Look at the picture.

7.11 × 10⁻⁴ is the solubility (in M) of PbCl[tex]_2[/tex] in a 0.15 M solution of HCl. The Ksp of PbCl[tex]_2[/tex] is 1.6 x 10⁻⁵.

The capability of a material, the solute, to combine with another material, the solvent, is known as solubility in chemistry. Insolubility, or the solute's inability to create such a solution, is the opposite attribute.

The amount of each of the solute within a saturated solution—a solution whereby no more solute is able to be dissolved—is typically used to gauge the degree of a substance's solubility in a particular solvent.

PbCl[tex]_2[/tex] ⇌ Pb[tex]_2[/tex]⁺(x) + 2Cl⁻ (2x)

HCl ⇌H⁺ (0.15M) + Cl⁻ (0.15M)

Ksp = {Pb[tex]_2[/tex]⁺} {Cl⁻}²

Ksp = {x} {2x+ 0.15}²

2x<0.15

Ksp = {x} {0.15}²

x = 7.11 × 10⁻⁴

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The concept stoichiometry is used here to determine the moles of oxygen needed. Stoichiometry is used for the calculation of products and reactants in a chemical reaction. The number of moles of O₂ is

Chemical stoichiometry refers to the quantitative study of the reactants and products involved in a chemical reaction. It is an important concept in chemistry which use the balanced equation to calculate the amounts of reactants and products.

2C₄H₁₀ +13O₂ ⟶ 8CO₂+10H₂O  

We want to convert moles of C₄H₁₀ to moles of O₂.

Moles of O₂ = 0.78 mol C₄H₁₀ × 13 mol O₂/2 mol C₄H₁₀ = 5.07 moles

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The formation of dunite is most likely to be described by option (B) "It formed when magma cooled slowly below ground."

Dunite is an igneous rock that is composed almost entirely of olivine minerals. It is believed to form from magma that is rich in magnesium and poor in silica.

As the magma cools slowly beneath the Earth's surface, the olivine crystals have time to grow and settle out, forming a rock that is dominated by olivine.

Option (A) is more likely to describe a sedimentary rock, formed by the compaction and cementation of sediment. Option (C) is more likely to describe an extrusive igneous rock, formed from lava that cools quickly above the ground.

Option (D) is more likely to describe the formation of metamorphic rock, which is formed from existing rock that has been subjected to heat and pressure.

Hence Option B, describes the formation of dunite.

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African Americans should take advantage of their power in the labour industry and demand their rights. Therefore, the correct option is option A.

African Americans are a race of Americans who have some or all of their heritage in one of the many black racial groupings of Africa (also known as Black Americans or Americans). The phrase "African American" typically refers to people who were born in the United States but are descended from slaves from Africa.

After White Americans or Hispanic and Latino Americans, African Americans are the third-largest racial and ethnic group in the United States.  African Americans should take advantage of their power in the labour industry and demand their rights.

Therefore, the correct option is option A.

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Liters of methane at STP would be produced is 13.2L.

To solve this problem, we need to use the combined gas law to convert the initial conditions of hydrogen gas to STP:

Gas laws are a set of physical laws that describe the behavior of gases under various conditions. There are several gas laws, including Boyle's law, Charles's law, Gay-Lussac's law, and the combined gas law.

Boyle's law states that at a constant temperature, the volume of a gas is inversely proportional to its pressure. In other words, as the pressure of a gas increases, its volume decreases, and vice versa.

5.0 atm x 5.00 L x 273 K)/(1 atm x 873 K) = 123.1 L

So we now know that 5.00 L of hydrogen gas at 600°C and 95.0 atm is equivalent to 123.1 L at STP.

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If HCl, HNO3, and NaOH solutions were prepared at higher concentrations, the change in concentration will make the measurement more accurate.

Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume. Mass concentration, concentration in moles, numerical concentration, or volume concentration are four different categories of mathematical description.

Any type of chemical mixture can be referred to by the term "concentration," however solvents and solutes in solutions are most usually mentioned. If HCl, HNO3, and NaOH solutions were prepared at higher concentrations, the change in concentration will make the measurement more accurate.

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Answer:

Explanation:

1/ I

2/ III

3/ V

4/ II

5/ IV

6/ 5

7/ 55

In the formation of O2 molecule, each oxygen atom has six valence electrons. One of these electrons in each oxygen atom is unpaired.

