There are four primary types of motor controllers and drives: stepper, servo, DC, and AC.
Which of the following control devices is beneficial in a circuit for a motor?One of the primary motor control devices is one that attaches or detaches the motors or loads from the line. The load is connected to the line by the main control devices, which comprise the motor contactor, starter, and controller.There are four primary types of motor controllers and drives: stepper, servo, DC, and AC. Each has an input power type that has been changed to the desired output function to fit with an application.They are inverse, integral, and derivative functions. Depending on how complex a process is and how much control is needed, these control approaches may be employed alone or in combination to apply automatic control to that process.To learn more about motor controllers refer to:
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23.
The escape velocity from the surface of the Moon is 2.4 x 10³ ms ¹.
(a)
An object is projected from the surface of the Moon with a speed
of 2.0 x 10³ ms'..
Calculate the maximum height reached above the Moon's surface.
used primarily in the united states for electricity generation: blank target 1 of 8 2. remains of ancient organisms, modified underground for long periods by temperature and pressure: blank target 2 of 8 3. the world's most abundant fossil fuel: blank target 3 of 8 4. a mixture of hundreds or thousands of different hydrocarbon molecules: blank target 4 of 8 5. primary fuel used in the united states for space and water heating: blanktarget 5 of 8 6. created very slowly and considered nonrenewable at current extraction rates: blanktarget 6 of 8 7. used primarily in the united states as a source of vehicle fuels: blanktarget 7 of 8 8. produces the least carbon dioxide per unit energy when combusted: blanktarget 8 of 8
Coal used primarily in the united states for electricity generation.
A readily combustible sedimentary deposit made primarily of carbon, coal is called. Black or brownish-black in color, coal is composed of more than 50% carbonaceous material by weight and more than 70% carbonaceous material by volume (including inherent moisture). It is made of plant remains that have undergone geologic pressure and heat been compacted, hardened, chemically changed, and metamorphosed.
The majority of the sites where coal is found worldwide, including in the United States, are where ancient forests and marshes formerly stood before being buried and compacted over millions of years. In the eastern United States, in the Appalachian basin, there are some of the greatest coal resources. In the United States, coal produced 23% of the electricity in 2021, which was less than natural gas plants and more than renewable energy or nuclear power. 19% of total generating capacity was coal.
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to increase the range of the water, isabella places her thumb on the hose hole and partially covers it. assuming that the flow remains steady, what fraction f of the cross-sectional area of the hose hole does she have to cover to be able to spray her friend? assume that the cross section of the hose opening is circular with a radius of 1.5 centimeters g
Isabella needs to cover a fraction f of the cross-sectional area of the hose hole equal to 0.50 to be able to spray her friend.
What is fraction?The fraction f of the cross-sectional area of the hose hole that Isabella needs to cover depends on the desired range of the water. The range is determined by the speed of the water, which is related to the pressure of the water. Pressure is determined by the amount of water flowing through the hose, which is determined by the size of the hose opening.
To increase the range of the water, Isabella needs to decrease the size of the hose opening. This can be done by partially covering the hose hole with her thumb. The fraction f of the cross-sectional area of the hose hole that she needs to cover can be calculated using the following equation:
f = 1 - (A/A₀)
where A is the area of the partially covered hose hole and A₀ is the area of the fully opened hose hole.
For a circular hose hole with a radius of 1.5 centimeters (A₀ = 7.07 cm²), the area of the partially covered hose hole (A) can be calculated using the following equation:
A = πr²(1 - f)
where r is the radius of the hose hole (1.5 cm) and f is the fraction of the cross-sectional area of the hose hole that Isabella needs to cover.
