Let A= [1 1 2 4]

(a) Find all eigenvalues and corresponding eigenvectors of A. (b) Find an invertible matrix P such that P^-1 AP is a diagonal matrix. (c) Compute A^30

Answers

Answer 1

(a) To find the eigenvalues and eigenvectors of matrix A, we need to solve the equation (A - λI)v = 0, where λ is the eigenvalue and v is the eigenvector.

(b) To find an invertible matrix P such that P^-1 AP is a diagonal matrix, we need to find the eigenvectors corresponding to the eigenvalues obtained in part (a).

(c) To compute A^30, we can use the diagonalization of matrix A obtained in part (b).

Given matrix A: A = [1 1 2 4]

First, we subtract λI from matrix A:

A - λI = [1 - λ, 1, 2, 4; 1, 1 - λ, 2, 4; 2, 2, 2 - λ, 4; 4, 4, 4, 4 - λ]

Setting the determinant of (A - λI) equal to zero, we can solve for λ to find the eigenvalues.

Determinant of (A - λI) = 0:

(1 - λ)[(1 - λ)(2 - λ)(4 - λ) - 2(2 - λ)(4 - λ)] - [(1)(2 - λ)(4 - λ) - 2(4 - λ)(4 - λ)] + (2)[(1)(4 - λ) - (1 - λ)(4 - λ)] - (4)[(1)(2 - λ) - (1 - λ)(2)]

Simplifying the above expression and solving for λ will give us the eigenvalues.

(b) To find an invertible matrix P such that P^-1 AP is a diagonal matrix, we need to find the eigenvectors corresponding to the eigenvalues obtained in part (a). These eigenvectors will form the columns of matrix P.

(c) To compute A^30, we can use the diagonalization of matrix A obtained in part (b). Since P^-1 AP is a diagonal matrix, we can easily raise the diagonal elements to the power of 30. The resulting matrix will be P^-1 A^30 P.

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Related Questions

The heights of 10 women, in \( \mathrm{cm} \), are \( 168,160,168,154,158,152,152,150,152,150 \). Determine the mean. A. 153 B. 155 C. 152 D. \( 156.4 \)

Answers

The mean height of 10 women to the nearest whole number is 156.

In statistics, the mean is a measure of central tendency that represents the average value of a set of data points. It is calculated by summing up all the values in the dataset and dividing the sum by the total number of data points.

To determine the mean (average) height of the 10 women, you need to sum up all the heights and divide the total by the number of women. Let's calculate it:

Sum of heights = 168 + 160 + 168 + 154 + 158 + 152 + 152 + 150 + 152 + 150 = 1556

Number of women = 10

Mean height = Sum of heights / Number of women = 1556 / 10 = 155.6

Rounding the mean height to the nearest whole number, we get 156.

Therefore, the correct answer is D. 156.

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A researcher is interested in the effects of room color (yellow, blue) and room temperature (20, 24, 28 degrees Celsius) on happiness. A total of 120 university students participated in this study, with 20 students randomly assigned to each condition. After sitting for 30 mins. in a room that was painted either yellow or blue, and that was either 20, 24, or 28 degrees, students were asked to rate how happy they felt on a scale of 1 to 15, where 15 represented the most happiness.
The results are as follows:
temperature room color happiness
20 yellow 12
24 yellow 10
28 yellow 6
20 blue 4
24 blue 4
28 blue 4
B) What is the name given to this type of design?

Answers

The name given to this type of design is a factorial design. A factorial design is a design in which researchers investigate the effects of two or more independent variables on a dependent variable.

In this study, two independent variables were used: room color (yellow, blue) and room temperature (20, 24, 28 degrees Celsius), while the dependent variable was happiness.

Each level of each independent variable was tested in conjunction with each level of the other independent variable. There are a total of six experimental conditions (two colors × three temperatures = six conditions), and twenty students were randomly assigned to each of the six conditions.

The researcher then examined how each independent variable and how the interaction of the two independent variables affected the dependent variable (happiness). Therefore, this study is an example of a 2 x 3 factorial design.

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1990s Internet Stock Boom According to an article, 11.9% of Internet stocks that entered the market in 1999 ended up trading below their initial offering prices. If you were an investor who purchased five Internet stocks at their initial offering prices, what was the probability that at least three of them would end up trading at or above their initial offering price? (Round your answer to four decimal places.)
P(X ≥ 3) =

Answers

The probability that at least three of them would end up trading at or above their initial offering price is P(X ≥ 3) = 0.9826

.The probability of an Internet stock ending up trading at or above its initial offering price is:1 - 0.119 = 0.881If you were an investor who purchased five Internet stocks at their initial offering prices, the probability that at least three of them would end up trading at or above their initial offering price is:

P(X ≥ 3) = 1 - P(X ≤ 2)

We can solve this problem by using the binomial distribution. Thus:

P(X ≥ 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2)]P(X = k) = nCk × p^k × q^(n-k)

where, n is the number of trials or Internet stocks, k is the number of successes, p is the probability of success (Internet stock trading at or above its initial offering price), q is the probability of failure (Internet stock trading below its initial offering price), and nCk is the number of combinations of n things taken k at a time.

We are given that we purchased five Internet stocks.

Thus, n = 5. Also, p = 0.881 and q = 0.119.

Thus:

P(X ≥ 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2)] = 1 - [(5C0 × 0.881^0 × 0.119^5) + (5C1 × 0.881^1 × 0.119^4) + (5C2 × 0.881^2 × 0.119^3)]≈ 0.9826

Therefore, P(X ≥ 3) = 0.9826 (rounded to four decimal places).

Hence, the correct answer is:P(X ≥ 3) = 0.9826

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2) A retailer buys a set of entertainment that is listed at RM X with trade discounts of 15% and 5%. If he sells the set at RM 15000 with a net profit of 20% based on retail and the operating expenses are 10% on cost, find: a) the value of X \{4 marks } b) the gross profit {3 marks } c) the breakeven price {3 marks } d) the maximum markdown that could be given without incurring any loss. \{3 mark

Answers

a)The value of X = RM 15125.

b) The Gross Profit = RM 3000.

c) The Break-even price = RM 13333.33.

d) The Maximum markdown that could be given without incurring any loss = RM -1333.33.

