Kelly purchased a toaster for $115. She made a down payment of 10% and financed the rest for 9 months with payments of $16.78. Find (a) the down payment and (b) the total installment price of the toaster.

Answers

Answer 1

(A) The down payment of the toaster = $ 11.5

(B)  The total installment price of the toaster = $151.02

(A) The down payment of the toaster made by Kelly is 10 % of $ 115

Down payment = 115 × 10/100

Down payment = 1150/100

Down payment = 11.5

The down payment of the toaster = $ 11.5

(B) Total installment price of the toaster for 9 months with payment of $ 16.78

Total installment price of toaster = 9 × 16.78

Total installment price of toaster = $ 151.02

The total installment price of the toaster = is $ 151.02

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Related Questions

solve all four parts

Answers

The rocket will hit the ground after 19.09 seconds.

How to calculate projectile

a) The height of the rocket can be describe as:

h(t) = -16t² + 210t + 75

where

t = time in seconds

h(t) = height of the rocket in feet

b) To find the time at which the rocket reaches its maximum height, we need to find the vertex of the parabolic function. The vertex is given by the formula:

t = -b/(2a)

where

a = -16

b = 210

Substituting these values, we get:

t = -210/(2(-16)) = 6.5625 seconds

To find the maximum height, we substitute this value of t back into the equation for h(t):

h(6.5625) = -16(6.5625)² + 210(6.5625) + 75 = 690.625 feet

This means that the rocket reaches its maximum height of 690.625 feet after 6.5625 seconds.

c) We need to find the time interval during which the height of the rocket is greater than 721 feet. We set the height function h(t) greater than 721 and solve for t:

-16t² + 210t + 75 > 721

-16t² + 210t - 646 > 0

Solving for t using the quadratic formula, we get:

t < 2.975 or t > 14.038

Therefore, the rocket will be more than 721 feet above ground level between 0 and 2.975 seconds, and between 14.038 and infinity seconds.

d) To find the time at which the rocket hits the ground, we set h(t) equal to 0 and solve for t:

-16t² + 210t + 75 = 0

Solving for t using the quadratic formula, we get:

t = [tex]\frac{-b \± \sqrt{b^{2} - 4ac } }{2a}[/tex]

a = -16, b = 210, c = 75

t = [tex]\frac{-210 \± \sqrt{210^{2} - 4(16)(75) } }{2(-16)}[/tex]

t = [tex]\frac{-210 \± \sqrt{22225} }{-32}[/tex]

t = [tex]\frac{-210 \± 149}{-32}[/tex]

t = 2.53125 or t = 13.53125

Since the rocket was launched from the top of a 75-foot building, it will hit the ground after an additional time of:

t + 2.53125 = 5.09375 seconds or t + 13.53125 = 19.09375 seconds

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find the area of the shaded region

Answers

The area of the shaded region is 51.75 in².

From the figure

Radius of semicircle = √25² - 20²

                                  =√625-  400 = 15 inch

Now, Area of Trapezium = 1/02 ( a +b ) h

= 1/2 (17 + 37) x 15

= 1/2 (54) x 15

= 27 x 15

= 405 in²

Then, Area of Shaded region

= Area of Trapezium -  Area of semicircle

= (405 - πr²)

= 405 - 353.25

= 51.75 in²

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Select all equations that have infinitely many solutions

Answers

2nd and 4th is correct. Hope you got it!

Help please


Expand the logarithm as much as possible


logy^10

Answers

Answer: 2.303

Explanation: In image

N Heracio's Computer Time Shopping Research 10% Videos 15% Homework 20% Games 20% Social dia 25% Heracio used the computer a total of 40 hours last week. How many more hours did Heracio use the computer to do homework than shop online?​

Answers

Heracio used the computer 4 more hours to do homework than shop online.

How to solve the proportion

To find out how many more hours Heracio used the computer to do homework than shop online, we first need to calculate the number of hours he spent on each activity.

Let's start by calculating the number of hours Heracio spent on each activity:

Shopping: 10% of 40 hours = 4 hours

Videos: 15% of 40 hours = 6 hours

Homework: 20% of 40 hours = 8 hours

Games: 20% of 40 hours = 8 hours

Social media: 25% of 40 hours = 10 hours

Now, to find out how many more hours Heracio used the computer to do homework than shop online, we need to subtract the number of hours spent shopping from the number of hours spent on homework:

8 hours (homework) - 4 hours (shopping) = 4 hours

Therefore, Heracio used the computer 4 more hours to do homework than shop online.

