The correct answer is (A & D).
In the case of total internal reflection: Total internal reflection occurs when the light travels from a denser medium to a rarer medium. And refraction does not occur at the critical angle
Thus the need for total internal reflection when the ray travels from medium B to medium A.
nB > nA
Thus the need for total internal reflection when the ray travels from medium A to medium
B.
nA > nB
Both the conditions can not be satisfied simultaneously so, the initial light travels from medium A to medium B therefore options C and B are incorrect in the given options.
Hence, the correct option is A and D respectively.
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Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelength of d/ 15. The lasers produce separate interference patterns on a screen a distance 4.40 m away from the slits. Part What is the distance Aymamin between the second maximum of laser 1 and the third minimum of laser 2 on the same side of the central maximum? Express your answer in meters. View Available Hint(s) Ay mas ma 5867 k m Submit Previous Answers x incorrect: Try Again; 3 attempts remaining
the distance Aymamin between the second maximum of laser 1 and the third minimum of laser 2 on the same side of the central maximum is 0.4 m
For part be we can use the equation
ym = m*λ*L/d
so for the first max for each one m =1
so for laser 1
y = (d/20)*(6.0m)/d
y = 6.0m /20 = 0.3
for laser 2 we do the same thing
y = 6.0m/15 = 0.4
y ( laser1 ) < y ( laser2 )
(1) hence first maxima of laser1 is closest to central maxima
Δy = 0.4m -0 .3 m = 0.1m
For part C)
we use the same equation to find the y for laser 1, except m =2
y= 2*6.0 m / 20 = 0.6 m
Now for laser 2 we use:
ym=(m+1/2)*λ*L/d
since there is no central minimum the first minimum is at m = 0.that means that the third minimum is at m = 2
simplifying the equation we get
y = (2.5)*6.0 / 15 = 1m
now we solve
Δy= 1m - 0.6m = 0.4 m
Double Slit Experiment:
The double-slit experiment shows that light and matter can exhibit properties of both classically defined waves and particles. Furthermore, it demonstrates the fundamental stochastic nature of quantum mechanical phenomena.
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why is the signal preferred over analogue signal for telecommunication?
The communication systems used analog signaling (telephones) are used but as the technologies use digital signals because of some advantages.
What is telecommunications?The term telecommunication refers to the transmission and exchange of information from one place to another. Telecommunication is beneficial for saving time, energy, and money. Nowadays, the companies are mainly used in telecommunication.
Telecommunications are mainly based on signals. Telecommunication is a type of electronic transaction that uses telephone, radio, data, image, optical, and electromagnetic waves. The electromagnetic spectrum means the frequency and wavelength of radiation. Signal which are continuous as time varies are analog signals.
Thus, examples of analog signals are Human voice, Thermometer, Analog phones etc. The advantage of digital technology are noise immunity, encryption, bandwidth efficiency, and the ability to use repeaters for long-distance transmission.
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Which section shows the greatest rate of positive acceleration?
The rate at which an object changes its velocity is known as acceleration, a vector quantity.
What kind of positive acceleration is the greatest?When the rate of change of velocity in an increasing sense (the slope of the velocity-time curve) is at its highest positive value, acceleration will be at its maximum positive value.The rate of change in velocity is greater for the graph with the sharpest slope. That thing is moving with the most velocity.The velocity-time graph displays a line with an upward slope, indicating a positive acceleration; the line is situated in the graph's positive area (corresponding to a positive velocity).When the car accelerates positively, its speed rises. As the car slows down, its speed decreases.When an object accelerates in the same direction as its velocity, it is doing so in that same direction. This object is therefore moving at a positive rate.To learn more about greatest rate of positive acceleration refer to:
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Your consulting firm is asked to design an activated carbon adsorption system to treat contaminated groundwater containing 10 mg/L of benzene with a treatment goal of 99% reduction in benzene concentration before injection into groundwater. The extraction well pumps groundwater at 100 gpm. The activated carbon removal capacity is expressed as the following Freundlich equation: 9 (mg/kg) = 0.2 CO.2, where Cis concentration (mg/L) of benzene after adsorption equilibrium. (a) What is the amount of activated carbon (kg) needed per day? (b) If the packing density of activated carbon is 1.2 g/L, how many 55-gallon tank it would fill? Approximate to nearest number exceeding the amount of activated carbon required.
the daily need for activated carbon in kg is 4319.327 kg of carbon. It would fill a 55-gallon tank, which is 18.
