Line, line segment, angle,ray

Answer:

87

Step-by-step explanation:

I am not sure but try (143-104=39)39+21+27 you get 87

Answer: A

Step-by-step explanation:

Volume= LxWxH so we get 20x28x24 as given.

Volume= 13,440 which is the volume of the box given. ANd so if the box is 10,500cubic inches, we subtract to find the difference.

13,440-10,500= 2,940 Cubic Inches

Option A

Answer:

Part A:  13440 cubic inches.

Part B: A - 2940 cubic inches.

Step-by-step explanation:

The volume of the box = 24x20x28 = 13440 cubic inches.

The problem tells us that his gift is 10,500 cubic inches. So subtract that from the volume of the box.

13440-10500 = 2940 cubic inches. The answer is A.

Let w be the weight on point s. Since the sum of the weights is 1, the weight on point t is 0.625, we can write:

w + 0.625 = 1

Subtracting 0.625 from both sides, we get:

w = 1 - 0.625 = 0.375

Therefore, the weight on point s is 0.375.

The sides of the triangle can be identified as follows:

6. The longest side is PR  7. The shortest side is QR

Based on the relationship between the sides of a triangle and its relative angle measures, we recall that the longest side will be opposite the largest angle measure and vice versa.

Therefore, we have the following:

m<Q = 83 degrees

m<P = 48 degrees

m<R = 180 - 83 - 48 = 49 degrees.

Angle Q is the largest angle, while angle P is the smallest.

Thus, we can conclude that:

6. The side that is the longest is PR

7. The side that is the shortest is QR

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When writing a proof , by copying the “given” statement(s) from the original problem

Given data ,

A true assertion that is provided in the problem or is known to be true should be the first statement in a proof. The subsequent logical argument has this as its foundation.

We can provide the groundwork for the proof and proceed to the desired conclusion by duplicating the "given" statement(s) from the original problem.

Once the first statement is established, we can move on to writing additional statements that are each logically supported by the first statement.

The logical evolution of the preceding assertions demonstrates that the last statement should be the intended conclusion.

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The next step in the construction of a regular hexagon is A. Use a compass and straightedge to continue drawing an equilateral

A circle with the required radius must first be drawn in order to make a regular hexagon. Draw a second circle whose centre is one of the spots on the first circle using the same radius. These two circles' intersection points will form the vertices of an equilateral triangle. Three of these equilateral triangles, with their vertices on the circle, must be drawn inside a circle. At the circle's centre, these three triangles will have a common vertex.

Drawing three more equilateral triangles, each of which shares a side with one of the previously drawn triangles, is necessary to finish the building of a regular hexagon. Drawing equilateral triangles keeps on until there are six of them, each of which has a side in common with a preceding triangle.

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The relationship between Dani's time and Candice's time, taking into account the fact that Dani took 5 minutes longer to run the course. it is Reasonable time to assume that the runners' rates were constant. Option C is the correct answer.

Let "t" be the time it took Candice to run the course.

Then, according to the problem statement, Dani took 5 minutes longer than Candice to run the course. Therefore, Dani's time is equal to Candice's time plus 5 minutes, which can be expressed as:

D = C + 5

where D is Dani's time and C is Candice's time.

This equation represents the relationship between Dani's time and Candice's time, taking into account the fact that Dani took 5 minutes longer to run the course. It can be used to solve problems related to the two runners' times, such as finding their individual times or comparing their rates. Option C is the correct answer.

It is important to note that this equation assumes that both runners ran the course at a constant rate. If the runners' rates varied throughout the course, then the equation would not accurately represent their times. However, for the purposes of this problem, it is reasonable to assume that the runners' rates were constant.

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Answer:

f : u = 12 : 9, so f : u : w = 12 : 9 : 5.

Answer:

A line that is parallel to y = 3x - 9 will have the same slope as the given line. The slope of y = 3x - 9 is 3. Therefore, the equation of the line that passes through (1, 2) and is parallel to y = 3x - 9 is:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the point (1, 2)

Substituting the values we get:

y - 2 = 3(x - 1)

Simplifying the equation we get:

y - 2 = 3x - 3

y = 3x - 1

Therefore, the equation of the line that passes through (1, 2) and is parallel to y = 3x - 9 is y = 3x - 1 .

;>

Answer:

A = (1/2)(5.5)(8.5 + 12.5) = 57.75 m^2

The length of the perpendicular from Q to PR is approximately 3.86 units.

slope of PR = (y2 - y1) / (x2 - x1)

slope of PR = (15 - 3) / (5 - 1)

slope of PR = 3

Using the point-slope form of a line, we have:

y - y1 = m(x - x1)

y - 3 = 3(x - 1)

y - 3 = 3x - 3

y = 3x

The equation of the line perpendicular to PR and passing through Q is y = (-1/3)x + (17/3).

Finally, we can find the point where this line intersects PR by solving the system of equations:

y = 3x

y = (-1/3)x + (17/3)

Substituting the first equation into the second equation, we have:

3x = (-1/3)x + (17/3)

10/3 x = 17/3

x = 1.7

Substituting x = 1.7 into the first equation, we have:

y = 3(1.7)

y = 5.1

the point where the line perpendicular to PR intersects PR is (1.7, 5.1).

Now we can find the distance between Q and (1.7, 5.1) using the distance formula:

d = ✓((x2 - x1)² + (y2 - y1)²)

d = ✓((5 - 1.7)² + (4 - 5.1)²)

d = ✓(14.89)

d = 3.86

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The equations of the three mediators of triangle ABC are:

x = 3 (the mediator of AB)

y = (-1/2)x + 5 (the mediator of AC)

y = (1/2)x + 2 (the mediator of BC)

The coordinates of A are (1,2) and the coordinates of B are (5,2), so the midpoint of AB is:

((1+5)/2, (2+2)/2) = (3,2)

The coordinates of A are (1,2) and the coordinates of C are (3,6), so the midpoint of AC is:

((1+3)/2, (2+6)/2) = (2,4)

The coordinates of B are (5,2) and the coordinates of C are (3,6), so the midpoint of BC is: ((5+3)/2, (2+6)/2) = (4,4)

The slope of BC is: (6-2)/(3-5) = -2

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The volume of a cube is 6859 cubic inches if the side of the cube is 19 inches.

The given function = V(x) = [tex]x^{3}[/tex]

Side of cube = 19 inches

The cube has six faces with 12 edges. That means three faces are visible at a time. That means the product of the three faces of a cube gives the volume of a cube.

In the question, it is stated that the length of the cube is to be substituted in the value of x in order to calculate the volume of a cube.

The volume V of a cube = V = [tex]x^{3}[/tex].

Substituting x = 19,

The volume of the cube = [tex]19^3[/tex]

Volume of cube = 6859

Therefore, we can conclude that the volume of a cube is 6859 cubic inches.

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The expressions 1 and 4 are having values less than 1.

Given are the expressions, we need to solve them,

1) -7 · 1/2 - 4

= -7/2-4

= -7-8 / 2

= -15/2

= -7.5 < 1

2) -7 · (1/2 - 4)

= -7 · -7/2

= 49/2

= 24.5 > 1

3) -7 · 1/2 · (- 4)

= -14/2 · (- 4)

= 56/2

= 28 > 1

4) -7 + 1/2 · (- 4)

= -7 -4/2

= -7 -2

= -9 < 1

5) -7 ÷ 1/2 · (- 4)

= -7 × 2 × -4

= -14 × -4

= 56 > 1

Hence, the expressions 1 and 4 are having values less than 1.

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The tuxedo was rented for 4 days.

Let's start by assigning variables to the unknowns. Let "x" be the number of additional days rented, and "d" be the total number of days rented (including the first day).

From the given information, we know that the flat fee for the rental is $150, so the cost of the additional days is the total cost minus the flat fee, which is $300 - $150 = $150. We also know that the cost for each additional day is $50. Therefore, we can set up the equation:

$150 + $50x = $300

Subtracting $150 from both sides, we get:

$50x = $150

Dividing both sides by $50, we get:

x = 3

So the tuxedo was rented for 3 additional days, making the total number of days rented:

d = 1 + 3 = 4

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The quotient is 2x² + 3x + 2 and the remainder is -32x - 13.

We have,

We can use long division to divide f(x) by p(x) as follows:

x² - 3 | 2x^4 - x³ - 7x² + 7x - 13

           - (2x^4 - 0x³ + 6x²)

               ---------------------

                       - 13x² + 7x

                       - (-13x² + 39x)

                           -----------------

                                     -32x - 13

The quotient is 2x² + 3x + 2 and the remainder is -32x - 13.

We can write the division in the form:

f(x) = p(x) x q(x) + r(x)

where p(x) is the divisor, q(x) is the quotient, and r(x) is the remainder. In this case, we have:

f(x) = (x² - 3) x (2x² + 3x + 2) - (32x + 13)

This means that we can write f(x) as the product of p(x) and q(x), plus the remainder r(x).

Thus,

The quotient is 2x² + 3x + 2 and the remainder is -32x - 13.

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Answer:

Question 3 : Less than one

Question 4 : Starting value

Step-by-step explanation:

Answer:

less than one + Starting value

Step-by-step explanation:

The answer for #3 is less than one because any number greater than one when multiplied increases the value of the number,

and #4 is starting value because it is what you are multiplying the change by. Please mark brainliest + enjoy the night!

Answer:

B. 40

Step-by-step explanation:

you would multiply 5 and 320 and then do the square root of the number

Answer:Xmin:

-10

Xmax:

10

Ymin:

-10

Ymax:

10

Step-by-step explanation:

Answer:

5.25

Step-by-step explanation:

not much to show, go 3 topping across then up to see the price

Answer:

Step-by-step explanation:

To find the order of the functions from least to greatest according to the average rate of change on the interval from x = −1 to x = 3, we need to calculate the average rate of change of each function over that interval and compare them.

For f(x), we have:

average rate of change = [f(3) - f(-1)] / (3 - (-1))

= [(3+3)^2 - 2 - ((-1)+3)^2 + 2] / 4

= 23

For g(x), we have:

average rate of change = [g(3) - g(-1)] / (3 - (-1))

= [0 - (-3/2)] / 4

= 3/8

For h(x), we have:

average rate of change = [h(3) - h(-1)] / (3 - (-1))

= [(62-14)/(3-(-1))]

= 12

Therefore, the correct order of the functions from least to greatest according to the average rate of change on the interval from x = −1 to x = 3 is:

g(x), f(x), h(x)

So the answer is option (b).

Answer:

Step-by-step explanation:

To compare the minimum y-values of the given functions, we need to find the minimum point of each function and compare their respective y-values.

For the function f(x) = 4 sin(2x-1) - 11, we know that the sine function oscillates between -1 and 1, and is multiplied by a factor of 4, which will change the amplitude of the function. We can find the minimum point of the function by setting its derivative equal to zero:

f'(x) = 8 cos(2x-1) = 0

cos(2x-1) = 0

2x-1 = (2n+1/2)π, where n is an integer

x = (2n+1/4)π + 1/2, where n is an integer

The minimum point will occur at x = (2n+1/4)π + 1/2, and the corresponding y-value can be found by substituting this value of x into the original function:

f(x) = 4 sin(2x-1) - 11

f((2n+1/4)π + 1/2) = 4 sin(2[(2n+1/4)π + 1/2]-1) - 11

f((2n+1/4)π + 1/2) = 4 sin(2nπ + π/2) - 11

f((2n+1/4)π + 1/2) = 4 (-1)^n - 11

We can see that the y-value of the minimum point alternates between -15 and -7 as n changes. Therefore, the smallest minimum y-value for the function f(x) is -15.

For the function h(x) = (x-2)² + 4, we know that it is a quadratic function with a minimum point at x=2. The y-value of the minimum point can be found by substituting x=2 into the function:

h(2) = (2-2)² + 4

h(2) = 4

Therefore, the smallest minimum y-value among the two given functions is 4, which is the minimum y-value of the function h(x) = (x-2)² + 4.

The Perimeter of the walkway is 18√5 ft.

Explanation:-

The perimeter of the rectangular walkway is the sum of the lengths of its four sides. If the width of the walkway is √5 ft and the length is 8√5 ft, then we can label the sides as follows:

Width = √5 ft

Length = 8√5 ft

Width = √5 ft

Length = 8√5 ft

The perimeter P is given by:

P = Width + Length + Width + Length

= 2(Width + Length)

= 2(√5 + 8√5)

= 2(9√5)

= 18√5 ft

Therefore, the perimeter of the walkway is 18√5 ft.

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TU is parallel to MN.

Given that the slope of a line MN is -3, we need to find a line which is parallel to the MN.
So we know that the parallel lines are having equal slope so the line which is parallel to the MN it must have slope of -3.

Therefore,

Considering the line TU, find the slope = y₂-y₁ / x₂-x₁

= 10-1 / 5-8 = -9/3 = -3

Since, the slope of the line TU is -3 therefore we can say the lines TU and MN are parallel liens.

Hence TU is parallel to MN.

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The slope of Line B would have to be -1/2.

Two lines are perpendicular to each other if the product of their slopes is -1. The slope of Line A is given as 2. Therefore, the slope of Line B would have to be the negative reciprocal of 2, which is -1/2. This ensures that the product of the slopes of Line A and Line B is -1, satisfying the condition for perpendicularity.

In general, if the slope of Line A is m, then the slope of a line perpendicular to Line A would be -1/m. This relationship holds because perpendicular lines form right angles, and the slopes of perpendicular lines are negative reciprocals of each other.

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The type of the conic basic x² - 4x + y² + 2y = 4 is a circle

From the question, we have the following parameters that can be used in our computation:

x² - 4x + y² + 2y = 4

The above equation has the following features

Using the above as a guide, we have the following:

A conic section that has the above features is a circle

This means that the type of the conic basic is a circle

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Answer:

P = (1/2)(6)(8)/(π(5^2))

= 12/(25π)

= .31 (about 31%)

[tex]Given:\ x_{n+1}=\sqrt[3]{6x_{n}-1}\ ,\ x_{1}=4\\\\The\ iterative\ formula\ can\ be\ re-written\ as:\\x_{n}=\sqrt[3]{6x_{n-1}-1}\\\hrule\ \\x_2=\sqrt[3]{6x_{1}-1}\\x_2=\sqrt[3]{6(4)-1}\\x_2=\sqrt[3]{23}\approx 2.84\\\hrule\ \\x_3=\sqrt[3]{6x_{2}-1}}\\x_3=\sqrt[3]{17.04-1}\\x_3=\sqrt[3]{16.04}\approx 2.52\\\hrule\ \\x_4=\sqrt[3]{6x_{3}-1}}\\x_4=\sqrt[3]{15.12-1}\\x_4=\sqrt[3]{14.12}\approx 2.41[/tex]