of a chord is a line that passes through the midpoint of the chord, creating two equal halves, and is perpendicular to the chord.

Notably, for any chord in a circle, its perpendicular bisector always intersects at the center of the circle, making it a significant geometric property.

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The equation 23 · y + 50 + 27 · y = 50 · y + 50 has infinite solutions.

In this question we have an equation in implicit form: 23 · y + 50 + 27 · y = 50 · y + 50, we need to transform its expression into explicit form by using algebra properties:

23 · y + 50 + 27 · y = 50 · y + 50         Given

50 · y + 50 = 50 · y + 50                      Commutative, associative and distributive properties / Definition of addition

0 = 0 Compatibility with addition / Existence of additive inverse / Modulative property / Result

The equivalence indicates that the equation 23 · y + 50 + 27 · y = 50 · y + 50 has infinite solutions.

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Answer:

-7624928000 is the right answer.

Step-by-step explanation:

(-7624928) × 997 + 7624928 × (-3)

= -7602053216 + (-22874784)

= -7624928000        Ans..

Hope its helpful :-)

If so, please mark me as brainlist :-)

Answer:

Step-by-step explanation:

=(-7624928) * 997 + 7624928 * (-3)

=-7602053216+(-22874784)

=-7624928000

If the p-value is smaller than the level of significance, then it indicates strong evidence against the null hypothesis, as there is less than a 5% probability the null hypothesis is correct.

In this question,

A p-value is a probability, calculated after running a statistical test on data and it lies between 0 and 1. The p-value only tells you how likely the data you have observed is occurred under the null hypothesis.

One of the most commonly used p-value is 0.05. If the value is greater than 0.05, the null hypothesis is considered to be true. If the calculated p-value turns out to be less than 0.05, the null hypothesis is considered to be false, or nullified (hence the name null hypothesis).

A small p-value (< 0.05 in general) means that the observed results are unusual, assuming that they were due to chance only. Now, the smaller the p-value, the stronger the evidence that should reject the null hypothesis.

Hence we can conclude that if the p-value is smaller than the level of significance, then it indicates strong evidence against the null hypothesis, as there is less than a 5% probability the null hypothesis is correct.

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By the comparison test, the series converges.

We have

[tex]\dfrac1{k\sqrt{k+2}} \le \dfrac1{k \sqrt k} = \dfrac1{k^{3/2}}[/tex]

so we can compare to a convergent [tex]p[/tex]-series,

[tex]\displaystyle \sum_{k=1}^\infty \frac1{k\sqrt{k+2}} \le \sum_{k=1}^\infty \frac1{k^{3/2}} < \infty[/tex]

By the comparison test, the series converges.

What are convergence series and diverging series?

If the infinite series converges to a real number it is called converging if not then it is called diverging series.

If the larger series is convergent the smaller series must also be convergent. Likewise, if the smaller series is divergent then the larger series must also be divergent.

For this series to be converging it must follow the following :

⇒ [tex]| \frac{t_{n+1} }{t_{n} } | \leq 1[/tex]

⇒Putting n = 1

[tex]| \frac{t_{2} }{t_{1} } | \leq 1[/tex]

[tex]\t_{2} t_{1}[/tex] [tex]t_{2}[/tex]= 1/4

[tex]t_{1}[/tex]=1/[tex]\sqrt{2}[/tex]

[tex]\frac{t_{2} }{{t_{1} }}[/tex] = 1/2[tex]\sqrt{2[/tex]

⇒ t₂/t₁≤1

⇒ Hence it converges

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The length of edge FC in the triangular prism is: 12 cm.

Volume of a right triangular prism = 1/2(Length of triangular base × height of triangular base × height of the prism).

Considering the image given showing a right triangular prism, we have the following:

Volume of triangular prism = 900 cubic centimeters

Length of triangular base = FC = ?

Height of triangular base = 10 centimeters

Height of the prism = 15 centimeters

Plugin the values

900 = 1/2(FC × 10 × 15)

900 = 1/2(FC × 150)

Multiply both sides by 2

2(900) = 2(1/2(FC × 150))

1,800 = FC × 150

Divide both sides by 150

1,800/150 = FC × 150/150

12 = FC

FC = 12 cm

The length of edge FC is: 12 cm.

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Answer: 12

Step-by-step explanation:

Answer:

.....................................

68 is the wrong number in the sequence 808, 408, 208,108, 68

A number system is defined as a system of writing to express numbers.

Sequence is an enumerated collection of objects in which repetitions are allowed and order matters.

The given sequence is 808, 408, 208,108, 68

Eight hundred eight, Four hundred and eight, two hundred and eight, one hundred eight and sixty eight.

808, 408, 208,108, 68

Let us find the difference between the consecutive numbers

400, 200, 100, 40

As we observe the first three terms having the common ratio where as 40 and 100 has different ratio.

Hence, 68 is the wrong number in the sequence 808, 408, 208,108, 68

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The answer is C. 3√5.