The retailer buys a set of entertainment that is listed at RM X with trade discounts of 15% and 5%.He sells the set at RM 15000 with a net profit of 20% based on retail.

The operating expenses are 10% on cost.a) The value of X. The trade discount is 15% and 5% respectively.

Thus, the net price factor is, 100% - 15% = 85% = 0.85 and 100% - 5% = 95% = 0.95

The retailer's selling price is RM15000. The operating expense is 10% on cost.

Hence, 90% of the cost will be converted into the total expense. 90% = 0.9

The net profit is 20% of the retail price.20% = 0.20

Therefore, the cost of the set is,15000 × (100% - 20%) - 15000 × 80% = RM 12000

Let X be the retail price of the set of entertainment.

Therefore, we have,

X × 0.85 × 0.95 = 12000 ⇒ X = RM 15125

b) The Gross Profit

The gross profit is given by,Gross Profit = Selling price - Cost of goods sold

The cost of goods sold is RM 12000.

Therefore,Gross Profit = RM 15000 - RM 12000 = RM 3000

c) The Break-even price

The Break-even price is given by,Break-even price = Cost price / [1 - (operating expenses / 100%)]

The operating expense is 10% of the cost price. Therefore, 90% of the cost price will be converted into the total expense.

Break-even price = 12000 / [1 - (10/100)] = 12000 / 0.9 = RM 13333.33

d) The Maximum markdown that could be given without incurring any loss

The maximum markdown that could be given without incurring any loss is given by,

Maximum markdown = Cost price - Breakeven price = RM 12000 - RM 13333.33 = RM -1333.33

Therefore, the maximum markdown that could be given without incurring any loss is RM -1333.33. However, it is not possible to sell a product with a negative value.

Therefore, the retailer should not give any markdown.

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Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 3). Which expression defines the transformation of any point (x, y) to (x′, y′) on the polygons? x′ = x − 3 y′ = y − 2 x′ = x − 2 y′ = y − 3 x′ = x − 1 y′ = y − 8 x = x′ + 3 y = y′ + 2

Answers

The expression that defines the transformation of any point (x, y) to (x′, y′) on the polygons is:

x′ = x - 3

y′ = y - 2

In this transformation, each point (x, y) in the original polygon is shifted horizontally by 3 units to the left (subtraction of 3) to obtain the corresponding point (x′, y′) in the translated polygon. Similarly, each point is shifted vertically by 2 units downwards (subtraction of 2). The given coordinates of point A (1, 5) and A' (-2, 3) confirm this transformation. When we substitute the values of (x, y) = (1, 5) into the expressions, we get:

x′ = 1 - 3 = -2

y′ = 5 - 2 = 3

These values match the coordinates of point A', showing that the transformation is correctly defined. Applying the same transformation to any other point in the original polygon will result in the corresponding point in the translated polygon.

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The graph shows the growth of a tree, with x
representing the number of years since it was planted,
and y representing the tree's height (in inches). Use the
graph to analyze the tree's growth. Select all that apply.
The tree was 40 inches tall when planted.
The tree's growth rate is 10 inches per year.
The tree was 2 years old when planted.
As it ages, the tree's growth rate slows.
O Ten years after planting, it is 140 inches tall.

Answers

Based on the graph, we can confirm that the tree was 40 inches tall when planted and estimate its growth rate to be around 10 inches per year.

Based on the information provided in the question, let's analyze the tree's growth using the graph:

1. The tree was 40 inches tall when planted:

  Looking at the graph, we can see that the y-axis intersects the graph at the point representing 40 inches. Therefore, we can conclude that the tree was indeed 40 inches tall when it was planted.

2. The tree's growth rate is 10 inches per year:

  To determine the tree's growth rate, we need to examine the slope of the graph. By observing the steepness of the line, we can see that for every 1 year (x-axis) that passes, the tree's height (y-axis) increases by approximately 10 inches. Thus, we can conclude that the tree's growth rate is approximately 10 inches per year.

3. The tree was 2 years old when planted:

  According to the graph, when x = 0 (the point where the tree was planted), the y-coordinate (tree's height) is approximately 40 inches. Since the x-axis represents the number of years since it was planted, we can infer that the tree was 2 years old when it was planted.

4. As it ages, the tree's growth rate slows:

  This information cannot be determined directly from the graph. To analyze the tree's growth rate as it ages, we would need additional data points or a longer time period on the graph to observe any changes in the slope of the line.

5. Ten years after planting, it is 140 inches tall:

  By following the graph to the point where x = 10, we can see that the corresponding y-coordinate is approximately 140 inches. Therefore, we can conclude that ten years after planting, the tree's height is approximately 140 inches.

In summary, based on the graph, we can confirm that the tree was 40 inches tall when planted and estimate its growth rate to be around 10 inches per year. We can also determine that the tree was 2 years old when it was planted and that ten years after planting, it reached a height of approximately 140 inches. However, we cannot make a definite conclusion about the change in the tree's growth rate as it ages based solely on the given graph.

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Without using a calculator, determine if it is possible to form a triangle with the given side lengths. Explain.

√99 yd, √48 yd, √65 yd

Answers

No, it is not possible to form a triangle with the given side lengths of √99 yd, √48 yd, and √65 yd.

To determine if it is possible to form a triangle, we need to check if the sum of any two sides is greater than the third side. In this case, let's compare the given side lengths:

√99 yd < √48 yd + √65 yd

9.95 yd < 6.93 yd + 8.06 yd

9.95 yd < 14.99 yd

Since the sum of the two smaller side lengths (√48 yd and √65 yd) is not greater than the longest side length (√99 yd), the triangle inequality theorem is not satisfied. Therefore, it is not possible to form a triangle with these side lengths.

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Assume a and b are positive integers. Determine whether each statement is true or false. If it is true, explain why. If it is false, give a counterexample.

(a !)^b=a^(b!)

Answers

The statement (a!)^b = a^(b!) is not true for all values of a and b, where they are positive integers. Hence, the given statement is false.

Given: a and b are positive integers.

To determine whether the given statement, (a!)^b = a^(b!) is true or false, we have to apply mathematical logic.  Let us test this statement for some random values of a and b.

