measurements show that the enthalpy of a mixture of gaseous reactants increases by 397.kj during a certain chemical reaction, which is carried out at a constant pressure. furthermore, by carefully monitoring the volume change it is determined that 110.kj of work is done on the mixture during the reaction.

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Answer 1

According to given information in this reaction, the heat transferred is 287 kJ (397 kJ - 110 kJ).

In this case, the enthalpy of the mixture of gaseous reactants increases by 397 kJ during the reaction.

Additionally, the volume change during the reaction allows us to calculate the work done on the system, which is determined to be 110 kJ.

It's important to note that work done on the system is considered positive.

The relationship between heat, work, and enthalpy change is given by the equation

∆H = q + w,

where ∆H is the enthalpy change, q is the heat transferred, and w is the work done on the system.

The enthalpy change (∆H) of a chemical reaction can be determined by measuring the heat transferred at constant pressure.

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Related Questions

The maximum number of electrons that can occupy the third principal energy level is what?

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The maximum number of electrons that can occupy the third principal energy level is 18. This can be determined by using the formula 2n^2, where n represents the principal energy level. For the third energy level (n = 3), the maximum number of electrons is 2(3)^2 = 18.

The principal quantum number (n) is a fundamental concept in quantum mechanics that describes the energy level and overall size of an electron orbital in an atom. It determines the distance of an electron from the nucleus and provides information about the shell in which the electron resides.

The principal quantum number defines the energy level of an electron in an atom. Higher values of n correspond to higher energy levels, with the first energy level assigned to n = 1, the second to n = 2, and so on.

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Give a test that can be used to differentiate between saturated and unsaturated hydrocarbons.

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One test that can be used to differentiate between saturated and unsaturated hydrocarbons is the bromine test. In this test, a solution of bromine in an organic solvent, such as carbon tetrachloride, is added to the hydrocarbon.

Saturated hydrocarbons do not react with bromine under normal conditions, while unsaturated hydrocarbons readily undergo addition reactions with bromine, resulting in a color change from reddish-brown to colorless.

The bromine test relies on the reactivity difference between saturated and unsaturated hydrocarbons towards bromine. Saturated hydrocarbons have all available carbon-carbon (C-C) bonds occupied by hydrogen atoms and are considered relatively inert.

On the other hand, unsaturated hydrocarbons contain one or more carbon-carbon double or triple bonds, which provide sites of unsaturation and are more reactive.

In the bromine test, a solution of bromine in an organic solvent is added to the hydrocarbon. Bromine is a reddish-brown liquid. If the hydrocarbon is saturated, no reaction occurs, and the bromine solution retains its color. However, if the hydrocarbon is unsaturated, the double or triple bond(s) present can undergo addition reactions with bromine.

The bromine adds across the carbon-carbon double or triple bond, breaking the pi bond and forming a new single bond with each carbon atom. This results in the decolorization of the bromine solution.

By observing the color change from reddish-brown to colorless, or a significant decrease in color intensity, it can be concluded that the hydrocarbon is unsaturated. In contrast, if the color of the bromine solution remains unchanged, the hydrocarbon is likely saturated.

This test is a useful qualitative tool for distinguishing between saturated and unsaturated hydrocarbons based on their reactivity with bromine.

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Explain how the calculated percent Na2CO3 by mass would be affected if the water and excess had not been completely driven off by the time the residue is weighed. indicate clearly your reasoning.

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The calculated percent Na2CO3 by mass would be affected if the water and excess had not been completely driven off before weighing the residue.

The reason for this is that the presence of water and excess can add to the mass of the residue, resulting in an overestimation of the mass of Na2CO3. The percent Na2CO3 by mass is calculated by dividing the mass of Na2CO3 by the total mass of the sample and multiplying by 100. If water and excess are present, they will contribute to the total mass of the sample, leading to a higher denominator in the calculation. This will result in a higher calculated percent Na2CO3 by mass. Therefore, it is important to ensure that the water and excess are completely driven off before weighing the residue to obtain accurate results.

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When used as pure gases for welding ferrous metals, ____ may produce an erratic arc action, promote undercutting, and result in other flaws.

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Pure helium gas used for welding ferrous metals can cause problems like erratic arc action, undercutting, and other flaws due to its properties.

