Light propagates from soda lime glass (n = 1.518) into pyrex glass (n = 1.473). determine the critical angle for this situation.

The energy of the red light emitted by a neon atom is 2.827*10^-19J

Light produces photons which might be small packets of power. as the atoms of an object are heated, it results within the manufacturing of photons. The electrons locate pleasure from the warmth and produce extra energy. This power emits inside the shape of a photon, and extra photons are released because the cloth becomes hotter.

The SI unit of wavelength is metre typically denoted as m. at the same time as measuring wavelength the multiples or fractions of a metre is also used. extensively, exponential powers of 10 are used while wavelengths are of a huge property. while there are shorter wavelengths they're expressed as negative exponential.

c=3*10^8 h=6.626*10^-34

wavelength= 703.2*10^-9m

E=2.827*10^-19J

Hence energy of the red light is 2.827*10^-19J.

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The area of a second piston that exerts a force of 24,000 N is 0.04 [tex]m^{2}[/tex].

Gravitational force is measured in newtons. Utilizing the physics formula pressure = force/area, you can compute pressure if you know the value of a force. Both pounds per square inch (psi) and newtons per square meter (N/m2) are acceptable units of measurement for this pressure.

Given force 1 =  12,000 N

The pressure which has produced a force of 12,000 N at the piston 1 = Force/ area

= 12,000N / 0.020 [tex]m^{2}[/tex]

= 6,00,000 N/[tex]m^{2}[/tex]

Now force at piston 1 must be equal to force at piston 2. thus, force at piston 2 is given by:

Force at piston 2 = pressure × area

24,000 N = 6,00,000 × area

area = 0.04 [tex]m^{2}[/tex]

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At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

[tex]B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }[/tex]

Now, for magnetic field intensity at the center of the loop can calculated by putting x = 0 in the above equation. On solving, we get -

[tex]B(0) = \frac{\mu_{o} i}{2R}[/tex]

Let us assume that the distance at which the magnetic field intensity is one-half its value at the center of the loop be ' r '. Then -

[tex]\frac{\mu_{o} iR^{2} }{2(r^{2} +R^{2})^{\frac{3}{2} } } = \frac{1}{2} \frac{\mu_{o}i }{2R}[/tex]

[tex]2R^{3} = (r^{2} +R^{2} )^{\frac{3}{2} }[/tex]

[tex]4R^{6} = (r^{2} +R^{2} )^{3}[/tex]

[tex]r^{2} =0.587R^{2}[/tex]

r = 0.766R

Hence, at r = 0.766 R - the magnetic field intensity will be half of its value at the center of the current carrying loop.

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The cost of operating the iron is $2186.49.

To find the answer, we have to know about the power.

              [tex]cost=power(kW)*t(hours)*(price/ kWh)[/tex]

                        [tex]P=IV=5.2*240=1248W[/tex]

                     [tex]t=2*365*24hours=17520hours.[/tex]

                  [tex]cost=1248*10^{-3}*17520*0.10} =\$2186.49[/tex]

Thus, we can conclude that the cost of operating the iron is $2186.49.

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The distance should be increased by 0.4 mm.

Lens formula is used here.

For a spherical mirror, the focal length, image distance, and object distance are all related by the lens equation, often known as the lens formula.

It is given by,

[tex]\frac{1}{f} = \frac{1}{v} -\frac{1}{u}[/tex]

where,

f = focal length

u = distance of the object

v = distance of the image formed

Given,

f = 40 mm

u = 4 m = 4000 mm

v =?

Using the lens formula,

[tex]\frac{1}{f} = \frac{1}{v} -\frac{1}{u}[/tex]

[tex]\frac{1}{40} = \frac{1}{v} -\frac{1}{4000}\\[/tex]

[tex]\frac{1}{v} = \frac{1}{40} + \frac{1}{4000}[/tex]

v = 39.6 mm

Change in distance = 40 - 39.6

                                 = 0.4 mm

Hence, the distance should be increased by 0.4 mm.

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0.4 mm

The distance should be increased by 0.4 mm.

We use lens formula here,

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{u}[/tex]

where,

f =  focal length

u = distance of the object

v = distance of the image formed

Given that,

f = 40 mm

u = 4 m = 4000 mm

v = ?

Using the lens formula, we get:

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{u}[/tex]

[tex]\frac{1}{40}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{4000}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{40}[/tex] + [tex]\frac{1}{4000}[/tex]

v = 39.6 mm

Change in the distance = 40 - 39.6

                                        = 0.4 mm

Therefore, the distance has to be increased by 0.4 mm

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Convex lens  had the largest overall magnification .

