Match each quadratic equation with its solution set.

Match Each Quadratic Equation With Its Solution Set.

Answers

Answer 1

Answer:

2x²-32 ⇒ x²=16⇒ (-4,4)

4x²-100 ⇒x²=25 ⇒(-5,5)

x²-55=9 ⇒x²=64 ⇒(-8,8)

x²-140=-19 ⇒x²=121 ⇒(-11,11)

2x²-18=0 ⇒x²=9 ⇒(-3,3)

Answer 2

Answer:

2x^2-32 = 0 ===> (-4,4)4x^2 -100=0 ===> (-5,5)x^2 -55=9 ==>(-8, 8)x^2-140= -19 ===>(-11 ,11)

Step-by-step explanation: Further explanation

[tex]2x^2-32=0\\\\\mathrm{Add\:}32\mathrm{\:to\:both\:sides}\\\\2x^2-32+32=0+32\\\\2x^2=32\\\\\frac{2x^2}{2}=\frac{32}{2}\\\\\mathrm{For\:}x^2=f\left(a\right)\\\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{16},\:x=-\sqrt{16}\\\\x=\sqrt{16},\:x=-\sqrt{16}\\x=4,\:x=-4[/tex]

[tex]4x^2-100=0\\\mathrm{Add\:}100\mathrm{\:to\:both\:sides}\\4x^2-100+100=0+100\\4x^2=100\\\frac{4x^2}{4}=\frac{100}{4}\\x^2=25\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{25},\:x=-\sqrt{25}\\\\x=5,\:x=-5[/tex]

[tex]x^2-140=-19\\x^2-140+140=-19+140\\x^2=121\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{121},\:x=-\sqrt{121}\\x=11,\:x=-11[/tex]

[tex]x^2-55=9\\x^2-55+55=9+55\\x^2=64\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{64},\:x=-\sqrt{64}\\x=8,\:x=-8\\[/tex]

[tex]2x^2-18=0\\2x^2-18+18=0+18\\2x^2=18\\\frac{2x^2}{2}=\frac{18}{2}\\x^2=9\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{9},\:x=-\sqrt{9}\\x=3,\:x=-3[/tex]


Related Questions

Allie, Ben, and Cliff plant ceilings in the neighborhood park. Ali plans 40% of the total number of ceiling, then place 45% of the total number of seed wings, and Cliff plans the rest of the siblings. If Cliff +84 siblings how many seedling do the three boys play together

Answers

Answer:

The number of seedlings the three boys planted together is 560 seedlings

Step-by-step explanation:

The possible information in the question are;

Percentage of the seedlings planted by Ali = 40%

Percentage of the seedling planted by Ben = 45%

The percentage of the seedling planted by Cliff = The rest of the seedling

The number of seedling planted by Cliff = 84 siblings

Therefore, the percentage of the seedling planted by Cliff = 100% - 45% - 40% = 15%

Given that Cliff planted 15% of the seedlings, we have;

15% of seedlings Cliff planted = 84

Let X = the total number of seedlings

15/100 × X = 0.15×X = 84

X = 84/0.15 = 560

The total number of seedlings = The number of seedlings the three boys planted together = 560 seedlings.

IT IS FOR NOW IM GIVING BRAINLIEST HRRY UP AND 10 POINTS Simplify the expression. What classification describes the resulting polynomial? (8x2 + 3x) − (12x2 − 1) A. linear binomial B. quadratic binomial C. quadratic trinomial D. linear monomial

Answers

Answer:

The equation would be a quadratic trinomial

Step-by-step explanation:

Step 1: Expand the equation to remove the brackets

0 = 8x² + 3x - 12x² + 1

Step 2: Collect like terms

0 = -4x² + 3x + 1

Step 3: Count number of terms

0 = -4x² + 3x + 1

1 2 3

Therefore there are 3 terms and this is a quadratic equation making the answer B, a quadratic trinomial

Do the ratios 2/3 and 12/18 form a proportion?
yes
no​

Answers

Answer:

Yes

Step-by-step explanation:

Because 12/18 = 2/3..(cancel 12 and 18 by 6)

Answer:

yes

Step-by-step explanation:

2x6=12

3x6=18

6 is the multiplying number

( the 2 equations are the same amount )

explanation pls? step by step i get confused on these questions! thank you!​

Answers

Answer:

5xyz

Step-by-step explanation:

10x^2 y^2z and 15xyz^2

Rewriting

2*5*x*x*y*y*z   and 3*5 *x*y*z*z

What is common to both terms

5 x y z

The greatest common factor is 5xyz

Answer:

the GCF is 5(xyz)

Step-by-step explanation:

For the numbers, you want to find the largest number that both of the coefficients can be divided by. I'm not sure if your answer choices include variables, but if they do, its only xyz, nothing can be squared because both equations have different variables squared.