To complete their octets, they share two electrons and form a double bond between them. This can be represented using a Lewis structure, where each oxygen atom shares two electrons with the other oxygen atom.

The valence bond picture for O2 shows two oxygen atoms with unpaired electrons, each forming a sigma bond by overlapping their 2p orbitals in the region between them. The two unpaired electrons of each oxygen atom then overlap to form a pi bond perpendicular to the plane of the sigma bond. The resulting molecule has a triple bond with a bond order of 2, consisting of one sigma bond and two pi bonds.

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Answer:

To determine the identity of metal X, we need to compare the standard reduction potentials of the possible metals with the standard reduction potential of the Mg half-reaction.

From Table 18.1, we can find the standard reduction potentials for each of the metals listed:

Pb: -0.13 V

Zn: -0.76 V

Ni: -0.25 V

Fe: -0.44 V

Mn: -1.18 V

The reduction half-reaction for the Mg electrode is:

Mg2+ + 2e- → Mg E° = -2.37 V

The overall reaction for the galvanic cell is:

Mg(s) + X2+(aq) → Mg2+(aq) + X(s)

The standard cell potential is given by:

E°cell = E°(cathode) - E°(anode)

where the cathode is the reduction half-reaction and the anode is the oxidation half-reaction.

Substituting the given values, we get:

1.61 V = E°(X2+/X) - (-2.37 V)

Simplifying, we get:

E°(X2+/X) = 1.61 V + 2.37 V = 3.98 V

Comparing E°(X2+/X) with the standard reduction potentials in Table 18.1, we see that only zinc (Zn) has a reduction potential that is more negative than 3.98 V. Therefore, the metal X is zinc (Zn).

Therefore, the answer is (b) Zn.

a) 18.2 g of N2 are created when 24.0 g of sodium azide disintegrate with 75.3% yield. The yield of 18.2 g of N2 is obtained by multiplying 24.0 g of sodium azide by 0.753.

b) The formula W = PV may be used to determine how much work was done throughout this operation. Here, the temperature (T) is 25.0°C, the volume change (V) is -1.90 m3, and the pressure (P) is 4.50 atm.

These numbers when entered into the equation result in a work of -7.48 x 105 J. This represents the labour involved in reducing the pressure from 4.50 atm to 2.60 atm.

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Answer:

The compound that is not an organic alcohol is C6H5COOH.

C3H7OH is propyl alcohol, CH3CH(OH)CH3 is 2-propanol, and (CH3)2CHCH(OH)CH2CH3 is 3-pentanol, all of which are organic alcohols.

On the other hand, C6H5COOH is benzoic acid, which is not an alcohol but an organic acid. It contains a carboxylic acid (-COOH) functional group and not the -OH functional group of alcohols.

HI is the aqueous solution which is the most acidic. Any aqueous solution in chemistry can be divided into one of three groups, including neutral, basic, or acidic solutions.

Any aqueous solution in chemistry can be divided into one of three groups, including neutral, basic, or acidic solutions. Any aqueous solution with a pH 7.0 ([H+] > 1.0 x 10-7 M) is considered an acidic solution.

Water serves as the solvent in an aqueous solution. Solutions that are acidic are sour, whereas alkaline solutions are soapy, thus it's rarely a good idea to try an unfamiliar solution. HI is the aqueous solution which is the most acidic.

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Answer:

We can use the principle of conservation of energy to solve this problem. The heat lost by the metal is equal to the heat gained by the water:

Q metal = -Q water

where Q metal is the heat lost by the metal, and Q water is the heat gained by the water.

The heat lost by the metal can be calculated using the formula:

Q metal = m metal * c metal * ΔT metal

where m metal is the mass of the metal, c metal is its specific heat, and ΔT metal is the change in temperature of the metal.

The heat gained by the water can be calculated using the formula:

Q water = m water * c water * ΔT water

where m water is the mass of the water, c water is its specific heat, and ΔT water is the change in temperature of the water.