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Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.

n = 109, x = 65; 88% confidence

Answers

Rounding to three decimal places, the confidence interval is (0.419, 0.574).

How can a confidence interval for a sample proportion be created?

The sample proportion, p′ = 0.842, which is the point estimate of the population proportion, must be determined in order to calculate the confidence interval. Given that CL = 0.95 is the requested confidence level, = 1 - CL = 1 - 0.95 = 0.05 ( 2) ( 2) = 0.025.

Confidence interval=proportion±margin of error

CI = p ± ME

The proportion is:

p = x / n

p = 55/110

p = 0.5

Margin of error=critical value × standard error

ME = CV × SE

n > 30, so we can approximate CV with a normal distribution.

At P=88%, CV=1.55.

SE = √(pq / n)

SE = √(0.5 (1−0.5)/110)

SE = 0.048

So the margin of error is:

ME = 1.55 × 0.048

ME = 0.074

So the confidence interval is:

CI = 0.5 ± 0.074

CI = (0.426, 0.574)

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Question:

Use the given degree of confidence and Sample data to construct income confidence interval for the population proportion p. n=110, x=55; 88% confidence

A) 0.426 B)0.442 C)0.425 D)0.421

Rebecca invests 600 into an account with a 2.7% interest rate that is compounded quarterly. How much money will she have in this account if she keeps it for 10 years

Answers

The accrued value of the account in 10 years is $641.75

Determining the accrued value of the account in 10 years

From the question, we have the following parameters that can be used in our computation:

Rebecca invests 600 in an account2.7% interest compounded quarterly

Using the above as a guide, we have the following:

Amount = P * (1 + 0.25r)ᵗ

Where

P = Principal = 600

r = Rate = 2.7% = 0.27

t = time = 10

Substitute the known values in the above equation, so, we have the following representation

Amount = 600 * (1 + 0.25 * 0.27)¹⁰

Evaluate

Amount = 641.75

Hence, the amount is 641.75

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9. (a) The scale model of the rocket stood 54 inches high. What was the height of the actual rocket?
(b) Find the height of the actual rocket in feet.
10. The volume of the rocket in problem 9 is how many times the volume of the model?

Answers

The actual rocket height is 1080 inches and the height of the actual rocket is 90 feet.

How to calculate the value

If the 1/20 scale model of the rocket stands 54 inches high, we can find the height of the actual rocket by multiplying the height of the model by 20:

Actual rocket height = 54 inches x 20 = 1080 inches

In order to convert inches to feet, we divide by 12:

Actual rocket height = 1080 inches / 12 = 90 feet

Therefore, the height of the actual rocket is 90 feet.

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The 1/20 scale model of the rocket stood 54 inches high What was the height of the actual rocket?

(b) Find the height of the actual rocket in feet.

WILL AWARD BRAINLIEST!!
The base of a right prism ABC is an isosceles triangle with AB = BC and m∠ACB 35°. The diagonal of lateral face ABA is 18 cm and m∠BAB = 50°. Find the volume of the prism. Round your answer to the nearest cm

Answers

Answer:

351 cm^3

Step-by-step explanation:

The base of a right prism ABC is an isosceles triangle with AB = BC and m∠ACB 35°. The diagonal of lateral face ABA is 18 cm and m∠BAB = 50°. Find the volume of the prism. Round your answer to the nearest cm

ChatGPT

Let AB = BC = x be the base of the isosceles triangle ABC. Then, the third side AC is:

AC = 2x * sin(35°)

Using the sine rule in triangle ABA, we have:

AB / sin(50°) = 18 / sin(80°)

Solving for AB, we get:

AB = 18 * sin(50°) / sin(80°)

The height of the prism is AB * cos(35°). Therefore, the volume of the prism is:

V = (1/2) * x^2 * 2x * sin(35°) * AB * cos(35°)

Substituting the values we have calculated, we get:

V = (1/2) * x^2 * 2x * sin(35°) * [18 * sin(50°) / sin(80°)] * cos(35°)

V ≈ 351 cm^3

Therefore, the volume of the prism is approximately 351 cubic centimeters.

