The words with their correct definition include the following below:
1. racket - C. a piece of sports equipment used to hit a ball.
2. in fact - F. used to emphasize what is true.
3. perpendicular - E. forming a 90-degree angle.
4. opposing - B. completely different in direction or position.
5. inelastic - D. not able to stretch or bend easily.
6. according to - A. as someone says or something shows.
What is Inelastic?This is a word which is is referred to as a variable not being sensitive to changes or other parameters and is also used to describe a substance which can't stretch or bend easily.
In other to emphasize something which is true or valid , in fact is used which is the correct choice.
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Use this for the day before the day of your work
The given equation is:
[tex]\frac{1}{2}mv^2+mgh=E[/tex]Note that:
The mass m is constant
Total energy E is constant
The derivative of a constant is zero
g = 9.81 m/s^2
dh/dt = v
Compute d/dt of both sides
[tex]\begin{gathered} \frac{d}{dt}(\frac{1}{2}mv^2)+\frac{d}{dt}(mgh)=\frac{dE}{dt} \\ \\ \frac{1}{2}m\frac{d}{dt}(v^2)+mg\frac{dh}{dt}=0 \\ \\ \frac{1}{2}(m)(2v)\frac{dv}{dt}+mgv=0 \\ \\ mv\frac{dv}{dt}+mgv=0 \\ \\ mv\frac{dv}{dt}+9.81mv=0 \\ \\ mv(\frac{dv}{dt}+9.81)=0 \\ \\ \frac{dv}{dt}+9.81=0 \\ \\ \frac{dv}{dt}=-9.81\text{ m/s}^2 \end{gathered}[/tex]How magnetic fields are formed?
Which thinker belongs at the beginning of Raj’s timeline?
The thinker belonging at the beginning of Raj’s timeline is Ptolemy.
Who is Ptolemy?
Claudius Ptolemy was a mathematician, astronomer, astrologer, geographer, and music theorist, who wrote about a dozen scientific treatises, three of which were of importance to later Byzantine, Islamic, and Western European science.
Ptolemy made his observations using nak-ed eyes. In his opinion, the Universe is ''a set of nested, transparent spheres, with Earth in the center. Ptolemy argued that the Moon, Mercury, Venus, and the Sun were all revolving around around Earth.
Although Ptolemy made significant contributions in Astronomy but he was wrong in his argument that the earth did not move at all.
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How long is the runway? And what is the planes take off speed
These relationships are referred to as the equation of motion.
s = ut + ½at². and v = u + at.
length of the Run way = 1350m
Take of speed of the plane is 90 m/s.
How many formulas of motion are there?We will learn how to relate quantities such as velocity, time, acceleration, and displacement as long as the acceleration is constant. These relationships are referred to as the equation of motion.The three equations of motion are as follows:
v = u + a t is the first equation of motion.s = u t + 1 /2 a t^2 is the second equation of motion. Third Element of Motion: v 2 = u 2 + 2 a sfrom equation of motion
s = ut + ½at².
here u =0 a =3 m/s^2 t= 30s
put these values on the above equation
s= 1/2x 3x 30x30= 1350 m
length of the Run way = 1350m
from equation of motion ,
v = u + at.
= 0+ 3x 30 = 90m/s.
Take of speed of the plane is 90 m/s.
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Distance = 1350m, speed = 90m/s
Given:
Initially the Aero plane is at rest. Therefore, initial velocity:
u = 0m/s
Acceleration = 3m/[tex]s^{2}[/tex]
Time taken = 30 seconds
So according to question, we have to find distance & speed
How to find distance?we know that
s = ut + 1/2a[tex]t^{2}[/tex]
Putting all the values, we get S = 1350 m
Now to find speed, we know,
[tex]v^{2} = u^{2} + 2aS[/tex]
Putting all the values,
v = [tex]\sqrt{8100}[/tex]
v = 90m/s
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Kara categorized her spending for this month into four categories: Rent, Food, Fun, and Other. The amounts she spent in each category are pictured here.Food - 267Rent - 333Other - 400Fun - 200What percent of her total spending did she spend on Rent? Round your answer to the nearest whole percent
Kara spending on food $267.
Spending on rent $333.
Spending on other things $400.
Spending on fun $200.
