Maths problem
Mass

Solve the problems below.

1. A box has 3 books. Each book has a mass of 250g.

(a) What is their total mass? ​

Answers

Answer 1

Answer:

250 x 3 = 750g

750g is your final answer

Answer 2
You have to multiply 250 by 3 because each book weighs 250g and you have three books.
Therefore the answer is 750g

Related Questions

I need help pls !!!!!!!

Answers

The answer is c because scales are usually 2x smaller

Find the product. If the result is negative, enter "-". If the result is positive, enter "+".

-7(- a2 ) 2 ( -b3 )

Answers

Answer:

7 a⁴ b³

Step-by-step explanation:

-7 ( -a²)²( - b ³)

A negative base raised to an even power equals a positive

= -7 ( a²)² ( - b³)

Multiplying an even number of negative terms make the product positive

= - 7 ( a²)² × b³

simplify the expression by multiplying exponent

= (-7)( a²*² )× b³

= 7 a⁴ b³

Answer:

Solution given:

(-a²)=-a*-a=a²

-b³=-b*-b*-b=-b³

now

-7(-a²)²(-b³)=-7*a⁴*-b³=-7*-1 *a⁴b³=7a⁴b³

the product is 7ab³.

so

enter"+".

Find the 66th term of the arithmetic sequence 25, 10, -5, ...

Answers

Answer:

1000

Step-by-step explanation:

Given data

we have the sequence

25, 10, -5, ...

we want to find the 66th term, let us apply the formula

an = a + (n – 1)d

a= 25

n= 66

d= 15

substitute

a66= 25+(66-1)15

a66= 25+(65)*15

a66= 25+975

a66= 1000

Hence the 66th term is 1000

Miguel is trying to find the height of a radio antenna on the roof of a local building. He stands at a horizontal distance of 22 meters from the building. The angle of elevation from his eyes to the roof (point A) is 26 degrees , and the angle of elevation from his eyes to the top of the antenna ( oint B) is 31 degrees If his eyes are 1.53 meters from the ground, find the height of the antenna (the distance from point A to point B). Round your answer to the nearest tenth of a meter if necessary.

Answers

Given the 22 m. horizontal distance and the angles of elevation of 26°

and 31° gives the height of the building as approximately 2.49 meters.

How can the height of the building be found?

Horizontal distance from the building = 22 m

Angle of elevation to the top of the roof = 26°

Angle of elevation to the top of the antenna = 31°

Height of his eyes from the ground = 1.53 m

Required:

The height of the antenna.

Solution:

In a right triangle, we have relative to an angle of the triangle, we have;

Opposite side = Adjacent side

Height of the building + Height of antenna = [tex]1.53 + 22 \times tan \left(31^{\circ} \right)[/tex] ≈ 14.75

Which gives;

Height of the building = [tex]1.53 + 22 \times tan \left(26^{\circ} \right)[/tex] ≈ 12.26

Height of antenna = Height of the building + Height of antenna - Height of the building

Therefore;

Height of the antenna ≈ 14.75 - 12.26 ≈ 2.49

Height of the antenna ≈ 2.49 m

Learn more about trigonometric tangent ratio here:

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proportional linear relationships can be represented in how many different forms

Answers

Linear relationships can be represented in several different ways: a graph, an equation, or a list of points. ... We can then graph the line to find the y-intercept, and use the slope and y-intercept to write an equation of the line.

Proportional Linear Relationships can be expressed in the following ways:

a graphan equation, or a list of points.

What is a proportional linear relationship?

From a graphical point of view, a relationship is proportional and linear if the line representing the equation goes via the origin. It is to be noted that a relationship must be linear for it to be proportional and vice versa.

Thus, it is correct to state that Proportional Linear Relationships can be expressed in the following ways:

a graphan equation, or a list of points.

An example of an equation that is proportional and linear is:
y = 6x + 8. Note that this linear equation is proportional because it has a constant component.

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For a project in his Geometry class, Mamadou uses a mirror on the ground to measure the height of his school's football goalpost. He walks a distance of 13.75 meters from his school, then places a mirror on flat on the ground, marked with an X at the center. He then steps 2.6 meters to the other side of the mirror, until he can see the top of the goalpost clearly marked in the X. His partner measures the distance from his eyes to the ground to be 1.75 meters . How tall is the goalpost? Round your answer to the nearest hundredth of a meter .

Answers

Answer:

Height of the goalpost is 9.25 m.