In optics, It is a quantification of comparing the size of the image with respect to the size of the object. It gives us information about the image in terms of how large or small is the image formed. Magnification is defined as the ratio of the height of image to the height of object.

The convex lens has the largest overall magnification. To get maximum magnification by convex lens object must be placed between center of curvature and pole of the lens .

Magnifying glasses make objects appear larger because their convex lenses (convex means curved outward) refract or bend light rays, so that they converge or come together.

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Hi, your answer is below.

Time dilation is usually defined as the slowing of the passage of time experienced by objects in motion relative to an observer; measurable only a relativistic speeds.  Because time moves at various rates for the two of them depending on their relative velocities and/or proximity to things of considerable mass, if two persons (or objects) are moving relative to one another, they will age at separate rates. They will age differently from one another over time since their two timepieces will really tick at separate speeds. If they cross paths again later, they will both have aged differently, which may be determined by using their own timepieces, presuming they each had one. Einstein's Special and General Relativity equations, which have undergone extensive testing over the past 115 years and have never been shown to falter, regulate this "time dilation." The general relativity theory of Einstein, which states that a huge body's gravity warps space-time around it, causes time to move more quickly or more slowly depending on how far away the mass is from the observer, is what causes this so-called "time-dilation" phenomenon.

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The total work done of 0.018 joules is needed to move the charges apart and double the distance between them.

We have two electric charges q(A) = 1μc and q(B) = -2μc kept at a distance 0.5 meter apart.

We have to calculate  much work is needed to move the charges apart and double the distance between them.

The potential energy of the system of two charges separated by a distance is given by -

[tex]U = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}[/tex]

In order to solve this question, it is important to remember the work - energy theorem which states -

"The change in the energy of the body is equal to work done on it"

Hence, using this work -energy theorem in the question given to us we get -

[tex]U_{f} -U_{i} =W_{net}[/tex]

In our case -

[tex]U_{f} = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r}\\\\U_{i} = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W=\frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r} - \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W = \frac{qQ}{4\pi\epsilon_{o}r} (\frac{1}{2} -1)\\\\W = 9\times 10^{9}\times \frac{1 \times 10^{-6} \times 2\times10^{-6} }{0.5} \times \frac{-1}{2}[/tex]

W = 0.018 joules

Hence, the total work done should be 0.018 joules.

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When testing for friction loss coefficients, departments that use a pitot tube should use Smooth bore nozzle

The pitot tube is a simple and convenient instrument to measure the difference between static, total and dynamic pressure (or head) .

It is a device used to measure velocity in pipe, wide tunnel, aero planes , etc. Pitot tube is completely based on its principle that if the velocity of flow at any point becomes Zero. A pressure measuring instrument used to measure fluid flow speed, especially used to determine the airspeed of an aircraft

Smooth bore nozzles also use the lowest engine pump pressures, allowing for maximum reach. Smooth bore nozzles are often referred to as solid bore nozzles because they produce a solid stream to provide maximum reach and penetration to the seat of the fire.

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Electric utility power blackouts will result in short electric power outages for the organization.

When the electrical power network, often known as the electrical grid, is down, there are power outages. Power outages can have a variety of causes, but they always tend to affect entire regions or cities rather than simply a single residence. For example, the Northeast blackout of 2003 left 50 million people without power from New York to Canada’s capital Ottawa.  

A place experiences a blackout when all power is lost. Power outages of this kind generally affect a sizable population over perhaps extraordinarily broad areas. Blackouts are particularly difficult to quickly fix because they typically result from significant damage to electrical generation facilities (such as structural damage from violent wind storms or lightning strikes). As a result, these types of outages can, in the worst-case scenarios, last for several weeks.

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What mechanisms function to localize sound in the horizontal and vertical planes?

Horizontal sound localization results from two mechanisms: interaural time delay and interaural intensity difference.

The capacity to pinpoint the position or source of a detected sound in terms of distance and direction is known as sound localization.

Numerous studies have been conducted on the mammalian auditory system's sound localization mechanisms. The auditory system uses a variety of indicators, such as spectral information, timing difference, level difference (or intensity difference) between the ears, and others, to locate the source of sound. Other animals, including birds and reptiles, employ these cues as well, however there may be variances in how they are used. In addition, there are localization cues that are not present in the human auditory system, such as the results of ear movements. It is obvious that animals that can localize sound have an evolutionary advantage.

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The frequency of a photon is  1.06 * [tex]10^{18}[/tex] Hz.