Her total expenditure;
[tex]\begin{gathered} \text{ total expenditure}=\text{ \$267}+\text{ \$333}+\text{ \$400}+\text{ \$200} \\ =\text{ \$1200} \end{gathered}[/tex]Percentage of her total spending on rent can be calculated as,
[tex]\begin{gathered} P=\frac{\text{ spending on rent}}{\text{ total expenditure}}\times100\text{ \%} \\ =\frac{\text{ \$333}}{\text{ \$1200}}\times100\text{ \%} \\ =27.75\text{ \%} \\ \approx28\text{ \%} \end{gathered}[/tex]Therefore, the percentage of total spending she spends on rent is about 28%.
An inclined plane makes an angle of 30 degrees above the horizontal. If a block of 7 kg rests on the incline, what is the magnitude of the normal force that the incline exerts on the block?
Given data
*The given mass of the block is m = 7 kg
*The given angle is
[tex]\theta=30^0[/tex]The formula for the magnitude of the normal force that the inclined plane exerts on the block is given as
[tex]f_n=mg\cos \theta[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} f_n=(7)(9.8)\cos 30^0 \\ =59.41\text{ N} \end{gathered}[/tex]Hence, the magnitude of the normal force that the inclined plane exerts on the block is F_n = 59.41 N
Imagine you want to watch a show, and an ad comes on beforehand. The ad is from Chic Shampoo. The voiceover says, “Shampoo Chic—we're unique!”
In this scenario, you are the:
Responses
message
stereotype
receiver
sender
In this scenario, you are the Receiver.
One possible scenario is moving to a city. The most likely scenario is he returns to school in the fall. In the best-case scenario, I'll finish the work by tomorrow. They looked at each other and weighed the situation. the sequence of events. chain of events. the course of the event. series of expansions. Your scenario is very similar to your situation, but it hasn't happened yet, and it may not happen at all.
The real world is where you actually have to live and the situations you actually have to deal with. Real-world examples are the life you are living now and the life you want to live someday. Almost any situation in which an unknown quantity exists can be described by a linear equation. To look at income over time, calculate mileage rates, and forecast profits. Many people use linear equations on a daily basis, even if they don't draw line graphs and do the calculations in their heads.
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Answer:
Receiver.
Explanation:
Optics 1. An object 2 cm high is placed 30 cm from a concave mirror with a radius of curvature of 10 cm. Find the position and size of the image.
Size of the image 0.4cm
Distance u =−30cm
Height h = 2cm
Radius of curvature R = 10cm
We know that,
-f = R/2 = 10/2 = -5 cm
Now, using the mirror’s formula
1/f = (1/v) + (1/u)
-1/5 = (1/v) - (1/30)
v = 6cm
Now, the magnification is
m = -v /u = -6 / -30 = 0.2
We know that,
m = h`/h
0.2 = h`/2
he = 0.4 cm
What is optics?Optics is the branch of physics that studies the behaviour and properties of light, including its interaction with matter and the structure of instruments that use or detect it. Optics typically describes the behaviour of visible, ultraviolet and infrared light.
Three main branches of optical science
Geometrical optics, the study of light as rays. Physical optics, the study of light as waves. Quantum optics, the study of light as particleTo learn more about optics, visit;
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if it take off a lost city of an airplane on a run away is 300 km/hr with an acceleration of 2 m/s^2 what is a takeoff time of the airplane
Given:
The take-off velocity of the plane, v=300 km/hr
The acceleration of the plane, a=2 m/s²
To find:
The takeoff time of the airplane.
Explanation:
The initial velocity of the plane, u=0 m/s
The takeoff velocity of the plane in m/s is,
[tex]\begin{gathered} v=300\times\frac{1000}{3600} \\ =83.33\text{ m/s} \end{gathered}[/tex]From the equation of motion,
[tex]v=u+at[/tex]Where t is the takeoff time of the plane.
On substituting the known values,
[tex]\begin{gathered} 83.33=0+2t \\ \Rightarrow t=\frac{83.33}{2} \\ =41.7\text{ s} \end{gathered}[/tex]Final answer:
The takeoff time of the plane is 41.7 s
Explain how the Earth, Moon, and Sun all cause the moon phases.