groundwater containing 10 mg/L of benzene
treatment goal of 99%
Flow rate of ground water =100 Gpm
=378.541 Liter/min
now weight of benzene in water
=378.541 Liter/min*10 mg/lit
= 3.78541 gram/min
now per day weight of benzene
=3.78541 g/min*(24*60)min=5450.9904 gram
now frewndlich equation derives
q(mg/g)=2 c[tex]^{0.2}[/tex]
c=0.01*10=0.1 mg/L
q=2*[tex](0.1)^{0.2}[/tex] = 1.262
q=1.262 (mg/g)
it means 1.262 mg of benzene adsorps on one gram of activated carbon
a)now per day mass=5450.9904*10³ mg
1.262 mg needs 1g of carbon
1mg needs 1/1.262 g of carbon
5450.9904*10³ mg needs
((1/1.262)*5450.9904*10³ ) grams
=4319.327 Kg of carbon /day
b) packing density of activated carbon = 1.2 g/L
tank size =55 gallon
now 1.2g fills in 1 lit
1g fills in (1/1.2)litre
4319.327*10³ g fills in(1/1.2)*4319.327*10³ liter
=3600 liter volume needed
1 tank volume =55gallon
=208.2 lit
number of tanks needed =3600 liter/208.2
=17.29≅18 tanks
∴18 such tanks are needed
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a 1.90 kg , horizontal, uniform tray is attached to a vertical ideal spring of force constant 200 n/m and a 300 g metal ball is in the tray. the spring is below the tray, so it can oscillate up-and-down. the tray is then pushed down 16.4 cm below its equilibrium point (call this point a) and released from rest.
(a) How high above point A will the tray be when the metal ball leaves the tray?
(b) How much time elapses between releasing the system at point A and the ball leaving the tray?
(c) How fast is the ball moving just as it leaves the tray?
a)When the metal ball leaves the tray, the tray will be 10.78 cm above point A.
b) The total time between the system being released at point A and the ball leaving the tray is 0.086 seconds.
c) The speed of the ball as it exits the tray is 1.175 m/s.
Given,
Mass of tray , m_t=1.90 kg
spring of force constant, k = 200N/m
mass of the ball, m_b = 300 g
Height below the equilibrium point A = 16.4 cm
a)
The tray's height above point A when the metal ball leaves it- The total mass of the tray and ball is 2.2 kg (1.90kg+0.3 kg). The spring force is equal to the product of the spring constant and displacement.Thus,
f=kx
but we know that, f=mg
equating both the equations
[tex]mg=kx\\\\2.2*9.8=200*x\\\\21.56=200x\\\\x=\frac{21.56}{200}\\\\x=0.1078 m=10.78 cm[/tex]
As a result, the tray is pushed down 17.4 cm below its equilibrium point (point A) and released from rest. Thus, the tray's position above point A is h=16.4+10.78=27.18 cm.
b)
The total amount of time that passes between releasing the system at point A and the ball leaving the tray.
The formula for the simple harmonic function of a spring is as follows:
[tex]y=Acos(\sqrt{\frac{k}{m}}-\phi)[/tex]
Here,
y= displacement = 10.78 cm
A=amplitude i.e 16.4 cm
k= spring constant = 200 N/m
m= total mass = 2.2 kg
and [tex]\phi = 0 \degree[/tex]
[tex]10.78=16.4cos(\sqrt{\frac{200}{2.2}}t-0)\\\\\frac{10.78}{16.4}=cos(\sqrt{90.909}t)\\\\0.657=cos(9.534t)\\\\cos^{-1}(0.657)=9.5434t\\\\0.829=9.543 t\\t=\frac{0.829}{9.543}\\\\t=0.086 s[/tex]
c)
The speed at which the ball moves as it exits the tray
The total mechanical energy for simple harmonic motion of a spring can be given as,Here, take the distance measurements in meters
[tex]\frac{1}{2}mv_y^2+\frac{1}{2}ky^2=\frac{1}{2}kA^2\\\\v_y^2=k\frac{A^2-y^2}{m}\\\\v_y^2=200*\frac{0.164^2-0.1078^2}{2.2}\\\\v_y^2=90.909(0.0268-0.0116)\\\\v_y^2=1.38\\\\v_y=1.175 m/s[/tex]
Thus, the speed of ball is 1.175 m/s
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7. The vectors d &e are [- 4, 1] \&[1,4] respectively. Find the angle b/n d&e( use dot product)
Answer:
90° or π/2 rad
Explanation:
Given two vectors:
[tex] \displaystyle{ \vec d = - 4 \hat i + \hat j} \ \: \text{and} \ \: \displaystyle{ \vec e = \hat i + 4 \hat j}[/tex]
We can find the angle by applying dot product:
[tex] \displaystyle{ \vec d \cdot \vec e = | \vec d| | \vec e| \cos \theta}[/tex]
Find magnitude of two vectors:
[tex] \displaystyle{ | \vec d| = \sqrt{ {( - 4)}^{2} + {1}^{2} }} \\ \\ \displaystyle{ | \vec d | = \sqrt{16 + 1} = \sqrt{17} }[/tex]
And
[tex] \displaystyle{ | \vec e| = \sqrt{ 1^{2} + {4}^{2} }} \\ \\ \displaystyle{ | \vec e | = \sqrt{1 + 16} = \sqrt{17} }[/tex]
Thus, we now have:
[tex] \displaystyle{ \vec d \cdot \vec e = \sqrt{17} \cdot \sqrt{17} \cos \theta} \\ \\ \displaystyle{ \vec d \cdot \vec e = 17 \cos \theta}[/tex]
Product of two vectors are:
[tex] \displaystyle{ \vec d \cdot \vec e = d_xe_x + d_ye_y}[/tex]
Therefore:
[tex] \displaystyle{( - 4)(1) + (1)(4) = 17 \cos \theta} \\ \\ \displaystyle{ - 4 +4= 17 \cos \theta} \\ \\ \displaystyle{0= 17 \cos \theta} \\ \\ \displaystyle{0 =\cos \theta}[/tex]
Therefore, the angle would be 90° or π/2 since we know that cos90° = 0.
A hopper jumps straight up to a height of 1.3 m. With what velocity did he leave the floor
The velocity with which the jumper leaves the floor is 5.1 m/s.
What is the initial velocity of the jumper?
The initial velocity of the jumper or the velocity with which the jumper leaves the floor is calculated by applying the principle of conservation of energy as shown below.
Kinetic energy of the jumper at the floor = Potential energy of the jumper at the maximum height
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
v is the initial velocity of the jumper on the floorh is the maximum height reached by the jumperg is acceleration due to gravityv = √(2 x 9.8 x 1.3)
v = 5.1 m/s
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question: how do we measure the rate of radioactive decay? observe: select the bar chart on the right side of the gizmo and click play. what happens to the numbers of radioactive and daughter atoms as the simulation proceeds? do the numbers of radioactive and daughter atoms change at the same rate throughout the simulation? explain. interpret: how does the half-life setting affect how quickly the simulated substance decays? (activity a continued on next page)
The quantity of radioactivity is stated in Becquerel (Bq), that's the worldwide unit, or the Curie (Ci), that's the unit used withinside the United States.
Geiger counters are generally used to degree the quantity of radioactivity, however there are different forms of detectors that can be used.
The decay fee is expressed as a percentage. We convert it to a decimal through really lowering the percentage and dividing it through 100. Then calculate the decay aspect b = 1-r. For instance, if the fee of degradation is 25%, the exponential function's decay fee is 0.25 and the decay aspect b = 1- 0.25 = 0.75.
Atoms of a determine radioactive isotope randomly decay right into a daughter isotope. Over time the range of determine atoms decreases and the range of daughter atoms increases. Rutherford and Soddy (1902) observed that the fee of degradation of a radioactive isotope relies upon on the quantity of the determine isotope remaining.
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astronomers observe galaxies and categorize them according to four different kinds of shapes: elliptical, spiral, barred-spiral, and irregular. in addition to shape, each of the four different galaxy types can be described by other common characteristics. match the following characteristics with their corresponding galaxy type.
Matching of the characteristics with their corresponding galaxy type is as follows.
Elliptical galaxy (E): Round, no disk, very little gas and dust, only old stars.
Spiral galaxy (S): Central bulge, flattened disk, spiral arms, gas, dust, young stars.
Barred-spiral galaxy (SB): Elongated central structure, flattened disk, spiral arms, gas and dust, young stars.
Irregular galaxy (Irr): Asymmetric, often with gas, dust, and young stars.
Galaxies are huge collections of gas, dust, and stars. Gravity and dark matter shape and held them together. Scientists have segmented galaxies into 4 main types. These are of spiral, elliptical, peculiar, and irregular shape.