Substituting the equation for A into the equation for f, we get:
f = 1 - (πr²(1 - f))/A₀
Solving for f, we get:
f = 1 - (πr²/A₀)
Therefore, for a circular hose hole with a radius of 1.5 centimeters, Isabella needs to cover a fraction f of the cross-sectional area of the hose hole equal to:
f = 1 - (π × (1.5 cm)²)/(7.07 cm²)
f = 0.50
Isabella needs to cover a fraction f of the cross-sectional area of the hose hole equal to 0.50 to be able to spray her friend.
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scoutmaster greg and his scout troop are working on their orienteering merit badge. they start at an old stump n the center of a large open meadow. they first march 400m west. then they march 1000m in a directions 37 degrees south of east. they then march 1500m in a drection 53 degrees north of esat. finally they march 500m west. Find their total displacement ( magnitude and direction ) from the stump.
According to our knowledge, the distance that an object has gone or covered after five seconds is that distance.
What is the displacement?Displacement refers to a movement or displacement of an object. Changes in an object's position are referred to as displacement.Displacement refers to a movement or displacement of an object. Changes in an object's position are referred to as displacement.You have 5 seconds. It is crucial to keep in mind that the space an object covers determines its total displacement, which is why an object's total displacement after five seconds equals the distance the thing has gone in that time.According to our knowledge, the distance that an object has gone or covered after five seconds is that distance.To learn more about Displacement refer to:
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A car accelerates uniformly from rest al reaches a speed of 24.8 m/s in 10.1 s.
T
diameter of a tire is 38.9 cm.
Find the number of revolutions the ti makes during this motion, assuming no sli ping.
Answer in units of rev.
The number of revolutions is 102.655 it makes during this motion, assuming no slipping.
V= u+ at
24.8= 0 + a× 10.1
a= (24.8/10.1) m/s²
s= ut +1/2at² = at²/2
= 24.8/10.1×2 × 10.1²
=125.24m
Circumference of tire = πd. =. 3.14 × 0.389= 1.22
Total revolution= 125.24/ 1.22 = 102.655
What is acceleration?
The measurement of a change in velocity called acceleration. Acceleration typically indicates a change in speed, albeit not necessarily. An object moving in a circular path at a constant speed is still moving forward because the direction of motion is shifting. Acceleration is the rate at which an object's velocity varies in relation to time in physics. Newton's Second Law states that an object accelerates as a result of the total of all the forces acting on it. The SI system uses the meter per second squared (m s2) as the measure of acceleration.
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Students want to design an experiment to study gravity. They decide they will drop four objects with the same mass from the top of their school's bleachers. They will time how long each object takes to reach the ground. How can they improve confidence in the experiment's results? (1 point)
Drop each object 10 times and use the average of each object's fall times.
Drop all four objects at once.
Randomly select the order in which the objects are dropped.
Let a different student time the drop of each object.
The students can improve their confidence in the experiment's results by dropping each object 10 times and using the average of each object's fall times.
The correct option is A.
What is an experiment?An experiment is a technique used to confirm or deny a hypothesis, as well as assess the likelihood or effectiveness of something that has never been tried before.
Experiments show what happens when a specific factor is modified, which sheds light on cause-and-effect relationships.
By taking repeated measurements in an experiment the accuracy and confidence of the experiment's results can be improved.
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Answer:
(Question) Melissa is working on the roof of her house. She drops a hammer and a nail. Why do both objects hit the ground at the same time?
(Answer) Earth’s gravity causes both objects to fall at the same rate.
(Question) Which of the following statements about gravitational mass is true?
(Answer) Gravitational acceleration is irrespective of mass.
(Question) Two objects fall from an apartment window sill at the same time. Object 1 lands on the sidewalk in 3.6 seconds. Object 2 lands on the sidewalk in 3.3 seconds. What can be concluded about the objects?
(Answer) Object 1 has more surface area than Object 2.
(Question) A company uses drones to fly food to people in regions that have experienced natural disasters. The food is packed in boxes that are attached to parachutes. How can the company change the design of its parachute to reduce the number of boxes that are damaged when they hit the ground?
(Answer) The company can design a parachute with more surface area.
