Let a and b be real numbers where a=/b=/c=/0 which of the following functions could represent the graph below?

Answer:

a)0.7 is greater than>0.52

b)0.52 is greater than>0.045

c)0.49 is less than<0.94

d)0.302 is greater than>0.23

e)0.9 is greater than>0.6

f)2.36 is less than<3.19

Answer:

B.

Step-by-step explanation:

You can cross multiply or multiply by the common denominator. The common denominator in this case is [tex]5\cdot x=5x[/tex]

[tex]5x(\frac{6}{x})=5x(\frac{2x+4}{5})[/tex]

[tex]30=2x^2+4x[/tex]

[tex]2x^2+4x-30=0[/tex]

Note that [tex]x\neq 0[/tex]

Answer:

B

Step-by-step explanation:

Well the common denominator of 5 and x is 5*x=5x.

[tex]5x(\frac{6}{x} )=5x(\frac{2x+4}{5} )\\\\30=2x^{2} +4x\\\\2x^2+4x-30=0[/tex]

Answer:

576"

Step-by-step explanation:

AL=ph

AL= (4*12)12

AL= 48*12

AL=576"

Answer:

1. true - dilating figures does not change their angle measure

2. true - dilating figures does not change the orientation, so AD would still be on a horizontal line parallel to its current position

Answer:

interior angle (2)= 70

interior angle (3)= 60

Step-by-step explanation:

Given:

exterior angle=120°

interior angle (1)=50°

Required:

interior angle (2)=?

interior angle (3)=?

Formula:

exterior angle=interior angle (1) + interior angle (2)

Solution:

exterior angle=interior angle (1)+ interior angle (2)

120°=50°+interior angle (2)

120°+50°=interior angle (2)

70°=interior angle (2)

interior angle (3)= 180°-interior angle (1)- interior angle (2)

interior angle (3)=180°-50°+70°

interior angle (3)=180°-120°

interior angle (3)= 60°

Theorem:

Theorem 1.16

The measure of an exterior angle of a triangle is greater than either of the measures of the remote interior angles.

Hope this helps ;) ❤❤❤

Hey there! I'm happy to help!

We see that it takes 45 minutes for a person to drive 50 miles. We can write this as a fraction that is 45/50, which simplifies to 9/10, meaning it would take this person 9 minutes to travel 10 miles.

So, how long would it take to travel 120? Well, we know that if we take 10 miles and multiply it by 12 we will have 120 miles. If we take the time it takes to drive those ten miles (9 minutes) and multiply it by 12, we will figure out how long it takes to drive 120 miles!

9×12=108

However, we want this to be written in hours. We know that there are 60 minutes in an hour, and if we subtract 60 from 108 we have 48. This gives us 1 hour and 48 minutes.

Therefore, it will take 1 hour and 48 minutes for this person to travel 120 miles at the same rate.

Have a wonderful day! :D

Answer:

We conclude that the percentage of blue candies is equal to 29​%.

Step-by-step explanation:

We are given that in a random selection of 100 colored​ candies, 28​% of them are blue. The candy company claims that the percentage of blue candies is equal to 29​%.

Let p = population percentage of blue candies

So, Null Hypothesis, [tex]H_0[/tex] : p = 29%     {means that the percentage of blue candies is equal to 29​%}

Alternate Hypothesis, [tex]H_A[/tex] : p [tex]\neq[/tex] 29%     {means that the percentage of blue candies is different from 29​%}

The test statistics that will be used here is One-sample z-test for proportions;

                         T.S.  =  [tex]\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of blue coloured candies = 28%

           n = sample of colored​ candies = 100

So, the test statistics =  [tex]\frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }[/tex]

                                    =  -0.22

The value of the z-test statistics is -0.22.

Also, the P-value of the test statistics is given by;

               P-value = P(Z < -0.22) = 1 - P(Z [tex]\leq[/tex] 0.22)

                            = 1 - 0.5871 = 0.4129

Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of z, so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the percentage of blue candies is equal to 29​%.