We know the values of all the variables except c metal, so we can solve for it. We can start by calculating the values of Q metal and Q water:

Q metal = -Q water

m metal * c metal * ΔT metal = -m water * c water * ΔT water

Substituting the given values, we get:

5.4 g * c metal * (100.0 °C - T) = -142 g * 4.18 J/(g*°C) * (T - 24.2 °C)

Simplifying and solving for c metal, we get:

c metal = [142 g * 4.18 J/(g*°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]

Multiplying out, we get:

c metal = [593.56 J/(°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]

To solve for c metal, we need to find the value of T that satisfies the equation. We can do this by substituting the given value of ΔT water = 0.9 °C into the equation and solving for T:

c metal = [593.56 J/(°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]

c metal = [593.56 J/(°C) * (T - 24.2 °C)] / [540 g - 5.4 g * T]

0.9 g * [593.56 J/(°C) * (T - 24.2 °C)] = [540 g - 5.4 g * T] * c metal

535.2044 J/(°C) * (T - 24.2 °C) = 540 g * c metal - 5.4 g * T * c metal

535.2044 J/(°C) * T - 12931.7808 J = 540 g * c metal - 5.4 g * c metal * T

5.4 g * c metal * T + 535.2044 J/(°C) * T = 540 g * c metal + 12931.7808 J

T * (5.4 g * c metal + 535.2044 J/(°C)) = 540 g * c metal + 12931.7808 J

T = [540 g * c metal + 12931.7808 J] / [5.4 g * c metal + 535.2044 J/(°C)]

Substituting the given values, we get:

T = [540 g * c metal + 12931.7808 J] / [5.4 g * c metal + 535.2044 J/(°C)]

T = [540 g * c metal + 12931.7808 J] / [5.4 g * c metal + 535.2044 J/(°C)]

T ≈ 23.3 °C

Therefore, the specific heat of the metal is:

c metal = [142 g * 4.18 J/(g°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]

c metal ≈ 0.39 J/(g°C)

So the specific heat of the metal is approximately 0.39 J/(g*°C).

A 5.4 g sample of the metal is heated to the 100.0 °C and is placed in the beaker containing 142 g of the water at 24.2 °C. The specific heat of the metal is 1.322 J/ g °C.

The mass of the metal = 5.4 g

The final temperature = 25.1 °C

The initial temperature = 100 °C

The specific heat capacity of metal = x

The mass of the water = 142 g

The final temperature = 25.1 °C

The initial temperature = 24.2 °C

The specific heat capacity of water = 4.184 J/ g °C

Loss of Heat of Metal = Gain of Heat by Water

-q metal = + q metal

- 5.4 × x × ( 25.1 - 100 ) = 142 × 4.184 ( 25.1 - 24.2 )

404.46 x = 534.71

x = 1.322 J/ g °C

The specific heat capacity of metal is  1.322 J/ g °C.

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The calculated ΔH reaction will be unaffected because ΔH reaction is independent of the value of the heat capacity of the solution.

Heat of reaction is also known as enthalpy of reaction and is defined as the amount of heat energy released or absorbed during a chemical reaction that occurs at constant pressure.

It is the difference between the total enthalpy of the products and the total enthalpy of the reactants, and is usually expressed in units of joules (J) or kilojoules (kJ).

The heat capacity of the solution refers to the amount of heat required to raise the temperature of the solution by a certain amount, whereas ΔH reaction refers to the heat of the chemical reaction itself and is independent of the heat capacity of the solution.

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We study the reactions that chemists utilise to create bizarre carbon-based structures in organic chemistry.

The study of the makeup, properties, and responses of organic compounds including organic materials, or matter in any of its many forms that contains carbon atoms, is the subject of the branch of science known as organic chemistry. Their structural formula is determined by study of structure.

We will study the reactions that chemists utilise to create bizarre carbon-based structures in organic chemistry, in addition to the analytical techniques used to characterise them. We'll also consider the molecular reaction mechanisms that are driving those reactions.

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The concept Rydberg formula is used here to determine the wavelength in nanometer of the spectra lines produced in the hydrogen spectrum when an electron falls from 4th orbital to the first. Here wavelength is  -9.72 × 10⁻⁸ m and energy is 12.756 J.

The Rydberg formula is:

1 / λ = RH [ 1 / n₁² - 1 / n₂²]

1 / λ = 1.097 × 10⁷ [ 1 / 4² - 1 / 1² ] = -0.9375

1 / λ = - 10,284,375

λ = -9.72 × 10⁻⁸ m

The energy of hydrogen spectrum is:

Eₙ = -13.606 eV / n²

E₄ = -13.606 / 4² = -0.85

E₁ = -13.606 / 1 = -13.606

E = Eupper - E lower

E = -0.85 - (-13.606) = 12.756 J

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C[tex]_3[/tex]H[tex]_8[/tex](g) + 5O[tex]_2[/tex] (g) → 3CO[tex]_2[/tex] (g) + 4H[tex]_2[/tex]O(g) is the balanced chemical equation for Propane + oxygen →carbon dioxide +water.