In the given question two columns of matching are not given. The rest part of the question is
Drag the appropriate items to their respective bins.
-Round, no disk, very little gas and dust, only old stars.
-Central bulge, flattened disk, spiral arms, gas, dust, young stars.
-Elongated central structure, flattened disk, spiral arms, gas and dust, young stars.
-Asymmetric, often with gas, dust, and young stars.
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Constants A film contains a single thin slit of width a. When monochromatic light passes through this slit, the first two dark fringes on either side of the center on a distant screen are a distance x apart. Part A If you increase the width of the slit, these two dark fringes will move closer together. move farther apart. remain the same distance apart.
These two dark fringes will travel in closer proximity if the slit's width is increased for a Constants A film has just one a-width tiny slit. When this slit is open, monochromatic light enters.
The relationship between the slit width and the distance from the centre maximum to y is (m*(lamda)*D/a, where D is the separation between the slit and the screen and lamda is the wavelength of light, meaning that y is inversely proportional to 1/a. Therefore, monochromatic light is simply light of a single colour. It denotes light that has only one wavelength in scientific terminology. The term "light" refers to the visible and near-visible components of electromagnetic radiation. It is made up of propagating, perpendicularly oscillating sinusoidal waves in the magnetic and electric fields.
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A cannon is mounted on a cart and carrying a cannonball. The total mass of the cart, cannon, and ball is M, and the cart is rolling with no friction at a velocity v in the positive x-direction as shown in the figure. The ball, of mass m, is fired with a velocity of Vball in the positive x-direction. What is the velocity of the cart (with cannon) after the ball is fired?
The velocity of the cart (with cannon) after the ball is fired is u₂ = Mv - mVb / ( M - m(ball) ).
option A is the correct answer.
What is the law of conservation of linear momentum?The law of conservation of linear momentum states that the sum of the initial momentum is equal to sum of the final momentum, provided that the system is Isolated.
Mathematically, the law of conservation of linear momentum is given as;
Pi = Pf
where;
Pi is the sum of the initial momentumPf is the sum of the final momentumm₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is the mass cannon ballu₁ is the final velocity of the cannon ballm₂ is the mass of the cartu₂ is the final velocity of the cartv is the initial velocity of the cannoncart-systemMass of the cannon ball + cart = M
mass of the cart only, m₂ = M - m(ball)
The final velocity of the cart is calculated as follows;
mVb + m₂u₂ = Mv
m₂u₂ = Mv - mVb
u₂ = Mv - mVb / m₂
u₂ = ( Mv - mVb ) / ( M - m(ball) )
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Assignment 6.3: PRESSURE IN WATER PIPE
Water is flowing smoothly through a closed pipe system. At one point the speed of
water is 3 ms, while at another point 3 m higher, the speed is 4 ms. At lower
point the pressure is 80 kPa. Find the pressure at the upper point.
The pressure of water at the upper point of the closed pipe system is 47,100 Pa.
What is the pressure of water at the upper point?
The pressure of water at the upper point is calculated by applying Bernoulli's equation as shown below;
P₂ = (P₁ + ¹/₂ρv₁² + ρgh₁) - ( ¹/₂ρv₂² + ρgh₂)
where;
P₁ is the pressure at the lower point = 80 kPa = 80,000 Pav₁ is the velocity at the lower point = 3 m/sh₁ is the height at the lower point = 0 mv₂ is the velocity at upper point = 4 m/sh₂ is height at the upper point = 3 m ρ is density of water = 1,000 kg/m³P₂ = (P₁ + ¹/₂ρv₁² + ρg(0)) - ( ¹/₂ρv₂² + ρgh₂)
P₂ = (P₁ + ¹/₂ρv₁²) - ( ¹/₂ρv₂² + ρgh₂)
The pressure of water at the upper point of the closed pipe system is calculated as follows;
P₂ = ( 80,000 + ¹/₂(1000)(3)² ) - ( ¹/₂(1000)(4)² + (1000 x 9.8 x 3) )
P₂ = 84,500 - 37,400
P₂ = 47,100 Pa
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A stick of length 2L and negligible mass has a point mass m affixed to each end. The stick is arranged so that it pivots in a horizontal plane about a frictionless vertical axis through its center. A spring of force constant k is connected to one of the masses. The system is in equilibrium when the spring and stick are perpendicular. The stick is displaced through a small angle theta. a) Determine the restoring torque when the stick is displaced from equilibrium through the small angle theta b) Determine the magnitude of the angular acceleration of the stick just after it has been released c) Write the differential equation whose solution gives the behavior of the system after it has been released d) Write the expression for the angular displacement theta of the stick as a function of time t after it has been released from rest
Answers:
a. τ = FLcos\Theta = FL = -kL2\Theta
b. a = -ke/2m
n
c. d2\Theta/dt2 = -k\Theta /2m
d. \Theta=\Theta0 cos (k/2m)1/2t
Please explain all the steps in arriving at the answers.