The mass of a neutron is:

m = 1.67 * [tex]10^{-27}[/tex] kg

Since we know its speed, we can calculate the neutron's momentum:

p = mv = (1.67 * [tex]10^{-27}[/tex] kg)(1400 m/s) = 2.34 * [tex]10^{-24}[/tex] kg m /s

The problem says the photon has the same momentum of the neutron, p.  The photon momentum is given by

                                               p = h / λ              

where h is the Planck constant, and  λ  is the photon wavelength. If we re-arrange the equation and we use the momentum we found before, we can calculate the photon's wavelength:

p = h / λ =  [6.6 * [tex]10^{-34}[/tex] J/s]  /  [2.34 * [tex]10^{-24}[/tex] kg m /s ]

             = 2.82 * [tex]10^{-10}[/tex] m

And since we know the photon travels at speed of light c, we can now calculate the photon frequency:

f = c /  λ  =  [3 * [tex]10^{8}[/tex] m/s] / [ 2.82 * [tex]10^{-10}[/tex] m ]

              = 1.06 * [tex]10^{18}[/tex] Hz.

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When a proton slows from 0. 8c up to 0. 6c, it’s kinetic energy decreases by what factor of 1/4.

Kinetic energy of a proton having a charge Q and Voltage V is given by:

Kinetic energy = Q×V

Where, Q is the charge

            V is the Voltage

Kinetic energy is directly proportional to the charge on a proton.

Let the kinetic energy of proton having charge 0.8C be KE₁ and kinetic energy of proton having charge 0.6C be KE₂

Hence KE₁ = 0.8 × V

KE₂ = 0.6 × V

Now, KE₁ / KE₂ = 0.8 V / 0.6 V

⇒          KE₁ / KE₂ = 4 / 3

⇒         KE₂ / KE₁ = 3/4

⇒         KE₂ = 3/4 times KE₁

Hence, the final kinetic energy becomes 3/4 times the initial kinetic energy.

The kinetic energy decreases by a factor of:

Change = KE₁ - KE₂

Change = KE₁ - 3/4KE₁

Change = 1/4 KE₁

Hence, the kinetic energy decreases by a factor of 1/4

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Building a telescope that detects radio waves must be built with a very large dish since radio waves have very large wavelengths is regarded as a true statement and is denoted as option A.

This is defined as the distance between two successive crests or troughs of a wave.

Radio waves have the longest wavelength in the electromagnetic spectrum which is therefore the reason why a very large dish is built to detect it.

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The probability that she makes 6 of them is 0.242

Simply put, the probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes. Statistics is the study of events that follow a probability distribution.

A basketball player has a probability = 0. 603

The player shoots 10 free throws.

Let x be a random variable that represents the number of free throws made by a basketball player.

x ≈ Binomial (n,p)

p = 0.603

n= 10

P(x=k) = [tex]_nC_k p^k (1-p)^{n-k}[/tex]

P(6)    [tex]= _1_0C_6 (0.603)^6 (1-0.603)^{10-6}[/tex]

           [tex]=210 (0.048) (0.397)^4[/tex]

           [tex]=210 (0.048)(0.024)[/tex]

           [tex]= 0.242[/tex]

Therefore, the probability that she makes 6 of them is 0.242

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A low partial pressure of oxygen promotes hemoglobin binding to carbon dioxide. This is an example of the  Haldane effect

The less saturated hemoglobin is and the lower the partial pressure of oxygen in the blood is, the more readily hemoglobin binds to carbon dioxide. This is an example of the Haldane effect.

The Haldane effect is a property of hemoglobin first described by John Scott Haldane, within which oxygenation of blood in the lungs displaces carbon dioxide from hemoglobin, increasing the removal of carbon dioxide. Consequently, oxygenated blood has a reduced affinity for carbon dioxide.

The Haldane effect is a property of hemoglobin first described by John Scott Haldane, within which oxygenation of blood in the lungs displaces carbon dioxide from hemoglobin, increasing the removal of carbon dioxide. Consequently, oxygenated blood has a reduced affinity for carbon dioxide.

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The hydroxide ion concentration in a solution is 3.31*10^-8M.

To find the answer, we have to know more concentration of solution.

                     [tex]pH=-log[H_3O^+][/tex]

                   [tex][H_3O^+]=-10^{pH}=10^{-6.25}=5.6*10^{-7}M[/tex]

                        [tex]K_w=[H_3O^+][OH^-]\\Where,\\K_w=10^{-14}[/tex]

                         [tex][OH^-]=\frac{K_w}{[H_3O^+]} =\frac{10^{-14}}{10^{-6.52}}\\\\[/tex]

                           [tex][OH^-]=3.31*10^{-8}M[/tex]

Thus, we can conclude that, the hydroxide ion concentration in a solution is 3.31*10^-8M.