Step-by-step explanation:

As per the rule of reflection in physics,

Angle of incidence = Angle of reflection

As we can see in the picture attached, both the angles (θ) are equal.

m∠ACB = m∠ECD = 90° - θ

m∠ABC = m∠ADC = 90°

Therefore, both the triangles ΔABC and ΔEDC will be similar.

And by the property of similar triangles, their corresponding sides will be proportional.

[tex]\frac{AB}{ED}= \frac{CB}{CD}[/tex]

[tex]\frac{1.75}{ED}=\frac{2.6}{13.75}[/tex]

ED = [tex]\frac{1.75\times 13.75}{2.6}[/tex]

ED = 9.25 m

Height of the goalpost is 9.25 m.

What is the surface area of this right circular cone?
radius=12
height=40

Answers

Answer:

2026.75 (units) squared

Step-by-step explanation:

SA of a cone = πr(r+h2+r2)

SA = π(12)(12+√(40^2)+(12^2))

SA = 12π(12+√1744)

Put in calculator and get 2026.75

A cylinder has a volume of 245x cubic units and a helght of 5 units. The diameter of the cylinder is
7 units
14 units
49 units

Answers

Answer:

Diameter = 14 units

Step-by-step explanation:

Volume ofa cylinder = πr²h

Volume of the cylinder = 245π cubic units

Height = 5 units

Volume of a cylinder = πr²h

245π = π × r² × 5

245π = 5r²π

Divide both sides by π

245π / π = 5r²π / π

245 = 5r²

r² = 245/5

= 49

r² = 49

r = √49

r = 7 units

Diameter = 2 × radius

= 2 × 7 units

= 14 units

Diameter = 14 units

(100 points)


4. MIke divided the group into 5 groups. If there were 28 people in each group how big was the original group?


a. What are they asking for? __________________


b. identify all the necessary numbers. __________________


c. write the equation or problem in numeric form. ______________


d. solve the math. ______________________________


e.write the answer. ______________________________


5. If he difference is 589 and the subtrahend is 339,what is the minuend?


a. What are they asking for? __________________


b. identify all the necessary numbers. __________________


c. write the equation or problem in numeric form. ______________


d. solve the math. ______________________________


e.write the answer. ______________________________


6. If the quotient is 17 and the dividend 765, what is the divisor?


a. What are they asking for? __________________


b. identify all the necessary numbers. __________________


c. write the equation or problem in numeric form. ______________


d. solve the math. ______________________________


e.write the answer. ______________________________

Answers

4. MIke divided the group into 5 groups. If there were 28 people in each group how big was the original group?

a. What are they asking for?

how big was the original group?

b. identify all the necessary numbers.

28,5

c. write the equation or problem in numeric form.

x=28*5

d. solve the math.

x=140

e.write the answer

. the original group contains 140 people.

5. If he difference is 589 and the subtrahend is 339,what is the minuend?

a. What are they asking for?

what is the minuend?

b. identify all the necessary numbers.

589,339

c. write the equation or problem in numeric form.

x=589-339

d. solve the math.

x=250

e.write the answer.

minuend=250

6. If the quotient is 17 and the dividend 765, what is the divisor?

a. What are they asking for?

what is the divisor?

b. identify all the necessary numbers.

17,765

c. write the equation or problem in numeric form.

x=765/17

d. solve the math.

x=45

e.write the answer.

divisor is 45.

4. Solution

a. How big was the original group?

b. 28 and 5

c. x = 28×5

d. x = 140

e. There are 140 people in original group.

5. Solution

a. What is the minuend?

b. 589 and 339

c. x = 589-339

d. x = 250

e. The minuend is 250.

6. Solution

a. What is the divisor?

b. 17 and 765

c. x = 765/17

d. x = 45

e. Hence, 45 is the divisor.

If the length of a is 6, the length of b is 4, and the length of c is 7, what is the measure of angle B

Answers

Answer:

B = 34.77°

Step-by-step explanation:

For this problem you are given all three side lengths and asked to find an angle. To do this you can use the law of cosines which is written:

[tex]b^{2} =a^{2} +c^{2} -2ac Cos(B)[/tex]

This can be rearranged to find the angle B:

[tex]b^{2} -a^{2} -c^{2} /-2ac = Cos(B)[/tex]

With lowercase letters being sides and uppercase being angles.

We simply plug in the sides and solve:

[tex]4^{2} -6^{2} -7^{2}/-2*6*7= Cos(B)[/tex]

0.8214 = Cos (B)

Then you use inverse cosine to get angle B alone.