When pure gases are utilized for welding ferrous metals, certain gases can exhibit unfavorable characteristics. These gases include helium (He) and argon (Ar), which are commonly used in gas metal arc welding (GMAW) and gas tungsten arc welding (GTAW) processes. When used in their pure form, these gases may result in an erratic arc action, making it challenging to maintain a stable and controlled welding process. This erratic arc can lead to inconsistent penetration and inadequate fusion, resulting in weak welds and potential failure of the joint.

Moreover, pure helium and argon gases have lower thermal conductivity compared to other shielding gases, such as carbon dioxide (CO2) or mixtures of argon and carbon dioxide. This lower thermal conductivity can cause localized overheating, leading to excessive melting and undercutting of the base metal. Undercutting refers to the formation of grooves or depressions along the edges of the weld joint, which weakens the overall strength of the weld.

In addition, pure helium and argon gases do not provide sufficient ionization potential for stable arc initiation and maintenance. As a result, there can be arc instability, with the arc flickering or extinguishing intermittently. This instability further contributes to inconsistent weld quality and increased likelihood of defects.

To address these issues, it is common to use gas mixtures rather than pure gases for welding ferrous metals. Gas mixtures, such as argon and carbon dioxide blends, provide better arc stability, improved thermal conductivity, and enhanced penetration characteristics. These mixtures offer a more controlled welding process, reduce the likelihood of undercutting, and help produce sound and defect-free welds on ferrous metals.

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For a radical addition reaction involving hbrhbr and propene, sort each reaction step into initiation, propagation and termination steps. ch3ch=ch2 hbr−→−−−−peroxidech3ch2ch2br

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In the radical addition reaction between HBr and propene, the reaction steps can be categorized into initiation, propagation, and termination steps.

Initiation Step:

HBr → H• + •Br

Propagation Steps:

H• + CH3CH=CH2 → CH3CH•-CH2•

•Br + CH3CH=CH2 → CH3CHBr-CH2•

Termination Steps:

CH3CH•-CH2• + •Br → CH3CHBr-CH2Br

CH3CH•-CH2• + CH3CH•-CH2• → CH3CH2-CH2CH2CH3

In the initiation step, the peroxide (•) is formed by the homolytic cleavage of the H-Br bond. This peroxide radical then initiates the radical chain reaction.

In the propagation steps, the peroxide radical reacts with propene, resulting in the formation of a propyl radical (CH3CH•) and a bromine radical (•Br). These radicals can then react with additional propene molecules, leading to the continuous propagation of the reaction.

In the termination steps, the propyl radical and bromine radical combine to form the product CH3CHBr-CH2Br. Additionally, two propyl radicals can also combine to form the product CH3CH2-CH2CH2CH3.

Overall, the reaction involves initiation steps where radicals are formed, propagation steps where radicals react with propene, and termination steps where radicals combine to form products.

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What is the frequency of a helium-neon laser light with a wavelength of 632.8 nm?

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The frequency of a helium-neon laser light with a wavelength of 632.8 nm can be calculated using the formula: frequency = speed of light / wavelength

The speed of light is a constant value of approximately 3.00 x 10^8 meters per second.
Converting the wavelength from nanometers to meters:
632.8 nm = 632.8 x 10^(-9) meters
Now we can calculate the frequency:
frequency = (3.00 x 10^8 meters per second) / (632.8 x 10^(-9) meters)
The frequency of the helium-neon laser light with a wavelength of 632.8 nm is approximately 4.74 x 10^14 Hz (hertz).

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if one mole of so2 was obtained by the reaction of one mole of cs2 with o2 according to the balanced equation cs2 3o2 → co2 2so2, then which one of the following statements must be true?

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If one mole of SO2 was obtained by the reaction of one mole of CS2 with O2 according to the balanced equation CS2 + 3O2 → CO2 + 2SO2, then it means that the reaction has occurred in a 1:1 ratio.

From the balanced equation, it is clear that for every mole of CS2 reacted, two moles of SO2 are produced. It shows that for every mole of CS2, three moles of O2 are required to produce one mole of CO2 and two moles of SO2.

This implies that if we were to double the amount of CS2, we would obtain two moles of SO2. Similarly, if we were to triple the amount of CS2, we would obtain three moles of SO2. However, it is important to note that this assumption is based on the stoichiometry of the balanced equation and assumes that the reaction has gone to completion.