Answer:The sun provides the light to see the moon, while the earth casts a shadow on the moon but on full moons there is no shadow from the earth on the moon, and the moon is the thing affected by all of this
Explanation:
Newer vehicles are designed with crumple zones at the front and rear ends. Crumplezones consist of materials that deform more easily than the other regions of the car.The purpose of these zones is to increase the safety of the passengers in case of acollision. Which statement correctly explains how crumple zones reduce the impactof a collision?They extend the distance over which the impact force slows the car's motion.They convert the nature of the collision from more inelastic to more elastic.They reduce the total momentum of the system involving the colliding vehicle.They increase the mass of the vehicle relative to that of other involved objects.
They extend the distance over which the impact force slows down the car's motion
Explanations:The essence of the crumpling zone in newer cars is to convert part of the Kinetic energy of the car into a controlled deformation.
This will reduce the motion of the car at impact so that it takes a considerably longer time to stop, extend the distance over which the impact force slows down the car's motion, and reduce the shock on the passengers. This is essentially because the impact force will be reduced
A position versus time graph is shown below.
A Position versus Time graph is shown with y-axis labeled position in meters north up to 20 and x-axis labeled time in seconds up to 10. A line connects points 0, 0 and 1, 4. A horizontal line connects points 1, 4 and 4, 4. A line connects points 4, 4 and 6, 10. A horizontal line connects points 6, 10 and 8, 10. A line connects 8, 10 and 9, 14, and then 10, 15.
Use the graph to determine the instantaneous velocity in m/s of the object at 7 seconds.
0 m/s north
1.4 m/s north
7 m/s north
10 m/s north
A Position versus Time graph is shown with y-axis labeled position in meters north up to 20 and x-axis labeled time in seconds up to 10. Using the graph the instantaneous velocity in m/s of the object at 7 seconds is 0 m/s north.
What is instantaneous velocity?Instantaneous velocity is the rate of change of location over a very brief period of time (almost zero). m/s, the SI unit of measurement. The size of the immediate velocity is known as the instantaneous speed. Its value is identical to that of instantaneous velocity but lacks direction.
Given that in the graph a line connects points (0, 0) and ( 1, 4). A horizontal line connects points (1, 4) and (4, 4). A line connects points (4, 4) and (6, 10). A horizontal line connects points (6, 10) and (8, 10). A line connects (8, 10) and (9, 14) and then (10, 15). The instantaneous velocity in m/s of the object at 7 seconds is 0 m/s north.
The instantaneous velocity in m/s of the object at 7 seconds is 0 m/s north.
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The first human-made satellite, Sputnik I, had a mass of 83.4 kg and a momentum with a magnitude of 660,730 kg·m/s. What was the satellite’s speed? Round your answer to the nearest whole number.
The satellite’s speed is 7922.4 m / s if the Sputnik I, had a mass of 83.4 kg and a momentum with a magnitude of 660,730 kg·m/s.
p = m v
p = Momentum
m = Mass
v = Velocity
m = 83.4 kg
p = 660730 kg m / s
v = p / m
v = 660730 / 83.4
v = 7922.4 m / s
Momentum can be described as a mass in motion. It is the product of the object's mass and its velocity. It can also be described as the power held by a moving body that it can exert on another body.
Therefore, the satellite’s speed is 7922.4 m / s
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A physics text book has a mass of 2.2kg What is the weight on the earth
Given data
*The given mass of the physics textbook is m = 2.2 kg
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The formula for the weight of the book on the earth is given as
[tex]W=mg[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} W=(2.2)(9.8) \\ =21.56\text{ N} \end{gathered}[/tex]Find the average speed from t = 0 - 12 seconds.0.917 m/s1.25 m/s1.33 m/s0.583 m/s
Given data:
* The initial value of the time is 0 s.
* The final value of the time is 12 s.
Solution:
The average speed from the graph is,
[tex]s=\frac{\text{Total distance}}{\text{ Total time taken}}[/tex]Substituting the known values,
[tex]\begin{gathered} s=\frac{7}{12} \\ s=0.583\text{ m/s} \end{gathered}[/tex]Thus, the average speed from 0 to 12 seconds is 0.583 m/s.
Hence, fourth option is the correct answer.
19:46 Thu 20 Oct
....
Value
isaacphysics.org
Q1. Calculate the weight of the following masses, which are at the Earth's surface.
(a) For a mass of 1.5 kg, what is its weight?