Example 1: Let a = 2 and b = 3.

(a!)^b = (2!)^3 = 8^3 = 512

a^(b!) = 2^(3!) = 2^6 = 64

Here, (a!)^b ≠ a^(b!). So, the statement (a!)^b = a^(b!) is false.

Example 2: Let a = 3 and b = 2.

(a!)^b = (3!)^2 = 6^2 = 36

a^(b!) = 3^(2!) = 3^2 = 9

Here, (a!)^b ≠ a^(b!) So, the statement (a!)^b = a^(b!) is false.

Therefore, the statement (a!)^b = a^(b!) is not true for all values of a and b. Hence, the given statement is false.

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Suppose you want to conduct an independent samples t-test. what specific information must you already know about a comparison population?

Answers

To conduct an independent samples t-test, you must already know the means and variances (or standard deviations) of the two comparison populations.

An independent samples t-test is a statistical test used to compare the means of two independent groups or populations. It is typically employed when we want to determine if there is a significant difference between the means of these two groups.

To perform the t-test, we need specific information about the comparison populations. Firstly, we must know the means of both populations. The mean represents the average value of the variable being measured in each population.

Secondly, we need information about the variances (or standard deviations) of the populations. The variance indicates the spread or variability of the data points within each population. The standard deviation is the square root of the variance and provides a measure of the average distance between each data point and the mean within each population.

By comparing the means and variances (or standard deviations) of the two populations, we can calculate the t-value and determine whether the difference between the sample means is statistically significant.

In summary, to conduct an independent samples t-test, you need to know the means and variances (or standard deviations) of the two comparison populations. These values allow for the calculation of the t-statistic, which helps assess the significance of the observed differences in means.

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A classmate says that the growth factor of the exponential function y=15(0.3)x is 0.3 . What is the student's mistake?

Answers

The correct growth factor of the given exponential function y = 15(0.3)x is approximately 0.3, and the student's mistake was that they correctly identified the growth factor.

The growth factor of an exponential function is a value that determines how much the function grows or decays with each unit increase in the input variable.

In the given function y = 15(0.3)x, the student mistakenly identified the growth factor as 0.3.
To understand the student's mistake, let's break down the function and its properties.

The general form of an exponential function is y = ab^x, where "a" is the initial value or y-intercept, "b" is the growth factor, and "x" is the input variable.
In this case, the function is y = 15(0.3)x.

The initial value or y-intercept is 15, and the growth factor is 0.3.

However, the student incorrectly identified the growth factor as 0.3.
To find the correct growth factor, we need to compare two different outputs of the function.

Let's consider the input x = 1 and x = 2.
For x = 1:
y = 15(0.3)^1 = 4.5
For x = 2:
y = 15(0.3)^2 = 1.35
Now, let's calculate the ratio of the outputs for x = 2 and x = 1:
(1.35 / 4.5) ≈ 0.3
We can see that the ratio is approximately 0.3.

This means that for each unit increase in the input variable, the output is multiplied by the growth factor of approximately 0.3.
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(a) What is ϕ(12) ? (b) Solve the following linear congruence using Euler's theorem. 19x≡13(mod12) The unique solution x 0 such that 0≤x 0 <12 is

Answers

The unique solution x0 such that 0 ≤ x0 < 12 is 7

(a). The Euler's totient function is defined as the number of integers between 1 and n that are relatively prime to n.

The value of ϕ(12) is calculated below.

ϕ(12) = ϕ(2^2 × 3)

ϕ(12) = ϕ(2^2) × ϕ(3)

ϕ(12) = (2^2 - 2^1) × (3 - 1)

ϕ(12) = 4 × 2

ϕ(12) = 8

Answer: ϕ(12) = 8

(b) Solve the following linear congruence using Euler's theorem. 19x≡13(mod12)Let a = 19, b = 13, and m = 12.

We can solve for x using Euler's theorem as follows.$$x \equiv a^{\varphi(m)-1}b \pmod{m}$$

where ϕ(m) is the Euler's totient function.ϕ(12) = 8x ≡ 19^(8-1) × 13 (mod 12)x ≡ 19^7 × 13 (mod 12)x ≡ (-5)^7 × 13 (mod 12)x ≡ -78125 × 13 (mod 12)x ≡ -1015625 (mod 12)x ≡ 7 (mod 12)

Therefore, the unique solution x0 such that 0 ≤ x0 < 12 is 7.

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Which arrangement shows −5 1/2 , −5 , −6.4 , and −2 6/4 in order from least to greatest?
25 points!

Answers

Answer:

-6.4, -5 1/2, -5, -2 6/4

-6.4,-5 1/2,-5,-2 6/4









7. (16 points) Find the general solution to the homogeneous system of DE: -11 41 x' = Ax where A = [269] Hint: Write your answer x(t) in the form of eat [cos(bt) + sin(bt)].

Answers

The general solution to the homogeneous system is:

x(t) = [-c1*e^(-11t); (11/41)*c1*e^(-11t) + c2*e^(269t); c2*e^(269t)]

Given the differential equation as:

-11*[x1'; x2'; x3'] = [269 0 0; 0 269 0; 0 0 269]*[x1; x2; x3]

The characteristic equation of the system is:

(-11 - λ)(269 - λ)^3 = 0

Thus, we have two eigenvalues. For λ1 = -11, we have one eigenvector u1 given by:

[-1; 0; 0]

For λ2 = 269, we have one eigenvector u2 given by:

[0; 0; 1]

Thus, the general solution to the homogeneous system is given by:

x(t) = c1*e^(-11t)*[-1; 0; 0] + c2*e^(269t)*[0; 0; 1]

= [-c1*e^(-11t); 0; c2*e^(269t)]

We can also write it in the form of e^(at)*(c1*cos(bt) + c2*sin(bt)) where a and b are real numbers.