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Based on the balanced equation, the statement that must be true is that the ratio of moles of CS2 to moles of SO2 is 1:2.

If one mole of SO2 was obtained by the reaction of one mole of CS2 with O2 according to the balanced equation

CS2 + 3O2 → CO2 + 2SO2, then the following statement must be true:

The ratio of moles of CS2 to moles of SO2 in the balanced equation is 1:2.

In the balanced equation, the coefficient in front of CS2 is 1, and the coefficient in front of SO2 is 2. This means that for every 1 mole of CS2, 2 moles of SO2 are produced.

For example, if you start with 2 moles of CS2, according to the balanced equation, you would expect to obtain 4 moles of SO2.

Therefore, based on the balanced equation, the statement that must be true is that the ratio of moles of CS2 to moles of SO2 is 1:2.

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You add phenol red to a tube containing Elodea and let it sit in front of bright light for an hour. What color will the solution in the tube be at the end of the hour, and is the pH acidic or basic

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The solution in the tube will be yellow at the end of the hour, and the pH will be acidic.

Phenol red is a pH indicator that changes color depending on the acidity or basicity of the solution. It is red at a pH greater than 8.2, yellow at a pH less than 6.8, and transitions between orange and pink in the pH range between 6.8 and 8.2.

When Elodea, a type of aquatic plant, undergoes photosynthesis in the presence of bright light, it takes in carbon dioxide and releases oxygen. This process leads to a decrease in carbon dioxide concentration in the solution.

As carbon dioxide is dissolved in water, it forms carbonic acid (H2CO3), which increases the concentration of hydrogen ions (H+) in the solution and lowers the pH, making it acidic. The decrease in pH causes phenol red to change from its initial color to yellow.

At the end of the hour, the solution in the tube containing Elodea will be yellow, indicating an acidic pH. This change in color is due to the decrease in pH caused by the release of carbon dioxide during photosynthesis.

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study the following experimental method: determination of the organophosphate concentration of a horn sample. enzyme solution: alkaline phosphatase in 50mm tris-hcl, ph

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The Tris-HCl buffer and the specific experimental conditions (incubation time, temperature, etc.) may vary depending on the protocol used.


To determine the organophosphate concentration, alkaline phosphatase is used as it can hydrolyze the organophosphate compounds into phosphate ions. The reaction can be monitored by measuring the amount of phosphate released, which is directly proportional to the concentration of organophosphates in the sample.

Here is a step-by-step process for conducting the experiment:

1. Prepare a horn sample by extracting the organophosphates of interest.
2. Prepare the enzyme solution by diluting alkaline phosphatase in 50mM Tris-HCl buffer at the specified pH.
3. Mix the horn sample with the enzyme solution and incubate at an appropriate temperature.
4. After incubation, measure the released phosphate ions using a spectrophotometer or a colorimetric assay.
5. Compare the phosphate concentration with a standard curve generated using known concentrations of organophosphate standards.
6. Calculate the concentration of organophosphates in the horn sample based on the standard curve.

It's important to note that the pH of the Tris-HCl buffer and the specific experimental conditions (incubation time, temperature, etc.) may vary depending on the protocol used.

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What type of orbitals best describe the bond between the adjacent carbons in peroxyacetic acid?

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The bond between the adjacent carbons in peroxyacetic acid is best described by the use of sp2 hybrid orbitals.

Peroxyacetic acid (CH3COOOH) consists of a peroxy group (-O-O-) attached to an acetic acid (-COOH) molecule. The carbon-carbon bond between the adjacent carbons is formed through the overlap of atomic orbitals.

In this case, the carbon atoms are sp2 hybridized, meaning that each carbon atom forms three sigma bonds and has one unhybridized p orbital perpendicular to the plane of the molecule. The sigma bond between the adjacent carbons is formed by the overlap of two sp2 hybrid orbitals.

The sp2 hybrid orbitals are formed by mixing one s orbital and two p orbitals, resulting in three hybrid orbitals arranged in a trigonal planar geometry.

The bond between the adjacent carbons in peroxyacetic acid is best described by the use of sp2 hybrid orbitals. These orbitals result from the hybridization of one s orbital and two p orbitals, forming a sigma bond in a trigonal planar geometry between the carbon atoms.