Private
?
Units
Check my answer
N/kg
Calculate the weight of the following masses, which are at the Earth's surface. For a mass of 1.5 kg, its weight is (W)=14.7N
What is weight?Weight is a physical term that means that how much force of attraction is applied on the mass of the object. It can be measured in Newton and Dyne.
How can we calculate the weight?To calculate the weight we are using the formula here is,
W= mg
Here we are given,
m= mass of the object on earth. = 1.5 kg
g= The force of acceleration of the object. = 9.8m/s²
We have to calculate the value of the weight = W N.
Now we put the values in the above equation, we get
W=mg
Or, W=1.5*9.8
Or, W=14.7 N
From the calculation we can say that, For a mass of 1.5 kg, its weight is (W)=14.7N
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I really need help on questions 4&5 I’m really lost. My teacher is never there to teach the class anything and never helps :(
Q. 4:
Recall Newton's second law of motion,
[tex]F=m\cdot a[/tex]Where F is the force, m is the mass, and a is the acceleration of the object.
Re-writing the above equation
[tex]m=\frac{F}{a}[/tex]As you can see, if force is held constant then the mass of the object is inversely proportional to the acceleration of the object.
Quadrupling the mass means 4 times the mass
[tex]undefined[/tex]Daisy throws her love-lock's key horizontally with a speed of 11.0 m/s from a bridge. It falls 2.94 s before reaching the water below. What was the total speed just before hitting the water?
Daisy throws her love-lock's key horizontally with a speed of 11.0 m/s from a bridge. It falls 2.94 s before reaching the water below. the total speed just before hitting the water was 17.836 m/s.
given that :
initial velocity u = 11.0 m/s
final velocity v = 0 m/s
using the formula :
v = u + at
0 = 11 - 9.8 t
t = 1.12 sec
time taken to hit the water = 2.94 sec
bow, time taken to reach water :
t' = 2.94 - 1.12
t' = 1.82 sec
therefore , speed just before hitting the water :
v = u + at'
v = 0 + 9.8 × 1.82
v = 17.836 m/s
Thus, Daisy throws her love-lock's key horizontally with a speed of 11.0 m/s from a bridge. It falls 2.94 s before reaching the water below. the total speed just before hitting the water was 17.836 m/s.
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Car A moving in a straight line and a constant speed of 20 m/s is initially 200 m behind car b moving in the same straight line at a constant speed of 15 m/s how far must car a travel from this initial position before it catches up with car bb
The distance travelled by the car A from the initial position before it catches up with car B is 800 m.
v = d / t
v = Velocity
d = Distance
t = Time
Let x be the distance travelled by car B before car A catches up.
For car A,
v = 20 m / s
d = ( 200 + x ) m
t = d / v
t = ( 200 + x ) / 20
For car B,
v = 15 m / s
d = x m
t = x / 15
The time taken by both car A and car B before they meet up is the same.
( 200 + x ) / 20 = x / 15
3000 + 15 x = 20 x
5 x = 3000
x = 600 m
Distance travelled by the car A = 200 + x
Distance travelled by the car A = 200 + 600
Distance travelled by the car A = 800 m
Therefore, the distance travelled by the car A from the initial position before it catches up with car B is 800 m.
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An ice skater with a mass of 80 kg pushes off against a second skater with a mass of 32 kg. Both skaters are initially at rest. (a) What is the total momentum of the system after they push off? (b) If the larger skater moves off with a speed of 3 m/s, what is the corresponding speed of the smaller skater
A. The total momentum of the system after they push off is zero.
B. m1v1=m2v2
v2=m1v1/m2
v2=80*3.0/32
v2=7.5 m/s
in fact
m1v1=80*3= 240 kgm/s
m2v2= 32*7.5= 240 kgm/s.
A penny board is a type of skateboard characterized by a short, narrow deck made of plastic. If you're on the short side, consider choosing a smaller deck. Smaller decks are easier to operate and control, lighter, and more portable. If you are taller, you should choose a larger deck.
The larger deck gives more stability and power when skating. A big part of being a skater girl is looking like that which means wearing skate-branded shoes and clothes. Other skaters tend to wear these clothes cut to allow the skater's movement. Good skatesHer brands include Vans DC Nike especially basketball lines and Etnies I have.