If line ℓ is parallel to plane P, how many planes containing line ℓ can be drawn parallel to plane P?

Answers

Answer:

One

Step-by-step explanation:

Only one plane containing line ℓ can be drawn parallel to plane P

Help? Hello Help me please

Answers

Answer:

  $562.75

Step-by-step explanation:

The future value formula is good for this.

  FV = P(1 +r/n)^(nt)

where principal P is invested at annual rate r compounded n times per year for t years.

Using your numbers, we find the account value to be ...

  FV = $500(1 +.06/2)^(2·2) = $500·1.03^4 ≈ $562.75

There will be $562.75 in the account after 2 years.

Help please on question 61!!

Answers

Answer:

r = 1

Step-by-step explanation:

2πr = x

πr² = y

x = 2y

2πr = 2πr²

r = 1

Select the equivalent expression. (8^-5/2^-2)^-4 = ?
Choose 1 answer:
A. 1/8*2^2
B. 2^6/8^9
C. 8^20/2^8

Answers

Answer:

C. 8^20/2^8

Step-by-step explanation:

(8^5/2²)^4

8^20/2^8

Graphically, a point is a solution to a system of two inequalities if and only if the point lies in the shaded region of the top inequality, but not in the shaded region of the bottom inequality. lies in the shaded region of the bottom inequality, but not in the shaded region of the top inequality. lies in the shaded regions of both the top and bottom inequalities. does not lie in the shaded region of the top or bottom inequalities.

Answers

Answer:

  lies in the shaded regions of both the top and bottom inequalities

Step-by-step explanation:

For a point to be a solution of two inequalities, it must lie in both solution sets. It ...

  lies in the shaded regions of both the top and bottom inequalities

We want to define when a point is a solution of a system of inequalities, we will see that the correct option is: "lies in the shaded regions of both the top and bottom inequalities."

Just like in a system of equations, a solution of the system is must be a solution of both equations.

Here, a solution ot the system of inequalities must be at the same time a solution of each inequality.

Remember that the solutions of the inequalities are represented by shaded regions, so the point must belong to the intersection of the two shaded regions.

So the correct option is:

"lies in the shaded regions of both the top and bottom inequalities."

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PLEASE HELP! Find the coordinates of the vertices of the figure after the given transformation: T<2,3>
A. N′(−1,0),U′(1,5),L′(3,2),H′(1,−2)
B. N′(1,0),U′(3,5),L′(5,2),H′(3,−2)
C. N′(0,−2),U′(2,3),L′(4,0),H′(2,−4
D. N′(1,−1),U′(3,4),L′(5,1),H′(3,−3)

Answers

Answer:

The correct option is;

B. N'(1, 0), U'(3, 5), L'(5, 2), H'(3, -2)

Step-by-step explanation:

The coordinates of the pre-image are given as follows;

H(1, -5), N(-1, -3), U(1, 2), and L(3, -1)

The required transformation is T₍₂, ₃₎,which is a translation of (two) 2 units right and an additional  translation of (three) 3 units up, which gives the coordinates of the image as follows;

N(-1, -3) transformed by N(-1 + 2, -3 + 3)  [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] N'(1, 0)

U(1, 2) transformed by U(1 + 2, 2 + 3)  [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] U'(3, 5)

L(3, -1) transformed by L(3 + 2, -1 + 3)  [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] L'(5, 2)

H(1, -5) transformed by H(1 + 2, -5 + 3)  [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] H'(3, -2)

The coordinates of the vertices of the given figure after the given transformation, T₍₂, ₃₎, are N'(1, 0), U'(3, 5), L'(5, 2), and H'(3, -2).