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The speed of one rocket relative to the other is 8.5 cc.

Let s be the frame at rest relative to the earth. Let the spaceship moving to the left with respect to the earth at speed [tex]v[/tex] be the particle in the terminology. Then the velocity of the spaceship relative to each other is simply the velocity of the second spaceship.

That for speeds small compared with the speed of light the relativistic velocity addition law gives the usual Newtonian result, whereas for speed near c the result is not what has been expected classically.

[tex]v' = 0.96cc\\\\v= 0.84cc\\\\\\v' = \frac{v+V}{1+ \frac{vV}{c^2} } \\\\v' = \frac{v+V}{ \frac{c^2+ vV}{c^2} }\\\\v' = \frac{(v+V) c^2} {c^2+ vV}\\\\\\v'c^2 + c^2v = V (c^2 - v'v)\\\\V = \frac{v'c^2+c^2v}{c^2 - v'v} \\ \\ = \frac{0.96 * 9* 10 ^1^6 + 0.84*9*10^1^6}{9*10^1^6 - 0.96 * 0.84} \\\\ =\frac{16.2}{1.9}\\ \\= 8.5 cc[/tex]

Therefore, the speed of one rocket relative to the other is 8.5 cc.

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The unit of the quotient of inductance and resistance will be Henry and ohm

Inductance is the tendency of an electrical conductor to oppose a change in the electric current flowing through it. The flow of electric current creates a magnetic field around the conductor. The field strength depends on the magnitude of the current, and follows any changes in current.

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.

unit of quotient of inductance = henry (H)

unit of resistance = ohm

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The maximum weight of a luminaire (lighting fixture) permitted to be hung directly from an outlet box in a ceiling 50 pound.

A luminaire that weighs more than 23 kg (50 lb) shall be supported independently of the outlet box, unless the outlet box is listed for not less than the weight to be supported.

Luminaire, or light fixture, complete lighting unit, consisting of one or more lamps (bulbs or tubes that emit light), along with the socket and other parts that hold the lamp in place and protect it, wiring that connects the lamp to a power source, and a reflector that helps direct and distribute the light.

Fluorescent fixtures usually have lenses or louvers to shield the lamp (thus reducing glare) and redirect the light emitted. Luminaires include both portable and ceiling- or wall-mounted fixtures.

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~400 nm to ~700 nm are the wavelengths of electromagnetic wave in free space.

What are the wavelengths of electromagnetic wave in free space?

Electromagnetic waves are categorized on the basis of their frequency f, which is equivalent to wavelength λ = c/f. Visible light has a wavelength that ranges from ~400 nm to ~700 nm. Violet light has a wavelength of ~400 nm, and having a frequency of ~7.5*1014 Hz.

So we can conclude that: ~400 nm to ~700 nm are the wavelengths of electromagnetic wave in free space.

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The wavelengths of the light are 4.3 * 10^-12 m and 0.2 m respectively.

The term wavelength has to do with the horizontal distance that is covered by a wave. We know that a long wavelength implies that the wave is able to travel a long distance from one point to another.

Given that;

c = λf

c = speed of light

λ = wavelength of ight

f = frequency of light

Thus;

λ = 3 * 10^8/ 7.00 x 10^19

λ = 4.3 * 10^-12 m

λ = 3 * 10^8/1.50 x 10^9

λ = 2 * 10^-1 or 0.2 m

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Missing parts:

What are the wavelengths of electromagnetic wave in free space that have the following frequencies? (a) 7.00 x 10^19 Hz______ pm (b) 1.50 x 10^9 Hz__________ cm

Vmax = 1.258 m/s

Maximum velocity of any point on the string is 1.258 m/s.

Maximum velocity is given by,

Vmax = Aω

where,

V = velocity

A = amplitude

ω = angular displacement

ω is given by,

ω = 2[tex]\pi[/tex]f

where f = frequency

ω = 2[tex]\pi[/tex]f

   = 2*3.147*100

   = 629.4 rad

A = amplitude = 2mm

Vmax = Aω

         = 2 ×[tex]10^{-3}[/tex] × 629.4

         = 1.258 m/s

Maximum velocity = Vmax =  1.258 m/s

Maximum velocity of any point on the string is 1.258 m/s.

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The amount of heat required to raise the temperature is 706.05J.

To find the answer, we need to know more about the specific heat capacity.

