List all the elements of the following set. Use set notation and the listing method to describe the set. The set of all counting numbers less than or equal to 2. Express the set using set notation and the listing method. (Use a comma to separate answers as needed. Use ascending order.)

Answers

Answer 1

Answer:

different question

Step-by-step explanation:

question is wrong


Related Questions

Mrs. Rodger got a weekly raise of $145. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.

Answers

Answer:

her salary will increase by $ 145 for every week

Step-by-step explanation:

x=1st paycheck (integer).

weekly raise = $ 145.

After completing the 1st week she will get $ (x+145).

Similarly after completing the 2nd week she will get

$ (x + 145) + $ 145.

= $ (x + 145 + 145)

= $ (x + 290)

So in this way end of every week her salary will increase by $ 145.

Which system of equations shows a solution of (0.5, -1)?
Need answers asap plzzz

Answers

Answer:

The first graph

Step-by-step explanation:

What is the growth factor that corresponds to a product that increases its value first by 2%, and then increases by 5% of
its value, and finally increases by 12% of its value? Round to the tenths place.
a. 1.20
C. 1.19
b. 3.19
d. 1

Answers

Answer:

1.19

Step-by-step explanation:

1+0.02+0.05+0.12 = 1.19

i got some summer h.w it doesn't have a answer but like it asks for me to Create a table of x and y values that represents a proportional relationship. and i dont know how cause it wont let me draw a graph so i have to write something down apparently any help pls?

Answers

Answer:

So for example a graph in typed in word format could look like

Time   Girls   Boys

1            3        5

2            4        6

3            5         7

4             6          8

5             7          9

Not saying that this graph would be sufficient value wise for the answer, but this is how I would tackle it if I wasn't given the option to draw a graph.

I’m stuck please help .

Answers

Answer:

me too

Step-by-step explanation:

me too

Find the solution set.

The solution set for 5v2 – 125 = 0

Answers

Answer:

5v2 – 125 = 0

5(v2−25)=0

v2−25=0

a couple more steps and the answer is...

v=-5

Solve for the following equation for x. l x/4 + 3 l < 6

Answers

Answer:

this is the answer I got! i don't know if it helps, but I hope it does

Is −8 a solution to the equation 3x = 16 − 5x? How do you know?

Answers

no it is not the solution.

since the question is saying -8 is the solution, it is saying that -8 = x

if we change x in the equation and put -8, it would end up as -24=56.

in order for the equation to be true, both sides of the equation have to be equal, which in this case it is not

Find the value for the side marked below.
Round your answer to the nearest tenth.
у
100
49°
y = [?]

Answers

Answer:

y = 75.5

Step-by-step explanation:

Reference angle (θ) = 49°

Hypotenuse = 100

Opposite = y

Apply trigonometric function, SOH. Which is:

Sin θ = Opp/Hyp

Plug in the values

Sin 49 = y/100

100*Sin 49 = y

y = 75.5 (nearest tenth)

find the value of the following 425×167+233×425 step by step explanation​

Answers

Answer:

so first we start from the left

425*167=70975

but instead of adding this to 233 we use pemdas so instead we do

233*425=99025

now we add them together

70975+99025=170000

Hope This Helps!!!

Answer:

170,000

Step-by-step explanation:

425 × 167 + 233 × 425

= (425 × 167) + (233 × 425)

= 70,975 + 99,025

= 170,000

2•^2=?

A) -4

B) 1/4

C) 4

Answers

B) 1/4
Explanation - I’m smart

Answer:

1/4.

Step-by-step explanation:

2^-2 = 1/2^2

= 1/4.

Angles A and B are complementary. If sin A = 4x + 10 and cos B = 2x + 16, what is the value of x? (

Answers

Answer:

x is 10.66

Step-by-step explanation:

What are complementary angles?

They are angles that up to 90

So we have Sin A and Cos B

4x + 10+ 2x + 16= 90

collect like terms

6x+ 26= 90

6x= 90-26

6x= 64

x= 64/6

x= 10.66

Hence the value of x is 10.66

Answer:

not 10.66

Step-by-step explanation:

Using a weight of 12 for the most recent observation, 13 for the second most recent observation, and 16 for third most recent observation, compute a three-week weighted moving average for the time series. (Round your answers to two decimal places.)

Answers

Answer: Hi some data is missing attached below is the missing data

answer:

WMA = 174.53

Step-by-step explanation:

Determine the three-week weighted moving average with weights

( 1/2, 1/3, 1/6 )

Weighted moving average ( WMA ) = 174.53

MSE = ∑ (xi - WMA)^2 / n

        = 9.71

attached below is the detailed solution/table

What is the length of an arc with a central angle of 2/3pi radians and a radius of 24 centimeters?

Use 3.14 for pi.

Enter your answer, as a decimal, in the box.

Answers

9514 1404 393

Answer:

  50.24 cm

Step-by-step explanation:

Fill in the given numbers and do the arithmetic.

  s = rθ

  s = (24 cm)(2/3π) = (24 cm)(2/3)(3.14) = 50.24 cm

Use the completing the square to solve x^2+6x=12.

Answers

Answer:

x= -3 ± [tex]\sqrt{21}[/tex]

Step-by-step explanation:

[tex]x^{2}[/tex]+6x=12

We add 9 [[tex](6/2)^{2}[/tex]] to both sides to complete the square as [tex]x^{2}[/tex]+6x+9 = [tex](x+3)^{2}[/tex].

[tex](x+3)^{2}[/tex]=21

Now we take the square root of both sides:

x+3=±[tex]\sqrt{21}[/tex]

x= -3 ± [tex]\sqrt{21}[/tex]

Answer:

x = -3 ± [tex]\sqrt{21}[/tex]

Step-by-step explanation:

[tex]x^2+6x=12[/tex]

[tex](\frac{b}{2} )^{2}[/tex] = 9

[tex]x^2+6x + 9 =12 + 9[/tex]

[tex](x+3)^{2} =21[/tex]

x + 3 = [tex]\sqrt{21}[/tex]

x = -3 ± [tex]\sqrt{21}[/tex]

The graph of a line goes through the points (-4,3) and (6,8). What is the equation of the line in slope-intercept form?
Enter the correct answer in the box by replacing m and b with the appropriate values.
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73°F Mostly cloudy
327 PM
7/3/2001

Answers

Answer:

[tex]y=\frac{1}{2}x+5[/tex]

Step-by-step explanation:

Hi there!

Slope intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0)

1) Determine the slope (m)

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] where two points that lie on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Plug the given points (-4,3) and (6,8) into the equation

[tex]m=\frac{8-3}{6-(-4)}\\m=\frac{8-3}{6+4}\\m=\frac{5}{10}\\m=\frac{1}{2}[/tex]

Therefore, the slope of the line is [tex]\frac{1}{2}[/tex]. Plug this into [tex]y=mx+b[/tex] :

[tex]y=\frac{1}{2}x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=\frac{1}{2}x+b[/tex]

Plug in one of the given points and solve for b

[tex]8=\frac{1}{2}(6)+b\\8=3+b[/tex]

Subtract 3 from both sides to isolate b

[tex]8-3=3+b-3\\5=b[/tex]

Therefore, the y-intercept is 5. Plug this back into [tex]y=\frac{1}{2}x+b[/tex]:

[tex]y=\frac{1}{2}x+5[/tex]

I hope this helps!

What is the volume of a cone with a height of 27 cm
and a radius of 13 cm? Round your answer to the
nearest tenth.
Use the button on your calculator to complete this
problem.
V=
cm3

Answers

Answer:4778.3 cm^3

Step-by-step explanation: The formula for volume of a cone is V=1/3h pi r^2. By plugging in the height and the radius we get our answer.

Answer:

4778.4 :)

Step-by-step explanation:

A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. The numbers y of cell sites from 1985 through 2011 can be modeled byy = 269573/1+985e^-0.308t where t represents the year, with t = 5 corresponding to 1985. Use the model to find the numbers of cell sites in the years 1998, 2003, and 2006.

Answers

Answer:

(a) 3178

(b) 14231

(c) 33152

Step-by-step explanation:

Given

[tex]y = \frac{269573}{1+985e^{-0.308t}}[/tex]

Solving (a): Year = 1998

1998 means t = 8 i.e. 1998 - 1990

So:

[tex]y = \frac{269573}{1+985e^{-0.308*8}}[/tex]

[tex]y = \frac{269573}{1+985e^{-2.464}}[/tex]

[tex]y = \frac{269573}{1+985*0.08509}[/tex]

[tex]y = \frac{269573}{84.81365}[/tex]

[tex]y = 3178[/tex] --- approximated

Solving (b): Year = 2003

2003 means t = 13 i.e. 2003 - 1990

So:

[tex]y = \frac{269573}{1+985e^{-0.308*13}}[/tex]

[tex]y = \frac{269573}{1+985e^{-4.004}}[/tex]

[tex]y = \frac{269573}{1+985*0.01824}[/tex]

[tex]y = \frac{269573}{18.9664}[/tex]

[tex]y = 14213[/tex] --- approximated

Solving (c): Year = 2006

2006 means t = 16 i.e. 2006 - 1990

So:

[tex]y = \frac{269573}{1+985e^{-0.308*16}}[/tex]

[tex]y = \frac{269573}{1+985e^{-4.928}}[/tex]

[tex]y = \frac{269573}{1+985*0.00724}[/tex]

[tex]y = \frac{269573}{8.1314}[/tex]

[tex]y = 33152[/tex] --- approximated

Please explain the misleading

Answers

There are more compact cars (4*10 = 40) compared to trucks (2*10 = 20); however, the pictogram might make it appear that there are more trucks because the individual truck icon is larger compared to an individual compact car icon.

To anyone giving this image a quick glance, they may erroneously conclude that there are more trucks since their eye would notice the trucks first. Also, the person might think there are more trucks because bigger sizes tend to correspond to more proportion.

In real life, a truck is larger than a compact car, but the icons need to be the same size to have the figure not be misleading.

A very similar issue happens with the mid-size cars vs the compact cars as well. The three mid-size car icons span the same total width as the compact cars do, indicating that a reader might mistakenly conclude that there are the same number of mid-size cars compared to compact ones (when that's not true either).

Could someone help me

Answers

Hello,

I have only found 113 solutions (i have num 15 given)

nb= 1         ::: 27*n +  98= 30*n + 56===> n= 1  4

nb= 2         ::: 28*n +  95= 30*n + 67===> n= 1  4

nb= 3         ::: 29*n +  65= 30*n + 17===> n= 4  8

nb= 4         ::: 29*n +  65= 30*n + 18===> n= 4  7

nb= 5         ::: 29*n +  65= 30*n + 47===> n= 1  8

nb= 6         ::: 29*n +  65= 30*n + 48===> n= 1  7

nb= 7         ::: 29*n +  74= 30*n + 16===> n= 5  8

nb= 8         ::: 29*n +  74= 30*n + 18===> n= 5  6

nb= 9         ::: 29*n +  74= 30*n + 56===> n= 1  8

nb= 10        ::: 29*n +  74= 30*n + 58===> n= 1  6

nb= 11        ::: 30*n +  16= 29*n + 74===> n= 5  8

nb= 12        ::: 30*n +  17= 29*n + 65===> n= 4  8

nb= 13        ::: 30*n +  18= 29*n + 65===> n= 4  7

nb= 14        ::: 30*n +  18= 29*n + 74===> n= 5  6

nb= 15        ::: 30*n +  47= 29*n + 65===> n= 1  8

nb= 16        ::: 30*n +  48= 29*n + 65===> n= 1  7

nb= 17        ::: 30*n +  56= 27*n + 98===> n= 1  4

nb= 18        ::: 30*n +  56= 29*n + 74===> n= 1  8

nb= 19        ::: 30*n +  58= 29*n + 74===> n= 1  6

nb= 20        ::: 30*n +  67= 28*n + 95===> n= 1  4

nb= 21        ::: 36*n +  97= 40*n + 25===> n= 1  8

nb= 22        ::: 38*n +  59= 40*n + 27===> n= 1  6

nb= 23        ::: 38*n +  65= 40*n + 27===> n= 1  9

nb= 24        ::: 38*n +  69= 40*n + 15===> n= 2  7

nb= 25        ::: 39*n +  78= 45*n + 6===> n= 1  2

nb= 26        ::: 39*n +  82= 40*n + 15===> n= 6  7

nb= 27        ::: 39*n +  82= 40*n + 17===> n= 6  5

nb= 28        ::: 39*n +  82= 40*n + 65===> n= 1  7

nb= 29        ::: 39*n +  82= 40*n + 67===> n= 1  5

nb= 30        ::: 40*n +  15= 38*n + 69===> n= 2  7

nb= 31        ::: 40*n +  15= 39*n + 82===> n= 6  7

nb= 32        ::: 40*n +  17= 39*n + 82===> n= 6  5

nb= 33        ::: 40*n +  25= 36*n + 97===> n= 1  8

nb= 34        ::: 40*n +  27= 38*n + 59===> n= 1  6

nb= 35        ::: 40*n +  27= 38*n + 65===> n= 1  9

nb= 36        ::: 40*n +  65= 39*n + 82===> n= 1  7

nb= 37        ::: 40*n +  67= 39*n + 82===> n= 1  5

nb= 38        ::: 46*n +  87= 50*n + 39===> n= 1  2

nb= 39        ::: 46*n +  87= 52*n + 9===> n= 1  3

nb= 40        ::: 47*n +  68= 50*n + 29===> n= 1  3

nb= 41        ::: 47*n +  83= 50*n + 26===> n= 1  9

nb= 42        ::: 47*n +  98= 51*n + 6===> n= 2  3

nb= 43        ::: 47*n +  98= 53*n + 2===> n= 1  6

nb= 44        ::: 48*n +  63= 50*n + 29===> n= 1  7

nb= 45        ::: 48*n +  73= 52*n + 9===> n= 1  6

nb= 46        ::: 49*n +  63= 51*n + 7===> n= 2  8

nb= 47        ::: 49*n +  72= 53*n + 8===> n= 1  6

nb= 48        ::: 49*n +  78= 52*n + 30===> n= 1  6

nb= 49        ::: 49*n +  87= 56*n + 3===> n= 1  2

nb= 50        ::: 50*n +  26= 47*n + 83===> n= 1  9

nb= 51        ::: 50*n +  29= 47*n + 68===> n= 1  3

nb= 52        ::: 50*n +  29= 48*n + 63===> n= 1  7

nb= 53        ::: 50*n +  39= 46*n + 87===> n= 1  2

nb= 54        ::: 52*n +  30= 49*n + 78===> n= 1  6

nb= 55        ::: 57*n +  92= 63*n + 8===> n= 1  4

nb= 56        ::: 58*n +  72= 60*n + 34===> n= 1  9

nb= 57        ::: 58*n +  73= 60*n + 49===> n= 1  2

nb= 58        ::: 58*n +  79= 60*n + 31===> n= 2  4

nb= 59        ::: 58*n +  97= 60*n + 13===> n= 4  2

nb= 60        ::: 59*n +  47= 62*n + 8===> n= 1  3

nb= 61        ::: 59*n +  71= 60*n + 23===> n= 4  8

nb= 62        ::: 59*n +  71= 60*n + 28===> n= 4  3

nb= 63        ::: 59*n +  71= 60*n + 43===> n= 2  8

nb= 64        ::: 59*n +  71= 60*n + 48===> n= 2  3

nb= 65        ::: 59*n +  74= 63*n + 2===> n= 1  8

nb= 66        ::: 59*n +  78= 61*n + 30===> n= 2  4

nb= 67        ::: 59*n +  84= 61*n + 30===> n= 2  7

nb= 68        ::: 59*n +  87= 61*n + 3===> n= 4  2

nb= 69        ::: 60*n +  13= 58*n + 97===> n= 4  2

nb= 70        ::: 60*n +  23= 59*n + 71===> n= 4  8

nb= 71        ::: 60*n +  28= 59*n + 71===> n= 4  3

nb= 72        ::: 60*n +  31= 58*n + 79===> n= 2  4

nb= 73        ::: 60*n +  34= 58*n + 72===> n= 1  9

nb= 74        ::: 60*n +  43= 59*n + 71===> n= 2  8

nb= 75        ::: 60*n +  48= 59*n + 71===> n= 2  3

nb= 76        ::: 60*n +  49= 58*n + 73===> n= 1  2

nb= 77        ::: 61*n +  30= 59*n + 78===> n= 2  4

nb= 78        ::: 61*n +  30= 59*n + 84===> n= 2  7

nb= 79        ::: 65*n +  89= 70*n + 24===> n= 1  3

nb= 80        ::: 68*n +  59= 72*n + 3===> n= 1  4

nb= 81        ::: 68*n +  91= 70*n + 45===> n= 2  3

nb= 82        ::: 69*n +  43= 70*n + 15===> n= 2  8

nb= 83        ::: 69*n +  43= 70*n + 18===> n= 2  5

nb= 84        ::: 69*n +  43= 70*n + 25===> n= 1  8

nb= 85        ::: 69*n +  43= 70*n + 28===> n= 1  5

nb= 86        ::: 69*n +  48= 72*n + 3===> n= 1  5

nb= 87        ::: 69*n +  52= 70*n + 14===> n= 3  8

nb= 88        ::: 69*n +  52= 70*n + 18===> n= 3  4

nb= 89        ::: 69*n +  52= 70*n + 34===> n= 1  8

nb= 90        ::: 69*n +  52= 70*n + 38===> n= 1  4

nb= 91        ::: 69*n +  54= 71*n + 8===> n= 2  3

nb= 92        ::: 69*n +  58= 73*n + 2===> n= 1  4

nb= 93        ::: 69*n +  82= 75*n + 4===> n= 1  3

nb= 94        ::: 69*n +  85= 74*n + 20===> n= 1  3

nb= 95        ::: 70*n +  14= 69*n + 52===> n= 3  8

nb= 96        ::: 70*n +  15= 69*n + 43===> n= 2  8

nb= 97        ::: 70*n +  18= 69*n + 43===> n= 2  5

nb= 98        ::: 70*n +  18= 69*n + 52===> n= 3  4

nb= 99        ::: 70*n +  24= 65*n + 89===> n= 1  3

nb= 100       ::: 70*n +  25= 69*n + 43===> n= 1  8

nb= 101       ::: 70*n +  28= 69*n + 43===> n= 1  5

nb= 102       ::: 70*n +  34= 69*n + 52===> n= 1  8

nb= 103       ::: 70*n +  38= 69*n + 52===> n= 1  4

nb= 104       ::: 70*n +  45= 68*n + 91===> n= 2  3

nb= 105       ::: 74*n +  20= 69*n + 85===> n= 1  3

nb= 106       ::: 76*n +  93= 80*n + 45===> n= 1  2

nb= 107       ::: 79*n +  45= 82*n + 6===> n= 1  3

nb= 108       ::: 79*n +  54= 83*n + 6===> n= 1  2

nb= 109       ::: 80*n +  45= 76*n + 93===> n= 1  2

nb= 110       ::: 87*n +  64= 90*n + 25===> n= 1  3

nb= 111       ::: 87*n +  65= 90*n + 23===> n= 1  4

nb= 112       ::: 90*n +  23= 87*n + 65===> n= 1  4

nb= 113       ::: 90*n +  25= 87*n + 64===> n= 1  3

Find the length of an arc that subtends a central angle of 224° in a circle of radius 20 m

Answers

Answer:

78.2m

Step-by-step explanation:

Lenght of the arc= ( circumference) × ( fraction of the circle)

Circumference=2πr = 2×20×π

Radius=20 m

fraction of the circle can be calculated as 224°/360°= 0.662

Then substitute the values we have

Lenght of the arc=

(2×20×π) ×0.662

= 78.2,

Lenght of the arc is 78.2m

Will give brainliest answer

Answers

Answer: 2/5x to the second.

may I have the brainiest? pls

What is the level of measurement for ​"year of birth​"?

Answers

interval level of mesurement

Answer:

interval?

Step-by-step explanation:

I'm not sure. I think so....hope its correct :)

A point is selected at random from a line segment of length l, dividing it into two line segments. What is the probability that the longer line segment is at least three times as long as the shorter segment

Answers

Answer:

3/4

Step-by-step explanation:

Let a be the length of the shorter line segment and b be the length of the longer line segment.

Since the length of the line segment is l, we have that the length of the line segment equals length of shorter line segment + length of longer line segment.

So, l = a + b

Since we require that the longer line segment be at least three times longer than the shorter line segment, we have that b = 3a

So, l = a + b

l = a + 3a

l = 4a

The probability that the shorter line segment will be a(or 3 times shorter than b) is P(a) = length of shorter line segment/length of line segment = a/l

Since l = 4a.

a/l = 1/4

So, P(a) = 1/4

The probability that a will be less than 3 times shorter that b is P(a ≤ 1) = P(0) + P(a) = 0 + 1/4 = 1/4

The probability that b will be 3 times or more greater than a is thus P(b ≥ 3) = 1 - P(a ≤ 1) = 1 - 1/4 = 3/4

if x can be divide by 7 and 9 without leaving a remainder, it can also divided by which number without leaving a remainder​

Answers

Answer:

all counting numbers except one

A number that can go into x would be 3

This is because 7 x 9 is 63 meaning x would be 63 and 63 divided by 3 is 21 which does NOT Leave a reminder.

Hannah ran 12 laps for 8 days. How many laps did she run in total if she take a break of 1 complete day and 1 half day.

Answers

Answer:

The correct answer would be - 9.75 laps (if runs 12 laps in 8 days) or 78 laps (if 12 laps each day for 8 days)

Step-by-step explanation:

Given:

a) Laps covered in 8 days = 12

interval = 1 and half day

total laps = ?

Solution:

To know the total laps with intervals we need to calculate the laps run each day :

= 12/8 laps per day

= 3/2 laps per day

Now multiply the daily run with days

= (3/2)*6.5              (due to 8 - 1.5 = 6,5 days)

= 9.75 laps

B) Given:

Laps covered in 8 days = 12*8 =96

interval = 1 and half day

total laps = ?

Solution:

To know the total laps with intervals we need to calculate the laps run each day :

= 96/8 laps per day

= 12laps per day

Now multiply the daily run with days

= 12*6.5              (due to 8 - 1.5 = 6,5 days)

= 78 laps

Find the simplified product:
V9x* - 33x
O
V12x12
о
327x12
O
3x4
O
9.x

Answers

9514 1404 393

Answer:

  (c)  3x^4

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

___

  [tex]\displaystyle\sqrt[3]{9x^4}\cdot\sqrt[3]{3x^8}=\sqrt[3]{9\cdot3x^4x^8}=\sqrt[3]{27x^{12}}=\sqrt[3]{(3x^4)^3}=\boxed{3x^4}[/tex]

In an international film festival, a penal of 11 judges is formed to judge the best film. At last two films FA and FB were considered to be the best where the opinion of judges got divided. Six judges where in favor of FA whereas five in favor of FB. A random sample of five judges was drawn from the panel. Find the probability that out of five judges, three are in favor of film FA.

Answers

Answer:

The answer is "0.4329 ".

Step-by-step explanation:

P( three in favor of FA)

Select 3 out of 6 FA supporters then select 2 out of 5 FB supportive judges  

[tex]=\frac{^{6}_{C_{3}}\times ^{5}_{C_{2}}}{^{11}_{C_{5}}}\\\\=\frac{\frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}}{\frac{11!}{5!(11-5)!}}\\\\=\frac{\frac{6!}{3! \times 3!}\times \frac{5!}{2! \times 3!}}{\frac{11!}{5! \times 6!}}\\\\=\frac{\frac{6 \times 5 \times 4 \times 3!}{3 \times 2 \times 1\times 3!}\times \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!}}{\frac{11 \times10 \times 9 \times 8 \times 7 \times 6! }{5 \times 4 \times 3 \times 2 \times 1 \times 6!}}\\\\[/tex]

[tex]=\frac{ (5 \times 4) \times(5 \times 2)}{(11 \times 3 \times 2 \times 7 )}\\\\=\frac{ 20 \times 10 }{(11 \times 42)}\\\\=\frac{ 200 }{462}\\\\=\frac{100 }{231}\\\\=0.4329[/tex]

ok i think you guys can do it​

Answers

[tex] {64}^{ \frac{2}{3} } \div {27}^{ \frac{5}{3} } \times 54 \\ = > \: {({2}^{3} )}^{ \frac{2}{3} } \div ({{3}^{3}})^{ \frac{5}{3} } \times 54 \\ = > \: {2}^{2} \div {3}^{5} \times 54 \\ = > \: 4 \div 243 \times 54 \\ = > \: 4 \div 13122 \\ = > \: \frac{4}{13122} \\ = > \: \frac{2}{6561} [/tex]

Hope it helps!!!!!!!!!!

((64)^1/3)^2 / ((27)^1/3)^5 x 54
= 4^2 / 3^5 x 54
= 16 x 54 / 243 [= 16 x (2 x 27) / (9 x 27)]
= 32/9

HELP!! Image inculded

Answers

Answer:

B.

[tex] \frac{ - 3}{ {x}^{2} - 5x + 6 }[/tex]

hope it helps

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