A stick of length 2L and negligible mass has a point mass m affixed to each end. The stick is arranged so that it pivots in a horizontal plane about a friction less vertical axis through its center, thus calculated values are:
(A) Torque (τ) = F × L cosθ
(B) α = - Kθ/2m
(C) d²θ/dt² = -Kθ/2m
(D) θ = cos ⁻¹ ( kθ t/2Lm)
What is torque?The term "torque" refers to the twisting force that an engine exerts as it works, and it expresses the rotating force. Everyday activities like turning a doorknob, opening a drink bottle, using a tool, or peddling a bicycle all involve torque.
(A)
General equation of torque (τ) will be product of force and perpendicular distance.
τ = F × (perpendicular distance)
In this case, restoring torque. Hence, force F we taken as restoring force, and the perpendicular distance x-axis is component of L.
or, τ = F × [tex]L_{x-axis}[/tex]
or, τ = F × L cosθ
(B)
Angular acceleration general equation is:
α = Δω/Δt
here, Δω = change in angular velocity.
Δt = change in time
As we know, acceleration = force/mass
now, angular acceleration = angular force / mass of body
so, α = - Kθ/2m
(C)
f(t) = α × (t²/2)
or, f(t) = - Kθ/2m × (t²/2)
or, f(t) = - Kθ t² / 4m
now differentiating with respect to t:
or, dθ/dt = -Kθ t/2m
differentiating again with respect to t:
d²θ/dt² = -Kθ/2m
(D)
The expression for angular displacement:
cos θ = adjacent side / opposite side
or, cos θ = adjacent side / 2L
or, θ = cos ⁻¹ ( kθ t/2Lm)
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A water tank is 1/8 full. the tank is 3/4 full when 42 gallons of water are added to the tank. how much water can the tank hold?
The tank can hold a water of volume 67.2gallons
What is volume?Volume is defined as the space occupied within the boundaries of an object in three-dimensional space. It is also known as the capacity of the object.
The capacity of an object can be measured in litres, gallon , cm³ e.t.c.
The tank is 1/8 full, when 42 gallons of water is added it is 3/4 full.
Therefore the fraction of water added is 3/4-1/8= 5/8.
This means 5/8 of the tank is 42 gallons. Therefore if 5/8 of the tank = 42gallons,
full tank will be 42× 8/5
= 67.2 gallons
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Part A
Consider the situation in the figure below, where two charged rods are placed a distance d on either side of an aluminum can. What does the can do?
View Available Hint(s)
Rolls to the left
Stays still
Rolls to the right
Part B
Now, consider the situation shown in the figure below. What does the can do?
Stays still
Rolls to the left
Rolls to the right
Part C
Using the setup trom the first question, imagine that you brielly touch the negatively charged rod to the can. You then hoid the two rods at equal distances or either side of the can. What does the can do?
View Avallable Hint(s)
Rolls toward the positively charged rod
Does not move
Rolls away from the positively charged rod
a) The can stays still
b) The can stays still
c) The can moves towards the positive rod
What is electrostatic force?We know that the electrostatic force is the force that attracts an object is the force that induces a charge on an object even though the objects do not touch each other. In all the cases that are shown in the images there is no contact between the charged bodies and the can.
In all the cases, we see that immediately the charged object is brought around the can, the object would cause the the electrons that are in the can to become polarized. It is the polarization of the electrons that are in the can that would make the can to move.
The movement of the can would be with reference to the kind of charges that are on the surrounding rods as well as the charges that are on the rods that have been brought around the can.
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two identical, thin rods, each with mass mm and length ll, are joined at right angles to form an l-shaped object. this object is balanced on top of a sharp edge (figure 1). if the l-shaped object is deflected slightly, it oscillates.
The length of time that an action or state persists. The given L-shaped object made of two rods oscillates at a frequency of 2π√√2L/3g.
The rod weighs m grams.
The length of a single rod is L.