For x1, we have:

x1(t) = -c1*e^(-11t)

For x3, we have:

x3(t) = c2*e^(269t)

Thus, for x2, we have:

x2'(t) = [(-11/41)  (41/41)  (0/41)] * [-c1*e^(-11t); 0; c2*e^(269t)]

= (-11/41)*(-c1*e^(-11t)) + (41/41)*(c2*e^(269t))

= (11/41)*c1*e^(-11t) + c2*e^(269t)

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75,75,80,86 mean median mode ​

Answers

Answer:

mean: 79
median: 77.5
mode: 75

Step-by-step explanation:

mean: all numbers added divided by number of numbers
(75 + 75 + 80 + 86)/4


median: 2 middle numbers divided by 2 (median is just the middle number if number of numbers is odd
(75+80)/2

mode: most often occurring number
75 occurs the most

Answer:

mean = 79

median = 77.5

mode = 75

Step-by-step explanation:

mean is to add all numbers and then divide the sum by the total numbers given

mean = (75 + 75 + 80 + 86) / 4 = 316 / 4 = 79

median is to arrange all the numbers in ascending order, if the numbers are odd the middle one is the median, if the numbers are even the average of the middle two numbers is the median.

the median of = 75, 75, 80, 86

= (75 + 80) / 2 = 155 / 2 = 77.5

mode is the number in the data set that is coming most frequently throughout the data.

mode = 75

Each of the positive integers 1 to 100 are written on a sheet of paper 123,...98,99,100 some of these integers are erased. the product of those integers still on the paper leaves a remainder of 4 when divided by 5 . find the least number of integers that could have been erased? (actual number answer)

Answers

The least number of integers that could have been erased is one.

Here, we are asked to find the least number of integers that could have been erased to leave a remainder of 4 when divided by 5 from the product of the remaining numbers.

On dividing 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 140, 141, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159, 160, 161, 162, 163, 164, 165, 166, 167, 168, 169, 170, 171, 172, 173, 174, 175, 176, 177, 178, 179, 180, 181, 182, 183, 184, 185, 186, 187, 188, 189, 190, 191, 192, 193, 194, 195, 196, 197, 198, 199, 200 by 5,

we get the remainders as 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1.

The product of these numbers is divisible by 5, i.e., the remainder is 0.On observing the remainders above,

we can say that if at least one number from the set (124, 129, 134, 139, 144, 149, 154, 159, 164, 169, 174, 179, 184, 189, 194, 199) is erased, then the product of the remaining numbers leaves a remainder of 4 when divided by 5.

The above set contains 16 numbers, therefore, the least number of integers that could have been erased is one.

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Year Unadjusted Federal Minimum Wage Adjusted Federal Minimum Wage in Constant 2020 Dollars
1985 $3.35 $8.19
1990 $3.80 $7.69
2000 $5.15 $7.87
2010 $7.25 $8.63
2020 $7.25 $7.25
5. Use the values in the table above to interpolate/extrapolate (whichever is appropriate) the value of minimum wage in adjusted 2020 dollars for each the years requested. Round intermediate values to three decimal places if needed. Round the final answer to two decimal places.
(2 x 8 pt = 16 pt)
a. Predict adjusted wages in
(d) 2002
Does this prediction require interpolation or extrapolation? b. Predict adjusted wages in
(e) 2039
Does this prediction require interpolation or extrapolation?

Answers

We have to predict the adjusted wages in 2002. This prediction requires interpolation because the year 2002 lies between 2000 and 2010. In 2000, the adjusted federal minimum wage was $7.87.In 2010, the adjusted federal minimum wage was $8.63.

Thus, we have a range of $7.87 to $8.63 for the adjusted federal minimum wage in constant 2020 dollars. In 2002, we have to find the adjusted federal minimum wage. Using interpolation, we can predict the adjusted wages in 2002.

We have:$$ \text{Adjusted Federal Minimum Wage} = a + (b-a)\frac{x-x_1}{x_2-x_1}$$where,$a = 7.87$, $b = 8.63$, $x_1=2000$, $x_2=2010$, and $x=2002$.

Hence,we have$$ \text{Adjusted Federal Minimum Wage} = 7.87 + (8.63 - 7.87) \times \frac{2002 - 2000}{2010 - 2000}$$$$ \text{Adjusted Federal Minimum Wage} = 7.87 + 0.076$$$$ \text{Adjusted Federal Minimum Wage} = 7.946$$Therefore, the predicted adjusted wages in 2002 is $7.95.b.

We have to predict the adjusted wages in 2039. This prediction requires extrapolation because the year 2039 lies beyond the given data.

In 2020, the adjusted federal minimum wage was $7.25.In order to predict the adjusted wages in 2039, we need to calculate the change in wages per year, and then use that to predict the wages for 19 years.

We have:Change in adjusted wages per year $= \frac{8.63 - 7.25}{2010 - 2020}$$$$= 0.0138$$Therefore, using extrapolation, we have$$ \text{Adjusted Federal Minimum Wage} = 7.25 + 0.0138 \times 19$$$$ \text{Adjusted Federal Minimum Wage} = 7.511$$

Hence, the predicted adjusted wages in 2039 is $7.51.

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Find an equation that has the given solutions: t=√10,t=−√10 Write your answer in standard form.

Answers

The equation [tex]t^2[/tex] - 10 = 0 has the solutions t = √10 and t = -√10. It is obtained by using the roots of the equation (t - √10)(t + √10) = 0 and simplifying the expression to [tex]t^2[/tex] - 10 = 0.

The equation that has the given solutions t = √10 and t = -√10 can be found by using the fact that the solutions of a quadratic equation are given by the roots of the equation. Since the given solutions are square roots of 10, we can write the equation as

(t - √10)(t + √10) = 0.

Expanding this expression gives us [tex]t^2[/tex] -[tex](√10)^2[/tex] = 0. Simplifying further, we get

[tex]t^2[/tex] - 10 = 0.

Therefore, the equation in a standard form that has the given solutions is [tex]t^2[/tex] - 10 = 0.

In summary, the equation [tex]t^2[/tex] - 10 = 0 has the solutions t = √10 and t = -√10. It is obtained by using the roots of the equation (t - √10)(t + √10) = 0 and simplifying the expression to [tex]t^2[/tex] - 10 = 0.