(Question) Students want to design an experiment to study gravity. They decide they will drop four objects with the same mass from the top of their school’s bleachers. They will time how long each object takes to reach the ground. How can they improve confidence in the experiment’s results?
(Answer) Drop each object 10 times and use the average of each object’s fall times.
Explanation:
i just finished the quick check
A truck weighs twice as much as a car, and is moving at twice the speed of the car
The kinetic energy of an object increases as the mass and speed increases. Here, the truck weighs twice that of car and has a twice speed then it has a kinetic energy 8 times greater than the car.
What is kinetic energy ?Kinetic energy is form of energy generated by virtue of the motion of the object. It is related to the mass and velocity of the object by the expression below:
Ke = 1/2 mv²
Let the mass and velocity of the car be m and v. Then its kinetic energy is 1/2 mv²
The mass and velocity of the truck are being 2m and 2v.
Then, kinetic energy of the truck = 1/2 2m (2v)²
Ke = 1/2 8 m v²
Therefore, the truck has 8 times the kinetic energy of the car. Hence, option d is correct.
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Your question is incomplete. But your complete question probably was:
A truck weighs twice as much as a car, and is moving at twice the speed of the car. Which statement is true about the truck's kinetic energy compared to that of the car?
a. All that can be said is that the truck has more kinetic energy.
b. The truck has twice the kinetic energy of the car.
c. The truck has 4 times the kinetic energy of the car.
d. The truck has 8 times the kinetic energy of the car.
A motorboat, which has a speed of 5 meters per sec-
ond in still water, is headed east as it crosses a river
flowing south at 3.3 meters per second. What is the
magnitude of the boat’s resultant velocity with respect
to the starting point?
1. 3.3 m/s
2. 5.0 m/s
3. 6.0 m/s
4. 8.3 m/s
The magnitude of the boat’s resultant velocity with respect to the starting point is 6.0 m/s. Hence, option (3) is correct.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
The velocity of the boat in still water = 5 meters per second along east.
The velocity of stream = 3.3 meters per second along south.
Hence, the magnitude of the boat’s resultant velocity with respect to the starting point is = √(5² + 3.3²) m/s
=6.0 m/s.
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At one time, people used to assume that poor reading abilities were caused by low
intelligence. The most thoroughly studied kind of reading problem is called dyslexia,
a learning disability which appears in elementary school readers has difficulty
learning to recognize individual words. Dyslexia can vary in seriousness from mild
forms to profound levels. In one study, researchers assessed a large number of
kindergarten and first-grade children for signs of dyslexia, and they also measured
the children's IQ using a standardized IQ measure. They found no relationship
between IQ and seriousness of dyslexia.
Choose the scatterplot below that is most consistent with the results of this
correlational study.
Poor reading skills were once thought to be the result of inferior intelligence, according to a common belief. The reading disorder known as dyslexia.
What is meant by the word "Hawthorne"? Poor reading skills were once thought to be the result of inferior intelligence, according to a common belief.The reading disorder known as dyslexia, a learning disability that manifests in elementary school readers who have trouble learning to distinguish individual words, is the most extensively researched type of reading issue.People will alter their conduct just because they are being watched, which is known as the Hawthorne Effect.One of the most well-known experiments in industrial history, which was conducted at the Western Electric factory in the Hawthorne suburb of Chicago in the late 1920s and early 1930s, gave rise to the effect.An experiment's lack of participant numbers is a common point of criticism. It is challenging to draw generalizations about a population from a tiny sample, which is the main justification for this argument.To learn more about dyslexia refer
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PLEASE HELP AS SOON AS POSSIBLE I NEED A LONG DETAILED ANSWER
According to section k of the cantilever, when a beam or frame is subjected to transverse loadings, the three potential internal forces that can be created are the normal or axial force, the shearing force, and the bending moment.
What force would it take to bring the beam to equilibrium?The object must be subject to zero net force, to start. The object's net torque must also be zero, which is the second condition. In other words, the static translational and static rotational equilibrium criteria need to be met.According to section k of the cantilever, when a beam or frame is subjected to transverse loadings, the three potential internal forces that can be created are the normal or axial force, the shearing force, and the bending moment.The object must be subject to zero net force, to start. The object's net torque must also be zero, which is the second condition.The complete question is,
What forces are at play when a beam is used?
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A basketball player grabbing a rebound jumps 80 cm vertically. How much total time (ascent and descent) does the player spend (a) in the top 10 cm of this jump and (b) in the bottom 10 cm? Do your results explain why such players seem to hang in the air at the top of a jump?
(a) The time spent by the player in the top of 10 cm of this jump is 0.14 second.
(b) The time spent by the player in the bottom 10 cm of this jump is 0.38 second.
(c) The result shows that the player spends more time during ascent and decent because of greater distance.
What is the time of motion of the player?
The time taken for the player to jump 80 cm and back to ground is calculated as follows;
t = 2 ( √ ( 2h / g ) )
where;
h is the vertical height travelled by the playerg is acceleration due to due to gravityt = 2 ( √ ( 2 x 0.8 / 9.8 ) )
t = 0.4 s
t = 0.8 second
The time spent by the player in 10 cm jump is calculated as follows;
t = √ ( 2h / g )
t = √ ( 2 x 0.1 / 9.8 )
t = 0.14 s
From 10 cm at the bottom, the player has travelled 70 cm, and the time of motion of this player is calculated as follows;
t = √ ( 2 x 0.7 / 9.8 )
t = 0.38 second
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When you perpendicular-park you should, when possible, select a space that lets you drive into the facing space so that when you leave you will:
a. Not have to back out
b. Be able to back out of your space and the one behind you giving you more practice
c. Already have your wheels straight
d. None of the above is correct
Answer:
a. Not have to back out
When you perpendicular-park, if possible, you should select a space that lets you drive into the facing space so that when you leave, you will not have to back out. This will make it easier and safer for you to exit the parking spot and get back on the road.
1)A ball with an initial velocity of 9.6 m/s rolls up a hill without slipping. a)Treating the ball as a spherical shell, calculate the vertical height it reaches in meters. b) Repeat the calculation for the same ball if it slides up the hill without rolling in m.
2) Suppose we want to calculate the moment of inertia of a 56.5 kg skater, relative to a vertical axis through their center of mass. Calculate the moment of inertia in (kg*m^2) when the skater has their arms pulled inward assuming they are cylinder of radius 0.125m
1 (a) The vertical height upto which the ball reaches will be 4.608 meters
a) We may use the theory of conservation of energy to compute the vertical height reached by the ball.
The ball's original total mechanical energy equals its ultimate potential energy.
The potential energy formula is mgh,
where m is the ball's mass,
g is the acceleration due to gravity (9.8 m/s2), and
h is the height.
The initial total mechanical energy equals the initial kinetic energy, which may be computed using the formula 1/2 * m * v2,
where v represents the beginning velocity.
By equating the two, we get:
1/2 * m * v^2 = mgh
Rearranging and solving for h:
h = v^2 / (2g)
= (9.6 m/s)^2 / (2 * 9.8 m/s^2)
= 4.608 m
b) If the ball glides up the hill without rolling, its final height will be lower than if it rolls.
As the ball slows down, part of its original kinetic energy is converted into frictional warmth, sound, and other types of internal energy.
To calculate the moment of inertia, we must first know the skater's mass distribution and the axis along which the moment of inertia is being computed.
Assuming the skater's arms are dragged inward and may be considered as cylinders with radius 0.125 m and mass m_a, the moment of inertia can be calculated as follows:
I = I_cm + m_a * r^2
where I_cm is the moment of inertia of the skater's body (assuming it can be treated as a point mass),
r is the distance from the axis of rotation to the center of mass of the cylinder (0.125 m), and
m_a is the mass of the cylinder (unknown).
To calculate I_cm, we need to know the skater's body's mass and shape. Without more information, we cannot calculate the moment of inertia.
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PLS HELP IM DESPERATE ILL GIVE 100 POINTS PLS
Answer:
1 no =5m/s
2 no=10m/s
3no=15m/s
4no=15m/s
Explanation:
why is gamma ray dangerous
Answer:
They can go through humans damaging their tissue.
Explanation:
Gamma rays are very dangerous in comparison to other rays such as radio waves as gamma rays have a higher frequency. This higher frequency gives them an immense about of energy in comparison to other waves. They have more penetrating power and are able to damage human tissue... which is dangerous.
If you throw a ball upward with an initial speed of 4m/s at 1.5m above the ground, find
c. the maximum height with respect to the ground.
Answer:
The maximum height with respect to the ground is 1.5m + 4m/s2 x (4m/s/2) = 6m.
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A roller-coaster car may be represented by a block of mass 50.0 kg . The car is released from rest at a height h = 45.0 m above the ground and slides along a frictionless track. The car encounters a loop of radius R = 15.0 m at ground level, as shown. As you will learn in the course of this problem, the initial height 45.0 m is great enough so that the car never loses contact with the track.
Part A: Find the kinetic energy K of the car at the top of the loop.
Part B: Find the minimum initial height hmin at which the car can be released that still allows the car to stay in contact with the track at the top of the loop.
b) For the car to stay just in contact with loop, normal force from loop on car should be zero.
What is force ?A force is an influence that can alter an object's motion in physics. A force can cause an object with mass to accelerate and change its velocity (for example, moving from a state of rest). Force can also be conceptualised as a push or a pull.
A force is a vector quantity since it has both magnitude and direction. It is calculated using newtons as the SI unit of measure (N). F stands for force (formerly P).
The net force acting on an object is equal to the rate at which its momentum changes over time, according to Newton's second law in its original form.
Balancing the forces on the car, centrifugal force = weight + normal force,
mv2/R = mg + 0
v2 = Rg
KE = 1/2*mv2 = 1/2*mRg
PE at the point = mg*(2R)
So, total energy = 1/2*mRg + mg*(2R) = 5/2*mgR
But total energy = mgH where H is inital height of fall.
Thus, mgH = 5/2*mgR
Thus, H = 5/2*R = 5/2*15 = 37.5 m
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Find the efficiency of a machine that does 900J of work if the input work is 1,200J
A 7.18 x10³ kg space vehicle and its empty 6.32 x10² kg booster unit are moving together through space at a speed of 369.66 m/s. An explosion lasting 2.81 s is used to separate the two parts. If the speed of the space vehicle after the separation increased to 444.57 m/s what is the magnitude force on the booster unit?
The magnitude of the force on the booster unit can be calculated using the principle of conservation of momentum. According to this principle, the momentum of a system is conserved before and after an interaction, as long as no external forces act on the system.
Before the separation, the total momentum of the system is:
m_total * v_initial = (7.18 x 10^3 kg) * (369.66 m/s)
After the separation, the momentum of the space vehicle is:
m_vehicle * v_final = (7.18 x 10^3 kg) * (444.57 m/s)
And the momentum of the booster unit is:
m_booster * v_final = (6.32 x 10^2 kg) * v_final
Since the total momentum is conserved, the initial momentum must equal the final momentum:
m_total * v_initial = m_vehicle * v_final + m_booster * v_final
Solving for v_final, we find:
v_final = (m_total * v_initial - m_vehicle * v_final) / m_booster
Now we can find the magnitude of the force on the booster unit using Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:
F = m_booster * a = m_booster * (dv/dt)
where dv/dt is the change in velocity over time, which can be approximated as (v_final - v_initial) / time.
Substituting the values we have found into this equation, we find:
F = (6.32 x 10^2 kg) * ((v_final - v_initial) / (2.81 s))
This equation can be evaluated to find the magnitude of the force on the booster unit.
a student standing on the ground throws a ball straight up. the ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground.you may want to review (page) .for help with math skills, you may want to review:quadratic equationsfor general problem-solving tips and strategies for this topic, you may want to view a video tutor solution of time in the air for a tossed ball.
Before the ball hits the ground, it is 2.8 seconds in the air. The result is obtained by using the equations in uniformly accelerated straight motion.
Uniformly Accelerated Straight MotionThe equations apply in uniformly accelerated straight motion in vertical dimension are
v₁ = v₀ + gt
v₁² = v₀² + 2gh
h = v₀t + ½ gt²
Where
v₀ = initial velocityv₁ = final velocityg = acceleration due to gravityt = timeh = height of objectA student standing on the ground throws a ball straight up with
Initial height, h₁ = 2.5 mSpeed of the ball at h₁, v₀ = 13.0 m/sFind the time it takes for the ball to reach the ground!
We use g = 9.8 m/s². See the illustration picture in the attachment!
The ball will go upward and stop at a certain height with v₁ = 0. The time needed is
v₁ = v₀ - gt₁
0 = 13.0 - 9.8t
13.0 = 9.8t
t₁ = 13.0/9.8
t₁ = 1.3 s
The height above the hand when the ball stops is
v₁² = v₀² - 2gh₂
0 = 13.0² - 2(9.8)h₂
13.0² = 2(9.8)h₂
169 = 19.6h₂
h₂ = 8,62 m
The ball stops at a height of
h₃ = h₁ + h₂
h₃ = 2.50 + 8.62
h₃ = 11.12 m
The ball goes downward and reach the ground. Initial velocity in this condition is v₁ = 0. The time needed is
h₃ = v₁t + ½ gt₂²
11.12 = 0 + ½ (9.8)t₂²
11.12 = 4.9t²
t₂² = 2.27
t₂ ≈ 1.5 s
The time that the ball in the air is
t = t₁ + t₂
t = 1.3 + 1.5
t = 2.8 s
Hence, the ball is in the air for 2.8 seconds.
Your question is incomplete, but most probably your full question was
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground. How long is the ball in the air before it hits the ground? (The student moves her hand out of the way).
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Cheetahs can accelerate to a speed of 20.0 m/s s and can continue to accelerate to reach a top speed of 29.8 m/s. Assume the acceleration is constant until the top speed is reached and is zero thereafter. Let the +x-direction point in the direction the cheetah runs.
Express the cheetah's top speed in miles per hour
The final speed of the Cheetah is 66.6607 miles per hour.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
If a body changes its velocity or direction of velocity, the physical quantity "acceleration" comes into play.
Initial speed of the Cheetah is = 20.0 m/s
Final speed of the Cheetah is = 29.8 m/s
Now 1 meter per second = 2.237 miles per hour
Hence, Final speed of the Cheetah is = 29.8 × 2.237 miles per hour
= 66.6607 miles per hour.
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Which of the following is a longitudinal wave? which of the following is a longitudinal wave?A.sound waveB.water waveC.light wave
Of the choices shown, sound wave is classified as a longitudinal wave (A)
A longitudinal wave is a type of wave that travels in a direction that is perpendicular to the motion of the particles that make up the medium in which the wave is traveling. Similar to light waves, sound waves oscillate in a direction parallel to the direction in which they propagate, producing compressions and rarefactions. Because of this, we refer to sound waves as longitudinal waves.
The particles that make up the wave do not move in the same direction as the wave; rather, they merely move back and forth in relation to their own equilibrium. Additional examples of longitudinal waves are the sound wave, the principal waves that are produced by an earthquake, ultrasound, the vibration of a spring, the fluctuation in gas, and the waves that are produced by a tsunami.
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10. Which of the following can be used to distinguish a solid ball from a hollow sphere of the same radius and mass?
(A) Measurements of the orbit of a test mass around the object.
(B) Measurements of the time it takes the object to roll down an inclined plane.
(C) Measurements of the tidal forces applied by the object to a liquid body.
(D) Measurements of the behavior of the object as it floats in water.
(E) Measurements of the force applied to the object by a uniform gravitational field
You should discover that, regardless of their exact mass or diameter, a solid object will always roll down the ramp quicker than a hollow object of the same shape (sphere or cylinder).
Do solid or hollow balls roll more quickly?You should discover that, regardless of their exact mass or diameter, a solid object will always roll down the ramp quicker than a hollow object of the same shape (sphere or cylinder).Yes, since Force=MassxAcceleration (F=MA), more force is required to move items with greater mass, and the more mass an object has, the faster it can move.Gravity is what causes a slope's change in speed. Things move more quickly when moving downhill and more slowly when moving upwards (slow down). If there is little friction on a flat surface, they will then keep moving at the same speed.To learn more about mass refer to:
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22 4 points
What is the mechanical advantage of a hydraulic system that has a small piston diameter of 6.5 inches and a large piston diameter of 20 inches?
A.8.84
B.15.35
C.9.47
D.3.7
This is 20 plus 6.5 squared, which equals.Nearly nine 478 is what this equates to.This system therefore has a 9.47 mechanical advantage.
What mechanical benefit does this hydraulic system offer? This is 20 plus 6.5 squared, which equals.Nearly nine 478 is what this equates to.This system therefore has a 9.47 mechanical advantage.In a hydraulic system, the fluid's capacity to convey pressure evenly accounts for the significant mechanical advantage.It enables you to apply a tiny amount of force to the small piston in order to generate a bigger amount of force on the large piston.The output force minus the input force is equal to the mechanical advantage.The ratio of the large piston area to the tiny piston area is the mechanical advantage of a hydraulic lift that is optimal.
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Use Gauss's theorem to prove that at the surface of a curved charged conductor, the normal derivative of the electric field is given by 譜--(1+1) 1 dE R1 R2 where Ri and R2 are the principal radii of curvature of the surface.
The normal derivative of the electric field is given by [tex]\frac{1}{E}\times\frac{dE}{dn}=-(\frac{1}{R_{1}}+\frac{1}{R_{2}} )[/tex].
The Gauss law is really applied in integral form, E da = 0.
then there is no contained charge. prior to thinking about the three-dimensional issue. Think about the similar circumstance in two dimensions.
Gauss laws therefore state that if you place a curve Gaussian box adjacent to the charged conductor's surface at a position where the radius of curvature is R.
[tex]0=\int {E.x} \, da=E_{top}\triangle a_{top} -E_{bottom}\triangle a_{bottom}[/tex]
[tex]\triangle a_{top}[/tex] and [tex]\triangle a_{bottom}[/tex] are the top and bottom portions of the box, respectively.
using [tex]\triangle a_{top}[/tex] =(R+E)d∅× dz and,
[tex]\triangle a_{bottom}[/tex]=Rd∅× dz gives
[tex]E_{bottom}=E_{top}(1+\frac{E}{R})[/tex]
This enables us to compute.
[tex]\frac{dE}{dn}= \lim_{E \to 0} \frac{E_{top}-E_{bottom}}{E} =\lim_{E \to 0}(\frac{-E_{top}}{R})= \frac{-E_{top}}{R}[/tex]
Taking into consideration that Flop is the same as E ,this may be written as
[tex]\frac{1}{E}\times\frac{dE}{dn}=-\frac{1}{R}[/tex]
This is a two-dimensional expression analogue.
Returning to the 3D issue, we will use the aforementioned methods. However, this time around, the top and bottom
[tex]\triangle a_{top}[/tex]=[tex](R_{1}+E)\times(R_{2}+E)\times[/tex]dФ
[tex]\triangle a_{bottom}[/tex]=[tex]R_{1}R_{2}[/tex]dФ
Now putting these in equation
[tex]E_{bottom}=E_{top}(1+\frac{E}{R_{1} })(1+\frac{E}{R_{2} })[/tex]
which gives,
[tex]\frac{dE}{dn}= \lim_{E \to 0} \frac{E_{top}-E_{bottom}}{E} =\lim_{E \to 0}(-E_{top}(\frac{1}{R_{1} }+\frac{1}{R_{2} }+\frac{E}{R_{1} R_{2} })=-E_{top}(\frac{1}{R_{1} }+\frac{1}{R_{2} })[/tex]
Rearranging the equation gives,
[tex]\frac{1}{E}\times\frac{dE}{dn}=-(\frac{1}{R_{1}}+\frac{1}{R_{2}} )[/tex]
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Define 1meter, 1second and 1kilogram
Answer:
Explanation:
1meter equals 100cm mt and cm are measure the distance.
1second, 60seconds equals 1minute second minute and hour meansures time.
1kg is equals 1000g and measures weight.
_____ involves relying on assumptions and beliefs about the world, whereas _____ involves making direct observations of the world.
Intuition involves relying on assumptions and beliefs about the world, whereas empirical observation involves making direct observations of the world.
Intuition refers to the process of using past experiences, beliefs, and assumptions to make quick, unconscious judgments or decisions about the world.
It is often associated with feelings or gut reactions and can be influenced by factors such as emotions, biases, and prior knowledge.
Empirical observation, on the other hand, refers to the process of gathering information about the world through direct sensory experience, such as seeing, hearing, touching, and measuring.
Empirical observations are the foundation of scientific inquiry as they provide the raw data that can be used to test and refine hypotheses and theories.
Unlike intuition, empirical observations are objective and uninfluenced by personal biases or assumptions.
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Exercise 18: Veanna is in Las Vegas waiting for her number to be called at the roulette
wheel, a large 3.0-kg disk of radius 0.60 m. What is the moment of inertia of the wheel?
The wheel's moment of inertia is a sizable 3.0-kg disk with a radius of 0.60 m and a mass of 0.54 kg/m².
Explain the moment of inertia.In physics, a body's inertial moment is a numerical representation of its resistance to having overall speed of its movement about an axis changed by that of the deployment of a torque. The axis could be local or exterior, fixed or not.
Forces of inertia: What are they?All materials share the attribute of force of inertia, which keeps them in their states—whether they are at rest and in motion an outside force is applied to cause them to change. Except when someone changes their state, bodies do not exhibit this force.
Moment of inertia,
solid disc of mass = M
radius = R
I = 1/2 MR²
= 1/2 * 3 * 0.60²
= 0.54 kg.m²
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use these expressions to find a formula for the mutual repulsive coulomb force, fcoulomb, due to like charges. this will give you a mathematical model, an equation, for fcoulomb in terms of r, l, and fgravity.
To find the formula for the mutual repulsive Coulomb force due to like charges, you can use the following equation:
Fcoulomb = (k * q1 * q2) / r²
Where k is the Coulomb constant, q1 and q2 are the charges of the two objects, and r is the distance between them.
You can also use the equation for gravitational force,
Fgravity = G * m1 * m2 / r²,
where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them. This will give you an equation for Fcoulomb in terms of r, L, and Fgravity.
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Two particles acting on a particle in opposite direction have a resultant of 10 unit if these vectors act at right angle to each other their resultant is 50 units find the magnitude of the vectors?
The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.
What is mean by magnitude of the vectors?the formula to determine the magnitude of a vector (in two dimensional space) v = (x, y) is: |v| =√(x2 + y2). This formula is derived from the Pythagorean theorem. the formula to determine the magnitude of a vector (in three dimensional space) V = (x, y, z) is: |V| = √(x2 + y2 + z2)
The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.
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