If it is connecting at, as indicated by the query, then the moment of inertia of the combined system follows.
mL²/3+3L²/3=2mL²/3
Here, I denotes the rod's moment of inertia, d denotes the separation of the center of gravity from the fixed point, and T denotes the length of time the L-shaped object oscillates.
Length of pendulam
Lcos45=L*1/√2=L/√2
Caluclate the time period
T=2π√I/mgl
=2π√2*mL²*√2/3*2mgl
oscillates at a frequency = 2π√√2L/3g
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When force is applied for some distance What is that called?; When a force acting on an object moves it across a distance is called?; What is the transfer of energy that occurs when a force makes an object move?; What is the transfer of energy accomplished by a force moving a mass some distance against resistance?
When force is applied for some distance, it is called work done, and When force acting on an object moves it across a distance is called work done.
When moving an object over a distance, an external force must direct at least a portion of its force in the direction of the displacement. This is referred to as work done in physics. If the force acting along the path is constant, work can be calculated by multiplying the length of the path by the force's component. The work W is mathematically defined as the product of the force f and the distance h, or W = mgh. The work is W = mas if the force is applied at an angle to the displacement.
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A computerized spin balance machine rotates a 25-inch-diameter tire at 430 revolutions per minute.
(a) Find the road speed (in miles per hour) at which the tire is being balanced. (Round your answer to two decimal places.)
Diameter D = 25 inch
Radius r= D/2 = 25/2 = 12.5 inch
"1 ft = 12 inch and 1 mile = 5280 feet". R = 12.5×(1/12)×(1/5280) mile
Revolution n =430 rev./minute , n=430 × 60 rev./hour
Angular speed=2 × pi × n =2 × pi × n radian per hour =2 × pi × 430 × 60
a) Road speed = r × angular speed
Road speed = 12.5 × (1/12) × (1/5280) × (2 × pi × 430 × 60)
Road speed = 31.98 miles per hour
What is a revolution?
A revolution is a radical transfer in the founded order, often the founded government and social institutions.
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a projectile is fired at an angle of 55 above the horizontal and has a maximum up[ward vertical diusplacement
A projectile being fired at 55 degrees after the magnitude of the horizontal component of the projectile's displacement is 40.2m
Initial velocity of projectile (v) = 35 m/s
Given Angle (θ)= 55°
Estimating, horizontal components of velocity
[tex]v_{x}[/tex] = v cosθ
= 35 cos 55°
= 20.1 m/s
Calculating the horizontal components of displacement after t = 2
d₂ = [tex]v_{x}t[/tex]
= 20.1 x 2
= 40.2 m
Projectile motion refers to the motion of an object or particle that is launched into a gravitational field, such as from the surface of the Earth, and travels along a curved path while only being influenced by gravity. An object that is fired into the air and only reacts to the acceleration of gravity is called a projectile.
The projectile's path is the name for the object's trajectory. A projectile is any object that is sent into space with only gravity acting on it. The primary force affecting a projectile is gravity. This doesn't mean that other forces don't have an impact; it just means that they have a much smaller one compared to gravity.
Note that the full question is:
A projectile is fired at an angle of 55° above the horizontal with an initial speed of 35.0 m/s. What is the magnitude of the horizontal component of the projectile's displacement at the end of 2 s?
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Where does water vapor come from when you exhale?; When you exhale outside on a cold winter day the water vapor in your breath cools and changes into tiny water droplets?; When you breathe into a cold window and water droplets appear it is an example of blank?; When we breathe on a cold windowpane we find dust or drops of water?
At the dew point, air can no longer absorb water vapor. When air cools above its dew point, water vapor becomes a liquid. This is a physical process known as condensation.
While you breathe out (exhale), your lungs put carbon dioxide again into the air. but, the breath you exhale doesn't only contain carbon dioxide. It additionally includes moisture from your mouth and lungs. This moisture is inside the form of water vapor, the gasoline shape of water.
While you exhale on a chilly day, the air that goes out is saturated and the temperature of the air you exhale is warmer than the encompassing air.
The water vapor to your breath condenses into many tiny droplets of liquid water and ice that you could see within the air as a cloud. It seems pretty similar to fog.
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What is the bouncing back of a ray of light sound or heat when the ray hits a surface that it does not go through?; Is the bouncing back of a light ray from a surface?; What is the bouncing back of the wave as it hits a surface?; What is the bouncing back of light when it hits?
When something bounces off a wall or other object, reflection happens. Following the rule of reflection, waves are reflected off of straight boundaries.