Answer:

The minimum svore required to get an A is 85.3.

Step-by-step explanation:

Complete Question

Exam grades: Scores on a statistics final in a large class were normally distributed with a mean of 75 and a standard deviation of 8.

The instructor wants to give an A to the students whose scores were in the top 10% of the class. What is the minimum score needed to get an A?

Solution

Scores in the top 10% of the class will have a minimum greater than the remaining bottom 90% of the class.

If the minimum score for the top 10% of the class is x'

P(X ≤ x') = 90% = 0.90

If the z-score of this minimum score of the top 10%, x', is z'.

P(X ≤ x') = P(z ≤ z') = 0.90

using the z-distribution tables

z' = 1.282

But the z-score of any value is given as the value minus the mean divided by the standard deviation.

z = (x - μ)/σ

So,

z' = (x' - μ)/σ

Mean = 75

Standard deviation = 8

z' = 1.282

1.282 = (x' - 75)/8

x' = (1.282 × 8) + 75 = 85.256

= 85.3 to 3 s.f.

Hope this Helps!!!

Answer:

x = 69°

Step-by-step explanation:

In the picture attached,

Length of the ladder = 15 ft

This ladder reaches the height of a building = 14 ft

We have to find the measure of angle formed between the base of the ladder and the ground.

By applying Sine rule in the right triangle formed,

sin(x)° = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

sin(x)° = [tex]\frac{14}{15}[/tex]

x = [tex]\text{sin}^{-1}(\frac{14}{15})[/tex]

x = 68.96°

x ≈ 69°

Answer:

(0,-2)

Step-by-step explanation:

The y-intercept is simply when the function touches or crosses the y-axis.

We're told that the graph crosses the y-axis at -2. In other words, the y-intercept is at -2.

The ordered pair would be (0,-2)

Answer:

[2.5 ,4]

Step-by-step explanation:

The graph in this interval has a vertex while opening up wich means it's a minimum

Answer:

3¾

Step-by-step explanation:

Geometric sequence also known as geometric progression, can be said to be a sequence with a constant ratio between the terms.

Formula for geometric sequence:

[tex] a^n = a ( n-1 ) * r [/tex]

Given:

First term, a1 = 30

ratio, r = ½

Required:

Find the fourth term

Where, the first term, a¹ = 30

Second term: a² = 30 * ½ = 15

Third term: a³ = 15 * ½ = 7.5

Fourth term: a⁴ = 7.5 * ½ = 3.75 = 3¾

Therfore the fourth term of the geometric sequence is 3¾

Answer:

5 mi  1432 yds

Step-by-step explanation:

   8mi 200 yds

- 2 mi 528 yds

---------------------------

We have to borrow 1 mile and convert to yards

1 mile = 1760 yds

 7mi 200+1760 yds

- 2 mi 528 yds

---------------------------

 7mi  1960 yds

- 2 mi 528 yds

---------------------------

5 mi  1432 yds

Answer:

8mi 200yds - 2mi 528yds

= 5mi 1432yds

Step-by-step explanation:

1 mile = 1760 yards

8 miles = 7miles + 1 mile = 7 miles + 1760 miles = 7 miles 1760 yards

8miles 200 yards = 7miles + 1760 yards + 200 yards = 7miles + 1960 yards

then:

8mi 200 yds - 2 mi 528 yds = 7mi 1960yds - 2mi 528yds

 7mi 1960yds

- 2mi   528yds

= 5mi  1432yds

Answer:

C) y = x + 5

Step-by-step explanation

Add 5 to both sides

Answer: Probability of visiting at most twice = 0.82

Step-by-step explanation: The probability distribution is of the form:

 X      0         1           2            3

P(X)  0.17   0.33      0.32       0.18

It wants the probability of visiting the gym at most twice in a month, which means the probability of never going to the gym, P(X=0), or going once, P(X=1), or going twice, P(X=2).

Using the "OR" probability:

P(visiting at most twice) = P(X=0) + P(X=1) + P(X=2)

P(visiting at most twice) = 0.17 + 0.33 + 0.32

P(visiting at most twice) = 0.82

Therefore, the probability of visiting the gym at most twice in a month is 0.82 or 82%

Answer:

a)13 b)no because at 18th term its -345

Answer:

-3x^2 -5x +2

Step-by-step explanation:

-2x(x+3)-(x+1)(x-2)=

Distribute

-2x^2 -6x  -(x+1)(x-2)

Foil

-2x^2 -6x  -(x^2 -2x +x -2)

Combine like terms

-2x^2 -6x  -(x^2 -x  -2)

Distribute the minus sign

-2x^2 -6x  -x^2  +x +2

Combine like terms

-2x^2  -x^2  -6x +x +2

-3x^2 -5x +2

Answer:

[tex]\huge\boxed{-2x(x+3)-(x+1)(x-2)=-3x^2-5x+2}[/tex]

Step-by-step explanation:

[tex]-2x(x+3)-(x+1)(x-2)[/tex]

Use the distributive property: a(b + c) = ab + ac

and FOIL: (a + b)(c + d) = ac + ad + bc + bd

[tex]=(-2x)(x)+(-2x)(3)-\bigg[(x)(x)+(x)(-2)+(1)(x)+(1)(-2)\bigg]\\\\=-2x^2-6x-\bigg(x^2-2x+x-2\bigg)=-2x^2-6x-x^2-(-2x)-x-(-2)\\\\=-2x^2-6x-x^2+2x-x+2[/tex]

Combine like terms:

[tex]=(-2x^2-x^2)+(-6x+2x-x)+2=-3x^2+(-5x)+2\\\\=-3x^2-5x+2[/tex]

Answer:

4/ 100000

hope it was useful for you

stay at home stay safe

pls mark me as brain.....m

keep rocking

Answer:

y = -3.5x² + 2.7x -8.2

Step-by-step explanation:

the quadratic equation is set up as a² + bx + c, so just plug in the values

Answer:

[tex]-3.5x^2 + 2.7x -8.2[/tex]

Step-by-step explanation:

Quadratic functions are always formatted in the form [tex]ax^2+bx+c[/tex].

So, we can use your values of a, b, and c, and plug them into the equation.

A is -3.5, so the first term becomes [tex]-3.5x^2[/tex].

B is 2.7, so the second term is [tex]2.7x[/tex]

And -8.2 is the C, so the third term is [tex]-8.2[/tex]

So we have [tex]-3.5x^2+2.7x-8.2[/tex]

Hope this helped!

Complete Question

The standard deviation of samples from supplier A is 0.4582, while the standard deviation of samples from supplier B is 0.3358. Which supplier would you be likely to choose based on these data and why?

1 Supplier A, as their standard deviation is higher and, thus easier to fit into our production line

2 Supplier B, as their standard deviation is higher and, thus, easier to fit into our production line

3 supplier B, as their standard deviation is lower and, thus, easier to fit into our production line

4 Supplier A, as their standard deviation is lower and, thus, easier to fit into our production line

Answer:

Option 3 is  correct

Step-by-step explanation:

From the question we are told that

     The  standard deviation of A is  [tex]\sigma_a = 0.4582[/tex]

      The  standard deviation of B is  [tex]\sigma _b = 0.3358[/tex]

Generally standard deviation defines the deviation element of a data set with respect to the mean of the set

So sample  it mean that samples from A deviates more from it mean(the standard value) than the samples from B so the best supplier to chose is B

Answer:

the actual answer is 78750

Step-by-step explanation:

summation of 2-176 in the equation 5n+5

Answer:

Z > Zα

6.511 > 1.645

Step-by-step explanation:

                                 University A           University B

Sample Size                      50                        40

Average Purchase         $280                   $250

Standard Deviation         $20                     $23

We formulate

H0:   x1` > x2`  null hypothesis that the mean of the University A is greater than the mean of the University B

HA:  x1`≤ x2`   one tailed test

Test statistic

Z= x1`-x2`/ √s₁²/n₁ +s²₂/n₂

Z= 280-250/√400/50 + 529/40

Z= 30/√8 +13.225

Z= 30 /4.607

Z= 6.511

For one tailed test at α= 0.05 = 1.645

Z > Zα

6.511 > 1.645

Thus we reject null hypothesis.On the average, students at University A spend more on textbooks then the students at University B.

Power and chain rule (where the power rule kicks in because [tex]\sqrt x=x^{1/2}[/tex]):

[tex]\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'[/tex]

Simplify the leading term as

[tex]\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}[/tex]

Quotient rule:

[tex]\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}[/tex]

Chain rule:

[tex](\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)[/tex]

[tex](1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)[/tex]

Put everything together and simplify:

[tex]\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}[/tex]

[tex]=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}[/tex]

[tex]=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}[/tex]

[tex]=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}[/tex]

[tex]=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}[/tex]

[tex]=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}[/tex]

[tex]=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}[/tex]

Answer:

A) P(A|B) = 0.01966

B) P(A'|B') = 0.99944

Step-by-step explanation:

A) We are told that A is the event "the person is infected" and B is the event "the person tests positive".

Thus, using bayes theorem, the probability that the person is infected is; P(A|B)

From bayes theorem,

P(A|B) = [P(A) × P(B|A)]/[(P(A) x P(B|A)) + (P(A') x P(B|A'))]

Now, from the question,

P(A) = 1/400

P(A') = 399/400

P(B|A) = 0.8

P(B|A') = 0.1

Thus;

P(A|B) = [(1/400) × 0.8)]/[((1/400) x 0.8) + ((399/400) x (0.1))]

P(A|B) = 0.01966

B) we want to find the probability that when a person tests negative, the person is not infected. This is;

P(A'|B') = P(Not infected|negative) = P(not infected and negative) / P(negative) = [(399/400) × 0.9)]/[((399/400) x 0.9) + ((1/400) x (0.2))] = 0.99944

Answer:

[tex]\large \boxed{\sf \ \ (-5,0) \ and \ (4,0) \ \ }[/tex]

Step-by-step explanation:

Hello,

We need to find the zeroes of

[tex]-0.25x^2-0.25x+5=0\\\\\text{*** multiply by -4 ***} \\ \\x^2+x-20=0\\\\\text{*** the sum of the zeroes is -1 and the product -20=-5x4 ***}\\\\x^2+5x-4x-20=x(x+5)-4(x+5)=(x+5)(x-4)=0\\\\x=4 \ or \ x=-5[/tex]

and then g(4)=0 and g(-5)=0

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:(-5,0) (4,0)

I took the test hope it helps you (:

Answer:

26

Step-by-step explanation:

Given that:

At time, t=0, Billy puts 625 into an account paying 6% simple interest

At the end of year 2, George puts 400 into an account paying interest at a force of interest, 1/(6+t), for all t ≥ 2.

If both accounts continue to earn interest indefinitely at the levels given above, the amounts in both accounts will be equal at the end of year n. Calculate n.

In order to calculate n;

Let K constant to be the value of time for both accounts

At  time, t=0, the value of time K when Billy puts 625 into an account paying 6% simple interest is:

[tex]K = 625 \times (1+ 0.06 K)[/tex]

[tex]K = 625 +37.5 K[/tex]

At year end 2; George  amount of 400 will grow at a force interest, then the value of  [tex]K = 400 \times e^{\int\limits^2_k {\dfrac{1}{6+t}} \, dx }[/tex]

[tex]K =400 \times \dfrac{6+K}{6+2}[/tex]

[tex]K =400 \times \dfrac{6+K}{8}[/tex]

[tex]K =50 \times ({6+K})[/tex]

[tex]K =300+50K[/tex]

Therefore:

If K = K

Then:

625 + 37.5 = 300 +50 K

625-300 = 50 K - 37.5 K

325 = 12.5K

K = 325/12.5

K = 26

the amounts in both accounts  at the end of year n = K = 26

Answer:

168 mm²

Step-by-step explanation:

Let A be the area of this shape

the kite is made of two triangles

Let A' and A" be the areas of the triangles

let's calculate A' and A" :

The area of a triangle is the product of the base and the height over 2

Let's calculate A

Answer:

2/6 which when simplified, is equal to 1/3

Answer:

1/3

Step-by-step explanation:

Step-by-step explanation:

If f(x) =x, is the father function, then all it's child function would be equally inclined to x and y-axis respectively.

If f(x) =x, is the father function, then all its child functions would be equally inclined to the x and y-axis respectively.

Each family of capabilities has a determining feature. A discern function is the best function that also satisfies the definition of a certain sort of function. As an instance, whilst we think about the linear capabilities which make up our own family of capabilities, the parent feature could be y = x.

Key commonplace points of linear determine features encompass the reality that the equation is y = x. Domain and variety are actual numbers. Slope, or fee of alternate, is steady.

Learn more about parent functions here: https://brainly.com/question/4025726

#SPJ2

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

[tex]p_{1}(t) = 1[/tex], [tex]p_{2}(t)= t^{2}[/tex] and [tex]p_{3}(t) = 3 + 3\cdot t[/tex]:

[tex]\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0[/tex]

[tex]\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0[/tex]

[tex](\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0[/tex]

The following system of linear equations is obtained:

[tex]\alpha_{1} + 3\cdot \alpha_{3} = 0[/tex]

[tex]\alpha_{2} = 0[/tex]

[tex]\alpha_{3} = 0[/tex]

Whose solution is [tex]\alpha_{1} = \alpha_{2} = \alpha_{3} = 0[/tex], which means that the set of vectors is linearly independent.

[tex]p_{1}(t) = t[/tex], [tex]p_{2}(t) = t^{2}[/tex] and [tex]p_{3}(t) = 2\cdot t + 3\cdot t^{2}[/tex]

[tex]\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0[/tex]

[tex]\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0[/tex]

[tex](\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0[/tex]

The following system of linear equations is obtained:

[tex]\alpha_{1}+2\cdot \alpha_{3} = 0[/tex]

[tex]\alpha_{2}+3\cdot \alpha_{3} = 0[/tex]

Since the number of variables is greater than the number of equations, let suppose that [tex]\alpha_{3} = k[/tex], where [tex]k\in\mathbb{R}[/tex]. Then, the following relationships are consequently found:

[tex]\alpha_{1} = -2\cdot \alpha_{3}[/tex]

[tex]\alpha_{1} = -2\cdot k[/tex]

[tex]\alpha_{2}= -2\cdot \alpha_{3}[/tex]

[tex]\alpha_{2} = -3\cdot k[/tex]

It is evident that [tex]\alpha_{1}[/tex] and [tex]\alpha_{2}[/tex] are multiples of [tex]\alpha_{3}[/tex], which means that the set of vector are linearly dependent.

[tex]p_{1}(t) = 1[/tex], [tex]p_{2}(t)=t^{2}[/tex] and [tex]p_{3}(t) = 3+3\cdot t +t^{2}[/tex]

[tex]\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0[/tex]

[tex]\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2}+ \alpha_{3}\cdot (3+3\cdot t+t^{2}) = 0[/tex]

[tex](\alpha_{1}+3\cdot \alpha_{3})\cdot 1+(\alpha_{2}+\alpha_{3})\cdot t^{2}+3\cdot \alpha_{3}\cdot t = 0[/tex]

The following system of linear equations is obtained:

[tex]\alpha_{1}+3\cdot \alpha_{3} = 0[/tex]

[tex]\alpha_{2} + \alpha_{3} = 0[/tex]

[tex]3\cdot \alpha_{3} = 0[/tex]

Whose solution is [tex]\alpha_{1} = \alpha_{2} = \alpha_{3} = 0[/tex], which means that the set of vectors is linearly independent.

The set of vectors A and C are linearly independent.