A movie theater considers upgrading to offer luxury seating. The manager randomly surveys 1,200 resident who live within 10 miles of the theater. What is the sample in the situation

Please it’s due in 2min

Answers

In this circumstance, the sample consists of 1,200 inhabitants living within a ten-mile radius of the movie theater that were selected for random deliberation by the overseer.

What is a sample?

Samples are frequently utilized to gain information concerning a larger population through the study of a single set of individuals or objects. The aim of selecting a sample is to inspect the populace by delving into a representative, relatively small group.

Surveys, polls, and experiments often utilize samples to make evidence-based inferences regarding the target population. For exact and dependable results, an instance should be randomly chosen, accurately mirroring those present in the whole population so as to reduce prejudice and fully optimize the evaluation.

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helpppp helppppp helppppp

Answers

Answer:

No, i do not believe i have learned this yet so good luck bestiee

. A and B completed a work together in 5 days. Had A worked at twice the speed and B at half the
speed, it would have taken them four days to complete the job. How much time would it take for
A alone to do the work

Answers

So it would take A 10 days to do the whole job alone.

What is equation?

An equation is a statement that asserts the equality of two expressions. It typically contains variables, constants, and mathematical operations such as addition, subtraction, multiplication, division, exponentiation, etc. The goal of solving an equation is to find the values of the variables that make the equation true. Equations are used in a variety of mathematical contexts, including algebra, calculus, and geometry, as well as in physics, engineering, and many other fields.

Here,

Let's denote A's speed as "a" and B's speed as "b" (in units of work per day). Then, we know that:

In 5 days, A and B together completed the job, so we can write: 5(a + b) = 1 (where 1 represents the whole job).

If A worked at twice the speed (2a) and B worked at half the speed (0.5b), then they would complete the job in 4 days, so we can write: 4(2a + 0.5b) = 1.

We can simplify the second equation by multiplying out the brackets and collecting like terms:

8a + 2b = 1

Now we have two equations with two unknowns. We can solve for one of the variables in terms of the other, and substitute the result into the other equation to find the value of the remaining variable. Let's solve for "b" in terms of "a" from the first equation:

5(a + b) = 1

5b = 1 - 5a

b = (1/5) - a

Now we can substitute this expression for "b" into the second equation:

8a + 2b = 1

8a + 2((1/5) - a) = 1

8a + (2/5) - 2a = 1

6a = (3/5)

a = (1/10)

So A can do 1/10 of the job in one day. To find out how long it would take A to do the whole job alone, we can use the formula:

time = amount of work / rate

Since A can do the whole job alone, the amount of work is 1, and A's rate is 1/10. Therefore:

time = 1 / (1/10)

= 10 days

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50 Points! Solve the equation or inequality. Please show as much work as possible. Photo attached. Thank you!

Answers

The equation 5ʷ ⁺ ³ = 17 when solved for w is approximately w = 0.41

Solving the equations or inequalities for w

From the question, we have the following parameters that can be used in our computation:

5ʷ ⁺ ³ = 17

Take the logarithm of both sides of the equation

So, we have

w + 3 = ln(17)/ln(3)

Evaluate the quotient on the left side of the equation

This gives

w + 3 = 2.59

So, we have

-3 + w + 3 = 2.59 - 3

Evaluate

w = 0.41

Hence, the equation when solved for w is approximately w = 0.41

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Solve the following quadratic equation by completing the square. Simplify the solutions and rationalize denominators, if necessary.

3x^2−30x=−2

Answers

The solutions to this quadratic equation are x = √(73/3) + 5 or x = -√(73/3) + 5.

What is a quadratic equation?

In Mathematics and Geometry, the standard form of a quadratic equation is represented by the following equation;

ax² + bx + c = 0

Next, we would solve the given quadratic equation by using the completing the square method;

3x² - 30x = -2

By dividing all through by 3, we have:

x² - 10x = -2/3

In order to complete the square, we would have to add (half the coefficient of the x-term)² to both sides of the quadratic equation as follows:

x² - 10x + (-10/2)² = -2/3 + (-10/2)²

x² - 10x + 25 = -2/3 + 25

x² - 10x + 25 = 73/3

By simplifying, we have;

(x - 5)² = 73/3

x = √(73/3) + 5 or x = -√(73/3) + 5

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Solve the equation for the indicated variable

X= (simplify your answer)

Answers

B = (715x) / (h^2)

Step 1: Get rid of the denominator by multiplying both sides by h^2

(B)(h^2) = 715x

Step 2: Isolate x by dividing both sides by 715

(Bh^2) / 715 = x

Answer: x = Bh^2 / 715

Hope this helps!