When light strikes a surface without being absorbed, what is the term used to describe the bounce back?Reflection
When light reflects off of something, it does so. The light will reflect at the same angle it struck the surface if the surface is smooth and shining, such as glass, water, or polished metal.
What does it mean for a sound to repeatedly bounce back to its source?Echoes. A sound that is repeated as a result of sound waves being reflected back is known as an echo. The way a rubber ball bounces off the ground is the same way that sound waves can bounce off smooth, hard things.
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First-order analysis of a seismogram record allows seismologists to do all but which of the following?
First-order analysis of a seismogram record enables seismologists to do all except to develop a Modified Mercalli Intensity map.
First-order analysis of a seismogram record identifies the different kinds of seismic waves reaching to the earth's surface by the fault movement. This analysis records P waves.
The P wave will be the first wave to reach the surface. P waves are the fastest seismic waves. So, they will usually be the first ones that are recorded by a seismograph. The next seismic waves to record on a seismogram are the S waves.
A seismograph is the main instrument used to measure earthquakes. The seismograph produces a digital graphic recording of the ground motion caused by the reaching seismic waves on the earth surface. The digital recording is known as a seismogram.
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1.he discovered details of a lunar surface galileo 2.he invented first reflecting telescope astrolabe 3.he found planets had elliptical orbits refracting telescope 4.he performed a systematic mapping of sky brahe 5.uses a large glass lens newton 6.uses a mirror to focus light radio telescope 7.tool used to determine location of a star reflecting telescope 8.instrument that accumulates light from an object to show more detail camera 9.records sounds of stars kepler
1. Galileo.
2. Newton.
3. Kepler.
4. Brahe.
5. Refracting telescope.
6. Reflecting telescope.
7. Astrolabe
8. Camera.
9. Radio telescope.
1. Galileo, who uncovered information about the lunar surface.
2. The first reflecting telescope was created by Newton.
3. Kepler discovered elliptical orbits for planets.
4. Brahe: He meticulously mapped the sky.
5. A large glass lens is used in a refractive telescope.
6. A reflecting telescope concentrates light using a mirror.
7. Astrolabe: a device used to pinpoint a star's location.
8. Camera: a device that gathers light from an item to display greater detail.
9. The sound of stars is captured by radio telescopes.
Complete question:
The complete questions is (see in attachments).
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measure and record the output voltage from the rc low-pass fi lter for each of the frequencies listed below. (use the oscilloscope to measure the output voltage.) next, calculate the decibel attenuation offered by the fi lter at each frequency.
Passive RC filters “filter-out” unwanted signals by separating and allowing to pass only sinusoidal input signals based upon their frequency. Here the most simple passive low pass filter network is utilized.
Filters are named according to the frequency range of signals allowed to pass through them, while blocking or “attenuating” the rest. Here are some common filter designs.
The Low Pass Filter : only allows low frequency signals from 0Hz to its cut-off frequency.
The High Pass Filter : only allows high frequency signals from its cut-off frequency.
The Band Pass Filter : allows signals falling within a certain frequency band setup between two points to pass through.
The question is incomplete. Answer is written giving basics of the concepts used in the question.
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a system of volume v and temperature t consists of n independent, distinguishable particles, each of which can be in one of two states, with energy equal to 0 or e respectively. determine the partition function of the system
The partition function of a system of particles is a statistical measure that describes the distribution of particles over different energy states.
It is defined as:
Z = Σexp(-E_i/kT)
where Z is the partition function, E_i is the energy of the i-th particle, k is the Boltzmann constant, and T is the temperature of the system. The sum is taken over all possible energy states of the particles.
In the case of a system of volume v and temperature t consisting of n independent, distinguishable particles, each of which can be in one of two states with energy equal to 0 or e, the partition function can be expressed as:
Z = exp(-0/kT) + exp(-e/kT)
This is because there are two possible energy states for each particle (0 or e), and the partition function is a sum over all possible energy states of the particles.
Substituting the values of k, T, and e into the partition function equation, we can compute the value of Z:
Z = exp(-0/kT) + exp(-e/kT)
= exp(0) + exp(-e/kT)
= 1 + exp(-e/kT)
Thus, the partition function of the system is given by the equation:
Z = 1 + exp(-e/kT)
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The ______ model develops knowledge to observe, analyze, and critique physical activity and sport issues and topics in a variety of contexts.