                                 Q=msΔT

                 [tex]m=2.50g=2.50*10^{-3}kg\\s=0.523 J/gK=\frac{0.523}{10^{-3}} J/kgK=523J/kgK\\T_1=65^0C=338K\\T_2=600^0C=873K\\[/tex]

            [tex]Q=2.5*10^{-3}*523*(873-333)=706.05 J[/tex]

Thus, we can conclude that, the amount of heat required to raise the temperature is 706.05J.

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The work done by the unstretched spring is 5 J.

Hooke's law states that the extension of a given material is directly proportional to the force applied as log as the elastic limit is not exceeded. Thus we have to know that; F = Ke

F = force applied

K = force constant

e = extension

Using the graph;

K = F/e

F = 200N

e = 5 cm or 5 * 10^-2 m

K = 200N/ 5 * 10^-2 m

K = 4000 N/m

Now;

Work = 1/2Ke^2

Work = 0.5 *  4000 N/m * (5 * 10^-2 m)^2

Work = 5 J

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The cannonball will travel 311.8 m  horizontally. Among the given options, 310 m is the correct answer.

What is a Projectile ?

A projectile is any object like stone, ball or javelin that take a trajectory path when thrown into the air.

The following parameters are given from the question

Resolve the initial velocity into horizontal and vertical components. That is,

To calculate the range that is, the horizontal distance, will can first calculate the total time take by the ball to reach the ground.

Total time T = 2usinФ / g

Substitute all the parameters

T = (2 x 60sin30) / 10

T = (2 x 30) / 10

T = 60 / 10

T = 6 s

The horizontal distance R = ucosФ x T

R = 60 x cos 30 x 6

R = 311.77 m

Therefore, the cannonball will travel 312 m approximately horizontally.

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A lorenz curve represents the cumulative percentage of total income received along the horizontal axis and the cumulative share of population along the vertical axis.

The distribution of the cumulative percent of occurrences by the cumulative percent of population is shown graphically by the Lorenz Curve. By expanding the neighbourhood income quintile group, the horizontal axis (x-axis) of the curve shows the cumulative percent of persons in the population, and the vertical axis (y-axis) shows the cumulative percent of events in the population.

The Lorenz curve can be described as the proportion of the population that the neighbourhood income quintile represents holding the proportion of population events.

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Answer:

-79.6

-80

-81.2

Explanation:

Fart

What is the change in temperature for the aluminum wire?

-79.6

What is the change in temperature for the steel wire?

-80

What is the change in temperature for the lead pellets?

-81.2

The volume of a unit cell is 4.3 × 10⁻¹⁰ pm³.

We need to start with the features of a face-centered cubic system in order to be able to determine the edge length of the unit cell.

As we know, a face-centered cubic system is characterized by a unit cell that has a total of 14 lattice points.

Now, these lattice points will contain

Assume that r is the edge length of the unit cell and that r is the radius of an iron atom. You'll see that we can represent x in terms of the cell's diagonal, d, using Pythagoras' Theorem.

        [tex]d^2 = x^2+ x^2[/tex]

        [tex]d^2=2x^2[/tex]

The cell's diagonal will be equal to one radius from the atom in the top corner, two from the atom in the face, and one from the atom in the lower corner.

[tex]d= r+2r+r = 4r[/tex]

This means that we have,

[tex](4r)^2=2x^2[/tex]

[tex]16.r^2 = 2x^2 \\x=\sqrt{8r^2}[/tex]

This is equivalent to

[tex]x=2\sqrt{2} r = 2\sqrt{2} .124= 350.7 pm[/tex]

So, the edge length of the unit cell is equal to 350.7 pm.

The volume of a unit cell. As we know, the volume of a cube is given by the formula

V = [tex]l[/tex] × [tex]l[/tex] × [tex]l[/tex]

[tex]l[/tex] = the edge length of the cube

Volume = (350.7)³ pm³

            = 4.3 × 10⁻¹⁰ pm³

            = 4.3e-30 cm³

Therefore, the volume of the unit cell is 4.3 × 10⁻¹⁰ pm³.

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565.2 lbs pressure can apply to a plunger.

It is given that,

The air supplied to a diaphragm is 20 psig.

Diameter is 6

Then r=3

We know that,

Area=

πr²

=(3.14×3²)

= 28.26

The formula is (3.14 ×radius of diaphragm squared) ×psig.

=( 28.26 ×20)

= 565.2 lbs of pressure.

Hence, the pressure is  565.2 lbs.

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#SPJ4.

Answer:

ΔV=Vi + Vf

           2

ΔV= 11m/s + 19m/s

                 2

ΔV= 15m/s

Explanation: