Answer:
[tex]10[/tex].
Step-by-step explanation:
See below for a proof of why all but the first digit of this [tex]N[/tex] must be "[tex]9[/tex]".
Taking that lemma as a fact, assume that there are [tex]x[/tex] digits in [tex]N[/tex] after the first digit, [tex]\text{A}[/tex]:
[tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{$x$ digits}}}[/tex], where [tex]x[/tex] is a positive integer.
Sum of these digits:
[tex]\text{A} + 9\, x= 2021[/tex].
Since [tex]\text{A}[/tex] is a digit, it must be an integer between [tex]0[/tex] and [tex]9[/tex]. The only possible value that would ensure [tex]\text{A} + 9\, x= 2021[/tex] is [tex]\text{A} = 5[/tex] and [tex]x = 224[/tex].
Therefore:
[tex]N = \overline{5 \, \underbrace{9 \cdots 9}_{\text{$224$ digits}}}[/tex].
[tex]N + 1 = \overline{6 \, \underbrace{000 \cdots 000000}_{\text{$224$ digits}}}[/tex].
[tex]N + 2021 = 2020 + (N + 1) = \overline{6 \, \underbrace{000 \cdots 002020}_{\text{$224$ digits}}}[/tex].
Hence, the sum of the digits of [tex](N + 2021)[/tex] would be [tex]6 + 2 + 2 = 10[/tex].
Lemma: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".
Proof:
The question assumes that [tex]N\![/tex] is the smallest positive integer whose sum of digits is [tex]2021[/tex]. Assume by contradiction that the claim is not true, such that at least one of the non-leading digits of [tex]N[/tex] is not "[tex]9[/tex]".
For example: [tex]N = \overline{(\text{A})\cdots (\text{P})(\text{B}) \cdots (\text{C})}[/tex], where [tex]\text{A}[/tex], [tex]\text{P}[/tex], [tex]\text{B}[/tex], and [tex]\text{C}[/tex] are digits. (It is easy to show that [tex]N[/tex] contains at least [tex]5[/tex] digits.) Assume that [tex]\text{B} \![/tex] is one of the non-leading non-"[tex]9[/tex]" digits.
Either of the following must be true:
[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is a "[tex]0[/tex]", or[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is not a "[tex]0[/tex]".If [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is a "[tex]0[/tex]", then let [tex]N^{\prime}[/tex] be [tex]N[/tex] with that "[tex]0\![/tex]" digit deleted: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{B}) \cdots (\text{C})}[/tex].
The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:
[tex]\begin{aligned}& \text{A} + \cdots + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + 0 + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].
However, with one fewer digit, [tex]N^{\prime} < N[/tex]. This observation would contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].
On the other hand, if [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is not "[tex]0[/tex]", then [tex](\text{P} - 1)[/tex] would still be a digit.
Since [tex]\text{B}[/tex] is not the digit [tex]9[/tex], [tex](\text{B} + 1)[/tex] would also be a digit.
let [tex]N^{\prime}[/tex] be [tex]N[/tex] with digit [tex]\text{P}[/tex] replaced with [tex](\text{P} - 1)[/tex], and [tex]\text{B}[/tex] replaced with [tex](\text{B} + 1)[/tex]: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{P}-1) \, (\text{B} + 1) \cdots (\text{C})}[/tex].
The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:
[tex]\begin{aligned}& \text{A} + \cdots + (\text{P} - 1) + (\text{B} + 1) + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].
However, with a smaller digit in place of [tex]\text{P}[/tex], [tex]N^{\prime} < N[/tex]. This observation would also contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].
Either way, there would be a contradiction. Hence, the claim is verified: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".
Therefore, [tex]N[/tex] would be in the form: [tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{many digits}}}[/tex], where [tex]\text{A}[/tex], the leading digit, could also be [tex]9[/tex].
Adya and Ashley complete a work separately in 20 and 25 days respectively. After 10 days of their working together, they both left then Amber came and completed the remaining work in 3 days. If Amber alone would do the work, calculate how many days he would take to complete the work.?
[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]
Number of days Adya took to complete the work = 20
Work done by Adya in 1 day = [tex]\frac{1}{20}[/tex]
Number of days Ashley took to complete the work = 25
Work done by Ashley in 1 day = [tex]\frac{1}{25}[/tex]
So,
Total work by Adya & Ashley in 1 day =
[tex] \frac{1}{20} + \frac{1}{20} \\ = \frac{5 + 4}{100} \\ = \frac{9}{100} [/tex]
•°• Their total work in 10 days =
[tex] \frac{9 \times 10}{100} \\ = \frac{90}{100} \\ = \frac{9}{10} [/tex]
Now,
The work left to be completed =
[tex]1 - \frac{9}{10} \\ = \frac{10}{10} - \frac{9}{10} \\ = \frac{1}{10} [/tex]
From this we know that,
Amber completes [tex]\frac{1}{10}[/tex] of the work in 3 days.
So,
Time taken by Amber to complete the whole work =
[tex]3 \times 10 \\ = 30 \: \: days[/tex]
↦ If Amber alone would do the whole work, he would take [tex]\boxed{30 \ \ days}[/tex] to complete it.
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꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
(Will put as Brainliest) Please help! :")
A speciality candy shop makes chocolate covered cherry and graham cookie bites. The cherry is spherical with a diameter of 3cm and the graham cookie is a rectangular prism with a base measuring 5cm by 5cm and a thickness of 0.5cm. What is the total surface area of the bite if each piece is drenched in chocolate from top to bottom before being put together, to the nearest tenth of a square centimetre.
Answer:
88.27 cm^2
Step-by-step explanation:
Cherry=4(3.14)(1.5)^2
=28.27
Cookie=2·(5·5+0.5·5+0.5·5)
=60
60+28.27=88.27
Suppose you find that the correlation coefficient for a set of data is 0.826. What is the coefficient of determination and what does it mean?
Answer:
[tex]r^2 = 0.826^ 2 =.6822[/tex]
[tex]r^2 =[/tex] a measure of how strong the ("how fit") the relationship is
it is always positive between 0 and 1
Step-by-step explanation:
coefficient of determination = r^2
r^2 = 0.826^ 2 =.6822
At a point 25 ft. from the base of a totem pole, the angle of elevation of the top of the pole is 50.1 °. How tall is the totem pole to the nearest foot?
Answer:
height ≈ 30 ft
Step-by-step explanation:
The situation is modelled by a right triangle.
let h be the height of the totem pole, then
tan50.1° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{h}{25}[/tex] ( multiply both sides by 25 )
25 × tan50.1° = h , then
h ≈ 30 ft ( to the nearest foot )
Will give brainliest!!!
2.6(5.5p – 12.4) = 127.92
p=
Answer:
[tex]p=11.2[/tex]
Step-by-step explanation:
Given [tex]2.6(5.5p-12.4)=127.92[/tex], distribute to remove the parentheses:
[tex]2.6\cdot 5.5p-2.6\cdot 12.4=127.92[/tex]
Simplify:
[tex]14.3p-32.24=127.92[/tex]
Add 32.24 to both sides:
[tex]14.3p=160.16[/tex]
Divide both sides by 14.3:
[tex]p=\frac{160.16}{14.3}=\boxed{11.2}[/tex]
help me solve the simultaneous linear inequalities
Answer:
The inequality form is -4<x<-2
The Interval Notation is (-4, -2]
I hope this helps!
x^3 - 3mx^2 + 3(2m - 1)+1
Answer:
21e
jjjjjjjoiooooooooooooooooooooimm
PLZ HELP its due soon!!!
Answer:
E)
Step-by-step explanation:
1) 6.50 (starting with his current wage)
2) 6.50 + 0.25 = 6.75 $
3) 6.75 + 0.25 = 7.00 $
4) 7.00 + 0.25 = 7.25 $
5) 7.25 + 0.25 = 7.50 $
6) 7.50 + 0.25 = 7.75 $
Tickets to a football final are selling well. On Thursday, 47 of the tickets are sold. On Friday, 14 of the tickets are sold. What fraction of tickets are available to sell on Saturday?
The question seems incomplete ; as the total number of tickets to be sold isn't given.
Answer:
61 / X
Step-by-step explanation:
Let's take the total Number of tickets to be sold as : X
Number of tickets sold on Thursday = 47
Number sold on Friday = 14
Fraction of tickets available for sale on Saturday :
(Total number of tickets already sold) / Total number of tickets to be sold
(Thursday + Friday sales) / total number of tickets to be sold
Fraction available for sale on Saturday = (47+14) / X
Fraction available for sale on Saturday = 61 / X
Kindly put value of x = total number of tickets available for sale to get the exact fraction.
PLZ I NEED ANSWER ILL GIVE BRAINLIEST
Answer:
c
Step-by-step explanation:
got it right
Answer:
y = 4x - 3
Step-by-step explanation:
y2 - y1 / x2 - x1
5 - (-3) / 2 - 0
8 / 2
= 4
y = 4x + b
5 = 4(2) + b
5 = 8 + b
-3 = b
solve the simultaneous equation: x-y=2
xy=36
Answer:
Y= –7.08, 5.08
Step-by-step explanation:
hope ya ready bro.
X=36/Y
replace 36/y instead of X
36/Y–Y=2===> 36–Y²=2Y===> Y²+2Y–36=0
Y1= –1+√37≈ –7.08
Y2= –1–√37≈ 5.08
on a coordinate gride what is the distance between (1,3) and (6,15)
Answer:
13
Step-by-step explanation:
Distance between points (1, 3) and (6, 15) is 13
Do anyone know this
Make sure is the correct answer please
9514 1404 393
Answer:
(a) P = 44 cm + 18 cm + 18 cm = 80 cm
(b) 396 cm²
(c) (i) see attached: radius = 7 cm; height ≈ 16.58 cm; slant height = 18 cm
(c) (ii) 7 cm
Step-by-step explanation:
(a) The length of arc PQR is given by the formula ...
s = rθ . . . . . where r is the radius and θ is the angle in radians
The angle θ in radians is (140°)(π/180°) = (140)(22/7)/(180) = 22/9
So, the arc length is ...
PQR = (18 cm)(22/9) = 44 cm
Then the perimeter of the figure is ...
P = PQR +RO +OP = 44 cm + 18 cm + 18 cm
P = 80 cm
__
(b) The area of a sector is given by ...
A = 1/2r²θ = 1/2(rs)
A = (1/2)(18 cm)(44 cm) = 396 cm² . . . area of the sector
__
(c) (i) A drawing of the cone is attached. The "slant height" is 18 cm. The radius is found in part (ii) as 7 cm. The height is given by the Pythagorean theorem:
height = √((slant height)² - radius²) = √(18² -7²) = √275
height ≈ 16.58 . . . cm
(ii) The length of arc PQR is the circumference of the base of the cone, given by ...
C = 2πr . . . . where r is the radius of the base of the cone
Filling in the known values, we find ...
44 cm = 2(22/7)r
(44 cm)(7/44) = r = 7 cm . . . . . multiply by 7/44 to find r
The radius of the base of the cone is 7 cm.
Which equation is a radical equation? 4p =√-3 + p x√3 + x =^3√2x 7√11– w = –34 5 – ^3√8= v√16
Answer:
See explanation
Step-by-step explanation:
The given options are not properly formatted; so, I will give a general explanation instead
An equation is said to be radical if its variable is in a radicand sign.
For instance, the following equation is a radical;
[tex]\sqrt x + 2 = 4[/tex]
In the above equation, x is the variable, and it is in [tex]\sqrt[/tex] sign
However, the following equation is not a radical equation
[tex]x + \sqrt 4 = 2[/tex]
Because the variable is not in a radicand
a solid cylinder has radius x cm and height (7x÷2) cm .the surface area of a sphere with radius R cm is equal yo the total surface area of the cylinder . find an expression for R in terms of x
Answer:
[tex]R=(\sqrt{11} )\frac{x}{2}[/tex]
Step-by-step explanation:
The expression for the radius of the sphere will be R = (3/2)x.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Given that a solid cylinder has a radius x cm and height (7x÷2) cm .the surface area of a sphere with a radius R cm is equal to the total surface area of the cylinder.
The expression will be solved as:-
SA ( sphere) = 4πR²
SA (cyl) = 2πr² + 2πrl
SA (cyl) = 2πx² + 2πx ( 7x / 2)
SA (cyl) = 2πx² + 7πx²
SA ( sphere) = SA (cyl)
4πR² = 2πx² + 7πx²
R² = 9πx² / 4π
R = √(9x²/4)
R = ( 3 / 2 )x
Therefore, the expression for the radius of the sphere will be R = (3/2)x.
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This frequency table represents the number of cars owned by each family on a street.
What is the mean number of the cars owned by each family?
A. 2.5
B. 3
C. 4
D. 5.5
Step-by-step explanation:
1+2+3+4+5=14 divided by 5=2.8 so, A.would be your answer.
pls pls pls answer and pls dont use this post just for extra points i actually rly need help
:( please don't
Answer:
1/2
Step-by-step explanation:
Probability is equal to the amount of desirable outcomes divided by the total amount of outcomes. Each coin has two sides, and there are three of them. This accounts for a total of 2^3 or 8 outcomes. Now, we need to find the amount of outcomes where two or more coins land on heads. We can start by listing those possibilities: THH, HTH, HHT, and HHH. Notice that the first three are just three ways of rearranging the same result. We can see that there are four desirable outcomes. This means the probability is 1/2.
Each side of a square office is 3 meters long. It will cost $44.14 per square meter to replace
the carpet in the office. What would be the total cost to replace the carpet?
Answer:
3*3*44.14$
That's the answer
Use a calculator
I dont understand what to do here, can somebody help, please? 4.2 / 6 = ____ tenths / 6 4.2 / 6 ____ tenths
Answer:
sei lá, pergunta pra tua mãe
Which of the following options results in a graph that shows exponential growth? (2 points)
f(x) = 0.4(3)x
f(x) = 3(0.5)x
f(x) = 0.8(0.9)x
f(x) = 0.9(5)−x
Answer:
Step-by-step explanation:
The formula for exponential equations is
[tex]y=a(b)^x[/tex] where a is the initial value and b is the growth rate. If b is greater than 1, we have growth; if 0 < b < 1, then we have decay. The only choice that shows a b value greater than 1 is the first one where b = 3. (The last one is also a decay as it can be written as
[tex]f(x)=0.9(\frac{1}{5x})[/tex] which isn't even exponential!)
Rewrite the following polynomial in standard form.
9x + 1 - x^2
Answer:
x²-9x-1
Step-by-step explanation:
move the -x² in front and get -x²+9x+1
then multiply the whole equation by -1 and get x²-9x-1
I THINK OKAY PLEASE DONE BE MAD
We can use SOH-CAH-TOA for
A. Any triangle ever
B. Non-right triangle only
C. right triangle only
D. Never
Answer:
C. right triangle only
Step-by-step explanation:
Other triangles use other laws such as law of cosines or sines to solve them. Right triangles exclusively use SOH-CAH-TOA because side opposite to 90 degree is always hypotenuse.
A certain medical test is known to detect 59% of the people who are afflicted with the disease Y. If 10 people with the disease are administered the test, what is the probability that the test will show that:
Answer:
[tex]P(x = 3) = 0.048[/tex]
Step-by-step explanation:
Given
[tex]n = 10[/tex]
[tex]p=59\% = 0.59[/tex]
Required
[tex]P(x = 3)[/tex] --- probability that 3 are afflicted
This question illustrates binomial probability and it is calcuated using:
[tex]P(x) = ^nC_x * p^x * (1 - p)^{n-x}[/tex]
So, we have:
[tex]P(x = 3) = ^{10}C_3 * 0.59^3 * (1 - 0.59)^{10-3}[/tex]
[tex]P(x = 3) = ^{10}C_3 * 0.59^3 * 0.41^7[/tex]
[tex]P(x = 3) = 120 * 0.59^3 * 0.41^7[/tex]
[tex]P(x = 3) = 0.048[/tex]
Find the sum -2/3+0 Pls answer right
Answer:
[tex] - 1[/tex]
-1 is the answer in your questions
Answer:
[tex] - \frac{2}{3} [/tex]
Step-by-step explanation:
[tex] \frac{ - 2}{3} + 0[/tex]
when adding or subtracting by 0, the value does not change.
[tex] = \frac{ - 2}{3} = - \frac{2}{3} [/tex]
Indicate in standard form the equation of the line passing through the given points, writing the answer in the equation box below.
G(4, 6), H(1, 5)
Answer:
x-3y=-14
Step-by-step explanation:
Slope = (5-6)/(1-4) = -1/-3 = 1/3
y-intercept is,
b=6-1/3×4 = 14/3
so the equation is,
y=x/3+14/3
or, 3y=x+14
or, x-3y=-14
Answered by GAUTHMATH
Standard form the equation of the line passing through the given points is x-3y=-14
What is equation?Statement of equality between two expressions consisting of variables and/or numbers
Given points are: G(4, 6), H(1, 5)
Now,
Slope = (5-6)/(1-4)
= -1/-3
= 1/3
and y-intercept is,
b=6-1/3×4
b = 14/3
Hence, the equation is,
y=x/3+14/3
or, 3y=x+14
or, x-3y=-14
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Assistance pleaseeees?!!
Answer:
Step-by-step explanation:
Which expression is equivalent to 8-(6r+2) HELP SMB PLEASE!
Answer:
A.
Step-by-step explanation:
A.-6r+6
A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the pitcher's hand at a velocity of 50 feet per second. If the softball's acceleration is –16 ft/s2, which quadratic equation models the situation correctly?
Answer:
The function is:
[tex]f(t) = -16t^2 + 50t + 3[/tex]
Step-by-step explanation:
Given
[tex]height = 3ft[/tex]
[tex]velocity = 50ft/s[/tex]
[tex]acceleration = -16ft/s^2[/tex]
Required
The function
Let t represents time;
So, we have:
[tex]f(t) = acceleration * t^2 + velocity * t + height[/tex]
So, we have:
[tex]f(t) = -16* t^2 + 50* t + 3[/tex]
[tex]f(t) = -16t^2 + 50t + 3[/tex]
Answer:
b on edge
Step-by-step explanation:
Which set of rational numbers is arranged from least to greatest? 1 over 5, −1.4, negative 1 over 2, 3
Answer:
[tex]-1.4, -\frac{1}{2}, \frac{1}{5}, 3[/tex]
Step-by-step explanation:
Given
[tex]\frac{1}{5}, -1.4, -\frac{1}{2}, 3[/tex]
Required
Order from least to greatest
We have:
[tex]\frac{1}{5}, -1.4, -\frac{1}{2}, 3[/tex]
Convert all fractions to decimal
[tex]0.2, -1.4, -0.5, 3[/tex]
Now order from least to greatest
[tex]-1.4, -0.5, 0.2, 3[/tex]
Replace fractions
[tex]-1.4, -\frac{1}{2}, \frac{1}{5}, 3[/tex]
Pier is a teacher
There are 13 boys and 17 girls in the class
Pier chooses one student at random
Workout the probability the student is a boy
Answer:
I think its 43%
Explanation
math
The probability of Pier choosing a boy is 0.43 or 43%.
What is probability?It is the chance of an event to occur from a total number of outcomes.
The formula for probability is given as:
Probability = Number of required events / Total number of outcomes.
Example:
The probability of getting a head in tossing a coin.
P(H) = 1/2
We have,
The total number of students in the class is:
13 boys + 17 girls
= 30 students
The probability of Pier choosing a boy is the number of boys in the class divided by the total number of students:
Probability of choosing a boy.
= number of boys / total number of students
Probability of choosing a boy.
= 13 / 30
Probability of choosing a boy.
= 0.4333 or approximately 0.43
Therefore,
The probability of Pier choosing a boy is 0.43 or 43%.
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