A chemical reaction involves a procedure that causes one group of chemical components to change chemically into another. Chemical bonds among atoms are formed and broken during chemical reactions, which traditionally only involve changes in the locations of electrons.

The study of chemical processes involving unstable and radioactive elements, where both electronic or nuclear changes may take place, is known as nuclear chemistry.

Propane + oxygen →carbon dioxide +water

C[tex]_3[/tex]H[tex]_8[/tex](g) + 5O[tex]_2[/tex] (g) → 3CO[tex]_2[/tex] (g) + 4H[tex]_2[/tex]O(g)

This is a single combustion reaction

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The volume at which the balloon bursts is 150.7 L.

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas.

The combined gas law is expressed as:

(P1 x V1) / (T1) = (P2 x V2) / (T2)

We can convert the initial pressure to torr by multiplying by 760 torr/1 atm, and convert the temperatures to Kelvin by adding 273.15 to the Celsius temperatures.

Substituting the given values into the equation, we get:

(1.00 atm x 14.9 L) / (293.15 K) = [tex](26.0\ torr *V2) / (223.15 K)[/tex]

Solving for V2, we get:

V2 = [tex](1.00\ atm * 14.9 L * 223.15 K) / (293.15 K * 26.0\ torr)[/tex]

= 150.7 L

Therefore, the volume at which the balloon bursts is 150.7 L.

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The catalyst increase the speed of the reaction as it lowers the activation energy.

The catalyst will increases the rate of the reaction as it will lowers the activation energy. The catalyst will increases the rate of the reaction in the both the forward and the backward directions as it providing the alternate pathway with the lower activation energy.

Because of the activation energy is reduced, the more reactants will cross the energy barrier and it will make the rate of the reaction increases. The catalyst is increases the rate of the reaction and without itself undergoes any of the permanent chemical change.

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This question is incomplete, the complete question is :

Select the correct answer.

How does a catalyst increase the speed of a reaction?

It lowers the activation energy.

It increases the activation energy.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers. Energy storage's inherent ability to offer backup power in the event of grid failure is a feature that both residential consumers and commercial owners find highly desirable.

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The products of the alpha decay of radium-226 and the beta decay of carbon-14 are radon-222 and nitrogen-14, respectively.

The alpha decay of radium-226 results in the emission of an alpha particle, which is a helium nucleus consisting of two protons and two neutrons.

Therefore, the product of the alpha decay of radium-226 is radon-222:

Ra-226 → Rn-222 + alpha particle

On the other hand, In the case of carbon-14, beta minus decay occurs, in which a neutron is converted into a proton, and an electron and an antineutrino are emitted.

So carbon-14 becomes nitrogen-14:

C-14 → N-14 + beta particle

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--The complete Question is, What is the product of the alpha decay of radium-226 and the beta decay of carbon-14?--

Ba(OH)₂ + H₂SO₄ → BASO₄ + 2 H₂O is the correct balanced equation for the neutralized of barium hydroxide with sulfuric acid. Therefore, the correct option is option A.

A neutralisation reaction is a chemical process whereby an acid or a base combine to produce water and salt as the end products. H+ ions and OH- ions combine to generate water during a neutralisation reaction. Acid-base neutralisation is the most common type of neutralisation reaction. Ba(OH)₂ + H₂SO₄ → BASO₄ + 2 H₂O is the correct balanced equation for the neutralized of barium hydroxide with sulfuric acid.

Therefore, the correct option is option A.

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The energy levels of a sodium atom are determined by the wavelength of light emitted by it.

A sodium atom's energy levels may be determined using the equation E = hc/, where h is Planck's constant, c is the speed of light, and is the wavelength.

If the wavelength of the emitted light is 589 nm, the energy levels of the sodium atom are E = hc/589nm = 6.626 x 10-34 x 3 x 108/589 x 10-9 = 4.62 x 10-19 J. This is the energy level of the sodium atom when light with a wavelength of 589 nm is emitted.

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