The Cultural Studies model develops knowledge to observe, analyze, and critique physical activity and sports issues and topics in a variety of contexts.
Cultural Studies:
The science of comprehending contemporary society, with a focus on politics and power, is known as cultural studies. It is an all-encompassing phrase that is used to discuss a variety of topics, such as media studies like journalism and film, sociology, industrial culture, globalization, and social theory. By pursuing this field, one is attempting to unravel the human condition.
Students who want to work in the media or politics find this profession to be quite popular due to the variety of disciplines it offers. Understanding culture in connection to power is one of the goals of science. It examines the varied social and political systems found in many nations as well as how they relate to one another and the rest of the world.
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The non-reflective coating in eyeglasses is based on:
A. total internal reflection
B. destructive interference
C. resonance
D. constructive interference.
The non-reflective coating in eyeglasses is based on: destructive interference. So, option (B) is correct.
What is destructive interference?When waves combine and totally cancel each other out, destructive interference occurs. Two waves must have the same amplitude travelling in opposing directions in order to interfere destructively.
Nature is home to a variety of fascinating wave phenomena that are not reducible to a single wave. We must look at the phenomenon of destructive interference based on the wave combination. We use the superposition principle, which states the following, to examine these:
The resulting wave function is the algebraic sum of the individual wave functions when two or more waves are passing through a medium.
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Suppose you hear an echo 0.15 seconds after banging. How long
is the barn? (Remember the relationship between distance, time, and speed from sections on motion.)
If you hear an echo 0.15 seconds after banging, the barn is 25.725 m long.
What is echo?
An echo is a sound that results from the return of sound waves to the listener from a surface. It is the reflection of sound, which reaches the listener after the direct sound has passed.
Given data:
you hear an echo 0.15 seconds after banging.
we know that speed of sound in air is 343 m/s.
As in this time sound waves goes to the barn and returns back.
Hence, the barn is = 343×0.15/2 m long = 25.725 meter long.
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A loop of wire is at the edge of a region of space containing a uniform magnetic field B. The plane of the loop is perpendicular to the magnetic field. Now the loop is pulled out of this region in such a way that the area A of the coil inside the magnetic field region is decreasing at the constant rate . That is, dA/dt=−c , with c >0 . The induced emf in the loop is measured to be V. What is the magnitude B of the magnetic field that the loop was in? Express your answer in terms of some or all of the variables A ,c , and V. Homework Equations :
ϵ=|dΦm.dt| Φm=AB ϵ=lvB
The magnitude of the magnetic filed B at the loop is found as V/c.
Explain the term magnetic flux?A measurement of a total magnetic field that traverses a specific area is called magnetic flux. It is a helpful tool for explaining how the magnetic force affects things inhabiting a certain area.For the stated question-
The formula for magnetic flux;
Φ = BA
In which,
B = magnetic field A = areaNow,
Differentiate the flux with respect to time as putting B as constant;
dΦ/dt = B•dA/dt
Using Faraday's law, EMF induced is;
E = -dΦ/dt
However, we prefer to describe it in terms of V and E.M.F., which are also used to refer to voltage or potential difference.
V = -dΦ/dt
Thus, potential difference be-
-V = B•dA/dt
In term of a given area dA/dt = - c
-V = B•(-c)
V = Bc
B = V/c
Therefore, the magnitude of the magnetic filed B at the loop is found as V/c.
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The correct question is attached.
three identical blocks, X, Y, and Z, hang up from identical strings, as shown in the figure. which of the following free-body diagrams could represent the forces exerted on block Y?
The free-body diagram that could represent the forces exerted on block Y is upward tension force due to block X and downward tension force due to block block Z and its own weight.
option D is the correct answer.
What is free body diagram?A free-body diagram is a sketch of all the forces acting on the given object with all the surrounding objects stripped away and all of the forces acting on the body shown in their respective direction.
For the three identical blocks, X, Y, and Z, hang up from identical strings, as shown in the figure, the following are the direction of the forces acting on the string.
weight of block X -----> acting downwards
weight of block Y ------> acting downwards
weight of block Z ------> acting downwards
According to Newton's third law of motion, acting and reaction are equal and opposite.
As the weight of the blocks are acting downwards, the tension in the rope supporting the weights will be acting upwards.
The total weights of the = downward force of gravity
The tension in the string = upward tension force
The free body diagram is sketched as;
↑ F (Tension Up)
Ф
↓ ↓ F (Gravity) + F (tension down)
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