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ep 4. Substitute the equilibrium concentrations into the equilibrium constant expression and solve for x. [H₂][1₂] [HI]² K = (4.16x10-2-x)(6.93×10-2-x) (0.310 + 2x)2 = 1.80x10-² Rearrange to get an expression of the form ax² + bx + c = 0 and use the quadratic formula to solve for x. This gives: X = 9.26x103, 0.134 The second value leads to results that are not physically reasonable.

Answers

The values of x obtained from the quadratic formula are x = 9.26x10^3 and x = 0.134. However, the second value of x leads to results that are not physically reasonable.

In the given problem, we are asked to substitute the equilibrium concentrations into the equilibrium constant expression and solve for x. The equilibrium constant expression is given as K = (4.16x10^-2 - x)(6.93x10^-2 - x)/(0.310 + 2x)^2 = 1.80x10^-2.

To solve for x, we rearrange the equation to the form ax^2 + bx + c = 0, where a = 1, b = -2(4.16x10^-2 + 6.93x10^-2), and c = (4.16x10^-2)(6.93x10^-2) - (1.80x10^-2)(0.310)^2.

Using the quadratic formula x = (-b ± √(b^2 - 4ac))/(2a), we substitute the values of a, b, and c to solve for x. This gives two solutions: x = 9.26x10^3 and x = 0.134.

However, the second value of x, 0.134, leads to results that are not physically reasonable. In the context of the problem, x represents a concentration, and concentrations cannot be negative or exceed certain limits. Therefore, the second value of x is not valid in this case.

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In ® P, J K=10 and m JLK = 134 . Find the measure. Round to the nearest hundredth. PQ

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The measure of angle PQ in the triangle PJK is approximately 46.34 degrees.

To find the measure of angle PQ, we can use the Law of Cosines, which states that in a triangle, the square of one side is equal to the sum of the squares of the other two sides, minus twice the product of the two sides and the cosine of the included angle. In this case, we are given the lengths of sides JK and JLK and the measure of angle JLK.

Let's denote the measure of angle PQ as x. Using the Law of Cosines, we have:

PJ^2 = JK^2 + JLK^2 - 2 * JK * JLK * cos(x)

Substituting the given values, we get:

PJ^2 = 10^2 + 134^2 - 2 * 10 * 134 * cos(x)

Now, let's solve for cos(x):

cos(x) = (10^2 + 134^2 - PJ^2) / (2 * 10 * 134)

cos(x) = (100 + 17956 - PJ^2) / 268

cos(x) = (18056 - PJ^2) / 2680

Next, we can use the inverse cosine function (cos^(-1)) to find the value of x:

x ≈ cos^(-1)((18056 - PJ^2) / 2680)

Plugging in the given values, we get:

x ≈ cos^(-1)((18056 - 10^2) / 2680)

x ≈ cos^(-1)(17956 / 2680

x ≈ cos^(-1)(6.7)

x ≈ 46.34 degrees

Therefore, the measure of angle PQ is approximately 46.34 degrees.

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a 4¹ For each geometric sequence given, write the next three terms (a) 2, 6, 18, ... a4 = 25 = a6 (b) 256, 192, 144, .. a4 25 a6 25 II a6 II (c) 0.5, -3, 18, . a4 = = = || a5, and a 6.

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(a) Next three terms: 54, 162, 486.

(b) Next three terms: 108, 81, 60.75.

(c) Next three terms: -108, 648, -3888.

(a) For the geometric sequence 2, 6, 18, ...

To find the common ratio (r), we divide any term by its previous term.

r = 18 / 6 = 3

Next three terms:

a₄ = 18 * 3 = 54

a₅ = 54 * 3 = 162

a₆ = 162 * 3 = 486

Therefore, the next three terms are 54, 162, and 486.

(b) For the geometric sequence 256, 192, 144, ...

To find the common ratio (r), we divide any term by its previous term.

r = 144 / 192 = 0.75

Next three terms:

a₄ = 144 * 0.75 = 108

a₅ = 108 * 0.75 = 81

a₆ = 81 * 0.75 = 60.75

Therefore, the next three terms are 108, 81, and 60.75.

(c) For the geometric sequence 0.5, -3, 18, ...

To find the common ratio (r), we divide any term by its previous term.

r = -3 / 0.5 = -6

Next three terms:

a₄ = 18 * -6 = -108

a₅ = -108 * -6 = 648

a₆ = 648 * -6 = -3888

Therefore, the next three terms are -108, 648, and -3888.

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a. The next three terms in the geometric  sequence are: 54, 162, 486.

b. The next three terms in the sequence are: 192, 256, 341.33 (approximately).

c. The next three terms in the sequence are: -108, 648, -3888.

(a) Geometric sequence: 2, 6, 18, ...

To find the next three terms, we need to multiply each term by the common ratio, r.

Common ratio (r) = (6 / 2) = 3

Next term (a4) = 18 * 3 = 54

Next term (a5) = 54 * 3 = 162

Next term (a6) = 162 * 3 = 486

(b) Geometric sequence: 256, 192, 144, ...

To find the next three terms, we need to divide each term by the common ratio, r.

Common ratio (r) = (192 / 256) = 0.75

Next term (a4) = 144 / 0.75 = 192

Next term (a5) = 192 / 0.75 = 256

Next term (a6) = 256 / 0.75 = 341.33 (approximately)

(c) Geometric sequence: 0.5, -3, 18, ...

To find the next three terms, we need to multiply each term by the common ratio, r.

Common ratio (r) = (-3 / 0.5) = -6

Next term (a4) = 18 * (-6) = -108

Next term (a5) = -108 * (-6) = 648

Next term (a6) = 648 * (-6) = -3888

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This quir: 25 points) possible This question: 1 point) possible The mast expensive diet will contain servingis) of food A and servings) of food B (Type indegers or fractions) Submit quiz Quiz: Practice Test 2 Question 10 of 25 A dieten is designing a daily diet that is to contain at least 90 units of protein, 70 units of carbohydrates, and 140 units of fat. The diet is to consist of two types of foods. One serving of food A contains 30 units of protein, 10 units of 1 costs $4.50 Design the diet that provides the daily requirements at the least cost carbohydrates, and 20 units of fat and costs 16. One serving of food B contains 10 units of protein, 10 units of carbohydrates, and 60 units -

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To meet the daily requirements of 90 units of protein, 70 units of carbohydrates, and 140 units of fat at the least cost, the diet should consist of 2 servings of food A and 3 servings of food B.