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How much time (in s) is needed for nocl originally at a concentration of 0.0158 m to decay to 0.0024 m?

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The time required for NOCl to decay from 0.0194 M to 0.0026 M, based on the second-order decomposition reaction with a rate constant of 15.4 atm⁻¹s⁻¹ at 450 K, is approximately 5,181 seconds (s).

For a second-order reaction, the rate law is given by the equation:

Rate = k[A]²

In this case, the reaction is the decomposition of NOCl, so the rate law can be written as,

Rate = k[NOCl]²

We can rearrange the rate law equation to solve for time,

t = 1/(k[NOCl]₀) - 1 / (k[NOCl]t)

Given the initial concentration [NOCl]₀ = 0.0194 M and the final concentration [NOCl]t = 0.0026 M, and the rate constant k = 15.4 atm⁻¹s⁻¹, we can substitute these values into the equation,

t = 1 / (15.4 × 0.0194) - 1/(15.4 × 0.0026)

t ≈ 5181 s

Therefore, the time required for NOCl to decay from 0.0194 M to 0.0026 M, considering the given rate constant and reaction conditions, is approximately 5,181 seconds.

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Complete question - How much time (in s) is needed for NOCl originally at a concentration of 0.0194 M to decay to 0.0026 M?

Consider the second-order decomposition of nitroysl chloride:

2NOCl(g) → 2NO(g) + Cl₂(g)

At 450 K the rate constant is 15.4 atm⁻¹s⁻¹.

bonds are responsible for binding atoms together within a molecule of propane, whereas ________ bonds bind separate propane molecules together in a condensed stat

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Bonds are responsible for binding atoms together within a molecule of propane, whereas van der Waals bonds bind separate propane molecules together in a condensed state. Van der Waals forces are attractive or repulsive forces between atoms, molecules, or even macroscopic bodies. The forces are named after Dutch scientist Johannes Diderik van der Waals, who first proposed these intermolecular forces in 1873. Van der Waals forces are weak, but they play an essential role in determining the properties of compounds.

They are responsible for the attractions between propane molecules, which lead to their condensation into a liquid state. When the temperature of propane is lowered to the point at which van der Waals forces between propane molecules can no longer be overcome by the thermal energy of the molecules, the propane condenses into a liquid. This process is reversible: When the temperature is raised, the propane molecules gain enough energy to overcome the van der Waals forces, and the liquid evaporates back into a gas. Van der Waals forces include dipole-dipole forces, dipole-induced dipole forces, and London dispersion forces. These forces are caused by fluctuating electron densities in the atoms or molecules involved. In propane, the van der Waals forces that lead to the condensation of the gas are primarily London dispersion forces.

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Escreve a formula racionais e o nome de todos isomeros em alcano alceno e alcino possessiveis para compostos com a formula molecular c9h20

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A fórmula molecular C9H20 indica que estamos lidando com hidrocarbonetos. Vamos começar com os alcanos, que são hidrocarbonetos de cadeia aberta contendo apenas ligações simples. Para um hidrocarboneto com a fórmula C9H20, o nome do isômero alcanos possível é nonano.

Nonano é um alcano com nove átomos de carbono. Agora, vamos analisar os alcenos, que são hidrocarbonetos de cadeia aberta contendo uma ligação dupla de carbono. Para um hidrocarboneto com a fórmula C9H20, não existem alcenos isômeros possíveis, já que todos os átomos de carbono precisam formar ligações simples para que a fórmula molecular seja satisfeita.

Por fim, vamos examinar os alcinos, que são hidrocarbonetos de cadeia aberta contendo uma ligação tripla de carbono. Para um hidrocarboneto com a fórmula C9H20, não existem alcinos isômeros possíveis, já que todos os átomos de carbono precisam formar ligações simples para que a fórmula molecular seja satisfeita.

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The sodium (Na) content of 1 particular can of soup is 890 mg sodium in 1 c. What is the molarity of sodium (Na) in the soup

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The molarity of sodium (Na) in the soup is approximately 0.1634 M, calculated by converting the mass of sodium to moles and dividing it by the volume of the soup in liters.

Given:

Amount of sodium (Na) in the soup = 890 mg

Molar mass of sodium (Na) = 22.99 g/mol

Volume of soup = 1 cup = 0.2366 L

Convert the mass of sodium to moles.