Where will X be after a rotation 90° clockwise about (-5,-1)?
Click on the grid to place the point.

Answers

The image point of the coordinate X after the rotation is (-1, 5).

Calculating the image point of the coordinate X

When a point is rotated 90° clockwise around the origin, the new point will be formed by switching the x and y-coordinates and then negating the new x-coordinate.

So for point X (-5, -1), the new x-coordinate will be -1, and the new y-coordinate will be -(-5) = 5, giving the new point (-1, 5).

Therefore, after a rotation of 90° clockwise, point X (-5, -1) will be at the new location (-1, 5).

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Water flows from the bottom of a storage tank. After t minutes, the water is flowing at a rate of r(t)=200-4t liters per
minute, where 0≤t<50. Find the amount of water (in liters) that flows from the tank between the 7 minute mark and the
37 minute mark.

Answers

The total amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark is 720 liters.  

What is rate of flow?

The amount of fluid that moves through a pipe or other container over a given amount of time.

The amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark can be calculated using the equation for the rate at which the water is flowing.

Given that the rate at which the water is flowing at time t is r(t)=200-4t liters per minute and that 0≤t<50, the total amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark can be calculated as follows:

Total amount of water = ∫r(t)dt  

                   = ∫(200 - 4t)dt  

                   = (200t - 4t²)  

                   = (200(37) - 4(37²)) - (200(7) - 4(7²))  

                   = 1924 - 1204  

                   = 720 liters

The rate of flow decreases linearly with time, which means that the total amount of water flowing from the tank at any given time is equal to the area under the graph of the rate of flow.

This means that the total amount of water that flows from the tank between the 7 minute mark and the 37 minute mark can be calculated by integrating the rate of flow function over the given time interval.

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Which function does the dotted line represent explain how do you know

Answers

Answer:

Step-by-step explanation:

An inequality can be represented graphically as a region on one side of a line. Inequalities that use < or > symbols are plotted with a dashed line to show that the line is not included in the region. Inequalities that use ≤ or ≥ symbols are plotted with a solid line to show that the line is included in the region.

Suppose the probability density function of a random variable X is
f(x)=[tex]\left \{ {{cx^{2}, 1\leq x\leq 2 } \atop {0, else}} \right.[/tex]

a. Find the value of constant c
b. Find the value of P(X>3/2)

Answers

The value of,

constant c is 3/7 andP(x>3/2) is 27/18

Given function f(x) = cx for 1 ≤ x ≤ 2

a) To find the value of constant x, we have to use the following p.d.f condition as shown below,

[tex]\int\limits^a_b {x} \, dx =1[/tex]

here, a is -∞ and b is ∞.

From the above condition to find the value of c,

[tex]\int\limits^2_1{cx^2} \, dx[/tex] = 1

c * [[tex]\frac{x^3}{3}[/tex]]²₁ = 1

c * [8/3 - 1/3] = 1

c * 7/3 = 1

c = 3/7.

b) To find the value of P(x>3/2) we have to substitute the value of 3/2 in the given expression of f(x) = 3/7 * x²

f(3/2) = 3/7 * (3/2)²

         = 3/7 * 9/4

         = 27/28.

From the above solution, we solved both problems.

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The components of v = 210i + 300i represent the respective number of gallons of regular and premium gas sold at a station. The components of w = 2.8i + 2.99i represent the respective prices per gallon for each kind of gas. Find Vw and describe what the answer means in practical terms.

Answers

The station earned $1485 in revenue from selling the gas.

In this problem, we are given two vectors, v and w, representing the number of gallons of gas sold at a station and the corresponding prices per gallon, respectively. We are asked to find the dot product of these two vectors, which is a scalar quantity known as the "Vw". We will then interpret the meaning of this dot product in practical terms.

To find the dot product of v and w, we will use the formula:

Vw = v . w = (210)(2.8) + (300)(2.99)

Vw = 588 + 897 = 1485

Therefore, the value of Vw is 1485.

Practical terms: The dot product of two vectors is a scalar quantity that represents the "projection" of one vector onto the other. In this case, the dot product Vw represents the total revenue earned by selling regular and premium gasoline at the given station.

The components of v represent the number of gallons of regular and premium gas sold, while the components of w represent the respective prices per gallon for each kind of gas. Multiplying the number of gallons sold by the price per gallon gives the total revenue earned for each type of gas. Adding these two values together gives the total revenue earned for both types of gas.

Therefore, the dot product Vw represents the total revenue earned by selling all the gas at the given station. In practical terms, this means that the station earned $1485 in revenue from selling the gas.

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Element X decays radioactivity with a half-life in 10 minutes if there are 660 g of element X how long to the nearest 10th of a minute would it take for the element to decay to 58 g

Answers

Step-by-step explanation:

58 g = 660 g * ( 1/2)^n

58 / 660 = (1/2) ^n       LOG both sides

-1.056 = n log 1/2

n = 3.508 half lives  

     3. 508  x 10 min = ~ 35.1 min

[tex]\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\dotfill & 58\\ P=\textit{initial amount}\dotfill &660\\ t=minutes\dotfill &t\\ h=\textit{half-life}\dotfill &10 \end{cases} \\\\\\ 58 = 660\left( \cfrac{1}{2} \right)^{\frac{t}{10}} \implies \cfrac{58}{660}=\left( \cfrac{1}{2} \right)^{\frac{t}{10}}\implies \cfrac{29}{330}=\left( \cfrac{1}{2} \right)^{\frac{1}{10}\cdot t}[/tex]

[tex]\log\left( \cfrac{29}{330} \right)=\log\left[ \left( \cfrac{1}{2} \right)^{\frac{1}{10}\cdot t} \right]\implies \log\left( \cfrac{29}{330} \right)=t\log\left[ \left( \cfrac{1}{2} \right)^{\frac{1}{10}} \right] \\\\\\ \cfrac{ ~~ \log\left( \frac{29}{330} \right) ~~ }{\log\left[ \left( \frac{1}{2} \right)^{\frac{1}{10}} \right]}=t\implies 35.1\approx t[/tex]

Jerome buys 4 pints of milk for the baby goats and has pint of milk left from yesterday. If each baby goat gets pint of milk, how many goats can Jerome
feed?

Jerome can feed (blank) baby goats.

Answers

Answer:

5 baby goats

Step-by-step explanation:

4 + 1 = 5 pints total

each baby goat gets 1 pint

In the diagram, AB, BC and CD are three sides of a regular polygon F
A
a) Work out the size of angle y.
square polygon P
B
D
square
regular 12-sided polygon
y z
b) Work out the size of angle z.
c) What is the name of polygon P?

Answers

Answer:

Step-by-step explanation:

The size of each interior angle of the polygon is 4x+28 °

The value of x is 34 degree and y is 56 degree.

What is a Tangent?

Tangents to circles are lines that cross the circle at a single point. Point of tangency refers to the location where a tangent and a circle converge. The circle's radius, where the tangent intersects it, is perpendicular to the tangent. Any curved form can be considered a tangent.

here, we have,

We have, BOA is an isosceles triangle.

< CBO = 90°

So, < DBO = 90 - 56

<DBO = 34

and, <ODB = 34°

Now, let the angle ODB be x

As, from the figure < EBD is also 90°

So, <y = 180 - (90+34)  (Angle sum property)

<y = 56

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complete question:

Work out the size of angle x and work out the size of angle y

Part 1
For the experiment of rolling a single fair​ die, find the probability of being even or divisible by 3.

Answers

The probability of rolling an even or divisible by 3 numbers is 2/3

When a single fair die is rolled, there are six possible outcomes:

1, 2, 3, 4, 5, or 6.

Of these outcomes, three are even (2, 4, and 6) and two are divisible by 3 (3 and 6). However, since the number 6 is both even and divisible by 3, we must count it only once to avoid overcounting. Thus, four outcomes are either even or divisible by 3: 2, 3, 4, and 6.

The probability of rolling an even or divisible by 3 number is the sum of the probabilities of these four outcomes, which is:

P(even or divisible by 3) = P(2) + P(3) + P(4) + P(6)

= 1/6 + 1/6 + 1/6 + 1/6

= 4/6

= 2/3

Therefore, the probability of rolling an even or divisible by 3 numbers is 2/3

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the probability of rolling a 4 or an even number of the die is thrown 2 times. (6 sided dice)

Answers

The probability of rolling a 4 on a single throw of a fair 6-sided die is 1/6, since there is only one way to roll a 4 and there are 6 equally likely outcomes in total.