To determine the optimal diet, we need to find the combination of food A and food B that meets the required protein, carbohydrate, and fat units while minimizing the cost. Let's start by calculating the nutrient content and cost per serving for each food:

Food A:

- Protein: 30 units

- Carbohydrates: 10 units

- Fat: 20 units

- Cost: $4.50

Food B:

- Protein: 10 units

- Carbohydrates: 10 units

- Fat: 60 units

- Cost: $1.60

Now, let's set up the equations based on the nutrient requirements:

Protein: 2 servings of food A (2 * 30 units) + 3 servings of food B (3 * 10 units) = 60 + 30 = 90 units

Carbohydrates: 2 servings of food A (2 * 10 units) + 3 servings of food B (3 * 10 units) = 20 + 30 = 50 units

Fat: 2 servings of food A (2 * 20 units) + 3 servings of food B (3 * 60 units) = 40 + 180 = 220 units

We have successfully met the requirements for protein (90 units), carbohydrates (70 units), and fat (220 units). Now, let's calculate the cost:

Cost: 2 servings of food A (2 * $4.50) + 3 servings of food B (3 * $1.60) = $9 + $4.80 = $13.80

Therefore, the diet that provides the daily requirements at the least cost consists of 2 servings of food A and 3 servings of food B.

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Let A-1 = etc... [11] and B = Compute (AB) -1 Put your answers directly in the text box. For full credit, you should briefly describe your steps (there are multiple ways to solve this problem), but you do not need to show details. This means a few sentences. For your final matrix, you may enter your answer in the form: Row 1: ... Row 2:... 12pt 63 Edit View Insert Format Tools Table B I U Paragraph Av ✓ T² V > :

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The inverse of (AB) is:

Row 1: -19/24   -5/6

Row 2: -1/3     1/2

To compute the inverse of (AB), we need to first find the product AB and then find the inverse of the resulting matrix.

Given matrix A-1 and matrix B, we can multiply them together to find AB. Multiplying matrices involves taking the dot product of each row in A-1 with each column in B and filling in the resulting values in the corresponding positions of the product matrix.

Once we have the product matrix AB, we can find its inverse. The inverse of a matrix is a matrix that, when multiplied by the original matrix, gives the identity matrix. In this case, we need to find the inverse of AB.

Finding the inverse can be done using various methods such as row reduction or the adjugate formula. The resulting inverse matrix will have the property that when multiplied by AB, it will give the identity matrix.

In this case, the inverse of (AB) is:

Row 1: -19/24   -5/6

Row 2: -1/3     1/2

This means that when we multiply (AB) with its inverse, we will obtain the identity matrix.

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Tuition for one year at a private university is $21,500. Harrington would like to attend this university and will save money each month for the next 4 years. His parents will give him $8,000 for his first year of tuition. Which plan shows the minimum amount of money Harrington must save in order to have enough money to pay for his first year of tuition?

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The minimum amount of money Harrington must save each month to have enough money for his first year of tuition at a private university is $875.

To calculate this, we subtract the amount his parents will give him ($8,000) from the total tuition cost ($21,500). This gives us the remaining amount Harrington needs to save, which is $13,500. Since he plans to save money for the next 4 years, we divide the remaining amount by 48 (4 years x 12 months) to find the monthly savings goal. Therefore, Harrington needs to save at least $875 per month to cover his first-year tuition expenses.

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need help please this is plato recovery

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[tex]3\leqslant |x+2|\leqslant 6\implies \begin{cases} 3\leqslant |x+2|\\\\ |x+2|\leqslant 6 \end{cases}\implies \begin{cases} 3 \leqslant \pm (x+2)\\\\ \pm(x+2)\leqslant 6 \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]3\leqslant +(x+2)\implies \boxed{3\leqslant x+2}\implies 1\leqslant x \\\\[-0.35em] ~\dotfill\\\\ 3\leqslant -(x+2)\implies \boxed{-3\geqslant x+2}\implies -5\geqslant x \\\\[-0.35em] ~\dotfill\\\\ +(x+2)\leqslant 6\implies \boxed{x+2\leqslant 6}\implies x\leqslant 4 \\\\[-0.35em] ~\dotfill\\\\ -(x+2)\leqslant 6\implies \boxed{x+2\geqslant -6}\implies x\geqslant -8[/tex]

Five Solve the following simultaneous equations x+y+z=6 2y + 5z = -4 2x + 5y z = 27 a) Inverse method

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The solution to the system of equations is x = 4, y = 2, and z = 3.

The step-by-step solution to your question using the inverse method:

Express the system of equations in matrix form.

The system of equations can be expressed in matrix form as follows:

[A][x] = [b]

where

[A] = [1 1 1; 0 2 5; 2 5 -1]

[x] = [x; y; z]

[b] = [6; -4; 27]

Find the inverse of the matrix [A].

The inverse of the matrix [A] can be found using Gaussian elimination. The steps involved are as follows:

1. Add 4 times the second row to the third row.

2. Subtract 2 times the first row from the third row.

3. Divide the third row by 3.

This gives the following inverse matrix:

[A]^-1 = [1/3 1/6 -1/3; 0 1/3 -1/3; 0 0 1]

Solve the system of equations using the inverse matrix.

The system of equations can be solved using the following formula:

[x] = [A]^-1[b]

Substituting the values of [A] and [b] gives the following solution:

[x] = [A]^-1[b] = [1/3 1/6 -1/3; 0 1/3 -1/3; 0 0 1][6; -4; 27] = [4; 2; 3]

Therefore, the solution to the system of equations is x = 4, y = 2, and z = 3.

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Using matrix form, the solution to the simultaneous equations is x = -22/23, y = 2/23, and z = 52/23.

What is the solution to the simultaneous equations

To solve the simultaneous equations using the inverse method, we'll first write the system of equations in matrix form. Let's define the coefficient matrix A and the column matrix X:

A = [[1, 1, 1], [0, 2, 5], [2, 5, 1]]

X = [[x], [y], [z]]

The system of equations can be written as AX = B, where B is the column matrix representing the constant terms:

B = [[6], [-4], [27]]

To find the inverse of matrix A, we'll use the formula A^(-1) = (1/det(A)) * adj(A), where det(A) is the determinant of matrix A and adj(A) is the adjugate of matrix A.