Moles of sodium (Na) = (amount of sodium in grams) / (molar mass of sodium)

= 0.890 g / 22.99 g/mol

≈ 0.03866 mol (rounded to five decimal places)

Calculate the molarity of sodium (Na).

Molarity (M) = (moles of sodium) / (volume of solution in liters)

= 0.03866 mol / 0.2366 L

≈ 0.1634 M (rounded to four decimal places)

Therefore, the molarity of sodium (Na) in the soup is approximately 0.1634 M.

Hence, by converting the mass of sodium to moles and dividing it by the volume of the soup in liters, we can determine the molarity of sodium in the soup.

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Acetone is a common solvent that has a density of 0.7899 g/mL. What volume of acetone, in milliliters, has a mass of 17.6 g

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The volume of acetone in milliliters is 22.28 mL, when it has a mass of 17.6 g.

The volume of acetone with a mass of 17.6 g can be calculated using its density, which is 0.7899 g/mL. To find the volume, we divide the mass by the density.

In the given scenario, the mass of the acetone is provided as 17.6 g, and we know the density of acetone is 0.7899 g/mL. Density represents the mass of a substance per unit volume. By dividing the mass of the acetone by its density, we can determine the volume of the acetone. Therefore, the volume of acetone is calculated to be 22.28 mL. This means that 17.6 grams of acetone occupies a volume of 22.28 milliliters.

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we will examine the two chair conformations of cis-1-tert-butyl-4-methylcyclohexane: which does a solid wedge to a substituent in the structure imply?

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In the context of chair conformations, a solid wedge to a substituent implies that the substituent is coming out of the plane of the paper or screen towards you.

This notation is used to show the three-dimensional orientation of the substituent. In cis-1-tert-butyl-4-methylcyclohexane, there are two chair conformations to consider. In one chair conformation, the tert-butyl group is axial, and in the other, it is equatorial. If a solid wedge is drawn to the tert-butyl group in either of the chair conformations, it means that the tert-butyl group is coming out towards you in three-dimensional space.

This notation helps to understand the spatial arrangement of the substituents in the molecule.

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Suppose that a formic acid (hcooh) solution has a ph of 3. 15. which of these substances would increase the ph of the solution?

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To increase the pH of a formic acid (HCOOH) solution with a pH of 3.15, a substance needs to be added that can accept hydrogen ions (H+) and increase the concentration of hydroxide ions (OH-) in the solution.

One such substance that can increase the pH is a strong base. Strong bases dissociate completely in water, releasing hydroxide ions and increasing the pH of the solution. Examples of strong bases include sodium hydroxide (NaOH), potassium hydroxide (KOH), and calcium hydroxide (Ca(OH)2).

Formic acid (HCOOH) is a weak acid that partially dissociates in water, releasing hydrogen ions (H+). The presence of these hydrogen ions gives the solution an acidic pH. To increase the pH, a substance that can accept hydrogen ions and increase the concentration of hydroxide ions needs to be added.

Strong bases, such as sodium hydroxide (NaOH), potassium hydroxide (KOH), and calcium hydroxide (Ca(OH)2), are highly alkaline substances that dissociate completely in water, releasing hydroxide ions (OH-). The hydroxide ions react with the hydrogen ions in the solution, forming water molecules and increasing the pH. By adding a strong base to the formic acid solution, the concentration of hydroxide ions increases, thereby shifting the pH towards the alkaline side and increasing the pH value.

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if connected such that one cell acts as a battery to power the other as an electrolytic cell, which two metals are plated, and what is the total potential, ????∘ ?

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To calculate the total potential, simply add the reduction potential of the battery cell to the reduction potential of the electrolytic cell.

When one cell acts as a battery to power another as an electrolytic cell, metal plating occurs at the cathode (positive electrode). The metal being plated is the same as the metal used in the anode (negative electrode) of the battery cell.

To determine the total potential, we need to consider the individual potentials of the battery and the electrolytic cell. The total potential is the sum of these two potentials.

1. Identify the metals used in the anode and cathode of the battery cell.
2. Look up the standard reduction potentials for the metals.
3. The metal with the higher reduction potential will be plated onto the cathode.