Therefore, the correct option is N'(1, 0), U'(3, 5), L'(5, 2), H'(3, -2).

anyone know how to solve a functions equation such as x^2-x-x <0

Answers

Answer:

Step-by-step explanation:

[tex]x^{2} -x-x<[/tex] 0

[tex]x^{2} -2x[/tex] < 0

x^2-2x+1<1

(x-1)^2<1

-1<x-1<1

0<x<2

[tex](x-1)^{2}[/tex][tex](x-1)^{2}[/tex]

Can somebody please help me

Answers

Exact area = 25piApproximate area = 78.5

You can pick one or the other to have as your answer

===========================

Explanation:

The formula you use is

A = pi*r^2

The radius is r = d/2 = 10/2 = 5

So,

A = pi*r^2 = pi*5^2 = pi*25 = 25pi

is the exact area

Replace pi with 3.14 to get 25*pi = 25*3.14 = 78.5

which is the approximate area

To get a better approximation, you would use more decimal digits of pi.

Find the product of all real values of $r$ for which $\frac{1}{2x}=\frac{r-x}{7}$ has exactly one real solution.

Answers

Answer:

-14

Step-by-step explanation:

Observe first that $x=0$ is not a solution to the equation since it makes the denominator of $\frac{1}{2x}$ equal to 0. For $x\neq 0$, we may multiply both sides by both denominators and move all the resulting terms to the left-hand side to get $2x^2-2rx+7=0$. Observe that there are two ways the original equation could have exactly one solution. Either $2x^2-2rx+7=0$ has two solutions and one of them is 0, or else $2x^2-2rx+7=0$ has exactly one nonzero solution. By trying $x=0$, we rule out the first possibility.

Considering the expression $\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ for the solutions of $ax^2+bx+c=0$, we find that there is exactly one solution if and only if the discriminant $b^2-4ac$ is zero. Setting $(-2r)^2-4(2)(7)$ equal to 0 gives $4r^2-4(14) = 0$. Add 4(14) and divide by 4 to find $r^2=14$. The two solutions of this equation are $\sqrt{14}$ and $-\sqrt{14}$, and their product is $\boxed{-14}$.

The value of r from the given equation is r=(2x²+7)/2x.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The given equation is [tex]\frac{1}{2x}=\frac{r-x}{7}[/tex].

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

By cross multiplication, we get

7=2x(r-x)

7=2rx-2x²

2rx=7+2x²

r=(2x²+7)/2x

Therefore, the value of r from the given equation is r=(2x²+7)/2x.

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PLEASE HELP!! Find the coordinates.

Answers

Answer:

Option (D)

Step-by-step explanation:

Coordinates of the points J, E and V are,

J → (-4, -5)

E → (-4, -3)

V → (-1, -1)

This triangle is translated by the rule [tex]T_{<2,4>}[/tex] given in the question.

Coordinates of the image will follow the rule,

(x, y) → [(x + 2), (y + 4)]

following this rule coordinates of the image triangle will be,

J(-4, 5) → J'(-2, -1)

E(-4, -3) → E'(-2, 1)

V(-1, -1) → V'(1, 3)

Therefore, points given in the option (D) will be the answer.

Alonso went to the market with \$55$55dollar sign, 55 to buy eggs and sugar. He knows he needs a package of 121212 eggs that costs \$2.75$2.75dollar sign, 2, point, 75. After getting the eggs, he wants to buy as much sugar as he can with his remaining money. The sugar he likes comes in boxes that each cost \$11.50$11.50dollar sign, 11, point, 50.

Answers

Answer:

2.75+11.50S[tex]\leq[/tex]55

4

Step-by-step explanation:

The Total amount of money Alonso went to the market with is: = $55

Items to be bought includes:

eggssugar

Alonso knows that:

A pack of 12 eggs costs = $2.75 Now, he wants to use the remaining amount to purchase as much sugar as possible

Requirement for his taste for sugar:

a box of sugar he likes = $11.50

From this information, the objective would be to determine the number of sugar he can purchase with the money left after he has already bought the eggs.