B = 34.77°

A toy is in the form of a cone mounted on a hemisphere of common base radius 7cm. The total height of the toy is 31cm. What's the total surface area of the toy?
1  465
2  769
3  835
4  912​

Answers

[tex]\huge\tt\pink{Answer}[/tex]

A≈852.83cm²

Radius

7cm

Height

31cm

What is the equation of the line written in general form? I need the answer ASAP

Answers

Answer:

The answer is 3x-y-2=0

Step-by-step explanation:

Answer:

2nd option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate the slope using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (1, 1) and (x₂, y₂ ) = (2, 4) ← 2 points on the line

m = [tex]\frac{4-1}{2-1}[/tex] = 3

The line crosses the y- axis at (0, - 2 ) ⇒ c = - 2

y = 3x - 2 ← in slope- intercept form

subtract y from both sides

0 = 3x - y - 2 , that is

3x - y - 2 = 0 ← in general form

3( + 4) + 8 = —3
solve

Answers

3x4 to 12
12+8
Answer 20

A Warming Liquid - A liquid is taken out of a refrigerator and placed in a warmer room, where its temperature, in F, increases over time. It can be modeled using the equation Tm 74 390.87m. (a) What temperature did the liquid start at? Show the work that leads to your answer. (b) What is the temperature of the room?

Answers

Answer:

The temperature at the start is 35F

The temperature of the room is 74F

Step-by-step explanation:

Given

[tex]T(m) = 74 - 39(0.87)^m[/tex]

Solving (a): The temperature at the start.

To do this, we set: [tex]m = 0[/tex]

So, we have:

[tex]T(0) = 74 - 39(0.87)^0[/tex]

[tex]T(0) = 74 - 39*1[/tex]

[tex]T(0) = 74 - 39[/tex]

[tex]T(0) = 35[/tex]

Hence, the temperature at the start is 35F

Solving (b): The room temperature

We have:

[tex]T(m) = 74 - 39(0.87)^m[/tex]

To get the temperature of the room, we simply remove the exponential function.

So, we have:

[tex]Initial = 74[/tex]

Hence, the temperature of the room is 74F

The initial temperature of the liquid is 35 F and the room temperature is 74 F.

What is Melting Point?

The melting point is the temperature at which the solid starts converting into liquid.

Given here,

[tex]T_m = 74- 39(0.87)^m[/tex]

Leat the [tex]m = 0,[/tex]

So,

[tex]T_0 = 74- 39(0.87)^0\\\\T_0 = 35 \rm \ F[/tex]

Thus the initial temperature is 35 F.

Now remove the exponential to get the room temperature,

So,

[tex]T_{RT} = 74[/tex]

Therefore, the initial temperature of the liquid is 35 F and the room temperature is 74 F.

Learn more about the Melting point:

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If you are camping in a rural setting and look up at the night sky, it can appear as if ________.

Answers

Answer:

If you are camping in a rural setting and look up at the night sky, it can appear

If you are camping in a rural setting and look up at the night sky, it can appear as if there are many more stars visible compared to what you would see in a city or suburban area.

We have,

There is less light pollution in rural areas, allowing for a clearer view of the stars.

Here are some reasons why the night sky can appear different when camping in a rural setting:

Less light pollution:

Clearer atmosphere:

Different orientation:

Altitude:

Relaxation and focus:

Thus,

If you are camping in a rural setting and look up at the night sky, it can appear as if there are many more stars visible compared to what you would see in a city or suburban area.

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I have this math problem I can't solve.

"Evelyn and Meredith decided to kayak 1 mile up and then back in the Humboldt channel.

The rate of the water flowing in the channel was 2 miles per hour. The total time it took them to kayak up and back was 3 hours and 40 minutes. Assuming they were padding their double kayak at a fairly consistent rate, find the rate Evelyn and Meredith were paddling.

Step 2 - Draw a picture to model the problem.
Step 3 - Label variables and create a table.
Step 4 - Write an equation to model the problem.
Step 5 - Solve the equation. Provide supporting work and detail.
Step 6 - Explain the results."

If you can help please do.

Answers

Evelyn and Meredith were paddling at a rate of [tex]\frac{3+\sqrt{493}}{11}mph[/tex] which is equivalent to 2.29mph approximately.

Step 2: See attached picture

Step 3: In this case we only have different variables, there is the rate at which Evelyn and Meredith were paddling, the rate at which they moved when rowing upstream, the rate at which they moved when rowing downstream, the time it took them to paddle upstream and the time it took them to paddle downstream.

v = rate at which Evelyn and Meredith were paddling.

[tex]v_{up}[/tex]= velocity at which they were moving when paddling upstream.