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During summer holidays, a group of children collected a lump of salt, green grass, broken glass piece, a small thermo-col box, pen, iron nail, glass marbles, oil, teddy bear and tried to group them on the basis of properties. help them in filling the table. appearance - hard, soft transparency - transparent, opaque, translucent floats / sinks in water soluble / insoluble in water

Answers

Here's how the items can be grouped based on their properties:

Appearance:
- Hard: iron nail, glass marbles
- Soft: teddy bear
- Transparent: glass marbles, pen
- Opaque: broken glass piece, thermo-col box
- Translucent: none
Floats/Sinks in Water:
- Floats: small thermo-col box, pen, teddy bear
- Sinks: iron nail, glass marbles, broken glass piece
Soluble/Insoluble in Water:
- Soluble: salt, oil
- Insoluble: green grass, broken glass piece, small thermo-col box, pen, iron nail, glass marbles, teddy bear

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The molecular weight of a polymer is MP= 1.00x105 g/mol. Assume 100g of the polymer are dissoved in one literof water at T=298K. Calculate the mole fr

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The mole fraction of the polymer in the solution is [tex]1.80 *10^{-5}[/tex] if the molecular weight of a polymer is MP is [tex]1.00 * 10^5[/tex] g/mol

Mass of the polymer (MP) = 100 g

Molecular weight (MP) = [tex]1.00 * 10^5[/tex] g/mol

The number of moles of the polymer can be calculated by using the formula:

Number of moles of the polymer = Mass of the polymer / Molecular weight of the polymer

Number of moles of the polymer = 100 g / ( [tex]1.00 * 10^5[/tex] g/mol)

Number of moles of the polymer =[tex]1.00 * 10^{-3} mol[/tex]

The number of moles in water can be calculated as:

Volume of water = 1 L

The density of water =  [tex]1 g/cm^3[/tex]

Mass of water = Volume of water x Density of water

Mass of water = 1 L x 1 g/mL = 1000 g

Number of moles of water = Mass of water / Molar mass of water

Number of moles of water = 1000 g / 18.015 g/mol (molar mass of water)

Number of moles of water = 55.49 mol

Mole fraction of the polymer = Moles of the polymer / (Moles of the polymer + Moles of water)

Mole fraction of the polymer =[tex](1.00 * 10^{-3} mol)[/tex] / [tex](1.00 * 10^{-3} mol)[/tex]  + (55.49 mol))

Mole fraction of the polymer =[tex]1.80 *10^{-5}[/tex]

Therefore, we can conclude that the mole fraction of the polymer in the solution is [tex]1.80 *10^{-5}[/tex].

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What is the empirical formula of a compound that breaks down into 4.12g of n and 0.88g of h?

a. nh4

b. nh3

c. n5h

d. n4h

Answers

The empirical formula of a compound that breaks down into 4.12g of n and 0.88g of H is NH₃, which is in option b. So option b is correct as to determine the empirical formula of a compound based on the given mass of elements, one need to calculate the mole ratio of the elements. 

Mass of nitrogen (N) = 4.12 g Mass of hydrogen (H) = 0.88 g

The number of moles for each element is calculated.

Moles of N = Mass of N / Molar mass of N

Moles of N = 4.12 g / (14.01 g/mol) ≈ 0.294 mol

Moles of H = Mass of H / Molar mass of H

Moles of H = 0.88 g / (1.01 g/mol) ≈ 0.871 mol

The mole ratio is found by dividing the moles of each element by the smallest number of moles.

Mole ratio of N to H = Moles of N / Moles of H

Mole ratio of N to H = 0.294 mol / 0.294 mol ≈ 1

To write the empirical formula using the mole ratio as the subscript for each element, and since the mole ratio is approximately 1:1, the empirical formula is NH.

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When appraising a manufactured home, an appraiser needs to look for the __________ to verify that the home was constructed in accordance with federal standards.

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When appraising a manufactured home, an appraiser needs to look for the HUD label to verify that the home was constructed in accordance with federal standards.

Appraisers look the condition of the property, improvements or additions made to the property, lot size  and "renovation" or recently sold properties of similar size and condition in the same market.

One of the biggest things that can have a negative impact is the age and condition of the home's HVAC systems and appliances. If the local market goes down, so will the assessed value of your home. Property valuation is influenced by recent sales of similar properties and  current market trends.

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Stars Choose one: A. begin as protoplanets, which fire up when they collapse and become denser and hotter. B. have unlimited amounts of fuel and therefore exist indefinitely. C. can explode cataclysmically when they die and contribute their matter to future star generations. D. create elements by splitting the nuclei of small atoms into the nuclei of larger atoms.

Answers

Stars can explode cataclysmically when they die and contribute their matter to future star generations. The correct option is C.

Stars undergo a process known as stellar evolution, which involves various stages throughout their lifetimes. When a star exhausts its nuclear fuel, it can undergo a supernova explosion, releasing an enormous amount of energy and matter into space.

These cataclysmic events can contribute heavy elements and enriched material to future star formations. The explosion disperses the star's outer layers, which can then become part of interstellar gas clouds and serve as the building blocks for new stars and planetary systems.

This process plays a vital role in the cycle of stellar birth and death, where the remnants of older stars contribute to the formation of new stars, planets, and other celestial objects.

Therefore, the correct option is C, can explode cataclysmically when they die and contribute their matter to future star generations.

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In a chemical reaction we end up with 0.52 g of crude benzoic acid. After recrystallization 0.37 g of benzoic acid is obtained. What is the % recovery of benzoic acid in this case

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Recrystallization is the process of dissolving a substance in a solvent at an elevated temperature and then slowly cooling it to form crystals. The solubility of the substance in the solvent varies at different temperatures. The impurities remain in the solution, while the pure substance crystallizes out. It's a common technique used to purify a substance. Benzoic acid is a white, crystalline, and organic compound that is used in the food and chemical industries.

The recrystallization of benzoic acid is a common undergraduate laboratory experiment. In this question, 0.52 g of crude benzoic acid is obtained from a chemical reaction, and 0.37 g of benzoic acid is obtained after recrystallization. We need to find the % recovery of benzoic acid in this case. How to calculate % recovery?% Recovery = (Pure benzoic acid obtained / crude benzoic acid used) × 100%The weight of pure benzoic acid obtained after recrystallization is 0.37 g. Crude benzoic acid obtained is 0.52 g. Substituting the values in the above formula,% Recovery = (0.37 / 0.52) × 100%≈ 71.15%Therefore, the % recovery of benzoic acid in this case is approximately 71.15%.

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One way to prevent corrosion is to add _____ to the water, which interact chemically with contaminates, rendering them inert.

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One way to prevent corrosion is to add corrosion inhibitors to the water. Corrosion inhibitors are chemical substances that, when added to the water, interact chemically with contaminants or the metal surface itself to form a protective layer.

Corrosion inhibitors are chemical compounds added to water or other corrosive environments to mitigate the degradation of metals. They work by interfering with the electrochemical reactions that cause corrosion, ultimately protecting the metal surfaces.

This layer acts as a barrier, preventing the corrosive substances from reaching the metal surface and causing damage. Corrosion inhibitors work through various mechanisms, such as:

1. Passivation: Certain inhibitors form a passivating layer on the metal surface, which reduces the metal's reactivity and enhances its resistance to corrosion. This layer acts as a physical barrier between the metal and the corrosive environment.

2. Adsorption: Corrosion inhibitors can adsorb onto the metal surface, forming a protective film that hinders the corrosive reaction. This film prevents corrosive substances from coming into direct contact with the metal and inhibits their ability to cause corrosion.

Common types of corrosion inhibitors used in water systems include organic compounds like amines, phosphates, silicates, and various other chemicals that possess inhibiting properties. The specific inhibitor chosen depends on the type of metal being protected, the nature of the corrosive environment, and the desired level of corrosion prevention.

It is important to note that the selection and application of corrosion inhibitors require careful consideration of the water chemistry, the specific metal involved, and other factors. Proper dosage and monitoring are crucial to ensure effective corrosion prevention without causing any adverse effects or compromising the water quality.

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hydrogen peroxide is commonly used for multiple select question. skin and wound cleansing disinfection of medical equipment disinfection of drinking water disinfection of food preparation equipment sterilization of diagnostic instruments

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The required answer to this question is Hydrogen peroxide is commonly used for the following purposes:

1) Skin and wound cleansing:

Hydrogen peroxide is used as an antiseptic to clean and disinfect minor cuts, scrapes, and wounds. It helps to prevent infection by killing bacteria and other microorganisms on the skin's surface.

2) Disinfection of medical equipment:

Hydrogen peroxide can be used to disinfect various medical instruments and equipment, including surfaces, surgical tools, and devices. It helps to eliminate or reduce the presence of bacteria, viruses, and other pathogens that may be present on the equipment.

3) Disinfection of drinking water:

In certain situations, hydrogen peroxide can be used to disinfect drinking water. It can help in killing harmful microorganisms and making the water safe for consumption. However, it's important to note that the concentration and usage should be carefully controlled to ensure it is safe for drinking water disinfection.

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what lab equipment would be best to measure 12.6ml of liquid ethanol?

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Answer: 25 mL volumetric flask

Explanation: this piece of equipment is especially designed to measure in great depth like what you are trying to do…

A bomb calorimeter has a heat capacity of 900 J/oC and contains 800 g of water (specific heat capacity 4.184 J/g.oC). If a 5.00 g sample of a carbohydrate is combusted in the calorimeter and the change in temperature is 20 oC, what is the approximate value of qrxn?


a. â€"425 kJ


b. â€"67 kJ


c. 85 kJ


d. â€"85 kJ

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A bomb calorimeter has a heat capacity of 900 J/oC and contains 800 g of water (specific heat capacity 4.184 J/g.oC). If a 5.00 g sample of a carbohydrate is combusted in the calorimeter and the change in temperature is 20 oC, the approximate value of qrxn is -85 kJ. The correct option is (d). Solution: Given, Mass of water = 800 g Specific heat capacity of water = 4.184 J/g.oC Change in temperature = 20oC Heat capacity of calorimeter = 900 J/oC Weight of carbohydrate = 5 g.

The amount of heat evolved in the reaction (qrxn) can be calculated using the formula qrxn = -(mcΔT) / n Where, m = mass of the water c = specific heat capacity of the waterΔT = change in temperature n = moles of the carbohydrate. Since carbohydrate is being completely combusted, it means it will be the limiting reagent in the reaction. Therefore, all the heat evolved will be due to the combustion of the carbohydrate. Hence, we can calculate the heat evolved directly from the combustion of 5 g of carbohydrate. qrxn = -85 kJ (approximately)The negative sign shows that the reaction is exothermic, which is expected in combustion reactions. Therefore, option (d) is correct.

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ground state chemistry under vibrational strong coupling: dependence of thermodynamic parameters on the rabi splitting energy

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The ground-state chemistry under vibrational strong coupling refers to the interaction between molecules and photons in a way that the vibrational modes of the molecules become coupled to the electromagnetic field. This coupling leads to the formation of new hybrid states known as polaritons.

The dependence of thermodynamic parameters, such as energy and entropy, on the Rabi splitting energy can be understood by considering the effect of strong coupling on the energy levels of the system.

The Rabi splitting energy is the energy difference between the lower and upper polariton states.

Here is a step-by-step explanation of how the thermodynamic parameters depend on the Rabi splitting energy:

1. Energy: The Rabi splitting energy directly affects the energy levels of the polaritons.

As the Rabi splitting energy increases, the separation between the lower and upper polariton energy levels increases.

This leads to a larger energy difference between the ground state and the excited state of the system.

Consequently, the overall energy of the system increases with the Rabi splitting energy.

2. Entropy: The entropy of a system is related to the number of available states. In the context of ground state chemistry under vibrational strong coupling, the coupling of vibrational modes with the electromagnetic field creates new hybrid states (polaritons) that have different vibrational and electronic character compared to the original molecule.

This increase in the number of available states leads to an increase in entropy.

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What is the major product of the following reaction? na2cr2o7h2so4h2o select one: a. b. c. d. e.

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The reaction formula "Na2Cr2O7 + H2SO4 + H2O" does not specify the reactants or the conditions under which the reaction occurs.

The information provided is not sufficient to determine the major product of the reaction. The reaction formula "Na2Cr2O7 + H2SO4 + H2O" does not specify the reactants or the conditions under which the reaction occurs. Without this information, it is not possible to identify the major product.

To determine the major product of a reaction, it is essential to know the specific reactants and the reaction conditions. Please provide more details or context for the reaction, and I will be glad to assist you further in identifying the major product.

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