To start with, the amount of money left after buying the eggs is:

= $55 - $2.75

= $52.25

Now, if a box of sugar he likes cost = $11.50

Then he will be able to purchase (x( bost of sugar with = $52.50

Now, to determine the number of boxes of sugar he can purchase, we have:

1 box of sugar = $11.50

x(box) of sugar = $52.25

[tex]\mathbf{x (box) of sugar = \dfrac{\$52.25 \times 1 box of sugar }{\$11.50}}[/tex]

x = 4.5 box of sugar

Therefore, after buying a pack of 12 eggs for = $2.75, Alonso will be able to buy [tex]\mathbf{ 4\dfrac{1}{2}}[/tex]  or 4.5 boxes of sugar.

Learn more about word problems here:

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Answer ASAP, Will give brainliest!!

Answers

Answer:

First. 115°

Second. 65°

Third. 65°

Fourth. 7

Fifth. 425.25

First

angle DAB = angle ADC (since this is an isosceles trapezoid)

Second

In a trapezoid adjacent angle are supplmentary (that is their sum is 180°)

180-115 is 65°

Third

(Same reason as second)

Fourth

The side 3x+4 is same as the opposite side

So 3x + 4 = 25

on solving you get x = 7 in

Fifth

[tex]area \: = \frac{1}{2} \times length \: of \: the \: perpendicular \: (b1 + b2)[/tex]

area = 1/2 × 13.5 (20+43)

area = 1/2 × 13.5 × 63

Thus area is 425.25

Answer:

Step-by-step explanation:

1)As ABCD is isosceles trapezium,

∠ADC= ∠DAB

∠ADC = 115°

2) AD //BC

∠ADC + ∠DCB = 180°   {co interior angles}

115 + ∠DCB = 180

 ∠DCB = 180 - 115

 ∠DCB = 65°

3) As ABCD is isosceles trapezium,

∠CBA = ∠DCB

∠CBA = 65°

4) As ABCD is isosceles trapezium, non parallel sides are congruent.

AB = DC

3x + 4 = 25 in

3x = 25 - 4

3x = 21

x = 21/3

x = 7 in

5) height = 13.5 in

a= 43 in

b= 20 in

Area of trapezium = [tex]\frac{(a+b)*h}{2}\\[/tex]

                   [tex]= \frac{(43 +20)*13.5}{2}\\\\=\frac{63*13.5}{2}\\\\\\= 425.25 in^{2}[/tex]

The length of a rectangle is 3 inches more than its width. The perimeter of the rectangle is 34 inches. The length of the rectangle is inches, and its width is inches.

Answers

Answer: Width= 7 in.

               Length= 10 in.

Step-by-step explanation:

[tex]l=w+3[/tex]

The perimeter of the rectangle is 34 inches.

[tex]2(w+l)=34[/tex]

substitute

[tex]2(w+w+3)=34[/tex]

[tex]2(2w+3)=34[/tex]

distributive property [tex]a(b+c)=ab+ac[/tex]

[tex]2\cdot 2w+2\cdot 3=34[/tex]

[tex]4w+6=34[/tex]

[tex]4w+6-6=34-6[/tex]

[tex]4w=28[/tex]

divide 4 on both sides

[tex]w=7[/tex]

Width is 7 inches

substitute w=7 in equation [tex]l=w+3[/tex]

[tex]l=7+3[/tex]

[tex]l=10[/tex]

Length is 10 inches

Tell me the answer
69:?::89:36​

Answers

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Find the midpoints of the points (-3,-2) and (1,-4)

Answers

Answer: (-1,-3)

Step-by-step explanation:

midpoint formula [tex]\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)[/tex]

[tex]\left(x_1,\:y_1\right)=\left(-3,\:-2\right),\:\left(x_2,\:y_2\right)=\left(1,\:-4\right)[/tex]

[tex]\left(\frac{1-3}{2},\:\frac{-4-2}{2}\right)[/tex]

[tex](\frac{-2}{2},\frac{-6}{2})[/tex]

-2/2=-1

-6/2=-3

So the midpoint is (-1,-3)

Please mark brainliest  

Find the value of x in the figure below.
A. 25
B. 35
C. 45
D. 65

Answers

Answer:x=45

Step-by-step explanation:

THE ANSWER IS C.45 or x=25

Someone pls help . Will be marking someone brainliest !

Answers

Answer:

27.89 hours.

Step-by-step explanation:

I hope this helps! If you would like an explanation, let me know!