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A group of extraterrestrial athletes travel from the Moon to Earth to train.
How would the amount of force they exert to move change on Earth?
(1 point)
O The force would be the same.
O The force needed would be less, so they would perform at a higher level.
O The force needed to move on the Earth is less than the force needed to move on the moon.
O The force would need to be greater, so they would not perform as well.
The force would need to be greater, so they would not perform as well.
Option D is the correct answer.
What is the force exerted by each extraterrestrial athletes?
The force exerted by each extraterrestrial athletes is proportional to the product of their mass and acceleration due to gravity.
Mathematically, the force exerted by each extraterrestrial athlete is given as follows;
F = mg
where;
m is mass of each extraterrestrial athleteg is acceleration due to gravity of the extraterrestrial athleteF is the force exerted by each extraterrestrial athleteThe acceleration due to gravity on moon = 1.6 m/s²
The acceleration due to gravity on Earth = 9.8 m/s²
The force exerted by each extraterrestrial athlete depends on the acceleration due to gravity since the mass will be constant.
The force required on earth will be greater than the force required to perform on moon due to greater acceleration due to gravity on earth.
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What is the term to describe the time that a force is applied to an object?
a) Inertia
b) Momentum
c) Impulse
d) Weight
Answer:
c)impulse
Explanation:
.............
The soccer player ran 50 yards in 5.1 seconds speed,acceleration,velocity
With the initial velocity of 0 m/s the final velocity will be 17.54 m/s and the acceleration will be 3.84yards/s².
What is Newton's law of motion?
Newton gave three laws of motion which can be utilized to find the velocity, acceleration and displacement of a body. These laws are only applicable for constant acceleration.
What is deacceleration in physics?
deacceleration is a physical quantity that refers to the change of velocity per unit time it decreases the velocity of the object also known as deacceleration.
given:
initial velocity of soccer player = 0 m/s
distance covered by the soccer player= 50 yards
time taken by the soccer player = 5.1 seconds
using newtons second law of motion:
i.e.
s = u × t + 0.5 × a × t²
here,
s is displacement
u is initial velocity
v is final velocity
a is constant acceleration
t is the time taken
substituting value in newtons second law of motion we get,
50 = 0 + 0.5×5.1×5.1×a
a = 3.44 yards/s²
using newtons first law of motion we get,
v = u + a × t
final velocity = 0 + 3.44×5.1
final velocity = 17.54m/s
therefore, with the initial velocity of 0 m/s the final velocity will be 17.54 m/s and the acceleration will be 3.84yards/s².
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Find the image distance of an object placed 3.00 cm in front of a convex mirror whose focal length is 8.00 cm.
Here,
object distance(u)= - 3.00cm;
focal length (f)= -8.00cm
object distance(v)= ?
Using lens formula
[tex]\begin{gathered} \frac{1}{f}\text{ = }\frac{1}{u}\text{ + }\frac{1}{v};\text{ } \\ \frac{1}{8.00}\text{ = }\frac{1}{3.00}\text{ +}\frac{1}{v}; \\ \therefore\frac{1}{v}=\text{ }\frac{1}{8}\text{ -}\frac{1}{3}=\text{ - }\frac{5}{24} \\ \therefore v=-\frac{24}{5}\text{ = -4.8 cm} \end{gathered}[/tex]Note: Here object is placed between focus and pole of the mirror as
u< f. Therefore a real and inverted image will be formed in same side that of object . So image distance have negative sigh according to sign convention.
Final answer is - 4.8 cm
As an object placed 3.00 cm in front of a convex mirror whose focal length is 8.00 cm, the image distance (di) is -24/5 cm.
The mirror equation can be used to determine the image distance (di) of an object put in front of a convex mirror:
1/f = 1/do + 1/di
Here,
f = focal length of the mirror
do = object distance
di = image distance
It is given that
Focal length = 8.00 cm
Object distance = 3.00 cm
So,
1/8.00 = 1/3.00 + 1/di
1/di = 1/8.00 - 1/3.00
1/di = (3 - 8)/(3*8) = -5/24
di = -24/5
Thus, the image distance (di) is -24/5 cm.