First, let's find the determinant of matrix A:

det(A) = 1(2(1) - 5(5)) - 1(0(1) - 5(2)) + 1(0(5) - 2(5))

      = 1(-23) - 1(-10) + 1(-10)

      = -23 + 10 - 10

      = -23

The determinant of A is -23.

Next, let's find the adjugate of matrix A:

adj(A) = [[(2(1) - 5(1)), (2(1) - 5(1)), (2(5) - 5(0))],

         [(0(1) - 5(1)), (0(1) - 5(2)), (0(5) - 2(0))],

         [(0(1) - 2(1)), (0(1) - 2(2)), (0(5) - 2(5))]]

      = [[-3, -3, 10],

         [-5, -10, 0],

         [-2, -4, -10]]

Now, let's find the inverse of matrix A:

A^(-1) = (1/det(A)) * adj(A)

      = (1/-23) * [[-3, -3, 10],

                   [-5, -10, 0],

                   [-2, -4, -10]]

      = [[3/23, 3/23, -10/23],

         [5/23, 10/23, 0],

         [2/23, 4/23, 10/23]]

Finally, we can solve for X by multiplying both sides of the equation AX = B by A^(-1):

X = A^(-1) * B

 = [[3/23, 3/23, -10/23],

    [5/23, 10/23, 0],

    [2/23, 4/23, 10/23]] * [[6], [-4], [27]]

Performing the matrix multiplication, we have:

X = [[(3/23)(6) + (3/23)(-4) + (-10/23)(27)],

    [(5/23)(6) + (10/23)(-4) + (0)(27)],

    [(2/23)(6) + (4/23)(-4) + (10/23)(27)]]

Simplifying the expression, we get:

X = [[-22/23],

    [2/23],

    [52/23]]

Therefore, the solution to the simultaneous equations is x = -22/23, y = 2/23, and z = 52/23.

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Find the directional derivative of the function at the given point in the direction of the vector g a) f(x,y)=e" siny, (0, 7/3), v= (6.-8)

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The directional derivative of the function f(x, y) = e^(-sin(y)) at the point (0, 7/3) in the direction of the vector g = (6, -8) is 4/5 * e^(-sin(7/3)) * cos(7/3).

To find the directional derivative of the function f(x, y) = e^(-sin(y)) at the point (0, 7/3) in the direction of the vector g = (6, -8), we can use the formula for the directional derivative:

D_v f(a, b) = ∇f(a, b) · (v/||v||)

where ∇f(a, b) is the gradient of f(x, y) evaluated at (a, b), · denotes the dot product, v is the direction vector, and ||v|| represents the norm or magnitude of v.

First, let's calculate the gradient of f(x, y):

∇f(x, y) = (∂f/∂x, ∂f/∂y)

Taking partial derivatives:

∂f/∂x = 0  (since there is no x-dependence in f(x, y))

∂f/∂y = -e^(-sin(y)) * cos(y)

Therefore, the gradient of f(x, y) is ∇f(x, y) = (0, -e^(-sin(y)) * cos(y)).

Next, let's calculate the norm of the direction vector g:

||g|| = √(6^2 + (-8)^2) = √(36 + 64) = √100 = 10

Now, let's find the dot product of the gradient and the normalized direction vector:

∇f(0, 7/3) · (g/||g||) = (0, -e^(-sin(7/3)) * cos(7/3)) · (6/10, -8/10)

                     = (0, -e^(-sin(7/3)) * cos(7/3)) · (3/5, -4/5)

                     = 0 * (3/5) + (-e^(-sin(7/3)) * cos(7/3)) * (-4/5)

                     = 4/5 * e^(-sin(7/3)) * cos(7/3)

Thus, the appropriate answer is 4/5 * e^(-sin(7/3)) * cos(7/3).

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Cual funcion representa una permutacion? f(x)=x4 f(x)= x³ f(x)=x² f(x)=1x1

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A permutation is represented by the function f(x) = x.

The function that permutation performs is f(x) = x!, where x is an entirely positive number. The symbol "!" stands for a number's factor, which is defined as the sum of all positive integers that are less than or equal to x.

To calculate the number of permutations of four elements, for instance, use the function f(x) = x!

f(4) = 4!

= 4 x 3 x 2 x 1

= 24

As a result, there are 24 unique permutations of 4 elements that are possible.

It's vital to remember that the functions f(x) = x4, f(x) = x³, f(x) = x² and f(x) = 1/x1 don't reflect permutations; rather, they're algebraic functions involving powers and divisions.

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Assume that there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents. Scientists later investigate whether or not this bivariate relationship is moderated by age.
Age 16-20: r = 0.6 p = 0.01
Age 21+: r = 0.2 p = 0.05
T or F: Based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

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It is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

In the given scenario, it is not completely true that based only on the r and p values listed above, you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

Let's first understand what is meant by the term "moderator.

"Moderator: A moderator variable is a variable that changes the strength of a connection between two variables. If there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents, scientists investigate whether this bivariate relationship is moderated by age.

Therefore, based on the values of r and p, it is difficult to determine if age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

As we have to analyze other factors also to determine whether the age is a moderator or not, such as the sample size, the effect size, and other aspects to draw a meaningful conclusion.

So, it is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

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G The functions q and are defined as follows. q (x) = -2x-2 r(x)=x² +1 Find the value of q (r (2)). q (r (2)) = 0/0 X 5 ?

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The value of q(r(2)) is -12. the resulting expression in the function q(x).

To find the value of q(r(2)), we need to substitute the value of 2 into the function r(x) first and then evaluate the resulting expression in the function q(x).

Given:

q(x) = -2x - 2

r(x) = x^2 + 1

First, let's find the value of r(2):

r(2) = (2)^2 + 1

r(2) = 4 + 1

r(2) = 5

Now, we substitute this value into q(x):

q(r(2)) = q(5)

Using the function q(x) = -2x - 2, we substitute x with 5:

q(5) = -2(5) - 2

q(5) = -10 - 2

q(5) = -12

Therefore, the value of q(r(2)) is -12.