Answer:

First question, 28 hours

Second question, 20 minutes

Step-by-step explanation:

$9.50 for each hour + $75 for showing up on time

Let's say the employee showed up on time

(340 - 75) ÷ 9.5 = 28 hours approximately

120 ÷ 6 = 20 minutes

Which of the following statements best describes the value of the expression 9x – 3 when x = 7?A.The result is a fraction.B.The result is a prime number.C.The result is a composite number.D.The result is a whole number that is neither prime nor composite.
pz help

Answers

Answer: C.The result is a composite number.

Step-by-step explanation:

A prime number has only 2 factors ( '1' and itself). For example : 2,3,5,..

A composite number has more than 2 factors. For example : 4, 6, 8...

The given expression: [tex]9x-3[/tex]

When x= 7 , the value of the expression will be

[tex]9(7)-3= 63-3=60[/tex]

Since 60 is a composite number [ it is divisible by 2,3,4,5,6,10,12,30,60]

Hence, the correct statement is C.The result is a composite number.

Answer:

C. The result is a composite number.

Sorry! I'm in a rush but I hope you do well on your quiz! Stay brainly :)

I WANT TO PASS HIGH SCHOOL PLEASE HELP

Given that the quadrilateral EFGH is a trapezoid, m∠H = 62° and m∠HEG = 64° calculate m∠FEG

Answers

Answer:

m∠FEG == 54°

Step-by-step explanation:

you should know that m∠FEG is equal m∠EGH. this is because sides HE and FG are equal this also means opposite angles of this sides (m∠FEG and m∠EGH) are equal.

first find the measure of m∠EGH from triangle EHG.

m∠H + m∠HEG + m∠EGH= 180°

62° + 64° + m∠EGH = 180°

m∠EGH=180° - 126°

m∠EGH=54°

due to the fact that sides HE and FG are equal thus opposite angles of sides HE and FG are also equal.

m∠FEG = m∠EGH = 54°

m∠FEG =54°

If an arrow is shot upward on Mars with a speed of 62 m/s, its height in meters t seconds later is given by y = 62t − 1.86t². (Round your answers to two decimal places.) Estimate the speed when t = 1. Can you please show me the steps to solve this?

Answers

Answer:

Approximately [tex]58.28\; \rm m \cdot s^{-1}[/tex].

Step-by-step explanation:

The velocity of an object is the rate at which its position changes. In other words, the velocity of an object is equal to the first derivative of its position, with respect to time.

Note that the arrow here is launched upwards. (Assume that the effect of wind on Mars is negligible.) There would be motion in the horizontal direction. The horizontal position of this arrow will stays the same. On the other hand, the vertical position of this arrow is the same as its height: [tex]y = 62\, t - 1.86\, t^2[/tex].

Apply the power rule to find the first derivative of this [tex]y[/tex] with respect to time [tex]t[/tex].

By the power rule:

the first derivative of [tex]t[/tex] (same as the first derivative of [tex]t^2[/tex] (same as [tex]t[/tex] to the second power) with respect to

Therefore:

[tex]\begin{aligned}\frac{dy}{d t} &= \frac{d}{d t}\left[62 \, t - 1.86\, t^2\right] \\ &= 62\,\left(\frac{d}{d t}\left[t\right]\right) - 1.86\, \left(\frac{d}{d t}\left[t^2\right]\right) \\ &= 62 \times 1 - 1.86\times\left(2\, t) = 62 - 3.72\, t\end{aligned}[/tex].

In other words, the (vertical) velocity of this arrow at time [tex]t[/tex] would be [tex](62 - 3.72\, t)[/tex] meters per second.

Evaluate this expression for [tex]t = 1[/tex] to find the (vertical) velocity of this arrow at that moment: [tex]62 - 3.72 \times 1 =58.28[/tex].

Answer:

58.28 m/s

Step-by-step explanation:

y = 62t - 1.86t²

Speed, S = dy/dt = 62 - 2(1.86)t

S = 62 - 3.72t

When t = 1

S = 62 - 3.72 = 58.28 m/s

Find x

A. 4√6
B. 4√6/3
C. 16√6/3
D. 32√3/3

Answers

Answer:

C

Step-by-step explanation:

let hypotenuse of triangle with 60°=y

[tex]\frac{8\sqrt{2}}{y} =sin ~60\\8 \sqrt{2}=y \times \frac{\sqrt{3}}{2} \\y=\frac{16 \sqrt{2}}{\sqrt{3}} =\frac{16 \sqrt{6}}{3}[/tex]

Two trees are growing in a clearing. The first tree is 17 feet tall and casts a 10 foot shadow. The second tree casts a 35 foot shadow. How tall is the
second tree to the nearest tenth of a foot?