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A father demonstrates projectile motion to his children by placing a pea on his fork's handle and rapidly depressing the curved tines, launching the pea to heights above the dining room table. Suppose the pea is launched at 7.47 m/s at an angle of 81.0° above the table. With what speed (in m/s) does the pea strike the ceiling 2.10 m above the table?
Given
Initial velocity is u=7.47 m/s
The angle is
[tex]\theta=81^0[/tex]The vertical height travelled, h=2.10 m
To find
The final speed of the pea.
Explanation
Along the vertical direction,
The final speed is given by the equation of kinematic
[tex]v_y^2=u_y^2+2ah[/tex]Putting the values
[tex]\begin{gathered} v_y^2=(7.47sin81^o)^2+2(-9.81)\times2.1 \\ \Rightarrow v_y=3.63\text{ m/s} \end{gathered}[/tex]Along the horizontal direction,
the speed is constant throughout the projectile
Thus,
[tex]v_x=7.47cos81^0=1.168\text{ m/s}[/tex]So the final velocity of the pea is
[tex]\begin{gathered} v=\sqrt{(3.63)^2+(1.168)^2} \\ \Rightarrow v=3.81\text{ m/s} \end{gathered}[/tex]Conclusion
The final velocity is 3.81 m/s
A weight is suspended
with a rope and hangs freely. In what direction is the tension on the rope?
A. Parallel to the rope
B. Perpendicular to the rope
The force of tension is always directed Parallel to the rope and away from the mass attached.
What is Tension?Tension is a contact force that transfers by means of string or cable or, similar objects when a mass is hanged vertically by it.
Given is a weight that is suspended with a rope and hangs freely.
The Force of Tension always acts away from the mass that is hanged by it. Refer to the figure attached it will give a clear explanation of the Tension force. Since the mass is at rest, then for the mathematical analysis, we can write -
T = mg
The force of tension is equal to the weight of the mass. Talking about direction, the force of tension acts along the rope or parallel to the rope and away from the mass.
Therefore, we can say that the force of tension is always directed Parallel to the rope.
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What is true about all the horses attached to a rotating merry-go-round? Select all correct answers. - They all have the same tangential speed.- They all have the same tangential acceleration.- They all have the same angular speed.- They all have the same centripetal acceleration.- They all experience the same angular displacement.- They all have the same angular acceleration.
Answer:
They all have the same angular speed.
They all experience the same angular displacement.
They all have the same angular acceleration.
Explanation:
They all have the same angular speed because as it is moving, all points n the body has the same angular velocity. The tangential velocity varies since it depends on the position of the horse.
2) Since they have the same angular speed and the entire merry go round starts, moves and stops together, they also have the same angular acceleration.
They also have the same angular displacement
Like magnetic poles repel; unlike magnetic poles attract. Is this true or false?
ANSWER
True
EXPLANATION
We want to know if the statement is true or false.
Like electric charges where like charges repel and unlike charges attract, like magnetic poles will also repel one another (North-North or South-South) while unlike poles will attract one another (North-South or South-North)
Therefore, the statement is True.
Imagine you want to watch a show, and an ad comes on beforehand. The ad is from Chic Shampoo. The voiceover says, “Shampoo Chic—we're unique!”
In this scenario, the phrase “Shampoo Chic—we're unique!” is the:
In this scenario, the phrase Shampoo Chic we are unique is the message.
One possible scenario is moving to a city. The most likely scenario is he returns to school in the fall. In the best-case scenario, I'll finish the work by tomorrow. Uncountable noun When something happens in real life, it actually happens, not just in a story or someone's imagination. They looked at each other and weighed the situation.
The course of the event series of expansions. Your scenario is very similar to your situation, but it hasn't happened yet, and Shampoo Chic may not happen at all. A scenario is a story that unfolds as a logical consequence of previous actions or events. It is a prediction of the future and must be written as if the future were the present. A usage scenario describes how someone might use an existing product or system. A design scenario is a description of the intended use of the product or system being designed.
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how much power is delivered by the acting force over the first 6 s period?
Answer:
6 watts
Explanation:
Power is defined as
Power = Work done / time taken
Now in our case the work done is
W = F * d
For the first 6 meters, the work done is ( the area under the graph )
W = 6 * 6 = 36
Now assuming that this work was done in 6 seconds, the power delivered by the acting force is
W / t = 36 / 6 = 6 Watts
Hence the answer is 6 Watts.