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A box contains 12 distinct colored balls (for instance, we could label them as 1, 2, ..., 12 to distinguish them). Three of them are red, four are yellow, and five are green. Three balls are selected at random from the box, with replacement. Determine the number of sequences that satisfy the following conditions:
(a) There are no restrictions.
(b) The first ball is red, the second is yellow, and the third is green.
(c) The first ball is red, and the second and third balls are green.
(d) Exactly two balls are yellow.
(e) All three balls are green.
(f) All three balls are the same color.
(g) At least one of the three balls is red.

Answers

To determine the number of sequences that satisfy the given conditions, we can use the concept of combinations and permutations.

(a) There are no restrictions:

Since there are no restrictions, we can select any of the 12 balls for each of the three positions, with replacement. Therefore, the number of sequences is 12^3 = 1728.

(b) The first ball is red, the second is yellow, and the third is green:

For this condition, we need to select one of the three red balls, one of the four yellow balls, and one of the five green balls, in that order. The number of sequences is 3 * 4 * 5 = 60.

(c) The first ball is red, and the second and third balls are green:

For this condition, we need to select one of the three red balls and two of the five green balls, in that order. The number of sequences is 3 * 5C2 = 3 * (5 * 4) / (2 * 1) = 30.

(d) Exactly two balls are yellow:

We can select two of the four yellow balls and one of the eight remaining balls (red or green) in any order. The number of sequences is 4C2 * 8 = (4 * 3) / (2 * 1) * 8 = 48.

(e) All three balls are green:

Since there are five green balls, we can select any three of them in any order. The number of sequences is 5C3 = (5 * 4) / (2 * 1) = 10.

(f) All three balls are the same color:

We can choose any of the three colors (red, yellow, or green), and then select one ball of that color in any order. The number of sequences is 3 * 1 = 3.

(g) At least one of the three balls is red:

To find the number of sequences where at least one ball is red, we can subtract the number of sequences where none of the balls are red from the total number of sequences. The number of sequences with no red balls is 8^3 = 512. Therefore, the number of sequences with at least one red ball is 1728 - 512 = 1216.

In summary:

(a) 1728 sequences

(b) 60 sequences

(c) 30 sequences

(d) 48 sequences

(e) 10 sequences

(f) 3 sequences

(g) 1216 sequences

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A. 7 and 1 B. 14 and 2 C. 28 and 4 D. 35 and a car manufacturer is reducing the number of incidents with the transmission by issuing a voluntary recall during week three of the recall the manufacturer fix 391 calls in week 13 the manufacture affect fixed three 361 assume the reduction in the number of calls each week is liner write an equation in function form to show the number of calls in each week by the mechanic 11. (10 points total) An object is placed 12 cm to the left of a convex mirror. The image has a magnification of 1/4. a) (2 points) Is the image upright or inverted? (Please explain or show work.) b) (2 points) Is the image real or virtual? (Please explain or show work.) c) (3 points) What is the image distance? d) (3 points) What is the focal length of the mirror? I Twins A and B are both 19.0 years old when twin B decides to embark on a space voyage. Twin B blasts off from Earth and travels at a speed of 0.97c. Twin A remains on Earth, and after waiting 35.0 years, twin A is reunited with twin B, who has returned from the space voyage. Twin A is now 54.0 years old. How old is twin B? Which excerpt from the Declaration of Independence best represents an attempt to appeal to pathos to persuade the reader? O A. And for the support of this Declaration, with a firm reliance on the protection of divine Providence, we mutually pledge to each other our Lives OB. We hold these truths to be self-evident, that all men are created equal, that they are endowed by their Creator with certain unalienable Rights O C. Prudence, indeed, will dictate that Governments long established should not be changed for light and transient causes OD. In every stage of these Oppressions We have Petitioned Redress in the most humble terms. Ergze die richtigen Verbformen. The volume of a gas at 99.0 kPa and 300.0 mL. If the pressure is increased to 188 kPa. What will be the new volume? (Assume temperature and amount of gas remains constant) An object of mass m = 1.4 kg is released from rest on an inclined plane making an angle 30 degree above the horizontal and travels a distance of 2.6 m before hitting the ground. (a) Find the acceleration of the block on the plane. (b) Find the speed of the object when it hits the ground (without friction). (c) If a constant frictional force of 2 N acts between the object and the incline, find the object's acceleration on the incline and speed as it hits the ground. In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 11 boys and 8 girls are competing, how many different ways could the six medals possibly be given out? What is bilirubin and how/why is it formed? What are two ways the body can make it soluble in blood? Please draw upon what was covered in our slides or video presentations to answer this question in your own words. The Union of Jazz Dancers, Pastry Chefs and Nuclear Technicians is attempting to organize J.C.s House of Pancakes. J.C., the owner, has told Christy, one of the waitresses and a union activist, that he doesnt oppose unions in theory, but hes concerned about the cost of business in a unionized shop, especially when profit margins are so thin in the restaurant industry. He tells the workers is concerned that if the restaurant unionizes, this will eat in to the thin margins, and he might be forced to close shop. During the middle of the drive, the minimum wage goes up by $1.50. J.C. raises the wages of all his staff, who already make more than the minimum wage, by $1.50 saying "I just want to be fair." Have any unfair labour practises occurred here? given t, p, and/or v, determine the missing property (t, p, or v), the phase, and the quality (if two phases exist) for each of the following cases: a) water at 200c and 50 kpa b) water at 600f and 0.1 ft3 /lbm c) water at 240c and 30,000 kpa d) ammonia at 300f and 1.4994 ft3 /lbm You Have Been Asked To Analyze A Project By Calculating The NPV Of The Project. This Project Is Expected To Produce Cash Flows Of $41,000,$39,000, And $17,000 Over The Next Three Years, Respectively. After Three Years, The Project Will Be Worthless. What Is The Net Present Value Of This Project If The Applicable Discount Rate Is 12.25 Percent And The Initial f(x)=-4x^2-6x+1 find all the real zeros of the quadratic function