[tex]v_{down}[/tex]= velocity at which they were moving when paddling downstreamstream.

[tex]t_{up}[/tex]= time it took them paddling upstream.

[tex]t_{down}[/tex]= time it took them paddling downstream

Se attached picture for the table.

Step 4: Building this equation will require us to combine different equations into a single one. Let's start with the equation for the final rate at which they paddled when rowing upstream.

[tex]v-2=v_{up}[/tex]

When rowing upstream, the current will drag the kayak, so we subtract it from the rate at which they were rowing.

Let's find the final rat at which they moved when rowing downstream.

[tex]v+2=v{down}[/tex]

next, the problem tells us it took them 3 hours and 40 minutes to row up and down the channel so we can convert it into just hours like this:

[tex]40min*\frac{1hr}{60min}=\frac{2}{3}hr[/tex]

[tex]3hr+\frac{2}{3}hr=\frac{11}{3}hr[/tex]

so now we can build our equation for time.

[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]

We also know that the rate is built by dividing the distance over the time it took them to travel the distance, so:

[tex]v_{up}=\frac{1}{t_{up}}[/tex]

[tex]v_{down}=\frac{1}{t_{down}}[/tex]

If we solved each of those equations for their respective times, we would end up with the following:

[tex]t_{up}=\frac{1}{v_{up}}[/tex]

[tex]t_{down}=\frac{1}{v_{down}}[/tex]

so we can now combine all the equations together so we get:

[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]

[tex]\frac{1}{v_{up}}+\frac{1}{v_{down}}=\frac{11}{3}[/tex]

[tex]\frac{1}{v-2}+\frac{1}{v+2}=\frac{11}{3}[/tex]

So this equation models the problem.

Step 5: We can solve this equation by multiplying everything by the LCD

In this case the LCD is:

3(v-2)(v+2)

so, when doing the respective multiplications we end up with:

[tex]\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}[/tex]

We can now simplify to get:

3(v+2)+3(v-2)=11(v+2)(v-2)

We can now do the respective multiplications to get:

[tex]3v+6+3v-6=11(v^{2}-4)[/tex]

and we can further simplify:

[tex]6v=11v^{2}-44[/tex]

Step 5: So we can now solve it by using the quadratic formula, first, we need to rewrite the equation in standard form:

[tex]11v^{2}-6v-44=0[/tex]

So we can now use the quadratic formula:

[tex]v=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]

we substitute:

[tex]v=\frac{-(-6) \pm \sqrt{(-6)^{2}-4(11)(-44)}}{2(11)}[/tex]

and simplify:

[tex]v=\frac{6 \pm \sqrt{36+1936}}{22}[/tex]

[tex]v=\frac{6 \pm \sqrt{1972}}{22}[/tex]

[tex]v=\frac{6 \pm \sqrt{4(493)}}{22}[/tex]

[tex]v=\frac{6 \pm 2\sqrt{493}}{22}[/tex]

[tex]v=\frac{3 \pm \sqrt{493}}{11}[/tex]

this gives us two possible results:

[tex]v=\frac{3 + \sqrt{493}}{11}[/tex] and [tex]v=\frac{3 - \sqrt{493}}{11}[/tex]

Step 6: We only pick the first result since it's the positive result. We don't take the second one because a negative result represents the kayak moving in the opposite direction which is not how the situation was modeled.

For further information, take a look at the following link:

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6. The coordinates of the vertices of triangle CDE are C(3, - 2), D(5, 2) , and E(7, 0) The figure is rotated 90about the origin . What are the vertices of the resulting image, Figure C'D'E?

Answers

Answer:

Step-by-step explanation:

if it is rotated in clockwise direction then C'(-2,-3),D'(2,-5),E'(0,-7)

if rotated in anticlockwise direction C'(2,3),D'(-2,5),E'(0,7)

Solve for 0 or x, round to the nearest tenth.

Answers

Answer:

theta = 44.4 degrees

Step-by-step explanation:

Since this is a right triangle, we can use trig formulas

cos theta = opposite/ hypotenuse

cos theta = 15/21

Take the inverse of each side

cos^ -1 (cos theta) = cos ^-1 (15/21)

theta =44.4153086

theta = 44.4 degrees

the volume of a swimming pool is 4x^3 - 20x^2 + 3x - 15 . what is one of the dimensions of the pool

Answers

Answer:

[tex]Height = x - 5[/tex] --- one of the dimension

Step-by-step explanation:

Given

[tex]Volume = 4x^3 - 20x^2 + 3x - 15[/tex]

Required

The side dimension

Factorize the given expression

[tex]Volume = 4x^2 (x- 5) + 3(x - 5)[/tex]

Factor out x - 5

[tex]Volume = (4x^2 + 3)(x - 5)[/tex]

Volume is the product of base area and height'

Hence:

[tex]Area = 4x^2 + 3[/tex]

[tex]Height = x - 5[/tex]

A boy bought an article for £9. He spent £4
repairing it and sold it for £18. Calculate the gain
percent on his total costs. (to nearest %)
Help

Answers

Answer:

Profit % = 39%

Step-by-step explanation:

Cost price of the article = 9

Price for repairing = 4

Therefore, Total cost of the article = 9 + 4 = 13

Selling price  of the article = 18

Profit = 18 - 13 = 5

Hence,

          [tex]Profit \% = \frac{Profit}{Cost \ price} \times 100\\\\[/tex]

                        [tex]= \frac{5}{13} \times 100\\\\=38.46 \%\\\\=38.5 \%[/tex]

Profit percent (to the nearest %) = 39%

which graph is that one of the inequality shown below?

Answers

Answer:

D

Step-by-step explanation:

The graph where the inequality is shown would be Graph D

The force of gravity on an object varies directly with its mass. The constant of variation due to gravity is 32.2 feet per second squared. Which equation represents F, the force on an object due to gravity according to m, the object’s mass?

Answers

Answer:

f=x−32

Step-by-step explanation:

Subtract 3232 from both sides.

Answer:

f=32.2m

Step-by-step explanation:

got it right on edge

evaluate log25+log8 _log2​

Answers

Step-by-step explanation:

log 25 + log 8 = log (25 × 8) = log 200

log 200 - log 2 = log (200 ÷ 2) = log 100

logarithm base 10 of 100 is 2.

find the x-intercept and y-intercept from the following linear equation: -7x+4y=56

Answers

Answer:

x-intercept = (-8,0)                         y-intercept = (0,14)

Step-by-step explanation:

-7x + 4y = 56

4y = 7x + 56

y = 7/4x + 14

y-intercept = 14

0 = 7/4x + 14

-7/4x = 14

x = -8

Meena has ₹600 in the form of notes of ₹10 and ₹20 denomination. Number of ₹10 notes is three times the number of ₹20 notes. Find the number of notes of each denomination.​

Answers

Answer:

Meena has twelve (12) ₹20 notes and thirty six (36) ₹10 notes

Step-by-step explanation:

The amount Meena has as notes in ₹10 and ₹20 denominations = ₹600

The number of ₹10 notes = 3 × The number of ₹20 notes

Let 'x' represent the number of ₹20 notes Meena has, we get;

The number of ₹10 notes = 3 × x

The total number of notes = x × 20 + 3·x × 10 = 50·x = ₹600

∴ 600/50 = 12

The number of the ₹20 notes, x = 12

The number of the ₹10 = 3 × x

∴ The number of the ₹10 = 3 × 12 = 36

What is domain and range of the following graph? 10 points!!!

Answers

Answer:

domain R

range is ] - infinity, -4]

to assure u :)

Which expression can be used to convert 22 Australian dollars to US dollars?
Assume 1.2 Australian dollars equals 1 US dollar.
O $22 AUD X
1.2 USD
1 AUD
O $22 AUD X
1 USD
1.2 AUD
O $1.20 AUD X
1 USD
1.2 AUD
O $1.20 AUD X
1.2 USD
1 AUD

Answers

Answer:

The answer is B

Step-by-step explanation:

B

The 22 Australian dollar in USD is 18.33.

What is currency?

Currency is a medium of exchange for goods or services within an economy, usually issued by a government or central bank and generally accepted at its face value.

Given that, we need to determine that there are how many USD in 22 AUD,

So, 1.2 Australian dollars equals 1 US dollar.

Therefore,

22 AUD = 22 x 1 / 1.2 = 18.33

Hence, the 22 Australian dollar in USD is 18.33.

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how do i answer this?​

Answers

Step-by-step explanation:

here is the answer. Hope that helps.

A heel travels 850 miles in 28 gallons of gas. How many miles does it travel in one gallon of gas

Answers

Answer:

850/28=30 miles a gallon

Step-by-step explanation:

mark as brainlist

y=x+2 y=-x +8 What is the solution for this system of equations?​

Answers

Answer:

x = 3     y = 5

Step-by-step explanation:

     y=x+2

+    y=-x +8

2y = 10

y = 5

y = -x + 8

5 = -x + 8

x = 3

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