Answers

Answer:

59.5 feet

Step-by-step explanation:

The second tree is 59.5 feet tall.

Given

Two trees are growing in a clearing.

The first tree is 17 feet tall and casts a 10-foot shadow.

The second tree casts a 35-foot shadow.

Let x be the tall is the second tree.

Then,

The ratio of the height of the tree is;

[tex]\rm \dfrac{17}{10} = \dfrac{x}{35}\\\\17 \times 35 = x \times 10\\\\595 = 10x\\\\x = \dfrac{595}{10}\\\\x = 59.5 \ feet[/tex]

Hence, the second tree is 59.5 feet tall.

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10. In 2005 there were 9 million bicycles in Beijing, correct to the
nearest million.
The average distance travelled by each bicycle in one day was
6.5 km correct to one decimal place.
Work out the upper bound for the total distance travelled by all the
bicycles in one day,

Answers

Answer:

Total distance = 6,540,000 km

Step-by-step explanation:

Given

Number of bicycles = 9,000,000

Average Distance = 6.5 km (to 1 d.p)

Required

Calculate the upper bound of all bicycle distance

First, we need to determine the range of the distance traveled by each bicycle;

Since, the average distance is approximated, then the Range is:

[tex]Range = (6.45km\ to\ 6.54km)[/tex]

All number in this range approximate to 6.5km

Note that the upper bound of the range is 6.54km;

Hence, total distance is calculated as thus;

[tex]Total\ distance = Number\ of\ bicycle * upper\ bound[/tex]

[tex]Total\ distance = 1,000,000 * 6.54km[/tex]

[tex]Total distance = 6,540,000km[/tex]

PLS ANSWER I WILL GIVE YOU BRAINLIST AND A THANK YOU!!

Answers

Answer:

x=45

Step-by-step explanation:

2x+45+x=180

Combine 2x and x to get 3x.

3x+45=180

Subtract 45 from both sides.

3x=180−45

Subtract 45 from 180 to get 135.

3x=135

Divide both sides by 3.

x=135/3

Divide 135 by 3

x=45

A balloon artist creates balloon hats for children at a store’s grand opening. The graph shows the number of balloons the artist has remaining, y, after creating x hats.

A coordinate plane showing Balloon Hat Creations. The x-axis shows Number of Balloon Hats and the y-axis shows Balloons Remaining. The straight line starts at (0. 500) and continues down and to the right through points, (50, 250) and ends at (100, 0).
What phrases can be used to describe the line representing the relationship between the number of balloons remaining and the number of hats created? Select three options.

positive slope
negative slope
constant slope
increasing function
decreasing function

Answers

Answer:

B, C, E

Step-by-step explanation:

I just took the test

Answer:

i dont know if im correct but

Step-by-step explanation:

B, C, and E are the right ones hope it helps

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared?

Answers

Answer:

[tex]\dfrac{1}{6561}[/tex]

Step-by-step explanation:

Given the expression [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex], Using the laws of indices to simplify the expression. The following laws will be applicable;

[tex]a^m*a^n = a^{m+n}\\(a^m)^n = a^{mn}\\[/tex]

[tex]a^{-m} = 1/a^m[/tex]

Given [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex]

open the parenthesis

[tex]= (2^{-2})^{-3}(3^{4})^{-3}* (2^{-3})^2(3^2)^2\\\\= 2^{-2*-3}* 3^{4*-3} * 2^{-3*2} * 3^{2*2}\\\\= 2^6 * 3^{-12} * 2^{-6} * 3^4\\\\collecting \ like \ terms\\\\= 2^6 * 2^{-6} * 3^{-12} * 3^4\\\\= 2^{6-6} * 3^{-12+4}\\\\= 2^0 * 3^{-8}\\\\= 1 * \frac{1}{3^8}\\ \\= \frac{1}{6561}[/tex]

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