The probability of rolling an even number on a single throw of a fair 6-sided die is 3/6, or 1/2, since there are three even numbers (2, 4, and 6) out of six possible outcomes.

To find the probability of rolling a 4 or an even number on a single throw, we can add the probabilities of these two events:

P(4 or even) = P(4) + P(even) - P(4 and even)

where P(4 and even) is the probability of rolling a 4 and an even number on the same throw. Since there is only one outcome (rolling a 4), which is not even, this probability is 0.

Therefore:

P(4 or even) = P(4) + P(even) - P(4 and even)

             = 1/6 + 1/2 - 0

             = 2/3

So the probability of rolling a 4 or an even number on a single throw of a 6-sided die is 2/3.

If the die is thrown 2 times, the probability of rolling a 4 or an even number on both throws is the product of the probabilities of rolling a 4 or an even number on each throw:

P(4 or even on both throws) = P(4 or even) × P(4 or even)

                           = (2/3) × (2/3)

                           = 4/9

Therefore, the probability of rolling a 4 or an even number on both throws of a 6-sided die is 4/9.

It’s due tomorrow I really need help

Answers

Answer:

B.

Step-by-step explanation:

As the steps imply,

Step 1 is to first convert the 3.5% (0.035) and then multiply it by 16 to find out by how many grams the amount should decrease (0.035 * 16 = 0.56).  Step 2 is to subtract this amount from 16 to find the amount remaining after one hour (16 - 0.56 = 15.44).  Step 3 is to convert 4.25% to a decimal (0.0425) and multiply it by the amount remaining at the end of one hour to find out by how many grams this amount should decrease after two hours (0.0425 * 15.44 = 0.6562)Step 4 finally is to subtract this amount from 15.44 to find the amount remaining after two hours (15.44 - 0.6562 = 14.7838)

The table represents the quadratic functions f(x) and g(x).


x f(x) g(x)
−8 16 4
−4 4 1
0 0 0
4 4 1
8 16 4

What transformation of f(x) will produce g(x)?
g of x equals one fourth times f of x
g of x equals f of the quantity of one fourth times x end quantity
g(x) = 4f(x)
g(x) = f(4x)

Answers

The transformation of f(x) that will produce g(x) is given as follows:

g(x) = f(x)/4.

How to obtain the function g(x)?

If we observe at the table, we have that each value of g(x) is one fourth of the value of the function f(x).

Hence the transformation of f(x) that will produce g(x) is given as follows:

g(x) = f(x)/4.

The transformation means that the function g(x) is a vertical compression by a factor of 4 of the function f(x).

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Graph the linear equation y=-3x-1​

Answers

Answer:

Step-by-step explanation:

y=-3x-1

format for formula:

y=mx+b

b=1  that is your y-intercept.  where it hits the y-axis

m= -3    this is your slope    [tex]\frac{rise}{run} =\frac{-3}{1}[/tex]  

from a point you have, the y-intercept, you go down 3 (because of the negative in front of it), this is your rise,
and to the right 1, this is your run

How do you find area?

Answers

The area of a shape is calculated by calculating the amount of space on the shape

How do you find area?

By definitinon, the area of a shape is the amount of space on the shape

using the above as a guide, we have the following:

Area of rectangle = Length * WidthArea of square = Length²Area of triangle = 1/2 * base * heightArea of circle = π * radius²Area of parallelogram = base * height

There are several formulas to calculate area

The formula to use is dependent on the shape whose area is being calculated

This means that the area of trapezoid cannot be calculated using the area of parallelogram

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1. Which of the following is a set or not?

(a) A=Set of tall man
(b) B=Set of beautiful women
(c) C=Set of tall students of class 10
(d) D=Set of counting number
(e) E=Set of good students
(f) F=Set of yellow roses​

Answers

Answer:

Step-by-step explanation:
Set of tall students of class 10 is a set. Thus, option C is the correct answer.

A set is defined as objects or things that can be justified as similar things combined together and grouped together.

The other sets are not specified. When we look at option A it is said that all the men are tall so they have a common factor i.e. they are tall but could have been more specified. Also in option B it is said that all the women are beautiful, here the common factor is beautiful but it could have been more specified. Similarly option d, option e and option f are also not specified.

When we look at option c, here it specified that the tal students are of class 10 and so I consider option "c" is the correct answer.

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